Answer: 94 cm
Explanation:
The answer is not among the given options, however it can be approximated to 94 cm.
Hooke's law establishes that the elongation of a spring is directly proportional to the modulus of the force [tex]F[/tex] applied to it, as long as the spring is not permanently deformed:
[tex]F=k (x-x_{o})[/tex] (1)
Where:
[tex]k[/tex] is the elastic constant of the spring
[tex]x_{o}[/tex] is the length of the spring without applying force.
[tex]x[/tex] is the length of the spring with the force applied.
According to this, we have a spring where only the force due gravity is applied. In other words, the force applied is the weigth [tex]W[/tex]:
[tex]W=m.g[/tex] (2)
So, equation (1) can be rewritten as:
[tex]W=k (\Delta x)[/tex] (3)
Isolating [tex]k[/tex]:
[tex]k=\frac{W}{\Delta x}[/tex] (4) From here we can deduce [tex]k[/tex] is the slope of the line of the graph shown, as follows:
[tex]k=\frac{m_{2}g-m_{1}g}{x-x_{o}}=g\frac{m_{2}-m_{1}}{x-x_{o}}[/tex]
Where:
[tex]m_{2}=400 g=0.4 kg[/tex]
[tex]m_{1}=200 g=0.2 kg[/tex]
[tex]g=9.8\frac{m}{s^{2}}[/tex] is the acceleration due gravity
[tex]x=15 cm=0.15 m[/tex]
[tex]x_{o}=7.5 cm=0.075 m[/tex]
[tex]k=9.8\frac{m}{s^{2}}\frac{0.4 kg-0.2 kg}{0.15 m-0.075 m}[/tex]
[tex]k=26.13 N/m[/tex] (5) This is the spring constant
Now, with the mass [tex]m=2.35 kg[/tex] we can calculate the weight:
[tex]W=m.g=(2.35 kg)(9.8\frac{m}{s^{2}})[/tex]
[tex]W=23.03 N[/tex] (6)
So, knowing [tex]k=26.13 N/m[/tex] and [tex]W=23.03 N[/tex] we can calculate [tex]\Delta x[/tex] from (3):
[tex]\Delta x=\frac{W}{k}[/tex] (7)
[tex]\Delta x=\frac{23.03 N}{26.13 N/m}[/tex] (8)
[tex]\Delta x=0.88 m=88.13 cm[/tex] (9)
The value that is nearest to 88.13 cm is 94 cm
The question is about determining how much a spring would stretch under a certain weight, based on Hooke's law. Without the spring constant or the graph data, it is impossible to provide the exact value. Nonetheless, it is crucial to acknowledge that the stretch (x) can be calculated from the formula of Hooke’s law (F=kx) substituting force (F) with mass times gravity (mg).
Explanation:This problem is based on Hooke’s law, which is a principle in physics that states that the force needed to extend or compress a spring by a certain distance scales linearly with respect to that distance. The law is usually formulated as F = kx, where F is the force applied, x is the displacement of the spring (how much it is stretched), and k is the spring constant.
In this case, you want to find x (the stretch of the spring) when a certain mass (m) is hung from the spring. According to Newton’s second law, F = ma, where a is the acceleration due to gravity. However, in this context, F can also be thought of as the weight of the mass, which is mg. So, F = mg. Therefore, mg = kx.
Unfortunately, without knowing the value of the spring constant (k), or having the actual data from the graph, it is not possible to calculate how much the spring would stretch when a 2.35 kg mass is hung from it.
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A spaceship hovering over the surface of Venus drops an object from a height of 17 m. How much longer does it take to reach the surface than if dropped from the same height on Earth? Neglect air resistance in both cases.
Explanation:
It is given that,
A spaceship hovering over the surface of Venus drops an object from a height of 17 m, h = 17 m
Acceleration due to gravity on the surface of Venus, [tex]g'=8.87\ m/s^2[/tex]
The second equation of motion is given by :
[tex]s=ut+\dfrac{1}{2}gt^2[/tex], u = 0
[tex]s=\dfrac{1}{2}gt^2[/tex]
[tex]t=\sqrt{\dfrac{2s}{g'}}[/tex]
[tex]t=\sqrt{\dfrac{2\times 17}{8.87}}[/tex]
t' = 1.95 s..............(1)
Acceleration due to gravity on the surface of Earth, [tex]g=9.8\ m/s^2[/tex]
Again using second equation of motion to find the time taken on the surface of earth.
[tex]s=ut+\dfrac{1}{2}gt^2[/tex], u = 0
[tex]s=0+\dfrac{1}{2}gt^2[/tex]
[tex]t=\sqrt{\dfrac{2\times 17}{9.8}}[/tex]
t = 1.86.................(2)
Change in time, [tex]\Delta t=t'-t=1.95-1.86=0.089\ s[/tex]
So, on the surface of earth it will taken 0.089 seconds more. Hence, this is the required solution.
Final answer:
When an object is dropped from a height on Venus, it takes longer to reach the surface compared to Earth due to the smaller acceleration due to gravity on Venus. It takes approximately 1.56 times longer for the object to reach the surface on Venus than on Earth.
Explanation:
When an object is dropped from a height on Venus, it will take longer to reach the surface compared to dropping the same object from the same height on Earth. This is because the acceleration due to gravity on Venus is smaller than on Earth. Gravity on Venus is about 0.904 times the gravity on Earth.
To calculate the time taken to reach the surface on Venus, we can use the equation:
t = sqrt((2h) / g)
Where h is the height and g is the acceleration due to gravity.
Let's assume the acceleration due to gravity on Earth is 9.8 m/s^2 and the acceleration due to gravity on Venus is 0.904 times that value. Plugging in the values, we get:
time on Venus = sqrt((2 * 17) / (0.904 * 9.8))
Simplifying the equation, we find that it takes approximately 1.56 times longer for the object to reach the surface when dropped on Venus compared to Earth.
Matt (m = 80 kg) and Trey (m = 90 kg) slide across an ice skating rink and collide with each other.
Before the collision, Matt was moving 3 m/s to the east and Trey was moving 2 m/s to the west.
After the collision, Matt is moving 1.5 m/s to the west.
a. What was the total momentum of the system before the collision? (1 point)
(80kg)(3m/s)+(90)(-2m/s)=60N*s
Answer:
Total momentum of the system before the collision is 60 kg-m/s.
Explanation:
Given that,
Mass of Matt, m = 80 kg
Mass of Trey, m' = 90 kg
Initial speed of the Matt before the collision, u = 3 m/s (east)
Initial speed of the Trey before the collision, u = -2 m/s (west)
After the collision, Matt is moving 1.5 m/s to the west.
We need to find the total momentum of the system before the collision. We know that the momentum is given by the product of mass and velocity. Initial momentum is given by :
[tex]p_i=mu+m'u'\\\\p_i=80\times 3+90\times (-2)\\\\p_i=60\ kg-m/s[/tex]
So, the total momentum of the system before the collision is 60 kg-m/s. Hence, this is the required solution.
which of these human variations is dependent on a group of genes
a. skin color
b. cleft chin
c. eye shape
d. attached earlobes
Among the options listed, skin color and eye shape are known to be dependent on a group of genes, making them polygenic traits. The others are believed to be influenced mainly by single genes, although this view is evolving.
Explanation:The human variations that are dependent on a group of genes, also known as polygenic traits, include skin color, eye shape, and potentially, other physical attributes. This means that these traits are not determined by a single gene but by the interactions of multiple genes.
Skin color, eye shape are complex traits that are determined by the interaction of several genes. For instance, in the case of skin color, about 20 genes have been associated with variations in skin color.
The other two variations, cleft chin and attached earlobes, are traditionally thought of as being controlled by a single gene each, although recent research suggests a more complex genetic basis as well.
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What must be true about tow objects if heat is flowing between them?
Explanation:
They have different temperatures. Heat always flows from high temperature to low temperature.
The process by which a substance changes from a gas tank state to the liquid state is
Answer:
Condensation
Explanation:
Condensation is the process in which a gas turns into a liquid, by releasing heat. In such a process, heat is released from the gas to the environment, and the molecules of the gas become closer to each other, and they feel more the intermolecular forces between each other.
The processes that describe the different changes of phase of matter are:
- Melting: when a solid turns into a liquid, absorbing energy
- Evaporation: when a liquid turns into a gas, absorbing energy
- Condensation: when a gas turns into a liquid, releasing energy
- Freezing: when a liquid turns into a solid, releasing energy
- Sublimation: when a solid turns into a gas, absorbing energy
- Deposition: when a gas turns into a solid, releasing energy
1A, 3B, and 7A are examples of
__________
on the periodic table.
Answer:
1 A, 3 B, and 7 A are examples of group number on the periodic table.
Explanation:
The table that consists of elements arranged systematically on the basis of atomic numbers is called periodic table. Groups and periods are two important part of a periodic table. A periodic table contains seven horizontal rows, called as periods and 18 vertical columns, called group.
The groups name is given in the form of number and alphabets. It represents the columns present in the periodic table.
Hence, 1 A, 3 B, and 7 A are examples of group number on the periodic table.
Answer:
group number
Explanation:
Match the vocabulary terms to their definitions.
See the attached picture:
Answer:
the order of blanks from top to bottom is
6
3
2
4
5
1
Explanation:
Someone places a chocolate bar near a working radar set that is used to locate ships and airplanes. Which best describes what is likely to happen to the chocolate bar?
A.It changes color as it absorbs visible light from the radar set.
B.It softens and melts as it absorbs microwaves from the radar set.
C.It becomes radioactive after it absorbs gamma rays from the radar set.
D.It begins to fluoresce after it absorbs ultraviolet light from the radar set.
Answer:
B. it softens and melts as it absorbs microwaves from the radar set.
Explanation:
Answer:
The Answer is defiantly B
Explanation:
I just know it is
The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed of objects on the planet’s surface? Round your answer to the nearest whole number.
Answer:
Tangential speed of objects on the planet’s surface = 241 m/s
Explanation:
Speed is given by the ratio of distance traveled to the time.
Radius of mars, r = 3397 km = 3.397 x 10⁶ m
Distance traveled = 2πr = 2 x π x 3.397 x 10⁶ = 2.13 x 10⁷ m
Time taken = 24.6 hours = 24.6 x 60 x 60 = 88560 s
[tex]\texttt{Tangential speed =}\frac{2.13\times 10^7}{88560}=240.51m/s[/tex]
Tangential speed of objects on the planet’s surface = 240.51 m/s = 241 m/s
The tangential speed of objects on Mars' surface is approximately 242 m/s, calculated using the planet's circumference and rotation time.
To calculate the tangential speed of objects on Mars' surface, we first find the circumference of Mars using the formula:
Circumference=2π×radius=2π×3,397km≈21,371km.
Next, convert the time taken for one rotation from hours to seconds:
24.6hours×60minutes/hour×60seconds/minute≈88,560seconds.
Now, calculate the tangential speed using the formula:
Tangential Speed= Circumference / Time taken for one rotation
Tangential Speed≈ 21,371km / 88,560seconds ≈0.2417km/s≈241.7m/s.
Rounding to the nearest whole number, the approximate tangential speed of objects on Mars' surface is ≈242m/s.
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What type of relationship does this graph show?
a negative relationship
an inverse relationship
a non-linear relationship
a direct relationship
Negative because the graph goes down
Answer:
Negative because the graph goes down
Explanation:
Select the correct answer. Which type of committees handle recurring tasks in an organization? A. task force B. standing C. ad hoc D. generic
Answer:
Standing :)
Explanation:
the change in velocity that occurs at a specific moment in time known as
The change in velocity at a specific moment is called Instantaneous acceleration. It is the acceleration at an exact instant as opposed to an average over a time period.
Explanation:The change in velocity that occurs at a specific moment in time is known as Instantaneous acceleration. Acceleration is the rate at which velocity changes with time. In general, it is calculated as the change in velocity divided by the time over which the change occurred. In physics, when we say 'at a specific moment in time', we refer to an infinitesimally small interval of time. In this case, we are referring to the concept of instantaneous acceleration. It's the acceleration at a particular instant in time as opposed to an average over a time interval.
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The change in velocity at a specific moment in time is known as instantaneous acceleration.
Explanation:The change in velocity that occurs at a specific moment in time is known as the instantaneous acceleration.
Instantaneous acceleration is the rate of change of velocity at a specific instant in time.
It is found by taking the derivative of the velocity function with respect to time.
For example, if a car is accelerating from rest to a speed of 60 mph in 10 seconds, the instantaneous acceleration at the moment when the car reaches a speed of 30 mph would be different from the instantaneous acceleration at the moment when the car reaches a speed of 60 mph.
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A boy pushes a toy car with the force of 50N. The force of friction as the car moves is 5N. What is the net force on the car
Explanation:
The first Newton Law of Motion states that an object at rest or describing a uniform straight line motion (moving at constant velocity), will remain at rest or moving unless a force is applied to it and changes its state of rest or motion.
According to his law, an object in rest can be in equilibrium (net force equals to zero), and a moving object can also be in equilibrium, as long as it keeps a constant velocity.
So, in the case of the toy car the forces acting on it (considering there is equilibrium between the normal force and the weight of the toy) are:
F1=50 N in the direction of the movement of the car
F2=-5 N (in the opposite direction of the movement of the car, that s why it has the negative sign)
Therefore the net force F is:
F=F1+F2=50N - 5 N
F=45N
What is magnetism ?
Hello There!
As you already know, magnetism is invisible. Magnetism comes from minerals that are found in the Earth. The earth has so many minerals so our planet is basically a giant magnet. The most common mineral that can be made into a magnet is Iron.
A light bulb with resistance of 22 ohms is connected to a 110 V battery. What is the current
flowing through the circuit?
5A. The current that flowing through the circuit with a lightbulb of 22Ω connected to a voltage source of 110V is 5A.
The key to solve this problem is using Ohm's Law equations V = I*R, where V is the voltage drop, I is the current that flow through the element and R its resistance.
Clear I from the equation above:
I = V/R
With V = 110V, and R(lightbulb) = 22Ω
I = 110V/22Ω = 5A
depending on their area of origin, whales can communicate in various (blank)
Answer: The correct answer (for Plato) would be ‘dialects’.
Explanation: Dialects are variations of a language that belong to a specific region, area, or group. E.g. Tagalog and Cebuano are both dialects of Filipino, or the southern American dialect and African American vernacular English (AAVE) are both dialects of English.
Compare and contrast power and work.
Answer:
Comparison
Displacement and force are factors of both work and power
Work=Force× Displacement
power=(Force×Displacement)/time
Therefore power is the derivative of work with respect to time.
Contrast
Work is defined as a product of force and distance while power is the rate at which the work is done.
In the light wave above, the property labeled A determines which characteristic of visible light?
brightness
speed
reflection
color
Explanation:
i think the answer is Reflection
How is the Sun similar to the stars that can be seen at night?
A) The Sun makes light energy.
B) The Sun takes light energy from space.
C) The Sun warms the Earth with its light.
D) The Sun reflects light from the planets.
Answer:
A
Explanation:
Answer:
A
Explanation:
cuz it is
n an adiabatic process, what happens when gases in a system are compressed?
The system absorbs all of the heat.
The system releases all of the heat.
The temperature of the system increases.
The temperature of the system decreases.
Answer:
The temperature of the system increases.
Explanation:
As we know that in adiabatic process the heat transferred to the system must be zero
now by first law of thermodynamics we know that
[tex]Q = \Delta U - W[/tex]
now we know that
Q = 0 (for adiabatic process)
now we have
[tex]\Delta U = W [/tex]
as we know that gas is compressed so the work is done on the gas which shows W is positive
So here change in internal energy must be positive which shows that temperature must be increased
so correct answer will be
The temperature of the system increases.
A light ray in air is incident on an air to glass boundary at an angle of 40 degrees and is refracted in the glass of 25 degrees with the normal. What is the index of refraction of the glass? A. 1.10 B. 1.25 C. 1.33 D. 1.52 HELP PLEASE!!!!!!!!!
Answer:
D
Explanation:
Snell's law states:
n₁ sin θ₁ = n₂ sin θ₂
where n is the index of refraction and θ is the angle of incidence (relative to the normal).
The index of refraction of air is approximately 1. So:
1 sin 40° = n sin 25°
n ≈ 1.52
Theindex of refraction of glass is calculated to be 1.52, which is option D.
To find the index of refraction of glass when a light ray in air is incident on an air to glass boundary at an angle of 40 degrees and is refracted in glass at 25 degrees with the normal, we use Snell's law. Snell's law is expressed as n1 sin(θ1) = n2 sin(θ2), where n1 and n2 are the indices of refraction of the first and second mediums, respectively, and θ1 and θ2 are the angles of incidence and refraction, respectively. Given that the index of refraction of air (n1) is approximately 1, we can solve for the index of refraction of glass (n2) as follows: 1 ×sin(40 degrees) = n2 × sin(25 degrees). Solving this equation gives us n2 = 1.52, which indicates the index of refraction of the glass is 1.52, corresponding to option D.
Work and Energy
A 68 kg students runs up a flight of stairs 3.5 meters high in 11.4 seconds. The student takes 8.5 seconds to run up the same flight of stairs during a second trial. Determine the following:
a. The work done in each trial. You should identify these values as W1 and W2.
b. The power exerted by the student in each trial. You should identify these values as P1 and P2.
a) [tex]W_1 = 2332 J[/tex], [tex]W_2= 2332 J[/tex]
The work done by the student in each trial is equal to the gravitational potential energy gained by the student:
[tex]W=mg\Delta h[/tex]
where
m = 68 kg is the mass of the student
g = 9.8 m/s^2 is the acceleration of gravity
[tex]\Delta h[/tex] is the gain in height of the student
For the first student, [tex]\Delta h = 3.5 m[/tex], so the work done is
[tex]W_1 = (68)(9.8)(3.5)=2332 J[/tex]
The second student runs up to the same height (3.5 m), so the work done by the second student is the same:
[tex]W_2 = (68)(9.8)(3.5)=2332 J[/tex]
2) [tex]P_1 = 204.6 W[/tex], [tex]P_2 = 274.4 W[/tex]
The power exerted by each student is given by
[tex]P=\frac{W}{t}[/tex]
where
W is the work done
t is the time taken
For the first student, [tex]W_1 = 2332 J[/tex] and [tex]t=11.4 s[/tex], so the power exerted is
[tex]P_1 = \frac{W_1}{t_1}=\frac{2332 J}{11.4 s}=204.6 W[/tex]
For the second student, [tex]W_2 = 2332 J[/tex] and [tex]t=8.5 s[/tex], so the power exerted is
[tex]P_2 = \frac{W_2}{t_2}=\frac{2332 J}{8.5 s}=274.4 W[/tex]
what phase of the moon is shown in the photo above.
a) waning crescent
b) waxing gibbous
c) third quarter
d) waning gibbous
The Moon phase described is the waxing gibbous phase, which occurs after the first quarter phase and before a full moon, with the majority of the illuminated side becoming increasingly visible.
The phase of the Moon depicted in the description corresponds to the waxing gibbous phase.
This phase occurs during the week after the first quarter phase, where more of the Moon's illuminated half becomes visible from Earth, leading up to a full moon.
At the waxing gibbous phase, the Moon has not yet reached the full moon stage where it is opposite the Sun and its entire illuminated side is visible from Earth.
The waxing gibbous Moon rises in the afternoon and is visible for most of the night, setting in the early morning hours.
Its visibility throughout the night can be particularly helpful for activities like taking a romantic stroll or returning from a late-night study session.
SO what exactly is beyond our atmosphere, like space, has anybody actually been in space ????? or are we just making hopeless fantasies
Answer:
The universe, milky Way even black holes. Yes the first people who went to the moon put a flag to represent America. We are not making hopeless fantasies.
Explanation:
The charge stored in a parallel plate capacitor is proportional to the _____(potential, current) and across _____ (resistance, capacitance) the plates.
Answer:
The charge stored in a parallel plate capacitor is proportional to the potential, and capacitance across the plates.
Explanation:
The capacitance of a parallel plate capacitor is given by:
[tex]C=\frac{Q}{V}[/tex]
where
Q is the charge stored
V is the potential difference across the capacitor
Re-arranging the formula, we get
[tex]Q=CV[/tex]
From this expression, we see that the charge stored (Q) is proportional to both the potential (V) and the capacitance (C).
Answer:
The answers are potental and capacitance
Explanation:
Which of the following types of units is based on the metric system in the United States?
the mile
the ounce
the dollar
the pound
Answer:
The mile
Explanation:
this is calculated using the metric system in kilometers..
Final answer:
None of the listed units (the mile, the ounce, the dollar, the pound) are based on the metric system used in the United States; these are all part of the customary or English system, except for the dollar, which is a currency.
Explanation:
None of the units mentioned - the mile, the ounce, the dollar, or the pound - are based on the metric system. These are all part of the English (Imperial) system of measurement that is primarily used in the United States. The metric system units for length, mass, and volume would be the meter (m), kilogram (kg), and liter (L), respectively. Meanwhile, the mile, ounce, and pound pertain to customary units of length and mass used in the U.S. which are based on the system developed in England. In contrast, the dollar is a unit of currency and not a unit of measurement for physical quantities.
When dealing with units used in science, the metric system is generally preferred because it facilitates easier conversion and calculation due to its base 10 structure. For example, a meter is approximately 1.1 yards, a kilogram is equivalent to about 2.2 pounds, and the second is the same in both the metric and American systems. In science, SI (International System of Units) units are used, which are metric units.
A train travels 53 kilometers in 2 hours, and then 54 kilometers in 4 hours. What is
its average speed?
Your Answer:
Answer
units
Average speed = (total distance) / (time to cover the distance)
total distance = (53 km + 54 km) = 107 km
time = (2 hr + 4 hr) = 6 hours
Average speed = (107 km) / (6 hrs)
Average speed = (107/6) (km/hrs)
Average speed = 17.833... km/hr
If a foam cube 20 cm on a side has a density of 300kg/m^3 is placed in fresh water, how much of the cube will be underwater?
Answer:
6 cm
Explanation:
The weight of the water displaced equals the weight of the cube.
mg = ρVg
m = ρV
The mass of the cube is its density times its volume, and volume of a cube is the side length cubed.
The volume of the water displaced is the area times the depth.
(300 kg/m³ * (0.20 m)³) = (1000 kg/m³) ((0.20 m)² h)
2.4 kg = 40 kg/m h
h = 0.06 m
h = 6 cm
So 6 cm of the cube will be underwater.
Into how many main groups are fish divided?
a. one
b. two
c. three
d. four
Answer:
Fish are divided into three main groups, which include Cartilaginous fish, Bony fish, and Lobe-finned fish.
The dispatcher of courier service receives a message from truck A that reports a position of +5 after a displacement of +2. What was the initial position of Truck A? First solve the problem using a number line and then solve the problem using an equation.
The formula we need to use is displacement.
[tex]d=\Delta{x}=x_f-x_i[/tex], where xf is final position and xi is initial position.
We report the final position of 5 and the displacement of 2 so the formula is now:
[tex]2=5-x_i\Longrightarrow x_i=3[/tex].
So the initial position of truck A is 3.
Hope this helps.
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