Cesar bought 2 bottles of juice that each hold 2 quarts and another bottle that hold 1 1/2 gallons of juice. How many quarts of juice did he buy?

Algebra Nation is an online educational platform that provides comprehensive resources and tutorials for learning algebra. Section 2 of Algebra Nation likely covers specific algebraic topics or concepts, such as equations, functions, expressions, or algebraic operations.

In this section, students may explore various algebraic principles and problem-solving techniques. Algebra Nation aims to make algebra more accessible and understandable for students, offering instructional videos, practice exercises, and opportunities for students to engage with algebraic concepts.

It's designed to support both teachers and students in their algebra education, fostering a deeper understanding of this critical branch of mathematics and helping students build a strong foundation for future mathematical endeavors.

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This question is not complete, Here I am attaching the complete question:

What key concepts or topics are covered in Algebra Nation Section 2, and how do these concepts relate to solving algebraic equations?

Answer:

it is true

Step-by-step explanation:

Move all terms not containing  

n

to the right side of the equation.

Tap for more steps...

−

5n= -12

Divide each term by  

-5

and simplify.

Tap for more steps...

n=12 5

The result can be shown in multiple forms.

Exact Form:

n=12 5

Decimal Form:

n=2.4

Mixed Number Form:

n=225

False. Correct equation: [tex]\(2n - 7 = -5\)[/tex]. Your proposed equation [tex]\(7 - 5n = -5\)[/tex] does not accurately represent the relationship.

The answer is False.

Here's why:

1. The statement "seven less than twice a number" can be represented as [tex]\( 2n - 7 \)[/tex], where [tex]\( n \)[/tex] is the number.

2. The equation for "seven less than twice a number is negative five" should be [tex]\( 2n - 7 = -5 \)[/tex], as the phrase "is negative five" translates to the equation being equal to [tex]\( -5 \)[/tex].

3. Your proposed equation, [tex]\( 7 - 5n = -5 \)[/tex], is incorrect because it represents a different relationship. It suggests that [tex]\( 7 \)[/tex] subtracted by [tex]\( 5n \)[/tex] is equal to [tex]\( -5 \)[/tex], which does not align with the given statement.

4. To correct the equation, simply rewrite it as [tex]\( 2n - 7 = -5 \)[/tex], which accurately represents the relationship described in the statement.

Therefore, the statement is false because the given equation does not correctly represent the phrase "seven less than twice a number is negative five."

Answer:

615.6

Step-by-step explanation:

First find the number of cubic feet.

V = B * h

B is a triangle with a right angle on your left and two 6 foot lengths on each leg.

Area = 1/2 b * h

b = 6 feet

h = 6 feet

Area = 1/2 * 6 * 6 = 18 square feet.

The volume = B * h

h = 11.4

B = 18 sq ft

Volume = 18 * 11.4

Volume = 205.2 Cubic Feet.

Each cubic foot costs 3.00 dollars

Cost = volume * cost/cu foot

Cost = 205.2 * 3

Cost = 615.6

Uhhh what are the coordinates of points X and Y? Please write in the comments so that I can help you.

Answer:

(2,-4)

Step-by-step explanation:

Use a variation of the midpoint formula : x = 1/4x1+3/4x2.

Also use this formula for the y coordinates as well.

For the x coordinate, you should get -5/2+9/2 which is 2.

For the y coordinate, you should get -1/4-15/4 which is -4.

Hope this helps.

Answer:

O

Step-by-step explanation:

Assuming you are asking for congruent parts, correspondence is the part which corresponds and is also equal.

Here Angle O is equal to Angle O as they are vertical angles across a vertex.

Answer:

The correct option is 2.

Step-by-step explanation:

From the given figure it is clear that the lines DE║RK, in triangle ODE and triangle OKR,

[tex]\angle DOE=\angle KOR[/tex]                         (Vertical opposite angles)

[tex]\angle ODE=\angle OKR[/tex]                         (Alternate interior angles)

[tex]\angle OED=\angle ORK[/tex]                         (Alternate interior angles)

By using AA property of similarity,

[tex]\triangle DOE\sim \triangle KOR[/tex]

D is correspondence to K, O is correspondence to O, E is correspondence to R.

O ↔ O

Therefore the correct option is 2.

Answer:

The answer is (d) ⇒ [tex]pq^{2}r\sqrt[3]{pr^{2}}[/tex]

Step-by-step explanation:

* To simplify the cube roots:

 If its number then the number must be written in the form x³

 then we divide the power by 3 to cancel the radical

 If its variable we divide its power by 3 to cancel the radical

∵ [tex]\sqrt[3]{p^{4}q^{6}r^{5}}=p^{\frac{4}{3}}q^{\frac{6}{3}}r^{\frac{5}{3}}}[/tex]

∴ [tex]p^{\frac{4}{3}}q^{2}}r^{\frac{5}{3}}=p^{1\frac{1}{3}}q^{2}r^{1\frac{2}{3}}[/tex]

∵ [tex]p^{\frac{1}{3}}=\sqrt[3]{p}[/tex]

∵ [tex]r^{\frac{2}{3}}=\sqrt[3]{r^{2}}[/tex]

∴ [tex]p(p)^{\frac{1}{3}}q^{2}r(r)^{\frac{2}{3}}=p(\sqrt[3]{p})q^{2}r(\sqrt[3]{r^{2}})[/tex]

∴ [tex]prq^{2}\sqrt[3]{pr^{2}}}[/tex]

∴ The answer is (d)

Answer: $13795

Step-by-step explanation: .89 x 15500

Answer :

27.5 minutes

Steps:

1) put into fraction form:

160/20 = 220/x

2) simplify:

160/20 = 8/1

3) cross multiply:

8 • x = 8x

220 • 1 = 220

4) divide on both sides:

8/8 = crosses out

220/8 = 27.5

Answer:

Not sure if this is the one you are looking for but

Which statement about the maximum wait time is correct?

The maximum wait time cannot be determined, but it is between 150 and 160 minutes.

The maximum wait time cannot be determined, but it is between 200 and 210 minutes.

The maximum wait time is 170 minutes.

The maximum wait time is 210 minutes.

B is the right answer

Step-by-step explanation:

edgy

Answer: Deanna has the higher mean score by .5

Step-by-step explanation: The important piece of information to remember here is that the mean is the average. In order to solve the question, the first thing that you need to do is calculate the average of each of their scores.

Deanna = 18+20+22+25+12+20 = 117

The mean = 117/6 = 19.5

Lilly = 20+20+21+21+16+16 = 114

The mean - 114/6 = 19

Answer:

Step-by-step explanation:

[tex]x^2+5x+4=0\\\\x^2+x+4x+4=0\\\\x(x+1)+4(x+1)=0\\\\(x+1)(x+4)=0\iff x+1=0\ \vee\ x+4=0\\\\x=-1\ \vee\ x=-4[/tex]

Answer:

-1

Step-by-step explanation:

Answer:

[tex]\large\boxed{x^2+y^2-10x+6y-47=0}[/tex]

Step-by-step explanation:

The equation of a circle:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

(h, k) - center

r - radius

We have the center (5, -3) and the radius r = 9.

Substitute:

[tex](x-5)^2+(y-(-3))^2=9^2\\\\(x-5)^2+(y+3)^2=81[/tex]

Use

[tex](a\pm b)^2=a^2\pm2ab+b^2[/tex]

[tex]x^2-2(x)(5)+5^2+y^2+2(y)(3)+3^2=81\\\\x^2-10x+25+y^2+6y+9=81\\\\x^2+y^2-10x+6y+(25+9)=81\\\\x^2+y^2-10x+6y+34=81\qquad\text{subtract 81 from both sides}\\\\x^2+y^2-10x+6y-47=0[/tex]

a,c,d are all correct

ANSWER

[tex]lim_{x \to \: 0}( {x}^{2} - 1) = - 1[/tex]

EXPLANATION

The given limit is

[tex] lim_{x \to \: 0}( {x}^{2} - 1) [/tex]

To evaluate this limit by direct substitution,

We put x=0 in the function.

This implies that that ,

[tex] lim_{x \to \: 0}( {x}^{2} - 1) = {0}^{2} - 1[/tex]

This simplifies to,

[tex] lim_{x \to \: 0}( {x}^{2} - 1) = 0 - 1[/tex]

[tex] lim_{x \to \: 0}( {x}^{2} - 1) = - 1[/tex]

This means that as x-values approach zero, the function approaches -1.

Answer:

-1

Step-by-step explanation:

For direct substitution, all you have to do is fill in the limit for x and solve... so the limit would be 0 in this case.

x^2-1

0^2-1

-1

Answer:

8 - 2x

Step-by-step explanation:

|2x -8| , x < 4

Two conditions:

(a) |2x - 8| =   (2x - 8) if (2x - 8) ≥ 0

(b) |2x - 8| = -(2x - 8) if (2x - 8) < 0

If x < 4, (2x - 8) <0, so condition (b) applies.

|2x - 8| = -(2x - 8) or

|2x - 8| = 8 - 2x

The equivalent expression is 8 - 2x.

Start with definition of absolute value, |x|.

It says,

|x| = x, for any x >= 0 and

|x| = -x, for any x < 0

Now, instead of x, we have the expression x+120 inside the absolute value brackets:

|x+120|

Play the same game as above - what is the absolute value here?

|x+120| = x+120 for (x+120)>=0 and

|x+120| = -(x+120) for (x+120)<0

Now, recognize that the last condition (x+120)<0 is the same as writing x<-120. That is the condition in the question. Therefore the absolute value |x+120| will equal the second expression (for that condition), namely -(x+120), or -x-120.

To simplify |x + 120| when x is less than -120, you change the sign of the expression inside the absolute value to get the simplified form as -x - 120.

To simplify |x + 120| when x < -120, we need to consider the definition of absolute value. The absolute value of a number is the non-negative value of that number without regard to its sign. Since x is less than -120, x + 120 is a negative number, and to find its absolute value, we change the sign to positive.

Therefore, the simplification of |x + 120| when x < -120 is simply -(x + 120), which equals -x - 120.

The answer is: mode

Mode can easily be remembered by saying “most” most=mode

Answer:

Step-by-step explanation:

The slope-intercept form:

y = mx + b

We have m = 2 and b = -4. Substitute:

y = 2x - 4

Answer:

x=12!

Step-by-step explanation:

Answer:

X=12

Step-by-step explanation:

[tex]\frac{2}{5}[/tex] = [tex]\frac{x}{30}[/tex]

cross multiply:

30 x 2 = 60

5 x x = 5x

and you get:

60=5x

x=12

plz give brainliestttt

Answer:

18

Step-by-step explanation:

Divide with by paratheses first. Use PEMDAS method

Answer:

36÷(6÷3) = 18

Step-by-step explanation:

First, you would solve what is in the parentheses.

36÷(6÷3) = 36÷(2)           Now, find 36÷2

               = 36÷2 = 18

so, 36÷(6÷3) = 18

Answer:

Last option: [tex]A=2\pi rh[/tex]

Step-by-step explanation:

 If  the shell of a bass drum was cut down one side and laid flat, the resulting shape would be a rectangle.

The area of a rectangle can be calculated with the formula:

[tex]A=l*w[/tex]

Where l is the lenght and w is the width.

In this case, the lenght of the rectangle obtained (the lenght of the shell)  is the circumference of the drum.

Remember that the circumference of the circle can be calculated with:

[tex]C=2\pi r[/tex]

Where r is the radius of the circle.

Then:

[tex]l=2\pi r[/tex]

The width is the height of the shell:

[tex]w=h[/tex]

Then, substituting into [tex]A=l*w[/tex], you get:

[tex]A=2\pi rh[/tex]

Answer:

Perpendicular

Step-by-step explanation:

The answer is 3x²

It’s actually pretty easy. If you have to like terms (in this case, they both have x²) then you just add the number in the front, or the coefficients! If it doesn’t have a number at the front ALWAYS assume it’s one.

2+1=3

2x²+(1)x²=3x²

The value of 2x² plus x² is; 3x².

According to the question;

The polynomial to be added are;

Hence;

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The answer is Undefined

Answer:

undefined

Step-by-step explanation:

The y-axis is a vertical line.

The point [tex](0,y_1)[/tex] and[tex](0,y_2)[/tex] lies on the y-axis.

The slope of this line is

[tex]=\frac{y_2-y_1}{0-0}[/tex]

[tex]=\frac{y_2-y_1}{0}[/tex]

Division by zero is undefined.

All vertical lines have undefined slopes because they are parallel to the y-axis.

Therefore the slope of m is undefined.

50x2=x

50 represents the red candies.

2 represents the other half of candies.

x represents the total amount of candies.

Hope this helps!

The equation representing the total number of candies in Meghan's jar, where x is the total, is x/2 = 50, giving us 100 candies in total. For Jenny's chocolates, Jenny initially had 14 chocolates before she ate two and gave half of the remaining to Lisa.

If Meghan discovered that half of the candies were red and she had 50 red candies, then to find the equation representing the total number of candies in the jar, we assign x to represent the total number. Since half of x is 50, the equation is x/2 = 50. To find x, we multiply both sides of the equation by 2, resulting in x = 100. Therefore, Meghan has 100 candies in total in her jar.

To address the question about Jenny and her chocolates: Initially, Jenny has some number of chocolates. When she eats two chocolates and gives half of the remainder to Lisa, and Lisa ends up with six chocolates, we can determine how many Jenny started with. Lisa's six chocolates represent half of what remained after Jenny ate two, which implies there were 12 before giving to Lisa, and so initially, Jenny had 14 chocolates.

Answer:

A= 12.56

Step-by-step explanation:

A= 3.14 x r^2

A= 3.14 x 2^2

The number of angles that are alternate exterior angles with angle 5 is equal to 1.

In Mathematics,  parallel lines are two lines that are cut through by a transversal and they always have the same (equal) distance apart and never meet.

In Mathematics, the alternate exterior angle theorem states that when two (2) parallel lines are cut through by a transversal, the alternate exterior angles that are formed lie outside the two (2) parallel lines, are located on opposite sides of the transversal, and are congruent angles.

In conclusion, we can logically deduce that both m∠5 and m∠11 are alternate exterior angles because they lie outside the two (2) parallel lines and are located on opposite sides of the transversal.

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Answer:

Step-by-step explanation:

The following have 3 significant figures:  85.3, 121.

The following have more or fewer significant figures than 3:  36.05, 50

Answer:

y = 15

x = 59

Step-by-step explanation:

move the -3 over to the -12 side. then divide by -1 on both sides getting:

{ y = 15

{ x- 3y = 14

change the y in the second equation to get:

x - 3 (15) = 14

x - 45 = 14

  +45 = +45

x = 59

hope this helps!!

Answer:

Part 1) [tex]a^{b+2}=(x)(a^{2})[/tex]

Part 2) [tex]2a^{3b}+a^{2b}+a^{b}=2x^{3}+x^{2}+x[/tex]

Step-by-step explanation:

Part 1) Given that [tex]a^{b}=x[/tex] evaluate the following

[tex]a^{b+2}[/tex]

we know that

[tex]a^{b+2}=(a^{b})(a^{2})[/tex]

Remember that when multiplying two powers that have the same base, you can add the exponents

[tex]a^{b}=x[/tex]

so

substitute

[tex]a^{b+2}=(x)(a^{2})[/tex]

Part 2) Given that [tex]a^{b}=x[/tex] evaluate the following

[tex]2a^{3b}+a^{2b}+a^{b}[/tex]

we know that

[tex]2a^{3b}+a^{2b}+a^{b}=2(a^{b})^{3}+(a^{b})^{2}+a^{b}[/tex]

Remember that

[tex]a^{b}=x[/tex]

so

substitute

[tex]2a^{3b}+a^{2b}+a^{b}=2x^{3}+x^{2}+x[/tex]