Carroll bikes 1 kilometer east, 4 kilometers north, and then 5 kilometers east again. How far is Carroll from her starting position, to the nearest tenth of a kilometer?

If no students attend the play, then 8 adults can see the play for $80.

The subject of this question is Mathematics, specifically linear equations. The scenario presented involves ticket sales for a school play with different ticket prices for students and adults. $7 is the price for a student ticket and $10 is for an adult ticket. The given equation 7x+10y=80 represents the total sum of $80 that needs to be reached with a combination of student tickets (x) and adult tickets (y).

If no students attend, x in the equation is 0, so we have 10y = 80. To find the number of adults (y) that can attend the play for $80, we need to solve this equation for y. So, y = 80 / 10. Therefore, y = 8, meaning 8 adults can attend the play for $80 when no students attend.

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Final answer:

The sequence ln(2n² +1) - ln(n² +1) simplifies to ln[(2n² + 1)/(n² + 1)]. As n approaches infinity, the sequence converges and the limit is ln(2).

Explanation:

To determine whether the sequence ln(2n² +1) - ln(n² +1) converges or diverges, we can use the properties of logarithms and limits.

First, we rewrite the expression using the property of logarithms that ln(a) - ln(b) = ln(a/b).

Our sequence then becomes ln[(2n² + 1)/(n² + 1)]

As n approaches infinity, the terms 2n² and n² dominate the behavior of the sequence.

Thus, the sequence can be approximated by ln(2n²/n²), which simplifies to ln(2).

Since ln(2) is a constant, we can conclude that the sequence converges and the limit is ln(2).

Answer:

[tex]\frac{2}{5}[/tex]

Step-by-step explanation:

The ratio is hot dogs to chicken the chicken isten tho to find the hot dogs first you do

10+6=16

So it says 20 members so then you needa see how much would equal the amont 20 obviously 4 so the hot dogs equal to 4 so the ratio is 4:10

Answer:

2/5

Step-by-step explanation:

just did it and it is correct

Answer:

(C) Triangles BPA and DPC are congruent.

Step-by-step explanation:

It is given that In quadrilateral ABCD, diagonals AC and BD bisect one another.

We have to prove that quadrilateral ABCD is a parallelogram.

(A) The given statement is:

Angles ABC and BCD are congruent

The above statement is not correct because these angles forms the corresponding angle pair and thus are not congruent.

Hence, this option is not correct.

(B) The given statement is:

Sides AB and BC are congruent.

The above statement is not correct because the given sides are formed by the same vertex and thus cannot be equal.

Hence, this option is not correct.

(C) The given statement is:

Triangles BPA and DPC are congruent.

The above statement is correct because the given triangles are congruent by the SAS rule of congruency.

Hence, this option is correct.

(D) The given statement is:

Triangles BCP and CDP are congruent.

the above statement is  not correct because the given triangles cannot be congruent using any rule of congruency,

Hence, this option is not correct.

Answer is provided in the image attached.

Robbin needs a GPA of at least 2.5 to be unconditionally accepted into the graduate program.

To determine the undergraduate grade point average (GPA) Robbin must have to be unconditionally accepted into the program, we can set up an equation based on the information given. The criterion for acceptance is that the GMAT score plus 400 times the GPA must be at least 1800. Robbin's GMAT score is 800, so we can use the following equation:

800 + 400(GPA) ≥ 1800

We can then isolate the GPA:

400(GPA) ≥ 1800 - 800
400(GPA) ≥ 1000
GPA ≥ 1000 / 400
GPA ≥ 2.5

When a vertical line passes through the graph of a function, it will intersect the graph at only one point. More than one point on any given vertical line means that the same x is being paired with 2 different y's and that make the graph not a function.

Please rate and thank : )

And btw copying and pasting is plagiarism

Hey there!

Good luck on your assignment and enjoy your day!

~[tex]\frak{LoveYourselfFirst:)}[/tex]

To find out how many 15-window coverings are needed for 50 windows, divide 50 by 15, which gives approximately 3.33. Rounding up because we can't have partial window coverings, we will need 4 coverings.

The question asks: How many window coverings are necessary to span 50 windows if each window covering is 15 windows long?

To answer this question, we can do a simple division. We divide the total number of windows (50) by the length of each window covering (15).

So, we have 50 ÷ 15 which equals approximately 3.33. However, since we cannot have a fraction of a window covering, we need to round this number up. Therefore, we would need 4 window coverings to span 50 windows.

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Answer:

P(x)=  x³ - 3 x² - 46 x +168

Step-by-step explanation:

given roots of the polynomial are given as    (4,6, -7)

hence the polynomial will be equal to

P(x) = (x-4) (x-6) (x+7)

P(x) = (x-4) (x²+7 x -6 x -42)

P(x) = (x-4) (x²+x -42)

P(x) = x³ + x²-42 x -4 x² -4 x +168

P(x) =  x³ - 3 x² - 46 x +168

hence, the required polynomial is P(x) =  x³ - 3 x² - 46 x +168

To calculate the probability that a windscreen wiper lasts for a time not within 1.7 years of the mean, one must find the corresponding z-scores and use a standard normal distribution table. The probability is approximately 39.58%.

To find the probability that a windscreen wiper lasts for a time that is not within 1.7 years of the mean lifetime of three years, we can use the properties of the normal distribution. We are given a mean (μ) of 3 years and a standard deviation (σ) of 2 years. We are interested in the probability that a wiper lasts less than 1.3 years (3 - 1.7) or more than 4.7 years (3 + 1.7).

First, we need to calculate the z-scores for 1.3 and 4.7 years:

Z1 = (1.3 - 3) / 2 = -0.85

Z2 = (4.7 - 3) / 2 = 0.85

Using a standard normal distribution table or a calculator, we find the probabilities corresponding to these z-scores. The probability of a wiper lasting less than 1.3 years is P(Z < -0.85), and the probability of lasting more than 4.7 years is P(Z > 0.85).

Since the normal distribution is symmetric, P(Z < -0.85) is equal to P(Z > 0.85). Thus, we only need to calculate one of these probabilities and double it to find the total probability. Let's say P(Z > 0.85) = p, then the total probability is 2p.

Assuming P(Z > 0.85) = 0.1979 (from standard normal distribution tables), the total probability is:

Probability = 2 * 0.1979 = 0.3958

Therefore, the probability that a windscreen wiper lasts for a time not within 1.7 years of the mean lifetime is approximately 0.3958 or 39.58%.

Final answer:

By standardizing the values and using a standard normal distribution table, we can find the probability to be approximately 0.7422 or 74.22%.

Explanation:

To solve this problem, we can use the normal distribution. Given that the mean lifetime of the windscreen wipers is 3 years with a standard deviation of 2 years, we want to find the probability that the wiper lasts for a time that is not within 1.7 years of the mean lifetime.

First, we need to standardize the values by calculating the z-scores.

The z-score formula is (x - mean) / standard deviation. In this case, we have x = 1.7, mean = 3, and standard deviation = 2.

Plugging in these values, we get a z-score of -0.65.

Using a standard normal distribution table or calculator, we can find the probability corresponding to a z-score of -0.65.

The area under the curve to the left of -0.65 is approximately 0.2578. Since we want the probability that the wiper lasts for a time that is not within 1.7 years of the mean, we subtract this probability from 1.

Therefore, the probability is approximately 1 - 0.2578 = 0.7422, or 74.22%.

Answer:

3/5

Step-by-step explanation:

i am doing the same thing right now and got it right

The limit does not exist for this expression.

To evaluate the limit as h approaches 0 of (sin(pi/6 + h) - sin(pi/6))/h, we can use the limit definition of the derivative of sin(x).

The derivative of sin(x) is cos(x), so we can rewrite the expression as:

lim h->0 (cos(pi/6 + h) - cos(pi/6))/h

Now, we can use the limit definition of the derivative to evaluate this limit. The derivative of cos(x) is -sin(x), so we have:

lim h->0 (-sin(pi/6 + h))/h

Now, let's substitute h = 0 into the expression:

(-sin(pi/6 + 0))/0

Since sin(pi/6) = 1/2, we have:

(-1/2)/0

However, division by zero is undefined. Therefore, the limit does not exist for this expression.

we have

[tex] y=\frac{2}{3} x+1 [/tex] ----------> equation [tex] 1 [/tex]

[tex] y=-\frac{2}{3} x-1 [/tex] ----------> equation [tex] 2 [/tex]

using a graph tool

we know that

the intersection point of both lines is the solution of the system

so

the solution is the point [tex] (-1.5,0) [/tex]

see the attached figure

therefore

the answer is

The solution of the system is the point [tex] (-1.5,0) [/tex]

The graph in the attached figure

Answer:

A rectangle has a width that is 7 centimeters less than its length, and its area is 330 square centimeters. What are the dimensions of the rectangle?

length =  

22

centimeters

width =  

15

centimeters

Answer:

18.4 ft

Step-by-step explanation:

Use Pythagorean Theorem: a^2+b^2=c^2

17^2+7^2=c^2

sqrt 338=sqrt c^2

(sqrt and power 2 cancel)

sqrt 338=c

sqrt 338= 18.4 ft

The dimensions of the box for minimal surface area when volume is 12 are both the cube root of 3. When surface area is 20 for minimal volume, the dimensions are sqrt(5) for the base and (15 / (4*sqrt(5))) for the height.

The concept in this problem is about minimizing surface area and volume with relation to the dimensions of a box.

Let's consider a box with a square base of side 'x' and height 'h'. For part (a), the volume V of a box is given by V = x^2 * h which implies h = V / (x^2).

Substituting V = 12, we get h = 12/x^2. The surface area S of a box is given by S = x^2 + 4xh.

Substituting the value of h in the surface area equation, we have S = x^2 + 48/x.

To find the minimum surface area, we differentiate the above with respect to 'x' and set it equal to 0, which gives the dimensions of the box to be x = h = cube root of 3.

For part (b), the surface area S is given to be 20. So, S = x^2 + 4xh implies 4xh = 20 - x^2. The volume of the box is V = x^2 * h = (20 - x^2) / 4.

To minimize the volume, we differentiate V with respect to 'x' and set it to 0. That gives us the value of 'x' to be sqrt(5), and 'h' to be (20 - 5) / (4*sqrt(5))

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The correct option is option C that is the solution of the inequality is 2.

What are inequalities ?

When two values are compared , an inequality represents whether one is greater than, less than, or not equal to the other.

It is given that an inequality is given y > 1.9. Here , y is a number which can be anything greater than 1.9.

Let's check which of the given options is a solution for the given inequality.

A)

-9 is a negative number whereas 1.9 is a positive number , so - 9 is not a solution to given inequality.

B)

-2 is also less than 1.9 , so this also not a solution to given inequality.

C)

2 is greater than 1.9 and it is a suitable solution to the given inequality. So , 2 is a solution of given inequality.

D)

As per the question value of y should be greater than 1.9 and not equal to 1.9 . So , this is also not a solution to given inequality.

Therefore , the correct option is option C that is the solution of the inequality is 2.

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Final answer:

To reach a height of 8 feet on the wall, Benton would need to use a ladder length of approximately 4.8 feet.

Explanation:

To determine which ladder length Benton would need to use to reach the desired height of 8 feet on the wall, we can use the concept of similar triangles. The distance from the base of the ladder to the wall is 6 feet and the height Benton wants to reach on the wall is 8 feet. Let x represent the length of the ladder needed. Using the properties of similar triangles, we can set up the following proportion:

(x)/(6) = (8)/(10)

Cross multiplying gives us:

x = (6 * 8) / 10 = 4.8

Therefore, Benton would need to use a ladder length of approximately 4.8 feet to reach a height of 8 feet on the wall. Since this length is not among the options provided, the correct answer is C. None of these ladder lengths would reach this height.