Choose the constant term that completes the perfect square trinomial x 2 - 18x

Let these there numbers be assigned to variables x, y and z. Since you want to find the sum, add all numbers. However, the sum has boundaries between 10 and 20. Therefore, you will have to use inequality symbols. The two addition equations that could be formulated are:

x+y+z > 10
x+y+z < 20

Final answer:

Shailen could have written two possible addition equations like 4 + 3 + 8 = 15 or 5 + 7 + 6 = 18. Both of these sum up to an even number between 10 and 20. Order of numbers doesn't matter in addition due to its commutative property.

Explanation:

The problem is asking for two possible addition problems that Shailen could be solving if his sum ends up being an even number between 10 and 20. This involves an understanding of the properties of addition and how different number combinations can result in an even sum.

Here are two possible addition equations that meet the conditions:

4 + 3 + 8 = 15

5 + 7 + 6 = 18

In both cases, the sums fall between 10 and 20 and are even. It's worth noting commutativity of addition, which says the order in which numbers are added doesn't change the sum. Hence, you can rearrange the numbers in the addition (e.g., 3 + 4 + 8 or 8 + 4 + 3) and the sum will still remain the same.

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The answer is D since 1/4 of the pineapple juice will give you the pinejuice

Answer: D

Step-by-step explanation: y costs less than p, only  1/4

as much. This translates to y =  1/4p or y =p/4.

Okay. We know that Center A charges $395 for an entire year. For Center B, there is a $25 sign up fee to pay one time, and then there is $15 monthly fee and $5 per aerobics class. There are 12 months in 1 year and 15 * 12 = 180. There are 52 weeks in 1 year, so 5 * 52 is 260. 260 + 180 + 25 = 465. He would pay $465 a year at Center B. Based off of the numbers, if Billy were to use a facility for only a year and go to aerobics once a week, then Center A is definitely cheaper than Center B. 

The Least expensive club for Billy to use for a year would be; Center B

What is the unitary method?

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Let just compare the cost of both the centers.

Cost of Center A:

One time charge of $495 in one complete year.

Cost of Center B:

Flat $25 dollar sign up fee

$15 per month, thus 15 x 12 = 180 dollars a year

$5 per aerobic class, so   5 x 52 = 260. dollars a year (given that Billy goes to class once a week)

There are 52 weeks in a year.

260 + 180 + 25 = 465  dollars

Hence, Center B would cost 30 dollars cheaper.

The Least expensive club for Billy to use for a year would be; Center B

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least 3/5, 0.65, 0.75, 7/8 greatest

Is it D?
I'm in middle school, so I'm not totally sure...

The recursive formula for the given AP series 2,5,8,11,14 is a₁ = 2 and [tex]a_{n} =a_{n-1} + 3[/tex] so option (D) will be correct.

What is Arithmetic progression?

The difference between every two successive terms in a sequence is the same this is known as an arithmetic progression (AP).

The arithmetic progression has wider use in mathematics for example sum of natural numbers.

Natural number = 1,2,3,4,5,6,7,8...

Now it has the same difference between any two consecutive terms d =2-1 = 3-2

Given an ap series,

2,5,8,11,14

The first term (a₁) = 2

The nth term of AP can be given as

[tex]a_{n} =a_{n-1} + d[/tex] where d is a common difference.

d = 5 - 2 = 3

So,

[tex]a_{n} =a_{n-1} + 3[/tex]

Hence "The recursive formula for the given AP series 2,5,8,11,14 is a₁ = 2 and [tex]a_{n} =a_{n-1} + 3[/tex] ".

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Hello!

First, let's write the problem.
[tex]9\le \:17-4x[/tex]
We are going to switch sides in order to have the x on the left side.
[tex]17-4x\ge \:9[/tex]
Subtract 17 from both sides.
[tex]17-4x-17\ge \:9-17[/tex]
[tex]-4x\ge \:-8[/tex]
We have two options, divide both sides by -4, or multiply both sides by -1 in order to reverse the inequality. Let's try the second option.
[tex]\left(-4x\right)\left(-1\right)\le\left(-8\right)\left(-1\right)[/tex]
[tex]4x\le \:8[/tex]
Divide both sides by 4.
[tex]\frac{4x}{4}\le \frac{8}{4}[/tex]

Our final answer would be,
[tex]x\le \:2[/tex]

You can feel free to let me know if you have any questions regarding this!
Thanks!

- TetraFish

1. slope = (n-k)/(m-j) 2. slope = (n-k))/(m-j) 3. P" = (m,n+e-3) 1. The slope of a line is the ratio between the change in y in regard to the change in x. Since we have two known points on the line r, we can simply subtract their respective x and y coordinates and divide. So slope = (n-k)/(m-j) One thing to pay attention to is to do the subtraction IN THE SAME ORDER. The actual order doesn't matter as long as it's the same for both top and bottom. For instance, this is another equation for the slope that's just as valid. slope = (k-n)/(j-m) 2. This is the exact same way. Just subtract the different y coordinates and divide by the difference between the x coordinates. slope=((n+e)-(k+e))/(m-j) Now because of the associative property, we can do some rearrangement of the expression to get slope=(n+e-k-e))/(m-j) and the "e" terms cancel each other, giving slope=(n-k))/(m-j) And you'll see that the slope is the same as for problem #1 above. 3. For this, let's look at the coordinates of point P' P' = (m,n+e) Since we want to move it 3 units down, just subtract 3 from the y coordinate, so P" = (m,n+e-3)

Given that in a national highway Traffic Safety Administration (NHTSA) report, data provided to the NHTSA by Goodyear stated that the mean tread life of a properly inflated automobile tires is 45,000 miles. Suppose that the current distribution of tread life of properly inflated automobile tires is normally distributed with mean of 45,000 miles and a standard deviation of 2360 miles.

Part A:

Find the probability that randomly selected automobile tire has a tread life between 42,000 and 46,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is between two numbers, a and b is given by:
[tex]P(a \ \textless \ X \ \textless \ b) = P(X \ \textless \ b) - P(X \ \textless \ a) \\ \\ P\left(z\ \textless \ \frac{b-\mu}{\sigma} \right)-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life between 42,000 and 46,000 miles is given by:
[tex]P(42,000 \ \textless \ X \ \textless \ 46,000) = P(X \ \textless \ 46,000) - P(X \ \textless \ 42,000) \\ \\ P\left(z\ \textless \ \frac{46,000-45,000}{2,360} \right)-P\left(z\ \textless \ \frac{42,000-45,000}{2,360} \right) \\ \\ =P(0.4237)-P(-1.271)=0.66412-0.10183=\bold{0.5623}[/tex]


b. Find the probability that randomly selected automobile tire has a tread life of more than 50,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is greater than a numbers, a, is given by:
[tex]P(X \ \textgreater \ a) = 1-P(X \ \textless \ a) \\ \\ =1-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life of more than 50,000 miles is given by:
[tex]P(X \ \textgreater \ 50,000) = 1 - P(X \ \textless \ 50,000) \\ \\ =1-P\left(z\ \textless \ \frac{50,000-45,000}{2,360} \right)=1-P(z\ \textless \ 2.1186) \\ \\ =1-0.98294=\bold{0.0171}[/tex]


Part C:

Find the probability that randomly selected automobile tire has a tread life of less than 38,000 miles.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is less than a numbers, a, is given by:
[tex]P(X \ \textless \ a) =P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles a standard deviation of 2360 miles.
The probability that randomly selected automobile tire has a tread life of less than 38,000 miles is given by:
[tex]P(X \ \textless \ 38,000) = P\left(z\ \textless \ \frac{38,000-45,000}{2,360} \right) \\ \\ =P(z\ \textless \ -2.966)=\bold{0.0015}[/tex]


d. Suppose that 6% of all automobile tires with the longest tread life have tread life of at least x miles. Find the value of x.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is greater than a numbers, x, is given by:
[tex]P(X \ \textgreater \ x) = 1-P(X \ \textless \ a) \\ \\ =1-P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles and a standard deviation of 2360 miles and that the probability that all automobile tires with the longest tread life have tread life of at least x miles is 6%.

Thus:
[tex]P(X \ \textgreater \ x) =0.06 \\ \\ \Rightarrow1 - P(X \ \textless \ x)=0.06 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=1-0.06=0.94 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=P(z\ \textless \ 1.555) \\ \\ \Rightarrow \frac{x-45,000}{2,360}=1.555 \\ \\ \Rightarrow x-45,000=2,360(1.555)=3,669.8 \\ \\ \Rightarrow x=3,669.8+45,000=48,669.8[/tex]
Therefore, the value of x is 48,669.8


e. Suppose that 2% of all automobile tires with the shortest tread life have tread life of at most x miles. Find the value of x.
The probability that a normally distributed data set with a mean, μ, and standard deviation, σ, is less than a numbers, x, is given by:
[tex]P(X \ \textless \ x) =P\left(z\ \textless \ \frac{a-\mu}{\sigma} \right)[/tex]
Given that the the mean tread life of a properly inflated automobile tires is 45,000 miles and a standard deviation of 2360 miles and that the probability that all automobile tires with the longest tread life have tread life of at most x miles is 2%.

Thus:
[tex]P(X \ \textless \ x)=0.02 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=1-0.02=0.98 \\ \\ \Rightarrow P\left(z\ \textless \ \frac{x-45,000}{2,360} \right)=P(z\ \textless \ 2.054) \\ \\ \Rightarrow \frac{x-45,000}{-2,360}=2.054 \\ \\ \Rightarrow x-45,000=-2,360(2.054)=-4,847.44 \\ \\ \Rightarrow x=-4,847.44+45,000=40,152.56[/tex]
Therefore, the value of x is 40,152.56

Answer:

→Number of people in the fitness club= 36 People

→Number of people who lifted weights [tex]=\frac{3}{8}\times 36=\frac{108}{8}[/tex]

→Number of people who did cross training [tex]=\frac{1}{3}\times 36=12[/tex]

=12 People

→Number of people who were running

 [tex]=1-\frac{3}{8}-\frac{1}{3}\\\\=\frac{24-9-8}{24}\\\\=\frac{7}{24}[/tex]

To determine the fraction of people running in the fitness studio, subtract the fractions of people lifting weights and doing cross training from the total, which comes to 7/24.

The fraction representing the number of people running can be found by adding the fractions of people lifting weights and doing cross training and subtracting that from the total, which gives the fraction of people running. Here's how:

Given: 3/8 lifting weights, 1/3 doing cross training, and the total is 1 (representing the whole).To find the fraction running: 1 - (3/8 + 1/3) = 1 - (9/24 + 8/24) = 1 - 17/24 = 7/24.

the answer is A 5(5^3/2/5)^2

5(5^3/2/5)^2

= 5 (125/2/5)^2


= 5 ( 125/2  x 1/5 ) ^2

= 5 ( 12.5) ^2 

= 5 x 156.25

= 781.25 >>>>>>>>>>>>>>>>>>>>>>>> Not equal to 125

= 

25%

3.24*.25= .81
3.24+.81=4.05

Answer:

percent increase = 25%

Step-by-step explanation:

The price of a gallon of milk has increased from $3.24 to $4.05

LEt x be the percentage increase

intitial cost + initial cost times percentage = new cost

[tex]3.24 + 3.24 (\frac{x}{100})= 4.05[/tex]

Subtract 3.24 from both sides

[tex]3.24 (\frac{x}{100})= 0.81[/tex]

divide by 3.24 on both sides

[tex](\frac{x}{100})= 0.25[/tex]

Multiply both sides by 100

x= 25 %

The point slope form of the line has the following form:

y – y1 = m (x – x1)

 

The slope m can be calculated using the formula:

m = (y2 – y1) / (x2 – x1)

m = (3 - 0) / (0 – 4) = - ¾

 

So the whole equation is:

y – 0 = - ¾ (x – 4)

y = - ¾ (x – 4) or

y = - 0.75 (x – 4)

Parameterize the line segment (call it [tex]C[/tex]) by

[tex]\mathbf r(t)=\langle0,0,1\rangle(1-t)+\langle2,1,0\rangle t=\langle2t,t,1-t\rangle[/tex]

where [tex]0\le t\le1[/tex]. Then the work done by [tex]\mathbf f(x,y,z)[/tex] along the line segment is

[tex]\displaystyle\int_C\mathbf f(x,y,z)\cdot\mathrm d\mathbf r=\int_{t=0}^{t=1}\mathbf f(x(t),y(t),z(t))\cdot\langle2,1,-1\rangle\,\mathrm dt[/tex]
[tex]=\displaystyle\int_0^1\langle2t-t^2,t-(1-t)^2,(1-t)-(2t)^2\rangle\cdot\langle2,1,-1\rangle\,\mathrm dt[/tex]
[tex]=\displaystyle\int_0^1(t^2+8t-2)\,\mathrm dt=\frac73[/tex]

$250. You would divide $1000 by 4 to get each 1/4 equaling $250, that would allow the dryer to be $750 which is 3x250, and 750+250 is 1000. So the washer is $750 and the dryer is $250

The washer is worth $750 the dryer is 150

It cost $1.77 more to park in A

To find your answer, simply subtract the smaller total from the larger.
5.52 - 3.75 = 1.77
It cost $1.77 more to park in parking lot A than it does to park in B.

51.25% is the answer for the problem

Answer:

48.75%

Step-by-step explanation:

If total number of people that voted = 240

Number of votes Garth got = 117

% vote he got = Number of Garth vote/Total number if vote ×100℅

% vote gotten by Garth = 117/240×100%

% vote gotten by Garth = 48.75%

The tomato is not picked because they do not need it nomore and that it only ways 4 ounces.

The decimal... lol  thats what mt grandmom told me

The decimal point without the decimal point there is no decimal at all. 
i hoped that works ill give you an example if you are still confused 

if you are trying to turn this number 89 into a decimal you would have to do 8.9 if you don't than  89 is just a number not a decimal if you forget the decimal you will more than likely get the question incorrect.

1/6 and 1/2. 

Multiply them together you get 1/12.

[tex] \frac{1}{3} (\frac{1}{4}) = \frac{1}{12} [/tex]

a. Brand G will end up costing $159.48 less than Brand F.

Answer:

a. Brand G will end up costing $159.48 less than Brand F.

Step-by-step explanation:

If you calculate the compound interest of paying the $650 barbecue to five years the cos would be around 1050 after paying the compound interests of 13.01% monthly, and when you calculate the cost of paying off a $200 over 3 years the cost of the three would be $898, so it would be cheaper to buy the three $200 barbecues over the spam of 15 years, that would be the answer.

24 is the result. 1/3 of 36 is 12 so you are subtracting 12 from 36.

 1/3=0.33 so then you do 36.00-0.33=35.67 

Hope i helped

Answer:

Option A.

Step-by-step explanation:

The original price of a television in a store = $250.00

The store is marking down the price of a television 25 percent from the original price.

25% = [tex]\frac{25}{100}[/tex] = 0.25

The expression can be used to find the marked down price

250 - ( 25% of 250)

= 250 - (0.25)(250)

Option A. is the answer.

check the picture below.

notice, the gift box is just 6 rectangles stacked up to each other at the edges,

left and right, two rectangles of 32x40

top and bottom, two rectangles of 25x32

front and back, two rectangles of 25x40

so, just get the area of all 6 rectangles, add them up, and that's the "surface area" of the rectangular prism, and that's how much paper will be needed to cover it.

red is most likely in the second situation because it is closer to a whole than the first.  i think

If the question asks, "in which situation is a car chosen at random most likely to be red?", then the answer is on the transporter lorry

Car Park: 4 red, 10 cars total, 40% are red.

Transporter Lorry: 3 red, 5 cars total, 60% are red

The area of a parallelogram, like a rectangle, is base times height. The base is 2 units. the height is 5 units, from y=3 to y=8
2 * 5 = 10
The area therefore, is A) 10 units.

10 units squared should be your answer

Let

q------> the number of quarters coins

d------> the number of dollars coins

we know that

[tex]1\ quarter=\$0.25[/tex]

[tex]q+d=22[/tex]

[tex]q=22-d[/tex] ------> equation A

[tex]0.25q+d=10.75[/tex] -----> equation B

substitute equation A in equation B

[tex]0.25[22-d]+d=10.75[/tex]

therefore

the answer is the option

[tex]0.25[22-d]+d=10.75[/tex]

An equation is formed when two equal expressions are equated together with the help of an equal sign '='. The correct option is C.

What is an equation?

An equation is formed when two equal expressions are equated together with the help of an equal sign '='.

Given that Giuliana has 22, quarters and dollar coins worth a total of $10.75.

Let the number of dollar coins be represented by d, while the number of quarter coins be represented by (22-d). Therefore, the sum of the total amount that is with Giuliana can be written as,

(1 x d) + (0.25 x (22-d)) = 10.75

d + 0.25(22-d) = 10.75

Hence, the equation can be used to find d, the number of dollar coins Giuliana has is 0.25d + 22 – d = 10.75.

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Convert 16 tenths into .16 so 
5 - .16 = 4.84

So your equation will be:

2(x+6) + 2(x+2) = 2(x+4) + 2(2x-2)

First, divide everything by 2

x+6+x+2 = x+4+2x-2

Then, combine like terms

2x+8 = 3x+2

Move the variables (the x's) to one side and the numbers to the other by subtracting 2x from one side and then 2 from the other

6 = 1x or 6 = x

Now that you know that x = 6, you go back to Earl's length and width equations

Length = x+2
Width = x+6

And plug in the value of x you got (6)

Length = 6+2 = 8
Width = 6+6 = 12

There are you answers! Hope this helped! (remember to add units, in this case the units are feet)

Hello there! You can do something like:
2/3 of a cake was sitting in the kitchen. You decide to eat 1/4 of it. How much of the whole cake did you eat?
Hope this helps you!

You made
2/3 batch of cookies but then you decided to give away
1/4 to some friends... How much did you give away?

2l+2w=100
2(w+20)+2w=100
2w+40+2w=100
4w+40=100
4w=60
w=15
l=w+20
l=15+20
Greatest length is 35ft.

Answer:

a) The greatest possible length is 35.

b) l = w + 20

Step-by-step explanation:

The farmer wants the length of the pen to be 20ft longer than the width. If we use w to represent the width. Then the length would be w + 20

The problem first ask us to find the greatest possible length considering the fencing will be no more than 100ft.

We know that the perimeter of a rectangular area is: 2l + 2w (where l is the length and w the width)

Therefore for the fencing we would need 2l + 2w ≤ 100.

We are going to substitute the values for l and w that we mentioned at the beginning and solve for w:

2l + 2w ≤ 100

2(w+20) +2w ≤ 100

2w + 40 +2w ≤ 100

4w ≤ 100 - 40

4w ≤60

w ≤ 15

Therefore the width has to be less or equal to 15.

Since the length is 20 ft longer than the width, the greatest possible length happens when the width has its greatest value.

So when w = 15, the length is 35 and this is the greatest possible length of it.

b) The expression that represents the length (as we said before) is w + 20