Ahmed's first error was in step 3 where he failed to express 54 in terms of π.
What is Volume?Volume is a mathematical term used to describe how much three-dimensional space an item or closed surface occupies.
We have,
Diameter = 6 cm
1. Radius = diameter/2
= 6/2
= 3cm
2. Area of base = π × 3²
= 9π cm²
3. Multiply the area of the base by the height
= 9π x 6
= 54π cm³
4. Divide 54π by 3 to find the volume of the cone
= 54π/3
= 18π cm³
So, the volume of the cone is 18π cm³.
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A manufacturer of t-shirts marks a shirt as "irregular" when it has defects such as crooked seams, stains, rips, or holes. A small number of irregular t-shirts are expected as part of the manufacturing process, but if more than 8% of the t-shirts manufactured at a plant are classified as irregular, the manager has to do an investigation to try to find the source of the increased mistakes in the manufacturing process. In order to test whether his plant is making a higher than expected number of irregular t-shirts, the manager of a plant randomly selects 100 t-shirts and finds that 12 are irregular. He plans to test the hypothesis: H0, P = 0.08, versus Ha, p > 0.08 (where p is the true proportion of irregular t-shirts). What is the test statistic
Answer:
The test statistic value is 1.474.
Step-by-step explanation:
In this case we need to determine whether the plant is making a higher than expected number of irregular t-shirts.
If more than 8% of the t-shirts manufactured at a plant are classified as irregular, the manager has to do an investigation to try to find the source of the increased mistakes in the manufacturing process..
The hypothesis for this test can be defined as follows:
H₀: The proportion of irregular t-shirts is 8%, i.e. p = 0.08.
Hₐ: The proportion of irregular t-shirts is more than 8%, i.e. p > 0.08.
The information provided is:
n = 100
X = number of irregular t-shirts = 12
Compute the sample proportion as follows:
[tex]\hat p=\frac{X}{n}=\frac{12}{100}=0.12[/tex]
Compute the test statistic as follows:
[tex]t=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]=\frac{0.12-0.08}{\sqrt{\frac{0.08(1-0.08)}{100}}}\\\\=1.47441\\\\\approx 1.474[/tex]
Thus, the test statistic value is 1.474.
Jane wants to buy a movie that costs $15.49. She has $8.75. How much more money does Jane need to buy the movie?
Answer:
$6.74
Step-by-step explanation:
Subtract 15.49 and 8.75
Answer: 6.74.
Step-by-step explanation: I took the quiz before!
Hope this helps! (✪ ω ✪)
A police officer is concerned about speeds on a certain section of Interstate 95. The data accompanying this exercise show the speeds of 40 cars on a Saturday afternoon. Click here for the Excel Data File Click here for the CSV Data File a. The speed limit on this portion of Interstate 95 is 64 mph. Specify the competing hypotheses in order to determine if the average speed is greater than the speed limit.
Answer:
Jo : μ ≤ 64.
Jo : μ > 64.
Step-by-step explanation:
From the question, the Important information to solve this question is that; ''the speed limit on this portion of Interstate 95 is 64 mph''.
The question wants us to find the fact that the average speed is greater or more than the speed limit.
Therefore, In order to solve this question, the formula to use is the ''null and alternative" hypothesis. It states that;
Jo : μ ≤ 64.
Jo : μ > 64.
The above expression is the competing hypotheses in order to determine if the average speed is greater than the speed limit.
A researcher wanted to test his claim that the mean walking pace of business
travelers is different from that of leisure travelers at the airport. To test his claim he
obtained the following lists of 9 business and 8 leisure travelers. Test his claim at the
.05 = level of significance.
Business
Travelers
42 31 37 45 49 52 43 39 45
Leisure
Travelers
32 29 35 40 38 34 42 33
Answer:
[tex] t = \frac{42.56-35.375}{\sqrt{\frac{6.327^2}{9} +\frac{4.34^2}{8}}}=2.755[/tex]
The degrees of freedom are given by:
[tex] df=n_1 +n_2-2 =9+8-2= 15[/tex]
Since we have a two tailed test the p value can be calculated like this:
[tex] p_v=2* P(t_{15} >2.755) = 0.0147[/tex]
And since the p value is lower than the significance lvel given of 0.05 we have enough evidence to conclude that we have significant differences between the two groups on this case.
Step-by-step explanation:
We have the following data given:
Business Travelers
42 31 37 45 49 52 43 39 45
Leisure Travelers
32 29 35 40 38 34 42 33
For this case we need to begin finding the sample mean and deviations for each group with the following formulas:
[tex]\bar X =\frac{\sum_{i=1}^n X_i}{n}[/tex]
[tex] s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And we got:
[tex] \bar X_1 = 42.56[/tex] represent the sample mean for the Business travelers
[tex]s_1 = 6.327[/tex] represent the sample deviation for the Business travelers
[tex]n_1= 9[/tex] the sample size for the Business travelers
[tex] \bar X_2 = 35.375[/tex] represent the sample mean for the Leisure travelers
[tex]s_2 =4.34[/tex] represent the sample deviation for the Leisure travelers
[tex]n_2= 8[/tex] the sample size for the Leisure travelers
The system of hypothesis for this case are:
Null hypothesis: [tex] \mu_1 =\mu_2[/tex]
Alternative hypothesis: [tex] \mu_1 \neq \mu_2[/tex]
The statistic for this case is given by:
[tex] t =\frac{\bar X_1 -\bar X_2}{\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}}[/tex]
And replacing we got:
[tex] t = \frac{42.56-35.375}{\sqrt{\frac{6.327^2}{9} +\frac{4.34^2}{8}}}=2.755[/tex]
The degrees of freedom are given by:
[tex] df=n_1 +n_2-2 =9+8-2= 15[/tex]
Since we have a two tailed test the p value can be calculated like this:
[tex] p_v= 2*P(t_{15} >2.755) = 0.0147[/tex]
And since the p value is lower than the significance lvel given of 0.05 we have enough evidence to conclude that we have significant differences between the two groups on this case.
A math teacher claims that she has developed a review course that increases the scores of students on the math portion of a college entrance exam. Based on data from the administrator of the exam, scores are normally distributed with mu equalsμ=522522. The teacher obtains a random sample of 20002000 students, puts them through the review class, and finds that the mean math score of the 20002000 students is 527527 with a standard deviation of 110110. Complete parts (a) through (d) below. (a) State the null and alternative hypotheses. Let muμ be the mean score. Choose the correct answer below. A. Upper H 0 : mu equals 522H0: μ=522, Upper H 1 : mu not equals 522H1: μ≠522 B. Upper H 0 : mu less than 522H0: μ<522, Upper H 1 : mu greater than 522H1: μ>522 C. Upper H 0 : mu greater than 522H0: μ>522, Upper H 1 : mu not equals 522H1: μ≠522 D. Upper H 0 : mu equals 522H0: μ=522, Upper H 1 : mu greater than 522
Answer: D
H0: μ=522
H1: μ>522
Step-by-step explanation:
The null hypothesis (H0) tries to show that no significant variation exists between variables or that a single variable is no different than its mean. While an alternative Hypothesis (Ha) attempt to prove that a new theory is true rather than the old one. That a variable is significantly different from the mean.
So, for this case;
The null hypothesis is that the mean score equals to 522
H0: μ=522
The alternative hypothesis is that the mean score is greater than 522.
H1: μ>522
The correct answer is D. [tex]Upper H_0: = 522, Upper H_1 > 522[/tex].
In this scenario, the math teacher is claiming that her review course increases the scores of students on the math portion of a college entrance exam. Therefore, the null hypothesis [tex](H_0)[/tex] should represent the claim that there is no increase in the mean score, which would be that the mean score is equal to the population mean of 522. The alternative hypothesis [tex](H_1)[/tex] should represent the teacher's claim that the mean score has increased, which would be that the mean score is greater than 522.The null hypothesis is a statement of no effect or no difference and serves as the baseline for testing. The alternative hypothesis is what we aim to support; it is a statement that there is an effect or a difference. In this case, we are testing whether the mean score of students after taking the review course is greater than the population mean.Therefore, the correct hypotheses are:- Null Hypothesis [tex](H_0): = 522[/tex] , indicating no increase in the mean score.- Alternative Hypothesis [tex](H_1): > 522[/tex] , indicating an increase in the mean score.This is a one-tailed test because we are only interested in whether the mean score has increased, not whether it has changed at all (which would require a two-tailed test).
To find the surface area of the figure shown, Mia found the surface area of the two triangular prisms and the rectangular prism. From this, Mia subtracted 6 ft2. Did Mia make an error?
Mia should have subtracted 16 square feet.
Mia needs to subtract another 6 square feet.
Mia must calculate each triangle separately.
There is no error—Mia is correct.
Answer:
Mia needs to subtract another 6 square feet
Step-by-step explanation:
Guessed it and got it right
Answer:
needs to subtract another 6 ft
Step-by-step explanation:
5. Melanie scored 20/25 on her quiz. What percent is this equal to? *
Answer:
0.8 or 80%
Step-by-step explanation:
To easily find percents, divide the numerator with the denominator. Or, first you can simplify the fraction first.
20/25 can be divided by 5. Which is 4/5.
4/5=0.8
So, the answer is 80%
Answer:
80%
Step-by-step explanation:
[tex]\frac{20}{25} = \frac{4}{5}[/tex]
To find the percentage, multiply by 100:
[tex]\frac{4}{5} * 100 = 80[/tex]
A dietitian wants to know the average time spent on breakfast in a primary school. The dietitian randomly samples 16 students and finds that the average is 15.8 minutes with a standard deviation of 2.31 minutes. Assume that the distribution of the time spent on the breakfast is normally distributed. The dietitian finds a 90% confidence interval for this sample is (14.788, 16.812) Flag question Select one or more:_________. a. The margin of error is 1.012. b. The margin of error is 2.024 c. The margin of error is 0.950 d. We believe that the true mean time spent on breakfast in this primary school is between 14.788 and 16.812 minutes. e. If we take many other samples from this population, 90% of them will have a sample mean that is between 14.788 and 16.812. f. There is a 90% chance that the true mean is between 14.788 and 16.812 minutes.
Answer: is their any picture? or an example?
A six sided number cube has
one number, from 1 through 6,
on each cube. Determine the
probability of the following:
Pleven #)
7.SP.5
Answer:
Probability of even = 0.5
Step-by-step explanation:
Probability of even = total number of even numbers/ total number
Total number of Eve number = [ 2,4,6] = 3
Total numbers = [ 1,2,3,4,5,6] = 6
Probability of even = 3/6
Probability of even = 1/2
Probability of even = 0.5
Compute: 3:40 - 1:55
Answer:
0 days 3 hours 40 minutes 0 seconds
- 0 days 1 hours 55 minutes 0 seconds
= 0 days 1 hours 45 minutes 0 seconds
= 0.0729167 days
= 1.75 hours
= 105 minutes
= 6,300 seconds
Step-by-step explanation:
Final answer:
To calculate the difference between given times, convert them into minutes and subtract. The result will be the time difference in minutes.
Explanation:
Compute: 3:40 - 1:55
To compute the difference between 3:40 and 1:55, you need to subtract the two times. First, convert both times into minutes: 3:40 = 3 x 60 + 40 = 180 + 40 = 220 minutes, and 1:55 = 1 x 60 + 55 = 60 + 55 = 115 minutes. Then, subtract 115 from 220 to get the result.
The difference between 3:40 and 1:55 is 105 minutes.
How many solutions does the equation 3(x + 2) – 10 = 4x – 6 + x have?
Answer:
1
Step-by-step explanation:
3(x+2)-10=4x-6+x
3x+6-10=5x-6
2x=2
x=1
This is the only solution to this equation, meaning that there is only one solution to the equation. Hope this helps!
The equation 3(x + 2) - 10 = 4x - 6 + x has one solution, which is x = 1. After simplifying the equation and solving for x, we confirm that substituting x = 1 back into the equation results in an identity, indicating that this is the correct solution.
To determine how many solutions the equation 3(x + 2) \\- 10 = 4x \\- 6 + x has, we must first simplify the equation and solve for x.
Let's simplify both sides of the equation:
Distribute the 3 on the left side: 3x + 6 \\- 10 = 4x \\- 6 + x.
Combine like terms on the right side: 3x \\- 4 = 5x \\- 6.
Get all the x terms on one side and constants on the other: 3x \\- 5x = \\-6 + 4.
Simplify the equation: \ -2x = \\-2.
Divide both sides by \\-2 to solve for x: x = 1.
So, the solution to the equation is x = 1. To verify that this is the solution, we can substitute x = 1 back into the original equation and check that it holds true, which would confirm that the equation is an identity. In this case, the substitution leads to an identity, confirming that x = 1 is the correct and only solution to the equation.
P
Q
R
S
T
-10
-8
6
4
2
0
2
4
6
Find the midpoint of PS.
someone help me please
Answer:
2.5 or 5/2
Step-by-step explanation:
The formula for the area of a triangle is \dfrac{bh}{2}, where b represents the length of the base and h represents the length of the height. With this in mind, you can set up the following equation:
[tex]\dfrac{15}{8}=\dfrac{1.5b}{2}[/tex]
[tex]\dfrac{15}{4}=1.5b[/tex]
b=2.5 or [tex]\frac{5}{2}[/tex]
Hope this helps!
The equation y= 2x represents a set of data.
Which statement is NOT true?
Answer:
2 is an initial value
tell me if its right because i garuntee it is
Find the value of g(7) for the function below. g(x)= 7/8x -1/2
g(x) = ⅞x - ½
g(7) = ⅞(7) - ½
= 49/8 - ½
= 49/8 - 4/8
= 45/8
= 5 ⅝
So, the value of g(7) for that function is 5 ⅝
Hope it helpful and useful :)
The value of the given function for g(7) is 45/8.
The given function is [tex]g(x)=\frac{7}{8}x-\frac{1}{2}[/tex].
What is the function?Functions are the fundamental part of the calculus in mathematics. The functions are the special types of relations. A function in math is visualized as a rule, which gives a unique output for every input x.
We need to find the value of g(7)
Substitute x=7 in the given function and simplify, we get
[tex]g(7)=\frac{7}{8}(7)-\frac{1}{2}[/tex]
= 49/8 - 1/2
= 49/8 - 4/8
= 45/8
Hence, the value of the given function for g(7) is 45/8.
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Lauren plans to deposit $6000 into a bank account at the beginning of next month and $225/month into the same account at the end of that month and at the end of each subsequent month for the next 4 years. If her bank pays interest at a rate of 3%/year compounded monthly, how much will Lauren have in her account at the end of 4 years?
Answer:
$18206.5
Step-by-step explanation:
Considering, r = interest rate
n = number of intervals
t = duration of the payment
A = monthly installment
PV = Present Value
FV = Final Value
Using the formula
FV=PV (1+ r/n[tex])^{nt-1[/tex] + a((1+ r/n[tex])^{nt[/tex]-1/[tex]\frac{r}{n}[/tex])
FV=6000[tex](1+ \frac{0.03}{12} )^{(12)(4)-1} +225\frac{(1+0.03/12)^{(12)(4)}-1 )}{0.03/12}[/tex]
FV= 6747 + 11459.5
FV=18206.5
Her balance in 4 years is $18206.5
3x^2 + 18x + 27 = 0 can you solve for x
Answer:
3x^2 + 18x + 27 = 0
<=> 3(x^2 + 6x + 9) = 0
<=> 3(x + 3)^2 = 0
<=> x = -3
Hope this helps!
:)
a) Spouses are asked about the number of hours of sleep they get each night. Upper A researcher wants to see if husbands get more sleep than wives. Choose the correct answer below. A. This scenario should not be analyzed using paired data because the groups are dependent but do not have a natural pairing. B. This scenario should not be analyzed using paired data because the groups are independent and do not have a natural pairing. C. This scenario should not be analyzed using paired data because the groups have a natural pairing but are independent. D. This scenario should be analyzed using paired data because the groups are dependent and have a natural pairing.
Answer:
D. This scenario should be analysed using paired data because the groups are dependent and have a natural pairing.
Step-by-step explanation:
Paired Data can be defined as data set, when sample units of one data set are related to sample units in other data set.
Research Study about spouses number of hours of sleep each night is paired data. As, each man in the male sample group is related to a corresponding woman (his wife) in the female sample group. So, they have a natural paring & they, their sleep schedules are dependent on each other.
Based on the information given, this scenario should be analyzed using paired data because the groups are dependent and have a natural pairing.
It should be noted that paired data is when sample units of one data set are related to sample units in another data set.Based on the information given, the case should be analyzed using paired data because the groups are dependent and have a natural pairing.In conclusion, the correct option is D.
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3. Erin's soccer team has won 17 of
their 20 games this season. What is
the probability that they will win their
next game?
Answer:
They have a 85% chance of winning their next game.
Step-by-step explanation:
100÷20 = 5
17×5=85
So, they have a 85% chance of winning their next game.
Hope This helped!!!!! :)
The net below represent a container. What solid figure does it show?
How many vertices does the container have?
The solid figure that is shown by the net would be a Rectangular prism.
The number of vertices would be 8 vertices.
How to describe a rectangular prism?A rectangular prism is a 3D shape with six faces, eight vertices, and twelve edges. It is a type of polyhedron, which is a solid figure with flat faces and straight edges.
The net given is a rectangular prism because the dashed lines show that the sides would fold up along with the triangles to form a rectangular prism.
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What is the mean of 3, 2, 26, 9
Answer:
10
Step-by-step explanation:
3+2=5+26=31+9=40/4=10
Step-by-step explanation:
When finding mean, you have to add up all of the number and divide that answer by the number of numbers used.
3 + 2 + 26 + 9 = 40
Now, we will divide 40 by 4 because there are 4 numbers.
40 / 4 = 10
So, the mean of the set is 10.
A major retail clothing store is interested in estimating the difference in mean monthly purchases by customers who use the store's in-house credit card versus using a Visa, Mastercard, or one of the other major credit cards. To do this, it has randomly selected a sample of customers who have made one or more purchases with each of the types of credit cards. The following represents the results of the sampling. In-House Credit Card National Credit Card Sample Size: 86 113 Mean Monthly Purchases: $45.67 $39.87 Standard Deviation: $10.90 $12.47 Suppose that the managers wished to test whether there is a statistical difference in the mean monthly purchases by customers using the two types of credit cards, using a significance level of 0.05, what is the value of the test statistic assuming the standard deviations are known? Round to two decimal places.
a box contains 8 red balls, 5 brown balls, 4 purple balls, and 3 green balls. what is the probability that a purple ball will be selected from the box after a red ball is taken out and not replaced?
Write the probability as a percent. Round to the nearest tenth of a percent as needed.
4. The null hypothesis for the chi-square goodness-of-fit test states that the distribution of A. cases for each group is equal to the expected distribution based on theory/knowledge of the population. B. sample means is equal to expectation based on the expected frequency. C. sample means for each group is equal. D. the sample means is equal to the expected distribution based on theory/knowledge of the population.
Answer:
D. the sample means is equal to the expected distribution based on theory/knowledge of the population.
Step-by-step explanation:
The Chi square goodness-of-fit test is used in statistical analysis to determine if the observed value in a collection of data, is significantly different from the expected value. Theoretical distribution which could be classified as normal, binomial, or poisson, are compared against the empirical distribution.To run a chi square goodness-of-fit test, we first formulate the null and alternate hypothesis. The degrees of freedom are then observed from the data given and the hypothesis is tested.
The null hypothesis assumes that the observed frequencies are equal to the expected frequencies. If there is a considerable difference, then the null hypothesis is rejected.
Bridget has swimming lessons every fifth day and diving lessons every third day. If she had a swimming lesson and a diving lesson on May 5, when will be the next date on which she has both swimming and diving lessons?
Answer:
The 20th of May
Step-by-step explanation:
I made a chart like a calendar and started on the 5th of may and counted every 5 days for the swimming lessons and every 3 days. Then I saw when she had both swimming and driving lessons and the first time after the 5th is the 20th.
Answer:
Bridget will have both swimming and diving lessons on the 15th.
According to the National Institute on Drug Abuse, a U.S. government agency, 17.3% of 8th graders in 2010 had used marijuana at some point in their lives. A school official hopes to show the percentage is lower in his district, testing LaTeX: H_0H 0: LaTeX: p=0.173p = 0.173 versus LaTeX: H_aH a: LaTeX: p<0.173p < 0.173. The health department for the district uses anonymous random sampling and finds that 10% of 80 eighth-graders surveyed had used marijuana. Are conditions met for use of the normal model to represent the distribution of sample proportions?
Answer:
The conditions for use of the normal model to represent the distribution of sample proportion are not met. He should increase the sample size until the conditions are met.
If the test is done anyway, the null hypothesis failed to be rejected.
The conclusion is taht there is not enough evidence to support the claim that the percentage is lower in this district.
Step-by-step explanation:
The conditions for use of the normal model to represent the distribution of sample proportion are not met, as the affirmative responses are less than 10.
[tex]np=80*0.1=8<10[/tex]
If the test of hypothesis is done as if the conditiones were met, we know that the claim is that the percentage is lower in this district.
Then, the null and alternative hypothesis are:
[tex]H_0: \pi=0.173\\\\H_a:\pi<0.173[/tex]
The significance level is 0.05.
The sample has a size n=80.
The sample proportion is p=0.1.
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.173*0.827}{80}}\\\\\\ \sigma_p=\sqrt{0.001788}=0.042[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{p-\pi+0.5/n}{\sigma_p}=\dfrac{0.1-0.173+0.5/80}{0.042}=\dfrac{-0.067}{0.042}=-1.578[/tex]
This test is a left-tailed test, so the P-value for this test is calculated as:
[tex]P-value=P(z<-1.578)=0.057[/tex]
As the P-value (0.057) is greater than the significance level (0.05), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the percentage is lower in this district.
Tanya has captured many purple-footed bog frogs. She weighs each one and
then counts the number of yellow spots on its back. This trend line is a
fit for these data.
Answer:it’s strong the person under me is slow
Step-by-step explanation: cause I said so
Inclusive of a 7.6% sales tax, a diamond ring sold for $1721.60. Find the price of the ring before the tax was
added (Round to the nearest cent, if necessary)
Answer:
$159075.84
Step-by-step explanation:
100-7.6=92.4
1721.60*92.4=$159075.84
Sherry is cooking chicken for her family. She wants to be sure the chicken has an internal temperature of at least 170 degrees Fahrenheit. She uses a thermometer to measure the internal temperature at four randomly chosen places. The minimum reading in the sample is 180 degrees Fahrenheit. Identify the population, the parameter, the sample, and the statistic. Population, minimum temperature of 170 degrees Fahrenheit; parameter, all chicken meat temperature readings; sample, four random thermometer readings; statistic, minimum sample reading of 180 degrees Fahrenheit Population, all chicken meat temperature readings parameter, minimum temperature of 170 degrees Fahrenheit; sample, minimum sample reading of 180 degrees Fahrenheit; statistic, four random thermometer readings Population, four random thermometer readings; parameter, all chicken meat temperature readings; sample, minimum temperature of 170 degrees Fahrenheit; statistic, minimum sample reading of 180 degrees Fahrenheit Population, all chicken meat temperature readings; parameter, minimum temperature of 170 degrees Fahrenheit; sample, four random thermometer readings; statistic, minimum sample reading of 180 degrees Fahrenheit Population, minimum sample reading of 180 degrees Fahrenheit; parameter, all chicken meat; sample, minimum temperature of 170 degrees Fahrenheit; statistic, four random thermometer readings
Answer:
Population, all chicken meat; parameter, minimum temperature of 170 degrees Fahrenheit; sample, four random thermometer readings; statistic, minimum sample reading of 180 degrees Fahrenheit
Step-by-step explanation:
When dragons on planet Pern lay eggs, the eggs are either green or yellow. The biologists have observed over the years that 32% of the eggs are yellow, and the rest green. Next spring the lead scientist has permission to randomly select 45 of the dragon eggs to incubate. Consider all the possible samples of 45 dragon eggs. What is the usual number of yellow eggs in samples of 45 eggs
Answer:
The usual number of yellow eggs in samples of 45 eggs is 14.4.
Step-by-step explanation:
For each egg, there are only two possible outcomes. Either they are yellow, or they are not. The probability of an egg being yellow is independent of other eggs, so we use the binomial probability distribution to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
32% of the eggs are yellow
This means that [tex]p = 0.32[/tex]
45 eggs
This means that [tex]n = 45[/tex]
What is the usual number of yellow eggs in samples of 45 eggs
[tex]E(X) = np = 45*0.32 = 14.4[/tex]
The usual number of yellow eggs in samples of 45 eggs is 14.4.
In a random sample of 45 dragon eggs on planet Pern, we would typically expect around 14 to 15 eggs to be yellow, based on the given probability of an egg being yellow (which is 32%).
Explanation:The subject of the question relates to probabilities in statistics. Here, we are given that the chance a dragon's egg on planet Pern is yellow is 32% or 0.32 in decimal form. We are then asked to predict the number of yellow eggs in a group of 45 eggs.
To solve this, we simply multiply the total number of eggs by the notation of the probability:
45 eggs * 0.32 = 14.4
However, you can't have 0.4 of an egg, so we have to round this number to 14 or 15 eggs. Therefore, in a random sample of 45 dragon eggs, we would typically expect around 14 to 15 of them to be yellow assuming that the probability remains constant.
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