Consider that lines u and v are parallel. Which equation models the relationship between the angles? What is the value of x? A) 12x - 4 = 10x + 10; x = 7 B) 12x - 4 + 10x + 10 = 180; x = 7.9 C) 12x - 4 = 10x - 10; x = -3 D) 12x + 4 = 10x + 10; x = 3
Answers
Answer:
A) 12x - 4 = 10x + 10; x = 7
Step-by-step explanation:
12x - 4 = 10x + 10; x = 7
Since lines u and v are parallel, the two angles are corresponding angles. Corresponding angles are equal to each other.
12x - 4 = 10x + 10
Solve for x:
2x = 14
x = 7
Related Questions
A farmer estimates that he has 9,000 bees producing honey on his farm. The farmer becomes concerned when he realizes the population of bees seems to be decreasing steadily at a rate of 5% per year. If the number of bees in the population after x years is represented by f(x), which statements about the situation are true? Check all that apply. The function f(x) = 9,000(1.05)x represents the situation. The function f(x) = 9,000(0.95)x represents the situation. After 2 years, the farmer can estimate that there will be about 8,120 bees remaining. After 4 years, the farmer can estimate that there will be about 1,800 bees remaining. The domain values, in the context of the situation, are limited to whole numbers. The range values, in the context of the situation, are limited to whole numbers.
Answers
Answer:
Step-by-step explanation:
The function f(x) = 9,000(0.95)x represents the situation.
After 2 years, the farmer can estimate that there will be about 8,120 bees remaining.
The range values, in the context of the situation, are limited to whole numbers.
The true representation of the declining bee population is f(x) = 9,000(0.95)^x, accounting for a 5% annual decrease. The function and expected number of bees after 2 years are correct if rounded to approximately 8,120. The domain and range values are limited to whole numbers in this context.
Explanation:The given situation of the farmer noticing a decrease of bees in his population can be represented by a mathematical function that models the decline. This function is f(x) = 9,000(0.95)^x, which correctly represents a 5% annual decrease in the bee population.
After analyzing the situation:
The statement f(x) = 9,000(1.05)^x is false because it suggests a 5% increase rather than a decrease.The correct function, as mentioned before, is f(x) = 9,000(0.95)^x.After 2 years, the population of bees expected can be calculated: f(2) = 9,000(0.95)^2 ≈ 8,122.5, which, when rounded to a whole number due to the context, is about 8,123 bees remaining, making this statement true if it refers to approximately 8,120 bees.After 4 years, using the function, the statement that there will be about 1,800 bees remaining is false; the correct calculation would yield a higher number.The domain values are limited to whole numbers since you cannot have a fraction of a year.The range values are also limited to whole numbers as you cannot have a fraction of a bee.Learn more about Exponential Decay here:https://brainly.com/question/2193799
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Kathryn, a college student, works part time at a coffee house. She worked 5 StartFraction 7 Over 20 EndFraction hours on Monday, 4 and one half on Tuesday, 6 and three fourths on Wednesday, 3 and one fourth on Thursday, and 7 on Friday. How many hours did she work altogether? She worked nothing hours altogether.
Answers
5 + 4 + 6 + 3 + 7 = 25
7/20 + 1/2 + 3/4 + 1/4 = 7/20 + 10/20 + 15/20 + 5/20 = 37/20 = 1 17/20
25 + 1 17/20 =
26 17/20 <====
Answer: I’m just adding this to verify that the other answer was correct
The factored form of 4a3b5 − 16a5b2 + 12a2b3 is ?
Answers
Answer:
The factored form of [tex]4a^3b^5-16a^5b^2+12a^2b^3[/tex] is [tex]4a^2b^2\left(ab^3-4a^3+3b\right)[/tex].
Step-by-step explanation:
To find the factored form of [tex]4a^3b^5-16a^5b^2+12a^2b^3[/tex] you must:
Apply exponent rule: [tex]a^{b+c}=a^ba^c[/tex]
[tex]a^2b^3=a^2b^2b,\:a^5b^2=a^2a^3b^2,\:a^3b^5=a^2ab^2b^3[/tex]
So, we can write our expression as [tex]4a^2ab^2b^3-16a^2a^3b^2+12a^2b^2b[/tex].
Next, rewrite 12 as [tex]3\cdot \:4[/tex] and -16 as [tex]4\cdot \:4[/tex]
[tex]4a^2ab^2b^3+4\cdot \:4a^2a^3b^2+3\cdot \:4a^2b^2b[/tex]
Factor out common term: [tex]4a^2b^2[/tex]
Therefore,
[tex]4a^3b^5-16a^5b^2+12a^2b^3= 4a^2b^2\left(ab^3-4a^3+3b\right)[/tex]
A rectangular board is 18 feet by 24 feet. How far from the center of the board should the foci be located in order to cut the largest elliptical tabletop from the board?
a. 7.94 ft
b. 4.06 ft
c. 15 ft
d. 15.9 ft
Answers
x = 24
y = 18
Length of Major Axis = a
Length of Minor Axis = b
Center (0, 0):
h = 0
k = 0
a = 1/2 x
a = 1/2 *(24)
a = 12
b = 1/2 y
b =1/2 (18)
b = 9
So, Equation of Ellipse:
General : (x - h)² / a² + (y - k)² / b² = 1
(x - 0)² / (12)² + (y - 0)² / (9)² = 1
x² / 144 + y² / 81 = 1
Focus = c:
_____
c = √a² - b²
_______
c = √(12)² - (9)²
______
c = √144 - 81 = sqrt63 = 7.9372
Focus : ( -7.9372, 0) and ( 7.9372, 0)
The correct answer is: a. 7.94 ft
Step 1
To find the distance from the center of the board to the foci of the ellipse that will result in the largest possible elliptical tabletop, we can use the formula:
[tex]\[ c = \sqrt{a^2 - b^2} \][/tex]
where:
- a is half the length of the major axis (which is half of the longer side of the rectangle)
- b is half the length of the minor axis (which is half of the shorter side of the rectangle)
Step 2
Given that the rectangle is 18 feet by 24 feet, [tex]\( a = \frac{24}{2} = 12 \)[/tex] feet and [tex]\( b = \frac{18}{2} = 9 \)[/tex] feet.
Step 2
Now, we can substitute these values into the formula:
[tex]\[ c = \sqrt{12^2 - 9^2} \]\[ c = \sqrt{144 - 81} \]\[ c = \sqrt{63} \][/tex]
Taking the square root of 63 gives us approximately 7.94 feet.
An electric current, I, in amps, is given by I=cos(wt)+√8sin(wt), where w≠0 is a constant. What are the maximum and minimum values of I
Answers
[tex] - w \sin(wt) + \sqrt{8} w cos(wt)[/tex]
the maximum and minimum values occur when the tangent line is zero so we set the derivative to zero
[tex]0 = -w \sin(wt) + \sqrt{8} w cos(wt)[/tex]
divide by w
[tex]0 =- \sin(wt) + \sqrt{8} cos(wt)[/tex]
we add sin(wt) to both sides
[tex]\sin(wt)= \sqrt{8} cos(wt)[/tex]
divide both sides by cos(wt)
[tex] \frac{sin(wt)}{cos(wt)}= \sqrt{8} \\ \\ arctan(tan(wt))=arctan( \sqrt{8} ) \\ \\ wt=arctan(2 \sqrt{2)} [/tex] OR[tex] \\ [/tex] [tex]wt=arctan( { \frac{1}{ \sqrt{2} } ) [/tex]
(wt)=2(n*pi-arctan(2^0.5))
(wt)=2(n*pi+arctan(2^-0.5))
where n is an integer
the absolute max and min will be
[tex]I=cos(2n \pi -2arctan( \sqrt{2} ))[/tex]
since 2npi is just the period of cos
[tex]cos(2arctan( \sqrt{2} ))= \frac{-1}{3} [/tex]
substituting our second soultion we get
[tex]I=cos(2n \pi +2arctan( \frac{1}{ \sqrt{2} } ))[/tex]
since 2npi is the period
[tex]I=cos(2arctan( \frac{1}{ \sqrt{2}} ))= \frac{1}{3} [/tex]
so the maximum value =[tex] \frac{1}{3} [/tex]
minimum value =[tex]- \frac{1}{3} [/tex]
The maximum value of the electric current is [tex]I_{max}=\dfrac{1}{3}[/tex]
the minimum value of the electric current is [tex]I_{min}=-\dfrac{1}{3}[/tex]
The given expression for electric current is [tex]I=\cos(\omega t)+\sqrt{8}\sin(\omega t)[/tex] where [tex]\omega \neq 0[/tex].
Differentiate the given function with respect to [tex]t[/tex]-
[tex]\dfrac{dI}{dt}=\dfrac{d(\cos(\omega t)+\sqrt 8 \sin(\omega t))}{dt}\\\dfrac{dI}{dt}=-\omega \sin(\omega t)+\sqrt 8 \omega \cos(\omega t)[/tex]
Equate the derivative to 0-
[tex]\dfrac{dI}{dt}=0\\-\omega \sin(\omega t)+\sqrt 8 \omega \cos(\omega t)=0\\\sin(\omega t)=\sqrt 8 \cos (\omega t)\\\tan (\omega t)=\sqrt 8\\\omega t=\tan^{-1}\sqrt 8\\\omega t=2n\pi-2\tan^{-1}\sqrt 2}\\or,\\\omega t=2n\pi+2\tan^{-1}\sqrt {1/2}}[/tex]
[tex]2n\pi[/tex] is the period of sine and the cosine trigonometric function.
So, the maximum value of the electric current is
[tex]I_{max}=\cos(2\tan^{-1}\sqrt {1/2})\\I_{max}=\dfrac{1}{3}[/tex]
Also, the minimum value of the electric current is
[tex]I_{min}=\cos(2\tan^{-1}\sqrt {2})\\I_{min}=-\dfrac{1}{3}[/tex]
Learn more about maximum and minimum values of the functions here:
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An artist agrees to paint a landscape painting at $0.30 per square inch. If the painting is 13 inches by 17 inches, how much should the artist charge?
Answers
area of painting = 13 * 17 = 221 square inches
221 * 0.30 = 66.30
the price would be $66.30
What is the value of m?
13m+3−56m=−15
Answers
-43m = -18
43m = 18
m = 18/43 or about .4186
The value of m in the equation [tex]13m +3 -56m = -15[/tex] is [tex]\frac{18}{43}[/tex]
Given: [tex]13m +3 -56m = -15[/tex]
To find: value of m
To find the value of m we need to move all the terms containing variables on LHS and the constants on RHS. This can be done as follows:
[tex]13m +3 -56m = -15\\13m -56m =-15-3\\[/tex]
Now we can solve for m as follows:
[tex]13m-56m =-15-3\\-43m = -18\\[/tex]
The negative sign on both LHS and RHS will cancel out and it will give us:
[tex]m = \frac{18}{43}[/tex]
Since 18 and 43 do not have any common multiples so the fraction cant be simplified further. So, [tex]m = \frac{18}{43}[/tex]
Speed skiing takes place on a course that is 2/3 mile long. How many feet long is the course? Show work too
Answers
1 mile = 5280 feet
5280 * 2/3 =
5280 *2 = 10560
10560/3 = 3520
it is 3520 feet long
What is the area of a circle with a radius of 7 cm? (Use 3.14 for pi and round to the nearest tenth.)
Answers
Radius = 7cm
Area of circle = [tex] \pi r^2[/tex]
= [tex]3.14*7*7[/tex]
= [tex]153.94 cm^2[/tex]
[tex]153.94[/tex] rounded to the nearest tenth = [tex]153.9cm^2[/tex]
Hope I helped (:
Have a great day!
Answer:
[tex]153.9\ cm^{2}[/tex]
Step-by-step explanation:
Hello, thanks for asking this question here at Brainly, I think I can help you with this
the area of circle is given by:
[tex]Area=\pi * radius^{2} \\[/tex]
Step one
Let
[tex]\pi =3.14\\and\\r= 7 cm[/tex]
Step two
put the values into the equation
[tex]Area=\pi * radius^{2} \\Area=3.14* (7 cm)^{2}\\ Area=3.14* 49\ cm^{2} \\Area=153.9\ cm^{2} \\[/tex]
Hence, the area of a circle with radius 7 cm is 153.9 cm2
I hope it helps,do not hesitage in asking me anything about this, have a great day
WILL GIVE BRAINEST
use the elimination method to solve the system of equations.
2x+4y=10
3x-4y=5
a.(1,3)
b.(3,4)
c.(5,0)
d.(3,1)
Answers
Answer:
(3,1)
Step-by-step explanation:
Hi, to solve this problem:
[tex]2 x + 4y = 10\\ +\\3x-4y=5\\-----\\5x =15\\x = 15/5\\x= 3[/tex]
then, replacing the value of "x" in one equation.
2x (3) + 4 y = 10
6 +4y =10
4y= 10- 6
4 y = 4
y = 4/4
y =1
So, the correct option is d.(3,1).
Feel free to ask for more if it´s necessary or if you did not understand something.
a triangle is classified as equilateral triangle when it has
Answers
Answer:
Three sides with the same length because that is what an equilateral triangle is.
Step-by-step explanation:
In the diagram, g ∥ h, m∠1 = (4x + 36)°, and m∠2 = (3x – 3)°.What is the measure of ∠3?
Answers
Lines a and b are parallel. What is the measure of angle s? Enter your answer in the box. s = ∘∘ Horizontal parallel lines a and b intersect with another line making eight angles, the top right angle of line a is labeled one hundred fifty eight degrees, and the top left angle of line b is labeled X degrees
Answers
Assuming I'm interpreting your description accurately, the top right angle of line b will also be 158 degrees because it's a corresponding angle to the top right angle of line a. That means that the top left angle of line b will be a supplementary angle. And supplementary angles add up to 180. So 180 - 158 = 22.
Answer:
Measure of angle s is 22°
Step-by-step explanation:
Given that lines a and b are parallel. Horizontal parallel lines a and b intersect with another line making 8 angles, the top right angle of line a is labeled 158° and the top left angle of line b is labeled s degrees
we have to find the measure of angle s.
As ∠1 and 158° and on straight line hence are supplementary
i.e ∠1+158°=180°
⇒ ∠1=180°-158°=22°
Also, angle s and ∠1 are alternate interior angles.
As a and b are parallel then alternate interior angles are equal.
Hence, ∠s=∠1=22°
Measure of angle s is 22°
Which investment has the least amount of risk? standard deviation = $450, expected return = $4,500 standard deviation = $600, expected return = $400 standard deviation = $500, expected return = $800 standard deviation = $400, expected return = $5,000?
Answers
Investment 1: standard deviation = $450, expected return = $4,500
expected return to standard deviation ratio = 4500 / 450 = 10
Investment 2: standard deviation = $600, expected return = $400
expected return to standard deviation ratio = 400 / 600 = 0.67
Investment 3: standard deviation = $500, expected return = $800
expected return to standard deviation ratio = 800 / 500 = 1.6
Investment 4: standard deviation = $400, expected return = $5,000
expected return to standard deviation ratio = 5000 / 400 = 12.5
Therefore, the investment that has the least amount of risk is the invetment with standard deviation = $400, expected return = $5,000
Where a is the frontal area of the ball (πd2/4), and cd is the drag coefficient (0.47 for a sphere). what is the drag force on the ball?
Answers
The graph shows a line and two similar triangles.
Answers
The equation of the line will be y = 4/3x + 3. The correct option is C.
What is an equation of the line?An equation of the line is defined as a linear equation having a degree of one. The equation of the line contains two variables x and y. And the third parameter is the slope of the line which represents the elevation of the line.
The general form of the equation of the line:-
y = mx + c
m = slope
c = y-intercept
Slope = ( y₂ - y₁ ) / ( x₂ - x₁ )
From the given graph the slope will be calculated as:-
Rise = 4
Run = 3
Slope = Rise / Run = 4 / 3
The y-intercept is 3.
The equation can be written as:-
y = mx + c
y = 4/3x + 3
Therefore, the equation of the line is y = 4/3x +3.
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To solve 49^3x = 343^2x+1, write each side of the equation in terms of base ____
Answers
Each side of [tex]49^{3x} = 343^{2x + 1}[/tex], expressed in terms of their bases, is: [tex]7^{2(3x)} = 7^{3(2x + 1)}\\\\[/tex].
Solving Equations by Expressing Equations in Terms of their BasesTo solve an equation, the bases can be made equivalent and cancelled out by creating exponents.
Given:
[tex]49^{3x} = 343^{2x + 1}[/tex]
First, express each side by simplifying their bases and make them equivalent. Let the base be 7.
Thus:
[tex]7^{2(3x)} = 7^{3(2x + 1)}\\\\[/tex]
To solve, cancel the bases to have, 2(3x) = 3(2x + 1) and solve for x.
Therefore, each side of [tex]49^{3x} = 343^{2x + 1}[/tex], expressed in terms of their bases, is: [tex]7^{2(3x)} = 7^{3(2x + 1)}\\\\[/tex].
Learn more about bases on:
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Answer: 7 then B on edge
Step-by-step explanation:
Answer: it’s
Step-by-step explanation:
2x^3-18x
factor completely
Answers
8/10 divided by 1 5/6
Answers
You can either use a calculator on your phone or computer
If 7.02 is subtracted 43.8 the correct answer will be
Answers
hope this helped!
Let f(x) = 4x-5 and g(x) = 3x, find (fog)(x)
Please answer the question
Answers
Hope I helped
Show the tens fact you used. Show the difference.
14-6=
10-?=?
Answers
(b) In this item, we are to find out or determine the number that when subtracted from 10, will yield the same number. If we let x be this number then,
10 - x = x
Simplifying the equation,
10 = 2x
Dividing both sides by 2 will give us an answer of 5.
ANSWERS: (a) 8
(b) 5
Question 1:
14 - 6 = ?
Further ExplanationTo determine the difference between 14 and 6 is the same is 14 – 6. In other words, the different is the result we get if we subtract both values.
Therefore, the difference between 14 and 6 is 8.
14 – 6
= 8.
There is always three parts in any subtraction equation and these include:
The number that is being subtracted from also called minuendThe number that is being subtracted from the minuend, also called subtrahendThe differences, which is the result you get from subtracting the subtrahend from minuendQuestion 2:
10 - ? = ?
Further ExplanationThe given question means you should for a number that when being subtracted from 10 will give the same number.
Therefore, to solve the question, let the missing be X
10 – X = X
If you simplify the equation, then you should have:
10 = X + X
10 = 2X (divide both side by 2)
[tex]\frac{10}{2}[/tex] = [tex]\frac{2x}{2}[/tex]
5 = X
X = 5
Therefore, the answer for question 1 and 2 are 8 and 5 respectively
LEARN MORE:
Show the tens fact you used write the difference 14 https://brainly.com/question/13620963Show the tens fact you used. Write the difference. https://brainly.com/question/1904682KEYWORDS:
differencetens factsubtractionequationminuendy=0.6x–3;(–2,2) parallel lines
Answers
y=0.6x+a
plug (-2,2) into the equation
2= -2*0.6+a
2+1.2=a
a=3.2
function of the parallel line is y=0.6x+3.2
write 60 as the product of two factors
Answers
The endpoints of line segment AB are A (9,4) and B (5,-4). Then endpoints of its image after dilation are A' (6,3) and B' (5,-4). Find the scale factor and explain
Answers
The length of AB is the distance from (9,4) to (5,-4).
Let's apply the distance formula:
AB = √ ((9-5)² + (4+4)²)
AB = √ (4² + 8²)
AB = √(16 + 64)
AB = √ (80)
AB = 4 √5
The length of AB is 4 √5.
Now for A'B':
A'B' = √ ((6-5)² + (3+4)²)
A'B' = √( 1 + 49)
A'B' = √ 50
A'B' = 5 √2
To find our scale factor k:
A'B' = k AB
5 √2 = 4 √5 * k Divide both sides by 4√5
5 √2 / (4 √5) = k To simplify, multiply the left side by (√5 / √5)
(5 *√5 * √2) / (4 *5) = k the 5's in the numerator and denominator cancel
√5 * √2 / 4 = k
√10 / 4 = k
To confirm, make sure AB * k = A'B', using the values that we've calculated.
Answer:To find the image of B, first find the scale factor for the dilation. The scale factor should be greater than 1 because the image of A is farther from the origin than A. Divide the coordinates of the image of A by the coordinates of A: –6/–4 = 3/2 and 9/6 = 3/2, so the scale factor is 3/2. Now, apply the dilation to B by multiplying the coordinates by 3/2 to get ((3/2)(1), (3/2)(4)), or (3/2, 6).
Hope I helped
When creating a scatterplot, if the points are too close together to see the relationship, how could you adjust your graph?
A.
decrease your scale values
B.
increase your scale values
C.
plot more points
D.
plot fewer points
Answers
Rafael walks 2.5 km every day. How far does he walk in 9 days?
Answers
All you have to do is multiply 2.5x9
Tell whether the two rates form a proportion
7 inches in 9 hours; 42 inches in 54 hours
explain how you got the answer/show your work
Answers
Another way I did it was that I divided 9/7 to get 1.2857. I tried the same to 54/42 and I got the same answer. I then used 1.2857 to multiply that by 7 and it ended up giving me 9 and I used that to multiply it by 42 as well to get 54.
The rates of 7 inches per 9 hours and 42 inches per 54 hours do form a proportion, as demonstrated by cross-multiplying the two ratios which resulted in equal cross products (378 inch-hours on both sides).
Explanation:To determine if the two rates form a proportion, we need to compare the ratios of inches to hours for both scenarios. For the first rate, we have 7 inches in 9 hours, and for the second rate, we have 42 inches in 54 hours. A proper proportion exists when two ratios are equivalent.
Let's set up our two ratios:
First ratio: 7 inches / 9 hoursSecond ratio: 42 inches / 54 hoursNow, we will test if these ratios form a proportion by creating a fraction out of each ratio and then cross-multiplying.
(7 inches / 9 hours) = (42 inches / 54 hours)
Cross multiply:
7 inches * 54 hours = 378 inch-hours
42 inches * 9 hours = 378 inch-hours
Since the cross products are equal, the two rates indeed form a proportion.
Pls help me with these three! Thanks!
Answers
The surface area of a snowball melting decreases at a rate of 6cm/min. how is the volume changing when the radius is 3
Answers
[tex]\bf \textit{surface area of a sphere}\\\\ s=4\pi r^2\implies \boxed{\cfrac{s}{4\pi }=r^2} \\\\\\ \cfrac{1}{4\pi }\cdot \cfrac{ds}{dt}=\stackrel{chain~rule}{2r\cfrac{dr}{dt}}\implies \boxed{\cfrac{\frac{ds}{dt}}{8\pi r}=\cfrac{dr}{dt}}\\\\ -------------------------------\\\\[/tex]
[tex]\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}\implies V=\cfrac{4\pi }{3}\cdot r^2\cdot r\implies V=\cfrac{\underline{4\pi} }{3}\cdot \boxed{\cfrac{s}{\underline{4\pi} }}\cdot r \\\\\\ V=\cfrac{1}{3}sr\implies \cfrac{dV}{dt}=\cfrac{1}{3}\left( \cfrac{ds}{dt}\cdot r+s\cdot \cfrac{dr}{dt} \right)\\\\ -------------------------------\\\\[/tex]
[tex]\bf \textit{now, when the radius is 3}\qquad \begin{cases} \frac{ds}{dt}=-6\\\\ s=4\pi 3^2\\ \qquad 36\pi \\\\ \frac{dr}{dt}=\frac{-6}{8\pi 3}\\\\ \qquad -\frac{1}{4\pi } \end{cases} \\\\\\ \cfrac{dV}{dt}=\cfrac{1}{3}\left(-6\cdot 3~~+~~36\pi\cdot -\cfrac{1}{4\pi } \right)\implies \cfrac{dV}{dt}=\cfrac{1}{3}(-18-9) \\\\\\ \cfrac{dV}{dt}=-\cfrac{27}{3}\implies \cfrac{dV}{dt}=-9[/tex]