Final answer:
The distance from the cannon to the ship is 32.0 km, but to calculate initial velocity and maximum height of the shell, additional information such as angle of launch or time is required. The Earth's curvature slightly affects the height of the ocean's surface relative to the ship over long distances.
Explanation:
Assuming the dread pirate Roberts never misses, the distance from the end of the cannon to the ship trying to be hit is the maximum distance the cannon shell can travel, which is 32.0 km when neglecting the dimensions of the cannon and air resistance. To calculate the initial velocity of the shell, we would use the kinematic equations for projectile motion. However, the question does not provide angle of launch or time required for the calculation, so further information would be needed to complete part (a).
For part (b), the maximum height reached by the shell cannot be calculated without additional information such as the launch angle or time of flight. For part (c), the curvature of the Earth impacts the level of the ocean's surface in relation to a straight line extending from the ship. Using the Earth's radius (6.37×10³ km), we can apply the principles of geometry to find the drop in height over a distance of 32.0 km, with the assumption that the ocean surface follows the curvature of the Earth.
A common small-molecular weight (and therefore fast diffusing for an organic molecule) ingredient in perfumes is vanillin, the primary component of vanilla bean extract (molecular weight = 152). the d for vanillin in air is 0.114 cm2/s. if i open a bottle of vanilla on the other side of the room 3 meters away, and the air is still so there is no convection, about how long would i have to wait before i could expect to smell the vanilla?
Using Fick's Law of Diffusion, it would take about 394,737 seconds for the scent of vanilla (vanillin) to travel 3 meters in still air, considering its diffusivity in the given conditions.
The time it takes for a scent to travel through air can be estimated using Fick's Law of Diffusion, which relates diffusion time to the diffusivity of the substance, the distance it needs to travel, and the area through which it diffuses.
Diffusion time = (Distance^2) / (2 * Diffusivity)
Given that the distance is 3 meters and the diffusivity (D) of vanillin in air is 0.114 cm^2/s, we need to convert the distance to centimeters before applying the formula:
Diffusion time = (300 cm)^2 / (2 * 0.114 cm^2/s)
Diffusion time ≈ 90,000 cm^2 / 0.228 cm^2/s
Diffusion time ≈ 394,737 seconds
So, it would take approximately 394,737 seconds for the smell of vanilla to reach you from a distance of 3 meters in still air.
a toy projectile is fired from the ground vertically upward with an initial velocity of 26.5 m/s. The project arrives at its maximum altitude in 2.7s.
Determine the greatest height the projectile reaches. How do you know?
Answer:
35.8 m
Explanation:
Given:
Initial Velocity u = 26.5 m/s
Time period t = 2.7 s
To find:
Maximum height H = ?
Solution:
The toy is projected vertically upward. So the motion is happening in y axis
When a projectile reaches its maximum height, at that point its velocity vill be zero
Using equations of motion we can find the height
[tex]v^{2} =u^{2} -2gH\\\\0^{2} =26.5^{2} -2\times 9.8 \times H\\\\19.6H = 702.25\\\\H = 35.8 m[/tex]
Verification
[tex]H = ut - \frac{1}{2} gt^{2}\\\\H = 26.5 \times 2.7- 0.5 \times 9.8 \times 2.7^{2}\\\\H = 35.8 m[/tex]
A head-on, elastic collision between two particles with equal initial speed v leaves the more massive particle (mass m1) at rest. find the ratio of the particle masses
The ratio of the particle masses is \boxed{\frac{1}{3}} or \boxed3 .
Further explain:
We have to calculate the ratio of the particle masses.
As we know, in the elastic collision between two masses the momentum and the energy both are conserved.
Here, the collision between the masses the head-on it means head to head.
For head on head collision the masses will travel parallel but opposite in the direction.
We have two masses one is heavier and another is lighter.
The mass of massive or heavier particle is [tex]{m_1}[/tex].
The mass of the lighter particle is [tex]{m_2}[/tex].
From the conservation of linear momentum total initial momentum is equal to the total final momentum.
Therefore,
[tex]\boxed{\left( {{m_1}v - {m_2}v} \right) = \left( {{m_1}{v_1} + {m_2}{v_2}} \right)}[/tex]
Here, after the collision the massive particle comes into rest.
So, final expression will be,
[tex]\left( {{m_1}-{m_2}}\right)v={m_2}{v_2}[/tex] …… (1)
From the conservation of the energy,
Total kinetic energy before collision is equal to the total kinetic energy after collision.
Therefore,
[tex]\begin{aligned}\frac{1}{2}{m_1}{v^2}+\frac{1}{2}{m_2}{v^2}&=\frac{1}{2}{m_2}{\left( {{v_2}} \right)^2}\\{m_1}{v^2}+{m_2}{v^2}&={m_2}{\left( {{v_2}}\right)^2}\\\left( {{m_1}+{m_2}}\right){v^2}&={m_2}{\left( {{v_2}}\right)^2}\\\end{aligned}[/tex]
Simplify the above equation,
[tex]\begin{aligned}{m_2}{\left( {{v_2}} \right)^2}&=\frac{{\left( {{m_1}+{m_2}} \right){v^2}}}{{{m_2}}}\\{v_2}&=\left( {\sqrt {\frac{{\left( {{m_1}+{m_2}} \right)}}{{{m_2}}}} }\right)v\\\end{aligned}[/tex]
Substitute the value of [tex]{v_2}[/tex] in equation (1).
[tex]\begin{aligned}\left( {{m_1} - {m_2}} \right)v&={m_2}\left( {\sqrt {\frac{{\left( {{m_1} + {m_2}}\right)}}{{{m_2}}}} } \right)v \\\left( {{m_1} - {m_2}} \right)&=\sqrt {{m_2}\left( {{m_1} + {m_2}}\right)}\\{m_2}\left( {\frac{{{m_1}}}{{{m_2}}} - 1}\right)&={m_2}\sqrt {\left( {\frac{{{m_1}}}{{{m_2}}} + 1} \right)}\\\left( {\frac{{{m_1}}}{{{m_2}}}-1}\right)&=\sqrt {\left( {\frac{{{m_1}}}{{{m_2}}}+ 1}\right)}\\\end{aligned}[/tex]
Substitute [tex]x[/tex] for[tex]\dfrac{{{m_1}}}{{{m_2}}}[/tex] in above equation.
[tex]\left( {x - 1} \right)=\sqrt {\left( {x + 1} \right)}[/tex]
Squaring both the sides in above equation,
[tex]\begin{aligned}{\left( {x - 1} \right)^2}&=\left( {x + 1}\right)\\{x^2} - 2x + 1&=x + 1\\{x^2}-3x&=0\\\end{aligned}[/tex]
Taking [tex]x[/tex] as a common in the above equation.
[tex]x\left( {x - 3} \right)=0[/tex]
On solving above equation
We get,
[tex]x = 3[/tex]
Replace the value of [tex]x[/tex]
[tex]\boxed{\frac{{{m_1}}}{{{m_2}}} = 3}[/tex]
Or,
[tex]\boxed{\frac{{{m_2}}}{{{m_1}}} = \frac{1}{3}}[/tex]
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Answer details:
Grade: Senior School
Subject: Physics
Chapter: Impulse and Momentum
Keywords:
Head on collision, two particles, equal speed, ratio of particle masses, momentum, conservation of momentum, energy, conservation of energy, masses, ratio.
List three reasons why knowing how to graph movement can help you on a practical level.
Knowing how to graph motion helps in understanding kinematics properties by deriving motion characteristics from the graph, visualizing equations in a comprehendible form, and revealing underlying relationships between physical quantities.
Explanation:Knowing how to graph movement can be practically beneficial for several reasons, these include:
Deriving motion characteristics: By graphing displacement versus time, velocity versus time, and acceleration versus time, you can derive specific and general characteristics of kinematics. For example, the slope of a displacement versus time graph is velocity whereas the slope of a velocity versus time graph represents acceleration. Visualizing Equations: Graphs are an excellent tool to visualize and understand equations. Rather than dealing with complex mathematical expressions, you can express the same information visually through graphs and get a better comprehension of the phenomena. Understanding Underlying Relationships: Graphs do not only present numerical information but also reveal the relationship between different quantities. Hence, they offer a way to interpret and understand the physics underlying the motion. Learn more about Graphing Motion here:
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Communications satellites are placed in a circular orbit where they stay directly over a fixed point on the equator as the earth rotates. these are called geosynchronous orbits. the radius of the earth is 6.37 * 106 m, and the altitude of a geosynchronous orbit is 3.58 * 107 m 1â22,000 miles2. what are (a) the speed and (b) the magnitude of the acceleration of a satellite in a geosynchronous orbit?
The speed of a satellite in a geosynchronous orbit is approximately 2.98 km/s, and the magnitude of the acceleration is approximately 1.92 x 10^-3 m/s^2.
Explanation:To determine the speed of a satellite in a geosynchronous orbit, we can use the formula:
speed = 2 x π x radius / period
Given that the radius of the Earth is 6.37 * 10^6 m and the altitude of a geosynchronous orbit is 3.58 * 10^7 m, we can use the formula to calculate the speed:
speed = 2 x 3.14 x (6.37 * 10^6 + 3.58 * 10^7) / (24 x 60 x 60)
The magnitude of the acceleration of a satellite in a circular orbit can be calculated using the formula:
acceleration = (velocity)^2 / radius
Using the calculated speed and the radius of the orbit, we can find the magnitude of the acceleration:
acceleration = (2.98 x 10^3)^2 / (6.37 * 10^6 + 3.58 * 10^7)
Therefore, the speed of a satellite in a geosynchronous orbit is approximately 2.98 km/s and the magnitude of the acceleration is approximately 1.92 x 10^-3 m/s^2.
A fan that can provide air speeds up to 55 m/s is to be used in a low-speed wind tunnel with atmospheric air at 23ºc. if one wishes to use the wind tunnel to study flatplate boundary layer behavior up to reynolds numbers of rex= 108, what is the minimum plate length that should be used? at what distance from the leading edge would transition occur if the critical reynolds number were rex,c= 5 à 105?
A flowerpot falls off a balcony 85m above the street how long does it take to hit the ground
It will take 4.12 s for the flowerpot to fall to the ground.
From the question given above, the following data were obtained:
Height (h) = 85 m
Time (t) =?NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the flowerpot to fall to the ground can be obtained as follow:
H = ½gt²85 = ½ × 10 × t²
85 = 5 × t²
Divide both side by 5
[tex]t^{2} = \frac{85}{5}\\\\t^{2} = 17[/tex]
Take the square root of both side
[tex]t = \sqrt{17}[/tex]
t = 4.12 sTherefore, it will take 4.12 s for the flowerpot to fall to the ground.
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Renee is on Spring Break and pulling her 21-kg suitcase through the airport at a constant speed of 0.47 m/s. She pulls on the strap with 120 N of force at an angle of 38° above the horizontal. Determine the normal force and the total resistance force (friction and air resistance) experienced by the suitcase.
The normal force is calculated by adding the weight of the suitcase and the vertical component of pulling force, while total resistance force is equal to the horizontal component of pulling force. Both forces play a significant role in Renee's effort to move the suitcase at a constant speed.
Explanation:Here's how to find the normal force and the total resistance force for Renee's suitcase:
Normal Force: The normal force is the force exerted by a surface that supports the weight of an object resting on it. It acts perpendicular to the surface. In this case, there are two components to Renee's force - the horizontal and the vertical. The vertical component of the force can be calculated using the formula F = F_pull*sin(angle), where F_pull is the force with which Renee pulls the suitcase (120 N) and the angle is 38°. After calculating the vertical component of the force, you subtract it from the weight of the suitcase (mass*gravity) to get the normal force. Total Resistance Force: The total resistance force is the force that opposes the motion of the suitcase. In this case, at constant speed, the total resistance force is equal to the horizontal component of the pulling force. This can be calculated using the formula F = F_pull*cos(angle).
Remember, while calculating remember to convert the angle to radians if your calculator is set to radian mode.
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To find the normal force on Renee's suitcase, we resolve the pulling force into its components and subtract the vertical component from the suitcase's weight. As the suitcase is moving at a constant speed, the horizontal component equals the resistance force, which includes both friction and any air resistance.
Explanation:Renee is pulling her 21-kg suitcase at a constant speed of 0.47 m/s through the airport. To determine the normal force acting on the suitcase, we need to consider the components of the pulling force. The force has a magnitude of 120 N and is exerted at an angle of 38° above the horizontal. We must resolve this force into vertical and horizontal components. The vertical component (Fy) helps support the weight of the suitcase and is calculated as Fy = 120 N × sin(38°). The weight of the suitcase is W = m × g, where m is the mass of the suitcase and g is the acceleration due to gravity (9.8 m/s²).
The normal force is given by N = W - Fy since the vertical component of the pulling force acts upwards, reducing the normal force exerted by the ground. As the suitcase is moving at a constant speed, the net horizontal force must be zero. Therefore, the horizontal component of the pulling force, which is Fx = 120 N × cos(38°), must be equal to the total resistance force (friction + air resistance).
The equations to find the normal force and resistance force are:
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What is tarzan's speed vf just before he reaches jane? express your answer in meters per second to two significant figures?
A 1000-kg car traveling at 70 m/s takes 3 m to stop under full braking. the same car under similar road conditions, traveling at 140 m/s, takes ______________ m to stop under full braking.
This physics problem involves the principle of kinetic energy and work-energy. Given the situation presented, the increase in the car's kinetic energy due to a doubling of initial speed means that the braking stopping distance quadruples from 3 meters to 12 meters.
Explanation:This Physics problem concerns the relationship between velocity, mass, and stopping distance under braking conditions. It's dealing with the principle of kinetic energy (1/2*m*v²) and the work-energy principle, which states that the work done on an object is equal to the change in its kinetic energy.
If the initial speed is doubled, as it is in this case from 70 m/s to 140 m/s, the kinetic energy (and thus the work needing to be done to stop the vehicle) quadruples, assuming the mass stays constant. This means, due to the direct relationship between work done and distance when force is held constant, the stopping distance will also quadruple from the original 3 meters.
Therefore, the 1000-kilogram car, when moving at 140 m/s, will take 12 meters to stop under full braking in similar conditions.
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Which is brighter in our sky, a star with apparent magnitude 5 or a star with apparent magnitude 10 ?
People watching their team lose important games often make faces, yell at the screen, and demonstrate general agitation. Although they aren't playing the game themselves, they may be able to experience the frustration felt by the players because of ________________ activity in the brain
Is the 3 in the molecule a coefficient, subscript, or element? 3H₂O₂
Does a person standing motionless in the aisle of a moving bus have kinetic energy
How are stars important to the Milky Way
a hockey player has an acceleration of -3.1m/s2 how long does it take him come to a complete stop from a speed of 13m/s
If a baseball pitch leaves the pitcher's hand horizontally at a velocity of 150 km/h by what percent will the pull of gravity change the magnitude of the velocity when the ball reaches the batter, 18 m away? for this estimate, ignore air resistance and spin on the ball.
A mirror faces a cliff located some distance away. mounted on the cliff is a second mirror, directly opposite the first mirror and facing toward it. a gun is fired very close to the first mirror. the speed of sound is 336 m/s. how many times does the flash of the gunshot travel the round-trip distance between the mirrors before the echo of the gunshot is heard?
The flash travels the round-trip distance approximately 1,000,000 times.
The speed of sound is 336 m/s, and the speed of light (which represents the speed at which the flash travels) is approximately [tex]3\times 10^8 m/s[/tex].
Let's denote the distance between the mirrors as d. The time it takes for the sound to travel the round trip (to the cliff and back) is [tex]2d/336[/tex]seconds. During this time, the flash of light travels at [tex]3\times10^8m/s.[/tex]
To find out how many times the flash of light can travel the round-trip distance before the sound is heard, we calculate:
[tex]\text{Number of round trips}=(3\times10^8\times2d/336)/2d=(3\times10^8)/336\approx1000,000[/tex]
Thus, the flash of the gunshot travels the round-trip distance approximately 1,000,000 times before the echo of the gunshot is heard.
What is the frequency of radiation whose wavelength is 2.40 x 10-5 cm?
A 500 lb steel beam is lifted up by a crane to a height of 100 ft and is held there.
A) How much work is being done to hold the beam in place?
B) How much work was done to lift the beam?
C) How much work would it take if the steel beam were raised from 100 ft to 200ft?
A. How much work is being done to hold the beam in place?
Work is the product of Force and Displacement. Since there is no Displacement involved in just holding the beam in place, hence the work is zero.
B. How much work was done to lift the beam?
In this case, force is simply equal to weight or mass times gravity. Hence the work is:
Work = weight * displacement
Work = 500 lbf * 100 ft
Work = 50,000 lbf * ft
C. How much work would it take if the steel beam were raised from 100 ft to 200ft?
The displacement is still 100 ft since 200 – 100 = 100 ft, hence the work done is still similar in B which is:
Work = 50,000 lbf * ft
Part a consider a bird that flies at an average speed of 10.7 m/s and releases energy from its body fat reserves at an average rate of 3.70 w (this rate represents the power consumption of the bird). assume that the bird consumes 4.00g of fat to fly over a distance db without stopping for feeding. how far will the bird fly before feeding again?
What is the change in the ball's position from t=0s to t=1.0s? express your answer using two significant figures?
What is the wavelength of a photon whose energy is twice that of a photon with a 600 nm wavelength?
The wavelength of the photon having twice the energy as that of the photon of wavelength [tex]600\,{\text{nm}}[/tex] is [tex]\boxed{300\,{\text{nm}}}[/tex] .
Further Explanation:
The photons are the small packets of energy that move at the speed of light. The photons are considered to remain always in motion. The energy associated with a moving photon is given by:
[tex]E = \dfrac{{hc}}{\lambda }[/tex]
Here, [tex]E[/tex] is the energy associated with the photon, [tex]h[/tex] is the Planck’s constant, [tex]c[/tex] is the speed of light and [tex]\lambda[/tex] is the wavelength of the moving photon.
The value of the Planck’s constant is [tex]6.6 \times {10^{ - 34}}\,{\text{J}} \cdot {\text{s}}[/tex] .
The wavelength of the photon is [tex]600\,{\text{nm}}[/tex] .
The energy associated with the photon of wavelength [tex]600\,{\text{nm}}[/tex] is:
[tex]\begin{aligned}{E_1}&=\frac{{\left( {6.6 \times {{10}^{ - 34}}} \right) \times \left( {3 \times {{10}^8}} \right)}}{{600 \times {{10}^{ - 9}}}}\\&=\frac{{1.98 \times {{10}^{ - 25}}}}{{6 \times {{10}^{ - 7}}}}\\&= 3.3 \times {10^{ - 19}}\,{\text{J}}\\\end{aligned}[/tex]
The wavelength of photon having energy double of this:
[tex]\begin{aligned}E' &= 2{E_1}\\&= 2 \times\left( {3.3 \times {{10}^{ - 19}}} \right)\,{\text{J}}\\&{\text{ = 6}}{\text{.6}} \times {\text{1}}{{\text{0}}^{ - 19}}\,{\text{J}}\\\end{aligned}[/tex]
The new wavelength of the photon will be:
[tex]\lambda ' = \dfrac{{hc}}{{E'}}[/tex]
Substitute [tex]6.6 \times {10^{ - 19}}\,{\text{J}}[/tex] for [tex]E'[/tex] in above expression.
[tex]\begin{aligned}\lambda ' &= \frac{{\left( {6.6 \times {{10}^{ - 34}}} \right) \times \left( {3 \times {{10}^8}} \right)}}{{6.6 \times {{10}^{ - 19}}}}\\&=\frac{{1.98 \times {{10}^{ - 25}}}}{{6.6 \times {{10}^{ - 19}}}}\,{\text{m}}\\&= 3.0 \times {10^{ - 7}}\,{\text{m}}\\&= 300\,{\text{nm}}\\\end{aligned}[/tex]
The wavelength of the photon having twice the energy as that of the photon of wavelength [tex]600\,{\text{nm}}[/tex] is [tex]\boxed{300\,{\text{nm}}}[/tex].
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Answer Details:
Grade: Senior School
Subject: Physics
Chapter: Photon and Energy
Keywords: Wavelength, photon, energy, E=hc/lamda, 600nm, twice the energy, Planck’s constant, small packets of energy, 300nm, speed of light.
Which characteristic does an object with a constant acceleration always have?
Explanation:
By definition, the word acceleration is equal to the rate of change of velocity. Mathematically, it is given by :
[tex]a=\dfrac{dv}{dt}[/tex]
[tex]dv=a.dt[/tex]
[tex]v=\int\limits^t_0 {a.dt}[/tex]
Since, it is given that acceleration is constant
[tex]v=at+v_o[/tex]
v₀ is the constant of integration and it corresponds to initial velocity
From above equation, it is clear that when acceleration is constant the speed varies linearly. Hence, when an object move with constant acceleration, it always changes its velocity.
The speed of sound in water is measured to be 1485 m/s. what is this in mph?
Answer:
v = 3321.85 mph
Explanation:
Equivalences :
1 mile = 1609.34 m
1 hour = 3600 seconds
Data
v= 1485 m/s : speed of sound in water
Problem Development
To calculate the speed of sound in mph (mile / hour), we multiply by the conversion factors using the equivalences:
[tex]v= (1485 \frac{m}{s} )*(\frac{1mile}{1609.34 m} )*(\frac{3600s}{hour})[/tex]
We cancel the units in seconds (s) and meters (m) to get the answer in miles per hour (miles / hour or mph)
[tex]v=\frac{1485*3600}{1609.34} \frac{mile}{hour}[/tex]
v= 3321.85 mile/hour
v = 3321.85 mph
on a very muddy football field, a 120 kg linebacker tackles an 75 kg halfback. immediately before the collision, the linebacker is slipping with a velocity of 8.6 m/s north and the halfback is sliding with a velocity of 7.4 m/s east.
The question is about the conservation of momentum. By calculating each player's momentum before the collision and combining them, we find the resultant momentum. The velocity after the collision can then be found.
Explanation:This is an example of conservation of momentum, a fundamental concept in physics. Whenever objects interact and there is no external force, the total momentum of the system of objects is conserved.
In the scenario given, the linebacker and the halfback can be regarded as a closed system because the only significant forces are their mutual ones. Before the collision, we can calculate the momentum for each player: the linebacker's momentum is mass x velocity = 120 kg x 8.6 m/s = 1032 kg.m/s (north), and the halfback's momentum is 75 kg x 7.4 m/s = 555 kg.m/s (east).
Using the law of vector addition, we can combine them to find the resultant momentum. We then divide the resultant momentum by the total mass (120 kg + 75 kg) to find the velocity of the resulting 'player blob' immediately after the collision.
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In general, which of the following is NOT a critical skill for participating in a sport? A. agility and balance B. endurance and muscle control C. hand-eye coordination and acuity D. none of the above
The answer is :D. None of the above
Agility and balance is very important in sport activities such as soccer, especially seen when players dribble the ball at high speed. Endurance and muscle control is very important in sport such as gymnastic or boxing. Hand-eye coordination and acuity is important in sports such as golf.
Answer:
the answer is d none of the above
Explanation:
A small smooth object slides from rest down a smooth inclined plane inclined at 30 degrees to the horizontal. What is (i) the acceleration
For questions 1-10, match the term with the correct phrase it corresponds to, by filling in the blank with the letter of the correct phase
A - Hormone that helps the body control the level of glucose in yhe blood.
B - The main cause of Type 2 Diabetes
C - Condition that makes it hard for the body to control the level of glucose in the blood
D - Damage to the pancreas caused by ones own antibodies
E - The elevation of glucose levels in the blood
F - Found to help with treatment of clinical depression
G - Organ where insulin is produced
H - "Good" cholesterol
I - 90% to 95% of the case of diabetes in America
J - Hardening of the arteries caused by a build up of fatty materials
1 - diabetes
2 - Atherosclerosis
3 - Hyperglycemia
4 - HDL
5 - Obesity
6 - Type 1
7 - Insulin
8 - Type 2
9 - Pancreas
10 - Regular aerobic exercise
These are your answers:
A is Insulin (7)
B is Obesity (5)
C is Diabetes (1)
D is Type 1 (6)
E is Hyperglycemia (3)
F is Regular aerobic exercise (10)
G is Pancreas (9)
H is HDL (4)
I is Type 2 (8)
J is atherosclerosis(2)
Here is why:
A. Hormone that helps the body control the level of glucose in the blood.
Insulin is a hormone. It helps regulate the levels of glucose in the blood by turning glucose into energy. This is why it plays an important role in metabolism. This hormone is produced by the pancreas.
B. Main cause of Type 2 Diabetes
Obesity is the main cause of Type 2 diabetes. Unhealthy eating and lack of exercise are often listed as causes of Diabetes 2, and this kind of lifestyle collectively leads to obesity.
C. Condition that makes it hard for the body to control the level of glucose in the blood.
Diabetes is a condition where the levels of glucose in the blood is high. This happens because the body cannot produce enough insulin, which is the hormone that controls glucose levels.
D. Damage to the pancreas caused by ones own antibodies.
In Diabetes Type 1, the immune system attacks the panceatic beta cells, which produce insulin. Unlike Type 2, Type 1 Diabetes is unavoidable and hereditary. So if you have it, you have it.
E. The elevation of glucose levels in the blood.
Hyperglycemia - Hyper means high or elevated. Gly means glucose or sugar. -cemia means blood. Put together, elevated glucose in the blood.
F. Found to help with treatment of clinical depression
Studies have shown that aerobic exercise can help with clinical depression. It helps elevate moods and lessen tension. This helps relieve stress.
G. Organ where insulin is produced
Like mentioned above, insulin is produced by the pancreas.
H. "Good" Cholesterol
HDL is High-density Lipoprotein. HDL is considered as good cholesterol because it actually assists in removing other forms of cholesterol from the blood.
I. 90% to 95% of the case of diabetes in America
Studies have shown that in America Diabetes 2 is the most common case. Like mentioned above, cause of Diabetes type 2 is eating habits and lack of exercise and many foods today are full of processed sugars and are consumed in great amounts because of convenience.
J. Hardening of the arteries caused by a build up of fatty materials.
Fatty materials create plaque and they accumulate in the blood vessels. This leads to constriction and hardening in arteries specifically. This constriction makes the vessel more narrow and it can limit the flow of oxygen to the other organs of the body.
Twenty students were surveyed to find out how many hours of tv they watch during a school week
Based on the survey of twenty students, the average number of hours watched during a school week is four.
Step 1: Gather Data
- Let's assume we have the following data from the survey:
| Student | Hours of TV watched (per week) |
|---------|--------------------------------|
| 1 | 3 |
| 2 | 2 |
| 3 | 4 |
| ... | ... |
| 20 | 5 |
Step 2: Calculate the Total Hours of TV Watched
- Add up all the hours reported by each student.
Total Hours = 3 + 2 + 4 + ... + 5
Step 3: Calculate the Average Hours
- Divide the total hours by the number of students surveyed.
Average Hours = Total Hours / Number of Students
Now, let's perform the calculations.
Given:
Number of students surveyed (N) = 20
Hours of TV watched by each student:
Student 1: 3 hours
Student 2: 2 hours
Student 20: 5 hours
Step 2: Calculate the Total Hours
Total Hours = 3 + 2 + 4 + ... + 5
Total Hours = (3 + 2 + 4 + ... + 5) (20 times)
We can simplify this by realizing that we're adding the same number (the hours of TV watched by each student) 20 times:
Total Hours = (3 + 2 + 4 + ... + 5) (20 times)
= (3 + 2 + 4 + ... + 5) * 20
Step 3: Calculate the Average Hours
Average Hours = Total Hours / Number of Students
= (Total Hours) / 20
Now, let's find the sum of the hours:
Sum of hours = 3 + 2 + 4 + ... + 5
To find the sum, we can use the formula for the sum of an arithmetic series:
[tex]\[S = \frac{n}{2}(a_1 + a_n)\][/tex]
where:
- (S) is the sum of the series,
- (n) is the number of terms in the series,
- (a_1) is the first term in the series, and
- (a_n) is the last term in the series.
In our case:
(n = 20 (number of students surveyed),
a_1 = 3 (hours of TV watched by the first student), and
a_n = 5 (hours of TV watched by the last student).
[tex]\[S = \frac{20}{2}(3 + 5)\][/tex]
S = 10(8)
S = 80
Now, let's plug this sum into the formula for the average:
Average Hours = Total Hours / Number of Students
= 80 / 20
= 4
So, on average, the students surveyed watch 4 hours of TV during a school week.
complete question :
Twenty students were surveyed to determine the number of hours they watch TV during a school week. The data collected from the survey are as follows (in hours):
3, 5, 8, 2, 4, 6, 7, 5, 3, 9, 10, 1, 4, 7, 8, 6, 5, 2, 3, 7.