The question involves using the free fall equation to calculate the positions of an object falling from rest every second, from the top of a tower. The positions calculated are 4.9m, 19.6m, 44.1m, 78.4m and 122.5m for each of the 5 seconds. On the position-time graph, the points would be plotted and connected by a curved line, indicating acceleration.
Explanation:The subject of this question involves the concept of free fall in Physics. In this scenario, an object falls from a height under the influence of gravity alone, with an acceleration of 9.8 m/s². We will utilize the displacement equation to calculate the object's position from the top of the tower every 1.0 seconds.
The equation used is: d = 0.5 * g * t² where g = acceleration due to gravity (9.8 m/s²), t = time, and d = distance fallen.
At t = 1.0s, d = 0.5 * 9.8 * (1.0)² = 4.9 m At t = 2.0s, d = 0.5 * 9.8 * (2.0)² = 19.6 m At t = 3.0s, d = 0.5 * 9.8 * (3.0)² = 44.1 m At t = 4.0s, d = 0.5 * 9.8 * (4.0)² = 78.4 m At t = 5.0s, d = 0.5 * 9.8 * (5.0)² = 122.5 mPlease note that these are positions from the top of the tower, so the object is falling downwards.
Unfortunately, a pictorial representation of a position-time graph cannot be shown here. However, your graph should have time (in s) on the x-axis, and position (in m) on the y-axis, with data points plotted for each second up to 5 seconds, connected by a curved line—an implication of the accelerating object.
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A planet is in circular orbit around the sun. its distance from the sun is nine times the average distance of the earth from the sun. the period of this planet, in earth years, is:
By the Kepler's third law, the time period of this planet in earth years can be calculated to be 8 years.
What is Kepler's third law?Kepler's Third Law states that the squares of the orbital periods of the planets are directly proportional to the cubes of the semi-major axes of the planet's orbits. Kepler's Third Law implies that the period for a planet to orbit around the Sun increases rapidly with the radius of its orbit.
In planetary motion, the planet's net external torque is equal to zero. As a result, the angular momentum will not change.
T² is proportional to r³, and the orbital period square is proportional to the distance cubes.
(Tearth/ Tplanet)² = (rearth/ r planet)³
The planet's distance from the sun is 4 times the semi-major axis of the earth's orbit.
(Tearth/ Tplanet)² = (1/4)³
Tearth = Tplanet × √1/64 = Tplanet × (1/8)
Tplanet = 8 × Tearth
Tearth = 1 year
Tplanet = 8 years
Therefore, the time period of this planet is 8 years.
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Your question is incomplete, most probably the complete question is:
A planet is in a circular orbit around the sun. It distance from the sun is 4 times the semi major axis of earth's orbits. The period of the planets is
earth years
Using Kepler's third law of planetary motion, the period of a planet in circular orbit around the Sun at a distance of nine times the Earth's from the Sun is calculated to be 27 Earth years.
Explanation:The question asks to determine the orbital period of a planet that is nine times farther from the Sun than the Earth, using Kepler's third law, which relates a planet’s orbital period to its distance from the Sun. The law states that the orbital period squared (P^2) is proportional to the average distance from the Sun cubed (a^3). Given that the Earth's average distance from the Sun is about 150 million km (1 astronomical unit or AU), the planet in question is 9 AU from the Sun.
According to Kepler's third law, (P_earth/P_planet)^2 = (a_earth/a_planet)^3. We know P_earth is 1 year and a_earth is 1 AU, so substituting for a_planet with 9 AU, we get (1 year / P_planet)^2 = (1 AU / 9 AU)^3.
Solving this equation for P_planet gives us an orbital period of 3^3, or 27 Earth years for the planet.
describe the motion of an unanchored rowboat when a water wave passes
The motion of an unanchored rowboat when a water wave passes, the boat moves along with the waves. The boat doesn't move forward as waves could not take the boat along with it.
What is the motion of water waves?The water waves are waves that have a combination of both longitudinal and transverse waves. Longitudinal waves are the waves that cause the medium to move parallel to the direction of the waves.
Transverse waves are the waves that cause the medium to move perpendicular to the direction of the waves. When the waves travel through the water, the particles move in a clockwise direction. Most of the waves are formed by the winds.
The motion of the unanchored rowboat, when water pass is a boat, is moved up and down along with the wave. But the boat does not move forwards along with the wave. Because the wave does not carry the boat with it.
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A 0.0075 kg bullet is traveling at a speed of 365 m/s. My coffee cup, when full, has a total mass of about 1.25 kg. How fast must I throw my full coffee cup in order to have the same momentum as the bullet?
Answer:
2.19 m/s
Explanation:
The momentum (p) is the product of the mass (m) and velocity (v) of an object.
p = m × v
The momentum of a 0.0075 kg bullet traveling at a speed of 365 m/s is:
p(bullet) = 0.0075 kg × 365 m/s = 2.74 kg.m/s
We want the 1.25 kg-coffee cup to have the same momentum than the bullet.
p(cup) = p(bullet) = 2.74 kg.m/s
p (cup) = m(cup) × v(cup)
2.74 kg.m/s = 1.25 kg × v(cup)
v(cup) = 2.19 m/s
List three examples of material culture.
There are various examples of material culture like Tool, Monuments, Machines, etc.
What is Material Culture?The physical components of a society—the things that humans have created or altered—are referred to as material culture. These things are identified by their characteristics, whether chemical, physical, or biological, and they surround a population and its activities.
Shape, size, surface roughness, chemical composition and organization, molecular or cellular structure, color, and weight are examples of intrinsic properties of an entity.
Some more examples of material culture are :
AppliancesBeverages ArchitectureBooksCosmeticsCraftsFactories etc.Get more details about Material Culture :
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Two identical spring-loaded dart guns are simultaneously fired straight forward. one fires a regular dart; the other a weighted dart. which dart goes farther?
In terms of physics, the regular dart goes further. Despite both darts being fired with the same energy from the spring-operated dart guns, the heavier weighted dart experiences a greater recoil force, which slows it down more than the regular dart.
Explanation:The question asks which of two darts fired from identical spring-loaded dart guns would go farther: a regular dart or a weighted dart. This relates to the principles of physics, specifically, the concepts of energy conservation and Newton's third law.
In a spring-operated dart gun, energy is stored in the compressed spring and then transferred to the dart when the spring is released. This total energy put into the system is conserved in the closed system of the dart gun and dart, and it is mostly converted into the kinetic energy of the dart (ignoring the system's internal energy losses).
Newton's third law states that for every action, there's an equal and opposite reaction. In this case, the spring's force propels both darts forward. However, the reaction - the backward push on the dart - will be greater for the heavier weighted dart, slowing it more compared to the regular one. Therefore, the regular dart will go further given that it faces less opposing force from the gun itself.
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A girl delivering newspapers travels one block west then three blocks north then five blocks east. what is her resultant displacement?
PLEASE HELP!!! A small, horizontal pipe with cross-sectional area A is joined to a large horizontal pipe with cross-sectional area 2A. Both pipes are at the same height, and completely filled with water (density 1000 kg/m^3). What is the pressure of the water in the large pipe if the speed of the water in the small pipe is one m/s and the pressure of the water in the small pipe is 1000 Pa?
The Fahrenheit temperature reading is 98 on a hot summer day. What is this reading on the Celsius scale?
To a stationary observer, a bus moves north with a speed of 10 m/s. A man inside walks toward the back of the bus with a speed of 0.4 m/s relative to the bus. What is the velocity of the man according to a stationary observer? A. 0.4 m/s north B. 10.4 m/s north C. 10 m/s north D. 9.6 m/s north
When Emeka was first training his dog, Smooches, to heel he would give Smooches a treat when she stayed close during walks. Now Smooches stays right by Emeka's side, even when she is not on her leash. In this case, a. the dog treats were positive reinforcers for staying close. b. the dog treats were negative reinforcers for staying close. c. the staying close was a positive reinforcer for receiving dog treats. d. the staying close was a negative reinforcer for receiving dog treats.
What is the difference between contact forces and forces that act through a force field?
Contact forces occur when two objects are in contact while Non-contact forces occur without any physical contact.
What is force?Force is the action of push or pull which cause an object to move or stop.
Contact forces are the forces that come into existence when two objects come in contact to apply a force, For example: Frictional Force.
Non-contact forces takes place without any physical contact. For example: Gravitational force, Electric force, Magnetic force.
Thus, Contact forces occur when two objects are in contact while Non-contact forces occur without any physical contact.
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Which statement is true regarding the "relationship merry-go-round"?
A. By the age of 40, about 75% of Americans have married at least once.
B. Most people chose to remain single in order to pursue career goals.
C. Arranged marriages are no longer the norm in India.
D. In some cultures, romantic love was considered a form of madness.
A common finding with couples who can’t connect or resolve their problems is that they reason out or feel that it’s the other individual who can’t connect, not them. It’s the other individual that has the problem and they remain to think "I’m right and you’re wrong." The answer is letter a. In 40 percent of new weddings, one or both partners has been wedded no less than once before. Men are more probable to re-wed than women who've been wedded before.
What was the correct answer?
Find an expression for the acceleration a of the red block after it is released. use mr for the mass of the red block, mg for the mass of the gray block, and μk for the coefficient of kinetic friction between the table and the red block. express your answer in terms of mr, mg, μk, and g.
Assuming pulley is frictionless. Let the tension be ‘T’. See equation below.
The expression for the acceleration of the red block after it is released from the rest is
[tex]\fbox{\begin{minispace}\\{a = \dfrac{{\left( {{m_g} - \mu {m_r}} \right)g}}{\left( {{m_g} + {m_r}} \right)}}\end{minispace}}[/tex]
Further Explanation:
The friction force acting on the red block placed on the table is acting opposite to the direction of motion of block. The motion of the system, of red block and grey block, is vertically downward direction. It implies that the tension on the string is less than the weight on the grey block.
Given:
The mass of the red block is [tex]{m_r}[/tex].
The mass of the grey block is [tex]{m_g}[/tex].
The coefficient of friction between red block and table is [tex]\mu[/tex].
Concept:
The net force on the red block is acting along the direction of motion of the system and is equal to the difference between the tension in the string and friction force.
The net force on the red block is:
[tex]{m_r}a = T - f[/tex]
Rearrange the above expression.
[tex]T = {m_r}a + f[/tex]
Substitute [tex]\mu {m_r}g[/tex] for [tex]f[/tex] in above equation.
[tex]\fbox{\begin\\T = {m_r}a + \mu {m_r}g\end{minispace}}[/tex] …… (1)
Here, [tex]T[/tex] is the tension on the string, [tex]{m_r}[/tex] is the mass of the red block, [tex]a[/tex] is the acceleration of the system and [tex]g[/tex] is the acceleration due to gravity.
The net force on the grey block is along the direction of motion of the system and it is equal to the difference between the weight on grey block and tension on the string.
The net force on the grey block is:
[tex]{m_g}a = {m_g}g - T[/tex] …… (2)
Here, [tex]{m_g}[/tex] is the mass of the grey block.
Substitute [tex]{m_r}a + \mu {m_r}g[/tex] for [tex]T[/tex] in equation (2).
[tex]{m_g}a = {m_g}g - \left( {{m_r}a + \mu {m_r}g} \right)[/tex]
Rearrange the above expression.
[tex]{m_g}a + {m_r}a = {m_g}g - \mu {m_r}g[/tex]
Simplify the above expression.
[tex]\fbox{\begin{minispace}\\{a = \dfrac{{\left( {{m_g} - \mu {m_r}} \right)g}}{\left( {{m_g} + {m_r}} \right)}}\end{minispace}}[/tex]
Learn more:
1. Change in momentum https://brainly.com/question/9484203
2. The motion of a body under friction brainly.com/question/4033012
3. A ball falling under the acceleration due to gravity brainly.com/question/10934170
Answer Details:
Grade: College
Subject: Physics
Chapter: Kinematics
Keywords:
Acceleration, friction, tension, system of two blocks, pulley mass system, motion, net force, string, block placed on the table, block hanging through a pulley, block is released from rest.
A force of 40 N is applied on a body so that it attains a velocity of 20 m/s in 5 s. What is the mass of the body?
Which positive result could develop if carbon dioxide increases in the atmosphere? A. People breathe carbon dioxide, so Earth could support more human life. B. Plants give off carbon dioxide, so an increase in plant life could decrease world hunger. C. Carbon dioxide will protect people from the sun's radiation. D. Carbon dioxide will create more sunny weather, which is good for plant growth.
What is the minimum work needed to push a 950-kg car 710 m up along a 9.0° incline? ignore friction?
Answer:
Work done, [tex]W=1.03\times 10^6\ J[/tex]
Explanation:
It is given that,
Mass of the car, m = 950 kg
Distance up to the incline, d = 710 m
Angle of inclination of the car is 9 degrees.
When the car is push in the inclined path, the vertical component of the force will act on it such that the work done is given by :
[tex]W=mg\ sin\theta\times d[/tex]
[tex]W=950\times 9.8\times \ sin(9) \times 710[/tex]
[tex]W=1.03\times 10^6\ J[/tex]
So, the minimum work needed to push a car is [tex]1.03\times 10^6\ J[/tex]. Hence, this is the required solution.
The minimum work needed to push a car up an incline can be found by calculating the work done against gravity. This is done by multiplying the mass of the car by the gravitational acceleration and the height, which can be deduced from the sin of the incline angle and the distance.
Explanation:The question is asking for the minimum work done to push a car up an inclined plane. To solve this, you use the concept of work done against gravity. The formula for work done against gravity is Work = m * g * h, where m is the mass, g is the gravitational acceleration and h is the height. Since the distance and incline angle are provided, we can calculate the height with the trigonometric function sine, h = sin(angle) * distance. Substituting these values, we get Work = 950kg * 9.81m/s² * sin(9.0°) * 710m. The required calculation will then provide the answer to the work done in pushing the car up the incline.
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Velocity Describes ______ ?
A) speed and direction
B) speed and momentum
C) force and direction
D) gravity and direction
Which of the following would most likely result in a flash flood?
An ice storm
Melting snow on a plain
Excess precipitation in one location
A tornado with speeds of 110 km/h
If 31.25
10
18
electrons are removed from a
neutral dielectric, how much charge is stored in
coulombs?
Answer:
it will become charged by Q = 5C
Explanation:
When electron is removed from matter then the system will get positively charged
So we will have
[tex]Q = Ne[/tex]
here N = number of electrons that is removed
[tex]N = 31.25 \times 10^{18}[/tex]
also we know that charge on one electron is given as
[tex]e = 1.6 \times 10^{-19}[/tex]
here we have
[tex]Q = Ne[/tex]
[tex]Q = (31.25 \times 10^{18})(1.6 \times 10^{-19})[/tex]
[tex]Q = 5 C[/tex]
so it will become charged by Q = 5C
When rocks experience high temperatures and differential stresses deep in the earth, their grains tend to ________?
Seafloor spreading causes an oceanic plate to collide with a continental plate. If it were to go through the whole tectonic cycle, number the steps that would follow.
Answer: The entire process is mentioned in step-wise below-
Firstly, two plates moves opposite to each other, due to this the crust gradually become thin and subsequently rises up.On continuous thinning of the crust, at one point, the magma will come out to the surface producing a small rift.Rifting continuously takes place and results in a rift valley,and slowly after millions of years will form an ocean.Then, the two diverging plate will collide with another oceanic or continental plate, in which the more denser oceanic crust will get subducted beneath the less denser one.This suducted plate, at much greater depth undergoes partial melting and slowly makes its way up to the crust.This magma on further pushing towards the surface, initiates sea floor spreading, thus repeating the entire cycle.Which of the following is an example of two sets?
Two cars are driving at the same constant speed on a straight road, with car 1 in front of car 2. car 1 suddenly starts to brake with constant acceleration and stops in 10 m. at the instant car 1 comes to a stop, car 2 begins to brake with the same acceleration. it comes to a halt just as it reaches the back of car 1. what was the separation between the cars before they starting braking?
To find the initial separation between two cars before braking, we use the kinematic equation related to uniform acceleration. By calculating the deceleration of car 1, we can determine the total stopping distance for car 2, which includes the initial separation distance plus the stopping distance of car 1.
Explanation:The question involves the concept of uniform acceleration and the use of kinematic equations to determine the initial separation between two cars before they start braking. Under the assumption that both cars decelerate with the same constant acceleration and car 2 stops exactly at the position where car 1 initially started to brake, we can use the kinematic equation:
\[ v^2 = u^2 + 2as \]
Where \(v\) is the final velocity, \(u\) is the initial velocity, \(a\) is the acceleration, and \(s\) is the distance. Since car 1 stops in 10 m, we can find the acceleration by setting \(v=0\), and since car 2 stops at the back of car 1 exactly, the initial separation
\(s\) is actually the distance car 2 travelled while car 1 was braking plus the 10 m stopping distance of car 1.
To solve this, we first calculate the acceleration of car 1 as it comes to a stop:
\[ 0 = u^2 + 2a(10) \]
This gives us the value of \(a\), and since car 2 has the same acceleration and stops in the same way, it will travel a distance of 10 m after starting to brake, plus the initial separation distance while car 1 was braking. This total distance equals the stopping distance of car 1, which is 10 m, plus the distance car 2 travels before it starts braking.
Therefore, the initial separation between the two cars before braking started is the distance car 2 travels while car 1 is braking (which can be calculated using the found acceleration and the fact that car 2 starts braking 10 m after car 1 has come to a stop).
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an object has a velocity of 8 m/s and a kinetic energy of 480 J what is the mass of the object
We have first velocity equals 8 m/s and the kinetic energy is 480 J
The order is the mass of the object
We have this formula K= mv2/2 isolating the mass we have m=k/v2
Now we will have m=480/8×8 > m= 480/64 m= 7.5kg now we deternimed the mass it's 7.5 kg
which is NOT a "big idea" involving force and motion?
a) a force acting on an object in motion causes it to stop moving
b) a force acting on an object in motion causes it to change its motion
c) a force action on an object at rest causes it to move
Answer:a) a force acting on an object in motion causes it to stop moving
Explanation: gradpoint
all but which of the following might cause a tsunami? a. volcanic eruption b. flooding c. landslide d. earthquake
A 7-hp (shaft) pump is used to raise water to an elevation of 19 m. if the mechanical efficiency of the pump is 82 percent, determine the maximum volume flow rate of water. (round the final answer to four decimal places.)
Final answer:
To determine the maximum volume flow rate of water, we need to calculate the power supplied by the pump. Plugging in the values, the maximum volume flow rate of water is approximately 0.0019 m³/s.
Explanation:
Answer:
To determine the maximum volume flow rate of water, we need to calculate the power supplied by the pump. The formula to calculate power is power = force * velocity. If we convert the horsepower of the pump to watts (
1 hp = 746 watts), we can use the formula power = (7 hp * 746 W/hp) * (0.82 efficiency) to find the power supplied by the pump. Next, we can use the formula power = work/time = force * distance/time = force * velocity to find the force exerted by the pump. Finally, we can use the formula volume flow rate = velocity * area, where the area can be calculated using the equation area = π * (diameter/2)^2, to find the maximum volume flow rate of water. Plugging in the values, the maximum volume flow rate of water is approximately 0.0019 m³/s.
PLZZZZ I NEED HELP ASAP!!!!
Would Wegener have been more or less successful in convincing scientists today than he was when he proposed his ideas? Why or why not?
what velocity does a 2kg mass have when its kinetic energy is 16 J
The velocity of a 2kg mass with a kinetic energy of 16 J is 4 m/s. This result is obtained by rearranging and plugging the given values into the kinetic energy formula.
Explanation:To find the velocity of a 2kg mass when its kinetic energy (KE) is 16 J, we can use the kinetic energy formula:
KE = (1/2)mv²
where:
m is the mass of the objectv is the velocity of the objectBy rearranging the formula to solve for v, we get:
v = √(2KE/m)
Substituting the given values:
v = √(2 × 16 J / 2 kg)
v = √(16 J / kg) = 4 m/s
So, the velocity of the 2kg mass when its kinetic energy is 16 J is 4 m/s.
The velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s, calculated using the kinetic energy formula KE = 0.5 * m * v² and solving for v.
Explanation:To find the velocity of a 2 kg mass when its kinetic energy is 16 J, we can use the kinetic energy formula:
KE = ½mv²
where:
KE is the kinetic energy,
m is the mass,
v is the velocity.
First, we can solve for v:
v = √(2KE/m)
Substitute the given values (KE = 16 J and m = 2 kg) into the formula:
v = √(2*16 J / 2 kg)
v = √(16 J/kg)
v = 4 m/s
Therefore, the velocity of the 2 kg mass is 4 m/s.
i need a answer quick pleasee!!!!
Which of the following are correct statements about electrons
A. the valence shell is the furthest shell from the nucleus
B. there are four electrons in every electron shell
C. Electrons are in the nucleus of an atom
D. Electrons are located in layers around the nucleus