A weightlifter holds a 1,700 N barbell 1 meter above the ground. One end of a 2-meter-long chain hangs from the center of the barbell. The chain has a total weight of 500 N. How much work (in J) is required to lift the barbell to a height of 2 m

Answer:

Width of the original rectangle is [tex]24 \\[/tex] meters

Step-by-step explanation:

Perimeter of reduced rectangle [tex]= 30\\[/tex] meters

Reduced length [tex]= 9 \\[/tex] meters

Reduced perimeter is equal to

[tex]2 ( Reduced width) + 2 (reduced length) \\2 (w) + 2 (l) = 30\\2 (w) + 2 (9) = 30\\w = 6\\[/tex]

The factor of reduction of perimeter of original rectangle

[tex]= \frac{30}{120} \\= \frac{1}{4} \\[/tex]

Width of reduced rectangle will be equal to [tex]\frac{1}{4} \\[/tex] the width of original rectangle

[tex]w = \frac{1}{4} * W\\6 = \frac{1}{4} * W\\\\W = 24 \\[/tex]

The gravitational force between two objects can be calculated using Newton's universal law of gravitation. This force is dependent on the masses of the objects and the distance between them, allowing us to calculate its value even for celestial bodies.

The gravitational force between two objects can be determined using Newton's universal law of gravitation. This law states that the force between two objects is proportional to the product of their masses and inversely proportional to the square of the distance between them. It's represented by the equation: F = G×(M₁×M₂)/r², where F is the gravitational force, G is the gravitational constant, M₁ and M₂ are the masses of the two objects, and r is the distance between their centres.

For instance, if we look at the gravitational force exerted on us by the Earth, our weight is actually this force. It can be calculated using Earth's mass (approximately 6 x 10²⁴ kg) and its radius (approximately 6,371 kilometres).

With masses in kilograms and distance in meters, the gravitational attraction between two 1 kg masses separated by 1 meter would be an extraordinarily small value, approximately 6.673 x 10⁻¹¹ N. Despite its small magnitude, this force affects our everyday life and the motion of celestial bodies like moons, planets, stars, and galaxies.

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The number of more pages that he wrote on Sunday will be 14 ³⁷/₄₀ pages.

Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.

The acronym PEMDAS stands for Parenthesis, Exponent, Multiplication, Division, Addition, and Subtraction. This approach is used to answer the problem correctly and completely.

Sebastian wrote 24 ¹/₅ of his novel on Saturday and 39 ¹/₈ pages of his novel on Sunday.

Convert the mixed fraction number into a fraction number. Then we have

24 ¹/₅ = 24 + 1/5 = 121 / 5

39 ¹/₈ = 39 + 1/8 = 313 / 8

The number of more pages that he wrote on Sunday will be given as,

⇒ 313/8 - 121/5

⇒ (1,565 - 968) / 40

⇒ 597 / 40

⇒ 14 ³⁷/₄₀

The number of more pages that he wrote on Sunday will be 14 ³⁷/₄₀ pages.

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1 3/5 hours = 8/5 hours

8/5 / 4 days =

8/5 x 1/4 = 8/20 = 2/5

2/5 hours per day

Answer:

The tennis ball is 8000 times larger than the neuron.

Step-by-step explanation:

Average neuron is about [tex]5\times10^{-6}[/tex] meter in diameter .

A standard table tennis ball is 0.04 meter in diameter .

To tell about how many times as great is the diameter of a ball than a neuron, we will divide the tennis ball diameter by the neuron diameter.

[tex]\frac{0.04}{5\times10^{-6}}[/tex]

We will move the 10^-6 in the numerator to positive 10^6

[tex]\frac{0.04\times10^{6}}{5}[/tex]

= [tex]\frac{0.04\times1000000}{5}[/tex]

= [tex]\frac{40000}{5}[/tex]

= 8000 times.

So, the tennis ball is 8000 times larger than the neuron.

Answer:

Total equipment required = 33 + 22 + 11 + 44

Step-by-step explanation:

Coach Smith is buying equipment for a soccer team of 11 players.

Each player need three uniforms so total uniforms required = 11×3 = 33

Each player require two shin guards so total guards required = 11×2 = 22

Each player require one ball, so total balls required = 11

Each player require two pairs of cleats then total cleats required = 11×2 = 22 pairs or 44 cleats

Now total equipment required = 33 + 22 + 11 + 44

The integer that when subtracted from its square results in a value that is neither negative nor positive is zero; however, this contradicts the condition of being a non-zero integer, making it an impossible scenario.

The question asks about an integer that when subtracted from its square gives a result that is neither negative nor positive. This occurs only with the integer zero. Let's represent the integer as n. According to the problem, n² - n = 0. If we factor n out of the equation, we get n(n - 1) = 0. There are two solutions to this equation: n = 0 or n - 1 = 0, which leads to n = 1. However, when n = 1 and we substitute it back into the original equation, we get 1² - 1 = 0, which is zero but not a non-zero integer as specified by the question. Hence, the only number that fits the condition of being a non-zero integer and yielding a result of zero when subtracted from its square is zero itself, which is contradictory because zero is not a non-zero integer. Therefore, it is impossible to find a non-zero integer that, when subtracted from its square, equals zero.

Answer:

6

Step-by-step explanation:

-1 + 7 = 6

The required value of y is 6 which is determined by the substituting the value of x=1 in t with the rule y = -x + 7.

A linear equation is one in which the greatest power of the variable is always one.

The following linear rule is provided to us:

⇒ y = -x + 7

We are asked to calculate the value of y if the point (1, y) is located on the graph of (i).

We are aware that If the point (1, y) is on the graph of equation I then the equation must be satisfied.

⇒ y = -x + 7

Substitute the value of x = 1 in the above equation,

⇒ y = -1 + 7

Apply the subtraction operation to get,

⇒ y = 6

As a result of the equation, we obtain y is 6.

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The simplified expression is 41 + 10.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

-4q - (-8q) + 10

-4q + 8q + 10

Combine like terms.

4q + 10

Thus,

The simplified expression is 41 + 10.

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the answer is 1.3 1.34 1 and1.3

The number is 54 nearest ten is 50 and the nearest hundred is 100.

When a number is rounded off, its value is maintained but is brought closer to the next number, simplifying the number. For entire numbers as well as decimals at different places of hundreds, tens, tenths, etc., it is done.

A number can be rounded off to its lower value if the number after the decimal is between 0 and 4. The number will be rounded off to its higher value if the number after it is between 5 and 9.

Let the number be 54 now the round-off is 50 nearest ten will be 100, and the number is double.

Therefore, the number is 54 nearest ten is 50 and the nearest hundred is 100.

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The second computer can process [tex]10^{14}[/tex] instruction per second.

The processing speed of a computer is [tex]10^{11}[/tex] and second computer can process [tex]10^{3}[/tex] times faster.

What is the n time of a number?

When we multiply n with that number we get the n times of the number.

Consider the processing speed of the second computer = x

Therefore, according to the question,

[tex]x = 10^{3} *10^{11} \\ =10^{14}[/tex]

Thus, the second computer can process [tex]10^{14}[/tex]  instruction per second.

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