A runner runs halfway around a circular path of a radios of 10m. What Is the displacement of the jogger

the answer c!!!!!!!!!!

Answer:

It would be best to start as close to the first point of your line on the Y-axis.

(Sorry if that doesn't make much sense, I tried to word it as best as I could. Basically, just start your line on the Y-axis closest to your starting point of the line.)

Explanation:

An object travels 8 meters in the first second of travel, 8 meters again during the second of travel, and 8 meters again during the third second. Its acceleration would be 0 m / s² , therefore the correct answer is option A.

The rate of change of the velocity with respect to time is known as the acceleration of the object. Generally, the unit of acceleration is considered as meter/seconds².

As given in the problem if an object travels 8 meters in the first second of travel, 8 meters again during the second of travel, and 8 meters again during the third second, then we have to find its acceleration ,

As the object is covering an equal distance in an equal interval of time its acceleration would be zero.

Thus , the correct answer is option A.  

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The box travels a distance of approximately 3.51 meters along the incline before coming to rest.

An angle of 14.0° with respect to the horizontal is made when box slides up an incline. 0.180 is the coefficient of kinetic friction between the box and the surface of the incline. It is given that 2.20 m/s is the initial speed of the box at the bottom of the incline. The box travels a distance of approximately 3.51 meters along the incline before coming to rest.

To find this, we use the equations of motion, taking into account the forces acting on the box, including gravity, normal force, friction force, and the component of gravity parallel to the incline. By applying these equations and considering the work done by friction, we can determine the distance traveled by the box.

To determine the rocket's acceleration, subtract the air resistance from the thrust and divide by the mass of the rocket.

To determine the rocket's acceleration, we need to calculate the net force acting on the rocket by subtracting the air resistance from the thrust.

The net force is equal to the mass of the rocket multiplied by its acceleration. Rearranging the equation, we can solve for acceleration: acceleration = (net force) / (mass). In this case, the net force is given as the thrust minus the air resistance, so the acceleration would be (1.250X10^7 N - 4.50X10^6 N) / (5.00X10^5 kg).

Simplifying the expression, the acceleration is approximately 17.6 m/s².

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Newton's First Law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. It may be seen as a statement about inertia, that objects will remain in their state of motion unless a force acts to change the motion. Any change in motion involves an acceleration, and then Newton's Second Law applies. The First Law could be viewed as just a special case of the Second Law for which the net external force is zero, but that carries some presumptions about the frame of reference in which the motion is being viewed. The statements of both the Second Law and the First Law here are presuming that the measurements are being made in a reference frame which is not itself accelerating. Such a frame is often referred to as an "inertial frame". The statement of these laws must be generalized if you are dealing with a rotating reference frame or any frame which is accelerating.

Newton's First Law contains implications about the fundamental symmetry of the universe in that a state of motion in a straight line must be just as "natural" as being at rest. If an object is at rest in one frame of reference, it will appear to be moving in a straight line to an observer in a reference frame which is moving by the object. There is no way to say which reference frame is "special", so all constant velocity reference frames must be equivalent.

Two of Newton's laws of motion are: the first law, stating that an object at rest stays at rest and an object in motion stays in motion at a constant velocity unless acted upon by an external force; and the second law, which describes how a force on an object results in an acceleration proportional to that force and inversely proportional to the object's mass.

Isaac Newton’s contributions to science include the formulation of three fundamental laws of motion that describe the relationship between a body and the forces acting upon it, and the body’s motion in response to these forces. The first two of Newton's laws are:

Newton’s first law, also known as the law of inertia, states that every object will continue to be in a state of rest or move at a constant speed in a straight line unless it is compelled to change that state by an outside force. This law emphasizes the tendency of objects to resist changes to their state of motion unless acted upon.

The change of motion of a body, as described by Newton’s second law, is proportional to and in the direction of the force acting on it. This law introduces the concept of acceleration, indicating that a force results in an acceleration of an object, and that acceleration is dependent on the object’s mass.

A force of 20 N acts on a rocket for 350 s, causing the rocket's velocity to increase, the impulse of the force, the rocket's momentum increase 7000 N-s.

A force in physics is an effect that has the power to alter an object's motion. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull.

A force is a vector quantity since it has both magnitude and direction.

The formula for impulse is force times time, so impulse would be 20N x 350s = 7000 N x s. Since this impulse of 7000 N x s, the momentum would also be the same since the velocity increased after this impulse.

A force of 20 N acts on a rocket for 350 s, causing the rocket's velocity to increase, the impulse of the force, the rocket's momentum increase 7000 N-s.

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The energy source which is most abundant in california due to its position in plate boundary is geothermal energy.

Geothermal energy is the thermal energy found in the Earth's crust that has been produced during the planet's formation and by the radioactive decay of minerals in an amount that is currently unknown but may be nearly equal.

Some rocks melt under the intense pressure and heat of the Earth's interior, while the solid mantle exhibits plastic behavior. As a result, since the mantle is lighter than the surrounding rock, some of it convicts upward.

Since the Paleolithic era, geothermal heating has been utilized for space heating and for bathing, respectively, utilizing water from hot springs.

Geothermal power, the phrase used to describe the production of electricity from geothermal energy, has become more significant in recent years.

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The man's upward acceleration is found using Newton's second law, calculating the man's weight and combining that with the force he exerts on the rope. The resulting net force is divided by his mass, giving a result inclusive of gravity. Subtracting gravity's acceleration gives his actual upward acceleration, 5.15 m/s².

The subject of the question falls under the domain of Physics, specifically Newton's second law of motion. The 72.0-kg man throwing the rope over the tree and pulling down with a force of 371 N creates a force that works against his weight. To find the acceleration, we use the equation: net force = mass x acceleration (Net F = ma).

First, calculate the man's weight. Weight is the force due to gravity and is calculated as mass x gravity. So the man's weight is 72.0 kg x 9.80 m/s² = 705.60 N.

The force the man exerts on the rope is 371 N. But remember, he is pulling down, so his force and gravity are working together. Thus, the net force is 371 N (the man's pull) + 705.60 N (the man's weight) = 1076.60 N.

Then, to find the acceleration, we rearrange the equation to a = net force/mass. So, this becomes 1076.60 N / 72.0 kg = 14.95 m/s². But this includes the acceleration due to gravity. So to get the upward acceleration, we subtract gravity: 14.95 m/s² - 9.80 m/s² = 5.15 m/s² upward. Therefore, the man's upward acceleration due to his pull is 5.15 m/s².

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Answer:

the answer is 5.0

Explanation:

Final answer:

The question asks for calculations involving the physics of car motion, specifically considering the static friction between tires and various road surfaces to find maximum deceleration and acceleration without slipping.

Explanation:

The student's question involves calculating the maximum deceleration and acceleration of a car under various road conditions, which requires an understanding of physics concepts such as centripetal force, coefficient of static friction, and normal force. These calculations are based on the equations of motion and the relationship between frictional force and the normal force, taking into account the angle of incline or decline of the road surface.

The coefficient of static friction is crucial in determining the car's ability to accelerate or decelerate without slipping. For example, the friction on dry concrete will differ from that on wet concrete or ice. The provided coefficients of static friction are used to determine the maximum safe speeds or accelerations to avoid tire slippage.

Final answer:

A column of mercury would need to be 73.5 cm high to measure a pressure of 1 atm.

Explanation:

The question asks for the height of a column of water needed to measure a pressure of 1 atm. We can use the information given to compare the density of water and mercury. Since water has a density that is 13.6 times less than that of mercury, a column of mercury only needs to be 13.6 times shorter than a column of water to measure the same pressure. It is stated that a column of water over 10 meters high can measure atmospheric pressure, so a column of mercury would only need to be 10 meters / 13.6 = 0.735 meters (or 73.5 cm) high to measure the same pressure.

Answer:

D. A reactant

Explanation:

The color of the spotlight will be blue since yellow will not be transmitted.

White light is composed of the colors seven close of light.

The seven colors rest of the seven colors can be produced from a combination of the colors red, blue and green light.

Yellow color is made from red and green color.

Since yellow will not be transmitted, the color of the spotlight will be blue.

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The kinetic energy of this vehicle in kilojoules is about 6.053 × 10² kiloJoules

Let's recall Kinetic Energy formula as follows:

[tex]Ek = \frac{1}{2}mv^2[/tex]

Ek = Kinetic Energy ( Joule )

m = mass of the object ( kg )

v = speed of the object ( m/s )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

mass of car = m = 1423 kg

speed of car = v = 105.0 km/h = 29¹/₆ m/s

Asked:

kinetic energy of car = Ek = ?

Solution:

We will use Kinetic Energy formula as follows:

[tex]Ek = \frac{1}{2}mv^2[/tex]

[tex]Ek = \frac{1}{2}(1423)(29\frac{1}{6})^2[/tex]

[tex]Ek \approx 6.053 \times 10^5 \texttt{ Joules}[/tex]

[tex]Ek \approx 6.053 \times 10^2 \texttt{ kiloJoules}[/tex]

[tex]\texttt{ }[/tex]

The kinetic energy of this vehicle in kilojoules is about 6.053 × 10² kiloJoules

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

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Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant

Answer:

The force needed to lift the crate is 50 N

Explanation:

[tex]P_{1} = \frac{F_{1}}{A_{1}} = \frac{1500N}{25 m^{2} } \\P_{1}= P_{2} \\P_{2} = \frac{F_{2}}{A_{2}}\\A_{2} = 25*\frac{1}{30} \\\frac{1500N}{25 m^{2} } =\frac{F_{2} }{\frac{25}{30}m^{2}  }\\ F_{2}* 25 m^{2} = 1500 N *\frac{25}{30}m^{2}\\ F_{2}= \frac{1250 N*m^{2}}{25 m^{2}}\\ F_{2}= 50 N[/tex]

Final answer:

To calculate the force needed to lift the crate, we can use Pascal's principle. The force needed to lift the crate is 50 N.

Explanation:

To calculate the force needed to lift the crate, we can use Pascal's principle. According to Pascal's principle, the pressure exerted on a fluid in a closed container is transmitted equally in all directions. In this case, the force applied by the heavy crate on the larger piston is 1500 N, and the smaller piston is 1/30 the size of the larger one. Therefore, the force needed to lift the crate can be calculated using the equation:

(Force on larger piston) / (Area of larger piston) = (Force needed to lift crate) / (Area of smaller piston)

Let's substitute the given values into the equation:

(1500 N) / (25 m^2) = (Force needed to lift crate) / (1/30 * 25 m^2)

Simplifying the equation, we find that the force needed to lift the crate is 50 N.