A ray of light in air is incident upon a glass plate at an angle of 45°. The angle of refraction of the ray in the glass is 30°. What is the index of refraction of the glass?

Answer:

E

Explanation:

Let the total capacity of the pool be x

Let the initial volume of water in the pool be y

then;

300 + y =80% of x

300 + y = (80/100) * x

300 + y = 0.8x   ...........................equation 1

300 gallons of water increased the volume by 30x

y +300 = y +30% of y

300 = 0.3y

y=  (300/0.3)

y= 1000

substitute y into equation 1 to get x

300 + y = 0.8x

300 + 1000 = 0.8x

1300 =0.8x

x= (1300/0.8)

x= 1625 gallons

Answer:a) Water is relatively resistant to an increase in temperature

Explanation:

Water has relatively high heat capacity i.e. it requires high amount of heat to raise a little increase in temperature.

Heat capacity is defined as ability of molecule to absorb heat . Mathematically heat capacity is defined as

[tex]C=\frac{Q}{\Delta T}[/tex]

where [tex]C=heat\ capacity[/tex]

[tex]Q=heat\ interaction[/tex]

[tex]\Delta T=change\ in\ Temperature[/tex]

Answer:

Adenosine Triphosphate - Phosphocreatine (ATP-PC)

Explanation:

The name ATP-PC in full means Adenosine Triphosphate - Phosphocreatine (ATP-PC). ATP-PC system is made up Adenosine Triphosphate (ATP) and  Phosphocreatine (PC). This system is otherwise known as the Phosphogen system. Energy coming from the breakdown of the ATP stores within the muscles supplies energy during the first few seconds of any activity after which the breakdown of PC provides energy for another 5-8 seconds of the activity until another energy is required. ATP-PC system is not oxygenated and it is and instant energy which allows ±12 seconds of maximum effort approximately.  Examples of activities where ATP-PC is used: a short sprint, pitching a baseball or lifting a heavy weight.

Answer:

I = 2.33 µA

Explanation:

given,

Effective resistance (R)= 300 Ω

Voltage of signal (V)= 700 µV

current flow in the antenna = ?

Using ohm's law

V = I R

where I is the current flow

[tex]I = \dfrac{V}{R}[/tex]

[tex]I = \dfrac{700\times 10^{-6}}{300}[/tex]

      I = 2.33 x 10⁻⁶ A

      I = 2.33 µA

Hence, the current flow in the antenna downloaded is equal to I = 2.33 µA

Answer:I = 2.33 µA

Explanation:

Answer:

Yes the frequency of the angular simple harmonic motion (SHM) of the balance wheel increases three times if the dimensions of the balance wheel reduced to one-third of original dimensions.

Explanation:

Considering the complete question attached in figure below.

Time period for balance wheel is:

[tex]T=2\pi\sqrt{\frac{I}{K}}[/tex]

[tex]I=mR^{2}[/tex]

m = mass of balance wheel

R = radius of balance wheel.

Angular frequency is related to Time period as:

[tex]\omega=\frac{2\pi}{T}\\\omega=\sqrt{\frac{K}{I}} \\\omega=\sqrt{\frac{K}{mR^{2}}[/tex]

As dimensions of new balance wheel are one-third of their original values

[tex]R_{new}=\frac{R}{3}[/tex]

[tex]\omega_{new}=\sqrt{\frac{K}{mR_{new}^{2}}}\\\\\omega_{new}=\sqrt{\frac{K}{m(\frac{R}{3})^{2}}}\\\\\omega_{new}={3}\sqrt{\frac{K}{mR^{2}}}\\\\\omega_{new}={3}\omega[/tex]

The recoil speed of the nucleus in the beta decay process is gotten as; 1354.27 m/s

From principle of conservation of momentum, we will have;

Recoil momentum of nucleus = Recoil momentum of emitted particle

We are given;

Mass of electron; m_e = 9.11 × 10⁻³¹ kg

speed of electron; v_e = 3.4 × 10⁷ m/s

Momentum of electron; P = 6.7 × 10⁻²⁴ kg.m/s

Thus;

Momentum of electron ignoring relativistic effect is;

P_f = m_e * v_e

P_f = 9.11 × 10⁻³¹ × 3.4 × 10⁷

P_f = 3.0974 × 10⁻²³ kg.m/s

Resultant momentum is gotten from;

R = √[(3.0974 × 10⁻²³)² + (6.7 × 10⁻²⁴)²]

R = 3.169 × 10⁻²³ kg.m/s

The formula for the recoil speed of the nucleus is;

v = R/m_n

where m_n is mass of neutrino = 2.34 × 10⁻²⁶ kg

v = (3.169 × 10⁻²³)/(2.34 × 10⁻²⁶)

v = 1354.27 m/s

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Final answer:

The recoil speed of the carbon nucleus after beta decay can be determined using the conservation of momentum and is found to be approximately 1381 m/s.

Explanation:

The recoil speed of the nucleus can be calculated using the principle of conservation of momentum, which states that the total momentum of a closed system is constant if no external forces are acting on it. In this case of beta decay, the initial momentum of the stationary carbon nucleus is zero. After decay, the sum of momenta of the electron, neutrino, and recoiling nucleus must also be zero, as momentum is conserved.

The momentum of the electron is given by its mass times its velocity (pe = me x ve), and the momentum of the neutrino is given (pν = 6.70 x 10-24 kg·m/s). The nucleus will recoil with momentum equal in magnitude but opposite in direction to the vector sum of the electron and neutrino momenta. Given that the electron and neutrino are emitted at right angles, we can use the Pythagorean theorem to find the magnitude of the resultant momentum that the nucleus must have:

Following through the calculations:

Therefore, the recoil speed of the nucleus is approximately 1381 m/s.

Answer:

132.70kg

Explanation:

Given:

Temperature of copper block = 55°C

Temperature of water = 22°C

Mass of copper block, m₁ = ?

Mass of water, m₂ = 55 mL = 5.5 × 10⁻⁵m³

                Density of water [tex]= \frac{mass}{volume}[/tex]

                                   m₂  = Density of water × volume

                                   m₂ = 1000kg/m³ × (5.5 × 10⁻⁵m³)

                                   m₂ = 0.055 kg

                                    m₂ = 55g

Quantity of heat lost by the copper block = m₁cΔT

                                            = m₁ × 0.385 × (55 - 28)

                                            = m₁ × 0.385 × 27

                                            = 10.395 × m₁  J

Quantity of heat gained by the water = m₂cΔT

                                           = 55 × 4.18 × (28-22)

                                           = 55 × 4.18 × 6

                                           = 1379.4 J

Heat lost by copper block = Heat gained by water

                              10.395m₁ = 1379.4

                                [tex]m_{1} =\frac{1379.4}{10.395}[/tex]  

                                   m₁ = 132.6984kg

                                   m₁ = 132.70kg

The mass of the copper block is 132.70kg

Answer: Mass remains the same and weight decrease

Explanation: mass is always constant but weight varies. Weight is affected by height. The higher you go the lesser your weight because you are moving away from gravity

The magnitude of the magnetic field in the given scenario is zero.

The magnitude and direction of the magnetic field can be determined by analyzing the force experienced by the positively charged particle q as it moves in the positive x direction and encounters an electric field in the positive y direction. The force experienced by the particle, due to the Lorentz force law, is given by:

F = qvB sin

Where F is the force, q is the charge, v is the velocity, B is the magnetic field, and θ is the angle between the velocity and the magnetic field. Since the velocity of the particle remains unchanged, the force experienced by the particle in the y direction must be zero. This means that the angle θ between the velocity and the magnetic field must be 90 degrees. Therefore, sin θ = 1. Substituting these values into the equation, we get

0 = qv0

Solving for B, we find that

B = 0

Therefore, the magnitude of the magnetic field in this scenario is zero.

Answer:

[tex]v=\frac{28\pi R}{\sqrt{2} }[/tex] m/sec

Explanation:

According to the question

[tex]\frac{1}{2}I\omega^2=\frac{1}{2} mv^2[/tex]

\omega= angular velocity = 14 spins per sec

I= MOI of the spinning eel= 0.5mR^2

m= mass of eel

v= linear velocity of eel.

[tex]\frac{1}{2}0.5mR^2\omega^2=\frac{1}{2} mv^2[/tex]

solving for v in the above equation we get

[tex]v=\sqrt{\frac{R^2\omega^2}{2} }[/tex]

now \omega in radians = 14 rev/sec×2π  radian/rev= 28π radian/sec

value of radius is not provided in the question

therefore we get

[tex]v=\frac{28\pi R}{\sqrt{2} }[/tex]

Answer:

Explanation:

when we get out of the water we feel quite cold due to the latent heat of evaporation of water.

Water at our body gets converted into gas and leaves behind the cooling effect which makes us feel cold.

While when we are inside the pool we are in constant touch of water, therefore, we get the warmth of the water and it becomes difficult to bear it.

Explanation:

Here mechanical energy is conserved.

Kinetic energy + Potential energy = Constant.

First the child does 5.0 J of work on a spring while loading a ball into a spring-loaded toy gun.

      That is potential energy = 5 J

      Kinetic energy = 0 J

      Kinetic energy + Potential energy = 0 + 5 = 5 J  

Secondly the spring is released.

      That is potential energy = 0 J

      Kinetic energy = ?

      Kinetic energy + Potential energy = Constant = 5 J

      Kinetic energy + 0  = 5 J

      Kinetic energy is 5 J

Option D is the correct answer.

The kinetic energy of the ball when it leaves the spring-loaded toy gun is 5.0 J. This is because the work done on the spring is entirely converted into the kinetic energy of the ball, according to the law of conservation of energy.

The subject of this question is based on the conservation of mechanical energy, which is a principle of physics. The principle states that the total mechanical energy in a closed system—meaning one that does not have any external forces, like air resistance, acting on it—remains constant. In this case, the child does 5.0 J of work on the toy gun's spring. This work is converted into potential energy that is stored in the compressed spring.

When the spring launches the ball, the potential energy of the spring is then converted into the kinetic energy of the ball, as there's no friction or air resistance to cause energy loss. So, according to the law of conservation of energy, all of the initial energy (5.0 J) used to compress the spring will be transferred to the ball as kinetic energy. Therefore, the kinetic energy of the ball as it leaves the gun is 5.0 J (Option D).

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Answer:

B. Once diverted to the alternate airport,you may fly a GPS-based approach as long as there is an operational ground-based NAVAID and appropriate airborne receiver for use as a backup.

Explanation:

As stated in the question, If someone is on-board GPS-based FMS/RNAV unit, and the destination is the minimum target, it is obvious that once diverted to the alternate airport,you may fly a GPS-based approach as long as there is an operational ground-based NAVAID and appropriate airborne receiver for use as a backup. The correct answer is option B.

GPS-based FMS/RNAV units can be used for approach procedures at the alternate airport, as long as there is a ground-based NAVAID and an appropriate airborne receiver available.

The subject of this question is Computers and Technology. The question is about the requirements for using a GPS-based FMS/RNAV unit for approach procedures.

The correct answer is B. Once diverted to the alternate airport, you may fly a GPS-based approach as long as there is an operational ground-based NAVAID and appropriate airborne receiver for use as a backup.

Therefore, as long as there is a ground-based NAVAID available and an appropriate backup receiver, you can use the GPS-based approach at the alternate airport.

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Answer:

Complete Question:

A company has two AWS accounts, each containing one VPC. The first VPC has a VPN connection with its corporate network. The second VPC, without a VPN, hosts an Amazon Aurora database cluster in private subnets. Developers manage the Aurora database from a bastion host in a public subnet as shown in the image.

A security review has flagged this architecture as vulnerable, and a Security Engineer has been asked to make this design more secure. The company has a short deadline and a second VPN connection to the Aurora account is not possible.

How can a Security Engineer securely set up the bastion host?

A. Move the bastion host to the VPC and VPN connectivity. Create a VPC peering relationship between the bastion host VPC and Aurora VPC.

B. Create a SSH port forwarding tunnel on the Developer's workstation to the bastion host to ensure that only authorized SSH clients can access the bastion host.

C. Move the bastion host to the VPC with VPN connectivity. Create a cross-account trust relationship between the bastion VPC and Aurora VPC, and update the Aurora security group for the relationship.

D. Create an AWS Direct Connect connection between the corporate network and the Aurora account, and adjust the Aurora security group for this connection.

Answer:

B. Create an SSH port forwarding tunnel on the Developer's workstation to the bastion host to ensure that only authorized SSH clients can access the bastion host.

Explanation:

To gain a better understanding of why the option selected in the answer to the question let first explain some terms.

AWS:

According to techtarget,

AWS (Amazon Web Services) is a comprehensive, evolving cloud computing platform provided by Amazon that includes a mixture of (1) infrastructure as a service (IaaS),(2) platform as a service (PaaS) and (3)packaged software as a service (SaaS) offerings.

An AWS account is a container for your AWS resources

A bastion host is a server whose purpose is to provide access to a private network from an external network, such as the Internet. Because of its exposure to potential attacks, a bastion host must minimize the chances of penetration to the private network.

SSH port forwarding, or TCP/IP connection tunneling, is a process whereby a TCP/IP connection that would otherwise be insecure is tunneled through a secure SSH(Secure Shell (SSH) is a cryptographic network protocol for operating network services securely over an unsecured network.) link, thus protecting the tunneled connection from network attacks.

So the Bastion protects the private network while the SSH prevent unauthorized access to the bastion

To securely set up the bastion host, it should be moved to the VPC with VPN connectivity. Subsequently, a cross-account trust relationship should be created between the bastion VPC and Aurora VPC, followed by updating the Aurora security group.

Considering the context and options given, one of the best ways to securely set up the bastion host is to follow the path described in Option C. This involves moving the bastion host to the VPC (Virtual Private Cloud) with VPN (Virtual Private Network) connectivity. Subsequently, create a cross-account trust relationship between the bastion VPC and Aurora VPC. Once this relationship is established, proceed by updating the Aurora security group for the relationship.

This setup aids in restricting access to only trusted entities and thus fortifies security. An important point to note is that the assurance of security provided by this method is largely based on proper configuration and stringent maintenance of the trust relationship and security groups.

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Answer:

.D.It will decrease because the charge will move in the direction of the electric field

Explanation:

which there is a uniform electric field. (A uniform field is one whose strength and direction are the same at all points within the region.) What happens to the electric potential energy of the positive charge, after the charge is released from rest in the uniform electric field?A. It will remain constant because the electric field is uniform.B.It will decrease because the charge will move in the opposite direction of the electric field.C.It will remain constant because the charge remains at rest.D.It will decrease because the charge will move in the direction of the electric field.E.It will increase because the charge will move in the direction of the electric field.

solution

The potential energy decreases, converted to kinetic energy

The charge will feel a force in the direction of the electric field (F=Eq) and thus it will accelerate with

a constant acceleration. (Just like releasing an object above the earth's surface - constant acceleration,

at least until it hits something.)

tus te answer will be

.D.It will decrease because the charge will move in the direction of the electric field

Answer:

Force of the ball against the bat

Explanation:

Newton's third law of motion states that for every action, there is an equal and opposite reaction. When a player hits a ball with a bat, the force the player exerted on the ball through the bat gave the ball a push force in the forward direction. This is an action force. Now that an action has been initiated, there must be a reaction according to Newton's third law of motion. The magnitude of the force on the ball equals the magnitude of the force on the bat. The direction of the force on the ball is opposite to the direction of the force on the ball. The ball will give the bat an equal and opposite force trying to push the bat backward by resisting the impact of the bat. This is the reaction. The ball will only move if the applied force is able to overcome the resisting force by the bat.

                             [tex]F_{A} = - F_{B}[/tex]

Where;

[tex]F_{A}[/tex] is the action force of the bat against the ball.

[tex]F_{B}[/tex] is the equal and opposite reaction force of the ball towards the ball.

If a player hit a ball with a bat the ore that which the ball is coming towards the player and the force with which the player is moving the bat will impact the ball which will have an equal and opposite reaction.

Hence the newtons law of motion will be applied.

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Answer:

approximately toward the golfer's feet

Explanation:

The golf club experiences two accelerations. when the club is horizontal, centripetal acceleration acts on it toward the center parallel to the ground. The tangential acceleration acts towards the ground in downward direction. So when the golf club is horizontal, the acceleration vector is given by the combination of tangential and centripetal acceleration. the acceleration vector thus points  in between horizontal and vertical direction . hence towards the golfer's feet.

Answer:

approximately toward the golfer's feet

Explanation:

The club head undergoes circular motion so it has a centripetal acceleration. As the speed of the club head is increasing, it also has an acceleration component pointed vertically down. Thus, the acceleration vector is pointed as described in (c)

Answer:

Diode is reverse biased when its negative us connected with positive terminal and positive is connected with negative terminal

Explanation:

A diode is reverse biased when the positive side of the diode is connected with the negative terminal of the voltage source

And negative side of he diode is connected with positive terminal of the diode

When diode is reverse bias there is no flow of current, as it makes barrier to the flow of current

A diode is reverse biased when the cathode is connected to the negative side and the anode to the positive side of the voltage source, preventing current flow by widening the depletion layer.

A diode is reverse biased when the cathode is connected to the negative side of the external voltage source and the anode is connected to the positive side. In this configuration, the depletion layer at the p-n junction within the diode becomes wider, which increases its resistance and allows very little to no current to flow through. This is because the electrons in the n-type material and holes in the p-type material move away from the junction, reinforcing the built-in potential barrier. Therefore, in reverse bias, the diode blocks current flow rather than allowing it.

In contrast, when the diode is forward biased, the anode is connected to the positive side and the cathode to the negative side, allowing current to flow easily through the diode. This is because the positive voltage applied to the p-type material and the negative voltage on the n-type material cause the depletion layer to narrow and the potential barrier to decrease, enabling charge carriers to flow across the junction.

Answer:

A) 130N

Explanation:

We know that:

[tex]E_i -E_f = W_f[/tex]

where [tex]E_i[/tex] is the initial energy, [tex]E_f[/tex] is the final energy and [tex]W_f[/tex] is the work of the friction force.

so:

[tex]\frac{1}{2}MV_i^2 -\frac{1}{2}MV_f^2 = Fd[/tex]

where M is the mass, [tex]V_i[/tex] is the initial velocity,  [tex]V_f[/tex] is the final velocity, F the force and d the distance.

Replacing values, we get:

[tex]\frac{1}{2}(0.028)(55m/s)^2 -\frac{1}{2}(0.028)(18m/s)^2 = F(0.3m)[/tex]

solving for F:

F= 126N

the closest answer is A. 130 N

The main cause of accidents related to vehicles is rash driving, inexperienced drivers, and bad driving manners. Lack of awareness regarding the driving methods.

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The blind spot behind a vehicle is a common cause of collisions while driving. Safety measures like properly adjusted mirrors and checking over the shoulder before changing lanes can help. Cars with lighter plastic components crumple upon collision, increasing collision time and reducing the force exerted on occupants for increased safety.

The blind spot behind a vehicle is one of the most common causes of collisions while driving. This pertains to the area of the road that cannot be directly seen by the driver while looking forward or through either the rear-view or side mirrors. The risk of such collisions can be minimized by proper adjustment of mirrors, use of blind spot mirrors, and always checking over one's shoulder before making a lane change.

Upon collision, cars with lighter weight are able to offer better protection to their occupants due to longer collision time, because of their plastic components. The crumpling of the car in an event of a collision or the deployment of dashboard padding and airbags increases the collision time and hence, the force exerted on the occupants to bring them to a stop is significantly less. Modern automobiles use this physics principle to enhance safety during collisions.

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Explanation:

The transmission stimulates  shifts at higher rotation per minutes and providing stepped acceleration at with linear acceleration feel.

D-Step Logic Control is found in other Nissan CVT equipped models such as 2020 Altima, 2020 Pathfinder, 2020 Murano and the sporty 2020 Maxima.

Answer:

L = W = 26 ft.

Explanation:

Let the length of the garden is L and the width is W.

area of garden , A = L x W

675 = L x W ... (1)

Costing is minimum when the perimeter is minimum.

Perimeter, P = 2 ( L + W)

[tex]P=2\left ( L+\frac{675}{L} \right )[/tex]

For maxima and minima, differentiate perimeter with respect to L.

[tex]\frac{dP}{dL}=2\left ( 1-\frac{675}{L^{2}} \right )[/tex]

It should be zero for maxima and minima

L² = 675

L = 26 ft

W = 675/26 = 26 ft

Now, [tex]\frac{d^{2}P}{dL^{2}}=4\frac{675}{L^{3}}[/tex]

It is positive, so the costing is minimum.

So, length and width of the garden is 26 ft.

Answer:

a) 29.55 sec

Explanation:

Let the total distance be s feet.

Speed while walking = s/44 ft/sec.

Speed on sidewalk = s/90 ft/sec.

Total speed while walking on moving sidewalk

= s/44+s/90 = (90s+44s)/44×90

=(134x)/3960 ft/sec

= x/29.55 ft per sec.

Hence your travel time will be 29.55 secs.

Answer:

The muzzle velocity of this cork is 2 m/s.                                

Explanation:

It is given that,

Spring constant of the spring, k = 10 N/m

Mass of the cork, m = 6 g = 0.006 kg

Initial position of the spring, x = 5 cm = 0.05 m

Final position of the spring, x' = 1 cm = 0.01 m

According to the law of conservation of energy, the initial potential energy of the spring is equal to the sum of final spring potential energy and the kinetic energy of cork such that,

[tex]\dfrac{1}{2}kx^2=\dfrac{1}{2}kx'^2+\dfrac{1}{2}mv^2[/tex]

v is the muzzle velocity of this cork.

[tex]kx^2=kx'^2+mv^2[/tex]      

[tex]v=\sqrt{\dfrac{k(x^2-x'^2)}{m}}[/tex]

[tex]v=\sqrt{\dfrac{10\times ((0.05)^2-(0.01)^2)}{0.006}}[/tex]

v = 2 m/s

So, the muzzle velocity of this cork is 2 m/s. Hence, this is the required solution.

Answer:

2 m/s

Explanation:

Spring constant, k = 10 N/m

Mass of the cork, m = 6 g = 0.006 kg

Initial position of the spring, x = 5 cm = 0.05 m

Final position of the spring, x' = 1 cm = 0.01 m

Let v be the muzzle speed of the cork.

According to the law of conservation of energy,

Initial potential energy = final potential energy + kinetic energy

0.5 x 10 x 0.05 x 0.05 = 0.5 x 10 x 0.01 x 0.01 + 0.5 x 0.006 x v²

0.0125 = 0.0005 + 0.003v²

v = 2 m/s

Thus, the muzzle speed of the cork is 2 m/s.

Answer:

Later high school years and freshman year of college

Explanation:

The transition from high school to college is an important developmental milestone that holds the potential for personal growth and behavioral change.  A cohort of 2,025 students was recruited during the summer before they matriculated into college and completed Internet-based surveys about their participation in a variety of behavioral risks during the last three months of high school and throughout the first year of college. Alcohol use, marijuana use, and sex with multiple partners increased during the transition from high school to college, whereas driving after drinking, aggression, and property crimes decreased. Those from rural high schools and those who elected to live in private dormitories in college were at highest risk for heavy drinking and driving after drinking.

Answer:61.72 kg

Explanation:

Given

Length of rope [tex]L=10 m[/tex]

Speed at bottom of swing [tex]v=8 m/s[/tex]

Breaking strength of string [tex]T=1000 N[/tex]

At bottom Point

weight is acting downward and Tension is opposing it

Thus [tex]T-mg=\frac{mv^2}{L}[/tex]

[tex]T=mg+\frac{mv^2}{L}[/tex]

[tex]1000=m(9.8+\frac{8^2}{10})[/tex]

[tex]1000=m\cdot 16.2[/tex]

[tex]m=61.72 kg[/tex]

maximum mass Tarzan can have is [tex]61.72 kg[/tex]

The  largest mass that Tarzan can have and still make it safely across the river is of 61.72 kg.

Given data:

The length of rope is, L = 10 m.

Speed at the bottom of swing is, v = 8 m/s.

Breaking strength of string is, T = 1000 N.

At the bottom point, the weight is acting downward and tension force on the string is acting upward. So, the balanced equilibrium condition is,

[tex]T - mg =\dfrac{mv^{2}}{L} \\\\T =mg+\dfrac{mv^{2}}{L} \\\\T =m(g+\dfrac{v^{2}}{L})\\\\1000 =m\times(9.8+\dfrac{8^{2}}{10})\\\\m=61.72 \;\rm kg[/tex]

Thus, we can conclude that the largest mass that Tarzan can have and still make it safely across the river is of 61.72 kg.

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Answer:

0.0195 m

Explanation:

[tex]\rho _{p}[/tex] = density of hockey puck = 9.45 gcm⁻³ = 9450 kgm³

[tex]d_{p}[/tex] = diameter of hockey puck = 13 cm = 0.13 m

[tex]h_{p}[/tex] = height of hockey puck = 2.8 cm = 0.028 m

[tex]\rho _{m}[/tex] = density of mercury = 13.6 gcm⁻³ = 13600 kgm³

[tex]d[/tex] = depth of puck below surface of mercury

According to Archimedes principle, the weight of puck is balanced by the weight of mercury displaced by puck

Weight of mercury displaced = Weight of puck

[tex]\rho _{m} (0.25)(\pi d_{p}^{2} d ) g = \rho _{p} (0.25)(\pi d_{p}^{2} h_{p} ) g\\\rho _{m} ( d ) = \rho _{p} ( h_{p} )\\(13600) d = (9450) (0.028)\\d = 0.0195 m[/tex]

The original frequency of the violin was 508 Hz. This is based on the principle of beats, where the beat frequency is the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.

The original frequency of the violin string can be found using the principle of beats. The frequency of the beats is equal to the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.

Initially, the beat frequency was heard as 4 Hz. This indicates that the original frequency of the violin was either 512 Hz + 4 Hz = 516 Hz, or 512 Hz - 4 Hz = 508 Hz. However, when the violin string was tightened, the beat frequency decreased to 2 Hz, which means the frequency of the note it was producing increased.

Therefore, the violin must have initially been producing a note with lower frequency (508 Hz), and even after tightening the string, the note it now produces (510 Hz) remains lower than that of the tuning fork.

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Answer:Stop

Explanation:

To avoid accident even thought you in the right

Answer:

Explanation:

Given

Jacques weight is W and is at  distance of L to the left

Gilles weight is [tex]\omega [/tex] and should be Placed at right at a distance of [tex]L_1[/tex] from pivot

Distance should be such that the torque of Jacques and Gilles is same in magnitude but opposite in direction.

[tex]W\times L-\omega \times L_1=0[/tex]

such that net torque is zero.

[tex]L_1=\frac{W}{\omega }\times L[/tex]  

To balance the seesaw, the product of the weight of Jacques and the distance he is sitting from the pivot must be equal to the product of the weight of Gilles and the distance he should sit from the pivot.

To balance the seesaw, the product of the weight of Jacques and the distance he is sitting from the pivot must be equal to the product of the weight of Gilles and the distance he should sit from the pivot.

So, we can write the equation as:

W * L = w * L₁

To find L₁, we can rearrange the equation:

L₁ = (W * L) / w

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