Answer:
Of longitudinal waves
Explanation:
Depending on the direction of the oscillation, there are two types of waves:
- Transverse waves: in a transverse wave, the oscillations occur perpendicularly to the direction of propagation of the wave. Examples are electromagnetic waves.
- Longitudinal waves: in a longitudinal wave, the oscillations occur parallel to the direction of propagation of the wave. In such a wave, the oscillations are produced by alternating regions of higher density of particles, called compressions, and regions of lower density of particles, called rarefactions. Examples of longitudinal waves are sound waves.
Compressions and rarefactions are characteristic of sound waves, which are longitudinal waves. Compressions are regions of high pressure, while rarefactions are regions of low pressure, both created by the vibrating motion of the sound source.
Explanation:Compressions and rarefactions are characteristic features of a sound wave, which is a type of longitudinal wave. When a sound source vibrates, it causes fluctuations in the pressure of the medium through which it travels, typically air. These fluctuations manifest as alternating regions of higher pressure, known as compressions, and lower pressure, known as rarefactions. Sound waves consist of these repeating patterns of compressions and rarefactions, moving away from the source of the sound in the form of a wave.
During compression, air molecules are pushed closer together, leading to a higher pressure region. Conversely, during rarefaction, air molecules are spread out, creating a lower pressure region. For example, when a speaker cone moves forward, it compresses the air in front of it, and when it moves backward, it creates a rarefaction. These disturbances travel through the air, causing our eardrums to vibrate and enabling us to perceive sound.
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Eruption of a large volcano on a tropical island releases ash and gases into the atmosphere. after the eruption, the air temperatures on the island cool temporarily before returning to normal. which is the most likely reason for the temporary cooling of the island?
Answer:
a volcanic winter.
Explanation:
the ash blocks the sun, preventing its heat and as the ash leaves, the sun can shine though. hope this helps
The temporary cooling of the island following a volcanic eruption is likely due to haze-effect cooling, a phenomenon where volcanic ash and gases block out sunlight, thereby lowering the temperature. This effect can last for a year or more, leading to temporary climate changes.
Explanation:The temporary cooling of the island after a volcanic eruption is most likely due to a phenomenon known as haze-effect cooling. This occurs when a volcano releases large volumes of gases and solids such as sulfur dioxide and ash into the atmosphere. These materials can block out sunlight, thereby causing a drop in temperature.
Volcanic eruptions are natural drivers of climate change influencing the climate over a few years, causing short-term climate changes. An example of this is when the volcanoes in Iceland erupted in 1783, releasing large volumes of sulfuric oxide. This led to haze-effect cooling, which produced some of the lowest average winter temperatures on record in Europe and North America in 1783 and 1784.
This haze-effect cooling usually extends for one or more years before dissipating. So it could be inferred that the cooling on the island is likely temporary and will return to normal once the suspended particles from the eruption have dissipated.
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Who was the second man to walk on the moon?
Answer:
Buzz Aldrin
Explanation:
Answer:
Buzz Aldrin
Explanation:
Neil Armstrong was the first man to walk on the moon, but Buzz Aldrin was the second man to walk on the moon. They both walked on the moon on the Apollo 11 Space Mission. Buzz Aldrin was a lunar module pilot working for NASA, and he went up with Neil Armstrong to land on the moon.
Mordancy.
For which optical devices does d sometimes have a positive value
Answer:
B) A & C
Explanation:
Many ionic and covalent compounds dissolve well in water. This is because (2 points) the temperature of liquid water is high enough to allow anything to mix well with its fast moving particles. the air pressure above the water is greater than the pressure exerted by the moving water particles. the solute particles are small enough to fit in the spaces between the tightly packed solvent particles. the attraction between the solute and solvent is about as strong as the attraction between the solvent particles.
Answer:
the attraction between the solute and solvent is about as strong as the attraction between the solvent particles.
Explanation:
Am radio signals are broadcast at frequencies between 550 khz and 1600 khz and travel 2.99792 × 108 m/s. What is the shortest am wavelength? Answer in units of m.
Answer:
187.37 m
Explanation:
The wavelength of an electromagnetic wave is given by:
[tex]\lambda=\frac{c}{f}[/tex]
where
c is the speed of light
f is the frequency
We see that the wavelength is inversely proportional to the frequency: this means that the shortest am wavelength will occur at the highest am frequency, which is
[tex]f=1600 kHz = 1600 \cdot 10^3 Hz[/tex]
And substituting also the speed of light
[tex]c=2.99792 \cdot 10^8 m/s[/tex]
We find the wavelength:
[tex]\lambda=\frac{2.99792 \cdot 10^8 m/s}{1600\cdot 10^3 Hz}=187.37 m[/tex]
Why do thunderstorms most often occur in the summer months?
Answer:
Because moisture and warmth are crucial to thunderstorms, it makes sense that they would occur more often in the spring and summer, particularly in humid areas such as the southeastern United States.The rising moisture that has lost an electron carries a positive charge to the top of the cloud.
A clear reflection of Mount Hood can be seen in Mirror Lake. Surfaces, such as this one, allow for specular reflection. Light can be thought of as a bundle of individual light rays which are traveling parallel to each other. Each individual light ray follows the law of reflection. If the bundle of light rays is incident upon a smooth surface, like Mirror Lake,
Answer:C) light rays reflect and remain concentrated in a bundle upon leaving the water's surface.
Explanation:
) light rays reflect and remain concentrated in a bundle upon leaving the water's surface.
Answer:
c
Explanation:
A car moves at a constant speed of 10 m/s. If the car doesn't accelerate during the next 40 s how far will it go?
A) 200 m
B) 400 m
C) 50 m
D) 0.25 m
the answer is b. space = time * velocity
The distance travelled by the car will be 400 m. Option B is correct.
What is distance?Distance is a numerical representation of the distance between two objects or locations.
Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.
Given data;
Speed (V)= 10 m/s.
Time (t)=40 s
The distance travelled by the car will be;
Distance = speed × time
Distance =10 m/s × 40 s
Distance =400 m
The distance travelled by the car will be 400 m.
Hence,option B is correct.
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Mechanical energy is conserved in the presence of which of the following types of forces?Select all that apply. A- electrostatic B- frictional C- magnetic D- gravitational
Mechanical energy remains constant (conserved) if only conservative forces act on the particles.
In this sense, the following forces are conservative:
-Gravitational
-Elastic
-Electrostatics
While the Friction Force and the Magnetic Force are not.
According to this, mechanical energy is conserved in the presence of electrostatic and gravitational forces. Therefore the correct options are A and D.
Answer:
A- electrostatic
C- magnetic
D- gravitational
Explanation:
As per mechanical energy conservation law we can say that when all conservative forces are present on the system then mechanical energy is always conserved
So here we have to choose all such options which will give conservative forces only
so correct answers are
A- electrostatic
C- magnetic
D- gravitational
A wire carries a 2a current. what is the current in a second wire that delivers twice as much charge in the same amount of time?
Answer:
4A
Explanation:
Current is charge per time. So if the second wire delivers twice as much charge in the same amount of time, it must have twice the current.
2 × 2A = 4A
The current in the second wire that delivers twice as much charge in the same amount of time is 4 amperes (4A).
How to determine the currentCurrent is defined as the rate of flow of electric charge, so if the first wire carries a 2A current, it delivers 2 coulombs of charge per second (1 A = 1 C/s).
To deliver twice as much charge in the same time, the second wire must deliver 4 coulombs of charge per second.
Therefore, its current is 4 amperes (4A) because it delivers 4C of charge per second, which is double the charge delivered by the first wire.
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A middle-age star that burns hydrogen is a A.neutron star B.white dwarf c.main sequence star D.pusar
A middle - aged star that burns hydrogen are called main sequence stars.
What is Star?Stars are huge celestial bodies made mostly of hydrogen and helium that produce light and heat from the churning nuclear forges inside their cores.
Given is a middle-age star that burns hydrogen.
A middle - aged star that burns hydrogen are called main sequence stars. These main sequence stars fuse hydrogen atoms which results in the formation of helium atoms in their cores. More than 90 percent of stars are main sequence stars. Our sun is also a main sequence star.
Therefore, a middle - aged star that burns hydrogen are called main sequence stars.
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A 650 × 10–4 F capacitor stores 24 × 10–3 of charge.
What is the potential difference between the plates?
a. 0.0016 V
b. 0.089 V
c. 0.37 V
d. 2.7 V
C. 0.37V. A capacitor of 650x10⁻⁴F that stores 24x10⁻³C has a potential difference of 0.37V between its plates.
The key to solve this problem is using the capacitance equation C = Q/Vᵃᵇ, where C is the capacitance, Q the charge stored in the plates, and Vᵃᵇ the potential difference between the plates.
A 650x10⁻⁴F capacitor stores 24x10⁻³C, clear Vᵃᵇ for the equation:
C = Q/Vᵃᵇ -----------> Vᵃᵇ = Q/C
Solving
Vᵃᵇ = 24x10⁻³C/650x10⁻⁴F = 0.37V
Answer:
c
Explanation:
edge
Are light waves longitudinal or transverse
Answer:
Transverse
Explanation:
There are two types of waves, depending on the direction of their oscillations:
- Transverse wave: in a transverse wave, the oscillation occurs in a direction perpendicular to the direction of propagation of the wave. Examples are electromagnetic waves
- Longitudinal wave: in a longitudinal wave, the oscillation occurs parallel to the direction of propagation of the wave. Examples are sound waves
Light waves are just the visible part of the electromagnetic spectrum, therefore they are electromagnetic waves, which consist of oscillations of electric and magnetic field in a direction perpendicular to the direction of propagation of the wave. Therefore, light waves are transverse waves.
When current is flowing in an ordinary metal wire, the magnitude of the average velocity of the electrons is closest toa) 10 m/sb) the speed of lightc) 10 microns/sd) 1 km/se) 1 m/s
Answer:
c) 10 microns/s
Explanation:
The drift velocity (the velocity of the current) of the electrons in a wire is given by
[tex]v=\frac{I}{nAq}[/tex]
where
I is the current
n is the electron number density (the number of electrons per unit volume)
A is the cross-sectional area of the wire
[tex]q=1.6\cdot 10^{-19} C[/tex] is the charge of one electron
Taking a current of
I = 1 A
in a wire of radius r = 1 mm (0.001 m), so with cross-sectional area
[tex]A=\pi r^2 = \pi (0.001 m)^2=3.14\cdot 10^{-6} m^2[/tex]
made of copper, whose electron density number is around
[tex]n=8.5\cdot 10^{28} m^{-3}[/tex]
we find
[tex]v=\frac{1 A}{(8.5\cdot 10^{28} m^{-3})(3.14\cdot 10^{-6} m^2)(1.6\cdot 10^{-19} C)}=2.34\cdot 10^{-5} m/s[/tex]
which means that the closest estimate is
c) 10 microns/s
Coherent light of wavelength 525 nm passes through two thin slits that are 4.15×10^(−2) mm apart and then falls on a screen 75.0 cm away.
Part AHow far away from the central bright fringe on the screen is the fifth bright fringe (not counting the central bright fringe)?y5= cm
Part BHow far away from the central bright fringe on the screen is the eighth dark fringe?y8= cm
This physics question involves the concepts of light interference and double-slit experiment. The formula Ym = m*λD/d is used to find the position of bright and dark fringes on a screen. The distances to the 5th bright fringe and 8th dark fringe were calculated as 4.7 cm and 7.6 cm respectively.
Explanation:The question involves the concept of interference of light, specifically as it pertains to a double-slit experiment. To find the distance from the central bright fringe to other fringes, you can use the formula for the path difference between two waves, given by Ym = m*λD/d, where:
Ym= fringe positionm= order of fringeλ= wavelength of lightD= distance of screen from slitsd= distance between two slitsPart A: For the 5th bright fringe, we use m=5 (not counting the central bright fringe). So, y5 = 5 * 525 × 10^-9 m * 75.0/4.15×10^-5 m = 0.047 m or 4.7 cm.
Part B: In the case of dark fringes, the formula changes a bit. For dark fringes, the path difference is given by (m+b)*λD/d , where b=1/2. So for the 8th dark fringe, m=8, and the formula becomes: y8 = (8+1/2) * 525 × 10^-9 m * 75.0/4.15×10^-5 m = 0.076 m or 7.6 cm.
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A collision between two large spiral galaxies is likely to produce
A large elliptical galaxy. Hope this helped
Final answer:
A collision between two spiral galaxies generally results in the creation of a single elliptical galaxy, involving gravitational interactions and often triggering new star formation. Through observations and simulations, we see this process unfold over very long time scales.
Explanation:
A collision between two large spiral galaxies is likely to result in the formation of a single, more massive elliptical galaxy. During such a collision, which is more accurately described as a 'merger', the gravitational forces between the stars and dark matter in each galaxy cause them to interact. While individual stars do not physically collide due to vast interstellar distances, the gas components of the galaxies can collide and trigger bursts of new star formation. This process can also give rise to phenomena such as starburst galaxies and active galactic nuclei (AGN), which can have a significant impact on the evolution of galaxies.
Galactic collisions are intricate, slow-moving interactions happening over timescales of hundreds of millions to a billion years. Through Hubble Space Telescope observations and computer simulations, we have been able to witness these awe-inspiring events, which provide insight into how galaxies evolve. For example, in a computer simulation of a collision between two spiral galaxies, one can see the transformation unfolding where two separate spirals gradually merge to form a single elliptical galaxy, marked by extensive star formation.
A technician fills a tank with a liquid to a height of 0.20 m. The tank is cylindrical with radius 0.10 m. The mass of the liquid is 1.0 kg. What is the density of the liquid in 160 kg/m3
Answer:
[tex]159.2 kg/m^3[/tex]
Explanation:
The mass of the liquid is
m = 1.0 kg
The volume of the cylindrical tank is given by
[tex]V=\pi r^2 h[/tex]
where
r = 0.10 m is the radius
h = 0.20 m is the heigth
Substituting,
[tex]V=\pi (0.10 m)^2 (0.20 m)=6.28\cdot 10^{-3}m^3[/tex]
So now we can find the density of the liquid:
[tex]\rho = \frac{m}{V}=\frac{1.0 kg}{6.28\cdot 10^{-3} m^3}=159.2 kg/m^3[/tex]
In a displacement versus time graph, what does the slope of a line at any point indicate?
acceleration
maximum displacement
minimum displacement
velocity
In a displacement versus time graph, the slope of the line at any point on the graph indicates the magnitude of velocity.
(It can't indicate velocity completely, because the graph shows nothing about the direction of the motion.)
In a displacement versus time graph, the slope of the line at any point on the graph indicates the magnitude of velocity.
What is velocity?Velocity is the time rate of change of displacement. The displacement and velocity both are vector quantities. They represent magnitude and direction as well.
velocity = change in displacement / change in time
v = ds/dt
So, the slope of line showing the graph of displacement vs time give s an idea of velocity of the particle.
Thus, the slope of the line at any point on the graph indicates the magnitude of velocity.
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What is the refractive index of a medium?
A. the ratio of the velocity of light in the medium over the velocity of light in a vacuum
B. the ratio of the velocity of light in a vacuum over the velocity of light in the medium
C. the ratio of the angle of incidence over the angle of refraction
D. the ratio of the angle of refraction over the angle of incidence
The refractive index is the speed of light in a vacuum over the speed of light in the medium.
The answer is B. the ratio of the velocity of light in a vacuum over the velocity of light in the medium
Answer: Option B: the ratio of the velocity of light in a vacuum over the velocity of light in the medium, n = c/v
Explanation:
When a wave of light enters in some materials, the velocity changes depending on the material, and this is why some times when light enters in something, for example, a glass of water, the "path" of the light changes (and you can see some cool visual effects)
then, we define the refractive index of a medium as:
n = c/v
where n is the refractive index, c is the velocity of the light in the vacuum and v is the velocity of the light in the material, here you can see that n is always greater or equal than 1 ( in the case n = 1, we also have v= c)
Then, the correct option is:
option B: the ratio of the velocity of light in a vacuum over the velocity of light in the medium
What is the largest object in the solar system
Answer: The largest object in the solar system would be the object in the middle because its mass bring smaller object into orbit. in our solar system that would be the Sun.
Explanation:
What name is given to the rate at which energy is transferred?
Answer:
Power
Explanation:
By definition, power is the rate of energy transfer from one system to another. It is measured in Watts or Joule per second. Power can also be defined as the rate work is done. It can also be calculated using the formula:
[tex]Power = \dfrac{Work}{Time}[/tex]
Power is the name given to the rate at which energy is transferred, and it's a fundamental concept in physics related to work and heat transfer.
Explanation:The name given to the rate at which energy is transferred is called power. This concept is central in the field of physics, especially when discussing mechanical or electrical systems where energy transfer can occur at varying rates. For example, when an external force is exerted on an object that causes it to move through a distance, the energy transferred in the process is known as work. The power of a system defines how quickly this work is done or how rapidly energy is transferred into, out of, or within the system.
The rate of heat transfer by emitted radiation can be described by the Stefan-Boltzmann law, which incorporates the surface area, temperature, and the Stefan-Boltzmann constant to calculate power. Common units of energy used in such calculations include the kilocalorie (kcal) and the joule (J).
Which of the following is the hottest part of the sun?
Convective zone
Inner core
Photosphere
Radiative zone
Answer:
Inner core
Explanation:
The hottest layer of the sun is its core
The hottest part of the sun in the solar system is the Inner core.
What is sun?Sun can be regarded as one of the star which is found around Earth.
This sun is part of the components of the solar system , and it consists of different layers such as the inner part which is the hottest as well as the radiative zone.
Therefore, the temperature of the inner core of the sun is approximately 27 million degrees F, which made it hotter than Photosphere as well as Convective zone.
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Two radio waves are used in the operation of a cellular telephone. To receive a call, the phone detects the wave emitted at one frequency by the transmitting station or base unit. To send your message to the base unit, your phone emits its own wave at a different frequency. The difference between these two frequencies is fixed for all channels of cell phone operation. Suppose the wavelength of the wave emitted by the base unit is 0.34394 m and the wavelength of the wave emitted by the phone is 0.36140 m. Using a value of 2.9979 108 m/s for the speed of light, determine the difference between the two frequencies used in the operation of a cell phone.
The difference between the two frequencies used in the operation of a cell phone is [tex]\( 1.224 \times 10^9 \) Hz.[/tex]
To calculate the difference between the frequencies, we first need to find the frequencies of the waves emitted by the base unit and the phone. We can use the formula [tex]\( v = f \times \lambda \)[/tex] , where [tex]\( v \)[/tex] is the speed of light, [tex]\( f \)[/tex] is the frequency, and [tex]\( \lambda \)[/tex] is the wavelength.
Given:
Speed of light, [tex]\( v = 2.9979 \times 10^8 \)[/tex] m/s
Wavelength of base unit, [tex]\( \lambda_{base} = 0.34394 \) m[/tex]
Wavelength of phone, [tex]\( \lambda_{phone} = 0.36140 \) m[/tex]
First, let's find the frequency of the wave emitted by the base unit:
[tex]\[ f_{base} = \frac{v}{\lambda_{base}} = \frac{2.9979 \times 10^8}{0.34394} \]\[ f_{base} = 8.720 \times 10^8 \text{ Hz} \][/tex]
Next, let's find the frequency of the wave emitted by the phone:
[tex]\[ f_{phone} = \frac{v}{\lambda_{phone}} = \frac{2.9979 \times 10^8}{0.36140} \]\[ f_{phone} = 8.288 \times 10^8 \text{ Hz} \][/tex]
Now, we can find the difference between the frequencies:
[tex]\[ \Delta f = |f_{base} - f_{phone}| = |8.720 \times 10^8 - 8.288 \times 10^8| \]\[ \Delta f = 1.224 \times 10^8 \text{ Hz} \][/tex]
So, the difference between the two frequencies used in the operation of a cell phone is [tex]\( 1.224 \times 10^8 \) Hz, or \( 122.4 \text{ MHz} \).[/tex]
Complete Question:
Two radio waves are used in the operation of a cellular telephone. To receive a call, the phone detects the wave emitted at one frequency by the transmitting station or base unit. To send your message to the base unit, your phone emits its own wave at a different frequency. The difference between these two frequencies is fixed for all channels of cell phone operation. Suppose the wavelength of the wave emitted by the base unit is 0.34394 m and the wavelength of the wave emitted by the phone is 0.36140 m. Using a value of 2.9979 108 m/s for the speed of light, determine the difference between the two frequencies used in the operation of a cell phone.
The frequency difference between the waves emitted by the base unit and the phone is calculated by determining each frequency and subtracting them. The resulting difference is 42.1 MHz.
Calculating the Frequency Difference for Cellular Phone Signals
To determine the difference in frequencies between the wave emitted by the base unit and the wave emitted by the phone, we use the relationship c = fλ, where c is the speed of light (2.9979 × 108 m/s), f is the frequency, and λ is the wavelength.
Step-by-Step Calculation
Step 1: Calculate the frequency of the wave emitted by the base unit.
[tex]f_{base} = c / \lambda_{base}\\f_{base} = 2.9979 × 10^8 m/s / 0.34394 = 8.714 \times 10^8 Hz[/tex]
Step 2: Calculate the frequency of the wave emitted by the phone.
[tex]f_{phone} = c / \lambda _{phone} \\f_{phone} = 2.9979 \times 10^8 m/s / 0.36140 = 8.293 \times 10^8 Hz[/tex]
Step 3: Find the difference between the two frequencies.
[tex]\Delta f = f_{base} - f_{phone} \\\Delta f = (8.714 \times 10^8 Hz) - (8.293 \times 10^8 Hz)\Delta f = 4.21 \times 10^7 Hz[/tex]
The difference between the two frequencies used in the operation of the cell phone is [tex]4.21 \times 10^7 Hz[/tex] or 42.1 MHz.
Determine the empirical formula of a compound containing 83% potassium and 17.0% oxygen.
The empirical formula of the compound containing 83% potassium and 17.0% oxygen is K2O.
Explanation:To determine the empirical formula of a compound containing 83% potassium and 17.0% oxygen, we need to convert these percentages into moles. Assuming we have 100g of the compound, we can calculate the moles of potassium and oxygen. The molar mass of potassium is 39.10 g/mol and the molar mass of oxygen is 16.00 g/mol.
So, the moles of potassium is 83g / 39.10 g/mol = 2.12 mol and the moles of oxygen is 17g / 16.00 g/mol = 1.06 mol.
Next, we divide the moles of each element by the smallest number of moles to get the simplest whole number ratio. In this case, the ratio is approximately 2 K: 1 O. Therefore, the empirical formula of the compound is K2O.
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The gas pressure inside a container decreases when
Answer:
When the volume increases or when the temperature decreases
Explanation:
The ideal gas equation states that:
[tex]pV= nRT[/tex]
where
p is the gas pressure
V is the volume
n is the number of moles of gas
R is the gas constant
T is the gas temperature
Assuming that we have a fixed amount of gas, so n is constant, we can rewrite the equation as
[tex]\frac{pV}{T}=const.[/tex]
which means the following:
- Pressure is inversely proportional to the volume: this means that the pressure decreases when the volume increases
- Pressure is directly proportional to the temperature: this means that the pressure decreases when the temperature decreases
The gas pressure inside a container can decrease due to a decrease in gas temperature, an increase in container volume, or the removal of gas particles from the container.
Explanation:The gas pressure inside a container can decrease due to several factors. The most common reasons include a decrease in the temperature of the gas, an increase in the volume of the container, or the removal of some gas particles from the container.
For example, if we take Charles's law into account which states that the volume of a gas is directly proportional to its temperature at constant pressure, so when the temperature decreases, the volume of the gas also decreases. Thus, the gas particles hit the container walls with less force and less frequently, which leads to a decrease in the pressure inside the container.
Similarly, according to Boyle's law, the pressure of a gas is inversely proportional to its volume at a constant temperature. So, when the volume of the container increases, the gas particles have more space to move around, thus they hit the container walls less frequently, resulting in lower pressure.
Lastly, if some of the gas particles are removed from the container, there would be fewer particles to exert force on the container walls, leading to a decrease in pressure.
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Which characteristic do all the planets in our solar system have in common?
Answer:
they all have the gravity.
Answer:
I believe they all have solid rocky surfaces. Hope this helps and good luck!
Explanation:
A dolphin jumps out of the water. As it falls back down it a clerated at a rate of -9,8m/s^2 for 0.8 seconds of free fall. To calculate how far the dolphin fell, what equation will you use?
Answer:
0.196 m
Explanation:
Given in the question that,
time taken by the dolphin to go back to water = 0.2 sec
To solve the question we will use Newton's Law of motion
S = ut + 0.5(a)t²here S is distance covered
u is initial speed
a = acceleration due to gravity
t = time taken
Plug value in the equation above
S = 0(0.2) + 0.5(-9.8)(0.2)²
S = 0.5(-9.8)(0.2)²
S = -0.196 m
Negative sign represent direction
(Assuming that dolphin have a vertical straight jump not a projectile motion)
The volume of a gas is reduced from 4 l to 0.5 l while the temperature is held constant. How does the gas pressure change?
Answer:
The pressure increases by a factor 8
Explanation:
For a gas held at constant temperature, Boyle's law can be applied. It states that the product of the gas pressure and the gas volume is constant, so we can write:
[tex]p_1 V_1 = p_2 V_2[/tex]
where
[tex]p_1[/tex] is the initial pressure
[tex]p_2[/tex] is the final pressure
[tex]V_1[/tex] is the initial volume
[tex]V_2[/tex] is the final volume
For the gas in this problem, the volume is reduced from
[tex]V_1 = 4 L[/tex]
to
[tex]V_2 = 0.5 L[/tex]
so we can rewrite the equation as
[tex]\frac{p_2}{p_1}=\frac{V_1}{V_2}=\frac{4 L}{0.5 L}=8[/tex]
this means that the pressure of the gas will increase by a factor 8.
A sample of iron has a volume of 10.0 mL. The density of iron is 7.87 g/mL. Which is the correct expression to calculate the mass of the sample using dimensional analysis? a. 10.0 mL x (7.87 g / 1 mL) b. 10.0 mL x (1 g / 7.87 mL) c. 10.0 mL x (1 mL / 7.87 g) d. 10.0 mL x (7.87 mL / 1 g)
Answer:
a. 10.0 mL x (7.87 g / 1 mL)
Explanation:
Mass is density times volume. Therefore:
m = 10.0 mL x (7.87 g / 1 mL)
A thin rod of length 1.3 m and mass 250 g is suspended freely from one end. It is pulled to one side and then allowed to swing like a pendulum, passing through its lowest position with angular speed 5.88 rad/s. Neglecting friction and air resistance, find (a) the rod's kinetic energy at its lowest position and (b) how far above that position the center of mass rises. (a) Number Enter your answer for part (a) in accordance to the question statement Units Choose the answer for part (a) from the menu in accordance to the question statement
(a) 2.42 J
The kinetic energy of a rotating object is given by:
[tex]K=\frac{1}{2}I \omega^2[/tex]
where
I is the moment of inertia
[tex]\omega[/tex] is the angular speed
Here we have
[tex]\omega=5.88 rad/s[/tex] at the lowest point of the trajectory
While the moment of inertia of a rod rotating around one end is
[tex]I=\frac{1}{3}ML^2 = \frac{1}{3}(0.250 kg)(1.3 m)^2=0.14 kg m^2[/tex]
And substituting in the previous formula, we find the kinetic energy at the lowest position:
[tex]K=\frac{1}{2}(0.14 kg m^2)(5.88 rad/s)^2=2.42 J[/tex]
(b) 0.99 m
According to the law of conservation of energy, the total mechanical energy (sum of kinetic energy and potential energy) must be conserved:
[tex]E=K+U[/tex]
At the lowest point, we can take the potential energy as zero, so the mechanical energy is just kinetic energy:
[tex]E=K=2.42 J[/tex]
At the highest point in the trajectory, the rod is stationary, so the kinetic energy will be zero, and the mechanical energy will simply be equal to the gravitational potential energy:
[tex]E=2.42 J = U = mgh[/tex]
where h is the heigth of the centre of mass of the rod with respect to the lowest point of the trajectory. Solving for h, we find
[tex]h=\frac{E}{mg}=\frac{2.42 J}{(0.250 kg)(9.81 m/s^2)}=0.99 m[/tex]