Andrew sold 45 tickets to the school play and Sara sold 40 tickets. What is the best ratio of the number of tickets Andrew sold to the number of tickets Sara sold?

No, a rational number is a number that can be expressed in the form of a fraction or "ratio"

yes. if it was 1,000,000.4 it wouldnt be. Basically, if it has a decimal its irrational.

Both are used to understand chance and to collect and analyze numerical data.

Statistical data is used to see if conclusions are true and to make future predictions.

Answer:

The reason is that none of these latter statements accurately reflects the data. Scientific data rarely lead to absolute conclusions.

Step-by-step explanation:

1. If tomorrow is Monday then, today is Sunday.
2. If today is not Sunday then tomorrow is not Monday.
3. If  tomorrow is not Monday then today is not Sunday

If tomorrow is not Monday then today is not Sunday.

The given statement is "If today is Sunday, then tomorrow is Monday".

What is contrapositive statement?

A contrapositive statement occurs when you switch the hypothesis and the conclusion in a statement, and negate both statements. In this example, when we switch the hypothesis and the conclusion, and negate both, the result is: If it is not a polygon, then it is not a triangle.

Here,

1. If tomorrow is Monday then, today is Sunday.

2. If today is not Sunday then tomorrow is not Monday.

3. If tomorrow is not Monday then today is not Sunday.

Therefore, if tomorrow is not Monday then today is not Sunday.

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-3/2 = (-4/7)u - (4/3)

-3/2 + 4/3 = (-4/7)u

-9/6 + 8/6 = (-4/7)u

(-9 + 8)/6 = (-4/7)u

-1/6 = (-4/7)u

(-1/6) * (-7/4) = (-7/4)*(-4/7)u

7/24 = u

The answer: u = 7/24

I had to do several calculations to get the answer.

First I calculated how many points each incorrect answer decreased:

6 questions * x = 30 points => x = 30 points / 6 questions = 5 points / question.

Then I converted it in an equation of the kind:

( ) ( ) = 5

And concluded it was 1/6 * 30 = 5

So, the numbers must be placed on either of these two forms:

( 1/6 ) ( 30) = 5, or

( 30 ) ( 1/ 6) = 5.

Of course, both of them are correct answers.

20 + 15 + 0.65x < = 45
35 + 0.65x < = 45
0.65x < = 45 - 35
0.65x < = 10
x < = 10 / 0.65
x < = 15.3......so the greatest number of games she can play is 15

Answer:  The required inequality is [tex]35+0.65x\leq 45[/tex] and teh maximum number of times that Chelsea can play the game is 15.

Step-by-step explanation:  Given that Chelsea had $45 to spend at the fair. she spends $20 on admissible and $15 on snacks. She wants to play a game that costs $0.65 per game.

We are to write an inequality  to find the maximum number of times, x, Chelsea can play games.

Also, to find the maximum number of times she can play he game.

According to the given information, the inequality can be written as follows :

[tex]20+15+0.65\times x\leq 45\\\\\Rightarrow 35+0.65x\leq 45.[/tex]

And, the solution of the above inequality is as follows :

[tex]35+0.65x\leq 45\\\\\Rightarrow 0.65x\leq 45-35\\\\\Rightarrow 0.65x\leq 10\\\\\Rightarrow x\leq \dfrac{10}{0.65}\\\\\Rightarrow x\leq 15.38.[/tex]

Thus, the maximum number of times Chelsea can play the game is 15.

the blank would be 4 as 4*7 is the same as 7*4

7 x 4=4 x 7

This is known as the commutative property, it basically means when using addition and multiplication the order of the numbers do not matter, because the answer will always turn out the same.

Write this sum as:

[tex]i^{600}+i^{599}+i^{598}+\ldots+i+1=1+i+i^2+i^3+\ldots+i^{599}+i^{600}[/tex]

This is sum of a geometric series with [tex]n=601 [/tex] terms, first term [tex]a=1[/tex] and common ratio [tex]r=i[/tex]. So the sum:

[tex]S=a\dfrac{1-r^n}{1-r}=1\cdot\dfrac{1-i^{601}}{1-i}=\dfrac{1-i\cdot i^{600}}{1-i}=\dfrac{1-i\cdot(i^2)^{300}}{1-i}=\\\\\\=\dfrac{1-i\cdot(-1)^{300}}{1-i}= \dfrac{1-i\cdot1}{1-i}=\dfrac{1-i}{1-i}=\boxed{1}[/tex]

24,000/8= 3,000 balls

The machine produce 3,000 balls per hour.

Hope that helps!

Answer: 3,000 balls per hour

Step-by-step explanation:

Given: The number of plastic balls manufactured by a machine = 24,000

Time taken to manufacture 24,000 plastic balls = 8 hours

To calculate the unit rate , we divide the number of plastic balls by the amount of time taken to produce it, we get

[tex]\text{Unit rate}=\dfrac{\text{Number of plastic balls}}{\text{Time}}\\\\\Rightarrow\ \text{Unit rate}=\dfrac{24,000}{8}\\\\\Rightarrow\ \text{Unit rate}=3,000\text{balls per hour}[/tex]

the Washington monument is 555 feet

555/3.28 = 169.21 meters

Answer:

169.164

Step-by-step explanation:

555 / 3.28 = 169.164

$16.32 is the correct answer.

In expanded form it would be:

(7 x 1) + (0/10) + (4/100) =7.04

if ya meant pi as in π



π is defined as the ratio between the circumference and diameter of any circle

the definition of pi is [tex] \pi=\frac{circumference}{diameter}[/tex]

I'm sure you mean π (pronounce as "pie" and spelled as "Pi"), the sixteenth letter of the Greek alphabet. π is the ratio between a circle's circumference and it's diameter.

well, from 2008 to 2010 is just 2 years, so let's say the initial amount is the 19300 from 2008, how many will it be in 2010?

[tex]\bf \qquad \textit{Amount for Exponential Growth}\\\\ A=I(1 + r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ I=\textit{initial amount}\to &19300\\ r=rate\to 20\%\to \frac{20}{100}\to &0.20\\ t=\textit{elapsed time}\to &2\\ \end{cases} \\\\\\ A=19300(1+0.2)^2[/tex]

Answer: The amount of cars they can expect to wash is 27, 792 in 2010.

Step-by-step explanation:

This problem asks us to calculate the potential growth of the business through a period. One of the ways to solve this problem is to use the formula for exponential growth to determine the number of cars they expect to wash in 2010.

[tex]f(x) = a(1 + r) ^x\\f(x) = 19, 300 (1+0.20)^2\\f(x) = 19, 300 (1.20)^2\\f(x) = 27, 792[/tex]

a = initial growth - 19, 300

r = growth rate - 0.20

x = time (years) - 2 years

We get 27, 792 as our final answer.

The number is 454.

This is because since the ones digit is 4 and the hundreds digit is the same as the ones digit, the hundreds digit is 400.

400 + 50 + 4 = 454

Hundreds digit as ones digit. The value of my tens digit is 50. The value of my ones digit is 4,then the number is 454.

What is Number system?

The system which deals with numbers and decimals is called number system.

The digit at ones place=4

The digit at tens place=50

hundreds digit as ones digit=400

Therefore the number is 400+50+4

=454

Therefore if same hundreds digit as ones digit. The value of my tens digit is 50. The value of my ones digit is 4. Then 454 is the Number.

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Sent a picture of the solution to the problem (s).

The average rate of change for the function is 6 on the interval [10, 60].

What is Lagrange mean value theorem?

Lagrange mean value theorem states that, if a function f is continuous over the closed interval [a, b] and differentiable over the open interval (a, b), then there must be at least one point c in the interval (a, b) where the slope of the tangent at the point c is equal to the slope of the tangent through the curve's endpoints, resulting in the expression f'(c) = {F(b) -F(a)}/(b-a)

According to the attached function graph,

At point x = 10,

F(10) = 400

At point x = 60,

F(60) = 700

Since the formula for the average rate of change of the function between x = a and x = b is,

The average rate of change = {F(b) -F(a)}/(b-a)

Here a = 10, b = 60 and F(10) = 400, F(60) = 700

Substitute the values in the formula,

So the average rate of change = (700 - 400)/(60 - 10)

The average rate of change = 300/50.

The average rate of change = 6

Hence, the average rate of change for the function is 6 on the interval [10, 60].

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Your question is incomplete, probably the missing graph is:

Final answer:

To find the average rate of change of f on the interval [10, 60], calculate the difference between the values of f at these two points and divide it by the difference between the two points.

Explanation:

To find the average rate of change of f on the interval [10, 60], we need to calculate the difference between the values of f at these two points and divide it by the difference between the two points. Let's assume that f(10) = a and f(60) = b. The average rate of change of f on the interval [10, 60] is then given by (b-a)/(60-10). To round the answer to the nearest integer, we can use the nearest neighbor rounding method.

The work done by the weightlifter to lift a barbell and a chain with a total weight of 2,200 N through a vertical distance of 1 meter is 2,200 joules.

The question involves calculating the work done when a weightlifter lifts a barbell from one height to a higher height. To find the work done, we can use the formula W = F  imes d  imes  ext{cos}(\theta), where W is the work, F is the force, d is the distance through which the force acts, and \theta is the angle between the force and the direction of motion. Since the weightlifter is lifting vertically, the angle \theta is 0 degrees, and cos(0) is 1, simplifying the formula to W = F  imes d.

The total weight of the barbell and the chain is the sum of both weights, which is 1,700 N + 500 N = 2,200 N. The barbell is initially 1 meter above the ground and needs to be lifted to a height of 2 meters, so the distance d is 2 m - 1 m = 1 m. Therefore, the work done to lift the barbell and chain is W = 2,200 N  imes 1 m = 2,200 J.

5+2= 7 so 7x7=49 so Shelia will spend $49 dollars on 7 rides

7x2= 14+5=19 Sheila will spend 19

Given the table below of the prices for the Lenovo zx-81 chip during the last 12 months

[tex]\begin{tabular} {|c|c|c|c|} Month&Price per Chip&Month&Price per Chip\\[1ex] January&\$1.90&July&\$1.80\\ February&\$1.61&August&\$1.83\\ March&\$1.60&September&\$1.60\\ April&\$1.85&October&\$1.57\\ May&\$1.90&November&\$1.62\\ June&\$1.95&December&\$1.75 \end{tabular}[/tex]

The forcast for a period [tex]F_{t+1}[/tex] is given by the formular

[tex]F_{t+1}=\alpha A_t+(1-\alpha)F_t[/tex]

where [tex]A_t[/tex] is the actual value for the preceding period and [tex]F_t[/tex] is the forcast for the preceding period.

Part 1A:
Given α ​= 0.1 and the initial forecast for october of ​$1.83, the actual value for october is $1.57.

Thus, the forecast for period 11 is given by:

[tex]F_{11}=\alpha A_{10}+(1-\alpha)F_{10} \\ \\ =0.1(1.57)+(1-0.1)(1.83) \\ \\ =0.157+0.9(1.83)=0.157+1.647 \\ \\ =1.804[/tex]

Therefore, the foreast for period 11 is $1.80


Part 1B:

Given α ​= 0.1 and the forecast for november of ​$1.80, the actual value for november is $1.62

Thus, the forecast for period 12 is given by:

[tex]F_{12}=\alpha A_{11}+(1-\alpha)F_{11} \\ \\ =0.1(1.62)+(1-0.1)(1.80) \\ \\ =0.162+0.9(1.80)=0.162+1.62 \\ \\ =1.782[/tex]

Therefore, the foreast for period 12 is $1.78



Part 2A:

Given α ​= 0.3 and the initial forecast for october of ​$1.76, the actual value for October is $1.57.

Thus, the forecast for period 11 is given by:

[tex]F_{11}=\alpha A_{10}+(1-\alpha)F_{10} \\ \\ =0.3(1.57)+(1-0.3)(1.76) \\ \\ =0.471+0.7(1.76)=0.471+1.232 \\ \\ =1.703[/tex]

Therefore, the foreast for period 11 is $1.70


Part 2B:

Given α ​= 0.3 and the forecast for November of ​$1.70, the actual value for november is $1.62

Thus, the forecast for period 12 is given by:

[tex]F_{12}=\alpha A_{11}+(1-\alpha)F_{11} \\ \\ =0.3(1.62)+(1-0.3)(1.70) \\ \\ =0.486+0.7(1.70)=0.486+1.19 \\ \\ =1.676[/tex]

Therefore, the foreast for period 12 is $1.68




Part 3A:

Given α ​= 0.5 and the initial forecast for october of ​$1.72, the actual value for October is $1.57.

Thus, the forecast for period 11 is given by:

[tex]F_{11}=\alpha A_{10}+(1-\alpha)F_{10} \\ \\ =0.5(1.57)+(1-0.5)(1.72) \\ \\ =0.785+0.5(1.72)=0.785+0.86 \\ \\ =1.645[/tex]

Therefore, the forecast for period 11 is $1.65


Part 3B:

Given α ​= 0.5 and the forecast for November of ​$1.65, the actual value for November is $1.62

Thus, the forecast for period 12 is given by:

[tex]F_{12}=\alpha A_{11}+(1-\alpha)F_{11} \\ \\ =0.5(1.62)+(1-0.5)(1.65) \\ \\ =0.81+0.5(1.65)=0.81+0.825 \\ \\ =1.635[/tex]

Therefore, the forecast for period 12 is $1.64



Part 4:

The mean absolute deviation of a forecast is given by the summation of the absolute values of the actual values minus the forecasted values all divided by the number of items.

Thus, given that the actual values of october, november and december are: $1.57, $1.62, $1.75

using α = 0.3, we obtained that the forcasted values of october, november and december are: $1.83, $1.80, $1.78

Thus, the mean absolute deviation is given by:

[tex] \frac{|1.57-1.83|+|1.62-1.80|+|1.75-1.78|}{3} = \frac{|-0.26|+|-0.18|+|-0.03|}{3} \\ \\ = \frac{0.26+0.18+0.03}{3} = \frac{0.47}{3} \approx0.16[/tex]

Therefore, the mean absolute deviation using exponential smoothing where α ​= 0.1 of October, November and December is given by: 0.157



Part 5:

The mean absolute deviation of a forecast is given by the summation of the absolute values of the actual values minus the forecasted values all divided by the number of items.

Thus, given that the actual values of october, november and december are: $1.57, $1.62, $1.75

using α = 0.3, we obtained that the forcasted values of october, november and december are: $1.76, $1.70, $1.68

Thus, the mean absolute deviation is given by:

[tex] \frac{|1.57-1.76|+|1.62-1.70|+|1.75-1.68|}{3} = \frac{|-0.17|+|-0.08|+|-0.07|}{3} \\ \\ = \frac{0.17+0.08+0.07}{3} = \frac{0.32}{3} \approx0.107[/tex]

Therefore, the mean absolute deviation using exponential smoothing where α ​= 0.3 of October, November and December is given by: 0.107




Part 6:

The mean absolute deviation of a forecast is given by the summation of the absolute values of the actual values minus the forecasted values all divided by the number of items.

Thus, given that the actual values of october, november and december are: $1.57, $1.62, $1.75

using α = 0.5, we obtained that the forcasted values of october, november and december are: $1.72, $1.65, $1.64

Thus, the mean absolute deviation is given by:

[tex] \frac{|1.57-1.72|+|1.62-1.65|+|1.75-1.64|}{3} = \frac{|-0.15|+|-0.03|+|0.11|}{3} \\ \\ = \frac{0.15+0.03+0.11}{3} = \frac{29}{3} \approx0.097[/tex]

Therefore, the mean absolute deviation using exponential smoothing where α ​= 0.5 of October, November and December is given by: 0.097

We are given:  cos theta = 1/3.  Thus, adj side = 1 and hyp = 3.  Using the Pythagorean Theorem to find the length of the opposite side, represented by x.  

1^2 + opp^2 = 3^2, or 1 + x^2 = 9, or x^2 = 8.  Here, x could be either sqrt(8) or -sqrt(8):  sqrt(8) if angle theta is in QI, and -sqrt(8) if in QIV.

Thus, the sine of angle theta could be either sqrt(8)/3 or -sqrt(8)/3.

Answer:

I'm pretty sure the answer for this is ±[tex]\frac{2\sqrt{2} }{3}[/tex]

Step-by-step explanation:

I did the assignment.

Thanks for your question!

8 + 3
11

11-7
4 degrees

Hope this helps!

[tex]\bf 81h^8k^6\quad \begin{cases} 81=9^{1\cdot 2}\\ h^8=h^{2\cdot 4}\\ k^6=k^{3\cdot 2} \end{cases}\implies 9^{1\cdot \stackrel{\downarrow }{2}}h^{\stackrel{\downarrow }{2}\cdot 4}k^{3\cdot \stackrel{\downarrow }{2}}\implies (9^1h^4k^3)^{\stackrel{\downarrow }{2}} \\\\\\ (9h^4k^3)^2[/tex]

The probability that at least 2 people have the same birthday is 29.37%

Further explanation

Probability is the likelihood of an event occurring. Probability is the number of ways of achieving success. Probability is also the total number of possible outcomes.

Suppose there are 30 people at a party. Do you think any two share the same birthday?

Let's use the random-number table to simulate the birthdays of the 30 people at the party, ignoring leap year.

Let's assume that the year has 365 days. number the days, with 1 representing January 1, 2 representing January 2, and so forth, with 365 representing December 31.

Draw a random sample of 30 days (with replacement). These days represent the birthdays of the people at the party. Would you expect any two of the birthdays to be the same?

[tex]1^{st} people = \frac{365}{365} \\ 2^{nd} people = \frac{364}{365} \\ 3^{rd} people = \frac{363}{365}[/tex]

For 30 people

365! = 365*364*363*...336

So

[tex]= \frac{365*364*363*...336}{(365^{30})}  =  \frac{365!}{(365^{30})}[/tex]

[tex]\frac{365!}{(365^{30})}[/tex] [tex]= \frac{365!/(365-30)!}{365^{30}}[/tex]

[tex]= \frac{365!/335!}{365^{30}} \\ = 0.2937 = 29.37%[/tex]

The probability that at least 2 people have the same birthday is 29.37%

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Answer details

Grade:  9

Subject:  mathematics

Chapter:  probability

Keywords: the same birthday, probability, random sample, party, simulate

4.

12 - 8 = 4

Hope this helps!

2/12 is the probbability

Greetings!

To find equivalent ratios, you must divide/multiply both terms of the ratio by the same number:

Examples:
1) 14*2=28
2*2=4
28:4

2) 14/2=7
2/2=1
7:1

3) 14*100=1400
2*100=200
1400:200

Hope this helps.
-Benjamin

The building in the sketch will be 10.25 inches long.

Answer:

10.25 inches in the sketch

Step-by-step explanation:

Since we are talking about scales drawing, we can solve this problem using proportions, the ratio John will use is 25:1. We will write the proportion using this information and then we will solve for x.

[tex]\frac{25}{1} =\frac{256.25}{x} \\x=256.25/25\\x=10.25[/tex]

Therefore, the building will be 10.25 inches in the sketch.

The current definition of the standard meter of length is based on the distance traveled by light in a vacuum. The speed of light in a vacuum is 186,282 miles per second and in kilometers it is 299,792 kilometers per second. According to the SI unit (which is the international standard unit system for the measurements), the unit of length is meter.

To solve this, we simply need to break down the problem. Doing this will yield us the correct equation.

"8.46 less than"
This shows we are going to have something subtracted by 8.46.
-8.46

"the product of"
This shows we will have a multiplication problem.
*-8.46

"42 and x"
This shows the values that we will be multiplying
42*x-8.46

Now we can simplify
42x-8.46

Using the logic above, we can see that the expression to represent the phrase is 42x-8.46.

Final answer:

The algebraic expression for the word phrase '8.46 less than the product of 42 and x' is '42x - 8.46'. The phrase 'less than' means to subtract the number from the result of the multiplication.

Explanation:

The process of writing an algebraic expression involves converting the given word phrase into mathematical symbols and operations. In this case, the word phrase is '8.46 less than the product of 42 and x'. 'Product' in mathematics means multiplication so 'the product of 42 and x' could be written as '42x'. 'Less than' means to subtract, but the order matters. '8.46 less than' means we subtract 8.46 from our product, not the other way around. Therefore, the algebraic expression for this word phrase is '42x - 8.46'.

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