At an accident scene on a level road, investigators measure a car's skid mark to be 84 m long. It was a rainy day and the coefficient of friction was estimated to be 0.36.

Answer:

b) Cells will pass through the G1/S checkpoint even if conditions are not ideal for cell division.

Explanation:

In the given problem, if there exists a gain-of-function mutation for the given cell, there would not be the formation of cyclin E when there is the possibility of cells movement via the checkpoint of the G1/S, even when there are non-deal conditions for the division of cell. Thus, the correct option in the lists of options is the option b.

Answer:

The milky way does not have an active galactic nuclei and active galactic nuclei reduce their activity as time pass.

Explanation:

An active galactic nucleus (AGN) is a region that is compact and at the galaxy's center. It has a extra high luminosity in which some observations indicate that the luminosity is not as a result of the presence of stars.

Answer:Upward

Explanation:

To hang the object in the halfway we need to direct the Electric field toward upward direction

Suppose object has mass m and charge q

If electric field is Pointing towards upward direction then the force experienced by charged particle is in the upward direction which will be balanced by weight of particle(pointing downward) such that

qE=mg

where q=charge of particle

E=Electric field

m=mass of particle

g=acceleration due to gravity

To find the new orbital period of a satellite at 1500 miles above Earth with a velocity of 38,000 mph, we use a proportional relationship comparing it to a known orbit. We set up the ratio using the direct variation with the orbit's radius and inverse variation with the orbital velocity, then solve for the unknown orbital period.

The duration of a satellite's orbit around Earth can be described as varying directly with the orbit's radius and inversely with the orbital velocity. To calculate the orbital period for a new satellite trajectory, we need to compare it with a known situation using a proportional relationship. Given that a satellite orbits 660 miles (or 1062 kilometers) above Earth in 13 hours at 32,000 mph, we can set up a ratio to determine the orbital period at 1500 miles (or 2414 kilometers) above Earth with a velocity of 38,000 mph.

The ratio for the original orbit is T1 / (r1 / v1) = T2 / (r2 / v2), where T is time, r is radius (distance from Earth's center to the satellite), and v is velocity. Using the provided values, we get:

13 / ((3963 + 660) / 32000) = T2 / ((3963 + 1500) / 38000)

Solving for T2 gives us the new orbital period. Considering that we should convert the altitude to the same units and use Earth's radius in miles (3963 miles), the final calculation will provide us with the new orbital period in hours.

Answer:

R=19.5m

[tex]\theta[/tex] = 4.65° S of W

Explanation:

Refer the attached fig.

displacement  of the x and y components

x-component displacement is ([tex]R_{x}[/tex]) = [tex]A_{x}+B_{x}[/tex]

= A [tex]\sin[/tex](20°) + B [tex]\cos[/tex](40°)

= -12.0[tex]\sin[/tex](20°) + 20.0[tex]\cos[/tex](40°)

= -19.425m

x-component displacement is ([tex]R_{y}[/tex]) = [tex]A_{y}+ B_{y}[/tex]

=  A [tex]\cos[/tex](20°) - B [tex]\sin[/tex](40°)

= 12.0[tex]\cos[/tex](20°) - 20.0[tex]\sin[/tex](40°)

= -1.579

resultant displacement

∴

R = [tex]\sqrt{R_{x}^{2} +R_{y}^{2} } }[/tex]

=[tex]\sqrt{(-19.425)^{2}+(-1.579)^{2} }[/tex]

=19.5m

[tex]\theta[/tex] = [tex]\tan^{-1}\left | \frac{R_{x}}{R_{y}} \right |[/tex]

[tex]\theta[/tex] = [tex]\tan^{-1}\left | \frac{1.579}{19.425} \right |[/tex]

[tex]\theta[/tex] = 4.65° S of W

This problem involves finding the result of two vector displacements using vector addition. Using the Pythagorean theorem, the magnitude of the overall displacement can be determined. The direction of the displacement can be calculated using the tangent formula.

This is a vector addition problem in physics. We can solve it using Pythagorean theorem for finding the magnitude and tangent formula for finding the direction.

For the first leg of the journey(A), you are going 20° W of N, or 70° clockwise from the x-axis. For the magnitude of this vector: Ax = 12.0m cos(70°) and Ay = 12.0m sin(70°).

For the second leg of the journey(B), you are going 40° S of W, or 130° clockwise from the x-axis. For the magnitude of this vector: Bx = 20.0m cos(130°) and By = 20.0m sin(130°).

Summing the x and y components gives: Rx = Ax + Bx and Ry = Ay + By. The magnitude R can then be found with Pythagorean theorem formula: R = sqrt(Rx² + Ry²).

The direction can be found using tangent formula: θ = atan(Ry / Rx). As Rx is negative and Ry is positive, θ will fall in the second quadrant.

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Answer:

2.03873 s

70.38735 m

4.07747 seconds

5.82688 seconds

27.37482 m from the ground

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

g = Acceleration due to gravity = 9.81 m/s² = a

[tex]v=u+at\\\Rightarrow t=\dfrac{v-u}{a}\\\Rightarrow t=\dfrac{0-20}{-9.81}\\\Rightarrow t=2.03873\ s[/tex]

time needed for the ball to reach its maximum height is 2.03873 s

The time taken to go up and the time taken to reach the point from where it was thrown is the same.

So, time needed for the ball to return to the height from which it was thrown is 2.03873+2.03873 = 4.07747 seconds

[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0^2-20^2}{2\times -9.81}\\\Rightarrow s=20.38735\ m[/tex]

The maximum height the ball will reach is 50+20.38735 = 70.38735 m

[tex]s=ut+\frac{1}{2}at^2\\\Rightarrow 70.38735=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{70.38735\times 2}{9.81}}\\\Rightarrow t=3.78815\ s[/tex]

Time needed to reach the ground is 2.03873+3.78815 = 5.82688 seconds

The time from the maximum height that is required is 5-2.03873 = 2.96127 seconds

[tex]s=ut+\dfrac{1}{2}at^2\\\Rightarrow s=0\times t+\dfrac{1}{2}\times 9.81\times 2.96127^2\\\Rightarrow s=43.01253\ m[/tex]

The ball will be 70.38735-43.01253 = 27.37482 m from the ground

The problem is solved using kinematic equations. The ball reaches its maximum height in approximately 2.04 s, with the maximum height reaching about 70.4 m. It returns to the original height in around 4.08 s with a velocity at -39.79 m/s, reaches the ground in about 5.82 s, and at t = 5 s, its position is approximately 49.4 m with velocity of around -29 m/s.

The calculations are based on the physics of kinematics, specifically related to the motion under constant acceleration which in this context is gravity (designated 'g'), typically -9.8 m/s².

(a) You can use the equation v = u + gt to solve for time (t). Since the velocity (v) at the maximum height is 0, initial velocity (u) is 20 m/s and g is -9.8m/s², the equation becomes 0 = 20 - 9.8t. Solving for t, we get t = 20/9.8 ≈ 2.04 s.  

(b) The maximum height can be found using the equation s = ut + 0.5gt². Substituting the known values we get the maximum height to be about 70.4m

(c) The time taken for the ball to return to its original height will be double the time to reach maximum height, so it's 2*2.04s = 4.08s. The velocity is simply gt, yields -39.79m/s (negative because it's moving downwards).

(d)We can utilize the equation s = ut + 0.5gt² to find out the time to hit the ground. The total distance covered is 50m + 20.4m = 70.4m. Solving the equation we get t = 3.78s (above the throwing point) and to find the total time on air, add t = 2.04s and value calculated you get t = 5.82 s.  

(e)Using equations of motion, we can find out that at t=5s, the position of the ball is 49.4 m above the ground and its velocity is -29m/s.

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Answer: it is very difficult to remove the inner electrons from an atom because of the strong electrostatic force of attraction by the nucleus. In contrast, it is very easy to remove the outer electrons from an atom because the electrostatic force of attraction from the nucleus is not strong enough to hold the outer electrons hence it is removed.

Answer:

3894531 coulombs

Explanation:

1 hour = 3600 seconds

Let g = 10m/s2

The distance that the car travel at 25 m/s over an hour is

s = 25 * 3600 = 90000 m

The total mechanical energy of the car is the sum of its kinetic energy to reach 25 m/s, its potential energy to climb up 200m high hill and it work to travel a distance of s = 90000m with F = 500 N force:

[tex] \sum E = E_k + E_p + E_W[/tex]

[tex]\sum E = mv^2/2 + mgh + Fs[/tex]

[tex]\sum E = 750*25^2/2 + 750*10*200 + 500*90000 = 46734375 J[/tex]

This energy is drawn from the battery over an hour (3600 seconds), so its power must be

[tex]P = E / t = 46734375/3600 = 12982 W[/tex]

The system is 12V so its current is

[tex]I = P/U = 12982 / 12 = 1081.8 A[/tex] or 1081.8 Coulombs/s

The the total charge it needs for 1 hour (3600 s) is

C = 1081.8 * 3600 = 3894531 coulombs

The quantity of charge the batteries must be able to move is equal to 3.9 μC.

Given the following data:

Scientific data:

To find the quantity of charge the batteries must be able to move:

In this scenario, we would calculate the distance traveled and the total energy that is possessed by this battery-operated car.

Mathematically, the distance covered by an object is given by this formula:

[tex]Distance = speed \times time\\ \\ Distance = 25 \times 3600[/tex]

Distance = 90,000 meters.

[tex]E = mgh + \frac{1}{2} mv^2 + Fd\\ \\ E=[750\times 9.8 \times 200] + \frac{1}{2} \times 750 \times 25^2 + [500 \times 90000]\\ \\ E=1470000+234375+45000000[/tex]

Total energy = 46,704,375 Joules.

Next, we would calculate the power consumed by this battery-operated car:

[tex]Power = \frac{Energy}{time}\\ \\ Power = \frac{46,704,375}{3600} [/tex]

Power = 12,973.44 Watts.

Also, we would calculate the current:

[tex]Current = \frac{power}{voltage} \\ \\ Current = \frac{12,973.44}{12}[/tex]

Current = 1,081.12 Amperes.

Now, we can calculate the quantity of charge the batteries must be able to move:

[tex]Q = current \times time\\ \\ Q = 1081.12 \times 3600[/tex]

Q = 3,892,032 Coulombs.

Note: 1 μC = [tex]1 \times 10^6 \;C[/tex]

Q = 3.9 μC

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Answer:

C. is responsible for sliding friction and contact forces

Answer:

B. 2.5 W

Explanation:

Power: This can be defined as the rate at which energy used or it i the rate at which work is done. The S.I unit of power is Watt (W).

Mathematically,

Power = Energy or work/Time

P = W/t ........................Equation 1

Where P = power used to perform the task, W = work, t = time.

Given: W = 50 J, t = 20 s.

Substitute into equation 1

P = 50/20

P = 2.5 W.

Hence the power is 2.5 W.

The right option is B. 2.5 W

The power used to perform the work of 50J in 20 seconds is 2.5 watts. This much power should be generated by it. The correct answer is B.

Given that 50 J of work was performed in 20 seconds,

The power used to perform a task, you can use the formula:

Power = Work / Time

Power = 50 J / 20 s

Power = 2.5 W

Therefore, the power used to perform the task is 2.5 W.

Therefore, the correct answer is B) 2.5 W.

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Answer:

ANULAR ECLIPSE

Explanation:

ANULAR ECLIPSE. Because the moon is very far, only a portion of the sun would be obscured, and then only the moon's outer ring will be viewable; this is called the anular eclipse.The ring of fire marks the maximum stage of an annular solar eclipse.

Answer:

Flight path angle= 15.12°, maximum range= 5.29× 10*6 km

Explanation:

u= 7200m/s, H= 180km= 180000m

Recall that

Maximum height, H= (u*2sin*2∆)/2g

180000= (7200×7200sin*2∆)/2×9.8

(18000×2×98)/7200×7200= sin*2∆

Sin∆= 0.2609

∆= 15.12°

Maximum range, R= u*2/g

(7200×7200)/9.8

= 5289795.92km

= 5.29× 10*6 km

The distance between the center of mass of the molecule and carbon atom is 0.65 × 10⁻¹⁰ m

To answwer the question, we need to know the center of mass of CO molecule

The center of mass of the CO molecule is given by

x = m₁x₁ + m₂x₂/(m₁ + m₂) where

Substituting the values of the variables into the equation, we have

x = (m₁x₁ + m₂x₂)/(m₁ + m₂)

x = (12 u × 0 m + 16 u × 1.13 × 10⁻¹⁰ m)/(12 u  + 16 u)

x = (0 + 16 u × 1.13 × 10⁻¹⁰ m)/28 u

x = 18.08 × 10⁻¹⁰ um/28 u

x = 0.646 × 10⁻¹⁰ m

x ≅ 0.65 × 10⁻¹⁰ m

Since the carbon atom is at x₁ = 0 m and the center of mass is at x = 0.65 × 10⁻¹⁰ m, the distance between the carbon atom and the center of mass of the molecule is d = x - x₁

= 0.65 × 10⁻¹⁰ m - 0 m

= 0.65 × 10⁻¹⁰ m

So, the distance between the center of mass of the molecule and carbon atom is 0.65 × 10⁻¹⁰ m

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Answer:

a. for any force, there is an equal and opposite reaction force.

Explanation:

Newton third law of motion states that " for every action, there is an equal and opposite reaction.

Action force= reaction force =

M₁ * a₁ = M₂ * a₂

where M₁ = mass of object 1

          a₁ = acceleration due to object 1

          M₂ = mass of object 2

          a₂ = corresponding acceleration due to object 2

this happen in everyday life of an individual. an example is seen in a groups of three man exerting a push force on a static car, the push force on the car make the car to exhibit some motion equivalent to the force applied by the three man.

Answer:

The magnitude of charge on each sphere is [tex]q=2.50\times 10^{-8}\ C[/tex].

Explanation:

Given that,

Force of repulsion between the charges, F = 22 mN

The distance between spheres, r = 16 mm = 0.016 m

It is mentioned that both the spheres carry equal charges. The force between charges is given by :

[tex]F=\dfrac{kq^2}{r^2}[/tex]

[tex]q=\sqrt{\dfrac{Fr^2}{k}}[/tex]

[tex]q=\sqrt{\dfrac{22\times 10^{-3}\times (0.016)^2}{9\times 10^9}}[/tex]

[tex]q=2.50\times 10^{-8}\ C[/tex]

So, the magnitude of charge on each sphere is [tex]q=2.50\times 10^{-8}\ C[/tex]. Hence, this is the required solution.

Answer:it is cold

Explanation:because of a winter storm it is very cold which doesn’t

Match Florida’s tropical warm climate

Weather refers to short-term atmospheric conditions while climate refers to long-term predictable conditions. Weather in Orlando today depicts the present conditions, whereas Florida's climate represents the long-term averages and patterns across the state.

The weather in Orlando today simply refers to the current atmospheric conditions in Orlando, such as temperature, humidity, precipitation, wind, etc. It's a mere snapshot of what's happening right now in the atmosphere around Orlando. Now, when we're talking about Florida's climate, we're referring to the long-term atmospheric conditions in the state of Florida. This includes consistent seasonal temperature and rainfall patterns over many years. Therefore, the primary difference between describing the weather in Orlando today and Florida's climate lies in the timeframe – weather explains temporary conditions, while climate refers to long-term, predictable conditions.

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Answer:

The answer is 199920 meters.

Explanation:

First we need to find how many seconds they walked to the store:

[tex]34*60=2040[/tex]

If they walked 2040 seconds to eastward with velocity of 89 m/s, the displacement will be:

[tex]2040*98=199920[/tex]

The amount of heat required is B) 150 J

Explanation:

The amount of heat energy required to increase the temperature of a substance is given by the equation:

[tex]Q=mC\Delta T[/tex]

where:

m is the mass of the substance

C is the specific heat capacity of the substance

[tex]\Delta T[/tex] is the change in temperature of the substance

For the sample of copper in this problem, we have:

m = 25 g (mass)

C = 0.39 J/gºC (specific heat capacity of copper)

[tex]\Delta T = 15^{\circ}C[/tex] (change in temperature)

Substituting, we find:

[tex]Q=(25)(0.39)(15)=146 J[/tex]

So, the closest answer is B) 150 J.

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Answer:

Yes, it is reckless. This is because it is the responsibility of the pilot to make sure that the direction of the propeller blast is away from people or other aircraft and in a safe direction.

Explanation:

Yes, it is reckless to let the propeller blast face people and other aircraft. This is because it is the responsibility of the pilot to make sure that the direction of the propeller blast is away from people or other aircraft and in a safe direction. People and other aircraft can be injured by the debris and the rocks that are scattered by the engine of the aircraft.

Final answer:

Causing debris and propeller blast to endanger others can be deemed reckless operation of an aircraft, akin to dangerous driving, and can be punishable by aviation law.

Explanation:

The operation of an aircraft in a manner that causes debris, rocks, and propeller blast to be directed towards people or other aircraft can indeed be considered reckless operation. For perspective, consider that landing an aircraft is described as an ultimate challenge and must ensure safety as if it were a casual drive to a golf course. Pilots are responsible for maintaining control of their aircraft and ensuring the safety of both passengers and bystandiles at all times, much like drivers on the road.

Reckless operation of an aircraft can endanger lives and property, and is typically prohibited by aviation law and regulations. If a pilot operates an aircraft without regard to the potential harm it could cause others, this could be construed as reckless. The key is the intent and awareness of the pilot; if they are knowingly causing potential harm, it is indeed reckless.

Answer:

Because its dangerous.

Explanation:

During lighting strikes, there is discharge or energy transfer(electrons) from the clouds to the earth, these electrons flow through the path with least resistance between the cloud and the earth. Also the electric field around the tip of the leaves are strong, which makes trees a great target.

we as humans have lower resistance than trees, that is to say, the lighting may leave the tree and flow trough the body to the earth.

The tree and the ground around it are then raised to a high potential relative to the ground some distance away.

If you stand with your legs far apart, one leg on a higher-potential part of the ground than the other, or if you lie down with a potential difference between your head and your feet, you may find yourself a conducting path.

If it is also raining, the electricity may transfer down the wet tree to the wet ground and shock anyone standing near the tree.

During a thunderstorm, it is advised not to stand under a tree to avoid being struck by lightning, not to stand with legs far apart to reduce the electric potential difference, and not to lie down due to increased risk. Staying inside a car provides safety as it acts as a Faraday cage.

Standing under a tree during an electrical storm is dangerous since lightning tends to strike the tallest object in an area, which could be the tree you're under, potentially causing serious injury or death. As for not standing with legs apart, this is because, in the event of a ground strike, electricity can travel through the ground. If your legs are far apart, there could be a significant electric potential difference between them, which can result in a stronger current passing through your body, leading to severe harm. Lying down increases your contact with the ground, and consequently, the risk of current flowing through your body from a ground strike is greater.

During thunderstorms, your car acts as a Faraday cage, which shields you from electric fields if a lightning strike occurs nearby. It's safest to remain inside the car with windows closed. However, it's critical to refrain from touching metal parts inside the car as lightning can transfer its charge through the car's metal frame.

Answer:

You have to apply force of 78.43 N to pull the sled or person across the snow at constant speed

Explanation:

Given data

Sled force F₁=58 N

Person weight F₂=655 N

Coefficient of kinetic friction u=0.11

To find

Friction Force

Solution

To pull the sled across the snow means the force you apply must be equal to and opposite the force of frictional.  

First we need to find the Total normal force

So

[tex]F_{Normal-Force}=F_{1}+F_{2}\\F_{Normal-Force}=58N+655N\\F_{Normal-Force}=713N[/tex]

Now the force of friction

[tex]F_{Friction-Force}=u_{coefficient}*F_{Normal-Force}\\F_{Friction-Force}=0.11*713N\\F_{Friction-Force}=78.43N[/tex]

So you have to apply force of 78.43 to pull the sled or person across the snow at constant speed

Answer:

32.67255 W

Explanation:

F = Force  = 22 N

r = Radius of crank = 0.26 m

s = Displacement = [tex]2\pi r[/tex]

[tex]\theta[/tex] = Angle = 0

t = Time taken = 1.1 s

Work done is given by

[tex]W=Fscos\theta\\\Rightarrow W=22\times 2\pi\times 0.26\times cos0\\\Rightarrow W=35.93981[/tex]

Power is given by

[tex]P=\dfrac{W}{t}\\\Rightarrow P=\dfrac{35.93981}{1.1}\\\Rightarrow P=32.67255\ W[/tex]

The average power being expended is 32.67255 W

Answer:

Option D.

Explanation:

The correct answer is Option D.

The shrinkage of the bridge material is because of thermal contraction.

Thermal contraction and thermal expansion are the phenomena of the bridge material which takes place due to the change in temperature of the atmosphere.

When the temperature of the surrounding increases expansion of the bridge material takes place and when temperature decreases the contraction of the material takes place.

This phenomenon sometimes damages the structure because due to continuous expansion and contraction of materials strength of the bridge decreases.

Thermal expansion joints in bridges prevent material breakage due to temperature changes.

Thermal expansion joints are used in bridges to allow for the changing length of the bridge due to temperature fluctuations. Without these joints, the bridge material would break due to thermal stress caused by expansion and contraction.

Answer:

2 in

Explanation:

Area of a sheet = 3.5 x 14 in²

Volume of ream, V = 98 in³

Let t be the thickness of ream

So, Volume of ream  Area of a sheet x thickness of ream

98 = 3.5 x 14 x t

t = 2 in

Thus, the  thickness of ream is 2 in.

Answer:

t = 2 in

Explanation:

given,

width of sheet, W = 3.5 in

Length of the sheet, L = 14 in

thickness of the ream = ?

volume of paper = 98 in³

we now,

Volume = Length x width x thickness

V = l w t

98 =  14 x 3.5 x t

[tex]t = \dfrac{98}{14\times 3.5}[/tex]

t = 2 in

thickness of the ream is equal to 2 in.

Answer:

v' = -0.0906 m/s

Explanation:

given,

mass of cannon, M = 2240 Kg

mass of the ball, m = 15.5 Kg

speed of cannon ball, v = 131 m/s

speed of he cannon = ?

initial speed of cannon and the cannon ball is equal to 0 m/s

using conservation of energy

(M+m)V = M v' + m v

(M+m) x 0= 22400 v' + 15.5 x 131

22400 v' = -2030.5

v' = -0.0906 m/s

negative sign represent the canon will move in opposite direction of the ball.

hence, speed of cannon is equal to 0.0906 m/s

Using the law of conservation of momentum and the given values, the recoil velocity of the cannon is found to be approximately 0.9058 m/s after firing a cannonball.

According to the law of conservation of momentum, the total momentum before an event must equal the total momentum after the event, if no external forces act on the system. In this case, the cannon and the cannonball system is isolated and free to recoil, so the momentum before the cannon fires must be equal to the momentum after the cannon fires.

Momentum is the product of mass and velocity. Before the cannon fires, both the cannon and the cannonball are at rest and have a momentum of zero. After the cannon fires, the momentum of the cannonball is mcannonball × vcannonball, which must be equal and opposite to the momentum of the cannon. Therefore, mcannonball × vcannonball = mcannon × vcannon.

Using the given values for mass and velocity of the cannonball (15.5 kg and 131 m/s), and the mass of the cannon (2240 kg), we can calculate the cannon's recoil velocity using the equation:

mcannonball × vcannonball = mcannon × vcannon

(15.5 kg × 131 m/s) / 2240 kg = vcannon

The calculated recoil velocity of the cannon is approximately 0.9058 m/s.

Answer:

A) Increasing,  Increasing,  Increasing

Explanation:

The greater the rate of fuel ejection higher will be the kinetic energy of the rocket. As rocket is fire upward its fuel rejection rate increases and hence it's kinetic energy increases.

Gravitational potential energy,

as the rocket moves further it's r from the Earth increases. Hence the Gravitational potential energy increases as its height from the Earth increases.

Therefore,  mechanical energy of the rocket must also increase as it is sum of kinetic and potential energy.

Hence Option A is correct.

For the first kilometer of the rocket's ascent, the kinetic energy, gravitational potential energy, and mechanical energy of the Earth-rocket system increase.

The changes in the kinetic energy, gravitational potential energy, and mechanical energy of the Earth-rocket system for the first kilometer of the rocket's ascent can be determined.

Since the mass of fuel ejected is small compared to the mass of the rocket, the rocket's kinetic energy will increase as it accelerates away from Earth. The gravitational potential energy of the Earth-rocket system will also increase as the rocket moves higher against the pull of gravity. Therefore, the changes in the three quantities are as follows:

Answer:

14.4 m/s

Explanation:

mass of Anna (Ma) = 68 kg

speed of Anna (Va) = 17 m/s

mass of SandraDay (Ms) = 76 kg

speed of SandraDay (Vs) = 12 m/s

We can find their speed (V) immediately after collision from the conservation of momentum where

(Ma x Va) + (Ms + Vs) = (Ma + Ms) x V

where V = speed immediately after collision

(68 x 17) + (76 + 12) = (68 + 76) x V

2068 = 144 V

V = 2068 / 144 = 14.4 m/s

Answer:

Explanation:

Given

mass of children [tex]m_1=20\ kg[/tex]

[tex]m_2=30\ kg[/tex]

distance between two children [tex]L=3\ m[/tex]

suppose  small child is at a distance of x m from  pivot point

so torque of small child and heavier child must be equal

[tex]20\times (x)=30\times (3-x)[/tex]

[tex]2x=9-3x[/tex]

[tex]5x=9[/tex]

[tex]x=1.8\ m[/tex]    

Answer:

The thickness of 1 card is between 0.006in and 0.016in

Explanation:

Thickness of a deck of 52 cards = 0.590in

Thickness of 1 card = 0.590in/52 = 0.011in

Uncertainty = + or - 0.005in

Lower limit of thickness of 1 card = 0.011in - 0.005in = 0.006in

Upper limit of thickness of 1 card = 0.011in + 0.005in = 0.016in

Therefore, thickness of 1 card is between 0.006in and 0.016in

Answer:

Weber's Law

Explanation:

Weber’s law is an important law in psychology.

This law quantifies the perception of change within a provided stimulus.

This law is also known as Weber-Fechner law as it relates two hypotheses in the field of psychophysics which are Weber law and the Fechner law.

Weber’s law describes that an observed change in a stimulus is a constant ratio of the original stimulus.

Final answer:

Weber's Law describes the relationship between a stimulus and the resulting sensation, stating that the Just Noticeable Difference (JND) is a constant fraction of stimulus intensity. It is a key principle in psychophysics, useful for experiments such as determining the JND for different weights of rice in bags.

Explanation:

The concept you're inquiring about is Weber's Law, which is a fundamental principle in the field of psychophysics, a branch of psychology. Weber's Law describes the relationship between a stimulus and its resulting sensation by proposing that the Just Noticeable Difference (JND) is a constant fraction of the stimulus intensity.

To put this into practice, for example, if one were testing the JND of various weights of rice in bags, they could use incremental percentage increases of the weight to determine the smallest difference that can be perceived. By choosing increments like 10 percent or 20 percent between certain weight thresholds, a researcher can apply Weber's Law to determine the JND in a standardized way.

This law helps explain why when you have a cup of coffee with little sugar, adding a teaspoon can make a noticeable difference, but in a cup with much more sugar, that same teaspoon becomes less detectable, requiring a proportionally larger amount of sugar to notice a change in sweetness.