Cable Strength: A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the cable can hold. The weight limit will be reported on cable packaging. The engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb. Using the sample information as given, construct a confidence interval for the mean breaking strength of the new steel cable.

Answers

Answer 1

Answer:

95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].

Step-by-step explanation:

We are given that the engineers take a random sample of 45 cables and apply weights to each of them until they break. The mean breaking weight for the 45 cables is 768.2 lb. The standard deviation of the breaking weight for the sample is 15.1 lb.

Since, in the question it is not specified that how much confidence interval has be constructed; so we assume to be constructing of 95% confidence interval.

Firstly, the Pivotal quantity for 95% confidence interval for the population mean is given by;

                            P.Q. =  [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex]  ~ [tex]t_n_-_1[/tex]

where, [tex]\bar X[/tex] = sample mean breaking weight = 768.2 lb

            s = sample standard deviation = 15.1 lb

            n = sample of cables = 45

            [tex]\mu[/tex] = population mean breaking strength

Here for constructing 95% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.

So, 95% confidence interval for the population mean, [tex]\mu[/tex] is ;

P(-2.02 < [tex]t_4_4[/tex] < 2.02) = 0.95  {As the critical value of t at 44 degree

                                           of freedom are -2.02 & 2.02 with P = 2.5%}  

P(-2.02 < [tex]\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }[/tex] < 2.02) = 0.95

P( [tex]-2.02 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]{\bar X-\mu}[/tex] < [tex]2.02 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

P( [tex]\bar X-2.02 \times {\frac{s}{\sqrt{n} } }[/tex] < [tex]\mu[/tex] < [tex]\bar X+2.02 \times {\frac{s}{\sqrt{n} } }[/tex] ) = 0.95

95% confidence interval for [tex]\mu[/tex] = [ [tex]\bar X-2.02 \times {\frac{s}{\sqrt{n} } }[/tex] , [tex]\bar X+2.02 \times {\frac{s}{\sqrt{n} } }[/tex] ]

                                     = [ [tex]768.2-2.02 \times {\frac{15.1}{\sqrt{45} } }[/tex] , [tex]768.2+2.02 \times {\frac{15.1}{\sqrt{45} } }[/tex] ]

                                     = [763.65 lb , 772.75 lb]

Therefore, 95% confidence interval for the mean breaking strength of the new steel cable is [763.65 lb , 772.75 lb].


Related Questions

actual times in seconds recorded when statistics students participated in a experiment to test their ability to determine when one minute had passed 53, 52, 75, 62, 68, 58, 49, 49

Answers

Answer:

Step-by-step explanation:

Hello!

To study time perception, 8 students measured one minute (counted to 60), the given data show the actual time (in seconds) it took each student to measure one minute:

53, 52, 75, 62, 68, 58, 49, 49

8 observations make this sample, n=8

You can summarize the observed data using descriptive statistics:

Central tendency measures:

Median (Me):

The median is the value that separates the sample in a half ( the bottom 50% from the top 50%). To calculate it you have to calculate its position:

(for even samples) PosMe: n/2= 8/2= 4

Then you arrange the data from least to greatest and identify the 4th value:

49, 49, 52, 53, 58, 62, 68, 75

Me= 53s

Mode (Md):

The mode is the most observed value, i.e. the value with the most absolute frequency:

In this data set, the only value that was observed more than once is 49, so that is the value of the mode

Md= 49s

Mean (X[bar]):

Is the average or expected value of the data set, it is always within the range of definition of the variable but it doesn't necessarily correspond to and observation. You calculate it as:

X[bar]= ∑X/n= (53+52+75+62+68+58+49+49)/8= 466/8= 58.25s

Measures of dispersion:

Range (R):

The is the difference between the minimum and maximum observations of the sample.

R= max - min = 75 - 49= 26s

Standard deviation (S):

It shows the variability between the values of the sample. A low standard deviation tells that the observations are close to the meanwhile a high standard deviation show that the values are further away from the mean.

∑X= 466

∑X²= 27772

[tex]S= \sqrt{(\frac{1}{n-1})[sumX^2-\frac{(sumX)^2}{n} ]= \sqrt{(\frac{1}{7} )[27772-\frac{(466)^2}{8} ]} = \sqrt{\frac{1255}{14} } = 9.47s[/tex]

S= 9.47s

I hope this helps!

Results of a poll of a random sample of 3003 American adults showed that 20% do not know that caffeine contributes to dehydration. The poll was conducted for the Nutrition Information Center and had a margin of error of ± 1.4%. (a) Does the margin of error take into account any problems with the wording of the survey question, interviewer errors, bias from sequence of questions, and so forth?

Answers

Answer:

Check the explanation

Step-by-step explanation:

The margin of error does not take into account any problems with the wording of the survey question, interview errors, bias from sequence of questions, and so forth.

The margin of error reflects the difference between p(sample proportion) and P(Population proportion).

The margin of error addresses sampling variability and does not cover errors from survey design or administration flaws. Issues like question wording or interviewer bias are separate from sampling error. These design-related problems are not included in the margin of error.

The margin of error in a poll typically accounts for the natural variability that comes from sampling a subset of the population, rather than the entire population. This means it does not include errors that may arise from problems such as the wording of the survey question, interview errors, or bias from the sequence of questions. These issues are related to the design and administration of the survey and not the sampling process, so they are not reflected in the reported margin of error.

What is the area of the sector, in square units, determined by an arc with a measure 45° in a circle with radius 6? Round to the nearest tenth

Answers

Answer:

14.1 u^2

Step-by-step explanation:

A=pi*6^2*45/360=3.14*36*45/360=3.14*45/10≈14.1

A company has a policy of retiring company cars; this policy looks at number of miles driven, purpose of trips, style of car and other features. The distribution of the number of months in service for the fleet of cars is bell-shaped and has a mean of 64 months and a standard deviation of 5 months. Using the empirical rule, what is the approximate percentage of cars that remain in service between 69 and 74 months?

Answers

Answer:

By the Empirical Rule, the approximate percentage of cars that remain in service between 69 and 74 months is 13.5%.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 64

Standard deviation = 5.

Using the empirical rule, what is the approximate percentage of cars that remain in service between 69 and 74 months?

69 = 64 + 1*5

So 69 is one standard deviation above the mean.

74 = 64 + 2*5

So 74 is two standard deviations above the mean.

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

This means that:

95 - 68 = 27% between 1 and 2 standard deviations of the mean.

The normal distribution is symmetric, which means that 27/2 = 13.5% of those are below the mean(within 1 and 2 standard deviations below the mean) and 13.5% of those are above the mean(between 69 and 74).

So

By the Empirical Rule, the approximate percentage of cars that remain in service between 69 and 74 months is 13.5%.

HELP PLZZZ

Which of the following quadrilaterals are always parallelograms? Select all that apply. square rhombus trapezoid rectangle

Answers

Answer:

A square

Step-by-step explanation: A square is a parallelogram. This is always true. Squares are quadrilaterals with 4 congruent sides and 4 right angles, and they also have two sets of parallel sides.

Answer:

I think it is the parallelograms and square

Step-by-step explanation:

because they never intersect they stay the length apart

Verify that the diferential equation

(5x + 4y)dx + (4x − 8y^3)dy = 0

is exact and find its solution curves.

Answers

Answer:

The answer is  " [tex]C= \frac{5}{2x^2}+ 4xy - 2y^4.[/tex]"

Step-by-step explanation:

It given that, [tex]\frac {\partial(5x + 4y)}{\partial y} = \frac{\partial(4x- 8y^3)} {\partial x} \\\\[/tex] it is the differential equation.

Solve the above equation.

[tex]\frac {\partial M (x, y)}{\partial y} = (5x+ 4y)[/tex]

So, [tex]M (x, y) = \frac{5}{2x^2}+4xy +\varphi (y).[/tex]

[tex]\frac{\partial M (x, y)}{ \partial y }= 4x- 8y^3 \ and \ \ 4x + \varphi ' (y) = 4x- 8y^3 \\\\\ so, \ \\varphi ' (y) = -8y^3[/tex]

or [tex]\varphi (y) = -2y^4+c[/tex]

To find the general solution

[tex]M(x, y )= c \\C= \frac{5}{2x^2}+ 4xy - 2y^4.[/tex]

What fractions are not equivalent to 7/8

Answers

Final answer:

Fractions not equivalent to 7/8 are those that do not share the same 7 to 8 ratio when simplified. Multiplying by the reciprocal is key to understanding fraction division, and it is important to comprehend fraction operations for proficiency in mathematics. Educational systems need to improve the teaching of fractions, as evidenced by standardized test results.

Explanation:

The fractions that are not equivalent to 7/8 are any fractions where the numerator and denominator do not have the same ratio as 7 to 8. For example, the fraction 14/16 is equivalent to 7/8 because if you divide both 14 and 16 by the same number, which is 2, you will get 7/8. However, fractions like 1/2, 6/8, or 9/10 are not equivalent to 7/8. To determine if fractions are equivalent, you can simplify them to their lowest terms or cross-multiply to compare ratios.

Turning to common misconceptions about fractions, remember that multiplication and division are intimately linked: dividing by 8 is the same as multiplying by its reciprocal (1/8), and vice versa. Understanding this concept helps to build a strong foundation for working with fractions. Furthermore, not all fractions of a total are equal, and understanding the mechanics of adding, subtracting, multiplying, and dividing fractions is essential for developing proficiency in mathematics.

As illustrated in the example with 1,000 and 1/8, recognizing the patterns and relationships between fractions and other numbers aids in solving problems quickly and accurately. Educational systems evidently need to better equip students with these essential skills for handling fractions and percentages, as highlighted by the results of the High School Exit Exam.

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Fractions that are not equivalent to 7/8 include 3/4, 1/2, 2/3, 1/3, and 1/5. These fractions represent different values when simplified.

To determine which fractions are not equivalent to 7/8, we need to understand the concept of equivalent fractions. Two fractions are equivalent if they represent the same part of a whole even if their numerators and denominators are different.

For example, 14/16 is an equivalent fraction to 7/8 because if you simplify 14/16, you divide both the numerator and the denominator by 2, which equals 7/8. However, some fractions that are not equivalent to 7/8 include:

3/41/22/31/31/5

These fractions do not simplify to 7/8 and therefore represent different values.

Solve the logarthmic equation. 2 log3(x + 4) - log39 = 2

Answers

Answer:

5

Step-by-step explanation:

2 log₃(x + 4) − log₃9 = 2

2 log₃(x + 4) − log₃3² = 2

2 log₃(x + 4) − 2 = 2

2 log₃(x + 4) = 4

log₃(x + 4) = 2

3^(log₃(x + 4)) = 3^2

x + 4 = 9

x = 5

The solutions to the logarithmic equation 2 log₃(x + 4) - log₃(9) = 2 are x = 5 and x = -13.

To solve the logarithmic equation 2 log₃(x + 4) - log₃(9) = 2, we can use logarithmic properties to simplify the equation and then solve for x.

First, let's apply the properties of logarithms:

2 log₃(x + 4) - log₃(9) = 2

Using the power rule of logarithms, we can rewrite 2 log₃(x + 4) as log₃((x + 4)²):

log₃((x + 4)²) - log₃(9) = 2

Next, we can combine the logarithms using the quotient rule:

log₃((x + 4)² / 9) = 2

Now, we can eliminate the logarithm by rewriting the equation in exponential form:

3² = (x + 4)² / 9

9 = (x + 4)² / 9

Multiplying both sides of the equation by 9:

81 = (x + 4)²

Taking the square root of both sides:

±√81 = ±√((x + 4)²)

±9 = x + 4

Solving for x, we have two possible solutions:

x + 4 = 9

x = 9 - 4

x = 5

or,

x + 4 = -9

x = -9 - 4

x = -13

Therefore, the solutions to the logarithmic equation 2 log₃(x + 4) - log₃(9) = 2 are x = 5 and x = -13.

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Are two regular hexagons always congruent?

Answers

Answer:

Polygons - Hexagons. So, the sum of the interior angles of a hexagon is 720 degrees. All sides are the same length (congruent) and all interior angles are the same size (congruent).

Step-by-step explanation:

Search google

Final answer:

Two regular hexagons are congruent when they have equal side lengths, making them identical in shape and size. The definition of a regular hexagon as having equal sides and angles, paired with the criteria for congruence, confirms this. However, without equal side lengths, hexagons may only be similar, not congruent.

Explanation:

The question of whether two regular hexagons are always congruent comes down to understanding the definition of both a regular hexagon and congruence in geometry. A regular hexagon is a six-sided polygon where all sides and angles are equal. Congruent figures, on the other hand, are those that are identical in shape and size, meaning their corresponding sides and angles are equal. Thus, two regular hexagons that have the same lengths of sides are indeed congruent because they will have identical shapes and sizes, fulfilling the criteria for congruence.

However, it's important to note that while all regular hexagons will be similar (having the same shape but not necessarily the same size), they are only congruent if their side lengths are equal. This distinction is key in understanding the conditions under which two regular hexagons can be considered congruent. Without the specification of size, two hexagons can still be similar but not congruent.

In summary, two regular hexagons are congruent when they have the same side lengths, hence matching in both shape and size. This specific condition must be met for congruence to hold between any two geometric figures, including regular hexagons.

What is the length of the diagonal?

Answers

Answer:

The value of x is equal to 26 cm.

Step-by-step explanation:

We can use the Pythagorean Theorem to solve this problem.

[tex]a^2+b^2=c^2[/tex]

[tex]a=10\\b=24\\c=?[/tex]

[tex]10^2+24^2=c^2[/tex]

[tex]100+576=c^2[/tex]

[tex]676=c^2[/tex]

[tex]\sqrt{676} =\sqrt{c^2}[/tex]

[tex]26=c[/tex]

Suppose that diameters of a new species of apple have a bell-shaped distribution with a mean of 7.25cm and a standard deviation of 0.43cm. Using the empirical rule, what percentage of the apples have diameters that are less than 6.82cm? Please do not round your answer.

Answers

Answer:

16% of the apples have diameters that are less than 6.82cm

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 7.25cm

Standard deviation = 0.43cm

The normal distribution is symmetric, which means that 50% of the measures are below the mean and 50% are above.

Using the empirical rule, what percentage of the apples have diameters that are less than 6.82cm?

6.82 = 7.25 - 1*0.43

So 6.82 is one standard deviation below the mean.

Of the 50% of the diameters below the mean, 68% are within 1 standard deviation of the mean.

So 100-68 = 32% are not within 1 standard deviation of the mean.

0.5*0.32 = 0.16

16% of the apples have diameters that are less than 6.82cm

Which are possible solutions for the number of minutes
Joshua can participate in each activity? Check all that
apply.
40 minutes walking, 40 minutes basketball
60 minutes walking, 20 minutes basketball
20 minutes walking, 60 minutes basketball
50 minutes walking, 50 minutes basketball
60 minutes walking, 80 minutes basketball
70 minutes walking, 60 minutes basketball

Answers

Answer: 4) 50 minutes walking , 50 minutes basketball and 6) 70 minutes walking, 60 minutes basketball

Final answer:

Joshua can distribute his time among walking and basketball in a variety of ways.

Without any constraints on total time spent, all provided options, from 40 minutes each for walking and basketball to 70 minutes walking and 60 minutes basketball, are considered valid solutions.

Explanation:

The problem seems to deal with the way Joshua divides his time between two activities, which are walking and basketball. As the question does not state a limit to the total time Joshau can spend on activities, we can assume each mentioned time division can be considered a possible solution.

Therefore, under this assumption, all provided options are valid as Joshua can spend:

40 minutes walking and 40 minutes playing basketball60 minutes walking and 20 minutes playing basketball20 minutes walking and 60 minutes playing basketball50 minutes walking and 50 minutes playing basketball60 minutes walking and 80 minutes playing basketball70 minutes walking and 60 minutes playing basketball

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An online company is hoping to sell a new product by placing a pop-up advertisement on their website. There are two different designs for the advertisement, and the company would like to determine which one is more effective, as measured by clicks and purchases. For the first 200 visitors to the updated website, half were randomly assigned to receive advertisement 1 and half to receive advertisement 2. The two-way table summarizes the results: Customer Behavior Did not click Clicked, no purchase Clicked, made purchase Total Advertisement 1 70 8 22 100 Advertisement 2 64 20 16 100 Total 134 28 38 200 (a) Is this study an observational study or an experiment

Answers

Answer:

This study is an experiment.

Step-by-step explanation:

This is a case of experiment, as the visitors are assigned randomly to one of the two advertisements. The researcher intervene introducing a variable (the type of advertisement) and then study the results.

If it was an observational study, the researcher would observe, for example, the behaviour of the visitor without defining or controlling the exposure to one of the advertisement for a group of visitors.

Si 16 obreros, trabajando 9 horas diarias en 12 días, hacen 60 sillas. ¿Cuántos días necesitarán 40 obreros trabajando una hora diaria menos para hacer un ciento de las mismas sillas?

Answers

Answer:

6 días (6 days)

Step-by-step explanation:

El número de horas-hombre es directamente proporcional a la cantidad de sillas producidas. Entonces: (The number of man-hours is inversely proportional to the quantity of manufactured chairs. Then:)

[tex]\frac{(16\,p)\cdot \left(9\,\frac{h}{d\cdot p} \right)\cdot \left(12\,d\right)}{60\,c} = \frac{(40\,p)\cdot \left(8\,\frac{h}{d\cdot p} \right)\cdot x}{60\,c}[/tex]

La cantidad de sillas producidas es (The quantity of manufactures chairs is):

[tex]x = \frac{\left(16\,p\right)\cdot \left(9\,\frac{h}{d\cdot p} \right)\cdot \left(12\,d\right)}{(40\,p)\cdot \left(8\,\frac{h}{d\cdot p} \right)}[/tex]

[tex]x = 5.4\,days[/tex]

Lo cual significa que se necesitan 6 días (Which mean that 6 days are needed).

A group of engineers developed a new design for a steel cable. They need to estimate the amount of weight the cable can hold. The weight limit will be reported on cable packaging. The engineers take a random sample of 47 cables and apply weights to each of them until they break. The 47 cables have a mean breaking weight of 777.4 lb. The standard deviation of the breaking weight for the sample is 15.5 lb.
Find the 90% confidence interval to estimate the mean breaking weight for this type cable. ( , ) Your answer should be rounded to 2 decimal places.

Answers

Answer:

The 90% confidence interval to estimate the mean breaking weight for this type cable is between 751.38 lb and 803.42 lb.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 47 - 1 = 46

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 46 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.6787

The margin of error is:

M = T*s = 1.6787*15.5 = 26.02 lb

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 777.4 - 26.02 = 751.38

The upper end of the interval is the sample mean added to M. So it is 777.4 + 26.02 = 803.42

The 90% confidence interval to estimate the mean breaking weight for this type cable is between 751.38 lb and 803.42 lb.

Answer:

[tex]777.4-1.679\frac{15.5}{\sqrt{47}}=773.60[/tex]    

[tex]777.4+1.679\frac{15.5}{\sqrt{47}}=781.20[/tex]    

We are 90% confident that the true mean for the breaking weigth for this typpe of cable is between 773.60 and 781.20

Step-by-step explanation:

Data provided from the problem

[tex]\bar X=777.4[/tex] represent the sample mean for the breaking weights

[tex]\mu[/tex] population mean

s=15.5 lb represent the sample standard deviation

n=47 represent the sample size  

Confidence interval

The confidence interval for the true population mean is given by:

[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex]   (1)

The degrees of freedom, given by:

[tex]df=n-1=47-1=46[/tex]

The Confidence level is 0.90 or 90%, the significance would be [tex]\alpha=1-0.9=0.1[/tex] and [tex]\alpha/2 =0.05[/tex] and the critical value for this case is [tex]t_{\alpha/2}=1.679[/tex]

Replacing into the confidence formula we got:

[tex]777.4-1.679\frac{15.5}{\sqrt{47}}=773.60[/tex]    

[tex]777.4+1.679\frac{15.5}{\sqrt{47}}=781.20[/tex]    

We are 90% confident that the true mean for the breaking weigth for this typpe of cable is between 773.60 and 781.20

Assume that voltages in a circuit vary between 6 volts and 12 volts, and voltages are spread evenly over the range of possibilities, so that there is a uniform distribution. Find the probability of the given range of voltage levels. In each case, draw a sketch and leave answers as a fraction. a. Greater than 10 volts b. Less than 11 volts c. Between 6.5 volts and 8 volts

Answers

Answer:

a) [tex] P(X>10) =1-P(X<10) = 1-F(10) = 1-\frac{10-6}{12-6} = 0.333[/tex]

b) [tex] P(X<11)= F(11) = \frac{11-6}{12-6}= 0.833[/tex]

c) [tex] P(6.5<X<8)= F(8) -F(6.5) = \frac{8-6}{12-6}-\frac{6.5-6}{12-6}= 0.333-0.0833 = 0.250[/tex]

In the figure attached we have the illustration for the probability for each part.

Step-by-step explanation:

For this case we define the random variable X as the voltages in a circuit  and the distribution for X is given by:

[tex]X \sim Unif (a= 6, b=12) [/tex]

Part a

we want this probability:

[tex] P(X>10)[/tex]

We can use the cumulative distirbution function given by:

[tex] F(x) = \frac{x-a}{b-a}, a\leq X \leq b[/tex]

And using the complement rule we have this:

[tex] P(X>10) =1-P(X<10) = 1-F(10) = 1-\frac{10-6}{12-6} = 0.333[/tex]

Part b

We want this probability:

[tex] P(X<11)[/tex]

And using the cumulative distirbution function we got:

[tex] P(X<11)= F(11) = \frac{11-6}{12-6}= 0.833[/tex]

Part c

We want this probability:

[tex] P(6.5<X<8)[/tex]

And using the cumulative distirbution function we got:

[tex] P(6.5<X<8)= F(8) -F(6.5) = \frac{8-6}{12-6}-\frac{6.5-6}{12-6}= 0.333-0.0833 = 0.250[/tex]

In the figure attached we have the illustration for the probability for each part.

Final answer:

To find the probability of a given range of voltage levels in a circuit, we need to determine the proportion of voltages that fall within that range. In this case, the range of voltages varies between 6 volts and 12 volts, and they are spread evenly. The probability of the voltage being greater than 10 volts is 1/3, the probability of the voltage being less than 11 volts is 5/6, and the probability of the voltage being between 6.5 volts and 8 volts is 1/4.

Explanation:

To find the probability of a given range of voltage levels, we need to determine the percentage of voltage values that fall within that range. In this case, the range of voltages varies between 6 volts and 12 volts. Since the voltages are spread evenly, we can calculate the probability by finding the proportion of the range compared to the total range of possibilities.

Greater than 10 volts: To find the probability that the voltage is greater than 10 volts, we need to determine the proportion of voltages that fall above this threshold. Since the range is from 6 volts to 12 volts, the proportion of voltages greater than 10 volts is (12 - 10) / (12 - 6) = 2/6 = 1/3.Less than 11 volts: To find the probability that the voltage is less than 11 volts, we need to determine the proportion of voltages that fall below this threshold. Since the range is from 6 volts to 12 volts, the proportion of voltages less than 11 volts is (11 - 6) / (12 - 6) = 5/6.Between 6.5 volts and 8 volts: To find the probability that the voltage is between 6.5 volts and 8 volts, we need to determine the proportion of voltages that fall within this range. Since the range is from 6 volts to 12 volts, the proportion of voltages between 6.5 volts and 8 volts is (8 - 6.5) / (12 - 6) = 1.5/6 = 1/4.

Evaluate A 2-B 2 for A = 3 and B = -4.

A. 21
B. 3
C. -7

Answers

Answer:

C - 7

Step-by-step explanation:

A^2-B^2

Let A = 3 and B=-4

(3)^2 - (-4)^2

9 - 16

-7

Nigel is one and one half as tall as his brother who is three and three fourths feet tall. How tall is Nigel?

Answers

Answer:

1/4

Step-by-step explanation:



If the tax rate on homes in Topeka, Kansas is 1.8 percent of their value and Bonnie owns a $100,000 house, how much will the real estate taxes add to her monthly mortgage payment?

the real estate taxes add to her monthly mortgage payment?

Answers

Answer:

$150

Step-by-step explanation:

Annual Real Estate Tax Rate =1.8%

Value of Bonnie's House = $100,000

Annual Tax= 1.8 % × $100,000 =0.018 × $100,000 = $1,800

Therefore, tax payment on a monthly basis

= $1,800÷12 Months

= $150 per month.

Real estate tax will add $150 per month to Bonnie's mortgage payment.

Final answer:

The real estate taxes on Bonnie's $100,000 house at a 1.8 percent tax rate add $150 to her monthly mortgage payment, after calculating the annual tax and dividing by 12 months.

Explanation:

To calculate the real estate taxes that will add to Bonnie's monthly mortgage payment, we need to apply the tax rate to the value of the home and then divide by 12 to find the monthly amount.

The annual real estate taxes would be calculated as follows:


 Multiply the value of the home ($100,000) by the tax rate (1.8 percent).
 Convert the percentage to its decimal form: 1.8 percent = 0.018.
 Calculate the annual tax: $100,000 x 0.018 = $1,800.
 Divide the annual tax by 12 to get the monthly tax: $1,800 / 12 = $150.

Therefore, the real estate taxes will add $150 to Bonnie's monthly mortgage payment.

The system of equations y = three-fourths x minus 4 and y = –x + 3 is shown on the graph below.


On a coordinate plane, 2 lines intersect at (4, negative 1).

According to the graph, what is the solution to this system of equations?
(4, –1)
(–1, 4)
(4, 1)
(1, 4)

Answers

Answer:

(4, -1)

Step-by-step explanation:

The point of intersection of two lines is also the solution to the system of equations of the two lines

Step-by-step explanation:

The answer to this question is where both of the lines intersect.  For this problem, the answer is (4, -1)

Look at the attachment for clarification:

144

A. Is not a perfect square
B. Is a perfect square

Answers

Yes 144 is a perfect square because 12*12=144

Find the 54th term of the arithmetic sequence -7,-23,-39

Answers

Answer:

-855

Step-by-step explanation:

Find the 54th term of the arithmetic sequence -7,-23,-39

The first term is a_1 = -7

we see that the common difference = d = -23 - (-7) = -16

so the formula:  a_n = (n- 1)*d + a_1

a_54 = (54 - 1)* (-16) + (-7)

a_54 = 53 *(-16) - 7 = -848 - 7 =  -855

Write an exponential function in the form y = ab that goes through points (0,18)

and (2,288).

Answers

Final answer:

The desired exponential function that goes through the points (0,18) and (2,288) is y=18 × 4^x.

Explanation:

To write an exponential function in the form y = ab^x that passes through the points (0,18) and (2,288), we first use the given points to find the values of a and b.

When x = 0, the equation simplifies to y = a because b0 equals 1. Therefore, from the point (0,18), we can conclude that a equals 18.

Next, substituting x = 2 and y = 288 into the equation and using the value of a, we have 288 = 18 × b^2. To find b, divide both sides by 18 to get b^2 = 16, which means b = 4 since b is positive in the growth of an exponential function.

So the desired exponential function is y = 18 × 4^x.

Choose the equation of the line that is parallel to the y-axis.
A: x = -2
B: x + y = 0
C: x = y
D: y = 2

Answers

Answer:

A

Step-by-step explanation:

because there will be a vertical line at x= -2

Final answer:

The equation of a line parallel to the y-axis is of the form x = constant. Thus, among the provided options, option A: x = -2 is the correct answer.

Explanation:

In Mathematics, a line that is parallel to the y-axis represents an equation where x equals a constant. The y values can change, but the x value will always remain constant. This is because parallel lines to the y-axis don't slope, they are vertical lines. In the provided options, the equation that fits this description is x = -2. Therefore, the answer to your question, 'Choose the equation of the line that is parallel to the y-axis' is option A: x = -2.

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Use a letter to represent the unknown Twenty packs of fruit snacks come in a box. Each pack weighs 6 ounces. Students eat some. There are 48 ounces of fruit snacks left in the box. How many ounces of fruit snacks did the students eat?​

Answers

Answer:

The students have eaten 72 ounces of fruit snacks.

X = 72 ounces

Step-by-step explanation:

There are total 20 packs of fruit snacks

The weight of each pack is 6 ounces.

Let us first find the total weight of the snacks.

Total weight = 6*20

Total weight = 120 ounces

Let X represents the ounces of fruit snacks that students have eaten.

Let Y represents the 48 ounces of fruit snacks left in the box

Total weight = X + Y

120 = X + 48

X = 120 - 48

X = 72 ounces

Therefore, the students have eaten 72 ounces of fruit snacks.

Answer:

x = 72 ounces

The number of ounces of fruit snacks the students ate is 72 ounces

Step-by-step explanation:

Given;

Let x represent the number of ounces of fruit the students ate;

The total number of ounces of fruit initially in the box is;

20 packs × 6 ounces/pack = 120 ounces

The remaining ounces of fruit is;

48 ounces

Therefore;

120 - x = 48

Solving for x;

x = 120 - 48

x = 72 ounces

The number of ounces of fruit snacks the students ate is 72 ounces

Your small farm encompasses 120 acres, and you are planning to grow tomatoes, lettuce, and carrots in the coming planting season. Fertilizer costs per acre are: $5 for tomatoes, $4 for lettuce, and $2 for carrots. Based on past experience, you estimate that each acre of tomatoes will require an average of 4 hours of labor per week, while tending to lettuce and carrots will each require an average of 2 hours per week. You estimate a profit of $3,000 for each acre of tomatoes, $1,400 for each acre of lettuce and $400 for each acre of carrots. You would like to spend at least $480 on fertilizer and your farm laborers can supply up to 600 hours per week. How many acres of each crop should you plant to maximize total profits?


tomatoes acre(s) =
lettuce acre(s) =
carrots acre(s)=
profit $ =

In this event, will you be using all 120 acres of your farm?

Answers

Answer:

tomatoes acre(s) = 120lettuce acre(s) = 0carrots acre(s)= 0profit $ = $360,000all 120 acres are used

Step-by-step explanation:

You can write the linear system model as follows. Let t, l, c represent acres of tomatoes, lettuce, and carrots, respectively. The we have ...

  t + l + c ≤ 120 . . . . . constraint on available land

  5t +4l +2c ≥ 480 . . requirement for spending on fertilizer

  4t +2l +2c ≤ 600 . . constraint on available labor

  t ≥ 0; l ≥ 0; c ≥ 0 . .  requirement for non-negative acres

Then the objective function (profit) is ...

  p = 3000t +1400l +400c

The linear programming problem is to maximize p subject to the above constraints.

__

Any of a variety of solvers can find the solution to this problem. That solution is ...

  (t, l, c) = (120, 0, 0) and p = 360,000

In summary ...

  tomatoes acre(s) = 120 (all available acres are used)

  lettuce acre(s) = 0

  carrots acre(s) = 0

  profit $ = $360,000

_____

Additional comments

This solution suggests that it can be found simply by examining the profit associated with each unit of resource.

  profit per acre is maximized for tomatoes, at $3000 per acre

  profit per fertilizer dollar is maximized for tomatoes, at $600 per dollar

  profit per labor hour is maximized for tomatoes, at $750 per hour

That is, the profit per acre is maximized for tomatoes, regardless of the resource being considered. Thus it make sense to put all of the acreage in tomatoes. At $5 per acre for fertilizer, we use $600 worth of fertilizer. At 4 hours per week per acre, we use 480 hours of labor, so not all available labor is used.

Final answer:

To maximize profits, use linear programming to find the number of acres for each crop. The total farm acres used depends on the constraints.

Explanation:

To maximize total profits, the number of acres of each crop should be determined. Let's assign the variables t, l, and c to represent the number of acres of tomatoes, lettuce, and carrots, respectively. We have the following constraints:

The total cost of fertilizer must be at least $480: 5t + 4l + 2c ≥ 480The total hours of labor must not exceed 600: 4t + 2l + 2c ≤ 600We want to maximize total profits: Profit = 3000t + 1400l + 400c

The objective is to find the values of t, l, and c that satisfy the constraints and maximize the profit. This is a linear programming problem that can be solved using methods such as the simplex method or graphical method.

To determine if all 120 acres will be used, we need to check if t + l + c = 120 under the constraints.

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Determine whether the underlined number is a statistic or a parameter. In a study of all 4548 employees at a college comma it is found that Modifying 45 % with underline own a computer. Choose the correct statement below. Parameter because the value is a numerical measurement describing a characteristic of a population. Statistic because the value is a numerical measurement describing a characteristic of a sample. Parameter because the value is a numerical measurement describing a characteristic of a sample. Statistic because the value is a numerical measurement describing a characteristic of a population.

Answers

Answer:

Parameter because the value is a numerical measurement describing a characteristic of a population.

Step-by-step explanation:

key word is, the study of all 4548 employees

Final answer:

The underlined number, 45%, is a parameter because it's a numerical measurement that describes a characteristic of an entire population (in this case, all 4548 employees at a college). If the data was from a subset of the population or a sample, then it would be a statistic.

Explanation:

The underlined number 45% is a parameter because the value is a numerical measurement describing a characteristic of a population. In statistics, a parameter refers to a numerical characteristic of a population. In this case, the whole population under study is all 4548 employees at a college, and the underlined number represents the proportion of this entire population that owns computers.

To illustrate this concept further, consider a situation where you are studying a smaller group or sample from the entire population of employees. A statistic, on the other hand, would be a numerical measurement that describes a characteristic of this sample. If you were to evaluate a subset of 1000 employees from this college and found that 40% of them own computers, that would be a statistic because the value is describing a characteristic of a sample, not the entire population.

In summary, a parameter is a numerical characteristic of a whole population while a statistic is a numerical characteristic of a sample taken from that population.

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elena lists the ages of all of the Family members who live in our house below what is the mean absolute deviation of all their ages?

Answers

Answer:

19

Step-by-step explanation:

We'll begin by calculating the mean of the data. This is illustrated below:

Mean = summation of data / number of data

Data from the question: 9, 13, 43, 55

Mean = (9 + 13 + 43 + 55)/4

Mean = 120/4

Mean = 30.

Now, we can calculate the mean absolute deviation (MAD) as follow:

MAD = summation of the absolute deviation from the mean / number of data.

MAD = [ |9–30| + |13–30| + |43–30| + |55–30| ] /4

MAD = [ 21 + 17 + 13 + 25] /4

MAD = 76/4

MAD = 19.

Therefore, the mea absolute deviation (MAD) of their ages is 19

Answer:

19

Step-by-step explanation:

TTriangle A B C is shown. Side A B has a length of 12. Side B C has a length of x. Side A C has a length of 15.
The value of x must be greater than ________.
A. 0
B. 1
C. 3
D.7

Answers

C:3........ explanation

Sofia’s mother sent her to the grocery store with $10. If the sales tax rate that will apply at the time of her purchase is 6%, will Sofia have enough money to purchase the items on her list? 1 gallon of milk, $3.66 1 pound of bananas, $0.72 1 head of lettuce, $1.77 1 pound of tomatoes, $2.17 A. No, the total of her purchase after sales tax is $13.81. B. No, the total of her purchase after sales tax is $13.31. C. Yes, the total of her purchase after sales tax is $8.82. D. Yes, the total of her purchase after sales tax is $8.32.

Answers

Answer:

c

Step-by-step explanation:

3.66+.72+1.77+2.17=8.32×6%=8.8192 =8.82

Answer:

C Yes, the total of her purchase after sales tax is $8.82.

Step-by-step explanation:

3.66+0.72+1.77+2.17= $8.32

8.32*.06 =0.4992

0.4992+8.32= $8.82

Hope this helps!

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