an object travels a distance of 6 m in 2 seconds if average speed is found using the equation distance traveled/ elapsed time what is the average speed of the object be sure to include units in your answer​

Answers

Answer 1

Answer:

3 m/s

Explanation:

average  speed = distance traveled / total time taken

                           = 6m/ 2s

                           = 3 m/s


Related Questions

a bowling ball rolled with a force of 15N accelerates at a rate of 5 m/sec^2 a second ball rolled with the same force accelerates 4 m/sec^2 . what are the mass of the two balls.

Answers

Answer:

3

3.75

Explanation:

First ball

Givens

a = 5m/s^2

m = ??

F = 15N

Formula

F = m*a

Solution

15 = m * 5

15/5 = m

m = 3 kg

Second ball

Givens

a = 4m/s^2

m = ??

F = 15N

Formula

F = m*a

Solution

15 = m * 4

15/4 = m

m = 3.75 kg

• Most of the galaxies in the universe are moving away from
Earth. Suppose a particular galaxy emits orange light with
a frequency of 5.00 * 1014 Hz. If the galaxy is receding
from Earth with a speed of 3325 km/s, what is the
frequency of the light when it reaches Earth?
• A) 4.945 x 1014 Hz
• B) 5.542 1012 Hz
• C) 5.055 1014 Hz​

Answers

Final answer:

The frequency of light changes when it is emitted from a moving source. When a galaxy is moving away from Earth, the light it emits becomes redshifted, meaning the frequency decreases. In this case, the observed frequency when the light reaches Earth is approximately 4.945 * 10^14 Hz. Option a is correct.

Explanation:

The frequency of light changes when it is emitted from a moving source. This change in frequency is known as the Doppler effect. When a galaxy is moving away from Earth, the light it emits becomes redshifted, meaning the frequency decreases. To calculate the new frequency, we can use the formula f' = f/(1+v/c), where f' is the observed frequency, f is the emitted frequency, v is the speed of the galaxy, and c is the speed of light.

In this case, the galaxy is moving away from Earth with a speed of 3325 km/s. The emitted frequency is 5.00 * 10^14 Hz. Plugging these values into the formula, we get f' = 5.00 * 10^14 Hz / (1 + 3325 km/s / 3 * 10^5 km/s). Simplifying this expression, we find that the observed frequency when the light reaches Earth is approximately 4.945 * 10^14 Hz.

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A) 4.945 x [tex]10^{14}[/tex] Hz is correct option. Using the Doppler effect formula, we calculate the observed frequency of the light from a galaxy receding at 3325 km/s.

To determine the frequency of light from a receding galaxy as observed on Earth, we use the Doppler effect formula for light:

[tex]f_{obs}[/tex] = [tex]f_{em}[/tex] x (1 - v/c)

Where:

[tex]f_{obs}[/tex] is the observed frequency[tex]f_{em}[/tex] is the emitted frequency (5.00 x [tex]10^{14}[/tex] Hz)v is the recession speed of the galaxy (3325 km/s or 3325000 m/s)c is the speed of light (3.00 * 108 m/s)

Let’s substitute the values into the formula:

[tex]f_{obs}[/tex] = 5.00 x [tex]10^{14}[/tex] Hz x (1 - 3325000 m/s / 3.00 x [tex]10^{8}[/tex] m/s)

[tex]f_{obs}[/tex] = 5.00 x [tex]10^{14}[/tex] Hz x (1 - 0.01108333)

[tex]f_{obs}[/tex] ≈ 4.945 x [tex]10^{14}[/tex] Hz

Therefore, the frequency of the light observed on Earth is 4.945 x [tex]10^{14}[/tex] Hz.

I got part c right but idk why the other parts are wrong HELP!

Answers

a) The impulse is 76.5 Ns

b) The average force is 546.4 N

c) The final speed is 31.5 m/s

Explanation:

a)

The impulse exerted on an object is defined as

[tex]J=\int F\Delta t[/tex]

where

F is the magnitude of the force exerted on the object

[tex]\Delta t[/tex] is the time interval during which the force is applied

If we consider a graph of the force applied vs time, it follows that the impulse exerted is equal to the area under the graph.

Therefore, in this problem, we can calculate the impulse by computing the area under the graph. We have a trapezium, whose bases are

[tex]B=0.14-0 = 0.14s\\b=8-5=3s[/tex]

and whose height is

[tex]h=900 N[/tex]

Therefore, the area (and the impulse) is

[tex]J=\frac{(B+b)h}{2}=\frac{(0.14+0.03)(900)}{2}=76.5 Ns[/tex]

b)

In this problem, the force applied is not constant. However, we can rewrite the impulse also as

[tex]J=F_{avg} \Delta t[/tex]

where

[tex]F_{avg}[/tex] is the average force exerted during the whole time [tex]\Delta t[/tex]

In this problem we have

J = 76.5 Ns is the impulse (calculated in part a)

[tex]\Delta t = 0.14 s[/tex] is the time interval

Solving for the average force, we find

[tex]\Delta t = \frac{J}{F_{avg}}=\frac{76.5}{0.14}=546.4 N[/tex]

c)

According to the impulse theorem, the impulse exerted on an object is equal to the change in momentum of the object:

[tex]J=\Delta p = m(v-u)[/tex]

where

m is the mass of the object

v is the final velocity

u is the initial velocity

In this problem, we have

J = 76.5 Ns

m = 3.0 kg is the mass

u = 6.0 m/s is the initial velocity

Solving for v, we find the final velocity (and speed):

[tex]v=u+\frac{J}{m}=6.0+\frac{76.5}{3}=31.5 m/s[/tex]

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What factors does weight depend on?

Answers

Answer:

m, g

Explanation:

G=m.g

m mass

g gravity

The steel ball rolls 2,862 meters in 347 seconds twords the south.what is the steel ball velocity

Answers

Answer:

8.25 m/s

Explanation:

From the fundamental equation of motion, velocity is rate of change of displacement per unit time

[tex]Velocity=\frac {Displacement}{time}[/tex]

Given information

Displacement=2862 m

Time=347 s

Substituting the given information we obtain

[tex]Velocity=\frac {2862 m}{347 s}=8.247838617\approx 8.25 s[/tex]

Which of the following is an example of matter?


(A) materials that make up the stars
(B) air
(C) metals, gems and minerals
(D) all of the above

Answers

Answer:

(D) all of the above

Explanation:

All of the choices describe matter.

D cause I learned this in the 5th grade and some how remember this (I think because it’s all up in space)

A punter kicks a football from the ground with a velocity of 19 m/s at an angle 32 degrees from the horizontal the football travels a horizontal distance of 33m before it hits the ground what is the maximum height the football reaches

Answers

Answer: 5.17 m

Explanation:

The football reaches its maximum height when the vertical component of the velocity is zero:

[tex]V_{y}=0 m/s[/tex]

This is exactly at the point where the football stops and then begins to fall thanks to the acceleration due gravity.

So, we can use the following equation:

[tex](V_{y})^{2}=(V_{oy})^{2}-2gy_{max}[/tex]

Where:

[tex]V_{y}=0[/tex] is the final velocity

[tex]V_{oy}=V_{o} sin(32\°)[/tex] is the vertical component of the initial velocity

[tex]V_{o}=19 m/s[/tex] is the initial velocity

[tex]g=9.8 m/s^{2}[/tex] is the acceleration due gravity

[tex]y_{max}[/tex] is the football's maximum height

Isolating [tex]y_{max}[/tex]:

[tex]y_{max}=\frac{(V_{o} sin(32\°))^{2}}{2g}[/tex]

[tex]y_{max}=\frac{(19 m/s sin(32\°))^{2}}{2(9.8 m/s^{2})}[/tex]

Finally:

[tex]y_{max}=5.17 m[/tex] This is the football's maximum height

The law of inertia states that an object
a. will continue moving at the same velocity unless an outside force acts on it.
b. will continue moving in a straight line unless an outside force acts on it.
c. that is not moving will never move unless a force acts on it.
d. at rest will remain at rest unless acted on by an outside force.
2. will do all of the above.

Answers

The law of inertia states that an object:

e. Will do all of the above.

Why?

Newton's First Law or the Law of inertia, states that an object at rest will always remain at rest if a force does not act on/upon it. Also, when an object is moving describing a straight line, if a force does not act upon it, it will keep the motion forever.

According to the Law, if an object is moving at constant velocity (same speed and same direction) it will keep the motion unless an outside force acts on it.

So, the correct option will be:

e. The object will do all of the above options.

Have a nice day!

Final answer:

The law of inertia states that an object at rest will remain at rest unless acted on by an outside force, while an object in motion will continue moving in a straight line at a constant speed unless acted on by an outside force.

Explanation:

The law of inertia, also known as Newton's first law of motion, states that an object at rest will remain at rest unless acted on by an outside force. Similarly, an object in motion will continue moving in a straight line at a constant speed unless acted on by an outside force. This law applies to all objects and is a fundamental principle in physics.

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Match the vocabulary terms to their definitions.

1. distance a measurement that has both magnitude and direction
2. velocity the net change in position of an object
3. displacement the rate and direction at which an object moves
4. vector the length along a path between two points
5. speed measure of the rate at which an object changes position
6. momentum the mass of an object multiplied by its veloci

Answers

Answer:

Distance-           The length along a path between two points .

Velocity-            The rate and direction at which an object moves .

Displacement-  The net change in position of an object .

Vector-               A measurement that has both magnitude and direction .

Speed-               Measure of the rate at which an object changes position .

Momentum-      The mass of an object multiplied by its velocity.

Explanation:

Vector: A physical quantity having both magnitude and direction is called Vector quantity. Example: Displacement, Velocity, Acceleration, Force etc.

On the other hand , quantity having only magnitude is called Scalar. Example: Distance, Speed, Time, Current etc.

Distance: The totle length of path traversed by a body in certain time is called distance. It is scalar quantity as it has only magnitude. SI unit of distance is meter.

Displacement: It is defined as change in position of a body in given period of time. Actually it is the distance between initial and final position along with given direction. So it is vector quantity. SI unit is meter.

Speed: The rate at which distance is traveled with respect to time is called speed.It is scalar quantity. SI unit is meter/second.

                                    [tex]Speed=\frac{Distance}{Time}[/tex]

Velocity: It can be defined as rate of change in position or displacement with respect to time.It is vector quantity. SI unit is meter/second.

                                    [tex]Velocity=\frac{Displacement}{Time}[/tex]

Momentum: The amount of motion contain in a body is the momentum. It is defined as product of mass and velocity. It is vector quantity. SI unit is kg.meter/second

                                    Momentum=Mass×Velocity

Answer: The answer above is correct! I got 100% :))

Explanation:

What is the horizontal acceleration of a ball taht is launched horizontally with a velocity of 5.6 m/s?

Answers

Answer:

Horizontal acceleration=0

Explanation:

Horizontal Launching

When an object is launched horizontally at a certain speed [tex]v_o[/tex], only one force will be acting throughout the whole duration of the motion: the force of gravity. If no effect of the wind is to be considered, then the horizontal speed will not change over time. It means the horizontal acceleration is zero. Please note the vertical acceleration is not zero, it is in fact, the acceleration of gravity (0.8 m/sec^2)

how much pressure is exerted by an 100n man with a shoe area of O.05cm square

Answers

Answer:

Pressure = 20 MPa

Explanation:

Given:

Force acting on the shoe is, [tex]F=100\ N[/tex]

Area of shoe on which the force acts is, [tex]A= 0.05\ cm^2[/tex]

Now, first we convert the area into its standard unit of m².

We have the conversion factor as:

1 cm² = [tex]10^{-4}\ m^2[/tex]

Therefore, the area of shoe in square meters is given as:

[tex]A=0.05\times 10^{-4}\ m^2\\A=5\times 10^{-6}\ m^2[/tex]

Now, pressure on the shoe is given as:

[tex]P=\frac{Force}{Area}\\P=\frac{F}{A}[/tex]

Plug in 100 N for 'F', [tex]5\times 10^{-6}[/tex] for 'A' and solve for 'P'. This gives,

[tex]P=\frac{100\ N}{5\times 10^{-6}\ m^2}\\P=20\times 10^{6}\ N/m^2[/tex]

Now, we know that,

[tex]10^{6}\ N/m^2=1\ MPa\\\therefore 20\times 10^{6}\ N/m^2=20\times 1\ MPa=20\ MPa[/tex]

Therefore, the pressure acting on the shoe is 20 MPa.

Which of the following statements about earthquakes is true?

A)Earthquakes and volcanic eruptions always occur at the same time.
B)Earthquakes can only occur on dry land or under water at depths less than 100 meters.
C)Earthquakes occur at regular intervals, usually every five years.
D)The date of future earthquakes cannot be precisely predicted.

Answers

Answer:

Option D)The date of future earthquakes cannot be precisely predicted.

Explanation:

Natural disasters take place without being able to be precisely predicted at times. For example, the volcanoes can more or less likely to be predicted due to the plate tectonics and profiling the history of the volcano.

However, earthquakes cannot be predicted. For example, the massive earthquake in Lisbon in Portugal hit unexpectedly. In addition, Japan was hit by an earthquake which could not be predicted. Thus, an earthquake's future is unpredictable.

Final answer:

D) The correct statement is that the date of future earthquakes cannot be precisely predicted. This is due to the complexity of the geological processes involved, which also explains why the other statements are false.

Explanation:

Among the given statements, it is true that the date of future earthquakes cannot be precisely predicted (Option D). This is due to the complex nature of geological processes. Volcanic eruptions and earthquakes do not always coincide (Option A).

Earthquakes can occur not only on dry land but also under water, at much greater depths than 100 meters (Option B). Earthquakes also do not occur at regular, predictable intervals (Option C).

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Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objects is doubled,
what is the new force of attraction between them?
A. 2.5 newtons
B. 5newtons
C. 20 newtons
D. 100 newtons

Answers

Answer:

20N option C

Explanation:

10× 2


C. 20 Newton’s because 10*2

8. What are the two types of friction and what is the difference?

Answers

Answer:

There are more than 2 but you are probably thinking of kinetic and static friction.  Kinetic friction is the friction between objects as they are moving.  Static friction keeps something in place and resists the movement.  Static friction can be overcome by force to move the object.

Explanation:

Iron combines with oxygen and water from the air to form rust. If an iron nail were
allowed to rust completely, one should find that the mass of the rust:

Answers

Final answer:

According to the Law of Conservation of Mass, the mass of the rust should be greater than the original mass of the iron nail, because the mass of the oxygen and water that form the rust are added to the mass of the iron nail.

Explanation:

The principle at play here is the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a chemical reaction. In this scenario, an iron nail is reacting with oxygen and water from the environment to form rust, or iron(III) oxide.

If the nail were left to rust completely, the mass of the rust would be greater than the original mass of the nail. This is because the mass of the oxygen and water that combines with the iron is added to the mass of the nail to form the rust. The additional mass comes from the oxygen atoms in the air and in the water that combine with the iron atoms in the nail.

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Find the distance between each pair of points.
6 units
5 units
2 units
4 units
3 units
E(-2, -1) and F(-2, -5)
arrowRight
C(-4, 1) and D(1, 1)
arrowRight
G(3, -5) and H(6, -5)
arrowRight
A (5, 4) and B( 5, -2)
arrowRight

Answers

The distances are:

- E and F: 4 units.

- C and D: 5 units.

- G and H: 3 units.

- A and B: 6 units.

Why?

We can find the distance between each pair of points using the following formula:

[tex]d(P_1,P_2)=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}[/tex]

So, calculating we have:

- E(-2, -1) and F(-2, -5):

[tex]d(E,F)=\sqrt{(-2-(-2))^{2}+(-5-(-1))^{2}}\\\\d(E,F)=\sqrt{0+(-5+1)^{2}}=\sqrt{0+(-4)^{2}}=\sqrt{16}=4units[/tex]

- C(-4, 1) and D(1, 1):

[tex]d(C,D)=\sqrt{(1-(-4))^{2}+(1-(1))^{2}}\\\\d(C,D)=\sqrt{(5)^{2}+0^{2}}=\sqrt{25+0}=\sqrt{25}=5units[/tex]

- G(3, -5) and H(6, -5):

[tex]d(G,H)=\sqrt{(6-(3))^{2}+(-5-(-5))^{2}}\\\\d(G,H)=\sqrt{(3)^{2}+0^{2}}=\sqrt{9+0}=\sqrt{9}=3units[/tex]

- A(5, 4) and B( 5, -2):

[tex]d(A,B)=\sqrt{(5-(5))^{2}+(-2-(4))^{2}}\\\\d(A,B)=\sqrt{0+(-6)^{2}}=\sqrt{0+36}=\sqrt{36}=6units[/tex]

Have a nice day!

Answer:

G(3, -5) and H(6, -5) ------>3 units

arrowRight

E(-2, -1) and F(-2, -5)------->4 units

arrowRight

A (5, 4) and B( 5, -2)------->6 units

arrowRight

C(-4, 1) and D(1, 1)---------->5 units

arrowRight

Explanation:

23. Imagine a ball on a track where no energy is transferred between the ball and the track
or between the ball and the air around it. The ball starts from rest at the position labeled B
and moves along the track toward Positions D, E, F, and G. Place a dot on the highest
position the ball will reach before stopping and going back down the track. Explain why the
ball stop at that position? (Remember that no energy is transferred between the ball and the
track or between the ball and the air around it.)

Answers

Final answer:

In the given physics problem, the ball comes to a stop at the highest point. This is because it has transformed all of its kinetic energy into potential energy, and has no more energy to continue moving upwards, as there is no energy transfer with either the track or the air.

Explanation:

In this physics problem, the ball on the track is an example of a system that conserves energy. Since there is no energy transfer with either the track or the surrounding air, the total mechanical energy of the ball, which comprises potential and kinetic energy, remains constant throughout its motion. Potential energy is energy due to height, and kinetic energy is energy due to motion.

To place the dot at the highest point the ball will reach, you identify where the ball has maximum potential energy and minimum kinetic energy because at the highest point, the ball momentarily stops and hence, kinetic energy is zero.

Therefore, the ball will stop at the highest point because it has converted all its kinetic energy (energy of motion) into potential energy (energy stored due to its position) and has no more energy left to continue moving upwards. At this point, it starts converting its potential energy back into kinetic energy as it moves downwards, hence it starts moving back down the track.

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The ball will reach the highest position at the same height as position B because of the conservation of mechanical energy. At this point, all kinetic energy converts back to potential energy, causing the ball to momentarily stop before reversing direction. This principle assumes no energy losses in the system.

To determine the highest position the ball will reach on the track before stopping and reversing direction, we need to consider the conservation of energy principle. In this scenario, the total mechanical energy (sum of potential and kinetic energy) remains constant because no energy is transferred between the ball and the track or the air.

When the ball starts from rest at position B, it possesses only potential energy and no kinetic energy. As the ball moves downward, it loses potential energy but gains kinetic energy, and as it moves upward, it loses kinetic energy and gains potential energy. The ball will reach the same height on the opposite side of the track as it started, assuming no energy losses. Therefore, the highest position the ball will reach will be the same height as position B.

The ball stops at this highest position because all of its kinetic energy is converted back to potential energy at that point, making its speed momentarily zero before it reverses direction. This illustrates the conservation of mechanical energy where the initial and final heights are the same when no external forces are acting on the system.

The apparent shift in measurement is called accurate meniscus parallax precision

Answers

Answer:
Parallax
Reason:
Parallax is the effect whereby the position or direction of an object appears to differ when viewed from different positions, e.g. through the viewfinder and the lens of a camera.

The apparent shift in measurement is called Parallax.

What is Parallax in physics?

Parallax is a displacement or difference in the apparent position of an object viewed along two different lines of sight, and is measured by the angle or semi-angle of inclination between those two lines.

Parallax is the apparent shift of an object's position relative to more distant background objects caused by a change in the observer's position.

In other words, parallax is a perspective effect of geometry.

The apparent shift of an observed object's position resulting from a change of perspective is called "parallax." With the previous demonstration, we've established an inverse relationship.

The closer the object, the greater the parallax angle. We can apply the same principle to the stars.

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will mark as brainliest if correct!!!!!!!!!!!!!!!!!!!!!!!!!
When light is reflected, the "incoming" ray is also called the _____ ray.
A. incident
B. reflected
C. bouncing
D. electromagnetic

Answers

Answer: A (Incident ray).

Explanation:

A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward. If friction is neglected, what would be the speed of the roller coaster at the bottom of the drop?

17.60 m/s
24.90 m/s
49.79 m/s
70.42 m/s

Answers

Answer:

Speed at the bottom of the roller coaster = 49.79 m/s

Explanation:

A new ride being built at an amusement park includes a vertical drop of 126.5 meters. Starting from rest, the ride vertically drops that distance before the track curves forward.

We have to find the speed at the bottom.

Here the gravitational energy fully converts to kinetic energy, so we equate it.

Gravitational energy = [tex]m\times g\times h[/tex]

Kinetic energy = [tex]0.5 \times m\times v^{2}[/tex]

[tex]m\times g\times h[/tex] = [tex]0.5 \times m\times v^{2}[/tex]

[tex]9.8\times 126.5 = 0.5\times v^{2}[/tex]

[tex]v^{2}[/tex] = 2479.4

Velocity, v = 49.79 m/s

Why is it important to cite units when engaging in scientific conversation / problem solving?

Answers

It is really important to cite units while engaging with scientific problems as they help in evaluating the right solution without any mistake.

Explanation:

While solving analytical questions to evaluate the right answers, the units play a crucial role in the equations. With the help of units in the formula, we can easily judge whether we are placing the values in the same parameters and hence, lessen the probabilities of wrong answers.

For example, while adding two measurements i.e. 4 m and 36 cm; if we don't consider the units and move on with the addition, the answer will be 40. Now, the first thing is that we are adding two measurements of different parameters. Besides this, the answers will be wrong i.e. 4.36 m is the correct answer instead of 40 and that too without mentioning the unit.

The chances of selecting the wrong answer are more when we need to choose options out of multiple choices because here we often get confused. That's why we should always make sure that we approach the scientific questions along with the units.


Scientists measure the time between the arrival of an earthquake's _______ and _______ waves to help determine the distance between the recording seismograph and the earthquake epicenter.

Answers

Scientists measure the time between the arrival of an earthquake's __P____ and ___S____ waves to help determine the distance between the recording seismograph and the earthquake epicenter.

Explanation:

P- (compressional) and S- (shear) waves produced in earthquakes travel at different speeds. P waves are faster than S waves and hence will be detected first by a seismograph after an earthquake. The further away a seismograph is from the epicenter of an earthquake,  the longer the time difference between the two (2) waves will be.

Using several, at least 3, seismographs located at different geoghraphical locations and detecting earthquakes, geologists can extrapolate the epicenter of an earthquake using the time differences in arrivals of the two waves in each of the seismographs, using the mathematics of triangulation.

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Final answer:

The time between the arrival of P waves and S waves, recorded by seismographs, is used to determine the distance to an earthquake's epicenter, with the precision being affected by the accuracy of wave speed and arrival time measurements.

Explanation:

Scientists gauge the distance to an earthquake's epicenter by measuring the time between the arrival of an earthquake's P waves and S waves. Seismographs can record these waves with a precision of 0.100 seconds. Given that P waves travel at 7.20 km/s and S waves travel at 4.00 km/s, the time difference recorded on seismograms allows scientists to calculate the distance to an epicenter with considerable accuracy. However, the precision of this distance measurement can be limited by the exactitude of the wave speed measurements and the timing of their arrivals.

Furthermore, the tracking of seismic waves can also be significant for monitoring underground nuclear tests. If there is uncertainty in the speeds of S and P waves, or in the measurement of their arrival times, this poses a limitation in accurately determining the source of seismic energy, which could hinder detection capabilities for such underground activities.

A motorcyclist travels 50 miles with an average speed of 40 mph and then another 20 miles with an average speed of 55 mph. What was the average speed of the cyclist over the entire 70 miles?

Answers

Answer:

43.48 mph

Explanation:

We are given;

First instance;

Distance = 50 miles Speed = 40 mph

Second instance;

Distance = 20 miles Speed = 55 mph

We are required to determine the average speed for the entire journey.

Average speed = Total distance ÷ total time We need to calculate time;

Time = Distance ÷ speed

First instance

Time = 50 miles ÷ 40 mph

        = 1.25 hours

Second instance;

Time = 20 miles ÷ 55 mph

        = 0.36 hours

Therefore;

Total distance = 70 miles

Total time = 1.25 hrs + 0.36 hr

               = 1.61 hrs

Thus;

Average speed = 70 miles ÷ 1.61 hrs

                          = 43.478 miles per hour

                          = 43.48 mph

what is the work done by a force equivalent to the weight of 100kg that moves an object in 7 minutes?​

Answers

Answer:

7000 Joules

Explanation:

We are given;

The mass of an object = 100 kg

But, Force = mass × g (taking g as 10 N/kg)

Then, Force = 1000 N

Assuming we are given the distance moved by the object as 7 m

We can calculate the work done by the force

We need to know that;

Work done = Force × distance

Therefore;

Work done = 1000 N × 7 m

                   = 7000 Joules

Therefore, the work done by the force is 7000 Joules

1. Complete the table with the appropriate equivalences

Scientific notation
Order of magnitude
Look the picture there’s a example

Answers

Answer:

The different values are in the located in the word document

Explanation:

In the attached document in  word, we can find each of the conversion for each one of the quantities.

You apply a horizontal force of 200N against a 50kg couch. The force of friction between the couch and the floor is 180N. If the couch is pushed 2 metres, the kinetic energy gained by the couch is: a) 0 b) 40 J c) 100 J d) 360 J e) 400 J

Answers

Answer:

The kinetic energy gained is 40[J]

Explanation:

This is a problem that applies the work and energy conservation. We must analyze the initial and final positions as well as the forces that act on the couch during displacement.

The working and energy conservation theorem says:

[tex]E_{k1} + W_{1-2}= E_{k2}[/tex]

The above equation tells us that kinetic energy plus the work done to move an object from one position to another will be equal to kinetic energy in the last position.

The kinetic energy in the initial position is zero since the couch is at rest, Ek1=0

The work will be given by the force that drives the couch multiplied by the distance, and the friction force that acts in the opposite direction to the displacement.

[tex]0+(200-180)*2= Ek2\\Ek2=20*2= 40 [J][/tex]

If we increase the distance traveled when doing work, and keep all other factors the same, what will happen?
A) The amount of force will go down
B) The amount of force will increase.
C) The amount of work will decrease
D) The amount of work will increase

Answers

Answer: D

Explanation:

A -amount of work

F-force

s-distance

If you keep same Force(F) and increase distance(s), amount of work will increase, according to:

A=F*s

Answer:

D) The amount of work will increase

Explanation:

Took test

in which type of wave are vibrations at right angles to the direction in which the wave is travelling​

Answers

Answer:

longitudinal waves have those properties

The gravitational force of attraction between Earth and the Sun
is 3.52 x 1022 newtons. Calculate the mass of the Sun. [Show all
work, including the equation and substitution with units.]

Answers

Final answer:

To calculate the Sun's mass, we use the formula for gravitational force, substitute the given and known values, and then rearrange the equation to solve for the Sun's mass.

Explanation:

The question involves the calculation of the Sun's mass using the known gravitational force between Earth and the Sun. Given that, the formula used to calculate the gravitational force between two objects is: F = G * m1 * m2 / r^2, where.

Substitution and rearranging the formula results in: m2 = F * r^2 / (G * m1) which substituting the given and known values, delivers the estimated mass of the Sun.

Learn more about Gravitational Force here:

https://brainly.com/question/32609171

#SPJ12

Add these measurements, using significant digit rules:

1.0090 cm + 0.02 cm = cm

Answers

Answer:  " 1.03 " .

____________________________________

Explanation:

_____________________________________

When we add "measured" or "obtained values" ; the rules for "signficant digits" (also known as "significant figures" ; or "sig figs")  are different from the rules we use when we multiply "measured or obtained values".

We are given 2 (two) "measured or obtained values" ; and we are asked to add these values together using the "significant digit rules.

In this case, we add up the "sum total value" of all the values—Not taking into account the number of significant figures.  Then, we take that "sum value" ; and we round that value to the number of "decimal places" that corresponds to the the number of decimals places in the "measured/obtained valued" that occurs in the value using to calculate the sum —the one that also happens to have the least number of significant digits among all the values used to calculate the "sum total".

As such:

_____________________________________

              1.0090 cm

+            0.02      cm          

      ________________    

           1.0290  cm.                                    

                                   

 →  Now, there were two (2) values used to calculate the "sum total" ;

1)  1.0090 cm ; which has 5 (five) significant digits.

2)  0.02 cm ;  which as 1 (one)  significant digits.

_____________________________________

 So, " 1" is less than "5" ;  so:  " 0.02" is the value within the calculations used to find the sum total — that has the "least" number of significant digits.    

  →  " 0.02 " ;  happens to have 2 (two) decimal spaces.

_____________________________________

So, we take the "sum total" :

      →   "  1.0290 cm " ;

      →  And round this number to:  " 2 (two) decimal places:

            → 1.029... ;  

      →  If the number after the second decimal place is from "1 to 4" ; we round down.  If the number after the second decimal place is

from "5 and 9" ; to round up.  Since the third decimal place is:  "9" ;

  [Note:  " 1.029.." ;  is between "5 to 9" } ; we round up:

→  The answer is:  " 1.03 " .

_____________________________________

Hope this is helpful to you!

     Wishing you the best!

_____________________________________

 

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