Daguerreotype is defined as the first practical photographic process which was introduced in Paris on January 7, 1839. To make the image permanent, Daguerre used salt solution. The result of his introduced process is a finely defined image with surface which is delicate. The major benefit of daguerreotype is if the images are correctly preserved, the pictures could last forever. Aside from this, since it produces superior quality of outline, it is thus suitable for portraitures.
Final answer:
The major benefit of the daguerreotype process was its ability to produce sharp, clear images with reduced exposure time, making photography more accessible and affordable for the general public in the 19th century.
Explanation:
A major benefit of the daguerreotype process is that it produced exceptionally sharp and clear images with reduced exposure time compared to previous photographic methods. The daguerreotype, invented by Louis Daguerre in 1839, utilized a polished copper plate coated with silver iodide to capture images. Despite the limitation of creating only a single, non-reproducible image, the daguerreotype was the first widely available and relatively affordable photographic technique for the general public, fulfilling the burgeoning middle-class demand for portraiture during that era.
According to your observations, how long does it take for the moon to return to the same position compared to the stars?
Final answer:
The Moon completes its orbit around Earth roughly every 27.3 days, known as a sidereal month. However, it takes approximately 29.5 days for the Moon to return to the same phase, or the same relative position with the Sun, which is known as a synodic month.
Explanation:
The moon orbits Earth and exhibits motion against the background stars. Observing this movement over a few hours, you may notice the Moon shifting eastward, but this movement is small due to the Moon's orbital period of about 29 days for its cycle relative to the Sun.
Specifically, the Moon completes one full sidereal month, or revolution around Earth, in approximately 27.3 days, moving steadily eastward in the sky. The Earth, during this time, also moves along its orbit around the Sun, which means that to complete the lunar cycle and return to the same phase, for example from full moon to full moon, the Moon needs an additional 2.2 days, totaling roughly 29.5 days to sync up with the Sun.
This is why we observe a new moon approximately every 29.5 days. When observing the moon's motion over several nights at the same time, it appears farther east each night, a result of its true orbital motion around Earth.
Over a single evening, the Moon's east to west motion is mainly a result of Earth's rotation on its axis. The combined effects demonstrate that the moon's path is a product of its own orbit and Earth's various motions.
A student compresses the spring in a pop up toy .020 meter if the sprinf has a spring constant of 340 newtons per meter how much energy is being stored in the spring
The potential energy stored in the spring is 0.068 Joule.
What is potential energy?Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.
If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.
Potential energy is a characteristic of systems rather than of particular bodies or particles; for instance, the system made up of Earth and the elevated ball has more potential energy as they become further apart.
Given parameters:
Compression of the spring: Δx = 0.020 meter.
Spring constant: k = 340 Newton per meter.
Hence, The potential energy stored in the spring = 1/2 × k × Δx²
= 1/2 × 340 × 0.020² Joule
= 0.068 Joule.
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You are building a race car. Your goal is to have a car that can go from 0 miles per hour to 80 miles per hour in 2 seconds. You are focusing on the car's
A.Speed.
B .Acceleration.
C.Deceleration.
D.Velocity.
Calculate the longest wavelength visible to the human eye 164 kj mol
The longest wavelength visible to the human eye corresponding to an energy of 164 kJ/mol is 732 nm, which falls in the red spectrum of visible light.
Explanation:In Physics, the energy of light can be determined by its wavelength using Planck's equation: E = hc/λ, where E is the energy, h is Planck's constant, c is the speed of light, and λ is the wavelength. Normally, the energy E is provided in Joules, but in this case, it's provided in kJ/mol. To convert it, we use Avogadro's number (6.022 x 1023 molecules/mol). Therefore, E in Joules = 164 kJ/mol x 103 J/kJ x 1 mol/6.022x1023 molecules = 2.723x10-19 J. Then replace this into the Planck's equation, rearranging for λ, we find that λ = hc/E. Substituting the values for h (6.626x10-34 J.s), c (3.0x108 m/s) and E, we calculate λ as 7.32 x 10-7 meters or 732 nm, which falls in the red spectrum of visible light for human eyes.
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What is a more accurate way to make an observation of an object than with your senses alone?
A. use an appropriate tool to make the same observation
B. make a prediction from previous data
C. make an inference from other observations
D. avoid the use of mathematical equations in recording your observation
Vector vector b has x, y, and z components of 4.00, 4.00, and 2.00 units, respectively. calculate the magnitude of vector
b.
What is a common greenhouse gas containing only hydrogen and oxygen?
You are pedaling a bicycle at 9.8 m/s. the radius of the wheels of the bicycle is 51.9cm. the angular velocity of rotation of the wheels is
Calculate the amount of heat (in kilojoules) required to vaporize 2.97 kg of water at its boiling point. (δhvap
The amount of heat required to vaporize 2.58 kg of water at its boiling point is 5826 kJ.
To calculate the amount of heat required to vaporize 2.58 kg of water at its boiling point, we can use the formula:
Q = m * ΔH_vap
Where:
Q is the heat energy,
m is the mass of the substance (water in this case),
ΔH_vap is the heat of vaporization.
The heat of vaporization of water is approximately 2260 J/g or 2260 kJ/kg.
Now, let's calculate the amount of heat required:
Q = 2.58 kg * 2260 kJ/kg
Q = 5826 kJ
So, the amount of heat required to vaporize 2.58 kg of water at its boiling point is 5826 kJ.
The question probable may be;
Calculate the amount of heat in kilojoules required to vaporize 2.58 kg of water at its boiling point.
A force scale is attached to a stack of books lying on a flat table. 1.What happens to the size of the static frictional force as you begin to pull on the force scale? 2.What happens to the stack of the books if the applied force exceeds the maximum static frictional force? 3.What is the minimum size for the static frictional force, and under what conditions will the minimum static frictional force be observed? 4.What type of friction acts when the books are at rest but a force is exerted?
Which scientific phenomenon helps scientists determine the chemical composition of some stars?
absorption of light in a star’s atmosphere
dispersion of light as it enters Earth’s atmosphere
reflection of light
refraction of light
Answer:
The answer is actually absorption of light in a star’s atmosphere
Explanation:
I chose "dispersion of light as it enters Earth's atmosphere" in a test and got it wrong. It showed the correct answer to be absorption of light in a star’s atmosphere.
what causes the phases of the moon
The lunar phases are produced as a result of the change of the relative positions of the Earth, the Moon and the Sun.
The part of the lunar surface illuminated by the Sun that we can see from the Earth, is changing throughout a cycle that is repeated periodically every 29 days, 12 hours, 43 minutes and 12 seconds.
The answer is: Earth revolving around the sun and the sun's light being reflected off the moon.
Suppose a straight 1.00-mm-diameter copper (density = 8.9 x103 kg/m3) wire could just “float” horizontally in air because of the force due to the earth’s magnetic field, which is horizontal, perpendicular to the wire, and of magnitude 5.0 x 10-5 t. (a) what current would the wire carry?
To solve this question, we balance the magnetic force required to keep a copper wire floating against its gravitational pull. Current comes to be 0.08 A.
Explanation:The problem can be solved using the concept of magnetic force and properties of copper. The force exerted by the Earth's magnetic field must counterbalance the weight of the copper wire to keep it floating. This balance can be represented mathematically as: F(magnetic) = F(gravity), or I * l * B = m * g.
We know the magnetic field strength (B) is given as 5.0 * 10^-5 T and the acceleration due to gravity (g) to be approximately 9.8 m/s^2. The mass (m) of the copper wire can be found using the given density and volume, with the latter obtained from the diameter of the wire. Copper wire usually carries one free electron per atom, which gives us a good approximation for the number (n) of free electrons available for electric current.
Substituting the values into our equation, we can solve for the current (I) that the wire would carry to maintain equilibrium.We can calculate the current to be approximately 0.08A.
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The current in the wire must be 1368 A, assuming that the length of the fire is 1m.
If the wire could just float in air due to the magnetic field, this suggests that the weight of the wire is being balanced out by the magnetic force of the field. The gravitational force and magnetic force will act in the opposite direction, i.e. the force will be directed upwards as the gravitational force always acts downwards. However, the magnitude of both forces will be the same.
From the given information regarding the density and diameter of the wire, one can find the mass of the wire. The density of the wire is given by the formula:
ρ (density) = [tex]\frac{Mass}{Volume}[/tex]
so Mass = m (let) = ρ × Volume, where Volume = πr²l for given radius r and length l. Since the length is missing, let us assume it to be 1 m. Given diameter (d) = 1.00 mm and ρ = 8.9 x10³ kg/m³.
so, m = 8.9 x10³ kg/m³ × πr²l = 8.9 x10³ kg/m³ × π[tex](\frac{d}{2})^2[/tex]l = (8.9 x10³ kg/m³ × 0.785 × 10⁻⁶) kg = 6.98 × 10⁻³ kg
Thus, the gravitational force of the wire [tex]F_g[/tex] = mg = 6.98 × 10⁻³ kg × 9.8 m/s² = 68.404 × 10⁻³ N
Magnetic force on the wire is given by the formula:
[tex]F_B = B I l[/tex], where B is the magnetic field, I is the current, and l is the length of the wire.
∴ [tex]F_B[/tex] = 5.0 x 10⁻⁵ T × I × 1 m
as [tex]F_g = F_B[/tex]
⇒ 5.0 x 10⁻⁵ T × I × 1 m = 68.404 × 10⁻³ N
or, I = (68.404 × 10⁻³ N) ÷ (5.0 x 10⁻⁵ T) = 1368 A
A 5.45-g combustible sample is burned in a calorimeter. the heat generated changes the temperature of 555 g of water from 20.5°c to 39.5°c. how much energy is released by the burning? the specific heat of water is 4.18 j/ (°c × g). 564 j 2,500 j 44,100 j 138,000 j
Why is it useful to calculate average speed?
What do you need to know to be able to determine how far a projectile travels horizontally?
Which distance measurement is the most precise?
a.26.3 miles
b.92.56 kilometers
c.30 centimeters?
The measurement with the highest precision in the given problems is 92.56 kilometers because it is measured to the hundredth of a kilometer.
Explanation:The precision of a measurement is determined by the smallest unit it is measured in. In this case:
a. 26.3 miles is measured to the tenth of a mile.b. 92.56 kilometers is measured to the hundredth of a kilometer.c. 30 centimeters is measured to a whole centimeter.In these options, the measurement with the highest precision is 92.56 kilometers because it is measured to the smallest unit, the hundredth of a kilometer. The more decimal places a measurement has, the more precise it generally is.
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Which indicates that a chemical reaction has occurred? A. a broken egg sinks after its has been sitting out for several days. B. you smell gasoline when you remove the cap on a gas tank. C. an unripe orange on a tree doesn't smell at all
Why would traders find it helpful to tow the cedar logs instead of storing them inside the the ship?
Towing the cedar logs saves valuable cargo space inside the ship.
By towing the cedar logs, traders can maximize the ship's internal storage for other valuable goods, improving the efficiency of their cargo space utilization and potentially increasing the profitability of their voyage.
What is the significance of the nose end marking on a rocket or missile?
Mechanical waves, such as sound waves, travel fastest in what medium?
A 1,200-watt water heater is plugged into a 120-volt outlet and used for 1.5 hours. How much current runs through the water heater?
Answer:
Current (i) = 10 Ampere
Explanation:
As we know that power consumed by the electrical heater is given by the rate of electrical energy consumed by it.
So as we know that electrostatic potential energy of charge is given by
[tex]U = qV[/tex]
now for electrical power we know that
[tex]P = \frac{dU}{dt}[/tex]
[tex]P = \frac{d}{dt}(qV)[/tex]
[tex]P = V\frac{dq}{dt}[/tex]
[tex]P = Vi[/tex]
so now by plug in data in this above equation we have
[tex]1200 = 120 \times i[/tex]
[tex]i = 10 A[/tex]
so current through the water heater will be i = 10 A
A plastic tube allows a flow of 15.9 cm3 /s of water through it. how long will it take to fill a 237 cm3 bottle with water? answer in units of s.
The flow rate of water through a plastic tube is 15.9 cm³/s. It will take approximately 14.905 seconds to fill a 237 cm³ bottle with water.
The flow rate of water through the plastic tube is 15.9 cm³/s. To determine the time taken to fill a 237 cm³ bottle, divide the bottle's volume by the flow rate:
Time (s) = Volume/Flow rate = 237 cm³ / 15.9 cm³/s = 14.905 s
Therefore, it will take approximately 14.905 seconds to fill the 237 cm³ bottle with water.
Which letter shows the type of wave that can be seen by the human eye?
The type of wave seen by human eyes are the visible light waves, having the range of wavelengths from 400 nm to 700 nm.
The given problem is based on the concepts of electromagnetic spectrum. The range or the distribution of electromagnetic radiation as per the frequency and wavelength, is known as electromagnetic spectrum.
As per the given question, the human eye can see the visible light spectrum. These spectrum of light rays can be visible or perceived by the human eye in normal condition, or we can say that the range of wavelengths fall under visible spectrum can be sensed by human eye.
Moreover, the visible light is usually defined as having the range of wavelengths from 400 nm to 700 nm, which are in color range from purple to red. The visible light is generally characterized by the symbol [tex]\lambda[/tex] , also known as Lambda.
Thus, we can conclude that the type of wave seen by human eyes are the visible light waves, having the range of wavelengths from 400 nm to 700 nm.
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Every second, the sun converts _________ of grams of matter into energy.
The sun converts approximately 4 million tons of matter into energy every second through the process of fusion. This conversion of mass into energy is the source of the sun's heat and light.
Explanation:The sun converts approximately 4 million tons of matter into energy every second. This conversion of mass into energy is the source of the sun's heat and light. The process involves the fusion of hydrogen into helium, with about 4 million tons of matter being converted into energy in the process.
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If a car can travel 108 miles on 12 gallons of gas, how far will it go on 18 gallons of gas?
The Bay of Fundy has the greatest tidal ranges on Earth. What can you infer about the Bay of Fundy?
a. It faces the moon more often than other places on Earth.
b. It has many rocky beaches.
c. It is a long, narrow inlet.
d. Its tides cannot be predicted accurately.
C is the answer
The Bay of Fundy has the greatest tidal ranges on Earth. What can you infer about the Bay of Fundy?
a.
It faces the moon more often than other places on Earth.
b.
It has many rocky beaches.
c.
It is a long, narrow inlet.
d.
Its tides cannot be predicted accurately.
Answer:
c.
Explanation:
A man stands on the roof of a 15.0-m-tall building and throws a rock with a speed of 30.0 m>s at an angle of 33.0%1b above the horizontal. ignore air resistance. calculate (a) the maximum height above the roof that the rock reaches; (b) the speed of the rock just before it strikes the ground; and (c) the horizontal range from the base of the building to the point where the rock strikes the ground.
a. [tex]\rm \(h_{\text{max}} = 13.62 \, \text{m}\)[/tex], b. [tex]\rm \(v_{\text{final}} = 34.554 \, \text{m/s}\)[/tex], c. [tex]\rm \(R = 102.756 \, \text{m}\)[/tex]
Given:
Initial height [tex]\rm (\(h_{\text{initial}}\))[/tex] = 15.0 m
Initial speed [tex]\rm (\(v_{\text{initial}}\))[/tex] = 30.0 m/s
Launch angle [tex]\rm (\(\theta\))[/tex] = 33.0°
Acceleration due to gravity (g) = 9.81 m/s²
a. To calculate the maximum height above the roof, we need to find the vertical component of the initial velocity [tex]\rm (\(v_{\text{vertical}}\))[/tex] using trigonometric functions:
[tex]\rm \[v_{\text{vertical}} = v_{\text{initial}} \cdot \sin(\theta)\][/tex]
The time taken to reach the maximum height [tex]\rm (\(t_{\text{max}}\))[/tex] can be calculated using:
[tex]\rm \[t_{\text{max}} = \frac{v_{\text{vertical}}}{g}\][/tex]
The maximum height above the roof [tex]\rm (\(h_{\text{max}}\))[/tex] can be found using kinematic equation:
[tex]\rm \[h_{\text{max}} = h_{\text{initial}} + v_{\text{vertical}} \cdot t_{\text{max}} - \frac{1}{2} g \cdot t_{\text{max}}^2\][/tex]
Substitute the given values:
[tex]\rm \[h_{\text{max}} = 15.0 + (30.0 \cdot \sin(33.0\°)) \cdot \frac{30.0 \cdot \sin(33.0\°)}{9.81} - \frac{1}{2} \cdot 9.81 \cdot \left(\frac{30.0 \cdot \sin(33.0\°)}{9.81}\right)^2 \\= 13.62 \, \text{m}\][/tex]
b. The speed of the rock just before it strikes the ground is the magnitude of the velocity vector [tex]\rm (\(v_{\text{final}}\))[/tex] at that point. We can use the vertical motion equation to calculate [tex]\rm \(v_{\text{vertical}}\)[/tex] at the time it hits the ground:
[tex]\rm \[v_{\text{vertical}} = v_{\text{initial}} \cdot \sin(\theta) - g \cdot t_{\text{total}}\][/tex]
Where [tex]\rm \(t_{\text{total}}\)[/tex] is the total time of flight, which can be found using:
[tex]\rm \[t_{\text{total}} = \frac{2 \cdot v_{\text{vertical}}}{g}\][/tex]
Substitute the given values to find [tex]\rm \(v_{\text{final}}\)[/tex]:
[tex]\rm \[v_{\text{final}} = \sqrt{(v_{\text{initial}} \cdot \cos(\theta))^2 + (v_{\text{initial}} \cdot \sin(\theta) - g \cdot t_{\text{total}})^2} \\= 34.554 \, \text{m/s}\][/tex]
c. The horizontal range (R) can be calculated using:
[tex]\rm \[R = v_{\text{horizontal}} \cdot t_{\text{total}}\][/tex]
Where [tex]\rm \(v_{\text{horizontal}}\)[/tex] is the horizontal component of the initial velocity:
[tex]\rm \[v_{\text{horizontal}} = v_{\text{initial}} \cdot \cos(\theta)\][/tex]
Substitute the values:
[tex]\rm \[R = (30.0 \cdot \cos(33.0\°) \cdot \frac{2 \cdot (30.0 \cdot \sin(33.0\°)}{9.81} \\= 102.756 \, \text{m}\][/tex]
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The student's question involves a physics problem on projectile motion, where kinematic equations and principles like conservation of energy are used to find the maximum height the rock reaches, the speed before impact, and the horizontal range of the throw.
Explanation:The question requires solving a projectile motion problem, involving a man throwing a rock from a building at a certain angle above the horizontal. To solve this, we'll use kinematic equations and principles such as the conservation of energy. To answer the question:
Maximum height above the roof the rock reaches can be found using the vertical component of the initial velocity and the acceleration due to gravity.Speed of the rock just before it strikes the ground involves both the vertical and horizontal components just before impact, calculated using kinematics equations and initial conditions.Horizontal range from the base of the building to where the rock strikes the ground is obtained by considering the horizontal component of the initial velocity and the time it takes for the rock to hit the ground.How many megabytes of data can a 4.7 gigabyte DVD store
Answer:
4,700 MB
Explanation:
A 25kg box fell 200m with an acceleration of 5 m/s2. with what force did it hit the floor when it landed?