A store is having a sale, each customer receives either a 15% discount on purchases under 100% or a 20% discount on purchases of $100 or more. Kelly is purchasing some clothes for $96.60 before the discount. She decides to buy the fewest packs of gum that will increase her purchase to over $100. The price of each pack of gum is $0.79. After the discount, how much less will kelly pay by purchasing the clothes and the gum instead of purchasing only the clothes? (Assume there is no sales tax to consider.) please help this is almost due please help I mark brainliest!!!​

A. $1.05

B. $1.67

C. $3.69

D. $3.87

Answer:

439cor.to 3 Sig. fig.

Step-by-step explanation:

(5+12)×6×14-(5÷2)²π×14

Answer:

two distinct real roots

Step-by-step explanation:

The coefficients of the equation are ...

a = 1

b = -5

c = -3

So, the discriminant, b^2-4ac, has the value ...

(-5)^2 -4(1)(-3) = 25 +12 = 37

This number is positive, so the square root of it is non-zero and real. This means the two roots are real and distinct.

Answer:

(b, c)

Step-by-step explanation:

The mid-point of two vertices or point is calculated by adding the respective coordinates of those points and then dividing by two. The x-coordinates will be added and then divided by 2 and then y-coordinates will be added and divided by 2.

So for the given question,

P(0,0)

Q(2a,0)

And

R(2b, 2c)

Mid-point of PR =( (0+2b)/2, (0+2c)/2)

=(2b/2, 2c/2)

=(b,c)

So the mid-point of PR is (b, c)

Last option is the correct answer..

Check the picture below.

Answer:

It's a Right Triangle

Answer:

where is the questions

Step-by-step explanation:

[tex]\bf \stackrel{\textit{using the exponential model}}{N=2^D}~\hspace{7em}\begin{array}{ccll} \stackrel{days}{D}&\stackrel{\$}{N}\\ \cline{1-2} 1&2^1\implies 2\\ 2&2^2\implies 4 \end{array}[/tex]

so, using that exponential model, the 1st output value works, but the second value of 2² does not give us 8 as output.

let's check the linear model using slopes to get the equation.

[tex]\bf (\stackrel{x_1}{1}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{2}~,~\stackrel{y_2}{8})\qquad \impliedby \begin{array}{|cc|ll} \cline{1-2} D&N\\ \cline{1-2} 1&2\\ 2&8\\ \cline{1-2} \end{array}[/tex]

[tex]\bf slope = m\implies \cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{8-2}{2-1}\implies \cfrac{6}{1}\implies 6 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-2=6(x-1) \\\\\\ y-2=6x-6\implies y=6x-4[/tex]

now, using that model, x = 6, then y = 6(6) - 4, or y = 32.

Answer:

D. [tex](x-2y)(x-y)(x+y)[/tex]

Step-by-step explanation:

In the polynomial [tex]x^3-2x^2y-xy^2+2y^3[/tex] group first two terms and second two terms:

[tex](x^3-2x^2y)+(-xy^2+2y^3)[/tex]

First two terms have common factor [tex]x^2[/tex] and last two terms have common factor [tex]y^2,[/tex] hence

[tex](x^3-2x^2y)+(-xy^2+2y^3)=x^2(x-2y)+y^2(-x+2y)[/tex]

In brackets you can see similar expressions that differ by sign, so

[tex]x^2(x-2y)+y^2(-x+2y)=x^2(x-2y)-y^2(x-2y)=(x-2y)(x^2-y^2)[/tex]

Now use formula

[tex]a^2-b^2=(a-b)(a+b)[/tex]

You get

[tex](x-2y)(x^2-y^2)=(x-2y)(x-y)(x+y)[/tex]

Answer: circumference: 22π  area: 121π

Step-by-step explanation:

area of a circle is [tex]\pi r^2[/tex]

circumference is [tex]2\pi r[/tex]

Answer:

Part A)  Is a directly proportional

Part B) The constant of proportionality is [tex]k=0.25[/tex]

Part C) The equation is [tex]y=0.25x[/tex]

Part D) [tex]62.5[/tex]  acres of soybeans

Step-by-step explanation:

Part A) Are the number of acres of corn and the number of acres of soybeans directly proportional or inversely proportional?

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form [tex]y/x=k[/tex]

Let

x-----> the number of acres of corn

y---->  the number of acres of soybeans

so

[tex]y/x=k[/tex]  

if the number of acres of corn increases then the number of acres of soybeans increases

if the number of acres of corn decreases then the number of acres of soybeans decreases

therefore

The relationship is a directly proportional

Part B) What is the constant of proportionality?

we have that

For x=200, y=50

substitute

[tex]y/x=k[/tex]

[tex]k=50/200[/tex]

[tex]k=0.25[/tex]

Part C) Let x equal the number of acres of corn and y equal the number of acres of soybeans. Write an equation to show this relationship.

The linear equation that represent the direct variation is equal to

[tex]y/x=k[/tex]

we have

[tex]k=0.25[/tex]

substitute

[tex]y/x=0.25[/tex]

[tex]y=0.25x[/tex]

Part D) How many acres of soybeans can the farmer plant this year if he plants 250 acres of corn?

For x=250

Find the value of y

substitute in the linear equation the value of x and solve for y

[tex]y=0.25(250)=62.5[/tex] -----> acres of soybeans

I'll do both.

[tex]

5x-97>-34\Rightarrow x>\frac{-34+97}{5}=\frac{63}{5}=\boxed{12.6} \\

\boxed{x\in(12.6, \infty)} \\ \\

2x+31<29\Longrightarrow x<29-31=\boxed{-2} \\

\boxed{x\in(-\infty, -2)}

[/tex]

[tex]2\log4 + \log3 -\log2 + \log5= \\ \\ = \log 2^4+ \log3 -\log2 + \log5 = \\ \\ = \log 16+ \log3 -\log2 + \log5 = \\ \\ = \log\Big(16\cdot 3:2\cdot 5\Big) = \log\Big(\dfrac{16\cdot 3\cdot 5}{2}\Big) = \log(8\cdot 3\cdot 5) = \\ \\ =\log120[/tex]

a term will be the expression between the + or - signs

[tex]\bf \stackrel{\stackrel{one}{\downarrow }}{x^2}+\stackrel{\stackrel{two}{\downarrow }}{xy}-\stackrel{\stackrel{three}{\downarrow }}{y^2}+\stackrel{\stackrel{four}{\downarrow }}{5}[/tex]

Answer:

[tex]5,890.5\ ft^{2}[/tex]

Step-by-step explanation:

step 1

Find the area that cover each individual head of a sprinkler system

The area of the circle is equal to

[tex]A=\pi r^{2}[/tex]

we have

[tex]r=25\ ft[/tex]

assume

[tex]\pi=3.1416[/tex]

substitute

[tex]A=(3.1416)(25)^{2}[/tex]

[tex]A=1,963.5\ ft^{2}[/tex]

step 2

Find the area that covers 3 sprinkler heads

[tex](3)*1,963.5=5,890.5\ ft^{2}[/tex]

Answer:

5890.5 ft²

Step-by-step explanation:

did it on edg

Step-by-step explanation:

3

√

2

2

⋅

2

Pull terms out from under the radical.

3

(

2

√

2

)

Multiply  

2

by  

3

.

6

√

2

The result can be shown in multiple forms.

Exact Form:

6

√

2

Decimal Form:

8.48528137

…

For this case we must simplify the following expression:

[tex]3 \sqrt {2} +3 \sqrt {8}[/tex]

We rewrite:

[tex]8 = 2 ^ 3 = 2 ^ 2 * 2\\3 \sqrt {2} +3 \sqrt {2 ^ 2 * 2} =[/tex]

For properties of potecnias and roots we have that:

[tex]\sqrt [n] {a ^ m} = a ^ {\frac {m} {n}}[/tex]

Then, rewriting the expression:

[tex]3 \sqrt {2} + 2 * 3 \sqrt {2} =\\3 \sqrt {2} +6 \sqrt {2} =\\9 \sqrt {2}[/tex]

Answer:

[tex]9 \sqrt {2}[/tex]

Answer:

Option b (1/2,1/3)

Step-by-step explanation:

we have

2x-3y=0 ------> equation A

4x+6y=4 -----> equation B

Solve the system by elimination

Multiply equation A by 2 both sides

2(2x-3y)=2(0)

4x-6y=0 ------> equation C

Adds eqution B and equation C

4x+6y=4

4x-6y=0

-------------

4x+4x=4+0

8x=4

x=1/2

Find the value of y

2x-3y=0

2(1/2)-3y=0

1-3y=0

3y=1

y=1/3

the solution is the point (1/2,1/3)

Answer:

₹[tex]9,600[/tex]

Step-by-step explanation:

we know that

The simple interest formula is equal to

[tex]I=P(rt)[/tex]

where

I is the amount interest Value

P is the Principal amount of money to be invested

r is the rate of interest  

t is Number of Time Periods

in this problem we have

[tex]t=4.5\ years\\ P=?\\ I=1,512\\r=0.035[/tex]

substitute in the formula above

[tex]1,512=P(0.035*4.5)[/tex]

[tex]P=1,512/(0.035*4.5)=9,600[/tex]

1. The area of a circle is calculated using the formula:

[tex]Area = \frac{\pi \: {d}^{2} }{4} [/tex]

The diameter is d=11 feet.

This implies that,

[tex]Area = \frac{\pi \times {11}^{2} }{4} [/tex]

[tex]Area = \frac{121\pi}{4} = 95.03 {ft}^{2} [/tex]

2. For this second question the diameter is d=10.5 feet.

We substitute into the formula to get;

[tex]Area = \frac{\pi \times {10.5}^{2} }{4} [/tex]

[tex]Area = \frac{441\pi }{16} = 86.60 {in}^{2} [/tex]

3. The area of a circle is given by the formula,

[tex]Area =\pi \: {r}^{2} [/tex]

where the radius is r=6.3

This implies that,

[tex]Area =\pi \: {(6.3)}^{2} [/tex]

[tex]Area =36.69\pi = 124.69 {cm}^{2} [/tex]

4. The given circle has a radius of 3.25 yards.

[tex]Area =\pi \times {3.25}^{2} [/tex]

[tex]Area =10.5625 \pi = 33.18 {yd}^{2} [/tex]

Answer:

156.25% increase (56.25% added)

Step-by-step explanation:

Area formula of circle: A = πr²

1. Area when rope = 20 ft:

Plug in: A = π(20)²

Multiply: A = 400π ft²

2. Area when rope = 25 ft:

Plug in: A = π(25)²

Multiply: A = 625 ft²

3. Percent increase:

Increase compared to original: 625/400 = 1.5625 = 156.25%

Answer:

56.25%

Step-by-step explanation:

We are given that a horse is tethered on a 20 ft rope. If the rope is lengthened to 25 ft, we are to percentage by which its grazing area increases.

Grazing area with 20 ft rope = [tex]\pi \times 20^2[/tex] = [tex]400\pi[/tex]

Grazing area with 25 ft rope = [tex]\pi \times 25^2[/tex] = [tex]625\pi[/tex]

Percentage by which area increases = [tex] \frac { 6 2 5 \pi - 400 \pi } { 400 \pi } \times 100 [/tex] = 56.25%

Opposite of adding three is subtracting three or adding -3

Answer:

Mindy uses more white beads

Step-by-step explanation:

For Mindy:

red : white = 4 : 5 = 12 : 15

For Daisy:

red : white = 6 : 7 = 12 : 14

When both use 12 red beads, Mindy uses 15 white beads and Daisy uses 14 white beads.

Mindy uses more white beads when both use 12 red beads.

When they each use 12 red beads, Mindy uses more white beads in her necklaces as per the given ratios. Mindy uses 15 white beads, while Daisy uses 14 white beads.

Mindy uses a ratio of 4 red beads to 5 white beads, and Daisy uses a ratio of 6 red beads to 7 white beads. If they each use 12 red beads, we can equate their ratios. For Mindy, the equivalent ratio would be 12 red beads to 15 white beads because 4 red beads go into 12 red beads three times and three times 5 gives 15 white beads. For Daisy, the equivalent ratio would be 12 red beads to 14 white beads as 6 red beads go into 12 red beads twice and twice 7 gives 14. Therefore, when they each use 12 red beads, Mindy uses more white beads in her necklaces using beads.

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Answer:

96 meatballs are required

Step-by-step explanation:

We know that the formula for he catering business is

[tex]m=4a+2c[/tex]

Where

c= the number of children, m=the number of meat balls, a= the number of adults

So if [tex]c = 8[/tex]  and [tex]a = 20[/tex] then

[tex]m = 4(20) + 2(8)[/tex]

[tex]m = 80 + 16[/tex]

[tex]m = 96[/tex]

Finally  96 meatballs are required for the party

41° because it’s a right angle and if 90=2y+8, y=41

Answer:

41

Step-by-step explanation:

After giving 93 centimeters (which is 0.93 meters) of his 214 meters of rope to his brother, Ravi has 213.07 meters of rope left.

This question involves the concept of subtraction in the measurement unit of meters and centimeters. Initially, Ravi has 214 meters of rope. If he gives 93 centimeters of rope to his brother, keep in mind that 1 meter equals 100 centimeters. So, 93 centimeters is equal to 0.93 meters.

So, to find out how much rope Ravi is left with, you subtract the amount he gave to his brother from the original amount he had: 214 meters - 0.93 meters = 213.07 meters. This is the amount of rope Ravi has left after giving some to his brother.

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Answer:

It will be 2 feet and 9.6 inches wide

Step-by-step explanation:

First you divide 24 inches(2 feet) by 5 inches to find out the rate unit rate of change. Your answer would be 4.8. Then you multiply 4.8 by 7 to figure out how wide it would be, which gives you 33.6 inches(or 2 feet and 9.6 inches)

x=3,y=2

lkajsdfvnkkkkkk

It's a system of linear equations; let me write it out more neatly for you:

[tex]\left \{ {x + 2y = 7} \atop {x - 2y = -1}} \right.[/tex]  

Good. In order to solve a system of equations with two variables, we can find one variable and then use that variable to find the other. This wouldn't be the case if we just had one equation, note.  

Let's work on the top one first. There's multiple ways of solving this one, but here's the most simple way: isolating a single variable. The goal is to get either just x or just y on one side.  

[tex]x + 2y=7\\x = 7-2y[/tex]  

Nice. Now that we have a value of x, we can just plug it into the other equation -- since we know that x is equal to another expression, we can replace x in the other equation with the expression.  

[tex]x - 2y = -1\\(7-2y)-2y = -1\\7 - 2y - 2y = -1\\7 - 4y = -1 \\-4y = -8\\y = 2[/tex]  

Now that we have y, we can do the same thing for x. This time, however, we have the actual value of y, meaning we can just plug that in.  

[tex]x = 7 - 2y\\x = 7 - 2(2)\\x = 7 - 4 \\x = 3[/tex]  

Our solution is  

[tex]\left \{ {{x=3} \atop {y=2}} \right.[/tex]  

We can check this by plugging the values back into the equation.  

[tex]3 + 2(2) = 7\\3 + 4 = 7[/tex]  

and  

[tex]3 - 2(2) = -1\\3 - 4 = -1\\[/tex]  

That's it. There's another (easier) way to handle this specific equation, but this is the simplest way to do it.

Answer:

The error is: The solution shows the Sam's age and the problem asked for Micaela's age.

Solution fixed: [tex]m=17[/tex]

Micaela is 17 years old now.

Step-by-step explanation:

The error is: The solution shows the Sam's age and the problem asked for Micaela's age.

To fix the error, you can set up these equations based on the information given:

[tex]m=s+2[/tex]  

[tex](m+4)+(s+4)=40[/tex]  

Solve for "s" from the first equation:

[tex]s=m-2[/tex]

Substitute this equation into the second equation:

[tex](m+4)+((m-2)+4)=40[/tex]  

Now you need to solve for "m":

[tex]m+4+(m-2+4)=40\\m+4+m+2=40\\m+m=40-4-2\\2m=34\\m=\frac{34}{2}\\\\m=17[/tex]

Micaela is 17 years old now.

Answer:

The error is: The solution shows the Sam's age and the problem asked for Micaela's age.

Solution fixed: m=17

Micaela is 17 years old now.

Step-by-step explanation:

brainliest please?

To solve the equation[tex]\(x^2 = 50\),[/tex] we'll take the square root of both sides. However, when we do this, we need to consider both the positive and negative square roots:

[tex]\[ x = \pm \sqrt{50} \]\[ x = \pm \sqrt{25 \cdot 2} \]\[ x = \pm 5\sqrt{2} \]So, the solutions to the equation \(x^2 = 50\) are \(x = 5\sqrt{2}\) and \(x = -5\sqrt{2}\).[/tex]

To solve the equation [tex]\(x^2 = 50\),[/tex]we'll take the square root of both sides. Remembering that the square root of a number has both positive and negative solutions, we have:

[tex]\[ x = \pm \sqrt{50} \]\[ x = \pm \sqrt{25 \cdot 2} \]\[ x = \pm 5\sqrt{2} \][/tex]

Therefore, the solutions to the equation[tex]\(x^2 = 50\) are \(x = 5\sqrt{2}\) and \(x = -5\sqrt{2}\). This means that when \(x\) is equal to either \(5\sqrt{2}\) or \(-5\sqrt{2}\), \(x^2\) will be equal to 50. These solutions represent the values of \(x\)[/tex]that satisfy the original equation and make it true.

Answer:

∴The distance CA =  = 2√2

Step-by-step explanation:

Find the distance CA:

The distance between two points (x₁,y₁),(x₂,y₂) = d

The coordinates of point C = (-2,2)

The coordinates of point A = (0,0)

The distance CA distance between C and A

∴The distance CA =  = 2√2

The distance[tex]\( C'B' \) is \( \sqrt{10} \)[/tex] units.

after applying the transformation[tex]\( T: (x, y) \rightarrow (x + 2, y + 1) \)[/tex], the distance between points [tex]\( C' \)[/tex] and [tex]\( B' \)[/tex] is [tex]\( \sqrt{10} \)[/tex] units.

The distance [tex]\( C'B' \)[/tex] is [tex]\( \sqrt{10} \)[/tex] units.

To find the distance [tex]\( C'B' \)[/tex], we first need to find the coordinates of points [tex]\( C' \)[/tex] and [tex]\( B' \)[/tex] after applying the transformation [tex]\( T: (x, y) \rightarrow (x + 2, y + 1) \) to points \( C \)[/tex] and [tex]\( B \).[/tex]

Given the coordinates of [tex]\( C \)[/tex] and [tex]\( B \)[/tex] as[tex]\( C(1, 2) \)[/tex] and [tex]\( B(4, 3) \)[/tex] respectively, we apply the transformation to each point:

For point [tex]\( C \):[/tex]

[tex]\[ C'(x', y') = (x + 2, y + 1) = (1 + 2, 2 + 1) = (3, 3) \][/tex]

For point [tex]\( B \):[/tex]

[tex]\[ B'(x', y') = (x + 2, y + 1) = (4 + 2, 3 + 1) = (6, 4) \][/tex]

Now, we use the distance formula to find the distance between [tex]\( C' \)[/tex]and [tex]\( B' \):[/tex]

[tex]\[ C'B' = \sqrt{(x'_2 - x'_1)^2 + (y'_2 - y'_1)^2} \][/tex]

[tex]\[ C'B' = \sqrt{(6 - 3)^2 + (4 - 3)^2} \][/tex]

[tex]\[ C'B' = \sqrt{(3)^2 + (1)^2} \][/tex]

[tex]\[ C'B' = \sqrt{9 + 1} \][/tex]

[tex]\[ C'B' = \sqrt{10} \][/tex]

Thus, the distance [tex]\( C'B' \)[/tex] is[tex]\( \sqrt{10} \)[/tex] units.

In conclusion, after applying the transformation [tex]\( T: (x, y) \rightarrow (x + 2, y + 1) \)[/tex], the distance between points [tex]\( C' \)[/tex] and [tex]\( B' \)[/tex] is [tex]\( \sqrt{10} \)[/tex] units.

Complete question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named. Find the distance C'B’

It would be 49,009 because LA of a cone is height (50) times the radius (120) and that equals about 49,009.

Answer:

48984 m^2

Step-by-step explanation:

The height(h) of cone is given by: 50 m.

Diameter of cone is: 240 m.

Also radius(r) of cone is:240/2=120 m.