According to Prof. Bill Baker, the freedom of practicing professionals to make ethical decisions may not be worth unless they use a patterned approach for the sake of people and society and their welfare. This is true statement.
Answer: Option A
Explanation:
Ethical Decisions and their impact on society
When we talk about the professional fields; Engineers and Doctors comes first in our minds. The professional fields and persons make the roots of an ideal society for which they must take ethical decisions surely worth for the society.
The society has a right to expect ethical conduct from professionals. The conduct of taking ethical decisions must involve reasoning, planning and well execution. According to the Association for Practical and Professional Ethics, there are certain moral values that one must apply while practicing ethical decisions.
A 5.00 g bullet traveling 355 m/s is stopped by lodging in the side of a building. The heat produced is shared between the building and the bullet. How much heat in Joules must be shared?
Answer:
Explanation:
Given
mass of bullet [tex]m=5\ gm[/tex]
speed of bullet [tex]v=355\ m/s[/tex]
bullet is stopped by building and heat produced is shared between building and bullet
Kinetic Energy of bullet is converted into Thermal energy
Kinetic Energy of bullet [tex]K=\frac{1}{2}mv^2[/tex]
[tex]K=0.5\times 5\times 10^{-3}\times (355)^2[/tex]
[tex]K=315.06\ J[/tex]
So 315.06 J of Energy is converted in to thermal energy
If three uncharged styrofoam balls are placed together and agitated so that one gains +3 C of charge and another gains +4 C of charge, how much charge must there be on the third one?If three uncharged styrofoam balls are placed together and agitated so that one gains 3 of charge and another gains 4 of charge, how much charge must there be on the third one?a.+7 Cb.+1 Cc.0 Cd.−7 C
Answer:
(d) −7 C
Explanation:
Like charges attracts and unlike charges repel. When the three charges are are agitated, the +3 C and +4 C will repel to give of +7 C. To create a balance in the system, the third charge will -7 C to give an algebraic sum of zero in the system.
If the skater started from rest 4 m above the ground (instead of 7m), what would be the kinetic energy at the bottom of the ramp (which is still 1 m above the ground)?
--> mass of skater is 75 kg and the acceleration of gravity is 9.81 N/kg
If the skater started from rest 4 above the ground (instead of 7), what would be the kinetic energy at the bottom of the ramp (which is still 1 above the ground)?
a. 735 J
b. 2940 J
c. 2205 J
d. 4410 J
Answer:
C. 2205 J
Explanation:
First we need to find the final velocity of skater at the bottom.
We, have:
Height lost = h = 4 m - 1 m = 3 m
Initial Velocity = Vi = 0 m/s (since, it starts from rest)
acceleration due to gravity = g = 9.8 m/s²
using third equation of motion:
2gh = Vf² - Vi²
2(9.8 m/s²)(3 m) = Vf² - (0 m/s)²
Vf² = 58.8 m²/s²
Now, for kinetic energy at bottom:
K.E = (1/2) m Vf²
K.E = (1/2)(75 kg)(58.8 m²/s²)
K.E = 2205 J
Hence, the correct option is C. 2205 J
Two steamrollers begin 105 m apart and head toward each other, each at a constant speed of 1.30 m/s . At the same instant, a fly that travels at a constant speed of 2.40 m/s starts from the front roller of the southbound steamroller and flies to the front roller of the northbound one, then turns around and flies to the front roller of the southbound once again, and continues in this way until it is crushed between the steamrollers in a collision.What distance does the fly travel?
According to the question,
Object's relative speed,
[tex]v_{rel} = 1.30+1.30[/tex]
[tex]= 2.60 \ m/s[/tex]
Time taken by the two steamrollers,
[tex]t = \frac{d}{v_{rel}}[/tex]
[tex]= \frac{105}{2.60}[/tex]
[tex]= 40.39 \ seconds[/tex]
hence,
The distance of fly travel will be:
→ [tex]s = vt[/tex]
By putting the values,
[tex]= 2.40\times 40.39[/tex]
[tex]= 96.94 \ m[/tex]
Thus the above response is right.
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A rotating flywheel can be used as a method to store energy. If it is required that such a device be able to store up to a maximum of 1.00 ×106J when rotating at 400 rad/s, what moment of inertia is required? a. 50 kg⋅m2b. 25 kg⋅m2c. 12.5 kg⋅m2d. 6.3 kg⋅m2
Answer:
[tex]I=12.5\ kg.m^2[/tex]
Explanation:
Given that
Stored energy ,[tex]E=1\times 10^6[/tex]
Angular speed ,[tex]\omega =400\ rad/s[/tex]
Lets take moment of inertia of the flywheel = I
As we know that stored energy in the flywheel is given as
[tex]E=\dfrac{1}{2}\omega^2 I[/tex]
[tex]I=\dfrac{2\ttimes E}{\omega^2}[/tex]
Now by putting the values in the above equation we get
[tex]I=\dfrac{2\times 1\times 10^6}{400^2}\ kg.m^2[/tex]
[tex]I=12.5\ kg.m^2[/tex]
Therefore the moment of inertia of the flywheel will be [tex]I=12.5\ kg.m^2[/tex]
The answer will be C.
[tex]I=12.5\ kg.m^2[/tex]
An airplane weighing 5000 lb is flying at standard sea level with a velocity of 200 mi/h. At this velocity the L/D ratio is a maximum. The wing area and aspect ratio are 200 ft2 and 8.5, respectively. The Oswald efficiency factor is 0.93. Calculate the total drag on the airplane.
Answer:
98.15 lb
Explanation:
weight of plane (W) = 5,000 lb
velocity (v) = 200 m/h =200 x 88/60 = 293.3 ft/s
wing area (A) = 200 ft^{2}
aspect ratio (AR) = 8.5
Oswald efficiency factor (E) = 0.93
density of air (ρ) = 1.225 kg/m^{3} = 0.002377 slugs/ft^{3}
Drag = 0.5 x ρ x [tex]v^{2}[/tex] x A x Cd
we need to get the drag coefficient (Cd) before we can solve for the drag
Drag coefficient (Cd) = induced drag coefficient (Cdi) + drag coefficient at zero lift (Cdo)
where
induced drag coefficient (Cdi) = [tex]\frac{Cl^{2} }{n.E.AR}[/tex] (take note that π is shown as n and ρ is shown as [tex]p[/tex])where lift coefficient (Cl)= [tex]\frac{2W}{pAv^{2} }[/tex]=[tex]\frac{2x5000}{0.002377x200x293.3^{2} }[/tex] = 0.245
therefore
induced drag coefficient (Cdi) = [tex]\frac{Cl^{2} }{n.E.AR}[/tex] = [tex]\frac{0.245^{2} }{3.14x0.93x8.5}[/tex] = 0.0024
since the airplane flies at maximum L/D ratio, minimum lift is required and hence induced drag coefficient (Cdi) = drag coefficient at zero lift (Cdo)Cd = 0.0024 + 0.0024 = 0.0048Now that we have the coefficient of drag (Cd) we can substitute it into the formula for drag.
Drag = 0.5 x ρ x [tex]v^{2}[/tex] x A x Cd
Drag = 0.5 x 0.002377 x (293.3 x 293.3) x 200 x 0.0048 = 98.15 lb
The total drag on the airplane is approximately 376.4 pounds (lb).
To calculate the total drag on the airplane, we'll use the following formula for total drag:
[tex]\[D = \frac{W^2}{q \cdot S \cdot \pi \cdot e \cdot AR}\][/tex]
Where:
- \(D\) is the total drag in pounds (lb).
- \(W\) is the weight of the airplane in pounds (lb), which is 5000 lb in this case.
- \(q\) is the dynamic pressure in lb/ft^2, given by [tex]\(q = 0.5 \cdot \rho \cdot V^2\)[/tex], where[tex]\(\rho\)[/tex] is the air density at standard sea level (0.002377 lb/ft^3) and \(V\) is the velocity in ft/s (200 mi/h converted to ft/s).
- S is the wing area in square feet (ft^2), which is 200 ft^2.
- pi is approximately 3.1416.
- e is the Oswald efficiency factor, which is 0.93 in this case.
- AR is the aspect ratio, which is 8.5 in this case.
Let's calculate it step by step:
1. Convert the velocity from miles per hour (mi/h) to feet per second (ft/s):
[tex]\[V = 200 \, \text{mi/h} \times \frac{5280 \, \text{ft/mi}}{3600 \, \text{s/h}} = 293.33 \, \text{ft/s}\][/tex]
2. Calculate the dynamic pressure (\(q\)):
[tex]\[q = 0.5 \cdot \rho \cdot V^2 = 0.5 \cdot 0.002377 \, \text{lb/ft}^3 \cdot (293.33 \, \text{ft/s})^2 = 21.81 \, \text{lb/ft}^2\][/tex]
3. Now, plug the values into the total drag formula:
[tex]\[D = \frac{5000 \, \text{lb}^2}{21.81 \, \text{lb/ft}^2 \cdot 200 \, \text{ft}^2 \cdot 3.1416 \cdot 0.93 \cdot 8.5} \approx 376.4 \, \text{lb}\][/tex]
So, the total drag on the airplane is approximately 376.4 pounds (lb).
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A particle beam is made up of many protons, each with a kinetic energy of 3.25times 10-15 J. A proton has a mass of 1.673 times 10-27 kg and a charge of 1.602 times 10-19 C. What is the magnitude of a uniform electric field that will stop these protons in a distance of 2 m?
Answer:
E = 1.024 x 10⁴ V/m
Explanation:
given,
KE of the particle = 3.25 x 10⁻¹⁵ J
mass of the proton = 1.673 x 10⁻²⁷ Kg
charge of the proton = 1.602 x 10⁻¹⁹ C
distance = 2 m
Electric field = ?
we know
work done = KE, and also
W = q V
now,
[tex]V = \dfrac{W}{q}[/tex]
[tex]V = \dfrac{3.25\times 10^{-15}}{1.602\times 10^{-19}}[/tex]
V = 2.028 x 10⁴ V
now, using equation of electric field
[tex]E = \dfrac{V}{d}[/tex]
[tex]E = \dfrac{2.028\times 10^4}{2}[/tex]
E = 1.024 x 10⁴ V/m
hence, the magnitude of the electric field is equal to E = 1.024 x 10⁴ V/m
Answer:
E = 1.024 x 10⁴ V/m
Explanation:
given,
KE of the particle = 3.25 x 10⁻¹⁵ J
mass of the proton = 1.673 x 10⁻²⁷ Kg
charge of the proton = 1.602 x 10⁻¹⁹ C
distance = 2 m
Electric field = ?
we know
work done = KE, and also
W = q V
now,
V = 2.028 x 10⁴ V
now, using equation of electric field
E = 1.024 x 10⁴ V/m
hence, the magnitude of the electric field is equal to E = 1.024 x 10⁴ V/m
Finally, you are ready to answer the main question. Cheetahs, the fastest of the great cats, can reach 50.0 miles/hour in 2.22 s starting from rest. Assuming that they have constant acceleration throughout that time, find their acceleration in meters per second squared.
Explanation:
We have equation of motion v = u + at
Initial velocity, u = 0 m/s
Final velocity, v = 50 miles/hr = 80 km/hr = 22.22 m/s
Time, t = 2.22 s
Substituting
v = u + at
22.22 = 0 + a x 2.22
a = 10 m/s²
Acceleration is 10 m/s²
Acceleration of cheetah is 10 m/s²
Consider a light, single-engine airplane such as the Piper Super Cub. If the maximum gross weight of the airplane is 7780 N, the wing area is 16.6 m2, and the maximum lift coefficient is 2.1 with flaps down, calculate the stalling speed at sea level?
The student's question concerns the calculation of the stalling speed for a Piper Super Cub airplane at sea level based on the maximum gross weight, wing area, and the maximum lift coefficient. By using the lift equation and rearranging it to solve for velocity, we can find the stalling speed that must be maintained for the airplane to generate enough lift to balance its weight.
Explanation:The student is asking to calculate the stalling speed of a Piper Super Cub airplane at sea level. The stalling speed is the minimum speed at which an airplane can maintain level flight. To find this, we can use the equation for lift, which at the stalling point must equal the weight of the airplane. The lift equation is L = (1/2) ∙ ρ ∙ V² ∙ S ∙ Cl where L is the lift force, ρ is the air density, V is the velocity, S is the wing area, and Cl is the maximum lift coefficient.
Given that:
Maximum gross weight (L) = 7780 N (this is the force that must be generated by lift at stalling speed)Wing area (S) = 16.6 m²Maximum lift coefficient (Cl) = 2.1 with flaps downAir density at sea level (ρ) = 1.29 kg/m³We can rearrange the lift equation to solve for velocity (V) and then plug in the numbers to calculate the stalling speed.
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10. A worker uses a pulley system to raise a 24.0 kg carton 16.5 m. A force of 129 N is exerted and the rope is pulled 33.0 m. a. What is the mechanical advantage of the pulley system?
Answer: Machanical advantage of the machine is 1.86
Explanation: Machanical advantage of a machine is the ratio of the Force to overcome which is the load in this case 24kg * 10= 240N to the force exerted(Effort) to overcome the load in this case 129N.
So, we have
MA = load/effort
= 240N/129N
= 1.86.
The mechanical advantage of the pulley system is equal to 1.82.
Given the following data:
Mass of carton = 24 kgLoad distance = 16.5 mEffort = 129 NewtonEffort distance = 33 mScientific data:
Acceleration due to gravity = 9.8 [tex]m/s^2[/tex]To determine the mechanical advantage of the pulley system:
First of all, we would calculate the force acting on the load as follows;
[tex]Force = mg\\\\Force = 24 \times 9.8[/tex]
Force = 235.2 Newton
Now, we can solve for mechanical advantage:
[tex]M.A = \frac{Load}{Effort} \\\\M.A=\frac{235.2}{129}[/tex]
Mechanical advantage = 1.82.
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A statement that the energy supplied to a system in the form of heat, minus the work done by the system, is equal to the change in internal energy represents the ___________
Answer:
First law of thermodynamics.
Explanation:
The first law of thermodynamics states that the change in internal energy of a system ΔE equals to the amount of heat energy supplied to the system H , minus the work done by the system on its surroundings. W.
The above definition can be expressed mathematically as: ΔE = H - W
This can also be restarted as energy of a close or isolated system is constant.
A pot of water on the stove has a temperature increase of 45 C. How much is that temperature increase in degrees Fahrenheit?
1. 25 degrees F increase2. 113 degrees F increase3. 57 degrees F increase4. 77 degrees F increase5. 81 degrees F increase
Answer:
2. 113 degrees F increase
Explanation:
Formula for converting °C to °F is
(°C × 9/5)+32
Where °C is the temperature value in degree Celsius. Given temperature to be 45°C, converting to °F we have;
(45°C × 9/5) + 32
= 81+32
= 113°F
An energy storage system based on a flywheel (a rotating disk) can store a maximum of 4.1 MJ when the flywheel is rotating at 14000 revolutions per minute.
Incomplete question.The complete question is here
An energy storage system based on a flywheel (a rotating disk) can store a maximum of 4.1 MJ when the flywheel is rotating at 14000 revolutions per minute.What is the moment of inertia of the flywheel?
Answer:
Moment of inertia=3.82 kg.m²
Explanation:
Given data
Energy E=4.1 MJ=4.1×10⁶J
Angular speed ω= 14000 rev/min= 14000×2π/60=1465.3 rad/s
To find
Moment of Inertia
Solution
A rotating flywheel must store its energy as kinetic energy
Let I be moment of inertia of the flywheel.We Know
[tex]E(Energy)=\frac{1}{2}Iw^{2}\\ I=\frac{2E}{w^{2} }\\ I=\frac{2(4.1*10^{6}) }{(1465.3)^{2} }\\ I=3.82 kgm^{2}[/tex]
The subject of this question is Physics and it relates to an energy storage system based on a flywheel.
Explanation:The subject of this question is Physics. The question relates to an energy storage system based on a flywheel.
A flywheel is a rotating disk that can store energy in the form of rotational kinetic energy. The maximum energy that can be stored in the flywheel depends on its moment of inertia and the square of its angular velocity.
In this case, the flywheel can store a maximum of 4.1 MJ when it is rotating at 14000 revolutions per minute.
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A container of water is lifted vertically 3.0 m then returned to its original position. If the total weight is 30 N, how much work total was done?
Answer:
Work done, W = 0
Explanation:
Given that, a container of water is lifted vertically 3.0 m then returned to its original position.The total weight of the container is 30 N. We need to find the total work done by the container. We know that the work done by an object is given by :
W = F × d
Where
F is the applied force
d is the displacement of the object
It is mentioned that the container returns to its original position, the displacement of the container is equal to 0. Hence, no work was done by the container of water.
Answer: No work was done when a container of water is lifted vertically 3.0 m and then returned to its original position.
Explanation:
Work is defined as a force causing the movement or displacement of an object.
work=[tex]f\times s[/tex]
Given: f = force = 30N
s = displacement = 0.0 m (as the initial and final position is same, there is no displacement)
Putting in the values we get,
work=[tex]30N\times 0m=0J[/tex]
Thus amount of work will be 0 J.
The subfield of anthropology that describes, analyzes, interprets, and explains social and cultural similarities and differences is ______ anthropology.
Answer:
cultural
Explanation:
Cultural anthropology studies the characteristics of the behavior learned in human societies, that is, science of human culture. In general, it is the science that studies the origin, development, structure, characteristics and variations of human culture in both past and present societies. Ethnography, ethnology, archeology, linguistics and physical anthropology are the disciplines on which cultural anthropology is founded.
A total resistance of 3.03 Ω is to be produced by connecting an unknown resistance to a 12.18 Ω resistance. (a) What must be the value of the unknown resistance, and
Answer:
(a) 4.0334Ω
(b)parallel
Explanation:
for resistors connected in parallel;
[tex]\frac{1}{R_{eq} } =\frac{1}{R1}+\frac{1}{R2}[/tex]
Req =3.03Ω , R1 =12.18Ω
[tex]\frac{1}{3.03 } =\frac{1}{12.18}+\frac{1}{R2}[/tex]
[tex]\frac{1}{R2}=\frac{1}{3.03 }-\frac{1}{12.18}[/tex]
[tex]\frac{1}{R2}=0.2479[/tex]
R2=1/0.2479
R2=4.0334Ω
(b)parallel connection is suitable for the desired total resistance. series connection can not be used to achieve a lower resistance as the equation for series connection is.
Req = R1+R2
To achieve a total resistance of 3.03 Ω when an unknown resistor is connected in parallel with a 12.18 Ω resistor, the unknown resistance must be 4.03 Ω.
Explanation:To determine the unknown resistance that needs to be connected to a 12.18 Ω resistor to produce a total resistance of 3.03 Ω, we can use the formula for resistors in parallel, since the total resistance is given and is less than the resistance of the known resistor. The formula is:
1 / Rtotal = 1 / R1 + 1 / R2
We can arrange the formula to solve for R2, the unknown resistance:
1 / R2 = 1 / Rtotal - 1 / R1
By plugging in the given values (Rtotal = 3.03 Ω, R1 = 12.18 Ω), we get:
1 / R2 = 1 / 3.03 - 1 / 12.18
Calculating the right side of the equation:
1 / R2 = 0.330 - 0.0821
1 / R2 = 0.2479
Finally, we take the reciprocal of both sides to find R2:
R2 = 1 / 0.2479
R2 = 4.03 Ω
So, the unknown resistance must be 4.03 Ω to achieve the specified total resistance when connected in parallel with a 12.18 Ω resistor.
During practice, a baseball player hits a very high fly ball, and then runs in a straight line and catches it. Which had the greatest displacement during the time period from the hitting of the ball to its catching
Answer:
The player and the ball have the same displacement
Explanation:
Displacement is the distance between the final position and initial position, When the ball is hit upwards, it is caught at the same height. The vertical displacement of the ball is zero. The horizontal displacement of the ball would be equal to the displacement of the player because the player runs in a straight line to catch the ball.
A ______ cell is the pattern mantle material takes as it rises when heated, then moves laterally as it cools, and sinks once its density is great enough.
Answer:
Convection cell
Explanation:
The convection current refers to the upward rising of the hot molten and less dense magma in the mantle. These currents are formed due to the heat supplied from the core of the earth. This upward movement of magma results in the movement of the lithospheric plates over the less dense viscous layer of the asthenosphere.
As the magma at the greater depth gets heated up, due to the increasing heat and pressure, it gets heated up and rises upward in the form of convection cells. As it rises upward, it cools and slowly moves laterally and eventually sinks after its density increases. This cycle repeats and forms the main mechanism for the plate tectonic movement.
The ____ is a unique cabling system that allows one cable to be adapted to various services through the use of interchangeable modular connectors at both the work area outlet and the patch panel in the TR.
Answer:
ACO cable mate
Explanation:
The water mass having both high salinity and warm temperature and found at about 1,000 meters water depth in the central north Atlantic has been formed
Answer:
In the Mediterranean sea
Explanation:
The water present in the deeper part of the North Atlantic ocean is warm and comprised of high salinity, and abundance in oxygen as well as rich in terms of nutrient ones. On the other hand, the opposite occurs in the southern part of the Atlantic ocean. This warm water is typically found up to a depth of about 1000 meters below the mean sea level.
This Atlantic ocean is directly connected to the Mediterranean sea through the Gibraltar Strait.
Therefore, this mass of water that is comprised of higher salinity and higher temperature that is found at a depth of 1000 meters in the northern part of the Atlantic ocean has been formed in the Mediterranean sea.
A ball is thrown straight up, reaches a maximum height, then falls to its initial height. Make a statement about the direction of the velocity and acceleration as the ball is coming down.
Answer:
Explanation:
When the ball is thrown upwards it's velocity is pointing upwards while acceleration i.e. acceleration due to gravity is pointing downwards.
As the ball moves upwards it's velocity is decreasing and the ball reaches maximum height it's velocity becomes zero while the acceleration is still pointing downwards.
During downward motion, both velocity and acceleration are pointing downward.
If your volume measurement is only good to two significant figures, will your results be more precise if you use mass measurements that have six significant figures. Is it true?
Using mass measurements with six significant figures does not increase the precision of your results if your volume measurement is only accurate to two significant figures, due to the rule that in multiplication or division, the result must be reported with the same number of significant figures as the measurement with the least number of significant figures.
Explanation:If your volume measurement is only good to two significant figures, will your results be more precise if you use mass measurements that have six significant figures? The answer is no. When determining the precision of your results in chemistry, particularly in calculations involving volume and mass, it is vital to understand the rules governing significant figures. According to these rules, when performing multiplication or division, the result should be reported with the same number of significant figures as the measurement with the least number of significant figures. For instance, if a calculation involving the density formula (density = mass/volume) uses a mass with six significant figures and a volume with only two, the final density value should be expressed with two significant figures.
This principle ensures that the precision of your results reflects the precision of the least precise measurement. It prevents the false impression of greater accuracy than the measurements allow. Therefore, even if your mass measurements are incredibly precise, having six significant figures, the precision of your results will still be limited by the two significant figures in your volume measurement. This rule highlights the importance of consistency in measurement precision for enabling accurate and reliable scientific work. The concept of significant figures serves as a fundamental aspect of data analysis and reporting in chemistry, ensuring that reported results accurately reflect the uncertainties inherent in experimental measurements.
A positively charged particle initially at rest on the ground accelerates upward to 140 m/s in 2.10 s. The particle has a charge-to-mass ratio of 0.100 C/kg and the electric field in this region is constant and uniform.What are the magnitude and direction of the electric field?
Answer:
764.7 N/C, the direction is upward
Explanation:
E electric field of the electron = F / charge
F force of the electron = Eq
acceleration of the body = change in velocity / time = 140 m / 2.10 s = 66.67 m/s² since the electron is from rest.
F upward = F of electron - force of gravity
F upward = Eq - mg
ma = Eq -mg
divide through with m
a = E (q/m) - g
(a + g) / (q/m) = E
(66.67 + 9.8) / 0.100 = 764.7 N/C, the direction is upward
g and the electric field in this region is constant and uniform.What are the magnitude and direction of the electric field?
An observer sees a lightning flash from a distant thunder-storm and 12 seconds later hears the sound. if the temperature of the air is 20 c, how far from the storm is the observer?
Answer:
The answer is 3597501.48 km
Explanation:
The speed of light is 299792 km/s.
The speed of sound is 0.343 km/s
The difference is 299791.76 km/s
and of there is 12 second difference between sound and the light. The distance will be:
[tex]299791.76*12=3597501.48[/tex]
It should be far from the storm is the observer is 3597501.48 km.
Air Temperature:It measured how hot or cold the air should be. It explained the kinetic energy, or energy of motion, of the gases that make up air. Since gas molecules move faster due to which there is an increment in the air temperature
Since the temperature of the air is 20c and there is 12 seconds.
Also,
The speed of light is 299792 km/s.
The speed of sound is 0.343 km/s
The difference is 299791.76 km/s
Now it is
[tex]= 299791.76 km/s \times 12[/tex]
= 3597501.48 km
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A fly wheel with a diameter of 1.20m is rotating at an angular speed of 200 Rev/min
(a) what is the angular speed of the flywheel in radians per second be
(b)what is the linear speed of a point in the rim of the flywheel
(c) what constant angular acceleration
Answer:a) 20.944rad/s (b) 12.57m/s (c) 800rev/min²
Explanation:
Final answer:
The angular speed of the flywheel in radians per second is 20π/3 radians/s. The linear speed of a point in the rim of the flywheel is 40π/9 m/s. The constant angular acceleration of the flywheel cannot be determined without additional information.
Explanation:
(a) To convert the angular speed from revolutions per minute (rpm) to radians per second, we need to multiply by a conversion factor of
2π radians = 1 revolution
First, convert the angular speed from rpm to revolutions per second:
200 rev/min × (1 min/60 s) = 200/60 rev/s
Next, convert the revolutions per second to radians per second:
200/60 rev/s × (2π radians/1 rev) = 20π/3 radians/s
So, the angular speed of the flywheel in radians per second is 20π/3 radians/s.
(b) The linear speed of a point on the rim of the flywheel can be calculated using the formula:
Linear speed = angular speed × radius
Given that the diameter of the flywheel is 1.20 m, the radius is 0.60 m.
Linear speed = (20π/3 radians/s) × (0.60 m) = 40π/9 m/s
So, the linear speed of a point in the rim of the flywheel is 40π/9 m/s.
(c) The flywheel has a constant angular acceleration if its angular velocity changes at a constant rate over time. The formula for angular acceleration is:
Angular acceleration = change in angular velocity / change in time
Since the question does not provide information about the change in angular velocity or time, we cannot determine the constant angular acceleration of the flywheel.
A baseball pitcher throws at 95 mile/hr at a hitter 60 feet 6 inches away. How long does it take for the baseball to reach the hitter?
Answer:
0.43 s
Explanation:
speed (s) = 95 mi/h = 95 x 1600/3600 = 42.5 m/s (converting to m/s)
distance (d) = 60 ft 6 inches = (60 x 0.3048) + (6 x 0.025) = 18.44 m (converting to meters)
speed = distance / time
time = distance / speed = 18.44 / 42.5 = 0.43 s
When a cold alcohol-in-glass thermometer is first placed in a hot tub of water, the alcohol initially descends a bit and then rises. Explain.
Answer:
Wen we place a cold alcohol in glass in a hot tub of water then the glass will be warmed first so it will expand a little due to which the level of alcohal decreases. After some time when thermal equilibrium is achevied then the alcohol will expand more then glass as the alcohol has the greater coeficient of expansion then glass so there will be an incerease in the level of alcohol which will indicate how much high the temperature is.
Explanation:
The alcohol level in a thermometer initially drops when placed in hot water because the glass expands first, temporarily increasing the volume before the alcohol heats up and rises. This illustrates the principle of thermal expansion.
When a cold alcohol-in-glass thermometer is initially placed in a hot tub of water, the column of alcohol first descends slightly before rising. This phenomenon can be explained by the principles of thermal expansion.
Initially, the cold glass of the thermometer comes into contact with the hot water. Because the glass directly touches the hot water, it heats up faster than the alcohol inside. Glass has a lower thermal conductivity compared to alcohol, so it responds quicker to the temperature change. As the glass heats up, it expands slightly. This initial expansion of the glass causes a temporary increase in the volume inside the thermometer, making the alcohol level drop slightly.After a brief moment, the alcohol begins to heat up and expand. The alcohol expands much more than the glass due to its higher coefficient of thermal expansion. As the alcohol expands, it rises up the narrow tube, indicating an increase in temperature.This behavior demonstrates the concept of thermal expansion where different materials expand at different rates when subjected to temperature changes. Understanding this concept helps explain the movement of the alcohol column within the thermometer.A plastic rod is charged up by rubbing a wool cloth, and brought to an initially neutral metallic sphere that is insulated from ground. It is allowed to touch the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod:A) is repelled by the sphere.B) is attracted to the sphere.C) feels no force due to the sphere.I know the answer is A, but I don't understand why. how do we know that the sphere and the rod have the same charge? What does it mean to be insulated from the ground?
Answer:
You are right. The answer to this question is option A. The metallic sphere is a conductor and can allow electric charges flow through it from one region to another. The reason the sphere is insulted from the ground is to block out the transfer of charges from the sphere to the ground or from the ground to the sphere. The ground itself can serve as infinitely large sink or source for electric charges.
The act of touching the sphere with the charged rod deposits some electric charge on the sphere. These charges in the absence of an insulator between the sphere and the ground will flow straight into the ground. But because there is an insulator connected to the sphere the charges remain on the sphere with no way of getting out of the sphere.
These charges are the same with that on the rod as they were conducted and not induced by polarization (in general if the shepre became charged by polarization, it would have a charge opposite that on the rod). Since like charges repeatedly and unlike charges attract. The sphere would always repel the rod.
Thank you for reading and I hope this was helpful to you.
When the plastic rod is charged and brought close to the neutral metallic sphere, charges are redistributed. After touching and separating, the rod is repelled by the sphere due to the imbalance of charges. Insulating the sphere from the ground prevents charge redistribution.
Explanation:When the plastic rod is rubbed with a wool cloth, it becomes charged and gains electrons. The charged rod is brought close to the initially neutral metallic sphere, which causes a redistribution of charges on the sphere's surface. Electrons in the sphere are attracted to the positively charged rod, causing an imbalance of charges.
When the rod touches the sphere, electrons from the sphere are transferred to the rod, neutralizing the rod's charge. The sphere gains a negative charge due to the excess electrons it lost to the rod. When the rod is separated from the sphere, it is now negatively charged and repelled by the negatively charged sphere.
Insulating the sphere from the ground means that the sphere is not in contact with any conductive material that can provide or receive charge. This ensures that the charge on the sphere remains constant and does not redistribute to the ground, allowing for the charge redistribution between the rod and the sphere.
Learn more about Charge redistribution during charging and repulsion here:https://brainly.com/question/31216711
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A man 6 feet tall walks at a rate of 5 feet per second away from a light that is 15 feet above the ground. When he is 10 feet from the base of the light, a) at what rate is the tip of his shadow moving?
Answer:
[tex]\frac{25}{3}ft/s[/tex]
Explanation:
Height of man= 6ft
Height of light=1 5ft
Let BC=x and CD=y
BD=x+y
Triangle ABD and ECD are similar
When two triangles are similar then the ratio of their corresponding sides are equal
[tex]\frac{AB}{EC}=\frac{BD}{CD}[/tex]
[tex]\frac{15}{6}=\frac{x+y}{y}[/tex]
[tex]\frac{5}{2}=\frac{x+y}{y}[/tex]
[tex]5y=2x+2y[/tex]
[tex]5y-2y=2x[/tex]
[tex]3y=2x[/tex]
Differentiate w.r.t t
[tex]2\frac{dx}{dt}=3\frac{dy}{dt}[/tex]
We have [tex]\frac{dx}{dt}=5ft/s[/tex]
Substitute the value then we get
[tex]2\times 5=3\frac{dy}{dt}[/tex]
[tex]\frac{dy}{dt}=\frac{2\times 5}{3}=10/3ft/s[/tex]
Rate at which the tip of shadow is moving=[tex]\frac{dx}{dt}+\frac{dy}{dt}[/tex]
Rate at which the tip of shadow is moving=[tex]5+\frac{10}{3}=\frac{15+10}{3}ft/s[/tex]
Rate at which the tip of shadow is moving=[tex]\frac{25}{3}ft/s[/tex]
A cargo elevator on Earth (where g = 10 m/s2) lifts 3000 kg upwards by 20 m. 720 kJ of electrical energy is used up in the process. What is the efficiency of this process?
Answer: 83%
Explanation:
Efficiency of the process = work output/work input × 100%
Work input is the energy used up in the process = 720,000Joules
Work output = Force × distance
= (3000×10)× 20
= 600000 Joules
Efficiency= 600000/720000 × 100
= 0.83×100
= 83%