Answer:
THE ANSWER IS: Water flows more rapidly out of the ground-floor faucet.
Explanation:
Water flows more rapidly out of the ground-floor faucet.
Why is the water flow more rapid out of a faucet on the first floor of a building than in an apartment on a higher floor?The first floor of a building has the biggest pressure differential, which is why water flows more quickly out of a faucet there than in an apartment on a higher floor. As we move up the structure, however, the pressure difference reduces.How much water does a water tower hold?An average water tower is usually about 165 feet (50 meters) tall, and its tank can hold about a million gallons of water or more.Why does water flow on the flour easily?Proteins: the higher protein content the higher water absorption.Pentosans: the higher the pentosans content the higher the water absorption.Is water pressure lower on higher floors?In actuality, the idea that a building's age affects water pressure is a fiction. However, it is true that in buildings where the roof tank serves as the supply of water, the water pressure at fixtures is lower in upper floor apartments than in lower level apartments.Learn more about municipal water supply here:
https://brainly.com/question/11961382
#SPJ2
Our Sun undergoes slight orbital motion mostly due to the gravitational force exerted by Jupiter. If our solar system only contained Saturn, how would the Sun's orbital period differ?
Answer:
it would be longer
In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x 5 20.0 cm to x 5 60.0 cm. (i) Does the electric po- tential energy of the charge-field system (a) increase, (b) re- main constant, (c) decrease, or (d) change unpredictably
Answer:
(a) increase
Explanation:
On a line graph; we have the x-axis to the positive side and the negative side .In a positive x-axis direction, the force is usually positive, vice versa the negative side as well.
The change in the potential energy of a charge field-system can be given as:
[tex]\delta U= -q(EdsCos \theta)[/tex]
where;
q = positive test charge
E = Electric field
ds = displacement between thee charge positions
θ = Angle between the electric field and the displacement.
Given that:
Charge of the particle = -q
displacement = (60.0 -20.0)cm = 40.0 cm
θ = 0
Replacing our values in the above equation, we have:
[tex]\delta U = -(-q)(60Cos 0)[/tex]
[tex]\delta U = qEds[/tex]
Since the potential energy of the system is positive, therefor the electric potential energy also increases.
The electric potential energy of a system consisting of a negatively charged particle in a uniform electric field increases when the particle is moved in the same direction as the field.
Explanation:The electric potential energy of the charge-field system increases as a negatively charged particle is moved in the same direction as the electric field. This is because work is done to overcome the force of the electric field, which opposes the movement of the negatively charged particle. The uniform electric field produces a constant force, and since work is force times distance, the amount of work (and hence energy) increases.
Learn more about Electric Potential Energy here:https://brainly.com/question/33051432
#SPJ3
The acceleration of gravity on the moon is one-sixth what it is on Earth. The radius of the moon is one-fourth that of the Earth. What is the moon's mass
Answer: moon mass = earth mass/96
Explanation:
The moon mass will be 1/96th of the earth mass. There is an attached detailed solution to this.
When you lift a bowling ball with a force of 71.6 N, the ball accelerates upward with an acceleration a. If you lift with a force of 82.3 N, the ball's acceleration is 1.91a. Calculate the weight of the bowling ball.
Answer:
59.84 N
Explanation:
The net force is responsible for the upward acceleration of the bowling ball.
The net force acting on a body accelerates the body in the same direction as that in which the resultant is applied.
Net force = ma
ma = F - mg
In the first case,
F = 71.6 N, a = a m/s²
ma = 71.6 - mg (eqn 1)
In the second case,
F = 82.3 N, a = 1.91a m/s²
m(1.91a) = 82.3 - mg
1.91 ma = 82.3 - mg (eqn 2)
Substitute for ma in (eqn 2)
1.91 (71.6 - mg) = 82.3 - mg
136.756 - 1.91 mg = 82.3 - mg
136.756 - 82.3 = 1.91 mg - mg
0.91 mg = 54.456
mg = 54.456/0.91
mg = 59.84 N
Hence, the weight of the bowling ball = 59.84 N
Hope this Helps!!!
The weight of the bowling ball is 59.84 N
What is the net force?The net force should be held responsible where there is the upward acceleration of the bowling ball. When it should be acted on the body so it should be in a similar direction.
We know that
Net force = ma
So,
ma = F - mg
Now
In the first case,
F = 71.6 N, a = a m/s²
ma = 71.6 - mg (eqn 1)
And,
In the second case,
F = 82.3 N, a = 1.91a m/s²
m(1.91a) = 82.3 - mg
So,
1.91 ma = 82.3 - mg (eqn 2)
Now
1.91 (71.6 - mg) = 82.3 - mg
136.756 - 1.91 mg = 82.3 - mg
136.756 - 82.3 = 1.91 mg - mg
0.91 mg = 54.456
mg = 54.456/0.91
mg = 59.84 N
Hence, the weight of the bowling ball = 59.84 N
Learn more about acceleration here: https://brainly.com/question/16335988
Point sources of air pollution are __________. Question 9 options: all the hydrocarbons produced by trees in the Smoky Mountains specific spots--such as a factory's smokestacks--where large quantities of pollution are discharged the diffuse release of pollution from autos and homes into the atmosphere the release of pollution from many unidentifiable sources
Answer:
Smoky Mountains specific spots--such as a factory's smokestacks--where large quantities of pollution are discharged
Explanation:
Point source pollution is characterized by the following components:
It is a single sourceThe source is identifiableThe source is known to release pollutants into the environmentFrom the options, Smoky Mountains specific spots--such as a factory's smokestacks--where large quantities of pollution are discharged ticked all the necessary box for a point source pollution.
The battery is now disconnected from the plates and the separation of the plates is doubled ( = 0.78 cm). What is the energy stored in this new capacitor?
Answer:
The energy stored in this new capacitor is [tex]4.4514\times10^{-9}\ J[/tex]
Explanation:
Suppose, Two parallel plates, each having area A = 2180 cm² are connected to the terminals of a battery of voltage [tex]V_{b}= 6\ V[/tex] as shown. The plates are separated by a distance d = 0.39 cm.
We need to calculate the charge
Using formula of capacitance
[tex]C=\dfrac{Q}{V}[/tex]
[tex]\dfrac{Q}{V}=\dfrac{\epsilon_{0}A}{d}[/tex]
[tex]Q=V\times\dfrac{\epsilon_{0}A}{d}[/tex]
Put the value into the formula
[tex]Q=6\times\dfrac{8.85\times10^{-12}\times2180\times10^{-4}}{0.39\times10^{-2}}[/tex]
[tex]Q=2.968\times10^{-9}\ C[/tex]
The distance between the plates is doubled.
We need to calculate the new capacitance
Using formula of capacitance
[tex]C'=\dfrac{\epsilon_{0}A}{d}[/tex]
Put the value into the formula
[tex]C'=\dfrac{8.85\times10^{-12}\times2180\times10^{-4}}{0.78\times10^{-2}}[/tex]
[tex]C'=2.473\times10^{-10}\ F[/tex]
We need to calculate the energy stored in this new capacitor
Using formula of energy
[tex]U=\dfrac{1}{2}C'V^2[/tex]
Put the value into the formula
[tex]U=\dfrac{1}{2}\times2.473\times10^{-10}\times(6)^2[/tex]
[tex]U=4.4514\times10^{-9}\ J[/tex]
Hence, The energy stored in this new capacitor is [tex]4.4514\times10^{-9}\ J[/tex]
3. A powerful motorcycle can produce an acceleration of while traveling at 90.0 km/h. At that speed the forces resisting motion, including friction and air resistance, total 400 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What force does the motorcycle exert backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg
Answer:
Total force = 1257.5N
Explanation:
Acceleration = 3.50 m/s2
Total Mass = 245kg
Force = Mass x acceleration
Force = 245 x 3.50 = 857.5N
Opposing Force = 400N
Total Force = Force of Motorcycle + Opposing force
Total force = 857.5N + 400N
Total force = 1257.5N
As you watch the video, notice that the size of the tidal bulges varies with the Moon's phase, which depends on its orbital position relative to the Sun. Which of the following statements accurately describes this variation? A. Low tides are lowest at both full moon and new moon.
B. High tides are highest at both full moon and new moon.
Answer:
Both
A. Low tides are lowest at both full moon and new moon.
B. High tides are highest at both full moon and new moon.
Explanation:
Tides are formed as a consequence of the differentiation of gravity due to the moon across to the Earth sphere.
Since gravity variate with the distance:
[tex]F = G\frac{m1\cdot m2}{r^{2}}[/tex] (1)
Where m1 and m2 are the masses of the two objects that are interacting and r is the distance Where m1 and m2 are the masses of the two objects that are interacting and r is the distance between them.
For example, see the image below, point A is closer to the moon than point b and at the same time the center of mass of the Earth will feel more attracted to the moon than point B. Therefore, that creates a tidal bulge in point A and point B.
On the other hand, a full moon it gets when Sun, the Earth and the moon are in a line and the moon is reflecting the sunlight.
When the Moon is between the Earth and the Sun it will be illuminated in its back, so it is not possible to see it from the Earth (that is called new moon).
In those two cases mentioned above, the Sun tidal force contributes to the tidal force of the moon over the earth making high tides higher and low tides lower.
In the dangerous "sport" of bungee-jumping, a daring student jumps from a balloon with a specially designed elastic cord attached to his waist. The unstretched length of the cord is 23.4 m, the student weighs 818 N, and the balloon is 31.3 m above the surface of a river below. Calculate the required force constant of the cord if the student is to stop safely 2.74 m above the river. Answer in units of N/m.
Answer:
k = 1755 N/m
Explanation:
Given:
- The length of the cord L = 23.4 m
- Weight of the student W = 818 N
- The elevation of balloon H = 31.3 m
Find:
Calculate the required force constant of the cord if the student is to stop safely 2.74 m above the river.
Solution:
- We know the potential energy of the student changes by
ΔP.E = m*g*( H - 2.74 )
mg*(31.3 - 2.74) = 818*28.56 = 23362.08 J
- When he stops at 2.74 m above ground his KE = 0 so ALL his lost potential energy must be stored in the extended or stretched bungee cord.
- He falls 23.4 m before the bungee cord starts to stretch. That means it doesn't start stretching until he is 31.3 - 23.4 = 7.9 m above the ground.
- It has to stop stretching at 2.74 m above the ground so the
total stretch = 7.9 - 2.74 = 5.16 m
- Therefore his PE from 31.3 m to 2.74 m is stored in a 5.16 m stretch of the bungee cord.
½kx² = ΔP.E
k = 2*ΔP.E / x^2
k = 2*23362.08 / 5.16^2
k = 1755 N/m
Which type of wave is classified as electromagnetic?
A) Sound
B) Light
C) Water
D) Seismic
FOR USA TEST PREP!!!
Answer: B) Light
Explanation: light waves are Electromagnetic waves. Visible light is one of the many types of electromagnetic waves. The others are mechanical waves.
The octet rule states that in chemical compounds atoms tend to have
Answer:
In chemical compounds, atoms tends to have the electron configuration of a noble gas.
Explanation:
The noble gases are unreactive because of their electron configurations. This noble gas neon has the electron configuration of 1s22s22p6 . It has a full outer shell and cannot incorporate any more electrons into the valence shell.
The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas. An exception to an octet of electrons is in the case of the first noble gas, helium, which only has two valence electrons.
The octet rule states that atoms (excluding some exceptions like hydrogen and helium) in a compound strive for eight electrons in their valence shell, making it stable. This is achieved by sharing, accepting or donating electrons. For instance, oxygen in a water molecule gains two electrons from two hydrogen atoms through covalent bonding.
Explanation:The octet rule is a principle in chemistry which states that atoms in chemical compounds tend to achieve a stable electron configuration with eight electrons, a complete 'octet', in their valence shell. Atoms will donate, accept, or share electrons to fulfill this rule. For example, oxygen, which has six electrons in its valence shell, will react with other atoms so as to gain two more electrons, completing its octet. This is achieved through covalent bonding, where electrons are shared between atoms, such as in a water molecule H2O. It is important to note that there are exceptions to this rule, notably hydrogen and helium which are stable with two and helium with two electrons in their valence shell respectively.
Learn more about Octet Rule here:https://brainly.com/question/33717924
#SPJ5
A solenoid used to produce magnetic fields for research purposes is 2.2 mm long, with an inner radius of 25 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.5 TT in the center.
Incomplete question as we have not told which quantity to find.So the complete question is here
A solenoid used to produce magnetic fields for research purposes is 2.2 mm long, with an inner radius of 25 cmcm and 1300 turns of wire. When running, the solenoid produced a field of 1.5 TT in the center.Given this, how large a current does it carry?
Answer:
[tex]I=2.021A[/tex]
Explanation:
Magnetic field B=1.5 T
Length L=2.2mm =0.0022m
Number of turns N=1300 turns
To find
Current I
Solution
From the magnetic at the center of loop we know that:
[tex]B=uI\frac{N}{L}[/tex]
Substitute the given values
[tex]B=uI\frac{N}{L}\\ as\\u=4\pi *10^{-7} T.A/m\\So\\B=uI\frac{N}{L}\\I=\frac{LB}{Nu}\\ I=\frac{0.0022m(1.5T)}{(1300)(4\pi *10^{-7} T.A/m)}\\I=2.021A[/tex]
The toothpick mass was 0.14 g, its speed before entering the branch was 218 m/s, and its penetration depth was 14 mm. If its speed was decreased at a uniform rate, what was the magnitude of the force of the branch on the toothpick
Answer:
= 238N
Explanation:
mass = 0.14g = 14 × 10⁻⁵kg
initial velocity = 218m/s
final velocity = 0
penetration depth (distance) = 14mm = 14 × 10⁻³m
v²(final) = v²(initial) + 2aΔx
0² = (218)² + 2(14 × 10⁻³)a
a = -(218)² / 2(14 × 10⁻³)
a = 16.97 × 10⁵m/s²
F = ma
= (14 × 10⁻⁵)(16.97 × 10⁵)
= 237.58N
≅ 238N
Explanation:
Below is an attachment containing the solution.
Which technique provides a smooth transition from acceleration to braking?
Answer:
Cover-braking technique
Explanation:
Cover braking involves the technique of taking off the foot from the accelerator and hovering it over the braking pedal. The foot must not be placed on the braking pedal to avoid the wear of brake unnecessarily.
It is done usually when an obstacle is expected in front of the moving car. This provides an edge in the reaction time of application of the brakes hence reducing the stopping time.
Regenerative braking and engine braking are techniques used for a smooth transition from acceleration to braking. These techniques convert kinetic and potential energy into electrical energy or use engine power to slow down the vehicle, respectively.
Explanation:The technique that provides a smooth transition from acceleration to braking is commonly recognized in physics and engineering called regenerative braking. Regenerative braking is a central component of the operation of hybrid and electric vehicles. It functions by converting a vehicle's kinetic and gravitational potential energy into electrical energy that recharges the vehicle's battery when deceleration is initiated.
Another method is engine braking, usually applied in larger vehicles like trucks to avoid overheating of brakes specially when traveling downhill.
Both methods, whether it is engine braking or regenerative, provide a smooth progression from accelerated motion to a decrease in speed, or braking. This way, they manage the transition smoothly while conserving and efficiently using energy.
Learn more about Braking Techniques here:https://brainly.com/question/32242758
#SPJ12
Large numbers of ribosomes are present in cells that specialize in producing which molecules?
Answer:
Protein molecules
Explanation:
Ribosomes are the cell organelles that are responsible for the synthesis of protein in the cell. Proteins are the fundamental building blocks and help in repair and damage of cell in the body.
Ribosome is a complex which is made up of protein and RNA. Ribosomes can be found floating within the cytoplasm or attached to the endoplasmic reticulum.
Two eagles fly directly toward one another, the first at 15.0 m/s and the second at 20.0 m/s. Both screech, the first one emitting a frequency of 3200 Hz and the second one emitting a frequency of 3800 Hz. What frequencies do they receive if the speed of sound is 330 m/s?
Answer:
The first eagle hear a frequency of 4.23kHz and the second eagle hear a frequency of 3.56kHz
Explanation:
Given that
both eagle are flying towards one another
speed of the first eagle v1 = 15m/s
speed of the second eagle v2 = 20m/s
frequency emitted by the first eagle f1= 3200Hz
frequency emitted by the second eagle f2 = 3800Hz
speed of sound v = 330m/s
[tex]F_1 = (\frac{v + v_2}{v - v_1} )f_1\\F_1 = (\frac{330 + 20}{330 - 15} )(3200)\\= 3.56 \times 10^3Hz\\= 3.56kHz\\[/tex]
the second part
[tex]F_1 = (\frac{v + v_2}{v - v_1} )f_1\\F_1 = (\frac{330 + 15}{330 - 20} )(3800)\\= 4.23 \times 10^3Hz\\= 4.23kHz\\[/tex]
The first eagle hear a frequency of 4.23kHz and the second eagle hear a frequency of 3.56kHz
Atmospheric pressure at sea level has a value of 100kpa. The density of sea water is 1020kg/m-3. At which depth in the sea would the total pressure be 110kpa?
Answer:
1 m
Explanation:
P = Patm + ρgh
110,000 Pa = 100,000 Pa + (1020 kg/m³) (9.8 m/s²) h
h = 1 m
At depth of 1 m the sea would the total pressure be 110kpa.
What is pressure?The physical force applied to an object is referred to as pressure. Per unit area, a perpendicular force is delivered to the surface of the objects. F/A is the fundamental formula for pressure (Force per unit area). Pascals are a unit of pressure (Pa). Absolute, atmospheric, differential, and gauge pressures are different types of pressure.
Given that:
Atmospheric pressure at sea level has a value of p = 100 kPa = 100000 Pa.
The density of sea water is 1020kg/m-3.
Let: at depth of x m the sea would the total pressure be: P =110 kPa = 110000 Pa.
So, P = p + ρgh
⇒ 110,000 Pa = 100,000 Pa + (1020 kg/m³) (9.8 m/s²) h
⇒ h = 1 m
Hence, at depth of 1 m the sea would the total pressure be 110kpa.
Learn more about pressure here:
https://brainly.com/question/12971272
#SPJ2
In a pickup game of dorm shuffleboard,students crazed by final exams use a broom to propel a calculus book along the dorm hallway. If the 3.5 kg book is pushed from rest through a distance of 0.90 m by the horizontal 25 N force from the broom and then has a speed of 1.60 m/s,what is the coefficient of kinetic friction between the book and floor?
Answer:
Coefficient of friction between the book and floor is 0.582.
Explanation:
Using the velocity formula;
v^2 = 2as
a = v^2/(2s)
a = 1.6^2/(2*0.9)
a = 2.56/1.8
a = 1.42 m/s^2
the force necessary to give the book the acceleration is
F = ma = 3.5*1.42 (m is mass of the book i.e. 3.5 kg)
F = 4.98 N
The difference in the force is the friction force, which is
Ff = 25 - 4.98 = 20 N
Ff = mgμ
where μ is coefficient of friction and g is acceleration due to gravity that is 9.8 m/s^2
μ = Ff/mg
μ = 20/(3.5*9.81)
μ = 0.582
Coefficient of friction between the book and floor is 0.582.
This question involves the concepts of the equation of motion and Newton's second law of motion.
The coefficient of kinetic friction between the book and the floor is "".
First, we will find the acceleration of the block by using the third equation of motion:
[tex]2as = v_f^2-v_i^2[/tex]
where,
a = acceleration = ?
s = distance covered = 0.9 m
vf = final speed = 1.6 m/s
vi = initial speed = 0 m/s
Therefore
[tex]a=\frac{(1.6\ m/s)^2-(0\ m/s)^2}{2(0.9\ m)}\\\\a=1.42\ m/s^2[/tex]
Hence, from Newton's second law of motion:
[tex]Net\ Force = Frictional\ Force + F\\Net\ Force = \mu mg+ma[/tex]
where,
Net Force = 25 N
μ = coefficient of kinetic friction = ?
m = mass of the book = 3.5 kg
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]25\ N = \mu(3.5\ kg)(9.81\ m/s^2)+(3.5\ kg)(1.42\ m/s^2)\\\\\mu=\frac{25\ N - 4.98\ N}{34.33\ N}\\\\\mu = 0.58[/tex]
Learn more about Newton's Second Law of Motion here:
brainly.com/question/13447525?referrer=searchResults
The attached picture shows Newton's Second Law of Motion.
The Department of Natural Resources has selected certain species that are on the verge of extinction due to a lack of prey. These species are used for game sport. In an effort to protect the species, the department has started arranging for food for these species. Which method is the department adopting?
Answer:
Habitat manipulation
Explanation:
Habitat manipulation, otherwise known as ecological engineering, is a technique of promoting natural enemies within an ecosystem by making thriving conditions more suitable for them.
In this case, thriving conditions for the species (which happens to be predators and hence, natural enemies) were promoted via artificial introduction of food.
In a vertical dive, a peregrine falcon can accelerate at 0.6 times the free-fall acceleration g (that is, at 0.6 g ) in reaching a speed of about 108 m / s. If a falcon pulls out of a dive into a circular arc at this speed and can sustain a radial acceleration of 0.6 g , what is the radius R of the turn?
The radius R of the turn is 1.984 km.
Explanation:
As the falcon is experiencing a centripetal motion, the acceleration exhibited by the falcon will be centripetal acceleration. The formula for centripetal acceleration is
[tex]a=\frac{v^{2} }{R}[/tex]
Here a is the acceleration for centripetal motion, v is the velocity and R is the radius of the circular path.
As the centripetal acceleration is given as 0.6 g, the velocity is given as 108 m/s, then the radius of the path can be determined as
[tex]0.6 \times 9.8=\frac{(108)^{2}}{R}[/tex]
[tex]R=\frac{(108)^{2}}{0.6 \times 9.8}=\frac{11664}{5.88}=1983.67\ \mathrm{m}[/tex]
So, the radius of the turn is 1.984 km.
a 360 mile trip began on a greeway in a car traveling at 62 mph. Once the road became a 2 lane highway, the car slowed to 54 mph. If the total trip took 6 hours, find the time spent on each type of road
Answer:
Time spent on the greenway road = 4.5 hours
Time spent on the 2 lane road = 1.5 hours
Explanation:
The distance of the trip is 360 miles and the initial speed of the car is 62 miles/hr and after the road became 2 lane highway the car slowed to 54 miles/hr.
Let us divide the trip into two
Greenway
speed = distance/time
speed = 62 mph
time = a
distance = speed × time
distance = 62a
2 lane highway
speed = distance/time
speed = 54 mph
time = b
distance = speed × time
distance = 54b
Total distance
62a + 54b = 360......................(i)
Total time
a + b = 6..............................(ii)
a = 6-b
insert a in equation (i)
62(6-b) + 54b = 360
372 - 62b + 54b = 360
-8b = 360-372
-8b = - 12
b = 12/8
b = 1.5
from equation (ii)
a + 1.5 = 6
a = 6 - 1.5
a = 4.5
Which of the following types of reactions would decrease the entropy within a cell?
digestion
hydrolysis
respiration
dehydration reactions
catabolism
Answer:
dehydration reactions
Final answer:
Dehydration reactions decrease entropy within a cell by building larger molecules from smaller units, unlike catabolic reactions like digestion and respiration which increase entropy by breaking down molecules.
Explanation:
The type of reaction that would decrease the entropy within a cell are dehydration reaction. Entropy is a measure of disorder or randomness in a system, and dehydration reactions are anabolic processes that build larger molecules from smaller ones, thus decreasing entropy. In contrast, catabolic reactions, such as digestion, hydrolysis, and respiration, generally increase entropy in a system by breaking down complex molecules into simpler ones and releasing energy in the process.
We have seen that the heart produces a magnetic field, and that this can be used to diagnose problems with the heart. The magnetic field of the heart is a dipole field that is produced by a loop current in the outer layers of the heart. Suppose the field at the center of the heart is 90 pT (a pT is 10−12T ) and that the heart has a diameter of approximately 12 cm. What current circulates around the heart to produce this field?
Explanation:
The field at the center of circular current can be calculated by
B = [tex]\frac{\mu _0 I}{r}[/tex]
here μ₀ is permeability constant and is equal to 4π x 10⁻⁷
I is the current in circular path and r is the radius of circle
Thus I =[tex]\frac{90x10^-^1^2x12x10^-^2}{4\pi x 10^-^7 }[/tex] = 8.8 x 10⁻⁵ A
The increase of carbon dioxide in the atmosphere has had which effect on the earth’s climate?
How did ernest rutherford discover the nucleus of the atom
Answer:
THE ANSWER IS: Rutherford, Marsden and Geiger discovered the dense atomic nucleus by bombarding a thin gold sheet with the alpha particles emitted by radium
Explanation:
Two flywheels of negligible mass and different radii are bonded together and rotate about a common axis (see below). The smaller flywheel of radius 30 cm has a cord that has a pulling force of 50 N on it. What pulling force needs to be applied to the cord connecting the larger flywheel of radius 50 cm such that the combination does not rotate?
Answer:
Explanation:
Torque on smaller wheel
= F x r
50 x .30
= 15 Nm
Torque on larger wheel
= F x .5
For equilibrium
F x .5 = 15
F = 15 / .5
= 30 N
two cars leave at the same time and travel in opposite directions. one travels 44mi/hr and the other travels 55mi/hr. in how many hours will they be 297 miles apart.
Answer:
In 3 hours, the cars will be 297 miles apart.
Explanation:
Speed=Distance/Time
Distance= Speed X Time
Speed of 1st Car=44 miles/hr
Distance=44 X Time taken = 44t
Speed of 2nd Car=55 miles/hr
Distance=55 X Time taken = 55t
Total Distance Covered by both Cars = 44t + 55t = 99t
The cars are 297 miles apart, therefore:
99t = 297
t = 3 hours
It means that in 3 hours, the distance between the cars is 297 miles.
A 73 kg person is riding in a car moving at 20 m/s when the car runs into a bridge abutment. Calculate the magnitude of the average force (in Newtons) on the person if he is stopped by a padded dashboard that compresses an average distance of 0.16 m
Answer:
The magnitude of average force [tex]F_{avg} =[/tex] [tex]9.125 \times 10^{4} N[/tex]
Explanation:
Given :
Mass of person [tex]m = 73[/tex] Kg
Initial velocity of car [tex]v_{o} = 20 \frac{m}{s}[/tex]
Average distance [tex]x = 0.16[/tex] m
According to the second law of newton.
[tex]F_{avg} = m a[/tex]
From the kinematic equations,
[tex]v^{2}- v_{o} ^{2} = 2ax[/tex]
Where [tex]v_{o} =[/tex] initial velocity, in our case final velocity is zero ([tex]v = 0[/tex])
[tex]a =- \frac{400}{2 \times 0.16} = -1250 \frac{m}{s^{2} }[/tex]
So average force is given by,
[tex]F _{avg} = 73 \times -1250 = -91250[/tex] N
But magnitude of average force is,
[tex]F_{avg} = 9.125 \times 10^{4}[/tex] N
The air in a room with volume 180 m3 contains 0.25% carbon dioxide initially. fresher air with only 0.05% carbon dioxide flows into the room at a rate of 2 m3/min and the mixed air flows out at the same rate. find the percentage p of carbon dioxide in the room as a function of time t (in minutes).
The situation can be modeled with a differential equation taking into account the inflow and outflow rates of carbon dioxide. By resolving this equation, we obtain a function representing the CO2 quantity over time. This can be easily converted into percentage by dividing by the room's volume and multiplying by 100.
Explanation:This problem can be solved using a mathematical model called a differential equation. The percentage of carbon dioxide in the room changes over time due to the input of fresher air and the removal of mixed air.
Let's denote the quantity (not the percentage, the actual quantity) of carbon dioxide in the room at time t by Q(t). Initially, we have Q(0) = 0.0025 * 180 = 0.45 m³.
Carbon dioxide flows into the room at a rate of 0.0005 * 2 = 0.001 m³/min and flows out at the rate proportional to the total quantity present, which is (Q(t) / 180) * 2 = (Q(t) / 90) m³/min. Therefore the situation can be modelled by the differential equation dQ/dt = 0.001 - Q(t) / 90. Here, 0.001 represents the rate on inflow of carbon dioxide, and Q(t) / 90 represents the rate of outflow.
By solving this differential equation, we can obtain the function Q(t) which gives the quantity of carbon dioxide in the room at each moment, and the percentage of carbon dioxide can be obtained by dividing Q(t) by the volume of the room and multiplying by 100 to get a percentage, i.e., p(t) = Q(t)/180 * 100.
Learn more about Differential Equations here:https://brainly.com/question/33433874
#SPJ12
The percentage of carbon dioxide in the room over time can be calculated using differential equations. The resulting function is[tex]p(t) = 0.005 * e^{(t/90)} + 0.02 * e^{(-t/90)}[/tex]. This takes into account both the inflow of fresh air and the mixture exiting the room.
To determine the percentage p of carbon dioxide in the room as a function of time t (in minutes), we need to use principles from differential equations to model the mixing process.
Initially, the volume of the room is 180 m³ containing 0.25% carbon dioxide. Fresh air with 0.05% carbon dioxide flows into the room at 2 m³/min.
Let's denote the amount of carbon dioxide in the room at time t by C(t), measured in cubic meters. The concentration of carbon dioxide p(t) is given by:
[tex]p(t) = ( C(t) / 180 ) * 100[/tex]The rate of change of the carbon dioxide in the room can be written as:
dC/dt = rate of carbon dioxide coming in - rate of carbon dioxide going outThe inflow of carbon dioxide is:
[tex]2 m^3/min * 0.0005 = 0.001 m^3/min[/tex]The outflow of carbon dioxide depends on the concentration in the room:
[tex]outflow = (C(t) / 180) * 2 m^3/min[/tex]Thus, the differential equation becomes:
[tex]dC/dt = 0.001 - (C(t) / 180) * 2[/tex]This simplifies to:
[tex]dC/dt = 0.001 - (2C/180)[/tex][tex]or, dC/dt = 0.001 - (C/90)[/tex]
To solve this, we use an integrating factor. The integrating factor is:
[tex]e^{\int\{(1/90) }dt} = e^{t/90}[/tex]Multiplying both sides by the integrating factor:
[tex]e^{(t/90)} * dC/dt = 0.001 * e^{(t/90)} - (C/90) * e^{(t/90)}[/tex]This simplifies to:
[tex]d/dt [C(t) * e^{(t/90)}] = 0.001 * e^{(t/90)}[/tex]Integrate both sides:
[tex]C(t) * e^{(t/90)} = \int\0.001 * e^{(t/90)}}dt = 0.001 * 90 * e^{(t/90)} + K[/tex]Hence,
[tex]C(t) = 0.09 * e^{(t/90)} + K/e^{(t/90)}[/tex]To find K, use the initial condition C(0):
Initial amount of CO2:
[tex]C(0) = 180 * 0.0025 = 0.45[/tex]Thus,
[tex]0.45 = 0.09 + K[/tex]Therefore, [tex]K = 0.36[/tex].
The solution is:
[tex]C(t) = 0.09 * e^{(t/90)}+ 0.36 * e^{(-t/90)}[/tex]The percentage of CO2 is:
[tex]p(t) = {C(t) / 180} * 100[/tex]This simplifies to:
[tex]p(t) = (0.09 * e^{(t/90)} + 0.36 * e^{(-t/90)}) / 1.8[/tex]Hence:
[tex]p(t) = (1/20) * (0.09 e^{(t/90)} + 0.36 e^{(-t/90)})[/tex][tex]p(t) = 0.005 * e^{(t/90)} + 0.02 * e^{(-t/90)}[/tex]
how does urban planning impact land?
Answer:
Ensures land is used for its designated purposes hence avoiding misuse of land.
Explanation:
The process of urban planning ensures that different land uses are shown such as commercial, residential, public land, forestry and agricultural and institutional lands. This process helps in designing for essential services such as roads, sewarage and water, gas and electricity. In the process, encroachment is controlled and land utilized as planned. Therefore, land is properly utilized while minimizing environmental pollution, leading to sustainable development.