Answers
Related Questions
An expression is shown below:
square root of 32 plus square root of 2
Which statement is true about the expression?
please help 25 points
A. It is rational and equal to 4
B. It is rational and equal to 5
C. It is rational and equal to 5√2
D. It is rational and equal to 4√2
Answers
4√2+√2
(4+1)√2
5√2
There is a problem however...5√2 is IRRATIONAL because √2 is irrational, ie, it cannot be expressed as a ration of two integers...
So the problems simplified is certainly 5√2, but it is irrational.
Maybe there is a typo and should read:
C. It is IRrational and equal to 5√2
One half of a number decreased by 16
Answers
"One half of a number" will be a number (x) divided by 2. This can also be shown as "0.5x" or "1/2x", whichever you prefer.
"...decreased by 16" will be "– 16", making your full equation 0.5x – 16. Remember that terms like remainder, difference, and fewer will always mean subtraction.
Hope this helped you out! :-)
Find the height of the figure below if the volume is 480.66^3 cm.
Answers
volume = PI x r^2 x H
you know the volume and the radius ( 12/2 = 6)
480.66 =3.14 x 6^2 x H
480.66 = 113.04 x h
h = 480.66/113.04 = 4.252
round off as needed.
Solve 4r2 – 7 = 29.
a. +-6
b. +-3
c. +-4
d. +-5
Answers
+7 both sides
4r^2=36
÷4 both sides
r^2=9
square root both sides
r=+/-3 B
If 300 cm^2 of material is available to make a box with a square base and an open top, find the maximum volume of the box in cubic centimeters. Answer to the nearest cubic centimeter without commas. For example, if the answer is 2,000 write 2000.
Answers
Assume a the side of the base, b the height.
[tex]V=a^2*b\\ a^2+4ab=300==\ \textgreater \ b= \dfrac{300-a^2}{4a} \\ V=a^2*\dfrac{300-a^2}{4a}= \frac{1}{4} *(300a-a^3)\\ \dfrac{dV}{da} = \frac{1}{4} *(300-3*a^2)=0\\ ==\ \textgreater \ a=10 \ and\ b=5\\ V=10^2*5=500\\ [/tex]
1. Find the coordinates of the circumcenter for ∆DEF with coordinates D(1,1) E (7,1) and F(1,5). Show your work.
2. What is the length of the 2nd base of a trapezoid if the length of one base is 24 and the length of the midsegment is 19? Show your work.
Answers
FD and DE are perpendicular, because D and F have the same x coordinate, and D and E the same y coordinate.
Let A(4, 1) be the midpoint of DE and B(1, 3) be the midpoint of FD.
Draw the perpendiculars from A and B. They meet at O(4, 3), since AO is parallel to DF and BO is parallel to DE.
the point where the perpendicular bisectors of the sides meet is the circumcenter, so the circumcenter is O(4, 3)
2.
Let the length of the second base be x.
the length of the midsegment is the sum of the ases divided by 2.
[tex]19= \frac{x+24}{2} [/tex]
19*2=x+24
38=x+24
x=38-24=14
Answers:
1) O(4, 3)
2) length of second base = 14 units
What are the solutions of the equation 2x2=2 use a graph of the related function
Answers
2x² = 2
x² = 1
x = √1
x = 1
The solution is both -1 and 1 and the graph is shown below
Answer:
[tex]x=-1\text{ or }x=1[/tex]
Step-by-step explanation:
We have been given an equation [tex]2x^2=2[/tex]. We are asked to find the solutions of our given equation.
First of all, let us divide both sides of our equation by 2.
[tex]\frac{2x^2}{2}=\frac{2}{2}[/tex]
[tex]x^2=1[/tex]
Upon taking square root of both sides of our equation we will get,
[tex]x=\sqrt{1}[/tex]
[tex]x=\pm 1[/tex]
[tex]x=-1\text{ or }x=1[/tex]
Therefore, [tex]x=-1\text{ or }x=1[/tex] are two solutions for our given function.
(06.01 LC)
What type of association does the graph show between x and y?
Linear positive association
Nonlinear positive association
Linear negative association
Nonlinear negative association
Answers
Answer:
b
im taking the same test 4 years later
Work out problem in picture
Answers
for x multiply 6 by sin(45) = 3sqrt(2) = 4.2426
for y since it is a right triangle with 45 degree angle both legs are equal
so y = x
Triangle ABC is similar to triangle XYZ. Which of the following proportions is correct?
1) AB/XY = AC/YZ
2) AC/XY=BC/XZ
3) AB/XY=AC/XZ
4) BC/XY=AB/YX
Answers
Answer:
The correct option is 3.
Step-by-step explanation:
It is given that triangle ABC is similar to triangle XYZ.
The corresponding sides of similar triangles are proportional.
Since it is given that the triangle ABC is similar to triangle XYZ, so by using the definition of similarity triangles
[tex]\frac{AB}{XY}=\frac{BC}{YZ}=\frac{AC}{XZ}[/tex]
From first and third term, we get
[tex]\frac{AB}{XY}=\frac{AC}{XZ}[/tex]
Therefore the correct option is 3.
The scale on a map indicates that 1 in = 2.5mi. How far apart are two cities that measure 2.5 ft apart on the map? A. 60 miles B. 6.25 miles C. 75 miles D. 90 miles
Answers
Use the discriminant of x^2+4x-32=0 to describe the roots
Answers
The formula for discriminant is:
discriminant = sqrt (b^2 – 4 a c)
Where,
a = 1
b = 4
c = -32
Therefore:
discriminant = sqrt (4^2 – 4 (1) (-32))
discriminant = sqrt 144
discriminant = 12
Since the discriminant is a positive real integer, then there are 2 unequal roots or 2 distinct real roots.
Simplify the product using the distributive property. (-4h +2)(3h +7)
A.
-12h 2 - 22h + 14
B.
-12h 2 - 34h - 14
C.
-12h 2 + 34h - 14
D.
-12h 2 + 22h + 14
please help
Answers
Answer:
A. -12h² - 22h + 14
Step-by-step explanation:
(-4h +2)(3h +7) = -4h(3h +7) +2(3h +7) . . . . . . . (a +b)c = ac +bc
= (-4h)(3h) + (-4h)(7) + (2)(3h) + (2)(7) . . . . . . . a(b +c) = ab +ac . . . (twice)
= -12h² -28h +6h +14
= -12h² -22h +14 . . . . . . . . collect terms
Which of these is NOT a part of formal proof? A.Reasons
b.statements
c. given
d. diagram
e.none of the above
Answers
A local carpet company has been hired to carpet a planetarium which is in the shape of a circle. If the radius of the planetarium is six yards, and the cost of the carpet is $14 per square yard, find the total cost to carpet the planetarium. (use 3.14 for π )
Answers
Total cost=[area of the carpet]*[price per square yard]
area of carpet is given by:
Area=πr^2
where;
radius,r=6 yeards
=π*6^2
=113.1 square yards
therefore the price of the carpet will be:
113.1*14
=$1,583.4
Calvin and hobbes are making snowballs to throw at suzi calvin made 3/7 of the snowballs and hobbes made 8/14 of the snowballs who mae more snowballs in fractions
Answers
recalculate 3/7 to have the same denominator as 8/14 ( 14)
so multiply both top and bottom by 2. 3/7 becomes 6/14
8/14 - 6/14 = 2/14 reduces to 1/7
Hobbes made more snowballs by 1/7
recalculate 3/7 to have the same denominator as 8/14 ( 14)
so multiply both top and bottom by 2. 3/7 becomes 6/14
8/14 - 6/14 = 2/14 reduces to 1/7
Hobbes made more snowballs by 1/7
There were n balloons at the beginning of the party. By the end of the party, 5 of them had popped. Using n, write an expression for the number of balloons that were left
Answers
Answer:
The expression for the number of balloons that were left is [tex]n-5[/tex].
Step-by-step explanation:
There were n balloons at the beginning of the party.
By the end of the party, 5 of them had popped.
Let the remaining balloons be represented by x
So, x = total balloons minus 5
This gives: [tex]x=n-5[/tex]
Therefore, the expression for the number of balloons that were left is [tex]n-5[/tex].
The sum of three consecutive even integers is 288. find the three integers.
Answers
288/3 =96
96-2 = 94
96+2 = 98
94 +96 +98 = 288
Answer:
94, 96, 98
Step-by-step explanation:
Let the smallest integer is x,
So, second larger integer = x + 2 (Because integer are even and consecutive),
And, largest integer = x + 2 + 2 = x + 4,
So, the sum of these integers = x + x + 2 + x + 4 = 3x + 6
According to the question,
3x + 6 = 288
3x = 282
⇒ x = 94
Hence, the integers are,
94, 94+2, 94+4
= 94, 96, 98
88 is the product of
8
and Jenny's score
Answers
product means multiplication
88 is the product of 8 multiplied by a number
so 88/8 =11
jenny's score is 11
How do I find ac in this problem
Answers
7 / x+4 = 5/x+1 =
5x+20 = 7x+7 =
20=2x+7
13=2x
x=13/2 = 6.5
6.5+4 = 10.5
6.5+1 =7.5
10.5+7.5 = 18
length of AC = 18
Given the points (2,k) and (0,−6) for which values of k would the distance between the points be square root of 5
?
Answers
d = sqrt( (x2-x1)^2 + (y2-y)^2 )
Some times is better the square of the distance:
d^2 = (x2-x1)^2 + (y2-y)^2
Now, in your case:
5^2 = (0-2)^2 + ( -6-k)^2 = (-2)^2 + (6+k)^2 = 4 + (6+k)^2
Notice the little thing about (-6-k)^2 = (6+k)^2 (less '-') Finally:
25 = 4 + (6+k)^2 ===> (6+k)^2 = 21,
6+k = sqrt(21)
Notice we did not expand (6+k)^2! No need this time. But now, the tricky part!
6+k=+sqrt(21) and 6+k=-sqrt(21), because both work (never forget that sqrt come with +/- when looking for solutions!)
k = -6 + sqrt(21) and k=-6-sqrt(21).
Both are valid answers. Some times one is not good because you need the solution be positive (for instance), but here, both are good.
Given the points (2,k) and (0,−6) for which values of k would the distance between the points be √5 ?
We will find that there are two possible values of k;
k = -5 and k = -7.
We know that the distance between two points (x₁, y₁) and (x₂, y₂) is given by:
[tex]d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}[/tex]
Here we have the points (2,k) and (0,−6), then the distance will be given by:
[tex]d = \sqrt{(2 - 0)^2 + (k - (-6))^2} = \sqrt{4 + (k + 6)^2}[/tex]
Now we want to find the value of k such that the distance is equal to √5, then we need to solve:
[tex]\sqrt{5} = \sqrt{4 + (k + 6)^2}[/tex]
removing the square root in both sides we get:
[tex]5 = 4 + (k + 6)^2\\\\5 - 4 = (k + 6)^2\\\\1 = (k + 6)^2[/tex]
Then we can see that (k + 6) = ± 1, solving these two equations (one for each sign) we get:
k + 6 = 1
k = 1 - 6 = -5
and
k + 6 = -1
k = -1 - 6 = -7
Then we found two possible values of k:
k = -5
k = -7
Below you can see the graph of the points A = (2, -5), B = (0, -6) and C = (2, -7)
If you want to learn more about distances, you can read:
https://brainly.com/question/5057237
Select the inequality that corresponds to the given graph. graph of an inequality with a solid line through the points negative 8 comma 0 and 0 comma negative 4 and shading above the line A 4x − 3y > − 12 B x + 4y > 4 C 4x − 2y < − 8 D 2x + 4y ≥ − 16
Answers
rearranging I can get the answer.
y>=-0.5x-4
y+0.5x>=-4
2y+x>=-8
the answer is
2x+4y>=-16
Step-by-step explanation: In the given graph x-intercept is -8 and y-intercept is -4.
Also the graph is shaded up of the line for greater values of y's.
On the option 2x+4y ≥ -16 has x-intercept at -8 and y-intercept at -4.
Also all other inequalities has only less than or greater than sign.
In the given graph we have a solid line.
So, there should be greater than or equal to inequality sign for the inequality.
Only option 4 has greater than with equal to sign.
Therefore, correct option is 2x+4y ≥ -16
which is enough information to prove that s||t
Answers
what is the domain and range of each function graohed below?
Answers
range is the y values
a.
the domain
hmm, seems to be all real numbers except for at x=0, it gets really close tho
so D=(-∞,0)U(0,∞)
range is all real numbers except for y=0, it gets really close tho
R=(-∞,0)U(0,∞)
b.
domain
that empty circle means something like < or >
goes from 5 to 6, not including 5
so domain is D=(5,6]
range is from -4 to 2, not including -4
range is R=(-4,2]
notice the holes, the excluded values, on the first one,due to an asymptote, on the second one, is in the line itself.
Please help me and show work so I can understand worth 20 points!!!
Answers
If x-5=2 then find the value of 6x-20
Answers
x-5=2
x=7
Now plug it in to the other equation to get your answer.
6(7)-20
42-20
22
The answer is 22.
6x-20
=6(7)-20
=42-20
=22
How do you solve all of these ?
Answers
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ -3}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -1 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-3)=-1(x-5) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y+3=-x+5\implies y=-x+2[/tex]
6)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 2}}\quad ,&{{ 1}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 3 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-1=3(x-2) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-1=3x-6\implies y=3x-5[/tex]
7)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 5}}\quad ,&{{ 2}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies 0 \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-2=0(x-5) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y-2=0\implies y=2[/tex]
8)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 0}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5[/tex]
9)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -2}}\quad ,&{{ 0}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{5}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-0=\cfrac{5}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y=\cfrac{5}{2}(x+2)\implies y=\cfrac{5}{2}x+5[/tex]
10)
[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{-2}}\quad ,&{{ -2}})\quad % (c,d) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2} \\\\\\ % point-slope intercept y-{{ y_1}}={{ m}}(x-{{ x_1}})\implies y-(-2)=\cfrac{3}{2}(x-(-2)) \\ \left. \qquad \right. \uparrow\\ \textit{point-slope form} \\\\\\ y+2=\cfrac{3}{2}(x+2)\implies y+2=\cfrac{3}{2}x+3\implies y=\cfrac{3}{2}x+1[/tex]
If k pencils cost c cents what is the cost in cents of p pencils
Answers
the cost in cents of p pencils = (c/k) * p
If k pencils cost c cents. Then the cost in cents of p pencils will be cp / k.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.
If k pencils cost c cents. Then the cost of each pencil is given as,
⇒ c / k
Then the cost in cents of p pencils is given as,
⇒ (c / k) x p
⇒ (cp) / k
If k pencils cost c cents. Then the cost in cents of p pencils will be cp / k.
More about the Algebra link is given below.
https://brainly.com/question/953809
#SPJ5
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
2x+9y=-30;(-8,0
Answers
9y=-2x-30 divide both sides by 9
y=-2x/9-30/9
So the slope of the reference line is -2/9. For a line to be perpendicular to this line their slopes must be negative reciprocals of one another, mathematically:
m1*m2=-1 and in this case:
-2m/9=-1
m=9/2
m=4.5, so far we have:
y=4.5x+b, using point (-8, 0) we can solve for b
0=4.5(-8)+b
0=-36+b
36=b, so our line is:
y=4.5x+36
Line p contains points A(–7, –9) and B(4, 0). Line q is parallel to line p. Line r is perpendicular to line q. What is the
slope of line r? Explain.
Answers
slope = (0 - (-9) / (4 - (-7) = 9/11...line P slope
line q is parallel....parallel lines have the same slope, so line q has a slope of 9/11.
line r is perpendicular to line q....that means line r will have a slope of -11/9. The reason is because perpendicular lines will have negative reciprocal slopes. To find the negative reciprocal of a number, just flip the number and change the sign. So, 9/11, when flipped and the sign changed is -11/9. <==