A point on a coordinate plane is located 3 units to the right of the origin and 7 units above the origin. What are the coordinates of this point? Use the drop-down menus to enter the coordinates below.

The coordinates of the point are
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For the first image, the median range would be 88. In order to find the median, you'll place all your numbers in numerical order (smallest to largest). If there are an odd amount of numbers, find the one directly in the middle. If there is an even amount, you'll take the two most central ones and find the mean, that will tell you the median. Therefore, B (88)  would be the answer to your first one.

The second one would be C (20.4). It's asking for the mean. In order to find the mean of a set of numbers, you'll simply add up all of the numbers and divide by how many numbers are in your number set. That gives you the mean.

Final Answer:

The maximum value of f(x) = xa(7 - x)b on the interval 0 ≤ x ≤ 7 occurs when x = 7/2 for a > 0 and b > 0.

Explanation:

To find the maximum value of f(x) on the interval 0 ≤ x ≤ 7, we'll use calculus. First, take the derivative of f(x) with respect to x.

f'(x) = a * (7 - x)^b * x^(a-1) - b * a * (7 - x)^(b-1) * x^a

Setting f'(x) = 0 to find critical points:

a * (7 - x)^b * x^(a-1) - b * a * (7 - x)^(b-1) * x^a = 0

Solving for x gives x = 7/2. To determine if this point is a maximum, minimum, or inflection point, we'll use the second derivative test.

f''(x) = a * (7 - x)^(b-1) * x^(a-2) * ((a - 1) * x - 7) - b * a * (7 - x)^(b-2) * x^(a-1) * ((b - 1) * x - 7)

When x = 7/2, f''(7/2) > 0, indicating a concave-up shape and confirming it as a local minimum. Therefore, the maximum value of f(x) occurs at the endpoints of the interval, x = 0 and x = 7, or potentially at x = 7/2 if it surpasses these values.

For a > 0 and b > 0, plugging in x = 7/2 into f(x) = xa(7 - x)b yields the maximum value of the function within the given interval.

Understanding the critical points through derivatives helps identify where the maximum or minimum points occur in the function. In this case, x = 7/2 stands as the point of maximum value within the interval 0 ≤ x ≤ 7 when a and b are both positive.

The probability of selecting 22 red balls is  [tex]\frac{^{44} C_{22} }{^{99} C_{22}}[/tex]

It is a branch of mathematics that deals with the occurrence of a random event.

Given,

A bag contains 44 red balls and 55 blue balls

The total number of balls=44+55=99

22 balls are selected at random from bag.

We need to find the probability of selecting 22 red balls.

The probability of selecting 22 red balls from 44 balls

[tex]^{44} C_{22}[/tex]

2,104,098,963,720

and [tex]^{99} C_{22}[/tex] is 5.7190121704386E+21

So probability of selecting 22 red balls is

[tex]\frac{^{44} C_{22} }{^{99} C_{22}}[/tex]

Hence, the probability of selecting 22 red balls is  [tex]\frac{^{44} C_{22} }{^{99} C_{22}}[/tex]

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Answer:

answer is 1440,ok

Step-by-step explanation:

We want to create a system of equations that allows us to find the values of two supplementary angles.

We will find that the larger angle measures 140° and the smaller one measures 40°.

------------------------

Two angles A and B are supplementary if their measures add up to 180°, so we have:

A + B = 180°.

Let's assume that B is the larger one, we also do know that:

"The larger is 20° less than 4 times the smaller"

Then we can write:

B = 4*A - 20°.

Then our system of equations is:

A + B = 180°.

B = 4*A - 20°.

To solve it we need to isolate one variable in one of the equations and replace it on the other equation. Here we can see that B is already isolated on the second equation, so we can replace it in the first one to get:

A + B = 180°.

A + (4*A - 20°) = 180°

Now we can solve this for A:

A + (4*A - 20°) = 180°

5*A - 20° = 180°

5*A = 180° + 20° = 200°

A = 200°/5 = 40°

Now that we know the value of A we can get the value of B:

B = 4*A - 20° = 4*40° - 20° = 140°

Then the larger angle measures 140° and the smaller measures 40°

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Answer:  The required probability of getting two green marbles is 49.45%.

Step-by-step explanation:  Given that a bag contains 10 green marbles and 4 yellow marbles. Two marbles are chosen at random, one at a time and without replacement.

We are to find the probability of getting two green marbles.

Let S denote the sample space for the experiment of choosing a marble from the bag and A denote the event of getting a green marble.

The, n(S) = 10 + 4 = 14   and   n(A) = 10.

So, the probability of event A will be

[tex]P(A)=\dfrac{n(A)}{n(S)}=\dfrac{10}{14}=\dfrac{5}{7}.[/tex]

After getting one green marble and not replacing, let S' denote the sample space for the experiment of choosing a marble from the bag

and

let B denote the event of getting another green marble.

Then, n(S') = 14 - 1 = 13    and    n(B) = 10 - 1 = 9.

Then, the probability of getting two green marbles is given by

[tex]P\\\\=P(A)\times P(B)\\\\=\dfrac{5}{7}\times\dfrac{n(B)}{n(S')}\\\\\\=\dfrac{5}{7}\times\dfrac{9}{13}\\\\\\=\dfrac{45}{91}\times100\%\\\\=49.45\%.[/tex]

Thus, the required probability of getting two marbles is 49.45%.

Answer:

a) [tex]4\left(3x+2\right)-2=12x+6[/tex]

b) [tex]20b-16= 4\left(5b-4\right)[/tex]

Step-by-step explanation:

a) To simplify the expression you must:

Expand [tex]4(3x + 2)[/tex]:

Apply the distributive law: [tex]\:a\left(b+c\right)=ab+ac[/tex]

[tex]a=4,\:b=3x,\:c=2\\\\4\left(3x+2\right)=4\cdot \:3x+4\cdot \:2[/tex]

Simplify [tex]4\cdot \:3x+4\cdot \:2= 12x+8[/tex]

[tex]12x+8-2[/tex]

Subtract the numbers: [tex]4\left(3x+2\right)-2=12x+6[/tex]

b) To factor the expression [tex]20b - 16[/tex] you must:

Rewrite 16 as [tex]4\cdot 4[/tex] and 20 as [tex]4\cdot 5[/tex]

[tex]20b-16=4\cdot \:5b-4\cdot \:4[/tex]

Factor out common term 4

[tex]20b-16= 4\left(5b-4\right)[/tex]

Answer:

4.5 hours

[tex]496 x= 558 x-279[/tex]

Step-by-step explanation:

We are given that two airplanes left the same airport and arrives at the same destination at the same time.

We have to find the number of hours taken by first plane to travel to the destination and find the equation that can be used to solve this problem

We are given that the first airplane left at 8:00 a.m

Let y be the distance traveled by the first airplane

The average rate of first airplane =496 miles per hour

The average rate of second airplane =558 miles per hour

Let x represents the number of hours that the first airplane traveled.

The number of hours that the second plane traveled =x-0.5

Because the second airplane take half an hour less than the first airplane

We know that [tex] distance=speed\times time [/tex]

[tex]d=496 x[/tex]

[tex]d=558(x-0.5)[/tex]

[tex]496 x= 558 x-279[/tex]

[tex]279=558 x-496 x[/tex]

[tex]279=62 x[/tex]

[tex]x=\frac{279}{62}[/tex]

x=4.5 hours

Hence, the first airplane takes 4.5 hours to travel to the destination.

I can tell you for sure that the answer to the first one is

C) 63,475

and the second is

A) 22,149

The attendance at the movie theater in seven years will be 63,476. Then option C is correct. And the number of customers that visit the business in 10 years will be 22,149. Then option A is correct.

Let a be the initial value and x be the power of the exponent function and b be the increasing factor.

The exponent is given as

y = a(b)ˣ

The yearly participation at a neighborhood movie theater is 42,000 and develops ceaselessly at a pace of 5.9% every year. Then the attendance at the movie theater in seven years will be given as,

[tex]\rm y = 42,000 \times (e)^{0.059\times 7}\\\\y = 42,000 \times (e)^{0.413}[/tex]

Simplify the equation further, then we have

y = 42,000 × 1.5113

y = 63,476

The quantity of clients that visit a neighborhood private venture is 29,600 and has been persistently declining at a pace of 2.9% every year.

Then the number of customers that visit the business in 10 years will be given as,

[tex]\rm y = 29,600\times (e)^{-0.029\times 10}\\\\y = 29,600 \times (e)^{-0.29}\\[/tex]

Simplify the equation further, then we have

y = 29,600 × 0.748

y = 22,149

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Answer:  The required sequence of transformations is

Transformation 1 : a rotation by 90 degrees in the counterclockwise direction about the origin, (x, y) ⇒  (-y, x).

Transformation 2 : a translation by 2 units right and 3 units down, (x, y) ⇒ (x+2, y-3).

Step-by-step explanation:  We are given to describe in words a sequence of transformations that maps ∆ABC to ∆A'B'C'.

From the figure, we note that

the co-ordinates of the vertices of triangle ABC are A(0, 4), B(0, 0) and C(2, 3).

And, the co-ordinates of the vertices of triangle A'B'C' are A'(-2, -3), B'(2, -3) and C'(-1, -1).

We see that if triangle ABC is rotated 90 degrees in anticlockwise direction about the origin, then its co-ordinates changes according to the following rule :

(x, y)  ⇒  (-y, x).

That is

A(0, 4)  ⇒  (-4, 0),

B(0, 0)   ⇒ (0, 0),

C(2, 3)    ⇒ (-3, 2).

Now, if the vertices of the rotated triangle are translated  2 units right and 3 units down, then

(x, y)  ⇒  (x+2, y-3).

That is, the final co-ordinates after rotation and translation will be

(-4, 0)  ⇒  (-4+2, 0-3) = (-2, -3),

(0, 0)   ⇒ (0+2, 0-3) = (2, -3),

(-3, 2)   ⇒ (-3+2, 2-3) = (-1, -1).

We see that the final co-ordinates are the co-ordinates of the vertices of triangle A'B'C'.

Thus, the required sequence of transformations is

Transformation 1 : a rotation by 90 degrees in the counterclockwise direction about the origin, (x, y) ⇒  (-y, x).

Transformation 2 : a translation by 2 units right and 3 units down, (x, y) ⇒ (x+2, y-3).

the answer would be 37