Scientific theories are subject to change. true or false
In a unimolecular reaction with three times as much starting material as product at equilibrium, what is the value of keq? is δg o positive or negative? enter keq as a decimal. be sure to answer all parts.
A. The formula for Keq is:
Keq = concentration of product [B] / concentration of reactant [A]
where
A = 3 B
Therefore Keq is:
Keq = [B] / [3 B]
Keq = 0.33
B. The formula for ΔG° is:
ΔG° = - R T ln(Keq)
Since Keq is 0.33 and ln Keq = - 1.1, therefore:
ΔG° = - R T (- 1.1)
ΔG° = +
Therefore ΔG° is positive
The value of Keq for the unimolecular reaction with three times as much starting material as product at equilibrium is 1.73. The value of ∆G° is positive.
Explanation:In a unimolecular reaction with three times as much starting material as product at equilibrium, the value of Keq can be calculated by taking the square root of the concentration ratio of product to reactant. Since there is three times as much starting material as product, the concentration ratio is 3:1. Taking the square root of this ratio gives us a Keq value of 1.73 (rounded to two decimal places).
The value of ΔG° for a reaction can determine whether it is spontaneous or non-spontaneous. If ΔG° is negative, the reaction is spontaneous and can proceed without any outside intervention. If ΔG° is positive, the reaction is non-spontaneous and requires an input of energy to proceed. In this case, since the reaction is at equilibrium and there is three times as much reactant, the value of ΔG° would be positive.
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Describe the difference between a polar and a nonpolar covalent bond. give and explain an example of each type of bond.
When methane is burned with oxygen, the products are carbon dioxide and water. if you produce 9 grams of water and 11 grams of carbon dioxide from 16 grams of oxygen, how many grams of methane were needed for the reaction? 4 31 20 40 none of the above?
The isotope of an atom containing 40 protons and 51 neutrons suddenly has two neutrons added to it.What isotope is created
The correct answer is
Zirconium-93
Since nothing else matches up with 40 protons and 51 neutrons
So your answer is
Zirconium-93
A stream of air (21 mole% o2, the rest n2) flowing at a rate of 10.0 kg/h is mixed with a stream of co2. the co2 enters the mixer at a rate of 20:0 m3/h at 150°c and 1.5 bar. what is the mole percent of co2 in the product stream?
To determine the mole percent of CO2 in a stream of mixed gases, one would first calculate the moles of each gas. The mole percent of CO2 in this case can be calculated as approximately 73%.
Explanation:The mole percent of CO2 in the product stream can be calculated by determining the number of mols of each gas and then using these values to calculate the mole fractions. First, we need to calculate the number of mols for air and CO2 separately.
Initial air is given as 10.0 kg/h, and it is composed of 21 moles% O2 and the rest is N2. Given that the molar mass of O2 is approximately 32 g/mol and N2 is approximately 28 g/mol, this gives us a total of approximately 0.289 moles of air per second. Next, the number of moles of CO2 entering the mixer can be calculated using the ideal gas law formula PV=nRT. Assuming standard pressure for this equation, we get approximately 0.784 moles of CO2 per second.
Finally, the mole percent of CO2 in the product could be calculated as the number of moles of CO2 divided by the total number of moles (number of moles of CO2 + number of moles of air) multiplied by 100. Plugging in the values gives us approximately 73% mole percent of CO2 in the product.
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What is the half-life of iron-59, a radioisotope used medically in the diagnosis of anemia, if a sample with an initial decay rate of 16,800 disintegrations/min decays at a rate of 10,860 disintegrations/min after 28.0 days?
Final answer:
To determine the half-life of iron-59, the decay rate formula is applied, using the provided decay rates and the time period. After calculations, the half-life of iron-59 is found to be approximately 44.5 days.
Explanation:
The half-life of a radioisotope can be determined by understanding how the decay rate changes over time. In this case, we need to find the half-life of iron-59, knowing that its initial decay rate is 16,800 disintegrations per minute, which falls to 10,860 disintegrations after 28.0 days.
To find the half-life of iron-59, we use the decay rate formula:
N(t) = N0 * (1/2)^(t/T), where N(t) is the decay rate at time t, N0 is the initial decay rate, and T is the half-life.
Plugging in the values we have, we get 10,860 = 16,800 * (1/2)^(28/T). To solve for T, we rearrange and take the natural logarithm of both sides to get T as the subject. In so doing, we find that the half-life of iron-59 is approximately 44.5 days.
Explain why it is not possible to draw a skeletal structure for methane.
Since its structure is depicted by dots, which cannot describe it,
Tetrahedral molecules like methane have four comparable C-H bonds.
Methane's chemical makeup:An organic compound's skeletal structure is made up of a group of atoms that are joined together to form the compound's fundamental structure. Chains, branches, and/or rings of bound atoms can make up the skeleton. Heteroatoms are skeletal atoms that are not carbon or hydrogen.
How can we know that methane has four spheres?
We start with what we already know: the geometry of the methane molecule has the carbon at the center and the four C-H bonds pointing towards the corners. In methane, the carbon atoms form four bonds, one to each of the four hydrogen atoms.
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Consider an ideal gas with a volume of V1. To what volume would you need to compress the gas to double its pressure? Express your answer in terms of V1.
Answer: The final volume should be [tex]\frac{V_1}{2}[/tex]
Explanation:
To calculate the new pressure, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.
The equation given by this law is:
[tex]P_1V_1=P_2V_2[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas= P atm
[tex]V_1[/tex] = initial volume of gas = [tex]V_1[/tex]
[tex]P_2[/tex] = final pressure of gas= 2P
[tex]V_2[/tex] = final volume of gas = ?
Putting values in above equation, we get:
[tex]P\times V_1=2P\times V_2[/tex]
[tex]V_2=\frac{V_1}{2}[/tex]
Thus the final volume should be [tex]\frac{V_1}{2}[/tex]
Which of these molecules has the same number of shared electron pairs as unshared electron pairs? (a) hcl, (b) h2s, (c) pf3, (d) ccl2f2 (e) br2?
Let us check each molecule
a) HCl : the number of shared electron pairs is "one"
the number of unshared electron pairs is six [on chlorine]
b) H₂S : the number of shared electron pairs is "two" as there are two bonds of sulphur with two hydrogen atoms.
The number of valence electrons on sulphur are six, out of these two are involved in bonding and rest four are in the form of two unshared (lone pair) pair of electrons
So in H₂S it has the same number of shared electron pairs as unshared electron pairs
c) PF₃ : the shared pair of electrons are "three"
the number of unshared electron pairs is one on phosphorous.
d) CCl₂F₂ : there are total four shared pair of electrons on carbon and zero unshared electron pairs
e) Br₂ : only one shared electron pair and three unshared electron pairs
The molecule that has the same number of shared electron pairs as unshared electron pairs is H2S.
In a molecule, chemical bonds are formed when atoms share electrons. However, some atoms have unshared electron pairs on their valence shells. These unshared electron pairs are called lone pairs and are localized on one of the atoms in the bond.
In the molecule H2S. There are two lone pairs or unshared pairs on sulfur and there are two shared pairs of electrons in the molecule. Hence the molecule that has the same number of shared electron pairs as unshared electron pairs is H2S.
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Write the ions present in solution of AgNO3. Express your answers as chemical formulas separated by a comma. Identify all of the phases in your answers.
Answer: The ions present in a given solution of silver nitrate are [tex]Ag^+,NO_3^-[/tex]
Explanation:
Silver nitrate is a strong electrolyte because it displaces into its ions in aqueous solution.
The chemical reaction for the ionization of silver nitrate solution follows the equation:
[tex]AgNO_3(aq.)\rightarrow Ag^+(aq.)+NO_3^-(aq.)[/tex]
By Stoichiometry of the reaction:
1 mole of silver nitrate solution ionizes into 1 mole of silver ions and 1 mole of nitrate ions.
Hence, the ions present in a given solution of silver nitrate are [tex]Ag^+,NO_3^-[/tex]
The chemical formula is[tex]\boxed{{\text{A}}{{\text{g}}^ + }{\text{,N}}{{\text{O}}_{\text{3}}}^ - }[/tex].
The phases of ions are[tex]\boxed{{\text{aqeuous phase}}}[/tex].
Further explanation:
Ionic compound:
Ionic compounds are those compounds formed from the ions of the species. Ions are the species that are formed due to the loss or gain of electrons. Cation forms by the loss of electrons and anion forms by the gain of electrons in a neutral atom.
Some of the properties of ionic compounds are as follows:
1. These are hard solids.
2. They have high melting and boiling points.
3. They are considered as good conductors of heat and electricity.
Ionic reaction:
Ionic reaction is a type of chemical reaction in which molecules in aqueous solution dissociate to form ions. In ionic reaction, the net charge is same on both sides.
[tex]{\text{AgN}}{{\text{O}}_{\text{3}}}[/tex]is a strong electrolyte and dissociates into ions in the aqueous solution. The reaction for dissociation of [tex]{\text{AgN}}{{\text{O}}_{\text{3}}}[/tex] solution is:
[tex]{\text{AgN}}{{\text{O}}_{\text{3}}}\left({aq}\right)\to{\text{A}}{{\text{g}}^+}\left({aq}\right)+{\text{N}}{{\text{O}}_{\text{3}}}^-\left({aq}\right)[/tex]
In this reaction, 1 mole of [tex]{\text{AgN}}{{\text{O}}_{\text{3}}}[/tex] dissociates to form 1 mole of [tex]{\text{A}}{{\text{g}}^+}[/tex] and 1 mole of [tex]{\text{N}}{{\text{O}}_{\text{3}}}^-[/tex].
Therefore, ions present in the solution of silver nitrate are [tex]{\text{A}}{{\text{g}}^+}[/tex], [tex]{\text{N}}{{\text{O}}_{\text{3}}}^-[/tex]. As ions are formed in solution only, so the phase of both the ions is aqueous phase.
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Grade: High School
Subject: Chemistry
Chapter: Chemical compound
Keywords: Ionic compound, aqueous solution, good conductor, high enthalpy, ions, dissociates, AgNO3, Ag+ and NO3-.
Which of the following processes would you predict to have a positive value for º ? 2SO2(g) + O2(g) → 2 SO3(g) P4O10(s) + 6H2O(l) → 4H3PO4(s) 2POCl3(g) → 2PCl3(g) + O2(g) 2H2(g) + O2(g) → 2H2O(l)
Answer:
[tex]2POCl_3(g) --> 2PCl_3(g) + O_2(g)[/tex]
Explanation:
Hello,
For the listed chemical reactions, one can predict the one which has a positive ΔS° is:
[tex]2POCl_3(g) --> 2PCl_3(g) + O_2(g)[/tex]
This is foreseen owing to the greater number of products (2) by contrast with the number of reagents (1). Moreover, for such reaction, there is a greater amount of moles at the products than at the reagents.
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Why does naphthalene have a higher melting point than biphenyl?
Naphthalene has a higher melting point than biphenyl because naphthalene is a polar compound while biphenyl is a non-polar compound. Studies show that polar compounds have higher melting and boiling points than nonpolar compounds. It is because polar compounds have strong intermolecular forces.
Final answer:
Naphthalene has a higher melting point than biphenyl due to its compact structure with fused benzene rings, resulting in greater π-electron delocalization and stronger intermolecular forces. The fulfillment of Hückel's rule with its 10 π electrons also contributes to naphthalene's stability and higher melting point.
Explanation:
Naphthalene has a higher melting point than biphenyl because of its structural differences and the stronger intermolecular forces that result from these differences. Naphthalene is composed of two fused benzene rings, which means it has a more compact structure and a greater degree of π-electron delocalization than biphenyl, which consists of two benzene rings connected by a single bond.
The π-electron delocalization in naphthalene contributes to a greater stability and a higher degree of symmetry than biphenyl, which in turn leads to stronger intermolecular forces, namely London dispersion forces. Furthermore, naphthalene fulfills Hückel's rule with its 10 π electrons, which provides additional stability due to the filled bonding molecular orbitals. These factors result in a higher energy requirement to overcome the intermolecular forces in naphthalene, thereby giving it a higher melting point compared to biphenyl.
How many hydrogen atoms are in 8.90 mol of ammonium sulfide?
The number of hydrogen atoms in 8.90 mol of ammonium sulfide is 4.28×10²⁵ atoms.
What is Avogadro's constant?This is referred to as a proportionality factor which tells us about the number of constituent particles in a sample. The constant is 6.02ₓ 10²³.
Ammonium sulfide which is denoted as (NH4)₂S has 2 nitrogen, 8 hydrogen and 2 sulfur atoms present.
We were told that the amount of ammonium sulfide is 8.90mol.
Number of hydrogen atoms = 8/1 × 8.9 mol= 71.2 moles of H₂.
The number of Hydrogen atoms in 8.90 mol of ammonium sulfide is 71.2 moles ˣ 6.02ˣ 10²³ = 4.28 ˣ10²⁵ atoms.
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Suppose Harry begins with the hydrate KAl(SO4)2·12H2O. After dehydration he finds that he is left with 3.0 g of the an-hydrate KAl(SO4)2. How many grams did he start with?
Harry started with [tex]\boxed{{\text{5}}{\text{.5 grams}}}[/tex] of [tex]{\text{KAl}}{\left( {{\text{S}}{{\text{O}}_{\text{4}}}} \right)_{\text{2}}} \cdot{\text{12}}{{\text{H}}_{\text{2}}}{\text{O}}[/tex] hydrated salt.
Further explanation:
Mole is the measure of the amount of substance. Mole is the relation between the mass of the substance and molar mass of a substance. It is defined as the mass of a substance in grams divided by its molar mass (g/mol).
The expression to calculate the number of moles is as follows:
[tex]{\text{Number of moles}}\;=\;\dfrac{{{\text{Given mass}}\left({\text{g}}\right)}}{{{\text{molar mass}}\left({{\text{g/mol}}}\right)}}[/tex]
Therefore, the formula to calculate the mass of the given compound is,
[tex]{\text{Mass}}\left({\text{g}} \right)=\left({{\text{Number of moles}}}\right)\left( {{\text{molar mass}}\left({{\text{g/mol}}}\right)}\right)[/tex]
The molar mass of [tex]{\text{KAl}}{\left( {{\text{S}}{{\text{O}}_{\text{4}}}} \right)_{\text{2}}} \cdot{\text{12}}{{\text{H}}_{\text{2}}}{\text{O}}[/tex] is 474.3884g/mol.
The molar mass of [tex]{\text{KAl}}{\left({{\text{S}}{{\text{O}}_{\text{4}}}}\right)_{\text{2}}}[/tex] is 258.2050 g/mol.
Therefore, mass of 12[tex]{{\text{H}}_2}{\text{O}}[/tex] molecules is,
[tex]\begin{aligned}{\text{Mass}}\left( {\text{g}} \right)&={\text{Moles}}\times{\text{molar mass of }{{\text{H}}_2}{\text{O}}\\&=12{\text{ mol }}\times 18{\text{ g/mol }}\\&=216{\text{ g}}\\\end{aligned}[/tex]
Since initially in [tex]{\text{KAl}}{\left( {{\text{S}}{{\text{O}}_{\text{4}}}} \right)_{\text{2}}} \cdot{\text{12}}{{\text{H}}_{\text{2}}}{\text{O}}[/tex] , 1 mole of [tex]{\text{KAl}}{\left({{\text{S}}{{\text{O}}_{\text{4}}}}\right)_{\text{2}}}[/tex] contained 12 moles of [tex]{{\text{H}}_2}{\text{O}}[/tex] . Thus 258.2050 g of [tex]{\text{KAl}}{\left({{\text{S}}{{\text{O}}_{\text{4}}}}\right)_{\text{2}}}[/tex] should contains 216 g of [tex]{{\text{H}}_2}{\text{O}}[/tex] before evaporation.
Therefore, the mass of [tex]{{\text{H}}_2}{\text{O}}[/tex] contained by 1 g of [tex]{\text{KAl}}{\left({{\text{S}}{{\text{O}}_{\text{4}}}}\right)_{\text{2}}}[/tex] is calculated as,
[tex]{\text{Mass}}\left({\text{g}}\right){\text{ of }}{{\text{H}}_2}{\text{O in 1 g of KAl}}{\left( {{\text{S}}{{\text{O}}_{\text{4}}}} \right)_{\text{2}}}{\text{ }}=\dfrac{{{\text{216 g of }}{{\text{H}}_2}{\text{O}}}}{{258.2050{\text{ g of KAl}}{{\left({{\text{S}}{{\text{O}}_{\text{4}}}} \right)}_{\text{2}}}}}[/tex]
Therefore, the mass of [tex]{{\text{H}}_2}{\text{O}}[/tex] contained by 3.0 g of [tex]{\text{KAl}}{\left({{\text{S}}{{\text{O}}_{\text{4}}}}\right)_{\text{2}}}[/tex] is calculated as follows:
[tex]\begin{aligned}{\text{Mass}}\left({\text{g}} \right){\text{ of }}{{\text{H}}_2}{\text{O in 3 g of KAl}}{\left({{\text{S}}{{\text{O}}_{\text{4}}}}\right)_{\text{2}}}&=\dfrac{{{\text{216 g of }}{{\text{H}}_2}{\text{O}}}}{{258.2050{\text{ g of KAl}}{{\left( {{\text{S}}{{\text{O}}_{\text{4}}}}\right)}_{\text{2}}}}}\times 3{\text{ g of KAl}}{\left({{\text{S}}{{\text{O}}_{\text{4}}}}\right)_{\text{2}}}\\&=2.50{\text{ g }}\\\end{aligned}[/tex]
This 2.5 g is the mass of water that is evaporated from hydrated salt.
The total mass of hydrated of [tex]{\text{KAl}}{\left( {{\text{S}}{{\text{O}}_{\text{4}}}} \right)_{\text{2}}} \cdot{\text{12}}{{\text{H}}_{\text{2}}}{\text{O}}[/tex] taken initially by harry is the sum of the mass of water that is evaporated and mass of dehydrated salt that is left after evaporation process.
[tex]\begin{aligned}{\text{Total mass of hydrated salt}}&={{\text{m}}_{{\text{KAl}}{{\left( {{\text{S}}{{\text{O}}_{\text{4}}}}\right)}_{\text{2}}}}}+{{\text{m}}_{{{\text{H}}_2}{\text{O evaporated}}}}\\&=3.0{\text{ g}}+{\text{2}}{\text{.5 g}}\\&=5.5{\text{ g }}\\\end{aligned}[/tex]
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Grade: Senior school
Subject: Chemistry
Chapter: Mole concept
Keywords: harry, hydrate salt, KAl(SO4)2•12H2O, dehydration process, hydration process, anhydrated salt, KAl(SO4)2, 3.0 gram KAl(SO4)2, grams of start with, 5.5 g.
Which of the following metals may tarnish to a greenish-blue color called verdigris
A- silver
B- chromium
C- gold
D- copper
Answer:
The correct answer is: D. copper
Explanation:
Copper is a chemical element that belongs to the group 11 and period 4 of the periodic table. It is a d-block element that has atomic number 29. Copper is a pinkish-orange colored metal that has high conductivity.
It readily oxidizes when exposed to atmospheric oxygen to form a greenish-blue layer of copper carbonate. This layer is known as verdigris or patina.
symbol for aluminum foil ?
Final answer:
The symbol for aluminum foil is Al. It is a silvery-white, soft, nonmagnetic, and ductile metal.
Explanation:
The symbol for aluminum foil is Al. Aluminum is a chemical element with the symbol Al and atomic number 13. It is a silvery-white, soft, nonmagnetic, and ductile metal in the boron group. Aluminum foil is commonly used in packaging, cooking, and insulation.
Scientists measure the time between the arrival of an earthquake's _______ and _______ waves to help determine the distance between the recording seismograph and the earthquake epicenter.
In the disproportionation reaction CI2 + H2Omc021-1.jpgHCIO + HCI, what describes the oxidation states of the substance Cl?
Cl has an oxidation number of 2 in Cl2. It is then reduced to Cl with an oxidation number of 1 in both HCl and HClO.
Cl has an oxidation number of –1 in Cl2. It is then oxidized to Cl with an oxidation number of 1 in both HCl and HClO.
Cl has an oxidation number of 0 in Cl2. It is then reduced to CI- with an oxidation number of –1 in both HCl and HClO.
Cl has an oxidation number of 0 in Cl2. It is then reduced to CI- with an oxidation number of –1 in HCl and is oxidized to Cl+ with an oxidation number +1 in HClO
Answer:
in other words its D
Explanation:
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What is nuclear fission?
the creation of high-energy plasma
when two or more atomic particles stick together and form a heavier atomic nucleus
the splitting of the atomic nucleus into parts
Why does radioactive decay occur?
The electric force and nuclear forces are in opposition to each other.
The electric force causes electrons to be released.
Nuclear forces disintegrate protons.
Answer:
D. the splitting of the atomic nucleus into parts
D.The electric force and nuclear forces are in opposition to each other.
Explanation:
Which of these orbital designations are invalid?
a. 4s
b. 2d
c. 3f
d. 3p
some studies has shown that peppermint odor increase people's mental sharpness especially when they solve math problems which best describes how this could be a valid scientific claim
Answer:
If it is tested in a controlled setting with repeated results.
Explanation:
Hello,
Every scientific foundation is preceded by a series of repetitive tests which allow the scientists to state both reliable and trustful conclusions. In such a way, by repeating the aforesaid test, the conclusion is strengthened, nevertheless, those tests must be carried out in a controlled manner in order to assure that the proposed conclusion is suitable under the specified conditions for scientific claims.
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Is all matter made up of tiny particles called atoms?
Answer:
true
Explanation:
Assuming all orbitals are in the same energy level which type of orbital has the lowest energy
Answer:
s atomic orbital
Explanation:
Lets us consider 4s, 4p, 4d and 4f. Here 4 is the energy level or the principal quantum number. For all the atomic orbital s, p, d and f the energy level is the same. But the energy level of each
Atomic orbital is different. s atomic orbital has the lowest energy followed by p, d and f.
Arranging the atomic orbitals in order of increasing energy:
s < p < d < f
Where are elements heavier than iron made
Elements heavier than iron are created during the violent explosion of a star known as a supernova. After the supernova, these elements are ejected into space and later form new stars and planets. Our presence on Earth, abundant in heavy elements, is a result of generations of stars synthesizing these elements.
Explanation:
Elements heavier than iron are made in the core of massive stars during the process of nucleosynthesis. However, when these stars exhaust their nuclear fuel, they die in an event known as a supernova. As the star explodes, its violent conditions lead to the creation of elements heavier than iron. The fusion of silicon into iron is the last step in nonexplosive element production inside a star. Beyond this point, due to iron's stability, fusion reactions end up absorbing energy instead of releasing it, leading to the star's collapse.
Most of these heavy elements are later ejected into space, enriching interstellar space with heavier elements. Over time, these elements are recycled to form new stars and planets, progressively leading to an increase in the proportion of heavier elements in the universe. Therefore, our presence on Earth, which is rich in heavy elements like silicon and iron, is due to generations of stars synthesizing these elements.
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A regulation nfl playing field of length x and width y has a perimeter of 346 2/3 or 1040/3 yards. What is width (y) and the area (a) of the rectangle.
The width (y) of the NFL field is 53 1/3 yards, and the area (a) is 6399 1/3 square yards, using a length (x) of 120 yards.
Explanation:The regulation NFL playing field is a rectangle. If the length is x and the width is y, the perimeter of the rectangle is represented as 2(x+y) which equals 346 2/3 or 1040/3 yards according to your question.
Given the standard dimensions of an NFL field, the length x is 360ft (120 yards) and the width y is 160ft (53 1/3 yards). Now we approach this problem using this knowledge.
To find the width y, we can rearrange the formula: y = 1040/6 - x/2. Substituting x = 120 yards into this equation, we find that y = 53 1/3 yards.
The area of the rectangle (field), represented by a, is found by multiplying the length by the width (x*y). Therefore, the area is a = 120 * 53 1/3 = 6399 1/3 square yards.
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in an aqueous solution of lithium chloride LiCl, what ions or molecules are present in solution
Final answer:
In an aqueous solution of LiCl, the compound dissociates completely into hydrated lithium ions (Li+(aq)) and chloride ions (Cl-(aq)), both surrounded by water molecules due to the polarity of water.
Explanation:
In an Aqueous Solution of Lithium Chloride (LiCl), What Ions or Molecules Are Present?
Lithium chloride (LiCl) is an ionic compound that dissociates completely in water due to the strong ion-dipole interactions between the ions and the polar water molecules. When LiCl is dissolved in water, it separates into its constituent ions, lithium (Li+) and chloride (Cl−). The process is facilitated by the polar nature of water molecules which arrange themselves around the ions to form a hydration shell. The oxygen ends of water molecules point towards lithium ions due to their positive charge, while the hydrogen ends tend to surround the chloride ions because of their negative charge. As a result, the solution contains hydrated lithium ions (Li+(aq)) and hydrated chloride ions (Cl−(aq)), indicating they are surrounded by water molecules in the solution.
Thus, in an aqueous solution of lithium chloride, the present species are Li+(aq) and Cl−(aq), fully dissociated and surrounded by water molecules, reflecting their hydrated state.
Solid lithium metal and diatomic nitrogen gas react spontaneously. give the balanced chemical equation (including phases) that describes this reaction.
The balanced chemical equation between sodium lithium metal and diatomic nitrogen gas is given by;
6Li(s) + N2(g) → 2Li3N(s)
Further Explanation:Chemical equations Chemical equations are equations showing reactions between reactants to form products. Chemical equations show the reactants or starting substances and products or substances formed during the reaction.Law of conservation of mass The law of conservation requires that when writing chemical equations, the mass of the reactants should be equal; to the mass of the products.This is done by making sure the number of atoms of each element involved in the chemical equation is equal on both sides of the equation.To ensure the law of conservation in chemical equations is observed we balance chemical equations.Balancing chemical equation:Balancing chemical equations is a try and error method that ensures the number of atoms in the side of the reactants is equal to the number of atoms in the side of products.Balancing chemical equations may also require inclusion of state symbols which shows the state of each compound or element involved in the chemical reactions.For example; the equation; 6Li(s) + N2(g) → 2Li3N(s) is balanced as the number of titanium and oxygen atoms are equal on both sides of the equation.There are six Lithium atom and 2 nitrogen atoms on either side of the equation.Keywords: Chemical equations, balancing of chemical equations
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Subject: Chemistry
Topic: Chemical equations
Sub-topic: Balancing chemical equations
The balanced chemical equation for the reaction between lithium metal and nitrogen gas to form lithium nitride is 6 Li (s) + N₂ (g) → 2 Li₃N (s). This reaction is exothermic.
The reaction between solid lithium metal and diatomic nitrogen gas produces lithium nitride.
The balanced chemical equation for this reaction is as follows:
Balanced Chemical Equation : 6 Li (s) + N₂ (g) → 2 Li₃N (s)In this reaction, six atoms of lithium react with one molecule of nitrogen gas to form two formula units of lithium nitride.This reaction is exothermic, meaning it releases heat.
Correct question is: Solid lithium metal and diatomic nitrogen gas react spontaneously to form a solid product. give the balanced chemical equation (including phases) that describes this reaction. indicate the phases using abbreviation (s), (I), (g) for solid, liquid and gas
Which olefin should predominate in the product of the dehydration of 2-methyl-2-butanol?
The predominant olefin formed in the dehydration of 2-methyl-2-butanol is 2-methylbutene.
Explanation:The predominant olefin formed in the dehydration of 2-methyl-2-butanol is 2-methylbutene. During the dehydration process, a water molecule is eliminated from 2-methyl-2-butanol, resulting in the formation of 2-methylbutene. This is the major product because it is the most stable and thermodynamically favored product.
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The olefin that would be predominate in the product of the dehydration of 2-methyl-2-butanol is 2-methyl-2-butene, also known as isobutene. The dehydration involves the removal of a hydrogen and a hydroxyl group, resulting in the formation of a double bond, creating the said olefin. The formation of isobutene is favored due to its relatively more stable structure.
Explanation:The olefin that should predominate in the product of the dehydration of 2-methyl-2-butanol is 2-methyl-2-butene, also known as isobutene. This reaction can produce either a cis-isomer or a trans-isomer.
The process of dehydration involves the removal of a hydrogen and a hydroxyl group (OH) from the 2-methyl-2-butanol molecule under the influence of a strong acid like sulfuric acid. This results in the formation of a double bond, creating the said olefin - 2-methyl-2-butene. The formation of isobutene is favored due to its relatively more stable structure, which is attributed to increased steric hindrance in the molecule.
Finally, it's worth noting that the overall intermolecular forces (IMFs), particularly hydrogen bonding, are important factors affecting the vapor pressure of the resultant olefin.
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