Answer: calorimeter.
A calorimeter is a device used to measure the absorption or release of heat in chemical and physical processes.
Explanation:
The word calor means heat in latin. So, the technique or science to measure the transfered (absorbed or released) heat in a chemical or physical process is called calorimetry and the apparatus (device) used is named calorimeter.
The physical principle on which this science is based is the conservation of energy or first principle of thermodynamic.
Heat realeased by a component = heat absorbed by other component.
When does a physical change occur
A physical change occurs when something is altered. Such as cutting a piece of paper or chopping a piece of wood into pieces. Melting ice, breaking glass, evaporating liquids are go through a physical change.
A reaction occurs when solid X is placed into solution Y. As a result, the temperature of the new solution increases by 3°C. The temperature rises another 2°C when more of solid X is added to the solution. What does this indicate about the effect of adding more solid?
The increase in temperature when solid X is added to solution Y indicates an exothermic reaction, and the further increase with additional solid could be due to supersaturation, the disturbance of equilibrium, and additional exothermic reactions.
Explanation:When solid X is added to solution Y and the temperature rises, this indicates an exothermic reaction, or a reaction that releases heat. The solubility of the solid in the solution may also be temperature-dependent, potentially leading to a supersaturated solution if the temperature is cooled after the solute is added. This supersaturated solution is relatively stable, but adding more solid or initiating other forms of agitation can disturb this equilibrium and trigger further reactions, potentially causing additional temperature changes. Note that this behavior is similar to certain hand warmer mechanisms that take advantage of such exothermic reactions and solubility behaviors to generate heat.
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please need help on this please
Answer:1.b
2.c
3.a
4.d
5.c
6.b
7.d
8.d
9.c
10.a
Explanation:
Oxidation/reduction (redox) reactions like this: 2H2(g) + O2(g) ⇒ 2H2O(l) will occur spontaneously. To make the reaction proceed in the reverse direction, you must put energy (electricity) into reaction. This is called
The process is called electrolysis.
Consider the reaction between no and cl2 to form nocl. 2no(g) + cl2(g) ⇌ 2nocl(g) a reaction mixture at a certain temperature initially contains only [no] = 0.50 m and [cl2] = 0.50 m. after the reaction comes to equilibrium, the concentration of nocl is 0.30 m. what is the value of kc at this temperature?
The reaction given is 2NO(g) + Cl2(g) ⇌ 2NOCl(g). The initial concentrations of NO and Cl2 are 0.50 M. At equilibrium, concentration of NOCl is 0.30 M, while concentrations of NO and Cl2 are 0.20 M. The equilibrium constant Kc for this reaction at this temperature is thus calculated to be 9.0 M⁻².
Explanation:The value of Kc at a given temperature for a reaction can be calculated using the equilibrium concentrations of the reactants and products in the chemical equation. The reaction described here is 2NO(g) + Cl2(g) ⇌ 2NOCl(g).
At equilibrium, the concentration of NOCl is given as 0.30 M, while we are not provided with the equilibrium concentrations of NO and Cl2, but we know that initially they were both 0.50 M.
The expression for the equilibrium constant Kc in this case would be: Kc = [NOCl]² / ([NO]² [Cl2])
Therefore, calculating equilibrium concentrations of NO and Cl2 from the balanced chemical equation since each 2 moles of NO and Cl2 react to form 2 moles of NOCl, [NO] = [Cl2] = 0.50M - 0.30M = 0.20M.
Substituting these equilibrium concentrations, the value of the Kc becomes:
Kc = (0.30²) / (0.20² * 0.20) = 9.0 M⁻²
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To determine the pH of a solution using a pH indicator paper, you need a .
Answer:
color key
creating a color key
Have known pH values
Explanation:
To determine the pH of a solution using a pH indicator paper, you need a Colour key.
What is pH value and colour key?pH is a measure of how acidic/basic water is. The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water.pH indicators are weak acids that exist as natural dyes and indicate the concentration of H+ (H3O+) ions in a solution via color change. A pH value is determined from the negative logarithm of this concentration and is used to indicate the acidic, basic, or neutral character of the substance you are testing.Colour key is need determine the pH of a solution.
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In which solution is AgCl most soluble?A. in a solution that is 0.20 M in CaCl2B. in a solution that is 0.20 M in AgNO3C. in a solution that is 0.20 M in KNO3
Answer: option C. in a solution that is 0.20 M in KNO₃.
Explanation:
This question deals with the common ion effect.
Any presence in a solution of a common ion with the solute will decrease its solubility and here you can find why.
AgCl (silver chloride) is highly insoluble in water.
Its solubility equation is given by this equilibrium equation:
AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq)
The constant for this equilibrim is called constant of solubility product and is indicated as Ksp:
Ksp = [Ag⁺][Cl⁻]Then, any increase of the product ions (on the right side of the equilibrium equation), will result, according to Le Chatelier's principle in a shift of the equilibrium toward the left side, this is in an increase of the AgCl(s), meaning that less AgCl will be soluble.
Let's see in which of the given solutions is AgCl most soluble
A. Solution 0.20 M in CaCl₂
CaCl₂ is a ionic compound which also ionizes in solution, given Ca²⁺ and Cl⁻ ions. So, you can see that it will increase the concentration of Cl⁻, which means that the equlibrium AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq), will be shifting to the left, decreasing the solubility of silver chloride.
B. Solution 0.20 M in AgNO₃
AgNO₃ is also a ionic salt which dissociates in water giving Ag⁺ and NO₃ ions. So, it will increase Ag⁺ ions, also shifting the equilibrium AgCl(s) ⇄ Ag⁺(aq) + Cl⁻(aq) to the left, decreasing the solubility of silver chloride.
C. Solution 0.20 M in KNO₃
Since KNO₃ has no common ions with AgCl, it will not affect the equilibrium equation in the same manner and you can expect that AgCl is most soluble in KNO₃.
AgCl is most soluble in the 0.20 M KNO3 solution because it does not provide common ions to AgCl, thus avoiding the reduction of AgCl's solubility due to the common ion effect.
Explanation:The solubility of AgCl (silver chloride) in various solutions can be affected by the common ion effect. However, due to the formation of a two-coordinate complex with chloride ions, AgCl₂⁻, AgCl's solubility in solutions can differ from what the common ion effect alone would predict. The given information states that AgCl is approximately 10 times more soluble in 1.0 M KCl than in pure water, despite the common ion effect suggesting it should be much less soluble.
Given the choices of:
A 0.20 M CaCl₂ solutionA 0.20 M AgNO₃ solutionA 0.20 M KNO₃ solutionAgCl would be most soluble in the solution that does not contain a common ion with AgCl. Because CaCl₂ and KNO₃ are both salts with different ions than Ag+ and Cl−, they would not directly provide a common ion that would decrease the solubility of AgCl through the common ion effect. Whereas the AgNO₃ solution contains Ag+ ions which would vastly decrease the solubility of AgCl due to the common ion effect. Therefore, the AgCl is most soluble in the 0.20 M KNO₃ solution (Choice C), because it does not supply any common ions that could reduce its solubility.
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Imagine you are on a roller coaster. Imagine that you are riding a skateboard or running across a ball field. What are some clues that you are moving?
✯Hello✯
↪ You can see the setting changing around you
↪ You can feel a higher pressure/wind on your face
↪ There is adrenaline going through you
↪ (if this isnt the context you are looking for just comment)
❤Gianna❤
Energy and Specific Heat
1. Draw a graph of an exothermic reaction. Label reactants, products and ∆H.
2. Calculate the amount of energy required to raise the temperature of 3.00g of gold from 45.9 to 93.0°C.
3. 1.70g of a silvery metal requires 1000.J of energy to change its temp from 298K to 2749K. Is the metal pure silver?
Answer:
1. Kindly, see the attached image.
2. 18.369 J.
3. Yes, the metal is pure silver.
Explanation:
1. Draw a graph of an exothermic reaction. Label reactants, products and ∆H.
Kindly, see the attached image that shows the graph of an exothermic reaction.2. Calculate the amount of energy required to raise the temperature of 3.00 g of gold from 45.9 to 93.0°C.
To solve this problem, we can use the relation:Q = m.c.ΔT.
Where, Q is the amount of energy required to raise the temperature of gold (J).
m is the mass of the gold (m = 3.0 g).
c is the specific heat of gold (c = 0.13 J/g.°C).
ΔT is the temperature difference between the initial and final T (ΔT = 93.0 °C - 45.9 °C = 47.1 °C).
∴ Q = m.c.ΔT = (3.0 g)(0.13 J/g.°C)(47.1 °C) = 18.369 J.
3. 1.70 g of a silvery metal requires 1000.0 J of energy to change its temp from 298 K to 2749 K. Is the metal pure silver?
To determine wither the metal is pure or not, we should calculate the specific heat (c) of Ag and compare it with the reported value in the table.As mentioned in details in the second point, we can use the relation:
Q = m.c.ΔT
Q = 1000.0 J, m = 1.70 g, ΔT = 2749 - 298 = 2451 °C.
∴ c = Q/(m.ΔT) = (1000.0 J)/(1.70 g)(2451 °C) = 0.239 J/g.°C ≅ 0.24 J/g.°C.
The calculated value is the same as the value reported in the table, so the metal is pure silver.What type of molecule is formed when a halogen combines with hydrogen
When a halogen combines with hydrogen, a covalent molecule is formed.
When a halogen, such as chlorine (Cl), fluorine (F), bromine (Br), or iodine (I), combines with hydrogen (H), they typically form covalent molecules. In covalent bonding, atoms share electrons to achieve a stable electron configuration. Halogens have one electron missing in their outermost electron shell, while hydrogen needs one more electron to complete its shell. To satisfy these electron needs, they share electrons through a covalent bond.
In hydrogen chloride (HCl), hydrogen shares its electron with chlorine, forming a covalent bond. This sharing allows both atoms to achieve a stable electron configuration. Covalent molecules, in contrast to ionic compounds, involve the sharing of electrons rather than the transfer of electrons, resulting in the formation of discrete molecules with relatively low melting and boiling points.
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Which of the following types of reactions would decrease the entropy within a cell? A. Dehydration reaction, B. Hydrolysis, C. Respiration, D. Digestion, E. Catabolism
A. Dehydration reactions.
Explanation;Dehydration reactions refer to chemical events where a water molecule is lost because of the presence of another reacting molecule.Dehydration reaction is said to cause a decrease in entropy in various cells. Entropy within a cell refers to a state of inner instability secondary to different energies provided by the different molecular components.When the water component is removed, there will be less molecular energy and therefore decreased entropy.How does the charge of one electron compare to that of another electron? How does it compare with the charge of a proton? How do the masses of protons and electrons compare?
Answer:
a) The charge of one electron is the same charge of another electron.
b) The charge of one electron has the same magnitude and opposite sign as the charge of a proton. The charge of an electron is negative by convention and the charge of a proton is positive by convention.
c) The mass of a proton is about 1,836 times the mass of an electron.
Explanation:
1) Electron discovery is due to J.J Thompson who is responsible for the famous experiment of the cathode-rays tube. J.J Thompson, in 1897, found that cathode rays could be deflected by an electric field. He could establish that electrons had negative charge, and also determined the approximate the ratio of its charge to the mass. Yet, he could not determine such magnitudes.
2) Later on, Ernest Rutherford, with the famous gold foil experiment, found that all of the positive charge (proton) and essentially all of the mass of the atom is concentrated in a tiny region which he named the nucleus.
3) Since, the atom has the same number of electrons and protons, and it is neutral, the charge magnitude of the charges electrons and protons are equal.
4) Robert Millikan, 1908 - 1917, was able to determine the charge of the electron, with which the mass was also determined.
The accepted relative values for the subatomic particles are:
Particle Relative mass Relative charge
Proton 1 +1
Neutron 1 0
Electron 1/ 1,836 -1
Answer:
all electrons have same charge. Electron is equal and opp to proton
Protean mass of electron
Explanation:
In the presence of hydrogen sulfide, silver oxidizes to form silver sulfide (silver tarnish). It forms a black film on the surface of silver. 4Ag 2H2S O2→2Ag2S 2H2O One way to reverse the chemical reaction and turn silver sulfide back into silver is by immersing the silver in an aluminum container filled with a hot solution of sodium bicarbonate. Metals like aluminum have a greater affinity for sulfur than silver. This tarnish-removal method uses a chemical reaction to convert the silver sulfide back into silver, resulting in no net loss of silver. The reaction between silver sulfide and aluminum takes place in the presence of a sodium bicarbonate (NaHCO3) solution, resulting in the transfer of sulfur atoms from silver to aluminum, freeing the silver metal and forming aluminum sulfide. The reaction can be summarized as follows: when silver sulfide reacts with aluminum, silver sulfide is reduced to form silver and aluminum is oxidized to form aluminum sulfide. Complete the balanced chemical equation for the reaction, showing the formation of silver metal from silver sulfide in the presence of aluminum metal. Express your answer as the products of a chemical equation. View Available Hint(s) 3Ag2S 2Al → 3 A g 2 S 2 A l →
The equation is:
3AgS2 + 4Al ---> 2Al2S3 + 3Ag
Answer: The balanced chemical equation is written below.
Explanation:
Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.
The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.
[tex]A+BC\rightarrow AC+B[/tex]
The chemical equation for the reaction of silver sulfide with aluminium follows:
[tex]3Ag_2S+2Al\rightarrow 6Ag+Al_2S_3[/tex]
By Stoichiometry of the reaction:
3 moles of silver sulfide reacts with 2 moles of aluminium metal to produce 6 moles of silver metal and 1 mole of aluminium sulfide
Hence, the balanced chemical equation is written above.
What is the ratio of Al ions to S ions in a neutral compound? 1:1 2:1 2:3 3:2
Answer:2:3
Explanation: on edginuity
What are the concentrations of hydroxide and hydronium ions in a solution with a pH of 4.6?
1.3 × 10–4 M H3O+ and 7.7 × 10–11 M OH–
2.5 × 10–5 M H3O+ and 4.0 × 10–10 M OH–
7.9 × 10–6 M H3O+ and 1.3 × 10–9 M OH–
8.7 × 10–7 M H3O+ and 1.1 × 10–8 M OH–
Answer:
2.5 × 10–5 M H3O+ and 4.0 × 10–10 M OH–
Explanation:
pH = - log[H3O+]
Therefore;
pH = - log[H3O+] = 4.6
Hence;
[H3O+] = 10^-4.6
= 2.51 ×10^-5 M
= 2.5 ×10^-5 M
Additionally;
pH + pOH = 14
Thus; pOH = 14 -pH
= 14 -4.6
= 9.4
but; pOH = - log [OH-]
Therefore;
[OH-] = 10^-9.4
= 3.98 × 10^-10 M
= 4 × 10^-10 M
Answer:
2.5 × 10–5 M H3O+ and 4.0 × 10–10 M OH–
When a mercury-202 nucleus is bombarded with a neutron, a proton is ejected. What element is formed?
That will make a gold-202 nucleus.
ExplanationRefer to a periodic table. The atomic number of mercury Hg is 80.
Step One: Bombard the [tex]\displaystyle ^{202}_{\phantom{2}80}\text{Hg}[/tex] with a neutron [tex]^{1}_{0}n[/tex]. The neutron will add 1 to the mass number 202 of [tex]^{202}_{\phantom{2}80}\text{Hg}[/tex]. However, the atomic number will stay the same.
New mass number: 202 + 1 = 203.Atomic number is still 80.[tex]^{202}_{\phantom{2}80}\text{Hg} + ^{1}_{0}n \to ^{203}_{\phantom{2}80}\text{Hg}[/tex].
Double check the equation:
Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.Step Two: The [tex]^{203}_{\phantom{2}80}\text{Hg}[/tex] nucleus loses a proton [tex]^{1}_{1}p[/tex]. Both the mass number 203 and the atomic number will decrease by 1.
New mass number: 203 - 1 = 202.New atomic number: 80 - 1 = 79.Refer to a periodic table. What's the element with atomic number 79? Gold Au.
[tex]^{203}_{\phantom{2}80}\text{Hg} \to ^{202}_{\phantom{2}79}\text{Au} + ^{1}_{1}p[/tex].
Double check the equation:
Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.A gold-202 nucleus is formed.
The equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfers 2 electrons? the equilibrium constant, k, for a redox reaction at 25° c is 7.3 × 107. what is the value of e° if the overall reaction transfers 2 electrons? 0.23 v 0.47 v 0.16 v 0.86 v
Answer:
0.23 V.
Explanation:
∵ ΔG° = -RT lnK.
∴ ΔG° = -RTlnK = -(8.314 J/mol)(298 K) ln(7.3 × 10⁷) = - 44.86 x 10³ J/mol.
∵ ΔG° = - nFE°
∴ E° = - ΔG°/nF = - (- 44.86 x 10³ J/mol)/(2 x 96500 s.A/mol) = 0.2324 V ≅ 0.23 V.
To calculate the value for the standard cell potential (E°) in a redox reaction given the equilibrium constant (K) and the number of electrons transferred, you can use the Nernst equation in a simplified form. The Nernst equation shows the relationship between the cell potential (E), the standard cell potential (E°), the number of electrons transferred (n), and the reaction quotient (Q). Assuming Q=K at equilibrium, solving the equation will provide you the value for E°.
Explanation:The equilibrium constant, K, for a redox reaction is logarithmically related to the reaction's cell potential. The Nernst equation, an essential concept in electrochemistry, can help calculate the standard cell potential, E°, with the provided K and number of electrons transferred.
The Nernst equation in a simplified form, including values for fundamental constants (R and F) and standard temperature (298 K), along with a factor converting from natural to base-10 logarithms, is:
E = E° - (0.0592/n)logQ Where E° is the standard cell potential, n is the number of electrons transferred, and Q is the reaction quotient, essentially a measure of the value of product and reactants concentrations at any point.
From the equilibrium constant K, we can calculate Q. For a redox reaction at equilibrium, Q is equal to K. Given that the overall redox reaction transfers 2 electrons (n=2), the equilibrium constant, K, is 7.3 x 10^7, and assuming that Q=K, the equation simplifies into: E = E° - (0.0592/2)log(7.3 x 10^7). Solving this equation will give you the value for E°.
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How would you describe the sequence of reactions in a hydrogen bomb
A hydrogen bomb relies on a nuclear fission bomb to trigger a fusion reaction between deuterium and tritium using lithium deuteride as the fusion fuel. The explosion is enhanced by a U-238 shell which reflects neutrons back into the fuel and fissions to add to the energy output. This process results in a bomb significantly more powerful than atomic bombs.
Explanation:The construction and subsequent chain of reactions in a hydrogen bomb, or a thermonuclear bomb, typically begin with a nuclear fission bomb. The fission bomb, when exploded, produces extremely high temperatures necessary for fusion to occur. A common method is to use lithium deuteride as the fusion fuel, which is in close proximity to the fission bomb. Upon detonation, the fission bomb's gamma rays heat and compress the fusion fuel. Meanwhile, neutrons from the fission reaction cause the lithium to undergo a reaction to generate tritium: n + 6Li → ³ H + ª He. This newly generated tritium then fuses with deuterium in the reaction 2H+ ³H → He + n + 17.6 MeV, producing helium, another neutron, and a significant amount of energy.
Additional fusion and fission fuels are enclosed within a dense shell of U-238. This uranium shell serves two purposes: it reflects some neutrons back into the fuel to enhance fusion, and the fast-moving neutrons cause the uranium itself to fission, adding to the overall energy output of the bomb.
The first hydrogen bomb was detonated in 1952, but unlike the atomic bomb, a hydrogen bomb has never been used in warfare. Thermonuclear bombs are significantly more powerful than atomic ones - the power of a modern hydrogen bomb is approximately 1000 times that of the bombs dropped on Hiroshima and Nagasaki during World War II.
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Which of the following is the best lewis symbol for oxygen?
The best Lewis symbol for oxygen in O2 is :O=O:, showing a double bond and octets for each oxygen atom. This structure, however, does not explain the paramagnetic properties of oxygen, which are due to unpaired electrons not depicted in the Lewis symbol.
Explanation:The best Lewis symbol for oxygen, when considering the molecule O₂, is :O=O:. This Lewis structure indicates that there is an O=O double bond and each oxygen atom has eight electrons around it, satisfying the octet rule. However, this structure does not account for the paramagnetic properties of oxygen, which experimental studies have shown is due to the presence of two unpaired electrons in each oxygen molecule.
Because the Lewis structure of O₂ is expected to show all electrons as paired, there is a discrepancy with the observed magnetic behavior. Paramagnetism arises in molecules that have unpaired electrons, which is why liquid oxygen is attracted to magnetic fields despite the Lewis structure suggesting otherwise.
A 10.0 ml solution of 0.300 m nh3 is titrated with a 0.100 m hcl solution. calculate the ph after the addition of 10.0 ml hcl.
To calculate the pH after the addition of 10.0 mL of HCl to a 10.0 mL solution of NH3, we need to understand the reaction that occurs between the two. NH3 is a weak base, while HCl is a strong acid. The reaction between NH3 and HCl results in the formation of NH4+ ions and Cl- ions, which will affect the pH of the solution.
Explanation:To calculate the pH after the addition of 10.0 mL of HCl to a 10.0 mL solution of NH3, we need to understand the reaction that occurs between the two. NH3 is a weak base, while HCl is a strong acid. The reaction between NH3 and HCl is:
NH3 + HCl -> NH4+ + Cl-
This reaction results in the formation of NH4+ ions and Cl- ions. Since HCl is a strong acid, it will completely dissociate in water, while NH3 is a weak base, it will only partially ionize. Therefore, after the addition of HCl, the solution will contain NH4+ ions and Cl- ions, which will affect the pH of the solution.
To calculate the pH, we need to determine the concentration of NH4+ ions in the solution. Since the initial solution of NH3 is 0.300 M, the concentration of NH4+ ions will be equal to the concentration of NH3 that has been converted to NH4+. To find this, we can use the stoichiometry of the reaction:
1 mol NH3 = 1 mol NH4+ ions
Therefore, the concentration of NH4+
...
Final answer:
To calculate the pH after the addition of 10.0 mL of 0.100 M HCl to a 10.0 mL solution of 0.300 M NH3, we need to consider the reaction between NH3 and HCl. NH3 is a weak base and HCl is a strong acid. The balanced chemical equation for the reaction is NH3 + HCl → NH4Cl.
Explanation:
To calculate the pH after the addition of 10.0 mL of 0.100 M HCl to a 10.0 mL solution of 0.300 M NH3, we need to consider the reaction between NH3 and HCl. NH3 is a weak base and HCl is a strong acid.
The balanced chemical equation for the reaction is NH3 + HCl → NH4Cl. Here, NH3 reacts with HCl to form NH4Cl.
Since NH3 is a weak base, it will not completely dissociate in water. However, HCl is a strong acid and will dissociate completely. Therefore, the concentration of HCl will be equal to 0.100 M after the addition.
Using the equation, we can determine the number of moles of HCl added and the resulting concentration of HCl in the final solution. Then, the pH can be calculated using the formula pH = -log[H+], where [H+] is the concentration of H+ ions in the solution.
A system at equilibrium contains i2(g) at a pressure of 0.21 atm and i(g) at a pressure of 0.23 atm . the system is then compressed to half its volume. find the pressure of i when the system returns to equilibrium.
The pressure would be 6000 Newton’s
The pressure of I when the system returns to equilibrium is 0.589 atm.
What is equilibrium?Equilibrium is defined as a state of a reversible chemical process in which there is no net change in the quantity of reactants and products.
To calculate the pressure we considered the equation
I2 -> 2Ig
Kp = I² / I2
= (0.23)² / 0.21 = 0.25
I2 at initial = 2 x 0.21 = 0.42
I2 at equilibrium = 0.42 - x
Ig at initial = 2 x 0.23 = 0.46
Ig at equilibrium = 0.46 - 2x
Solving x using equilibrium constant
0.25 = (I)² / I2 = (0.46 + 2x)² / 0.42-x
0.25 (0.42 - x) = (0.46 + 2x)²
0.105 - 0.25x = 0.1764 + 4x²
-0.25 - 4x² = 0.1764 - 0.105
4.25 x² = 0.0714
x² = 0.714 / 4.25
x² = 0.0168
x = 0.129 atm
PI2 = 0.42 + 2x0.129
PI2 = 0.678 atm
PI = 0.46 + 0.129
PI = 0.589 atm
Thus, the pressure of I when the system returns to equilibrium is 0.589 atm.
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Which is a spectator ion in the reaction between these two solutions?
BaBr2(aq) + Na2SO4(aq) →
A. Br– (aq)
B. BaBr2(aq)
C. Ba2+(aq)
D. SO42–(aq)
Im not sure what it is but i will try
BaCl₂(aq) + Na₂SO₄(aq) = BaSO₄(s) + 2NaCl(aq)
Ba²⁺(aq) + 2Cl⁻(aq) + 2Na⁺(aq) + SO₄²⁻(aq) = BaSO₄(s) + 2Na⁺(aq) + 2Cl⁻(aq)
Ba²⁺(aq) + SO₄²⁻(aq)= BaSO₄(s)
The ionic reaction is
Ba2+ + 2 Br- + 2 Na+ + SO42-----> 2 Na+ + 2Br- + BaSO4.
Na+ and Br- are on both sides of the equation so they are spectator ions.
The answer is A Br- (aq).
HELP ASAP PLEASE!!!!
Two organic molecules with the same formula but different structures are called:
1
alkanes
2
alkenes
3
alkynes
4
isomers
5
polymers
The small intestine couldn't work without the _________ because fats couldn't be broken down
This chart shows discrpitions of the atoms for four different substances. Which substance is a solid
Atoms that are bunched together the closest are solids.
a propane tank containing 55l has 2.46 moles of the gas C3 is propane what would the number of moles if 1/2 of the gas is used
= 1.23 moles
Explanation;V1/n1 = V2/n2
V1 = 55 L, n1 =2.46 moles
1/2 of the gas was used and thus; 1/2 or 27.5 L remained.
Therefore;
55 L/2.46 moles = 27.5 L/ n2
n2 = (2.46 × 27.5)/55
= 1.23 moles
The number of moles if 1/2 of the gas is used is mathematically given as
n2= 1.23 moles
What would the number of moles if 1/2 of the gas is used?Question Parameter(s):
a propane tank containing 55l
has 2.46 moles of the gas C3 is propane
Generally, the equation for the volume is mathematically given as
V1/n1 = V2/n2
Therefore
55 L/2.46 = 27.5 L/ n2
n2 = (2.46 * 27.5)/55
n2= 1.23 moles
In conclusion, the number of moles
n2= 1.23 moles
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In an electromagnet, you can increase the strength of the magnetic field by Question 6 options: decreasing the thickness of the wires increasing the number of coils in the wires
The electromagnetic strength can be increased by increasing the number of coils in the wires but not by decreasing the thickness of the wires - there is no mathematical relationship between wire thickness and field strength.
Hope this helps!
Which of the listed statements describes the results of the following reaction? C 6 H 12 O 6 + 6 O 2 → 6 CO 2 + 6 H 2 O + Energy A) C 6 H 12 O 6 is oxidized and O 2 is reduced. B) O 2 is oxidized and H 2 O is reduced. C) CO 2 is reduced and O 2 is oxidized. D) O 2 is reduced and CO 2 is oxidized.
Answer:
Answer: option A) C₆H₁₂O₆ is oxidized and O₂ is reducedExplanation:
1) Chemical equation:
C₆H₁₂O₆ + 6O₂ → 6CO₂+ 6H₂O + Energy2) Oxidation states in the reactants
a) C₆H₁₂O₆
The oxidation state of all H atoms is +1.The oxidation state of all O atoms is -2Here, you will see that the oxidation state of carbon in glucose is zero.
There are 6 atoms of C which may have different oxidation number.
You can work with a more developed formula such as:
O OH OH OH OH OH
║ | | | | |
H - C¹ - C² - C³ - C⁴ - C⁵ - C⁶ - H
| | | | |
H H H H H
C¹ is bonded to one O, one C and one H.∴ C¹ 's oxidation state may be determined from x + (−2) + (0) + (+1) = 0
⇒ x = + 1
C²,C³,C⁴, and C⁵ are bonded to one OH radical, two C atoms, and one H atoms.∴ Their oxidation states are given by:
x + (−1) + 2(0) + (+1) = 0 ⇒ x=0
C⁶ is bonded to one OH, one C, and two H atoms.∴ C⁶ 's oxidation state may be determined from:
x + (−1) + (0) + 2(+1) = +1 ⇒ x = −1
The overall oxidation state of C in that molecules is the algebraic sum of all each of C atom oxidation states: +1 + 0 + 0 + 0 + 0 + (-1) = 0
b) O₂ : since it is alone, its oxidation state is zero.
3) Oxidation states in the products
c) CO₂
Oxidation state of O: -2Oxidation state of C: +4d) H₂O
Oxidation state of O: -2Oxidation state of H: + 14) Changes in the oxidation state
C changed from 0 in the reactats to +4 in the productsO changed from O in the reactants to - 2 in the products5) Conclusion:
Since C increased its oxidation state, it is oxidizedSince O reduced its oxidation state, it is reduced.Answer: option A) C₆H₁₂O₆ is oxidized and O₂ is reducedAnswer:
C₆H₁₂O₆ is oxidized and O₂ is reduced.
Explanation:
A solution of 20.0 g of which hydrated salt dissolved in 200 g H2O will have the lowest freezing point? (A) CuSO4 • 5 H2O (M = 250) (B) NiSO4 • 6 H2O (M = 263) (C) MgSO4 • 7 H2O (M = 246) (D) Na2SO4 • 10 H2O (M = 286) The correct answer is D, but I really don't know WHY, so I ask... Thank you very much for your help and explanation ! :)
Answer:
(D) Na₂SO₄•10H₂O (M = 286).
Explanation:
The depression in freezing point of water by adding a solute is determined using the relation:ΔTf = i.Kf.m,
Where, ΔTf is the depression in freezing point of water.
i is van't Hoff factor.
Kf is the molal depression constant.
m is the molality of the solute.
Since, Kf and m is constant for all the mentioned salts. So, the depression in freezing point depends strongly on the van't Hoff factor (i).van't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass.(A) CuSO₄•5H₂O:
CuSO₄ is dissociated to Cu⁺² and SO₄²⁻.
So, i = dissociated ions/no. of particles = 2/1 = 2.
(B) NiSO₄•6H₂O:
NiSO₄ is dissociated to Ni⁺² and SO₄²⁻.
So, i = dissociated ions/no. of particles = 2/1 = 2.
(C) MgSO₄•7H₂O:
MgSO₄ is dissociated to Mg⁺² and SO₄²⁻.
So, i = dissociated ions/no. of particles = 2/1 = 2.
(D) Na₂SO₄•10H₂O:
Na₂SO₄ is dissociated to 2 Na⁺ and SO₄²⁻.
So, i = dissociated ions/no. of particles = 3/1 = 3.
∴ The salt with the high (i) value is Na₂SO₄•10H₂O.
So, the highest ΔTf resulted by adding Na₂SO₄•10H₂O salt.
The rate of a chemical reaction can be measured as the rate of appearance of any of the products or as the rate of disappearance of any of the reactants. These relative rates of reaction are related through the stoichiometry of the overall reaction. For example, the rate of the reaction shown below can be determined by measuring the initial rate of disappearance of I-, -D[I-]/Dt. ClO3-(aq) + 9I- (aq)+ 6 H+ (aq) → 3I-3 (aq) + Cl-(aq) + 3H2O If the initial rate of disappearance of I- under a given set of experimental conditions is 81.1 x 10-3 M/s then what is the rate of disappearance of ClO3- under those same experimental conditions? Enter your answer with units.
The rate of disappearance of the ClO₃⁻ ion is equal to 9.01 ×10⁻³ M/s.
What is the rate of the chemical reaction?The rate of reaction can be defined as the speed at which the products are produced or the reactants are consumed in a chemical reaction. The rate provides information about the time frame under which a reaction can be completed.
The rate of reaction can be described as the speed of a chemical reaction at which reactants are converted into products. Some reactions are instantaneous, while some take a little longer to reach the final equilibrium.
Given the chemical reaction is:
[tex]ClO_3^-(aq) + 9I^- (aq)+ 6 H^+ (aq) \longrightarrow 3I^{-3} (aq) + Cl^-(aq) + 3H_2O[/tex]
The initial rate of disappearance of I⁻ ion = 81.1 ×10⁻³ M/s.
The rate of disappearance of iodide ion is given by:
[tex]-\frac{D[I^-]}{Dt} =81.1\times 10^{-3}[/tex]
The relation between the rate of disappearance of I⁻ and ClO₃⁻ ion:
[tex]-\frac{D[ClO_3^-]}{Dt} =-\frac{1}{9} \frac{D[I^-]}{Dt}[/tex]
[tex]-\frac{D[ClO_3^-]}{Dt} =-\frac{1}{9} \times 81.1 \times 10^{-3}[/tex]
[tex]\frac{D[ClO_3^-]}{Dt} = 9.01 \times 10^{-3}M/s[/tex]
Therefore, the rate of the disappearance of ClO₃⁻ ion is equal to 9.01 ×10⁻³ M/s when the initial rate of disappearance of I⁻ is 81.1 ×10⁻³ M/s.
Learn more about the rate of reaction, here:
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