An electron in a TV is accelerated toward the screen. The potential between the back of the tube and the screen is 22,000 V (which is why it is a VERY good idea not to play around TV picture tubes). How much kinetic energy does the electron lose when it strikes the TV screen?

Answers

Answer 1

Answer:

The kinetic energy lost by the electron ΔK.E is 3.5244 × 10⁻¹⁵ J

Explanation:

Here we have;

Change in electric potential, ΔV, of the screen = 25000 V

The energy gained by the electron can be derived from the relation of change in electrical potential energy, ΔEPE, as follows;

ΔEPE = -Charge, q × ΔV

Therefore, since charge, q = -1.602 × 10⁻¹⁹ C we have;

ΔEPE = -(-1.602 × 10⁻¹⁹ C) × 25,000 V = 3.5244 × 10⁻¹⁵ C·V =

Also, since the electron is accelerated to the screen by the electrical potential energy, we have;

From the principle of conservation of energy in a given system;

The change in potential energy, ΔEPE of the electrons = Change in kinetic energy, ΔK.E, of the electrons3.5244 × 10⁻¹⁵ J

[tex]\Delta KE = \frac{1}{2} \cdot m \cdot v_f^2 - \frac{1}{2} \cdot m \cdot v_i^2[/tex]

Where:

m = Mass of the electron = 9.11 × 10⁻³¹ kg

[tex]v_i[/tex] = Initial velocity of the electrons = 0 m/s (electrons at rest)

[tex]v_f[/tex] = Final velocity of the electrons

[tex]\therefore \Delta KE = \frac{1}{2} \cdot m \times (v_f^2 - \cdot v_i^2)[/tex]

[tex]\therefore \Delta KE = \frac{1}{2} \cdot m \times (v_f^2 - 0) = \frac{1}{2} \cdot m \cdot v_f^2[/tex]

Hence;

The kinetic energy lost by the electron ΔK.E = ΔEPE = 3.5244 × 10⁻¹⁵ J.


Related Questions

A sound wave with a frequency of 510 Hz and a wavelength of 3.5 m is directed toward the bottom of a lake to measure its depth. If the echo of the sound from the bottom is heard 0.39 seconds later, how deep is the lake?

Answers

Answer:

Approximately [tex]2.9 \times 10^2 \; \rm m[/tex].

Explanation:

In that [tex]0.39\; \rm s[/tex], this sound wave travelled from the surface of the lake to the bottom, got reflected, and travelled back from the bottom to the surface. The sound wave travelled from the surface to the bottom (without bouncing back) in only [tex]1/2[/tex] that much time. In other words, it took only [tex]\displaystyle ((1/2) \times 0.39)\; \rm s[/tex] for the sound wave to travel from the surface to the bottom of the lake.  

The speed [tex]v[/tex] of sound in cold water ([tex]20\; \rm ^\circ C[/tex], [tex]1\; \rm atm[/tex]) is approximately [tex]1.482\times 10^{3} \; \rm m \cdot s^{-1}[/tex].

In [tex]t = ((1/2) \times 0.39) \; \rm s[/tex], that sound wave would have travelled a distance of:

[tex]\begin{aligned}s &= v \cdot t \\ &= 1.482 \times 10^3 \; \rm m \cdot s^{-1} \times \left(\frac{1}{2} \times 0.39 \; \rm s\right) \\ &\approx 2.9 \times 10^2\; \rm m \end{aligned}[/tex].

Therefore, the depth of the lake is approximately [tex]2.9 \times 10^2 \; \rm m[/tex].

What has more gravity-Earth's moon or the Sun?Why?

Answers

Answer:

Even though the sun is much more massive and therefore has stronger overall gravity than the moon, the moon is closer to the earth so that its gravitational gradient is stronger than that of the sun.

Explanation:

I need help with my physics. It’s on waves :(

Answers

Answer:

E is the Crest.

A tennis ball has a mass of 0.058 kg and is moving to the right at 40 m/s. What is the momentum

Answers

Explanation:

Mass = 0.058Kg

Velocity = 40m/s

Momentum P = ?

P = mv

P = 0.058 × 40

P = 2.32Kgm/s

Are quarks and or gluons smaller than photons.​

Answers

Answer:

V

Explanation:

Photons can be any size that I’d greater than around 6 Planck Lengths. So, technically they take the prize on both ends. We can see since the Higgs has the highest Energy. Therefore it will be smaller than most quarks except the top quark

Based on the solar system, which planet would you expect to have the slowest orbital speed? *
Mercury
Neptune
Jupiter
Earth

Answers

Final answer:

Neptune, being the furthest from the Sun, has the slowest orbital speed at approximately 5 kilometers per second, in accordance with Kepler's laws.

Explanation:

Based on Kepler's laws of planetary motion, the planet with the slowest orbital speed in our solar system is Neptune. This is because the speed at which a planet orbits the Sun is inversely related to its distance from the Sun. As Neptune is the furthest planet from the Sun with a vast orbital period of 165 Earth-years, it also has the slowest average orbital speed, which is approximately 5 kilometers per second. In contrast, Mercury, with an orbital period of only 88 Earth-days, moves much faster with an average speed of 48 kilometers per second.

A tennis ball has a mass of 0.058 kg and is moving to the right at 40 m/s. What is
the momentum of the tennis ball? (p = mv)
2.32
690
1.35
2320
A pinanong ball has a mass of 0 045 ka Approximately how fast must the ping

Answers

Answer:

since momentum = mass x velocity

m = 40m/s 0.058kg

m = 2.32

1) How is chemical energy
transformed into potential
energy?

Answers

Answer:

Chemical potential energy is a form of potential energy related to the structural arrangement of atoms or molecules. This arrangement may be the result of chemical bonds within a molecule or otherwise. Chemical energy of a chemical substance can be transformed to other forms of energy by a chemical reaction.

Explanation:

a man crossed a road 8.25m wide at a speed of 2.01m/s,how long does it take to get man to cross the road​

Answers

Answer:

t = 4.1 seconds

Explanation:

It is given that,

Width of road which is to be crossed by a man is 8.25 m, it means it is distance to be covered.

Speed of man is 2.01 m/s

We need to find the time taken by the man to cross the road. It is a concept of speed. Speed of a person is given by total distance covered divided by time taken. So,

[tex]v=\dfrac{d}{t}[/tex]

t is time taken

[tex]t=\dfrac{d}{v}\\\\t=\dfrac{8.25}{2.01}\\\\t=4.1\ s[/tex]

So, the time taken by the man to cross the road is 4.1 seconds.

What are all atoms with the same number of protons called
A. cells
B. elements
c. molecules
OD. compounds

Answers

Answer:

B elements

...............

Romeo lanza suavemente guijarros a la ventana de julieta y quiere que los guijarros golpeen la ventana solo con con un componente horizontal de velocidad el esta parado en el extremo de un jardin de rosas 4.5m por abajo de la ventana y a 5.0m de la base de la pared cual es la rapidez de los guijarros cuando golpean la ventana

Answers

The speed of the pebbles when they hit the window is approximately 7.07 m/s.

What is the speed of the pebbles when they hit the window?

Romeo wants to throw pebbles horizontally at Juliet's window. The window is 4.5m above him and 5.0m away from the wall. The pebbles' speed when they hit the window is about 7.07 m/s. This is calculated by determining the time it takes for the pebbles to reach the window vertically, using the equation t = [tex]\sqrt{\frac{2d}{g} }[/tex].

Then, the horizontal velocity is found by dividing the horizontal distance by the time of flight. The overall speed is the square root of the horizontal velocity squared, which is approximately 7.07 m/s.

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Romeo stands 4.5 meters below Juliet's window, 5.0 meters from the wall, and throws pebbles with horizontal velocity. Calculations based on time of flight and Pythagoras yield a speed of approximately 5.21 meters per second at impact.

To find the speed of the pebbles when they hit Juliet's window with only a horizontal component of velocity, we can use the following steps:

Calculate the time it takes for the pebbles to reach the window vertically.

We can use the formula for the time of flight for an object in free fall:

[tex]\[t = \sqrt{\frac{2d}{g}}\][/tex]

Where:

- t is the time of flight.

- d is the vertical distance (4.5 meters in this case, the height of the window).

- g is the acceleration due to gravity (approximately 9.81 m/s² on Earth).

Let's calculate t:

[tex]\[t = \sqrt{\frac{2 \cdot 4.5\,m}{9.81\,m/s^2}}\][/tex]

t is approximately 0.96 seconds.

Calculate the horizontal velocity.

Now that we know the time of flight (t), we can find the horizontal velocity [tex](\(v_x\))[/tex] by dividing the horizontal distance (5.0 meters) by the time of flight:

[tex]\[v_x = \frac{5.0\,m}{0.96\,s}\][/tex]

[tex]\(v_x\)[/tex] is approximately 5.21 m/s.

Calculate the overall speed when the pebbles hit the window.

To find the overall speed (v), we use the Pythagorean theorem because the pebbles' motion consists of both horizontal and vertical components:

[tex]\[v = \sqrt{v_x^2 + v_y^2}\][/tex]

Where:

- [tex]\(v_x\)[/tex] is the horizontal velocity (5.21 m/s, as calculated).

- [tex]\(v_y\)[/tex] is the vertical velocity. Since the pebbles are thrown horizontally, \[tex](v_y[/tex]= 0.

Now, calculate v:

[tex]\[v = \sqrt{5.21\,m/s)^2 + 0^2}\][/tex]

v is approximately 5.21 m/s.

So, the speed of the pebbles when they hit Juliet's window is approximately 5.21 m/s.

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The question probable may be:

Romeo gently throws pebbles at Juliet's window and wants the pebbles to hit the window with only a horizontal component of velocity. He is standing at the end of a rose garden, 4.5 meters below the window and 5.0 meters away from the base of the wall. What is the speed of the pebbles when they hit the window?

In chemical reactions, the products _____.
A. contain fewer atoms than the reactants
B. contain more atoms than the reactants
O c. are found on the left-hand side of the equation for the reaction
D. are found on the right-hand side of the equation for the reaction

Answers

In chemical reactions, the products are the substances that are found on the right-hand side of the chemical equation, indicating the outcome of the reaction.

In chemical reactions, the products are the substances that are found at the end of the reaction. The correct answer is D. The reactants, which are the chemical before the reaction starts, are situated on the left side of the chemical equation, represented by a plus sign. An arrow points from the reactants to the products, indicating the direction of the reaction. The products, which are the chemical after the reaction ends, appear on the right-hand side of the equation. For instance, in the combustion of methane, the chemical equation is CH4 + 2O2
ightarrow CO2 + 2H2O, where CH4 and O2 are the reactants and CO2 + 2H2O are the products.

A5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.
What is the distance of the image from the lens? Round your answer to three significant figures.
cm
What is the height of the image? Round your answer to three significant figures.
cm
Intro

Answers

Answer:

answer in picture

Explanation:

An arrow is fired vertically upwards by a bow and reaches an altitude of 134 m. Find the initial speed of the arrow on the ground level.

Answers

Answer:

Explanation:

Let the initial speed be u . final speed = 0

v² = u² - 2gh

v is final speed , u is initial speed , h is height .

0 = u² - 2g x 134

u² = 2 x 9.8 x 134

u = 51.25 m /s .

Final answer:

The initial speed of the arrow fired vertically upwards and reaching an altitude of 134m is approximately 51.7 m/s. This was calculated using the second equation of motion and taking into account gravitational acceleration.

Explanation:

This physics problem relates to projectile motion and can be solved using the concepts of kinematic equations. The known variables from the question are the final altitude (y = 134m) and the acceleration due to gravity (g = 9.81 m/s^2), which is always acting downward. We're looking for the initial speed (v0) of the arrow when it was released from the ground level.

Due to the arrow being launched upwards and then coming back down, the final velocity would be the negative of its initial velocity. Hence, we can say that v = -v0

According to the second equation of motion, v^2 = v0^2 + 2gy. Replacing known values, we get (-v0)^2 = v0^2 + 2*(-9.81)*134. From which we can solve for v0.

After simplifying the equation, we find that v0 = sqrt(v0^2 - 2*(-9.81)*134), this leads us to find that the initial speed of the arrow was approximately 51.7 m/s.

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Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends toward the normal.

Which statement best describes Cleo’s mistake?

Light travels through air and water in angled, scattered paths.
Light does not change direction when it moves from air into water.
Light slows down when it moves from air into water.
Light bends away from the normal when it moves from air into water.

Answers

Answer:

Light slows down when it moves from air into water.

Explanation:

It is the property of light that travels faster in a less dense medium.

In a more dense medium, the speed of the light slows down and bends towards the normal.

The air is less dense medium and water is a more dense medium.

When light passes from air to water, the light bends.

This is known as the refraction of light.

Answer:

C is the correct answer on Ed gen uity

A current in a wire increases from 2 A to 6 A. How will the magnetic field 0.01 m from the wire change?

Answers

Answer:

It increases to three times its original value.  Given the same radius of wire and other constant property. current is directly proportional to the magnetic field.

B1=B2

MoI1/2pir=MoI2/2pir; cancel the same values  on both sides

B2/B1=6/2 =3

         

Explanation:

Final answer:

The magnetic field produced by a current-carrying wire depends on the current and distance from the wire.

Explanation:

The magnetic field produced by a current-carrying wire is given by the formula B = μi / (2πR), where B is the magnetic field strength, μ is the permeability of free space, i is the current in the wire, and R is the distance from the wire.

In this case, the current in the wire increases from 2 A to 6 A. As a result, the magnetic field at a distance of 0.01 m from the wire will also increase. However, the exact value of the magnetic field change can only be determined if the initial distance from the wire is known.

It is important to note that the magnetic field strength is inversely proportional to the distance from the wire, meaning that as the distance increases, the magnetic field strength decreases.

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Vicente is going to spend the afternoon in his yard. He has the choice to get in the pool, lay on a cotton chaise longue, sit on the porcelain tile bordering the pool, or sit on a plastic chair. The specific heats of these items are:
Water = 4.19 J/g•°C
Cotton = 1.30 J/g•°C
Porcelain = 1.07 J/g•°C
Plastic = 1.67 J/g•°C
Based on the specific heat values given, where is the coolest location for Vicente to be?
pool
cotton chaise lounge
porcelain tile
plastic chair

Answers

Answer:

Pool

Explanation:

I just answered it

On the basis of specific heat values, the coolest location for Vicente to be is known as Pool. Thus, the correct option for this question is A.

What is Specific heat?

Specific heat may be defined as the quantity of heat that is ultimately required in order to increase the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree.

According to the question, the specific heat of water is maximum, while the specific heat of porcelain is minimum. This represents that water is the coolest place in the Vicente while porcelain tile is the warmest place in the Vicente.

Therefore, on the basis of specific heat values, the coolest location for Vicente to be is known as Pool. Thus, the correct option for this question is A.

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A truck exerts 2700 N of force on a car that is stuck in the mud, and does not move. How much work has the truck performed?

Answers

Answer:

zero

Explanation:

although force was applied as long as there's no movement ,no work has been done

mathematically;work=force×distance

work=2700×0

work=0J

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Need help with Physics. 100 points + Brainliest

1. Two point charges are 10.0 cm apart and have charges of 2.0 µC and –2.0 µC, respectively. What is the magnitude of the electric field at the midpoint between the two charges? (Use G.U.E.S.S.)

Answers

Answer:

I wrote down the answer and attached it below.

Explanation:

Hope this Helps!!!!

⬇⬇⬇⬇⬇⬇⬇⬇

Answer:

Every electric charge has a electric field.

The charges in the electric field are affected each other.

As you move away from the electric charge, the intensity of the electric field decreases.

The electric field is a vector quantity.

The electric field of each charge is calculated to find the intensity of the electric field at a point.

The vectorial sum of the vectors are found.

The electric field of the positive charge is directed outward from the charge.

Explanation:

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A test model for a new experimental gasoline engine does 45 J of work in one cycle for every 76 J of heat it takes in. What is the engines efficiency?

Answers

Answer:

The efficiency of the engine is 59.2%.

Explanation:

We have,

Work done by the gasoline engine is 45 J and the for every 76 J of heat it takes in.

It is required to find the efficiency of the engine. Efficiency of the engine is given by the ratio of work done to the heat taken i. Its formula is given by :

[tex]\eta=\dfrac{W}{Q}\\\\\eta=\dfrac{45}{76}\\\\\eta=0.592\\\\\eta=59.2\%[/tex]

So, the efficiency of the engine is 59.2%.

Final answer:

The efficiency of the engine is approximately 59.21%, calculated by dividing the work done by the engine (45 J) by the heat input (76 J) and then multiplying by 100.

Explanation:

The efficiency of a heat engine is the ratio of work output to heat input, expressed as a percentage. To calculate the engine's efficiency, you divide the work done by the engine by the heat energy that was put into the engine, and then multiply by 100 to convert the decimal to a percentage. In the given problem, the engine does 45 J of work and takes in 76 J of heat, which means the efficiency (η) is calculated as:

η = (Work done / Heat input) × 100

η = (45 J / 76 J) × 100

η = (0.59210526315...) × 100 ≈ 59.21%

The engine's efficiency is therefore approximately 59.21%.

What are two ways in which you can increase the potential energy of a marble on a ramp?

Answers

Answer:

As the marble starts rolling down the roller coaster, the amount of potential energy stored in the marble decreases while its kinetic energy increases. Potential energy is also converted into heat energy due to friction.

Explanation:

As the marble rolls down the hill its potential energy is converted to kinetic energy (its height decreases, but its velocity increases). When the marble goes back up the loop its height increases again and its velocity decreases, changing kinetic energy into potential energy.

The two (2) ways in which the potential energy of a marble on a ramp can be increased are:

I. By placing the marble higher on the ramp.

II. By increasing the mass of the marble.

Potential energy can be defined as a type of energy possessed by an object (body) as a result of its position (height) above the earth.

Mathematically, potential energy (P.E) is calculated by using the following formula:

[tex]P.E = mgh[/tex]

Where:

m is the mass of an object. g is the acceleration due to gravity. h is the height of an object.

Hence, potential energy (P.E) is highly dependent on two (2) main factors and these are:

1. Height above the ground.

2. The mass of an object.

In conclusion, the two (2) ways in which the potential energy of a marble on a ramp can be increased are:

Increasing the height of the marble, by placing the marble higher on the ramp.By increasing the mass of the marble such as adding more marbles.

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¿Por qué si cargas a uno de tus compañeros por cierto tiempo no estás realizando un trabajo mecánico?

Answers

Answer:

I will answer this in English, we can translate it to:

Why if you charge a mate by an amount of time you are not doing work?

This happens because work is defined as the displacement done by a force:

W = d*F

where W is work, d is the distance, and F is the force.

This means that the amount of time that you are charging your mate does not affect the mechanical work, the only time that you are doing work is when you are lifting him.

If the potential difference across the bulb in a certain flashlight is 3.0 V, What is the potential difference across the combination of batteries used to power it?

Answers

Answer:

3.0 V

Explanation:

The voltage across the bulb is the voltage across the batteries, since the batteries are the only source of power for the bulb. So the voltage across the batteries is 3.0 V.

The potential difference should be 3.0 V.

Calculation of the potential difference:

In the case when the potential difference for the flashlight is 3.0V so here the batters should be considered as the only source with respect to the power for the bulb. Due to this, the potential difference across the batteries combination that used to power should also be 3.0 V.

Therefore, The potential difference should be 3.0 V.

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The weight of a bicyclist and bicycle together is 51.0kg how much work has been done if the bicyclist slows down the bicycle from a seed of 3.95 m/s to 1.31 m/s

Answers

Answer:

The work done is 354.1032 Joules

Explanation:

To answer the question we note that the amount of work done is equivalent to the reduction in the kinetic energy of the bicyclist and bicycle.

Therefore, initial kinetic energy. KE[tex]_i[/tex] of the system is given by the following relation;

[tex]KE_i=\frac{1}{2} mv_{1}^{2}[/tex]

Final kinetic energy [tex]KE_f = \frac{1}{2} mv_{2}^{2}[/tex]

Where:

v₁ = Initial velocity = 3.95 m/s

v₂ = Final velocity = 1.31 m/s

m = Mass of the bicyclist and bicycle = 51.0 kg

Change in kinetic energy ΔKE;

[tex]\Delta KE = KE_f - KE_i[/tex]

[tex]\Delta KE =\frac{1}{2} mv_{2}^{2}-\frac{1}{2} mv_{1}^{2} = \frac{1}{2} m(v_{2}^{2}-v_{1}^{2}) = \frac{1}{2} \times 51 \times (1.31^{2}-3.95^{2}) = -354.1032 \ J[/tex]

Therefore, work done = -ΔKE = 354.1032 Joules.

Length is fundamental quantity whereas area is derived quantity. Justify

Answers

Answer:

A fundamental quantity is something that can only be found by measuring, such as measuring the length of a pencil. We have no other way to find out the length of the pencil other than measuring it in some way.

A derived quantity is something that is calculated and that is not measured directly. Area is found by multiplying two lengths together. We cant find the area other than computing it somehow

A plane lands at a speed of 38 km/s and comes to rest (0m/s) 36.3 seconds later. What is the acceleration during landing?

20 points!!!!!!!!

Answers

Acceleration = (change in speed) / (time for the change)

Change in speed = (speed at the end) - (speed at the beginning)

Change in speed = (0 km/sec) - (38 km/sec) = -38 km/sec

Acceleration = (-38 km/sec) / (36.3 sec) = -1,046.8 m/s²

Now, before we split up our points and go home, let's see what we've actually got here.

-- The plane's landing speed is about 111 times the speed of sound !

-- It rolls to rest 36.3 seconds after it touches down at this speed.

-- In order to do that, it pulls about 107 G's !

It seems to me that during the ground roll, the flight crew's eyeballs fall out, then they get ripped out of their seat belts and crash through the windshield, and the plane continues on with no life forms aboard. Then, maybe 1 second later, the drogue  parachute tears off, the tires on the landing gear blow out and get shredded, the remaining fuel sloshes through the walls of the tanks and evaporates catastrophically, the wings fall off and scrape along the ground in a shower of sparks, the cloud of fuel vapor ignites and then erupts in a ball of flame, the people downtown notice it on the horizon and marvel at it, and then any remaining flaming pieces of the plane come to rest in the dense pine forest and the apartment complex 2 miles past the end of the runway.

This is not my business.  I only used the numbers you gave me in the question.  My math and physics are flawless, I gave you a theoretically bullet-proof answer, and this is a privilege and a pleasure for you and will stand you in good stead.  You're welcome.

What does ROCAPV mean? It says related to electricity.

Answers

Answer:  Rancho de Area Comunes PV

Explanation: it means

Rancho de Area Comunes PV

In an AC Monte Roca PV System Profile, where the following are depicted:

Location

Commissioning

Production

Operator

PV system power

Module

And communication.

A model rocket is fired vertically upward from rest. Its acceleration for the first three seconds is a(t) = 66 t, at which time the fuel is exhausted and it becomes a freely "falling" body. 15 seconds later, the rocket's parachute opens, and the (downward) velocity slows linearly to -23 ft/s in 5 s. The rocket then "floats" to the ground at that rate.

Determine the position function s and the velocity function v (for all times t).

Answers

(x=yt-2)^2(56-tea)^2x10r

Final answer:

Using the given information, we determined the position and velocity functions of the model rocket at different time intervals. The velocity function varies during the rocket's upward acceleration, free fall, and the subsequent parachute slowing. The position function gives the height of the rocket at any time.

Explanation:

To determine the position function s(t) and the velocity function v(t), we need to analyze the rocket's motion in different time intervals:

From time t = 0 to t = 3 seconds: The acceleration is given by a(t) = 66t. To find the velocity function, we integrate the acceleration function, v(t) = ∫ 66t dt = 33t2 + C1, where C1 is a constant of integration. We can determine C1 by using the initial condition of the rocket being at rest at t = 0 (initial velocity is 0), which gives us C1 = 0. So, v(t) = 33t2.From time t = 3 to t = 18 seconds: The rocket becomes a freely falling body. This means it is subject to a constant acceleration due to gravity, a(t) = -32 ft/s2. The velocity function can be found by integrating the acceleration, resulting in v(t) = -32t + C2. To determine C2, we use the fact that at t = 3 seconds, the velocity is 0 (since the fuel is exhausted). Plugging in these values, we find C2 = 96. Thus, v(t) = -32t + 96.From time t = 18 to t = 23 seconds: The velocity decreases linearly from -23 ft/s to 0 ft/s in 5 seconds. This means the acceleration is given by a(t) = (-23 - 0) / 5 = -4.6 ft/s2. Integrating the acceleration function, we get v(t) = -4.6t + C3. Using the fact that at t = 23 seconds the velocity is 0, we find C3 = 105.8. Thus, v(t) = -4.6t + 105.8.

To find the position function s(t), we integrate the velocity function for each time interval:

From time t = 0 to t = 3 seconds: s(t) = ∫ (33t2) dt = 11t3 + C4. Using the initial condition s(0) = 0, we find C4 = 0. Therefore, s(t) = 11t3.From time t = 3 to t = 18 seconds: s(t) = ∫ (-32t + 96) dt = -16t2 + 96t + C5. Since the rocket is at rest at t = 3 seconds, we have the condition s(3) = 0, which gives us C5 = 1176. Hence, s(t) = -16t2 + 96t + 1176.From time t = 18 to t = 23 seconds: s(t) = ∫ (-4.6t + 105.8) dt = -2.3t2 + 105.8t + C6. Since the rocket starts floating to the ground at t = 18 seconds, we have the condition s(18) = 0, giving us C6 = -685. Thus, s(t) = -2.3t2 + 105.8t - 685.

The position function s(t) represents the height of the rocket at any time t, while the velocity function v(t) represents the rate at which the height is changing with respect to time.

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A wire on the left with 9 coils and labeled primary winding. Another coil is near it with 3 coils labeled secondary winding V subscript 2 baseline equals 120. Use the values provided to calculate the initial voltage at the primary winding.


V1 = ? V

Answers

Answer:

V1 = 360 V

Explanation:

Applying,

Vs/Vp = Ns/Np................ Equation 1.

Vs = Voltage of the secondary coil, Vp = voltage of the primary coil, Ns = number of coils in the secondary winding, Np = number of coils in the primary winding

make Vp the subject of the equation

Vp = VsNp/Ns............ Equation 2

Given: Vs = 120 V, Np = 9 coils, Ns = 3 coils

Substitute into equation 2

Vp = 120(9)/3

Vp = 360 V.

Hence, V1 = 360 V

Answer:

V1 = 360 V

Explanation:

hope i helped

Which planets receive more of the Sun's concentrated light?

Answers

Answer: Mercury is closest to the Sun and receives more of the Sun's concentrated light.

Explanation: I hope this helps :]

Answer:

The planets closest in the solar system rotation, or the "inner four"

Mercury recieves the most though.

(The inner four include Mercury, Venus, Earth, and Mars)

i hope this helps!

Explanation:

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