1. The face of a brick is 3 1/2 inches by 8 inches. Suppose you want to create a
brick pathway that is 56 inches wide by 20 inches long. How many 3 1/2 inch by 8
inch bricks would you need?
Answer:
40 bricks
Step-by-step explanation:
3 1/2×8
=28
56×20
=1,120
1,120÷28
=40 bricks
What is the opposite of -0.8
Answer:
0.8
Step-by-step explanation:
the opposite of a negative is the positive version of the number
Answer:
the opposite of -0.8 is 0.8
Step-by-step explanation:
opposite of a negative number is the same number but positive or vice verse
Rectangleville's limits form a perfectly rectangular shape whose length is 20 kilometers and width is 12 kilometers. It has a population density of 320 people per square kilometer? What is the population of Rectangleville?
Answer:
Step-by-step explanation:
answer 76800
length- 20
width- 12
20x12=240
240x320(people)= 76800
The population of given Rectangleville is 76800.
What is Area of Rectangle?The area of Rectangle is length times of width.
Given that Rectangleville's limits form a perfectly rectangular shape whose length is 20 kilometers and width is 12 kilometers
length is 20 km
width is 12 km
Area of rectangleville = Length × width
=20x12
=240 square kilometer.
Now It has a population density of 320 people per square kilometer
We need to find the population.
To find this we need to multiply two hundred forty with three hundred twenty.
240x320
= 76800
Hence, the population of given Rectangleville is 76800.
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A state Department of Transportation claims that the mean wait time for various services at its different locations is at most 6 minutes. A random sample of 34 services at different locations has a mean wait time of 10.3 minutes and a standard deviation of 8.0 minutes. Is there enough evidence to reject the claim at alpha equals 0.01? Find the critical value. Round your answer to the thousandths place.
To determine whether there is enough evidence to reject the claim of the state Department of Transportation, a hypothesis test needs to be performed. The null hypothesis (H0) is that the mean wait time is 6 minutes or less, while the alternative hypothesis (H1) is that the mean wait time is greater than 6 minutes. Using a one-sample t-test, the test statistic is calculated and compared to the critical value obtained from the t-distribution table or calculator. In this case, the test statistic is greater than the critical value, indicating that there is enough evidence to reject the null hypothesis.
Explanation:To determine whether there is enough evidence to reject the claim of the state Department of Transportation, we need to perform a hypothesis test.
Hypotheses:
Let:
μ be the mean wait time for various services at different locations.
The null hypothesis (H0) is that the mean wait time (μ) is 6 minutes or less:
H0: μ ≤ 6
The alternative hypothesis (H1) is that the mean wait time (μ) is greater than 6 minutes:
H1: μ > 6
Test statistic:
We will use a one-sample t-test since the population standard deviation is unknown.
The test statistic (t) is calculated using the formula:
t = (Xbar - μ)/(s/√(n))
Where:
Xbar is the sample mean - 10.3 minutes,
μ is the claimed mean - 6 minutes,
s is the sample standard deviation - 8.0 minutes, and
n is the sample size - 34.
Critical value:
To find the critical value, we need to determine the rejection region using the significance level (alpha) of 0.01 and the degrees of freedom (df) which is n - 1 = 33.
From the t-distribution table or calculator, the critical value for a one-tailed test at alpha = 0.01 and df = 33 is approximately 2.449.
Conclusion:
The test statistic (t) = (10.3 - 6)/(8.0/√(34)) = 3.720.
Since the test statistic (t) = 3.720 > 2.449 (the critical value), we have enough evidence to reject the null hypothesis.
Therefore, we can conclude that there is sufficient evidence to reject the claim of the state Department of Transportation at alpha = 0.01.
Kevin has 6 cups of flour. It takes 3/8 cup of flour to make one cake. How many cakes can Kevin make?
Answer:
16 cakes
Step-by-step explanation:
If you do 6 divided by 3/8, you would get 16, which is the amount of cakes that Kevin will be able to make.
Carl is balancing his checking account. After comparing the bank statement to his register, he notices an outstanding debit of $58.00.
Which shows the correct amount in Carl’s checking account?
$51.75
$109.75
$167.75
$221.87
Answer:
$51.75
Hope this helps!
(Please mark brainliest!)
Answer:
Step-by-step explanation:
A. $51.75
23
19
100
Expanded notation what it is
Answer:
Hello dear, your question might not be complete, but if you want to know the expanded notation form for the numbers given, here they are;
(1). 20 + 3.
(2). 10 + 9.
(3). 100 + 0 + 0
Step-by-step explanation:
Expanded notation can simply be defined as the depiction of numbers or digits for what they are really are that is to say the representation of the values of numbers or digits. The numbers can be shown or represented from ones, through to hundreds and many more.
For the numbers given in this question, below are the expanded notation form;
(1). 20 × 1 + 3 × 1 = Expanded Factors Form.
20 + 3 = Expanded Notation Form.
(2). 10 ×1 + 9 × 1 = Expanded Factors Form.
10 + 9 = Expanded Notation Form.
(3). 100 × 1 + 0 × 10 + 0 × 1 = Expanded Factors Form.
100 + 0 + 0 = Expanded Notation Form.
one length of a swimming pool is 25m Alison swims 60 lengths of the pool. how many more lengths must Alison swim to complete 1 mile?
hint= 1 mile is 1.6km
Answer:
4
Step-by-step explanation:
1 mile = 1.6 km
1 km = 1000 m
1.6 * 1000 = 1600, So to swim 1 mile, she must swim 1600 m
She has already swam 60 lengths which is 1500 m because 60 (the number of lengths)*25 (the length of the pool) = 1500.
1600 (the amount she needs to swim) - 1500 (the amount she has already swam) = 100.
She needs to swim 100 m more, which is 4 lengths because 100/25 = 4.
he United States Marine Corps is reviewing its orders for uniforms because it has a surplus of uniforms for tall men recruits and a shortage for shorter men recruits. Its review involves data for 772 men recruits between the ages of 18 to 24. That sample group has a mean height of 69.7 inches with a population standard deviation of 2.8 inches. Construct a 99% confidence interval for the mean height of all men recruits between the ages 18 and 24.
Answer:
The 99% confidence interval for the mean height of all men recruits between the ages 18 and 24 is between 69.44 inches and 69.96 inches.
Step-by-step explanation:
We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:
[tex]\alpha = \frac{1-0.99}{2} = 0.005[/tex]
Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].
So it is z with a pvalue of [tex]1-0.005 = 0.995[/tex], so [tex]z = 2.575[/tex]
Now, find the margin of error M as such
[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]
In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.
[tex]M = 2.575\frac{2.8}{\sqrt{772}} = 0.26[/tex]
The lower end of the interval is the sample mean subtracted by M. So it is 69.7 - 0.26 = 69.44 inches
The upper end of the interval is the sample mean added to M. So it is 69.7 + 0.26 = 69.96 inches
The 99% confidence interval for the mean height of all men recruits between the ages 18 and 24 is between 69.44 inches and 69.96 inches.
One number is six less than a second number. Six times the first is 8 more than 4 times the second. Find the numbers.
To find the values of the two numbers, we can set up a system of equations based on the given information and then solve for x and y. The first number is 16 and the second number is 22.
Explanation:Let's represent the first number as x and the second number as y.
We can set up two equations based on the given information.
The first equation is: x = y - 6
The second equation is: 6x = 4y + 8
Now we can solve this system of equations to find the values of x and y.
Substituting the first equation into the second equation, we get: 6(y - 6) = 4y + 8
Simplifying, we get: 6y - 36 = 4y + 8
Bringing like terms together, we have: 6y - 4y = 8 + 36
Combining like terms, we get: 2y = 44
Dividing both sides by 2, we have: y = 22
Now substitute y = 22 back into the first equation: x = 22 - 6
Simplifying, we get: x = 16
Therefore, the first number is 16 and the second number is 22.
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In ideal conditions, 200 colony-forming units (cfu) of E. coli can grow to 400 cfu in 20 minutes, to 800 cfu in 40 minutes, and to 1600 cfu in an hour.
Part A: Jenny says that the E. coli growth can be modeled with an exponential function. Do you agree? Justify your answer.
Part B: Write the equation that models the function.Immersive Reader
Answer:
(a)Yes, it is an exponential function.
(b)[tex]P(t)=200\cdot 2^{t/20}[/tex]
Step-by-step explanation:
(a)A population grows exponentially if it increases by a common ratio(called the growth ratio). We can see from the given information that the population of E.coli doubles every 20 minutes, therefore it is an exponential growth with a growth ratio of 2.
(b)The population, P(t) at any time t of an initial population, [tex]P_o[/tex] with a growth ratio of r over a period k can be modeled using the function:
[tex]P(t)=P_o\cdot r^{t/k}[/tex]
In this Case:
[tex]P_o[/tex]=200
Growth rate,r=2
Growth Period,k=20 minutes
Therefore, the equation that models the function is:
[tex]P(t)=200\cdot 2^{t/20}[/tex] , t is in minutes
Jenny is correct that E. coli growth can be modeled with an exponential function, characterized by doubling in population size at regular time intervals. An equation representing this growth is N(t) = N0 x 2^(t/20), where N0 is the initial amount of E. coli and t is time in minutes.
I agree with Jenny, the E. coli growth can indeed be modeled with an exponential function. This is supported by the fact that the E. coli population doubles after each consistent time period (20 minutes). In an exponential growth model, the rate of increase of a population is proportional to the current population size, which means as the population gets larger, it grows at an even faster rate.
Part B: Equation of Exponential Growth:
The exponential growth model for a population starting with N0 individuals and a growth rate r can be described by the equation N(t) = N0ert, where N(t) is the population at time t, N0 is the initial population size, e is the base of the natural logarithm, and r is the growth rate per unit time. For E. coli, with a doubling time of 20 minutes, the growth rate can be calculated using the doubling formula: Td = ln(2)/r, solving for r gives r = ln(2) / 20 minutes. The continuous exponential growth equation can be simplified to a discrete model for this case: N(t) = N0 * 2(t/20), where t is given in minutes.
A person recently read that 84% of cat owners are women. How large a sample should the researcher take if she wishes to be 90% confident that her proportion is within 3% of the true population proportion?
Answer:
405
Step-by-step explanation:
To find sample size, use the following equation, where n = sample size, za/2 = the critical value, p = probability of success, q = probability of failure, and E = margin of error.
[tex]n=\frac{(z_{\frac{\alpha }{2} })^{2} *p*q }{E^2}[/tex]
The values that are given are p = 0.84 and E = 0.03.
You can solve for the critical value which is equal to the z-score of (1 - confidence level)/2. Use the calculator function of invNorm to find the z-score. The value will given with a negative sign, but you can ignore that.
(1 - 0.9) = 0.1/2 = 0.05
invNorm(0.05, 0, 1) = 1.645
You can also solve for q which is 1 - p. For this problem q = 1 - 0.84 = 0.16
Plug the values into the equation and solve for n.
[tex]n =\frac{(1.645)^2*0.84*0.16}{(0.03)^2}\\n= 404.0997333[/tex]
Round up to the next number, giving you 405.
Giving brainliest for CORRECT awnser. Am I correct?
Step-by-step explanation:
-13 > x - 43
-13 + 43 > x
30 > x
Multiplication mod 29 by 30 is equivalent to standard multiplication by ___
?
Figure out what value is ___.
PLS HELP ITS A GRADE!!!
The graph on the right shows two angles that
share the same terminal side: 45° and -315º.
Together, the angles form a circle.
What if you subtract the angle measures?
45°-(-3159) =
-315º – 45º =
Answer:
45°-(315°) = 360°
-315°-45°=-360°
Second part: WOULD
Step-by-step explanation:
Trust me I gotchu
Subtracting angles involves accounting for the directions implied by their positive or negative signs. The subtraction of 45°-(-315°) equates to an addition, giving a resultant angle of 360°. Conversely, -315° – 45° provides a resultant angle of -360°.
Explanation:The question involves the mathematical concept of angles, specifically, subtracting them. Here, we are dealing with angles of 45° and -315°. When subtracting angles, consider the directions indicated by the positive and negative signs. A positive angle is measured counterclockwise from the initial side to the terminal side, while a negative angle is measured clockwise.
So, for 45°-(-315°), you're essentially adding 45 and 315 because subtracting a negative number becomes the addition of the positive equivalent. This gives you a resultant angle of 360°.
And in the case of -315° – 45°, you're subtracting 45 from -315 which gives you a resultant angle of -360°.
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Mason and Christian go to the movie theater and purchase refreshments for their friends. Mason spends a total of $45.75 on 3 bags of popcorn and 6 drinks. Christian spends a total of $71.50 on 6 bags of popcorn and 4 drinks. Write a system of equations that can be used to find the price of one bag of popcorn and the price of one drink. Using these equations, determine and state the price of a drink, to the nearest cent.
Answer:
A bag of popcorn costs $10.25One drink costs $2,5Step-by-step explanation:
Let the cost of a bag of popcorn=p
Let the cost of a drink=d
Mason spends a total of $45.75 on 3 bags of popcorn and 6 drinks.
Therefore: 3p+6d=45.75Christian spends a total of $71.50 on 6 bags of popcorn and 4 drinks.
Therefore: 6p+4d=71.50The required system of equations is:
3p+6d=45.756p+4d=71.50Multiply the first equation by 2 to eliminate p
6p+12d=91.5
6p+4d=71.50
Subtract
8d=20
d=20/8=$2.5
Substitute d=2.5 into any of the equations to obtain p.
6p+12d=91.5
6p+12(2.5)=91.5
6p=91.5-12(2.5)
6p=91.5-30
6p=61.5
Divide both sides by 6
p=$10.25
Therefore:
A bag of popcorn costs $10.25One drink costs $2,5graph the following line f(x)=-2/3x+4
Answer:
Ermm here I graphed it :)
Sorry for dark mode..
help?? question is above^^ 12 points
Answer:
61/495
Step-by-step explanation:
There are 250 economy class seats on board. The airline sells some economy class seats at a discount price of $440 in advance and reserve a number of seats to sell at the full price of $770. Suppose that Dallas One Airline can always sell all discount tickets, and the demand for full price tickets is normally distributed with a mean of 100 and a standard deviation of 25. What is the probability that there will be no empty seat when the Dallas One Airline uses the optimal protection level? Choose the closest number.
Answer:
Check the explanation
Step-by-step explanation:
Cost of over reserving full cost tickets, Co = $440 ( empty seats as we cannot get even the discounted revenue)
Cost of under reserving Cu = 770-440 = $330 ( because you sell more discounted tickets)
Now critical ratio = Cu / (Cu+Co) = 330/770 = 0.42857
Now for above critical ratio ,z = -0.18 ( refer standard normal distribution table)
Optimal protection level = mean +z*standard deviation = 100-0.18*25 = 95.5 = 96
The possible costs include: all the above. You may need to provide compensation to passenger and make alternative travel arrangements. Also passenger won't be happy by over booking and their will be loss of good will.
In the right triangle shown, DF=EF=3DF=EF=3D, F, equals, E, F, equals, 3.
How long is DEDED, E?
The length of side DE in the right triangle shown is 4.24 units.
We can use the Pythagorean Theorem to solve for the length of DE, since we know the lengths of the other two sides.
The Pythagorean Theorem states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
The hypotenuse of the triangle is DE, and the other two sides are DF and EF. We know that DF = EF = 3 units. Therefore, we can set up the following equation:
[tex]DE^2 = DF^2 + EF^2[/tex]
Substituting in the known values, we get:
[tex]DE^2 = 3^2 + 3^2[/tex]
[tex]DE^2 = 9 + 9[/tex]
[tex]DE^2 = 18[/tex]
Taking the square root of both sides, we get the length of DE:
DE = √18
DE ≈ 4.24 units
Therefore, the length of side DE in the right triangle shown is 4.24 units.
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Question
1. Add and write in standard form.
(2x2 - 6x3 + 4) + (2x3 + 3x2 + 4)
Answer:
because I said one is the best number
Step-by-step explanation:
[tex](2x^2-6x^3+4)+(2x^3+3x^2+4)[/tex]
Since this is addition, you can just easily combine the terms.
[tex](2x^2+3x^2)+(-6x^3+2x^3)+(4+4)[/tex]
[tex]5x^2 -4x^3+8[/tex]
Now, all we have to do is put it in standard form meaning the exponents have to go in descending order. Largest exponent to smallest exponent.
[tex]-4x^3+5x^2+8[/tex]
So, this is your answer in standard form.
You finance a $500 washing machine completely on credit, you will just pay the minimum payment each month for the next three months. The APR is 18.99% and the minimum payment each month is 4% of the balance. Determine the finance charge, carry-over balance, and minimum payment required for each of the next two months, and the carry-over balance for month 3 in the table below:
Step-by-step explanation:
Let me know if it's all right! Good luck
6/2 as a mixed number
Answer:
Step-by-step explanation:
6 /2
=3
Good luck honey!
Use this information to answer the following 7 questions.
A large financial institution is interested in training its college educated workforce "Advanced Microsoft Excel". Management is considering 3 approaches: online, traditional classroom and hybrid (a mix of both). Prior to launching the program throughout the entire organization, they decided to pilot test the three approaches. Because they believed that educational background may affect the results, they selected 3 employees from each of 10 different college major program of study (liberal arts, accounting, economics, management, marketing, finance, information systems, computer science, operations, other), and randomly assigned each to one of the three approaches. At the end of training, each participant took an exam. Below is the partially completed ANOVA table.
Source DF SS MS F P-value
Treatment (Training) 2 171.47
Block (Major) Error 9 2239.47
Error 18 206.53
Total
The above study is ________.
a. an observational study
b. an experimental study
Answer:
1) b. an experimental study
2) a. μ1=μ2=μ3
3) a. MSE
4) MSTR =85.735
5) value of the F-statistics =7.472
6) b. 0.004
7) a. We reject the null hypothesis
8) b. Yes
Step-by-step explanation:
See the attached image
Simplify 2/3 - 5/6 times 8
please answer
Answer:
-6
Step-by-step explanation:
simplify
Given that tan^2 0 =3/8, what is the value of sec 0?
Answer:
B…
Step-by-step explanation:
How are the measures of angles, arcs and segments formed by secant lines that intersect within a circle related?
Answer:
The answers below ._.
Step-by-step explanation:
A secant is a line that intersects a circle in exactly two points. When a tangent and a secant, two secants, or two tangents intersect outside a circle then the measure of the angle formed is one-half the positive difference of the measures of the intercepted arcs.
The formation of secant lines that intersect within a circle is related when a secant and a tangent or two tangents intersect each other outside a circle.
What is a secant line?A secant line is a straight line that connects two points on a curve. The secant line approaches a tangent line when the two points are drawn together.
So, If a tangent and a secant, or two tangents intersect at the exterior side of a circle, the angle created has a measure equal to one-half the positive difference between the intercepted arcs' measures.
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Plzzzzz help
45
55
95
Answer:
95
Step-by-step explanation:
yeah
From a point 31 meters from the base of a telephone pole the angle of elevation to a worker on the pole is 35 degrees. The angle of elevation to the top of the pole is 68 degrees. Find the distance from the worker to the top of the pole.
Answer:
51.02 metres
Step-by-step explanation:
The pictorial representation of the problem is attached.
We are required to find the distance from the worker to the top of the pole, |DA| in the diagram.
In Triangle ABC
[tex]Tan 68^\circ =\frac{|AB|}{|BC|}\\Tan 68^\circ =\frac{|AB|}{31}\\|AB|=31 X Tan 68^\circ=72.73m[/tex]
In Triangle BCD
[tex]Tan 35^\circ =\frac{|BD|}{|BC|}\\Tan 35^\circ =\frac{|BD|}{31}\\|BD|=31 X Tan 35^\circ=21.71m[/tex]
The distance, |DA| =|AB|-|BD|
=72.73-21.71
=51.02 metres
The distance from the worker to the top of the pole is 51.02 metres.
The U.S. Census Bureau conducts annual surveys to obtain information on the percentage of the voting-age population that is registered to vote. Suppose that 513513 employed persons and 604604 unemployed persons are independently and randomly selected, and that 287287 of the employed persons and 280280 of the unemployed persons have registered to vote. Can we conclude that the percentage of employed workers ( p1p1 ), who have registered to vote, exceeds the percentage of unemployed workers ( p2p2 ), who have registered to vote? Use a significance level of α=0.05α=0.05 for the test.
Answer:
We conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.
Step-by-step explanation:
We are given that 513 employed persons and 604 unemployed persons are independently and randomly selected, and that 287 of the employed persons and 280 of the unemployed persons have registered to vote.
Let [tex]p_1[/tex] = percentage of employed workers who have registered to vote.
[tex]p_2[/tex] = percentage of unemployed workers who have registered to vote.
So, Null Hypothesis, [tex]H_0[/tex] : [tex]p_1\leq p_2[/tex] {means that the percentage of employed workers who have registered to vote does not exceeds the percentage of unemployed workers who have registered to vote}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]p_1>p_2[/tex] {means that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote}
The test statistics that would be used here Two-sample z test for proportions;
T.S. = [tex]\frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+\frac{\hat p_2(1-\hat p_2)}{n_2} } }[/tex] ~ N(0,1)
where, [tex]\hat p_1[/tex] = sample proportion of employed workers who have registered to vote = [tex]\frac{287}{513}[/tex] = 0.56
[tex]\hat p_2[/tex] = sample proportion of unemployed workers who have registered to vote = [tex]\frac{280}{604}[/tex] = 0.46
[tex]n_1[/tex] = sample of employed persons = 513
[tex]n_2[/tex] = sample of unemployed persons = 604
So, the test statistics = [tex]\frac{(0.56-0.46)-(0)}{\sqrt{\frac{0.56(1-0.56)}{513}+\frac{0.46(1-0.46)}{604} } }[/tex]
= 3.349
The value of z test statistics is 3.349.
Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.
Since our test statistic is more than the critical value of z as 3.349 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.
Therefore, we conclude that the percentage of employed workers who have registered to vote exceeds the percentage of unemployed workers who have registered to vote.