Answer:
Average velocity is 32 miles/hr.
Step-by-step explanation:
Given that a particle moves on a line away from its initial position so that after t hours it is [tex]s=6t^2+2t[/tex] miles from its initial position.
We have to find the average velocity of the particle over the interval [1, 4].
As, average velocity is the change is position over the change in time.
[tex]s(4)=6(4)^2+2(4)=104[/tex]
[tex]s(1)=6(1)^2+2(1)=8[/tex]
∴ [tex]\text{Average Velocity=}\frac{s(4)-s(1)}{4-1}[/tex]
=[tex]\frac{104-8}{3}=\frac{96}{3}=32miles/hr[/tex]
Hence, average velocity is 32 miles/hr.
The average velocity of the particle is [tex]\boxed{{\mathbf{21 units}}}[/tex] .
Further explanation:
Velocity is the speed of an object in a given direction. Velocity is the vector quantity.
The average velocity can be calculated as,
[tex]{\text{average velocity}}=\frac{{{\text{distance travelled}}}}{{{\text{time taken}}}}[/tex]
Given:
The position of the particle after [tex]t[/tex] hours is [tex]s\left(t\right)=4{t^2}+t[/tex] . The given interval is [tex]\left[{1,4}\right][/tex] .
Step by step explanation:
Step 1:
The position of the particle after [tex]t[/tex] hours is [tex]s\left(t\right)=4{t^2}+t[/tex]
First we need to find the distance travelled in the interval of [tex]\left[{1,4}\right][/tex] .
The distance travelled by the particle at [tex]t=1[/tex] is as follows,
[tex]\begin{gathered}s\left(t\right)=4{\left(t\right)^2}+t\hfill\\s\left(1\right)=4{\left(1\right)^2}+1\hfill\\s\left( 1 \right)=5\hfill\\\end{gathered}[/tex]
The distance travelled by the particle at [tex]t=4[/tex] is as follows,
[tex]\begin{gathered}s\left(t\right)=4{\left(t\right)^2}+t\hfill\\s\left(4\right)=4{\left(4\right)^2}+1\hfill\\s\left( 1 \right)=68\hfill\\\end{gathered}[/tex]
Now find the distance travelled by the particle in the interval of [tex]\left[{1,4}\right][/tex] .
[tex]\begin{aligned}{\text{distance travelled}}&=s\left(4\right)-s\left(1\right)\\&=68-5\\&=63\\\end{aligned}[/tex]
Step 2:
The given interval is [tex]\left[{1,4}\right][/tex] .
Now we need to find the time as,
[tex]\begin{aligned}{\text{time elapsed}}&=4-1\\&=3\\\end{aligned}[/tex]
Step 3:
Now we find the average velocity of the particle.
The average velocity can be calculated as,
[tex]\begin{aligned}{\text{average velocity}}&=\frac{{{\text{distance travelled}}}}{{{\text{time taken}}}}\\&=\frac{{63}}{3}\\&=21{\text{units}}\\\end{aligned}[/tex]
Therefore, the average velocity of the particle is [tex]21{\text{ units}}[/tex] .
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Answer details:
Grade: High school
Subject: Mathematics
Chapter: Speed, distance and time
Keywords: velocity, initial position, particle, moves, interval, distance travelled, time elapsed, position, average velocity, units, vector quantity, speed, direction, hours.
Solve for y.
7y - 6y - 10 = 13
y = -23
y = -3
y = 3
y = 23
y = 1/2 x + 2
x = 8
y = __
Find the perpendicular slope of the line 3X-9Y=15
Joshua used two wood beams, PC and QA, to support the roof of a model house. The beams intersect each other to form two similar triangles QRP and ARC as shown in the figure below. The length of segment PR is 4.8 inches and the length of segment CR is 7.2 inches. The distance between A and C is 9.6 inches.
What is the distance between the endpoints of the beams P and Q?
7.2 inches
3.6 inches
6.4 inches
12.0 inches
Answer:
The answer is C, 6.4 inches
Step-by-step explanation:
What is the first step in solving a quadratic equation of the form given below?
(ax + b)2 = c
A.Divide both sides by c
B.Use the zero product rule
C.Factor out a common factor
D.Take the square root of both sides
the answer is d,,,,,,,,,,,,,,,,,
Answer:
Correct option is D.
Step-by-step explanation:
Given the quadratic equation
[tex](ax+b)^2=c[/tex]
we have to define the first step in solving a quadratic equation.
To find the value of x we have make the equation linear i.e taking the square root on both sides as c is any constant.
If c is 0 the we use the zero product rule.
Hence, our first step in solving a quadratic equation of the form
[tex](ax+b)^2=c[/tex]
is to take the square root of both sides.
Correct option is D.
Which pair of angles must be congruent?
A. Supplementary angles
B. Complementary angles
C. Adjacent angles
D. Vertical angles
For Earth Day, the school plans to sell the following buttons to students and the community. The school will have to pay $18 for 15 dozen buttons. How much will the school have to pay for 50 dozen buttons?
The school will have to pay $60 for 50 dozen buttons, by using a proportional calculation based on the known cost of $18 for 15 dozen buttons.
Explanation:The student's question involves calculating the cost of purchasing a larger quantity of buttons based on a known cost for a smaller quantity. To solve this, we will use proportional reasoning.
The school pays $18 for 15 dozen buttons. First, we find the cost for one dozen by dividing the total cost by the number of dozens:
$18 ÷ 15 dozen = $1.20 per dozen
Next, we calculate the cost for 50 dozen buttons by multiplying the cost per dozen by the number of dozens:
$1.20 per dozen × 50 dozen = $60
Therefore, the school will have to pay $60 for 50 dozen buttons.
n is a positive integer.
Explain why n(n-1) must be an even number.
Ria is an Indian student who was admitted to a US university. Her annual tuition is $42,000. She has to pay her tuition fees in US dollars. She needs to calculate how many Indian rupees she will need to buy one dollar. The dollar to rupee exchange rate is 63.76 and rupee to dollar exchange rate is 0.015. How many Indian rupees will Ria need to buy one dollar?
50.00 rupees
56.00 rupees
63.76 rupees
76.63 rupees
Answer:
C:63.76
Hope this helps
Final answer:
Ria will need 63.76 Indian rupees to buy one US dollar according to the given exchange rate.
Explanation:
The student is asking how many Indian rupees are needed to buy one US dollar based on the given exchange rates. According to the given information, the exchange rate from dollars to rupees is 63.76. This means that one US dollar is equivalent to 63.76 Indian rupees. The other exchange rate provided, which is the value of a rupee in terms of dollars (0.015), is not directly relevant to the question being asked. Therefore, Ria will need 63.76 Indian rupees to buy one US dollar.
This is a continuous set of numbers. every real number from the starting value to the ending value is included. it is called an ___.
Three identical coins, labeled A, B, and C in the figure, lie on three corners of a square 10.0 cm on a side. Determine the x coordinate of each coin, xA, xB, and xC.
Write the tangent ratios for P and Q. The figure is not drawn to scale.
Answer:
tan P = 24/7 and tan Q = 7/24
Step-by-step explanation:
tangent of any angle in a right angle triangle is always represented by
tan x = opposite side/ adjacent side = height / base
from the question we have to write tangent of P and Q.
tan P = QR/PR = 24/7
tan Q = PR / RQ = 7/24
So the answers are tangent ratios for P and Q are 24/7 and 7/24.
Use the elimination method to solve the following system of equations.
2x - y + z = -3
2x + 2y + 3z = 2
3x - 3y - z = -4
A pack of gum costs 75 cents. That is 3 cents less than three times what the pack cost 20 years ago. Which equation could be used to find the cost of the gum 20 years ago?
A)
0.3x - 0.3 = 0.75
B)
3x - 0.3 = 0.75
C)
3x - 3 = 75
D)
3 - 3x = 75
Answer:
C
Step-by-step explanation:
Let the cost of a pack of gum 20 years ago = x cents
Given, present cost of a pack of gum = 75 cents
Given, present cost of a pack of gum is 3 cents less than three times what the pack costs 20 years ago.
So,
[tex]75 + 3 =3x[/tex]
[tex]75= 3x -3[/tex]
[tex]3x-3=75[/tex]
Therefore,
Equation , [tex]3x-3=75[/tex] , can be used to find the cost of the gum 20 years ago.
jamal is 167 cm tall which expression expression finds jamals height in dekametres
A.167 times 100
B.167 times 1000
C.167 divided by 100
D.167 divided by 1000
Jamal's height can be converted to dekametres by dividing his height in centimeters (167 cm) by 1000, because there are 1000 centimeters in a dekametre.
To convert Jamal's height from centimeters to dekametres, we should recall that 1 dekametre equals 10 meters or 1000 centimeters. Since Jamal is 167 cm tall, we need to divide his height in centimeters by the number of centimeters in a dekametre to get his height in dekametres.
Therefore, the correct expression to find Jamal's height in dekametres is:
167 divided by 1000
This is option D: 167 / 1000.
If two sides of a triangle are not =, the angle opposite the ___ side is the larger angle. shortest, intermediate, longest?
Answer: First option is correct.
Step-by-step explanation:
Since we have given that
If two sides of a triangle are not equal,
According to Relationship between the angle and side , we know that the angle opposite the shortest side is the larger angle,
And,
The angle opposite the longest side is the shortest angle
So, First option is correct.
Which description represents the expression 3x+4 ? A.4 less than 3 times a number B.4 divided by the product of 3 and a number C. 4 added to 3 plus a number D.the sum of 3 times a number and 4
on a grid, what is the distance between two points located at (2,1) and (14,6)
A.) 5
B.) 13
C.) 12
D.) 17.46
What is the mean of 4, 6, 8, 20, 12?
Answer:
The correct answer is A. 10
4+6+8+20+12=50
50/5 =10
Step-by-step explanation:
The sum of 8 and 7, doubled
Use the polynomial identity to determine which values of x and y generate the values of the sides of the following right triangle.
x = 8, y = 3
x = 3, y = 8
x = 6, y = 4
x = 4, y = 6
Randolph has 8 ties, 6 pairs of pants, and 4 dress shirts. how many days can randolph go without wearing the same combination of these three items?
Is the area between y = 1/x and y = 1/x^2 on the interval from x = 1 to finite or infinite?
The exponential expression 4^-2 is equal to what fraction value
If he swim 900m in a day how many kilometers he swim
An obtuse triangle with area 12 has two sides of lengths 4 and 10. Find the length of the third side. (There are two answers.) (Use law of cosines) ...?
Final answer:
Using the Law of Cosines, the length of the third side of the obtuse triangle is x = sqrt(52) or x = 2sqrt(13).
Explanation:
To find the length of the third side of an obtuse triangle with sides of lengths 4 and 10 and an area of 12, you can use the Law of Cosines. The Law of Cosines states that in a triangle with sides a, b, and c, and angle C opposite side c, the equation c^2 = a^2 + b^2 - 2ab * cos(C) can be used to find the length of side c.
In this case, let's assume that the third side of the triangle has length x. We can set up the equation as x^2 = 4^2 + 10^2 - 2*4*10 * cos(C), where C is the angle opposite side x.
Simplifying the equation, we get x^2 = 116 - 80*cos(C).
Since we know that the area of the triangle is 12, we can use the formula Area = 0.5 * a * b * sin(C) to find the value of sin(C). Plugging in the given values, we get 12 = 0.5 * 4 * 10 * sin(C). Solving for sin(C), we find sin(C) = 0.6.
Using this value of sin(C), we can then find the value of cos(C) by using the trigonometric identity sin^2(C) + cos^2(C) = 1. Substituting sin(C) = 0.6, we get 0.6^2 + cos^2(C) = 1. Solving for cos(C), we find cos(C) = 0.8.
Now, we can substitute the value of cos(C) into the equation x^2 = 116 - 80*cos(C), giving us x^2 = 116 - 80*0.8. Simplifying further, we get x^2 = 52, which means that the length of the third side is either x = sqrt(52) or x = -sqrt(52).
However, since we are dealing with the length of a side, it cannot be negative. Therefore, the length of the third side is x = sqrt(52), which simplifies to x = 2sqrt(13).
What is the number of real solutions?
–11x2 = x + 11
cannot be determined
one solution
two solutions
no real solutions
Answer:
no real solutions.
Step-by-step explanation:
-11[tex]x^{2}[/tex] = x+11. Put into standard form of a quadratic equation.
11[tex]x^{2}[/tex] + x + 11 = 0 Find a, b, and c.
a = 11, b =1, c = 11 Write and substitute into the quadratic equation[tex]\frac{-b+/-\sqrt{b^{2}-4ac}}{2a}[/tex] .
[tex]\frac{-1 +/- \sqrt{1^{2} - 4(11)(11)} }{2(11)}[/tex] Simplify.
[tex]\frac{-1 +/- \sqrt{1-484} }{2(11)}[/tex]=
[tex]\frac{-1 +/-\sqrt{-483} }{22}[/tex] BUT because the [tex]b^{2} -4ac[/tex] part under the √ is less than 0, THERE IS NO SOLUTION!
if y=15 when x=3/4, find x when y=25
The value of the x is 5/4 when y=25 if y=15 when x=3/4 the answer would be 5/4
What is a proportional relationship?It is defined as the relationship between two variables when the first variable increases, the second variable also increases according to the constant factor.
It is given that:
x and y are in a proportional relationship if y=15 when x=3/4,
y ∝ x
y = kx
15 = k(3/4)
k = 20
y = 20x
Plug y = 25
25 = 20x
x = 25/20
x = 5/4
Thus, the value of the x is 5/4 when y=25 if y=15 when x=3/4 the answer would be 5/4
The complete question is:
x and y are in a proportional relationship if y=15 when x=3/4, find x when y=25.
Learn more about the proportional here:
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How many real solutions does the function shown on the graph have?
Can someone explain?
One, Two, None, or can't be determined?
what happens to the graph of a line when the slope is negative? Check all that apply. may choose more then 1.
A. As the absolute value of the negative slope gets bigger, the graph of the line gets steeper.
B. As the absolute value of the negative slope gets smaller, the graph of the line gets steeper.
C. The line goes down from left to right.
D. The line shifts down.
E. The line goes up from left to right