A recent survey showed that 102 adults out of a sample of 400 do not like cold weather. However, 115 of those studied said that they had interest in taking skiing lessons. Based on this sample, if an adult is chosen at random, what is the probability that he or she has no desire to take skiing lessons? Express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.

Answer:

Andrew walks more steps than Sarah.

Step-by-step explanation:

The question is incomplete. The complete question is :

Andrew and Sarah are tracking the number of steps they walk. Andrew records that he can walk 6000 steps in 50 minutes. Sarah writes the equation y=118x, where y is the number of steps and x is the number of minutes she walks, to describe her step rate. This week, Andrew and Sarah each walk for a total of 5 hours. Who walks more steps?

Solution:

Given:

Andrew walks 6000 steps in 50 minutes.

Number of steps Sarah walks is given by the equation :

[tex]y=118x[/tex]

where [tex]y[/tex] is the number of steps and [tex]x[/tex] is the number of minutes she walks.

Finding the number of steps each walks in 5 hours.

Total number of minutes in 5 hours = [tex]5\times 60 = 300\ min[/tex]

For Andrew:

Using unitary method:

If in 50 minutes Andrew walks = 6000 steps.

In 1 minute he will walk = [tex]\frac{6000}{50}[/tex] = 120 steps

In 300 minutes he will walk = [tex]120\times 300 = 36000[/tex] steps

Thus, Andrew will walk 36,000 steps in 5 hours.

For Sarah:

We will plugin [tex]x=300[/tex] in the equation and solve for [tex]y[/tex].

We have:

[tex]y=118(300)[/tex]

∴ [tex]y=35400[/tex]

Thus, Sarah will walk 35,400 steps in 5 hours.

Therefore, Andrew walks more steps than Sarah as [tex]36,000>35,400[/tex].

Answer:

- √5

Step-by-step explanation:

Given that, a ray intersects point (negative 3, 6) in quadrant 2 and we are told to find the value of secant theta.

To get the answer to the question,  

The first step is to find the hypotenuse, we have to use the Pythagoras theorem  where, Hypotenuse = opposite raise to power two + adjacent raise to power.  

(I.e. h= O² + A²)

H = 6² + (-3)2

H = 36 + 9

H = 45

We then convert the answer to surds form.  

H = 3√5

The next step is to find the value of secant theta.  

To get the value of secant theta we will have to divide the hypotenuse by adjacent with a negative sign because of the negative sign in the second quadrant  

We have  

Sec ø = - (hypotenuse/adjacent)  

Sec ø = - (3√5/ 3)

Sec ø = - √5

Answer:

-√5

Step-by-step explanation:

Answer:sdxfrcgtvyhujikokjhgfdsasdfghjknbv 6yujhgtrfgb         srry .\.

Answer:

Chris will make $1905.22 by selling gold.

Step-by-step explanation:

Amount of gold Chris will have = 42 g

Current rate of gold = $1286 per ounce

We need to find the amount Chris will make after selling the gold.

Now we will first find Current rate of gold in grams.

We know that 1 ounce = 28.3495 grams.

So we can say that

28.3495 g = $1286

So 1 g = Rate of gold for 1 gram.

By Using Unitary method we get;

Rate of gold for 1 gram = [tex]\frac{1286}{28.3495} \approx \$45.3624[/tex]

Now we will find the amount for 42 g of gold

if 1 g = $45.3624

so 42 g = Amount of money for 42 g

Again by using Unitary method we get;

Amount of money for 42 g = [tex]42 \times 45.3624 \approx \$1905.22[/tex]

Hence Chris will make $1905.22 by selling gold.

Chris can get $1,736.10 by selling 42 grams of gold.

Chris's uncle from Japan has promised to give him 42 grams of gold. The local jewellery exchange will buy gold for $1286 per ounce. To find out how much money Chris can get for selling the gold, we need to convert grams to ounces and then multiply by the price per ounce. There are approximately 31.1035 grams in an ounce. So, to convert grams to ounces we use the following formula:

Divide the amount of gold in grams by the number of grams per ounce. 42 grams ÷ 31.1035 grams/ounce = 1.35 ounces.

Multiply the amount of gold in ounces by the current price of gold per ounce. 1.35 ounces × $1286/ounce = $1,736.10.

Answer: the employee worked for 41 hours

Step-by-step explanation:

Let x represent the total number of hours that the employee worked. An employee earns $7.00 an hour for the first 35 hours worked in a week and $10.50 for any hour over 35. Let y represent the amount earned for x hours. Therefore

y = 7×35 + 10.5(x - 35)

y = 245 + 10.5x - 367.5

One week's paycheck (before deduction) was for $308.00. This means that y = $308.00. Therefore,

308 =245 + 10.5x - 367.5

308 = 10.5x - 122.5

10.5x = 308 + 122.5 = 430.5

x = 430.5/10.5

x = 41

Answer:

3

Step-by-step explanation:

Simplify :

(5-4i)-(2-4i)

5-4i-(2-4i)

=3

Answer:280 miles

let x=rate of speed on the way to mountains

x+21=rate of speed on the way home

travel time*rate=distance

8x=5(x+21)

8x=5x+105

3x=105

x=35

8x=280

how far away does Bob live from the mountains? =280 miles

Final answer:

Bob lives 280 miles away from the mountains. We solved for the slower speed and then calculated the distance using the time it took Bob to get to the mountains and his average speed during that trip.

Explanation:

Finding the Distance to the Mountains

To find out how far Bob lives from the mountains, we need to set up an equation based on the information given about time and average speed. Since the average rate was 21 miles per hour faster on the return trip and the times for the trips are known (8 hours to the mountains and 5 hours returning), we can let the slower speed be 's' and the faster speed be s' + 21'.

We can now create two equations based on the definition that Distance = Speed *Time:

Coming back home (faster speed): Distance = (s + 21) *5 hours

Since the distance to the mountains and back home is the same, we can equate these two expressions:

s * 8 = (s + 21)* 5

Calculating the Speed and Distance

Now we solve for 's':

8s = 5s + 105

8s - 5s = 105

3s = 105

s = 35

Thus, the slower speed was 35 miles per hour. We can plug this back into either equation to find the distance:

Distance = 35 miles/hour * 8 hours

Distance = 280 miles

Therefore, Bob lives 280 miles away from the mountains.

Answer:

C. 122

Step-by-step explanation:

Given,

Dimension of the cake:

Length = 12 in      Width = 16 in      Height = 4 in

We have to find out the area of the tray that is not covered by the cake.

Indra centered the cake on a circular tray.

Radius of the tray = 10 in.

So area of the tray is equal to π times square of the radius.

Framing in equation form, we get;

Area of tray =[tex]\pi\times r^2=3.14\times{10}^2=3.14\times 100=314\ in^2[/tex]

Since the cake is placed in circular tray.

That means only base area of cake has covered the tray.

Base Area of cake = [tex]length\times width=12\times 16=192\ in^2[/tex]

Area of the tray that is not covered by the cake is calculated by subtracting area of base of cake from area of circular tray.

We can frame it in equation form as;

Area of the tray that is not covered by the cake = Area of tray - Base Area of cake

Area of the tray that is not covered by the cake =[tex]314-192=122\ in^2[/tex]

Hence The area of the tray that is not covered by the cake is 122 sq. in.

Answer:

Step-by-step explanation:

Since the length of time taken on the SAT for a group of students is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - u)/s

Where

x = length of time

u = mean time

s = standard deviation

From the information given,

u = 2.5 hours

s = 0.25 hours

We want to find the probability that the sample mean is between two hours and three hours.. It is expressed as

P(2 lesser than or equal to x lesser than or equal to 3)

For x = 2,

z = (2 - 2.5)/0.25 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.02275

For x = 3,

z = (3 - 2.5)/0.25 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.97725

P(2 lesser than or equal to x lesser than or equal to 3)

= 0.97725 - 0.02275 = 0.9545

Final answer:

The probability that the sample mean is between two and three hours is practically 1, or 100%.

Explanation:

To find the probability that the SAT exam completion time sample mean for a group of students is between two and three hours, we need to calculate the z-scores for 2 hours and 3 hours and then use these z-scores to determine the corresponding probabilities.

Given:

- Population mean (= 2.5 hurs

- Standard deviation = 0.25 hours

- Sample size  = 60

We'll use the z-score formula:

[tex]\[ z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}} \][/tex]

For X = 2  hours:

[tex]\[ z = \frac{2 - 2.5}{\frac{0.25}{\sqrt{60}}} \][/tex]

[tex]\[ z = \frac{-0.5}{\frac{0.25}{\sqrt{60}}} \][/tex]

[tex]\[ z \approx \frac{-0.5}{\frac{0.25}{7.746}} \][/tex]

[tex]\[ z \approx \frac{-0.5}{0.0323} \][/tex]

[tex]\[ z \approx -15.49 \][/tex]

For X = 3 hours:

[tex]\[ z = \frac{3 - 2.5}{\frac{0.25}{\sqrt{60}}} \][/tex]

[tex]\[ z = \frac{0.5}{\frac{0.25}{\sqrt{60}}} \][/tex]

[tex]\[ z \approx \frac{0.5}{\frac{0.25}{\sqrt{60}}} \][/tex]

[tex]\[ z \approx \frac{0.5}{0.0323} \][/tex]

[tex]\[ z \approx 15.49 \][/tex]

Using the z-scores, we consult a standard normal distribution table or use a calculator to find the corresponding probabilities. Then, we calculate the difference between the two probabilities to get the probability that the sample mean is between two and three hours. Let me calculate the exact probabilities.

Using the z-scores calculated:

For z = -15.49 , the corresponding probability is practically 0 (since it's far in the left tail of the distribution).

For z = 15.49, the corresponding probability is practically 1 (since it's far in the right tail of the distribution).

Therefore, the probability that the sample mean is between two and three hours is practically 1, or 100%.

Answer:

[tex]18x+12y\geq 300[/tex]

Step-by-step explanation:

Let

x ---> the number of an adult tickets

y ---> the number of a child tickets

Remember that the word "at least" means "greater than or equal to"

so

The number of an adult tickets multiplied by its price ($18) plus the number of a child tickets multiplied by its price ($12) must be greater than or equal to $300

The inequality that represent this situation is

[tex]18x+12y\geq 300[/tex]

using a graphing tool

the solution is the shaded area

Remember that the number of tickets cannot be a negative number

see the attached figure

Answer:

The profits for firma A and B will decrease.

Step-by-step explanation:

Oligopoly by definition "is a market structure with a small number of firms, none of which can keep the others from having significant influence. The concentration ratio measures the market share of the largest firms".

If the costs remain the same for both companies and both firms decrease the prices then we will have a decrease of profits, we can see this on the figure attached.

We have an equilibrium price (let's assume X) and when we decrease a price and we have the same level of output the area below the curve would be lower and then we will have less profits for both companies.

Answer:

No solution , The line's are parallel

Step-by-step explanation:

Given set of equations are y = 56x + 2 and y = 56x - 2

If we observe carefully these lines are in the form of y=mx+c where m is the slope of the line and c is the y-intercept

Here both the line's have slope m = 56

We also know that two lines are parallel only if their slopes are equal ie m1=m2

Here the two line's have same slope, so the giventwo line's are parallel And they don't have a solution So jane is wrong.

Answer: 13

Step-by-step explanation: first we have to know what an integer, which is a single whole number without fractions or decimal numbers e.g. 1,2,3,4,5,6,7,8,9

So now we are to find the least possible positive difference between two digit integers with combination of 2,4,6,9

So first, since it has to be the lowest difference, we have to look between these numbers for the lowest difference between the given integers, 6-4 = 2, 4-2 = 2, now the rest of the combination will give numbers higher that 2, e.g. 9-6 = 3, 6-2 = 4, 9-4 = 5, 9-2 = 7, so we can say our two digit integers can start with either 4 and 2, or 6 and 4, which is the tens in the two digit integers, so to get the least difference in this values, the units number of the bigger two digit integer will be smaller than the units number of the smaller two digit integers

So let's take the number 2, and 4

The bigger two digit integer will obviously start will 4, and since it's supposed to have the smaller units number, the two digit integer will be 46, and the second two digit integer will be 29, the finding the difference

We have 46-29=17

The taking the other combination of integer to give the smallest value, which was 2, (6 and 4) then giving the units number of the bigger integer which will be the smaller units number value (2), that two digit integer will be 62, and the other 49, finding the difference

62-49= 13

So therefore the least possible positive difference = 13

Answer: Two-sample t-test

Step-by-step explanation:

The Two-sample t-test is used to test the difference between two random and distinct population means. It help test whether the difference between the two populations is statistically significant.

In the case above the researcher wants to determine whether there is a difference in mean number of minutes of television viewing between men and women which makes it a Two-sample t-test.

Answer:

Step-by-step explanation:

Suppose the time required for an auto shop to do a tune-up is normally distributed, we would apply the formula for normal distribution which is expressed as

z = (x - u)/s

Where

x = points scored by students

u = mean time

s = standard deviation

From the information given,

u = 102 minutes

s = 18 minutes

1) We want to find the probability that a tune-up will take more than 2hrs. It is expressed as

P(x > 120 minutes) = 1 - P(x ≤ 120)

For x = 120

z = (120 - 102)/18 = 1

Looking at the normal distribution table, the probability corresponding to the z score is 0.8413

P(x > 120) = 1 - 0.8413 = 0.1587

2) We want to find the probability that a tune-up will take lesser than 66 minutes. It is expressed as

P(x < 66 minutes)

For x = 66

z = (66 - 102)/18 = - 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.02275

P(x < 66 minutes) = 0.02275

Answer: the length is 6 feet. The width is 2 feet

Step-by-step explanation:

The garden pool is rectangular in shape.

Let L represent the length of the rectangular garden.

Let W represent the width of the rectangular garden.

The area of a rectangle is expressed as L× W. The area of the rectangular garden pond is 12ft^2. It means that

L× W = 12 - - - - - - - - - - 1

The length of the pool needs to be 2ft more than twice that width. This means that

L = 2W + 2 - - - - - - - - - - - 2

Substituting equation 2 into equation 1, it becomes

W(2W + 2) = 12

2W^2 + 2W = 12

2W^2 + 2W - 12 = 0

W^2 + W - 6 = 0

W^2 + 3W - 2W - 6 = 0

W(W + 3) - 2(W + 3) = 0

W - 2 = 0 or W + 3 = 0

W = 2 or W = - 3

Since the Width cannot be negative, then the width is 2 feet

Substituting W = 2 into equation 2. It becomes

L = 2×2 + 2 = 6 feet

Answer:

The answer to your question is Midpoint  ( [tex]\frac{1}{2} , -2)[/tex]

Step-by-step explanation:

Data

A (3, -7)

B (-2, 3)

Formula

[tex]Xm = \frac{x1 + x2}{2}[/tex]

[tex]Ym = \frac{y1 + y2}{2}[/tex]

Substitution and simplification

[tex]Xm = \frac{3 - 2}{2}[/tex]

[tex]Xm = \frac{1}{2}[/tex]

[tex]Ym = \frac{-7 + 3}{2}[/tex]

[tex]Ym = \frac{-4}{2}[/tex]

[tex]Ym = -2[/tex]

Solution

Midpoint  ( [tex]\frac{1}{2} , -2)[/tex]

Answer:

Option B is right

Step-by-step explanation:

Given that in the graduating class of a certain college, 48 percent of the students are male and 52 percent are female. In this class 40 percent of the male and 20 percent of the female students are 25 years old or older.

                      Males              Females

                        48%                    52%

25 or more

age                  40%                     20%

One student in the class is randomly selected,

to find the probability that he or she will be less than 25 years old

= Prob (male and less than 25 years old)+Prob (female and less than 25 years old)

(since mutually exclusive and exhaustive)

= [tex]0.48(1-0.4) + 0.52(1-0.20)\\= 0.288+ 0.416\\= 0.704\\[/tex]

After rounding off to 1 one decimal

we get 0.7

Option B is right

Answer:

k-5

Step-by-step explanation:

"k and 12" : (k + 12)

"17 less than k and 12" : (k + 12) - 17

simplifying:

(k + 12) - 17

= k + 12 - 17

= k-5

[tex]\fontsize{18}{10}{\textup{\textbf{The number of different combinations is 120.}}}[/tex]

Step-by-step explanation:

A, B and C are integers between 1 and 10  such that A<B<C.

The value of A can be minimum 1 and maximum 8.

If A = 1, B = 2, then C can be one of 3, 4, 5, 6, 7, 8, 9, 10 (8 options).

If A = 1, B = 3, then C has 7 options (4, 5, 6, 7, 8, 9, 10).

If A = 1, B = 4, then C has 6 options (5, 6, 7, 8, 9, 10).

If A = 1, B = 5, then C has 5 options (6, 7, 8, 10).

If A = 1, B = 6, then C has 4 options (7, 8, 9, 10).

If A = 1, B = 7, then C has 3 options (8, 9, 10).

If A = 1, B = 8, then C has 2 options (9, 10).

If A = 1, B = 9, then C has 1 option (10).

So, if A = 1, then the number of combinations is

[tex]n_1=1+2+3+4+5+6+7+8=\dfrac{8(8+1)}{2}=36.[/tex]

Similarly, if A = 2, then the number of combinations is

[tex]n_2=1+2+3+4+5+6+7=\dfrac{7(7+1)}{2}=28.[/tex]

If A = 3, then the number of combinations is

[tex]n_3=1+2+3+4+5+6=\dfrac{6(6+1)}{2}=21.[/tex]

If A = 4, then the number of combinations is

[tex]n_4=1+2+3+4+5=\dfrac{5(5+1)}{2}=15.[/tex]

If A = 5, then the number of combinations is

[tex]n_5=1+2+3+4=\dfrac{4(4+1)}{2}=10.[/tex]

If A = 6, then the number of combinations is

[tex]n_6=1+2+3=\dfrac{3(3+1)}{2}=6.[/tex]

If A = 7, then the number of combinations is

[tex]n_7=1+2=\dfrac{2(2+1)}{2}=3.[/tex]

If A = 3, then the number of combinations is

[tex]n_8=1.[/tex]

Therefore, the total number of combinations is

[tex]n\\\\=n_1+n_2+n_3+n_4+n_5+n_6+n_7+n_8\\\\=36+28+21+15+10+6+3+1\\\\=120.[/tex]

Thus, the required number of different combinations is 120.

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Question : ow many types of zygotic combinations are possible between a cross AaBBCcDd × AAbbCcDD?

Link : https://brainly.in/question/4909567.

Number -13 is classified as real and integer

Solution:

Given that The number -13 can be classified as

Let us first understand about real numbers, whole numbers, Integers and irrational numbers

Whole numbers are positive numbers, including zero, without any decimal or fractional parts. Negative numbers are not considered "whole numbers."

But -13 is a negative number. Therefore -13 is not a whole number

Positive or negative, large or small, whole numbers or decimal numbers are all Real Numbers. They are called "Real Numbers" because they are not Imaginary Numbers.

Therefore -13 is a real number

An integer is a whole number (not a fractional number) that can be positive, negative, or zero. Examples of integers are: -5, 1, 5, 8, 97, and 3,043.

Therefore -13 is a integer

An irrational number is real number that cannot be expressed as a ratio of two integers. An irrational number is not able to be written as a simple fraction because the numbers in the decimal of a fraction would go on forever

But -13 can be expressed in fraction as [tex]-13 \div 1[/tex]

Therefore -13 is not a irrational number

Thus we can conclude that number -13 is classified as real and integer

Answer:

The cost of a 12 minute call to France is $ 3.63

Step-by-step explanation:

given:

The cost of 15 minute call to France = $ 4.29

The cost of 10 minute call to France   = $ 3.19

To Find :

The cost of a 12 minute call to France = ?

Solution:

Let the flat fee be X

and the cost per minute be Y

so the  15 minute call to France will be

X + 15(Y) = 4.29---------------------------(1)

the  10 minute call to France will be

X + 10(X) = 3.19----------------------------(2)

Subtracting (2) from (1)

X + 15(Y) = 4.29

X + 10(Y) = 3.19

-      -           -

---------------------------------

      5Y = 1.10

--------------------------------

[tex]Y =\frac{1.10}{5}[/tex]

Y = 0.22

So the cost per minute of a call = $0.22

substituting the values in (1)

X + 15(0.22) = 4.29

X + 3.3 = 4.29

X = 4.29 -3.3

X = 0.99

Now the cost of 12 minute call is

=>X + 12(Y)

=> 0.99 + 12(0.22)

=> 0.99 + 2.64

=> 3.63

Answer:

The money Rachael plan to collect for the shelter is $350.

Step-by-step explanation:

Given:

Rachel is collecting donations for the local animal shelter.

So far she has collected $245, which is 70% of what she hopes to collect.

Now, to find the money Rachael plan to collect for the shelter.

Let the total amount Rachael plan to collect be [tex]x[/tex].

Amount she collected = $245.

Percentage of amount she collected = 70%.

Now, to get the amount Rachael plan to collect we put an equation:

[tex]70\%\ of\ x=\$245.[/tex]

⇒ [tex]\frac{70}{100} \times x=245[/tex]

⇒ [tex]0.70\times x=245[/tex]

⇒ [tex]0.70x=245[/tex]

Dividing both sides by 0.70 we get:

⇒ [tex]x=\$350.[/tex]

Therefore, the money Rachael plan to collect for the shelter is $350.

Answer:

Domain: set of all real numbers; (-∞, ∞)

Range : {y | y f > 2}

Check the attached figure to visualize the graph.

Step-by-step explanation:

The graph of the given function is attached. Please check the attached figure.

As the function is given as:

                                              [tex]f(x) = (\frac{1}{3})^{x} +2[/tex]

As the table of some of the values of x and y values for [tex]f(x) = (\frac{1}{3})^{x} +2[/tex] is given as follows:

               -2                    11

                -1                    5

                 0                   3

                 1                   2.33

                  2                  2.111

Hence, it is clear that the function is defined for every input value of x. So, domain is the set of all real numbers.

Domain: set of all real numbers; (-∞, ∞)

If we carefully analyze the graph of this function, it is clear that no matter what input value of x we put, range or y-value of this function would always be be greater than 2. Check the attached graph figure to better visualize the range of the function.

Range can also be denoted as: Range : {y | y f > 2}

Keywords: graph, function, domain and range

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The points after Dilation are (0,0), (9,-3), and (9,9).

Step-by-step explanation:

The given points are A(0,0), B(3,-1), and C(3,3).

The scale factor is 3.

[tex]D_{new}[/tex]([tex]p_{x} , p_{y}[/tex]) = scale factor × ([tex]p_{x} , p_{y}[/tex]) .

If the triangle starts form the origin (0,0) retains the same after the dilation.

[tex]D_{Anew}(p_{x} , p_{y})[/tex]= (0,0).

For point B(-1,3),

[tex]D_{Bnew}(p_{x} , p_{y})[/tex] = 3 × (3,-1).

[tex]D_{Bnew}(p_{x} , p_{y})[/tex] = (9,-3).

For Point C(3,3),

[tex]D_{Cnew}(p_{x} , p_{y})[/tex] =  3 × ( 3,3).

[tex]D_{Cnew}(p_{x} , p_{y})[/tex] = ( 9,9).

Refer the graph for dilated triangle.

Answer:

  -1/2

Step-by-step explanation:

Slope is calculated as ...

   (change in y)/(change in x) = (y2 -y1)/(x2 -x1)

   = (-4 -1)/(0 -(-10)) = -5/10 = -1/2

The slope of the line is -1/2.

Answer:

  1000

Step-by-step explanation:

Each value of the first digit can be paired with any value of the second digit, so there are 10×10 = 100 possible pairs of the first two digits. Each of those can be combined with any third digit to give a total of ...

  10×10×10 = 1000

possible combinations.

Final answer:

A combination lock with a 3-digit code where each digit can be 0-9 allows for 1000 different combinations, as calculated by 10 x 10 x 10, which equals 10³ or 1000.

Explanation:

The question asks how many different 3-digit combinations are possible with a combination lock where each digit can range from 0-9. Each digit of the code is independent and can take any of the ten possible values (0-9), leading to a total combination of possibilities calculated by multiplying the number of choices for each digit position. Given that there are three digit positions and each can be any of the ten digits, the calculation is as follows:

10 (choices for first digit) × 10 (choices for second digit) × 10 (choices for third digit) = 10³

Therefore, there are 1000 different possible combinations for the lock, ranging from 000 to 999.

Question is Incomplete, Complete question is given below:

In Triangle ABC shown below, side AB is 6 and side AC is 4.

Which statement is needed to prove that segment DE is parallel to segment BC and half its length?

Answer

Segment AD is 3 and segment AE is 2.

Segment AD is 3 and segment AE is 4.

Segment AD is 12 and segment AE is 4.

Segment AD is 12 and segment AE is 8.

Answer:

Segment AD is 3 and segment AE is 2.

Step-by-step explanation:

Given:

side AB = 6

side AC = 4

Now we need to prove  that segment DE is parallel to segment BC and half its length.

Solution:

Now AD + DB = AB also AE + EC = AC

DB = AB - AD also EC = AC - AE

Now we take first option Segment AD is 3 and segment AE is 2.

Substituting we get;

DB = 6-3 = 3 also EC = 4-2 =2

From above we can say that;

AD = DB and EC = AE

So we can say that segment DE bisects Segment AB and AC equally.

Hence From Midpoint theorem which states that;

"The line segment connecting the midpoints of two sides of a triangle is parallel to the third side and is congruent to one half of the third side."

Hence Proved.

Answer:

Step-by-step explanation:

let length=x

width=y

area A=xy

[tex]\frac{dA}{dt}=x\frac{dy}{dt}+y\frac{dx}{dt}\\ \frac{dx}{dt}=0.5 ~cm/sec\\\frac{dy}{dt}=-0.5~cm/sec\\\frac{dA}{dt}=10*(-0.5)+7(0.5)=-5+3.5=-1.5[/tex]

area is decreasing at the rate of 1.5 cm^2/sec

The rate of change in the area of the rectangle when the length is 10 cm and the width is 7 cm, with their rates of change being 0.5 cm/sec and -0.5 cm/sec respectively, is -1.5 cm²/sec.

To determine the rate of change in the area of a rectangle where the length is increasing at 0.5 cm/sec and the width is decreasing at 0.5 cm/sec, we can use the concept of derivatives from calculus.

Let L be the length and W be the width of the rectangle. The area A of the rectangle is given by A = L * W. Given that the length is increasing at 0.5 cm/sec (dL/dt = 0.5 cm/sec) and the width is decreasing at 0.5 cm/sec (dW/dt = -0.5 cm/sec) the rate of change of the area with respect to time can be found using the product rule for derivatives: dA/dt = (dL/dt) * W + L * (dW/dt).

At the moment when the length L is 10 cm and the width W is 7 cm, we can plug these values into the formula: dA/dt = (0.5 cm/sec) * 7 cm + 10 cm * (-0.5 cm/sec). This simplifies to dA/dt = 3.5 cm2/sec - 5 cm2/sec, giving us the rate of change in the area as dA/dt = -1.5 cm2/sec.

Answer: Option 'B' is correct.

Step-by-step explanation:

Since we have given that

90 students represent x percent of the boys at Jones Elementary School.

So, it is expressed as

[tex]90=\dfrac{x}{100}[/tex]

If the boys at Jones Elementary make up 40% of the total school population of x students,

[tex]90=\dfrac{x}{100}\times 0.4x\\\\9000=0.4x^2\\\\\dfrac{9000}{0.4}=x^2\\\\22500=x^2\\\\x=\sqrt{22500}\\\\x=150[/tex]

Hence, the value of x is 150.

Therefore, Option 'B' is correct.