is this a true of false cuz if so this it true
A 24-V battery is powering a light bulb with a resistance of 3.0 ohms. What is the current flowing through the bulb? A) 7.20 A B) 8.0 A C) 12.0 A D) 72.0 A
According to Ohm's law for a portion of the circuit we have:
U=RI=>I=U/R=24/3=8 A
The correct answer is B
The current flowing through the bulb having a resistance of 3 ohms is 8 A.
The correct answer to the question is Option B. 8 A
From the question given above, the following data were obtained:
Voltage (V) = 24 V
Resistance (R) = 3.0 ohms.
Current (I) =?The current flowing through the bulb can be obtained by using the ohm's law equation as illustrated below:
V = IR24 = I × 3
Divide both side by 3
I = 24 / 3
I = 8 ATherefore, the current flowing through the bulb is 8 A.
The correct answer to the question is Option B. 8 A
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Extra credit calculate the total mechanical energy of a pendulum as it swings from its highest point to its lowest point
Cell division results in two new cells. Which of these statements correctly describes the relationship of these two new cells and the parent cell?
The statement that correctly describes the relationship between these two new cells and the parent cell is, mitosis results in two exact copies of the parent cell's genetic information. The correct option is A.
What is mitosis?In the cell division process known as mitosis, the parent cell divides to produce two genetically identical daughter cells. Cells from the same father and daughter share genetic information.
Prophase, Metaphase, Anaphase, and Telophase make up Mitosis. Human somatic cells go through a process called mitosis. A cell divides into two identical daughter cells after duplicating all of its components, including its chromosomes, during mitosis.
Therefore, the correct option is A. Mitosis results in two exact copies of the parent cell's genetic information.
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The question is incomplete. Your most probably complete question is given below:
A.Mitosis results in two exact copies of the parent cell's genetic information
B.Mitosis results in four exact copies of the parent cell's genetic information.
C.Mitosis results in two new cells that are genetically different from the parent cell.
D.Mitosis results in four new cells that are genetically different from the parent cell
someone please help on this one?
so other scientists can see how spread out your data are
You are 15.0m from the source of a sound. At that distance, you hear it at a sound level of 20.0dB. How close must you move to the sound to increase the sound level to 60dB?
I think its 45.0cm?
15.0cm
45.0cm
55.0cm
60.0cm
85.0cm
Answer:
Explanation:
its 85 cm because it just is in meters it would be .8m which would be decent distance to hear it
Derek and Diane race each other on bicycles. Derek starts 4 seconds before Diane. He goes at a steady speed of 6 m/s. Diane starts from rest and has an acceleration of 2 m/s2.
a. Write an expression for Derek's position in terms of t and v. (1 point)
b. Write an expression for Diane's position in terms of t and a. (1 point)
c. At what time does Diane catch up to Derek? (2 points)
d. How far has she gone when she catches up with him?
a. [tex]x(t) = vt' = v(t+4) = 6(t+4) [m][/tex]
Let's call:
[tex]t[/tex] the time calculated from the moment Diane starts her motion and [tex]t'[/tex] the time calculated from the moment Derek starts his motion. Derek starts his motion 4 seconds before Diane: this means that has an "advantage" of 4 seconds, so we can write
[tex]t'=t+4[/tex]
Then:
[tex]v=6 m/s[/tex] is the uniform speed of Derek
Derek is moving in a uniform motion, so Derek's position will be given by (assuming that the starting position is zero):
[tex]x(t) = vt' = v(t+4) = 6(t+4) [m][/tex]
We see that this is correct: in fact, when t=0 (instant when Diane starts her motion), Derek has already travelled for
[tex]x(t=0)=v(0+4)=6 (4)=24 m[/tex]
b. [tex]x'(t)= \frac{1}{2}at^2 =\frac{1}{2}(2)t^2=t^2 [m][/tex]
t is the time calculated from the moment Diane starts her motion. Diane is moving by accelerated motion, with constant acceleration [tex]a=2 m/s^2[/tex] and initial velocity [tex]v_0=0[/tex], so its position at time t is given by the law of uniform accelerated motion:
[tex]x'(t)= \frac{1}{2}at^2 =\frac{1}{2}(2)t^2=t^2[/tex]
c. t = 8.74 s
The time t at which Diane catches up with Derek is the time t at which the positions of the two persons is equal:
[tex]x(t)=x'(t)[/tex]
By solving, we have:
[tex]6 (t+4) = t^2\\t^2 -6t -24 =0[/tex]
Which has two solutions:
t = -2.74 s --> negative, we can discarde it
t = 8.74 s --> this is our solution
d. 76.4 m
When Diane catches Derek, at t=8.74 s, she has covered the following distance:
[tex]x'(t=8.74s)=t^2 = (8.74 s)^2=76.4 m[/tex]
We can verify that Derek is at the same position:
[tex]x(t=8.74 s)=6(t+4)=6(8.74 +4)=76.4 m[/tex]
Newton's second law states that F = m x a (Force is mass times acceleration). Which example would have the GREATEST acceleration? (Hint: You need to do calculations for these!)
A) a 10 kg ball thrown with a 50 Newton force
B) a 1 kg ball thrown with a 0.5 Newton force
C) a 50 kg student launched by a 100 Newton catapult
D) a 500 kg car accelerated by 1000 Newtons from the engine
A 3 kg lunch box is pushed across the lunch table. The acceleration of the lunch box is 2.0 m/s2. What was the net force applied to the lunch box? (Hint: F = ma) Show all your work!
Find the weight of a 10 kg rock. Remember, acceleration due to gravity is -9.8 m/s2. (Hint: w = mg) Show all your work!
A 3 kg lunch box is pushed across the lunch table. The acceleration of the lunch box is 2.0 m/s2. What was the net force applied to the lunch box? (Hint: F = ma) Show all your work!
The motion of an orbiting satellite can be described by the same motion characteristic of any object in uniform circular motion. The centripetal force acting toward the center of the circle, in this case, is supplied by
The force exerted by Earth plays the role of centripetal force.
Answer:
A- GRAVITY
Explanation:
IF IS ON USATestprep
Which are properties of an electromagnetic wave? Check all that apply. carries energy only through matter travels at the speed of light made of magnetic fields made of electrical fields radiates from a source
properties of electromagnetic waves are as follows
1. travels at the speed of light
All electromagnetic waves can travel at speed of light through vacuum or air.
2. made of magnetic fields
All electromagnetic waves has magnetic field that oscillates perpendicular to the direction of wave
3. made of electrical fields
All electromagnetic waves has electric field that oscillates perpendicular to the direction of wave
4. radiates from a source
these electromagnetic waves are radiated from source in all directions normally outwards
The wave generated due to electric fields is electromagnetic waves. The properties of electromagnetic waves include - travels at the speed of light and made of magnetic fields.
What is an Electromagnetic Wave?The vibrations caused due to oscillating electric as well as magnetic fields are known as electromagnetic waves. Electromagnetic waves are also produced by the motion of charged particles.
Following are the properties of electromagnetic waves -
All electromagnetic waves can travel at the speed of light through a vacuum or air.Electromagnetic waves have a magnetic field that oscillates perpendicular to the direction of the wave.All electromagnetic waves have an electric field that oscillates perpendicular to the direction of the wave.Electromagnetic waves are radiated from the source in all directions normally outwards.Thus, we can conclude that the properties of electromagnetic waves include - travels at the speed of light and made of magnetic fields.
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Using Hooke's law, Fspring=kΔx, find the elastic constant of a spring that stretches 2 cm. when a 4 Newton force is applied to it.
A) 1/2N/cm
B) 2N/cm
C) 4N/cm
D) 8N/cm
The correct answer is 2 N/cm, I take k12 and that was the correct answer
Why isnt the atmosphere a closed system?
Gasses from the earth escape from higher realms of the atmosphere.
A cat chase a mouse across a 1.0 m high table. The mouse steps out of the way, and the car slides off the table and strikes the floor 2.2m from the edge of the table. When the car slid off the table what was it’s speed?
Answer is 4.9 m/s how do we get 4.9 m/s?
The cat fell 1.0 m from the ground.
Using the formula
[tex]h = v_{oy}t - \frac{gt^2}{2}[/tex]
Here, [tex]v_{oy} = 0, \; h = 1.0 \; m.[/tex]
Solving for t, the time it spent in the air is
[tex]t = \sqrt{\frac{2h}{g}} = \sqrt{\frac{2(1.0 \; m)}{9.8 \; m/s^2}} = 0.451753951 \; s[/tex]
The cat does not accelerate along the horizontal, so it has constant horizontal velocity. Since it strikes the floor 2.2 m from the table, then
[tex] v_x = \Delta x/t = \frac{2.2\; m}{0.451753951 s} = 4.869907597 \; m/s \Rightarrow 4.9 \; m/s [/tex]
The problem involves concepts of projectile motion and gravity. It first calculates the falling time under gravity and then uses this time to figure out the cat's horizontal speed when it slid off the table, which comes out to be 4.9 m/s.
Explanation:This problem involves multiple concepts from physics including projectile motion and gravity. The cat sliding off the table can be viewed as a projectile because it moves in two dimensions: horizontally (the cat sliding across the table and off the edge) and vertically (the cat falling down due to gravity). The key is to break down the problem into these two dimensions and solve them separately.
To calculate the horizontal speed, we first need to use the gravitational acceleration and the vertical distance to determine the time it takes for the cat to hit the ground. Assume the gravitational acceleration is approximately 9.8 m/s^2. When an object is falling freely under influence of gravity (from a certain height), the distance is equal to 0.5*g*t^2, where g is the gravitational acceleration and t is time. So, from the equation 1.0m = 0.5*9.8m/s^2*t^2, we solve for t and get t = sqrt(2h/g) = sqrt(2*1/9.8) ≈ 0.45 seconds.
Now, we know the cat hit the floor 2.2 meters away from the edge of the table. Given it did this in approximately 0.45 seconds, we can use the basic speed equation, distance/time, to find out the speed. Therefore, speed = 2.2 m / 0.45 s ≈ 4.9 m/s. This is the speed at which the cat was sliding off the table.
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What average net force is required to stop a 4 kg bowling ball in 0.5 s if it’s initially traveling at 10 m/s?
The average net force required to stop the 4 kg bowling ball in 0.5 s is -80 N.
Explanation:To find the average net force required to stop the bowling ball, we can use the equation:
average net force = change in momentum / time taken
First, calculate the change in momentum:
Substitute the given values:
Next, divide the change in momentum by the time taken:
Average net force = -40 kg·m/s / 0.5 s = -80 N
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The average net force required to stop a 4 kg bowling ball initially traveling at 10 m/s in 0.5 seconds is -80 N, echoing that the force is used to stop the ball's motion.
Explanation:To calculate the average net force, we'll need to know the initial velocity, final velocity, and the time it took for the change to occur. In this scenario, the initial velocity is 10 m/s, the final velocity is 0 m/s (since the bowling ball comes to a stop), and the time over which this change happens is 0.5 seconds. The change in velocity (or acceleration) is calculated as (final velocity - initial velocity)/time. So, it's (0 m/s - 10 m/s) / 0.5 s = -20 m/s². As the force is calculated using F = ma, where m is the mass and a is the acceleration, the force would be F = 4 kg × (-20 m/s²) = -80 N. The negative sign indicates that the force is used to stop the motion of the bowling ball.
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A player hits a tennis ball in the air with an initial velocity of 32 meters per second at 35 degrees from the vertical how fast is the ball moving at the highest point
Answer: 18.35 m/s
Explanation:
At the highest point of trajectory, the vertical component of the velocity would be zero and the tennis ball would have horizontal component of velocity.
It is given that the initial velocity of the ball is 32 m/s and it makes 35° with the vertical. Hence the horizontal component of the velocity,
v sin θ = 32 m/s × sin 35° = 18.35 m/s
Hence, at the highest point in its trajectory, the tennis ball would be moving with the speed 18.35 m/s.
Physics student is dropped. If they reach the floor at a speed of 3.2 m/s, from what height did they fall?
Answer:
0.52 m
Explanation:
The motion of the studnet is an accelerated motion, with constant acceleration [tex]g=9.8 m/s^2[/tex] (acceleration of gravity) toward the ground. We can find the distance covered by the student (which is equal to the height from which he falls) by using the SUVAT equation:
[tex]v^2 -u^2 = 2ad[/tex]
where
v = 3.2 m/s is the final speed
u = 0 is the initial speed
a = 9.8 m/s^2 is the acceleration
d is the distance covered
By re-arranging the equation, we find:
[tex]d=\frac{v^2-u^2}{2a}=\frac{(3.2 m/s)^2-0}{2(9.8 m/s^2)}=0.52 m[/tex]
Final answer:
The student fell from a height of 0.52 meters.
Explanation:
To calculate the height from which the physics student fell, we can use the formula for free fall. The initial velocity is 0 m/s as the student is dropped. The final velocity is given as 3.2 m/s. We can use the equation v² = u² + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration due to gravity (approximately 9.8 m/s²), and s is the height. Rearranging the equation to solve for s, we get s = (v² - u²) / (2a). Plugging in the values, s = (3.2² - 0) / (2 * 9.8) = 0.52 meters. Therefore, the student fell from a height of 0.52 meters.
Kamala made a table to describe parts of the electromagnetic spectrum.
What mistake did Kamala make?
Gamma rays should have a very high frequency, not a very low frequency.
Visible light should have a low frequency and a long wavelength.
Infrared light should have a short wavelength, not a long wavelength.
Microwaves should have a high frequency and a short wavelength.
As per the spectrum due to electromagnetic waves we know that the frequency is increased as we move from radio waves to gamma rays.
So gamma rays must be with highest frequency and lowest wavelength
So error in the above mentioned table is
Gamma rays should have a very high frequency, not a very low frequency.
The mistake that Kamala made from the table is that Gamma rays should have a very high frequency, not a very low frequency.
What are gamma rays?These are the rays that happen due to radioactive decay that occurs in the atomic nuclei.
The frequencies of these rays are high. The frequency occurs at a rate of 10¹⁹ per second.Read more on gamma rays here:
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You are on a ParKour course. First you climb a angled wall up 9.5 meters. They you shimmy along the edge of a 3.5 meter long walk. Lastly you traverse 15 meters of obstacles to reach the end of the course. The trip takes 43 seconds . What is your average speed?
1.53 meters per second
How many electrons does a neutral atom of oxygen-18 have? 8 O 16.00
A. 8
B. 10
C. 18
D. 16
Answer:
A. 8
Explanation:
Atomic number of oxygen = 8
Oxygen is the 8th element in periodic table.
Atomic no. = 8, means one oxygen atom has 8 protons. Now, because the atom is neutral, so number of electrons = no. of protons in an atom.
Hence, the number of electrons in a neutral oxygen atom is 8.
Answer:A
Explanation:The answer is a because a neutral atom of oxygen is represented as O. It is atomic number of 8. Hence, it contains 8 electrons and 8 protons.
A person behind a moving siren will interpret the frequency of the siren as being
A person that is standing behind a moving siren will interpret the frequency to be lower compared to the person that would be standing in front of it. This is because the sound is now moving away from the person behind the siren and at this point the sound is juts lingering but, still very low.
Answer: Smaller than it actually is.
Explanation:
The person is behind the moving siren, and in this case, we assume that the siren is moving away from the man. By the Doppler effect, we know that a wave that comes from a source that is moving away will suffer a "redshift", which means that the wavelength increases a little bit, now, as you may know, the relation between the wavelength and the frequency comes by the equation:
velocity = wavelength/frequency.
If we keep the velocity constant (the velocity of the sound is the same independent of the frequency) then, if we have an increase in the wavelength, we must have a decrease in the frequency to maintain the velocity constant. From this, we can see that a redshift is also associated with a decrease in the frequency of the wave.
Then, the person behind the moving siren will interpret the frequency as being smaller than it actually is.
The equation for distance is d = st. If a car has a speed of 35 m/s, how long will it take to go 100 m?
A. 3500 s
B. 2.9 s
C. 5.9 s
D. 65 s
d = st
100 = 35t
35t = 100
35t/35 = 100/35
t = 20/7 or 2.9 s
Accretion is defined as:
A. Gravity that pushes matter in a circular manner into an outer source.
B. The disk of material surrounding a black hole.
C. Gravity that pulls matter inward in a spiraling matter.
D. None of the above.
Answer: C. Gravity that pulls matter inward in a spiraling matter.
Explanation:
In astrophysics, particles are pulled towards a massive object due to gravity which further attracts more particles. A disk of particles is formed around the object. Hence, we can define Accretion as a process in which particles are accumulated in a form of a disk of surrounding a massive object (like a black-hole) due to gravity which pulls the matter inwards and matter spirals around the massive object. Galaxies, planets etc. are formed out of accretion process. Thus, the correct option is C.
Answer:
Answer C
Explanation:
Edge
People who pay attention to detail:
A. follow procedures precisely
B. only need to check their work once
C. perform routine tasks without thinking
D. are able to multitask
follow procedures precisely.
apex
Please help on this one? The mass on the spring in this diagram is in harmonic motion between x = -5cm and x=5cm
c ... max speed zero accel
Answer:
A
Explanation:
PLEASE HELP FAST
3. Use the attached graph to identify the following variables.
a. Independent variable: ____________
b. Dependent variable: ____________
a. Independent variable: TIME
b. Dependent variable: DISTANCE
a car starts from rest and accelerates from u seconds until it reaches a speed of 10ms
the car then travels at 10ms for 2u seconds.
the diagram shows the speed time graph for journey.
the distance travlled by the car in the first 3u seconds is 125m
a, find the value of U
b,find the acceleration in the first u seconds ?
The value of 'u' is 5 seconds and the acceleration in the first 'u' seconds is 2 m/s^2.
Explanation:The car first accelerates for u seconds, then travels at a constant speed for 2u seconds. The total time is equal to 3u seconds, and the total distance covered is 125 meters.
We need to find the value of u. According to the equation for motion, the distance covered while accelerating is given by 0.5*a*u^2 (where 'a' is acceleration) and while moving at a constant speed it is given by speed*time which equates to 10*2u.
Therefore we set up the equation: 0.5*a*u^2 + 10*2u = 125. Since the acceleration is constant in the first part of the journey, and we know that speed = acceleration * time, we can say that 10 (final speed) = a * u. Solve this equation for 'a' and you get a = 10 / u.
Next substitute 'a' back to the main equation : 0.5*(10/u)*u^2 + 20u = 125. This simplifies to 5u + 20u = 125. Solving this equation, we find that u = 5 seconds. Substituting u back to the earlier equation, we find acceleration 'a' = 10 / 5 = 2 m/s^2.
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1) A force of 157 N is applied to a box 25o above the horizontal. If it is applied over a distance of 14.5 m how much work is done?
2) Jamie decides to drop an egg that has a mass of 345 g off the top of a 8.2 m building. How fast will it be falling right before it hits the ground?
3) Snookie is riding in her little red wagon (total mass of 215 kg) at a constant speed of 9.5 m/s. All of a sudden a magenta lemur (19.7 kg) appears in her lap. How fast is the Snook-meister traveling now?
4) Police are investigating an accident. They know that Tom Brady was driving 20 m/s before being hit by Jay Z head on. Tom Brady’s car has a mass of 1100 kg and Jay Z’s has a mass of 1475 kg. They also know that the two cars stuck together and were traveling 7 m/s in the same direction as Jay Z was driving. The speed limit was 25 m/s, was Jay Z speeding?
5) A ball is being swung in a horizontal circle of radius .23 m at a rate of 7.8 m/s. If the ball has a mass of 0.63 kg, find the force of tension on the string.
#1
Work done is given by
[tex]W = F.d cos\theta[/tex]
here we know that
F = 157 N
d = 14.5
[tex]\theta = 25^0[/tex]
now from the above formula
[tex]W = (157)(14.5)cos25 = 2063.2 J[/tex]
#2
By energy conservation
Initial total potential energy of egg = final total kinetic energy of egg
[tex]mgh = \frac{1}{2}mv^2[/tex]
[tex]v = \sqrt{2gh}[/tex]
[tex]v = \sqrt{2(9.8)(8.2)}[/tex]
[tex]v = 12.7 m/s[/tex]
#3
By momentum conservation we know that
[tex]m_1v_1 = (m_1 + m_2)v[/tex]
[tex]215(9.5) = (215 + 19.7) v[/tex]
[tex] v = \frac{215 (9.5)}{215 + 19.7}[/tex]
[tex]v = 8.7 m/s[/tex]
#4
by momentum conservation we know that
[tex]m_1v_1 + m_2v_2 = (m_1 + m_2) v[/tex]
let direction of velocity of Jay Z car motion is positive direction
now we will say
[tex]1100(-20) + 1475v = (1100 + 1475)(7)[/tex]
[tex]1475 v = 2575(7) + 1100(20)[/tex]
[tex]v = 27.14 m/s[/tex]
Yes Jay Z is overspeeding as his speed is more than speed limit
#5
Tension force in the string will be centripetal force
so here we can say
[tex]T = \frac{mv^2}{R}[/tex]
here we know that
m = 0.63 kg
v = 7.8 m/s
R = 0.23 m
[tex]T = \frac{0.63 (7.8)^2}{0.23}[/tex]
[tex]T = 166.6 N[/tex]
A boat loaded with a barrel of water floats in a swimming pool. When the water in the barrel is poured overboard, the swimming pool level will _____.
Question 6 options:
fall
remain unchanged
rise
Answer: Remain unchanged
Explanation:
The boat with water barrel overboard floats in swimming pool when weight of the water displaced by the boat is equal to the buoyant force acting on the boat.
When the water in the barrel is poured overboard, the level of the swimming pool level would remain unchanged as the weight of the boat with the water and barrel would remain unchanged ( as the density and volume of the whole system remains same) and hence, the weight of the water (of the swimming pool) displaced by the boat would remain same.
A boat loaded with a barrel of water floats in a swimming pool. When the water in the barrel is poured overboard, the swimming pool level will remain unchanged.
When water is poured from the barrel in the boat into the pool, the swimming pool water level remains unchanged due to the principles of buoyancy and displacement.
The phenomenon in question is related to the principles of buoyancy and displacement. When the barrel of water is onboard the boat, the total weight of the water and the boat is what displaces the pool water, causing it to rise up to a certain level. When the water is poured overboard, it is still in the pool, but the boat now weighs less and displaces less water. However, since the water from the barrel is now directly part of the pool, it displaces the same volume that the boat was displacing when holding the barrel full of water.
Therefore, the overall level of the swimming pool water will remain unchanged.
The potential difference across a resistor is 4.4 × 10 V. If the resistance of the resistor is 1.8 k?, how much current flows through the resistor?
The current flowing through the resistor is 2.44 x 10^-3 A.
Explanation:To find the current flowing through the resistor, you can use Ohm's Law which states that the current (I) is equal to the potential difference (V) across the resistor divided by the resistance (R). In this case, the potential difference across the resistor is 4.4 × 10 V and the resistance is 1.8 kΩ (which can be converted to 1.8 x 10^3 Ω). Using Ohm's Law:
I = V / R = (4.4 x 10) / (1.8 x 10^3) = 2.44 x 10^-3 A
Therefore, the current flowing through the resistor is 2.44 x 10^-3 A.
It is not just lab chemicals but also common household substances that can be classified as acidic, basic, and neutral materials. This categorization is based on the concentration of hydrogen ion (H+), or hydronium ion (H3O+), and hydroxide ion (OH-) present in the solutions. Based on these ion concentrations, the pH or pOH can be calculated giving a quantitative assessment. Additionally, litmus paper or pH paper can be used to qualitatively determine if the solution is acidic, basic, or neutral. Red litmus paper turns blue in acid. Blue litmus paper turns red in base. pH paper gives a more precise pH number based on the color the pH paper turns when a small amount of solution is placed on the paper.
Most materials are either acidic or basic. Baking soda, bleach, codeine, detergent, egg whites, household cleaners, and seawater are basic because they have a high concentration of hydroxide ions in solution and pH above 7. Acid rain, beer, coffee, lemon juice, maple syrup, mouth wash, pickles, rain, soda, tea, tomatoes, and vinegar are acidic because they have a high concentration of hydrogen ions in solution and pH below 7. A few solutions have neutral pH due an equal concentration of hydrogen ions and hydroxide ions. Water is the only truly neutral substance but human blood, milk, plant food, saliva, and tofu are very close to neutral pH with nearly equal hydrogen ion and hydroxide ion concentration and pH near 7.
Listed in the Item Bank are key terms and expressions, each of which is associated with one of the columns. Some terms may display additional information when you click on them. Drag and drop each item into the correct column. Order does not matter.
In the acidic column: Coffee, Lemon juice, Orange juice, Soft drink, Vinegar, and Tomato are included. In the basic column: Baking soda and Milk of magnesia are included. In Neutral column: Antacid, Detergent, Salt, Sugar and Water are included.
Here are the classifications of the items in the image:
Acidic:
Coffee - Coffee has a pH of around 5, which is slightly acidic. This is due to the presence of organic acids such as chlorogenic acid and quinic acid.
Lemon juice - Lemon juice has a pH of around 2, which is very acidic. This is due to the presence of citric acid.
Orange juice - Orange juice has a pH of around 3-4, which is acidic. This is due to the presence of citric acid and ascorbic acid.
Soft drink - Soft drinks typically have a pH of around 2.5-3.5, which is acidic. This is due to the presence of phosphoric acid, carbonic acid, and citric acid.
Tomato - Tomatoes are slightly acidic, with a pH of around 4. This is due to the presence of citric acid and malic acid.
Vinegar - Vinegar has a pH of around 2-3, which is very acidic. This is due to the presence of acetic acid.
Basic:
Baking soda - Baking soda has a pH of around 9, which is slightly basic. This is due to the presence of sodium bicarbonate.
Milk of magnesia - Milk of magnesia has a pH of around 10, which is basic. This is due to the presence of magnesium hydroxide.
Neutral:
Antacid - Antacids are typically designed to have a pH of around 7, which is neutral. This is because they are used to neutralize stomach acid.
Detergent - Detergents can have a pH range of 6-12, depending on the type of detergent. However, most detergents are formulated to be neutral or slightly alkaline.
Salt - Salt (sodium chloride) has a pH of around 7, which is neutral.
Sugar- Sugar (sucrose) has a pH of around 7, which is neutral.
Water - Pure water has a pH of 7, which is neutral.
If the 1kg standard body is accelerated by only f1=(3.O)+(4.0) and f2=(-2.0)+(-6.0) then what is fnet(al in unit vector notation and as (b) magnitude and (c) an angle relative to the positive x direction? What are the (d) magnitude and (e) angle of a ?
(a) [tex]\vec{F} = 1.0 \vec{i} - 2.0 \vec{j}[/tex]
The two forces are:
[tex]\vec{F_1} = 3.0 \vec{i} + 4.0 \vec{j}\\\vec{F_2} = -2.0 \vec{i} -6.0 \vec{j}[/tex]
To calculate the net force, we must calculate the resultant of the two vectors, which is obtained by separately summing the components of each vector:
[tex]F_x = 3.0 \vec{i}+(-2.0) \vec{i} = 1.0 \vec{i}\\F_y = 4.0 \vec{j} + (-6.0) \vec{j} = -2.0 \vec{j}[/tex]
So, the net force is
[tex]\vec{F} = 1.0 \vec{i} - 2.0 \vec{j}[/tex]
(b) 2.24 N
The magnitude of the net force is given by the Pythagorean theorem: it is equal to the square root of the sum of the squares of the single components:
[tex]|F|= \sqrt{F_x^2+F_y^2}=\sqrt{(1.0)^2+(-2.0)^2}=\sqrt{5}=2.24 N[/tex]
(c) [tex]-63.4^{\circ}[/tex]
The angle of the net force, relative to the positive x direction, is equal to the arctangent of the ratio between the vertical component and the horizontal component:
[tex]\theta=tan^{-1} (\frac{F_y}{F_x})=tan^{-1}(\frac{-2.0}{1.0})=-63.4^{\circ}[/tex]
(d) 2.24 m/s^2
The mass of the object is m = 1 kg, so according to Newton's second law the acceleration is given by
[tex]\vec{a} = \frac{\vec{F}}{m}[/tex]
Since we are interested in the magnitude of the acceleration, we have to take the magnitude of the net force into the calculation:
[tex]|a| = \frac{|F|}{m}=\frac{2.23 N}{1.0 kg}=2.24 m/s^2[/tex]
(e) [tex]-63.4^{\circ}[/tex]
According to Newton's second law:
[tex]\vec{a} = \frac{\vec{F}}{m}[/tex]
The acceleration has the same direction of the force, therefore the angle of the acceleration (measured with respect to the positive x direction) is [tex]-63.4^{\circ}[/tex].
The net force acting on the 1kg standard body is 1.0i - 2.0j in unit vector notation. The magnitude of the net force is 2.236 units. The angle of the net force is -63.43 degrees relative to the positive x-direction. The magnitude and angle of a are not provided in the question.
Explanation:To find the net force acting on the 1kg standard body, we need to add the two given forces vectorially. Adding f1 and f2 gives us fnet= (3.0 + (-2.0))i + (4.0 + (-6.0))j = 1.0i - 2.0j. So, fnet = 1.0i - 2.0j in unit vector notation.
The magnitude of fnet is found by taking the square root of the sum of the squares of its components: √(1.0² + (-2.0)²) = √5 = 2.236. So, the magnitude of fnet is 2.236 units.
The angle of fnet relative to the positive x-direction can be found using the inverse tangent function: tan^(-1)(-2.0/1.0) = -63.43 degrees. So, the angle of fnet is -63.43 degrees relative to the positive x-direction.
The magnitude and angle of a are not provided in the question, so we cannot determine those values.