A nuclear weapon in which enormous energy is released is called

The catapult is basically a type of simple lever or first class lever, which is a device used to transmit force and displacement to an object, by means of the amplification of the applied mechanical force, thus increasing its speed or distance traveled.

These simple levers are composed of a rigid bar that can rotate freely around a point of support (the fulcrum). However what differentiates them from the other levers is that the fulcrum is between the point where the effort must be applied and the point where the resistance  is.

With this configuration it is posssible to make several arrangements, depending on the purpose to be achieved, either control and decrease the speed and distance traveled by the object or increase it.

A catapult is a simple machine that functions largely as a lever, one of the classical types of simple machines that provides a mechanical advantage by altering force and distance.

A catapult is a simple machine that utilizes the principles of a lever to multiply the force applied to it. Simple machines are devices that can be used to multiply or augment a force that we apply. The catapult lever operates by converting stored energy into kinetic energy, effectively using the conservation of energy principle. When designing a  small catapult to try at home, you can use materials such as rubber bands, spoons, popsicle sticks, or small plastic containers to create a device that demonstrates this principle.

Simple machines like the lever, nail puller, wheelbarrow, and crank are designed to give us a mechanical advantage. This involves changing the magnitude or direction of forces, helping to perform tasks more easily by requiring less force over a greater distance. Catapults, in particular, allow a small input force to be converted into a much larger output force, launching projectiles over a distance.

Answer:

B

Explanation:

Newton's second law:

F = ma

The acceleration is Δv/Δt, so:

F = m Δv/Δt

Given m = 1300 kg, Δv = 15 m/s, and Δt = 2 s:

F = (1300 kg) (15 m/s) / (2 s)

F = 9750 N

Answer B.

C is the answer if not I’m sorry but I came to the conclusion of C being the answer

Answer:

The answer is A. Because it describes better a semiconductor diode

Explanation:

A semiconductor diode is formed of a junction of P dopped material (excess of electrons), with a N dopped material (absence of electrons). Under the correct polarization, the electron flows from one side to another, other way electrons wont flow.

Answer: They move more slowly, causing the forces of attraction holding them together to increase, resulting in a liquid.

Explanation:

The attraction overcomes the movement of particles, and bonds form.

Answer: One neutron

Explanation:

one neutron 1/0n

Sum up the mass numbers on the right 99 + 135 + 2 = 236.

The sum of the mass numbers on the left should equal 236. 235 + 1 = 236

Only one neutron is needed to initiate a fission reaction in Uranium-235. This initiates a chain reaction where released neutrons cause further fission. However, not all neutrons result in further fission, as some may escape or interact without causing a split.

To initiate a fission reaction in Uranium-235, only one neutron is needed. As the process begins, the uranium-235 nucleus absorbs a neutron, making it an unstable uranium-236 nucleus. This unstable nucleus then breaks down into two smaller nuclei, releasing a large amount of energy in the process. Additionally, two or three neutrons are also released during the breakdown of the unstable uranium-236 nucleus. These extra neutrons can in turn go on to initiate fission in other uranium-235 nuclei, leading to a nuclear chain reaction. However, not every neutron produced results in further fission as some neutrons may escape the material or interact with a nucleus without causing it to split.

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Answer:

Speeed

Explanation:

The speed of an object is defined as the rate of change of distance:

[tex]v=\frac{d}{t}[/tex]

where

d is the distance covered by the object

t is the amount of time needed to cover that distance

Speed is measured in meters per second (m/s). It should be noted that speed is a scalar quantity, so it only has a magnitude (and no direction).

Answer:

[tex]3 m/s^2[/tex]

Explanation:

Newton's second law states that:

[tex]\sum F = ma[/tex]

where

[tex]\sum F[/tex] is the resultant of the forces acting on an object

m is the mass of the object

a is the acceleration

In this case we have two forces:

F = +70 N (east direction) is the horizontal push

Ff = -10 N (west direction) is the frictional force

so the net force is

[tex]\sum F=70 N - 10 N = 60 N[/tex]

We also know the mass of the crate

m = 20 kg

So we can find the acceleration

[tex]a=\frac{sum F}{m}=\frac{60 N}{20 kg}=3 m/s^2[/tex]

The amswer is a i think cuz it make semse

Answer:

Cleavage

Explanation:

Toughness is the resistance of a solid to breakage. The tougher a solid is, the less likely it would succumb to breakage of any form.

Hardness is very similar to toughness and it describes how unyielding a sold is to pressure or force of any form.

Cleavage on the other hand describes the tendency or ability of a solid to spilt or be broken along a specified plane of weakness. When such a solid is hit hard, they show some fracturing directions which represents weaknesses in their lattice structures or crystal forms. Most solids have cleavage directions in them.

Answer:

The Moon’s shadow falls on Earth.

The Moon is between Earth and the Sun.

Explanation:

Eclipses are known as game of shadows. During an eclipse shadow of an object falls on another object. From the perspective of Earth we can see two kind of eclipses: Lunar and Solar.

In Solar eclipse, the Moon lies in between our planet the Earth and the Sun such that they are in the same line. Shadow of Moon will fall on Earth. Looking from the Earth, the Sun will look like it has been hidden by the Moon.

Final answer:

A solar eclipse occurs when the Moon moves between the Sun and Earth, casting a shadow on Earth. Total solar eclipses happen when the Moon's umbra reaches Earth, while partial eclipses occur within the penumbral shadow. Lunar eclipses differ as they involve the Moon entering Earth's shadow.

Explanation:

During a solar eclipse, the Moon moves between the Sun and Earth, casting its shadow on our planet. If the eclipse is total, it occurs when the umbra, the Moon's darkest shadow, reaches the surface of the Earth, covering the Sun completely for a brief time. This results in the solar atmosphere, known as the corona, becoming visible. During the eclipse, the observers within the penumbra, a lighter shadow, will see only a partial covering of the Sun, known as a partial solar eclipse. A solar eclipse requires a specific alignment on the ecliptic plane, which is the plane of Earth's orbit around the Sun. In contrast, a lunar eclipse takes place when the Moon passes into Earth's shadow and is visible from the entire night hemisphere of our planet.

Regarding the options given in the question:

The notions that Earth is closest to the Sun and that the Moon is covered in Earth's shadow describe other phenomena, not a solar eclipse. Additionally, tides may be affected during a solar eclipse but are not specifically mentioned in the context of the eclipse itself.

Answer:

[tex]1.6726\cdot 10^{-27} kg[/tex]

Explanation:

The three main particles that make an atom are:

- Proton: its mass is [tex]1.6726\cdot 10^{-27} kg[/tex], it carries an electric charge of +e ([tex]e=1.6\cdot 10^{-19}C[/tex]), and it is located in the nucles of the atom

- Neutron: its mass is [tex]1.6749 \cdot 10^{-27}kg[/tex], it carries no electric charge, and it is also located in the nucleus of the atom

- Electron: its mass is [tex]9.1094 \cdot 10^{-31}kg[/tex], it carries an electric charge of -e ([tex]e=1.6\cdot 10^{-19}C[/tex]), and it is located outside the nucleus

1. 3.20 m/s

Assuming the string is inextensible, the cart and the weight travels the same distance: so, since the cart travels for 0.521 m, the distance travelled by the weigth is the same:

d = 0.521 m

The motion of the weigth is a free-fall motion with acceleration g = 9.8 m/s^2, so its final speed can be found by using the equation

[tex]v^2 = u^2 + 2gd[/tex]

where

u = 0

is the initial speed of the weigth (at rest). Substituting into the formula, we find

[tex]v=\sqrt{0+2(9.8 m/s^2)(0.521 m)}=3.20 m/s[/tex]

2. 1.022 J

The change in kinetic energy of the system is equal to the sum of the kinetic energies acquired by the cart and the weight. They both started from rest, so their initial kinetic energies were zero.

The cart has

mass: m = 1.000 kg

final speed: v = 0.931 m/s

so its gained kinetic energy is

[tex]K_c = \frac{1}{2}mv^2=\frac{1}{2}(1.000 kg)(0.931 m/s)^2=0.433 J[/tex]

The weight has

mass: m = 0.115 kg

final speed: v = 3.20 m/s

so its gained kinetic energy is

[tex]K_w = \frac{1}{2}mv^2=\frac{1}{2}(0.115 kg)(3.20 m/s)^2=0.589 J[/tex]

So the change in kinetic energy of the system is

[tex]\Delta K= K_f - K_i = (0.433 J+0.589 J)-0=1.022 J[/tex]

3. -5.693 J

The potential energy of the falling cart decreases by the following amount:

[tex]\Delta U = mg \Delta h[/tex]

where

m = 1.000 kg is the mass

g = 9.8 m/s^2

[tex]\Delta h = -0.521 m[/tex] is the change in height of the cart

Substituting, we find

[tex]\Delta U=(1.000 kg)(9.8 m/s^2)(-0.521 m)=-5.106 J[/tex]

the potential energy of the falling weight decreases by the following amount:

[tex]\Delta U = mg \Delta h[/tex]

where

m = 0.115 kg is the mass

g = 9.8 m/s^2

[tex]\Delta h = -0.521 m[/tex] is the change in height of the weight (calculated at point a)

Substituting, we find

[tex]\Delta U=(0.115 kg)(9.8 m/s^2)(-0.521 m)=-0.587 J[/tex]

So, the change in potential energy is

[tex]\Delta U = -5.106 J-0.587 J=-5.693 J[/tex]

4. +4.671 J

The change in thermal energy of the system due to friction is equal to the loss in mechanical energy of the system.

The system has gained a kinetic energy equal to

[tex]\Delta K=+1.022 J[/tex]

while it has lost a potential energy equal to

[tex]\Delta U =-5.693 J[/tex]

So the loss in mechanical energy of the system is

[tex]\Delta E=\Delta K+\Delta U=+1.022 J-5.693 J=-4.671 J[/tex]

So the change in termal energy is

[tex]\Delta E_{th} = -(\Delta E)=-(-4.671 J)=+4.671 J[/tex]

The 30-gram bullet fired and 50-gram bullet dropped from the same height, ignoring air resistance, will hit the ground at the same time. The reason is that the acceleration due to gravity is a constant and act only vertically downward. If air resistance were present, the fired bullet would hit the ground first due to deceleration caused by air resistive force.

The subject of this question is Physics, and it deals with the concept of free fall and projectile motion. Free fall is a type of motion in which an object falls downward due to gravitational force only, with no other forces having an impact. Projectile motion is the motion of an object that is launched into the air and subject to gravity and air resistance.

In this case, we are asked which of the two objects, a bullet fired horizontally and another dropped directly downward from the same height, will hit the ground first, ignoring air resistance. The surprising answer is that they hit the ground at the same time. While the fired bullet travels a further horizontal distance, the vertical component of its motion behaves just like that of the dropped bullet. Therefore, both bullets hit the ground simultaneously.

However, if air resistance is taken into account, the bullet will decelerate quicker due to its higher speed resulting in a greater air resistive force. This would cause the fired bullet to hit the ground first. This is derived from the fundamental laws of Physics that describe the effect of gravity on an object's motion. The acceleration due to gravity is a constant and acts only vertically downward, therefore, it affects both scenarios the same, making both bullets hit the ground at the same time in vacuum.

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Answer:

Light entering  through a small hole in a door is an example if Diffraction.

Explanation:

Slight bending of light passing  through an edge or  opening  of an object is called as diffraction of light.  The rate of bending of light depends on the size of slit or opening in the object and relative size of light’s wavelength.

If the slit or the opening is much larger than the wavelength of the light, the bending  of the light will be almost  smaller and becomes unnoticeable. If  both the slit and the opening are equal in  size, the light bends to an considerable amount.There are two types of diffraction namely  Fraunhoffer diffraction and Fresnel diffraction.

-- The 'pole star', Polaris, is always nearly stationary in the sky.  

-- It's located almost straight overhead when seen from the north pole.  

-- When viewed from the equator, Polaris is right on the northern horizon.

-- Looking from anywhere in the southern hemisphere (south of the equator), Polaris is below the horizon, and can't be seen at all.  

A person who was born and raised in the southern hemisphere, and who has never crossed the equator, has never seen Polaris, the "North Star" !

Polaris, known as the pole star, appears nearly overhead at the North Pole. As one moves towards the equator, Polaris drops closer to the horizon and is directly on the northern horizon when viewed from the equator. This appearance changes due to Earth's rotation and the precession of the equinoxes, meaning Polaris won't always be the pole star.

The pole star, Polaris, occupies a special position in the sky nearly aligned with Earth's rotational axis. At the North Pole, Polaris appears almost directly overhead. However, as one travels towards the equator, the angle at which Polaris is seen decreases. This is because the celestial sphere appears to turn around the Earth's axis, and Polaris is situated close to the north celestial pole. Thus, at the equator, Polaris is positioned right at the northern horizon, and as one goes further south,

it is no longer visible. Instead, one can observe the southern celestial pole. It is interesting to note that the close alignment of Polaris with the north celestial pole is temporary in the grand scheme of Earth's history due to the precession of the equinoxes. In the past, other stars, like Thuban, have served as the pole star, and in the future, Polaris will no longer hold that position.

The Mariner 10 probe was launched by NASA on November 3rd, 1973, with the purpose of exploring the characteristics of two planets in the solar system that were closest to the Sun, Mercury and Venus.

In addition, it was launched to explore the atmosphere and surface of both planets and prove that it was possible to use gravitational assistance (also called slingshot effect, a special orbital maneuver in order to use the gravitational field energy of a planet or massive body to accelerate or slow the probe and change the direction of its trajectory) in long interplanetary trips to save fuel.

In this case, Mariner 10 first arrived at Venus and succeded in using its gravitational field to accelerate its trajectory towards Mercury.

Mariner 10 was the first spacecraft to visit Mercury in 1974, transmitting over 2000 detailed photographs of the planet's surface.

The planet that Mariner 10 first visited in 1974 is Mercury. On its flyby, Mariner 10 passed 9,500 kilometers from the surface of Mercury and sent back more than 2000 photographs. These photographs were groundbreaking, offering detailed views with a resolution down to 150 meters and marking a milestone in space exploration. Mercury is the 1st planet in the solar system of Milky way and it is comparatively much smaller than the Earth.

Answer:

3/7 ω

Explanation:

Initial momentum = final momentum

I(-ω) + (2I)(3ω) + (4I)(-ω/2) = (I + 2I + 4I) ωnet

-Iω + 6Iω - 2Iω = 7I ωnet

3Iω = 7I ωnet

ωnet = 3/7 ω

The final angular velocity will be 3/7 ω counterclockwise.

Answer:

[tex]\omega_{net} = 3\omega/7[/tex]

Explanation:

For this problem we will use the conservation of angular momentum. This is, the momenta of each disk added together is equal to the momenta of the single piece at angular velocity [tex]\omega_{net}[/tex]. If

[tex]L_{0} = -I\omega-4I\frac{\omega}{2}+2I(3\omega) \\L_{0} = -I\omega-2I\omega+6I\omega \\L_{0} = 3I\omega\\[/tex],

and because all disks are spinning on the same axle, the total inertia moment of the single piece at angular velocity [tex]\omega_{net}[/tex] is the sum of the inertia moment of the three disks. This way, we have that

[tex]L_{f} = (I+2I+4I)\omega_{net}\\\\L_{f}=7I\omega_{net}\\[/tex].

The conservation of angular momentum leads us to

[tex]L_{0}=L_{f}\\[/tex],

[tex]3I\omega = 7I\omega_{net}\\[/tex],

thus

[tex]\omega_{net} = \frac{3}{7}\omega[/tex].

Answer:

venus

Explanation:

         Answer:

► Venus

         Explanation:

Venus is the hottest planet in the Solar System. It is not the closest, but it is the hottest. Venus's temperature has an average if 462 degrees Celsius. That is 863.6 Fahrenheit.

D. Force is equal to mass times acceleration.

F=ma

m/F=a

a = F ÷ m is the correct equation for acceleration. Hence, option (A) is correct.

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.

Acceleration is a vector quantity since it has both a magnitude and a direction. A vector quantity is also velocity. The velocity vector change during a time interval divided by the time interval is the definition of acceleration.

According to Newton's second law of motion:

Force = mass × acceleration

Hence, acceleration (a) = force (F) ÷ mass (m).

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Answer:

They have a round shape

Explanation:

The gas giants which are the outer planets, and the terrestrial planets which are the inner ones have lot of differences between them. They have different sizes, different composition, different atmospheres, temperatures etc. But they also have something in common, which is pretty much the most obvious thing, they all have round shape. All of the planets have round shape, or rather they are slightly elliptical as they are more elongated around their equators, and slightly more flattened around their poles. This kind of shape has occurred because of these planets spin around their own axis, and around the Sun, thus the surface has become much smoother over time because of the friction.

Answer: they have a round shape

Explanation:

Over the first 2.30 s, the wheel turns by angle [tex]\theta[/tex] according to

[tex]\theta=\left(20.0\dfrac{\rm rad}{\rm s}\right)t+\dfrac12\left(35.0\dfrac{\rm rad}{\mathrm s^2}\right)t^2[/tex]

so that after 2.30 s, it will have turned

[tex]\theta=138.575\,\mathrm{rad}[/tex]

Then the wheel turns a total of [tex]\theta+433\,\mathrm{rad}[/tex] over this entire interval, or [tex]572\,\mathrm{rad}[/tex].

Answer:

the current flowing in each is the same.

Explanation:

When resistors are connected in series, they are connected in the same branch of the circuit - this means that the same current flows through each resistor.

The other options listed are wrong because:

the same power is dissipated in each one --> false: the power dissipated in each resistor is [tex]P=I^2 R[/tex], where I is the current and R the resistance, so it depends on the value of the resistance

the potential difference across each is the same.-- > false: this is true in parallel circuits, not series circuits

the equivalent resistance of the circuit is less than that of the smallest resistor.--> false: the equivalent resistance of a series circuit is the sum of the individual resistances: [tex]R = R_1 + R_2 + ...[/tex], so it is larger than the resistance of the smallest resistance

the equivalent resistance of the circuit is equal to the average of all the resistances. --> false: the equivalent resistance of a series circuit is the sum of the individual resistances: [tex]R = R_1 + R_2 + ...[/tex], not the average

Answer:

Venus

Explanation:

The object will reach a height of 90ft

To solve this exercise we are going to use  the discriminant of the quadratic polynomial ax²+bx+c=0, which is b²-4ac.  

If the discriminant is negative, then there are no real solutions to the equation.

If the discriminant is zero, there is only one solution.

If the discriminant is positive, there are two real solutions.

We have the equation h(t)=18t-16t² which describes the model of the height h (feet) reached in t (seconds) by an object propelled straight up from the ground at a speed of 80 ft/s. We want to use the discriminant to find whether the object will ever reach a height of 90ft.

First, we have to rewrite the equation to the form ax²+bx+c=0 and we know the height that is possible to reach for the object h=90ft.

90 = 80t-16t² ---------->  -16t²+80t-90=0

Using the discriminan equation D = b²- 4ac.

From the quadratic polynomial -16t²+80t-90=0, we have a = -16, b = 80, and c = -90

D = (80)² - 4 (-16)(-90)

D = 6400 - 5760 = 640

Since the discriminant D is positive, the object will reach a height of 90ft.

Answer:

D

Explanation:

because 50.0/10.0 = 5.0

Answer:

D

Explanation:

because 50.0/10.0 = 5.0

Answer:

450 Bq, 0.15325u

Explanation:

Half life equation:

A = A₀ (½)^(t / T)

A = (7200 Bq) (½)^(22 min / 5.50 min)

A = 450 Bq

Mass defect is the difference between the sum of the proton and neutron masses and the isotope mass.

The mass of a proton is 1.007276u, and the mass of a neutron is 1.008665u.

So the mass defect is:

(8 × 1.007276u + 10 × 1.008665u) − 17.99161u

0.15325u

Answer: The structure of axon bundle in nervous system is just like a telegraph wire.

Explanation: There is structural and functional similarity between the nervous system and telegraph. In a telegraph the wire of the cable are bundled to form a single cable just like the way a group of axons bundle themselves.

Also the axons are covered by a myelin (also known as white matter) to insulate them in a similar way as the plastic coating of an electric wire of telegraph.  Both axon in the nervous system and the telegraph wire send signal across its ends.  

Explanation:

The Drag Force equation is:

[tex]F_{D}=\frac{1}{2}C_{D}\rho A_{D}V^{2}[/tex]   (1)

Where:

[tex]F_{D}[/tex]  is the Drag Force

[tex]C_{D}[/tex]  is the Drag coefficient, which depends on the material

[tex]\rho[/tex]  is the density of the fluid where the bicycle is moving (air in this case)

[tex]A_{D}[/tex] is the transversal area of the body or object

[tex]V[/tex] the bicycle's velocity

Now, if we assume [tex]C_{D}[/tex], [tex]\rho[/tex] and [tex]A_{D}[/tex] do not channge, we can rewrite (1) as:

[tex]F_{D}=C.V^{2}[/tex]   (2)

Where [tex]C[/tex]  groups all these coefficients.

So, if we have a new velocity [tex]V_{n}[/tex] , which is the double of the former velocity:

[tex]V_{n}=2V[/tex]   (3)

Equation (2) is written as:

[tex]F_{D}=C.V_{n}^{2}=C.(2V)^{2}[/tex]

[tex]F_{D}=4CV^{2}[/tex]   (4)

Comparing (2) and (4) we can conclude the Drag force is four times greater when the speed is doubled.

Answer:

im not sure what your asking

Explanation: