According to Plato what is the highest principle in reality

Answer:

10 calories

Explanation:

The thermal energy needed to increase the temperature of a substance is given by

[tex]Q=m C \Delta T[/tex]

where

m is the mass of the substance

C is the specific heat of the substance

[tex]\Delta T[/tex] is the increase in temperature

In this problem, the mass of the ice is m=20 g, the specific heat is C=0.5 calories/gram°C, and the increase in temperature is [tex]\Delta T=1^{\circ}[/tex]. Therefore, the energy required is

[tex]Q=(20 g)(0.5 cal/g^{\circ}C)(1^{\circ}C)=10 cal[/tex]

The magnitude of the normal force, fn, for a block on a horizontal rigid surface with a gravitational force fg of 40 N is equal to the gravitational force, making fn also 40 N.

The magnitude of the normal force, fn, acting on a block on a horizontal surface is equal to the weight of the block when the surface is rigid and there are no other vertical forces except gravity. If we denote the gravitational force as fg, which in this case is 40 N, and given that there are no additional vertical forces and the surface is horizontal, the normal force will balance the gravitational force. Therefore, we have  fn = fg, so the normal force fn is also 40 N.

In scenarios where there are additional vertical forces or the surface is not horizontal, the normal force is calculated by summing all vertical forces, where forces pushing the block into the surface increase the normal force and forces lifting the block reduce the normal force. However, in this example, such complexities are absent, making the calculation straightforward.

According to the calculations, the water balloon does not hit the professor. It comes closest to her when it is approximately 0.316 meters away.

In order to determine if the water balloon hits the professor, we need to calculate the time it takes for the balloon to reach the ground. The time can be found using the equation:

t = \sqrt{\frac{2h}{g}}

Where t is the time, h is the height (18.0 meters), and g is the acceleration due to gravity (9.8 m/s^2). Plugging in the values, we find that it takes approximately 1.52 seconds for the balloon to reach the ground.

We also need to calculate the horizontal distance the professor walks in that time. The distance can be found using the equation:

d = vt

Where d is the distance, v is the velocity (0.450 m/s), and t is the time (1.52 seconds). Plugging in the values, we find that the professor walks approximately 0.684 meters during that time.

Therefore, since the professor is 1.00 meter from the point directly beneath the window, the balloon does not hit her. It comes closest to her when it is 0.316 meters away from her.

Answer:

Energy  the electron have initially [tex]E_4=-0.85 \rm ev[/tex],

The change in energy if the electron from part a now drops to the ground state is [tex]12.75\rm ev[/tex]

Explanation:

Given information:

Electron have initially in the n=4 excited state,

We know,

Energy of an electron is given by,

[tex]E_n=-13.6\rm ev\times\frac{z^2}{n^2}[/tex]

On substituting n=4 for excited state energy,

[tex]E=-13.6\rm ev\times\frac{1^2}{4^2}=-0.85\rm ev[/tex]

Change in energy from excited state to ground state,

For ground state n=1,

[tex]E=-13.6\rm ev\times z^2\times( \frac{1}{(n_2)^2}-\frac{1}{(n_1)^2})[/tex]

On substituting [tex]n_1=1[/tex],[tex]n_2=4[/tex],

[tex]\Delta E=E_4-E_1=-13.6\rm ev\times 1^2\times( \frac{1}{(4)^2}-\frac{1}{(1)^2})=12.75ev[/tex]

Hence, energy  the electron have initially [tex]E_4=-0.85 \rm ev[/tex],

NOTE:- [tex]1\rm ev=-1.602\times 10^{-19}joule[/tex]

Energy  the electron have initially [tex]E_4=-0.85 \rm ev[/tex],

The change in energy if the electron from part a now drops to the ground state is [tex]12.75\rm ev[/tex]

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Answer:

[tex]108\ N[/tex]

Explanation:

Mass of object, [tex]m=1.50\ kg.[/tex]

Length of string, [tex]r=0.50\ m.[/tex]

Tangential speed, [tex]v_t=6.0\ m/s.[/tex]

Now, centripetal force F of a object moving in given radius r and mass m moving with velocity v.

Here , object moves along the ends of string. Therefore, radius is equal to length of string.

[tex]F=\dfrac{m \times v_t^2}{r}.[/tex]

Putting values of m,v and r in above equation.

We get, [tex]F=\dfrac{1.50\times (6.0)^2}{0.50} \ N=108 \ N.[/tex]

Hence, this is the required solution.

By six times, a person should jump farther on the moon as compared to the earth if the takeoff speed and angle are the same.

The height of the earth can be computed using the third equation of motion. The third equation of motion, referred to as one of the kinematic equations, relates the final velocity, initial velocity, acceleration, and displacement of an object.

The height of the earth is given as:

[tex]v^2-u^2= 2gH_e\\v^2 = 2\times9.8\timesH_e\\H_e = v^2/2g[/tex]

The height of the moon is given as:

[tex]v^2-u^2 = 2(g/6)H_m\\v^2 = g/3H_m\\H_m = 3v^2/g[/tex]

The ratio of both heights is given as:

[tex]H_m/H_e = 3v^2/g/(v^2/2g)\\H_m/H_e = 6\\H_m = 6H_e[/tex]

Hence, by six times, a person should jump farther on the moon as compared to the Earth if the takeoff speed and angle are the same.

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A person can jump about six times further on the Moon compared to Earth given the same initial angle and speed. This is because the acceleration due to gravity on the moon is one-sixth that of Earth, resulting in a weaker gravitational pull.

The topic in question involves the concept of gravitational forces and its influence on the jump length of a person on Earth versus the Moon. The acceleration due to gravity on the Moon is about one-sixth that of Earth, meaning the gravitational force is much weaker. Therefore, if a person jumps with the same speed and angle on the moon as on Earth, they would be able to jump approximately six times farther due to the weaker gravitational pull.

For better understanding, consider this example. If a person jumps and covers a certain distance on Earth in a given time, the same person would be airborne six times as long on the Moon if they jumped with the same velocity. This is due to the inverse relationship between the time of flight (airborne time) and acceleration due to gravity (g). Since g for the Moon is one-sixth that of Earth, a person can jump about six times further.

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Answer: The efficiency of the lever is 80%.

Explanation:

An efficiency is the measure of how much wok or energy is conserved in a given process. It is defined as the ratio of output work and input work. If the energy is totally conserved in a process, the the percentage efficiency will be 100%.

Mathematically,

[tex]\%\text{ efficiency}=\frac{W_{out}}{W_{in}}\times 100[/tex]

Where,

[tex]W_{out}[/tex] = Work done by the lever = 20 J

[tex]W_{in}[/tex] = Work put in the lever = 25 J

Putting values in above equation, we get:

[tex]\%\text{ efficiency}=\frac{20}{25}\times 100\\\\\%\text{ efficiency}=80\%[/tex]

Hence, the efficiency of the lever is 80%.

If the mass of the crate is doubled but the initial velocity is not changed, the crate slides distance d before stopping.

[tex]\texttt{ }[/tex]

Let's recall the formula of Kinetic Energy as follows:

[tex]\large {\boxed {E_k = \frac{1}{2}mv^2 }[/tex]

Ek = Kinetic Energy ( Newton )

m = Object's Mass ( kg )

v = Speed of Object ( m/s )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial height = h₁ = 26 m

final height = h₂ = 16 m

initial speed = v₁ = 0 m/s

coefficient of friction = μ

gravitational acceleration = g

distance = d

Asked:

final speed = v₂ = ?

Solution:

We will use Work and Energy formula to solve this problem as follows:

[tex]W = \Delta Ek[/tex]

[tex]-f d = Ek_{final} - Ek_{initial}[/tex]

[tex]-\mu N d = \frac{1}{2}m (v_f)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2}m (v_f)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2}m (0)^2 - \frac{1}{2} m (v_i)^2[/tex]

[tex]-\mu mg d = \frac{1}{2} m (v_i)^2[/tex]

[tex]\mu g d = \frac{1}{2} (v_i)^2[/tex]

[tex]d = \frac{1}{2} (v_i)^2 \div ( \mu g )[/tex]

[tex]\boxed {d = \frac { (v_i)^2 } { 2 \mu g } }[/tex]

[tex]\texttt{ }[/tex]

From information above we can conclude that the distance is independent to the mass of the crate.

If the mass of the crate is doubled but the initial velocity is not changed, the crate slides the same distance d before stopping.

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

If the mass of the crate is doubled while maintaining the same initial velocity, the stopping distance will be halved. This is due to the doubled frictional force from the increased mass. Therefore, the crate will slide a distance of d/2 before coming to a stop.

Thus, the crate will slide half the distance before stopping if the mass is doubled but the initial velocity is unchanged.

Answer:

Newton's third law of motion

Explanation:

As per Newton's third law of motion, every action has its equal and opposite reaction.

When a jet aircraft takes off it exerts a force and gains upward acceleration, the same force is applied on your body as it is moving along the jet hence this force tries to push you back into the seat.

For instance, while rowing a boat you try to apply force on water with paddles in backward direction, the same amount of force is reverted by water thus moving the boat in forward direction.

Hence Newton's third law of motion explains the phenomena.

Answer:

Newton's third law of motion

Explanation:

As per Newton's third law of motion, When two bodies interact they apply force to one another that are equal in magnitude and opposite  in direction.

During the take off a jet aircraft it exerts a force and gain upward acceleration, the same amount of force is applied on our body because we are in contact with jet due to third law we pushed back into the seat..

[tex]F_1=-F_2[/tex]

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Answer:

a)Mechanical to heat energy.

b)potential to kinetic energy

c)kinetic to potential energy

d)kinetic to heat energy.

Answer: Option (a) is the correct answer.

Explanation:

When only one element gets displaced upon chemical reaction between a compound and an element then it is known as a single replacement reaction.

For example, [tex]Fe_{2}O_{3}(s) + 2Al(s) \rightarrow Al_{2}O_{3}(s) + 2Fe(l)[/tex]

On the other hand, when two compounds chemically react together and their ions get replaced by each other then it is known as a double replacement reaction.

For example,  [tex]AgNO_{3}(aq) + NaCl(aq) \rightarrow AgCl(s) + NaNO_{3}(aq)[/tex]

Thus, we can conclude that the reaction which has two reactants with ions that seem to switch places clue can be used to identify a chemical reaction as a replacement reaction.

In order to maintain equilibrium and have a downslope acceleration of 0.64 m/s² with a 2.3 kg mass, the right-hand mass should be approximately 0.15 kg.

In physics, the question is referring to the concept of equilibrium through the force of gravity. When a downtrend pushes left-hand mass with a certain acceleration, it implies that any other force (potentially from another mass on the opposite direction) counteracts. This counteraction or the right-hand mass is what we are now to calculate.

Assuming there is no friction, the force acting on the left-hand mass (F1) can be calculated using Newton's second law of motion, F = ma where m is the mass and a is the acceleration, yielding F1 = 2.3 kg * 0.64 m/s² = 1.472 N

For equilibrium to be maintained, the force due to the right-hand mass (F2) must equal F1. Therefore, if g is the acceleration due to gravity (9.81 m/s²), the right-hand mass (m2) can be found using the formula m2 = F1 / g, simplifying to m2 = 1.472 N / 9.81 m/s² = 0.15 kg.

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Final answer:

The magnitude of the average acceleration the football player experiences is 38.02 m/s², and the direction of the acceleration is backward, towards the line of scrimmage.

Explanation:

To calculate the magnitude and direction of the average acceleration experienced by the football player, we use the following kinematic equation:

a = (v_f - v_i) / t

Where:

Given:

Now we can plug these values into our equation to find a:

a = (0 - 7.68 m/s) / 0.202 s

a = -7.68 m/s / 0.202 s

a = -38.02 m/s2

The negative sign indicates that the acceleration is in the opposite direction of the player's initial motion. Since the player was moving forward and came to a stop, the acceleration is directed backward, towards the line of scrimmage.

Answer:

Sulfuric acid.

Explanation:

A battery is a device which contains one or more electrical chemical cells which are connected in a electrical circuit to power the objects like flashlight, speaker, etc.

When a battery is supply electric power then its positive terminal classified as cathode and negative as anode.

And as we know that the electrolyte in a typical wet storage battery or cell contains 67% water and 33% of sulfuric acid.

Actually we could create a triangle in this case. The hypotenuse is the radius of Earth plus the height above the earth, while the two sides are the radius of Earth and the scope of vision.

That is:

(6,400,000 m + 100 m)^2 = (6,400,000 m)^2 + b^2

b^2 = 1,280,010,000

b = 35,777.23 m

You can see 35,777.23 m far.

The puma, cougar, or mountain lion leaves the ground to make a leap with a speed of approximately 8.32 m/s.

To find the speed at which the animal leaves the ground, we can use the kinematic equation for projectile motion:

[tex]\[v = \sqrt{2gh},\][/tex]

where [tex]\(v\)[/tex] is the speed, [tex]\(g\)[/tex] is the acceleration due to gravity (approximately [tex]\(9.81 \, \text{m/s}^2\))[/tex], and [tex]\(h\)[/tex] is the vertical height.

Given that the height  [tex]\(h\)[/tex] is 13.7 ft, we first convert it to meters:

[tex]\[h = 13.7 \, \text{ft} \times 0.3048 \, \text{m/ft} = 4.1756 \, \text{m}.\][/tex]

Substituting [tex]\(h\)[/tex] into the equation, we have:

[tex]\[v = \sqrt{2 \times 9.81 \, \text{m/s}^2 \times 4.1756 \, \text{m}} \approx 8.32 \, \text{m/s}.\][/tex]

We must always take note that mass is an inherent property of an object. It never change unless there is change in size of the object. While weight is the product of mass and gravity, so it changes depending on the gravitational pull.

If the gravitational pull decreases as he moves from the poles to the equator, therefore its weight will decrease.

Answer:

D.Its weight will decrease

Final answer:

Bernoulli's equation is a form of the conservation of energy principle in fluid flow. It states that the sum of pressure, kinetic energy, and potential energy is constant at any two points in an incompressible, frictionless fluid.

Explanation:

Bernoulli's equation is a form of the conservation of energy principle in fluid flow. It states that the sum of pressure, kinetic energy, and potential energy is constant at any two points in an incompressible, frictionless fluid.

For example, if a fluid flows through a pipe with varying diameters, according to Bernoulli's equation, the pressure decreases as the fluid velocity increases.

This concept is important in the study of fluid mechanics and is used to analyze and predict the behavior of fluids in various applications.

The pitch of a note is determined by its frequency, with higher frequencies leading to higher pitches. The quality, or timbre, of a note depends on the shape of the waveform, influenced by various frequencies and phases of sound waves. These aspects combine to give each note its unique character.

The quality and pitch of a note depend on different aspects of sound waves. The pitch of a note is primarily determined by its fundamental frequency, which is measured in hertz (Hz). A higher frequency results in a higher pitch, making a note sound “sharper” or higher on the musical scale. For example, the piano note middle C has a frequency of 261.63 Hz. Musical intervals, like the octave, are based on the doubling of frequencies.

On the other hand, the quality or timbre of a note depends on the waveform's shape, which is influenced by the frequencies and phases of other sound waves produced alongside the fundamental frequency. This complexity allows us to distinguish between different instruments playing the same note due to the variety in waveforms. The timbre is what makes the same note played on a trumpet distinctly different from the same note played on a clarinet.

In summary, while pitch is a direct correlation to the frequency of sound, quality or timbre involves the intricate interplay of multiple frequencies and their waveform shapes, contributing to the unique character of each musical note.