Answer:
3.99 kg
Explanation:
The period of a harmonic oscillator is given by:
[tex]T=2 \pi \sqrt{\frac{m}{k}}[/tex]
where
m is the mass attached to the spring
k is the spring constant
In this problem, we know:
k = 712 N/m
T = 0.47 s
Therefore, we can re-arrange the equation to find the mass that should be attached to the oscillator:
[tex]m=\frac{k T^2}{(2 \pi)^2}=\frac{(712 N/m)(0.47 s)^2}{(2 \pi)^2}=3.99 kg[/tex]
A mass of 3.97 kg should be attached.
The student asks what mass should be attached to a spring for a horizontal spring oscillator to oscillate with a period of 0.47 seconds, given the spring constant is 712 N/m and there is no friction. To find the mass, we use the formula for the period T of a simple harmonic oscillator: T = 2π√(m/k), where m is the mass in kilograms and k is the spring constant in newtons per meter. Rearranging the formula to solve for m gives us m = (T/(2π))2 × k.
Plugging in the given values:
Calculate (0.47 / (2π))2 = 0.005577... (rounded to nine decimal places).
Multiply this by the spring constant 712 N/m gives us 0.005577 × 712 = 3.970544 kg.
Therefore, the mass that should be attached to the spring is approximately 3.97 kg.
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how much power would a light bulb have if it used 30 joules of energy every 3 seconds
Given that:
Energy of bulb (Work ) = 30 J,
Time (t) = 3 sec
The power consumption = ?
We know that, Power can be defined as rate of doing work
Power (P) = Work(Energy supplied) ÷ time
= 30 ÷ 3
= 10 Watts
The power consumption is 10 W.
A 0.5-kg ball moving at 5 m/s strikes a wall and rebounds in the opposite direction with a speed of 2 m/s. If the impulse occurs for a time duration of 0.01 s, then the average force (magnitude only) acting upon the ball is ____ Newtons.
Given that:
mass of the ball (m) = 0.5 Kg ,
ball strikes the wall (v₁) = 5 m/s ,
rebounds in opposite direction (v₂) = 2 m/s,
time duration (t) = 0.01 s,
Determine the force (F) = ?
We know that from Newton's II law,
F = m. a Newtons
(velocity acting in opposite direction, so a = ( (v₁ + v₂)/t
= m × (v₁ + v₂)/t
= 0.5 × (5 + 2)/0.01
= 350 N
The force acting up on the ball is 350 N
Please find the equivalent resistance. (the question has been attached below)
Answer:
The final (equivalent) resistance of the circuit is 5 Ohms.
Explanation:
Use the formulas for combining two resistors
(a) in series [tex]R=R_1+R_2[/tex]
(b) in parallel [tex]\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}[/tex]
Steps:
Start simplifying the circuit at the right end (I am indexing the resistors by the index of the current in the schema)
Step 1: combine resistors 5 and 6 (parallel):
R_A = 1/(1/10+1/30)= 30/4 =15/2 Ohm
Step 2: combine 4 and 7 with R_A (series)
R_B = R4+R_A+R7 = 2 + 15/2 + 1/2 = 10 Ohm
Step 3: Resistor 3 with R_B (parallel):
R_C = 1/(1/15 + 1/10) = 6 Ohm
Step 4: Resistor 2 with R_C (parallel):
R_D = 1/(1/12+1/6) = 4 Ohm
Ste 5 Resistor 1 with R_D (series):
R = 1 + 4 = 5 Ohm
The final (equivalent) resistance of the circuit is 5 Ohms.
The planet Jupiter’s mean orbital radius is 5.2025 AU’s. what is the period of Jupiter in earth years?
11.86 years, or around that time it would take about 12 years.
The period of Jupiter's orbit around the sun is 11.862 Earth years.
What is Kepler's law of planetary motion?Kepler's laws of planetary motion are a set of three laws that describe the motion of planets around the sun. They were formulated by the German mathematician and astronomer Johannes Kepler in the early 17th century, based on observations made by the astronomer Tycho Brahe.
Kepler's first law, also known as the law of orbits, states that the planets move in elliptical orbits around the sun, with the sun located at one of the foci of the ellipse.
Kepler's second law, also known as the law of areas, states that the line connecting a planet to the sun sweeps out equal areas in equal times. This means that a planet moves faster when it is closer to the sun and slower when it is farther away.
Kepler's third law, also known as the law of harmonies, relates the period and distance of a planet's orbit to its mass and the mass of the sun. Specifically, it states that the square of a planet's orbital period is proportional to the cube of its average distance from the sun.
These laws helped to revolutionize the field of astronomy and laid the foundation for the later development of Isaac Newton's laws of motion and gravitation.
Here in the question,
We can use Kepler's third law of planetary motion to calculate the period of Jupiter's orbit around the sun, which relates the period of an orbit to the average distance of the planet from the sun.
Kepler's third law states that:
(T^2) / (R^3) = (4π^2) / G,
where T is the period of the orbit, R is the average distance between the planet and the sun, G is the gravitational constant, and π is pi.
To solve for T in Earth years, we need to convert Jupiter's average distance from AU to kilometers (km) and then to meters (m), and we need to convert Earth years to seconds.
1 AU = 149,597,870.7 km
1 year = 365.25 days = 31,557,600 seconds (approx.)
So, Jupiter's average distance from the sun is:
R = 5.2025 x 149,597,870.7 km = 778,547,200 km = 7.785 x 10^11 m
Substituting the values into Kepler's third law, we get:
(T^2) / (7.785 x 10^11 m)^3 = (4π^2) / 6.6743 x 10^-11 m^3/(kg s^2)
Solving for T, we get:
T = ∛[(7.785 x 10^11 m)^3 / ((4π^2) / 6.6743 x 10^-11 m^3/(kg s^2))] = 11.862 Earth years
Therefore, the period of Jupiter's orbit around the sun is approximately 11.862 Earth years.
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What sequence shows electromagnetic waves arranged from shorter to longer wavelengths ?
A. Visible light , infrared radiation, microwaves,and ultra violet rays
B. infrared radiation, Visible light, ultra violet radiation, and microwaves
C. Microwaves, infrared radiation, Visible light , and ultra violet radiation
D. ultra violet radiation,visible light , infrared radiation, and microwaves
so from what i was looking at i think the answer is d because The shorter the wavelength, the higher measure of vitality it produces.So the request is D. Bright beams, Visible light, Infrared, and Microwaves.
what is the final volume of a gas with an initial volume of 200 .0ml if the pressure decreases from 500.0 kpa to 250.0 kpa
Answer:
Given Data:
V2 ?
V1 = 200 ml,
P1 = 500kpa and P2 = 2500kpa
From Boyels law (Ideal gas law) Where temperature remains constant, Pressure is inversely proportional to volume.
P1 .V1 = P2 . V2 ; T=Constant
V2 = (P1.V1) ÷ P2
= (500×200) ÷(250)
= 400 ml
The final volume of the gas is 400 ml.
Note: Increased pressure decreases the volume or decreased pressure increase the volume as they are inversely proportional. Here in our answer pressure decreases from 500 kpa to 250 kpa so volume increases from 200 ml to 400 ml.
Using Boyle's Law, the final volume of a gas with an initial volume of 200.0 mL and an initial pressure of 500.0 kPa decreases to 250.0 kPa is calculated by rearranging the equation P₁V₁ = P₂V₂ to solve for the final volume, resulting in a final volume of 400.0 mL.
Find the final volume of a gas following a decrease in pressure, given the initial volume and the initial and final pressures. To solve this problem, we use Boyle's Law, which states that the pressure of a gas is inversely proportional to its volume when temperature and the amount of gas remain constant. The equation derived from this law is P₁V₁ = P₂V₂, where P₁ and V₁ are the initial pressure and volume, respectively, and P₂ and V₂ are the final pressure and volume.
To find the final volume (V₂), we rearrange the equation to V₂ = (P₁V₁)/P₂. Substituting the given values into the equation, we have:
V₂ = (500.0 kPa × 200.0 mL) / 250.0 kPa
V₂ = (100000.0 kPamL) / 250.0 kPa
V₂ = 400.0 mL
Therefore, the final volume of the gas is 400.0 mL.
which of the following is an inclined plane wrapped around a rod?
A. A Screw
B. A Lever
C. A Wheel and Axle
D. A Pulley
Alright well the Answer to your question is A). Screw
Hope this helps have a nice day : )
If u want i can explain why
Answer:
answer is screw my good fellow
Explanation:
On a hike, you travel 2800 m in 2 h. What is your average speed?
Firstly, to find speed you need to remember the speed formula:
Speed = Distance ÷ Time
You can do it by doing 2800 ÷ 2 but that gives m/h (metres per hour)
So to convert hours into seconds, you multiply 2 by 7200 (amount of second in 2 hours:
2 * 7200 = 14400 seconds
Now we can do distance ÷ time by plugging the values in:
2800 ÷ 14400 = [tex]\frac{7}{36}[/tex] ≈0.194
So the average speed is 0.194m/s (metres per second) Hope this helps!a toy car moves around a loop-the-loop track.The loop is 0.5 high.What is the minimum speed of the car at the top of the loop for it to stay on track?
Answer:
The speed of the car at the apex of the loop must be grater than 2.45 m/s
Explanation:
In order for the car to not fall off the track at the apex of the loop, the norm force of the track at the apex must be greater than zero.
Assuming frictionless life on the track which is also to have a perfectly circular shape near the top (radius being 0.25m), the norm force of the track and gravity both point down and result in the centripetal force:
[tex]F_c=F_N+F_g[/tex]
The formula for centripetal force on a circular trajectory is
[tex]F_c = m\frac{v^2}{r}[/tex]
and so the condition for the car to stay on the track can be written as
[tex]m\frac{v^2}{r} = F_N + mg\implies F_N = m\frac{v^2}{r}-mg>0\\\implies |v| >\sqrt{gr}=\sqrt{9.8\frac{m}{s^2}0.25m}=2.45\frac{m}{s}[/tex]
The speed of the car at the apex of the loop must be grater than 2.45 m/s
The minimum speed of the car at the top of the loop for it to stay on track be 1.57 m/s.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center. In your daily existence, you must have encountered numerous instances of centripetal acceleration. A centripetal acceleration occurs when you drive in a circle, and a centripetal acceleration also occurs when a satellite orbits the earth. Centripetal refers to being in the center.
Given parameters:
Height of the loop: h = 0.5 m.
Radius of the loop be: r = h/2 = 0.25 m.
If the mass of the toy car be m, total force acting on the top of the loop be:
F = mv²/r -mg
For the minimum speed of the car at the top of the loop for it to stay on track: F = 0
⇒ mv²/r -mg = 0
⇒ v = √(gr) = √(9.8×0.25) m/s = 1.57 m/s.
Hence, the minimum speed of the car at the top of the loop for it to stay on track be 1.57 m/s.
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how far will a rubber ball fall on 20 seconds?
Given that:
time (t) = 20 s ,
S = ?
We know that S = ut + 1/2 at² meters
since free fall, a = g = 9.81 m/s² ; u =0 ;
S = 0 + 1/2 × 9.81 × 20²
S= 1962 m
A primary succession does not include any invasive species
True or false
A primary succession does not include any invasive species. This is true statement.
What is primary succession?When a new piece of land is produced or is first exposed, primary succession occurs. This may occur, for instance, when lava solidifies and forms new rocks or when a glacier recedes and reveals bare rocks. In the initial succession, organisms have to start over. First, lichens may cling to rocks, followed by a few small plants capable of surviving without much soil. The term "pioneer species" refers to these.
More and larger plants start to colonize the region as a result of the decomposition of those plants, which gradually helps to create soil. Once sufficient soil has accumulated and sufficient nutrients are accessible, a climax community, such as a forest, is created. In the event that the site is disturbed after this, secondary succession takes place.
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What is the SI unit for momentum
The impulse of the material point is equal to the product of mass and its velocity.
The unit of measurement of the imouls is:
[P] = [m] * [v] = kg * m / s.
Answer:
kg·m/s
Explanation:
The momentum of a body is calculated according to the following formula.
momentum = mass * velocity
Since the SI unit unit for mass is kilogram and the SI unit for velocity is metres/second then the multiplication of both will, algebraically give kg·m/s
which fossil fuel is mostly used for heating and cooking
Natural gas is used for cooking and heating and it is a fossil fuel.
Natural gas is the most used energy sorces in homes
How do climate factors affect temperature patterns where you live?
how do we measure or think of speed in the united states?
I'm not sure what you mean by "think of speed", but the way we measure it is by plugging the numbers into this formula: distance divided by time. If you are trying to find an average speed, then your formula would be: total distance divided by total time. I hope this helped!:)
imagine you are in a sports team, there is one player on you team who is the star athlete. you notice that he/she does not include players who are good as they are; he/she puts down their teammates. how would you encourage this player to be more inclusive and supportive of all the player on the team? create a dialogue with this person.
Final answer:
In order to encourage the star athlete to be more inclusive and supportive, start by acknowledging their talent and having a gentle conversation about their behavior. Emphasize the importance of teamwork and suggest activities to foster inclusivity.
Explanation:
To encourage the star athlete on your sports team to be more inclusive and supportive of all the players, you could have a dialogue with them. Start by acknowledging their talent and achievements and express your admiration for their skills. Then, gently bring up the issue of their behavior towards other players and explain how it affects team dynamics.
Next, emphasize the importance of teamwork and how their support can uplift and motivate other players. Share examples of successful teams that have thrived because of a positive and inclusive team culture. Encourage them to recognize and appreciate the strengths of their teammates.
Suggest activities or team-building exercises that can help foster inclusivity and encourage interactions among all team members. Additionally, remind them of the power of their influence as a star athlete and how they can set an example for others by embracing a supportive and inclusive attitude.
In which situation is maximum work considered to be done by a force
Answer:
Work done is maximum when the movement of object is in line and direction of force.OR
Work done is maximum, when displacement takes place along the direction of force. Work done is given by the equationW = F.S
W = F. S cos Θ
When cos Θ = 0° ; cos 0 = 1
Answer:
The angle between the force and displacement is 0°.
Explanation:
What is the DNA in the G1 stage called?
Final answer:
The DNA in the G1 phase is unreplicated chromosomal DNA, as this phase involves the cell growing and accumulating the necessary components and energy for upcoming DNA replication in the S phase.
Explanation:
Understanding the G1 Phase of Interphase
The G1 phase is the initial stage of the cell cycle and falls under interphase. It is often referred to as the "first gap" mainly because there are no significant changes visible under a microscope during this period. Despite this, the cell is not dormant; it is engaged in vital preparatory activities. During the G1 stage, the cell grows and increases in size, meticulously assembling the basic biochemical compounds needed for DNA replication.
This includes the building blocks of chromosomal DNA and the associated proteins. In addition to this, the cell is also building up sufficient energy reserves necessary to go through the upcoming phase of DNA synthesis or the S phase, where each chromosome is replicated.
Students can take the aspire test in ninth and grade
A. First
B. Tenth
C. Eleventh
D. Twelfth
Answer:
The correct answer is option B, tenth
Explanation:
ASPIRE test is basically given by students of ninth and tenth grade as pre-test to the ACT test. ACT ASPIRE test can be given from third grade till tenth grade. The scoring obtained in this test helps the student, teachers and parents to monitor the preparation of their kids towards completing a successful ACT test.
Apart from ninth and tenth grade , students belonging to lower grades (i.e from 3rd grade to 8th grade) can opt for online test. However, higher grades can opt for both online and paper based test.
Students can take the Aspire test in the ninth and grade Tenth. The correct option is B.
What is the Aspire test?The Aspire test is an assessment designed to measure students' readiness for college and careers. It evaluates their skills in English, math, reading, and science. The test is administered by the ACT organization and is typically taken by students in grades 3-10.
While students in ninth grade may be eligible to take the Aspire test, it is not the earliest grade at which it can be taken, and thus option A. First is not correct. The Aspire test is not typically administered to students in the first grade.
Option C. Eleventh and option D. Twelfth are not correct because by these grades, students may have already taken the ACT or SAT, which are the college entrance exams typically taken during the junior and senior years of high school.
Therefore, the correct option is B. Tenth, as this is the grade level at which most students take the Aspire test.
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Which of the following shows a car holding a steady speed
The answer is the velocity that is in a straight horizontal line.
The second one as the velocity doesn't change over time.
a bowling boal has a mass of 5 kg. what happens to its momentum when its speed increase from 1 m/s to 2 m/s?
Answer:
change in momentum (p) = m. (v₂ -v1)
= 5. (2-1)
momentum = 5 m/s.
Answer:
Momentum also increases (doubles from 5 kgm/s to 10 kgm/s)
Explanation:
the momentum is given by
[tex]p=mv[/tex]
where [tex]p[/tex] is momentum, [tex]m[/tex] is mass of thebowling ball ([tex]m=5kg[/tex]), and [tex]v[/tex] is speed.
The momentum when [tex]v=1m/s[/tex] is:
[tex]p=(5kg)(1m/s)\\p=5kgm/s[/tex]
and the momentum when [tex]v=2m/s[/tex] is:
[tex]p=(5kg)(2m/s)\\p=10kgm/s[/tex]
so we can see that the momentum doubles from 5 kgm/s to 10 kgm/s.
how much work does a 30W engine do if it operates for 40 seconds
Given that :
Power (P) = 30 W ,
time (t) = 40 s,
Work = ?
we know that, power is defined as rate of doing work
Power = Work ÷ time
=> Work = Power × time
= 30 × 40
W = 1200 J
Why will interference occur
Two waves interfere when they run into each other.
The barrier reflects waves that run straight into it. It acts as a wave source and sends wave pulses back up the page towards the incoming waves.
Imagine a loose string tied to a wall. Someone sends two consecutive pulses along the string towards the wall. The first pulse gets reflected right away. It will travel backward towards the person holding the string. Along its way, it will run into the second pulse. The two pulses will interfere. The wall will make the reflected pulse out of phase with the second one. They will end up creating a destructive interference.
So is the case with the water waves running into the barrier. The barrier will send incoming waves back toward where they came from. Reflected waves interfere with incoming ones.
Why are electric motors used in circuits?
An electric motor converts electrical energy into physical movement. Electric motors generate magnetic fields with electric current through a coil. The magnetic field then causes a force with a magnet that causes movement or spinning that runs the motor. Electric motors are used in all sorts of applications.
Please help, I really don't know
Estimate the length of the day if the centripetal acceleration at the equator due to the spinning Earth was equal to the acceleration of free fall (g=9.8 ms⁻²)
Thanks
By setting the formula for centripetal acceleration equal to the acceleration due to gravity and using the known radius of the Earth, we find the speed at the equator. Using this speed to divide the Earth's equator's circumference, we estimate the length of a day to be approximately 1.41 hours or 84 minutes.
Explanation:To estimate the length of the day if the centripetal acceleration at the equator due to the spinning Earth was equal to the acceleration of free fall (g=9.8 ms⁻²), we need to utilize known physical constants and the formula for centripetal acceleration.
The formula for centripetal acceleration is a_c = v²/r, where v is the speed, and r is the radius of the circular path. We set this equal to g (9.8 m/s²), so v²/r = 9.8 m/s2. Given the known radius of Earth R = 6.376 x 10^6 m, we can solve for the speed at the equator v.
From the speed, we can calculate the time it would take for the Earth to complete a single rotation. Since the distance the Earth covers in a day is a circular path around the Earth’s equator, this distance is equal to the Earth's circumference, which is 2πR. Dividing this by the speed gives the length of a day, which we can calculate to be 1.41 hours or approximately 84 minutes.
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What is used to identify elements on the periodic table?
Elements on the periodic table are identified by their atomic number (Z), which indicates the number of protons in an atom's nucleus, and by their unique chemical symbol that may derive from their English or Latin names.
Identifying Elements on the Periodic Table
The periodic table is a tabular arrangement of chemical elements, organized by their atomic number, electron configurations, and recurring chemical properties. Each element on the periodic table is represented by a unique chemical symbol, which is a one-, two-, or three-letter abbreviation of its name. The atomic number, represented by the symbol Z, defines the identity of an element by indicating the number of protons in the nucleus of an atom of that element.
For each element listed in the periodic table, you can find its atomic number above the chemical symbol. This is central to the element's identity, as no two different elements share the same number of protons. Additionally, the element's atomic mass is included in the entry, giving an indication of the relative mass of an atom of that element compared to other elements.
Historical elements with symbols based on their Latin names, such as Fe for iron (ferrum) and Pb for lead (plumbum), may seem unrelated to their English names. The periodic table also helps in identifying elements as metals, nonmetals, and organizes them into groups and periods where elements exhibit similar properties.
The density of an object is .835 g/cm3. If its volume is 34 cm3, what is the mass of the object?
D = m/v
Given:
D: .835 g/cm3
V: 34 cm3
M: ?
M= Dxv
M= .835 g/cm3 x 34 cm3
M= 28.39 g
Answer:
28.39
Explanation:
yes I did the math to
A pendulum makes 36 vibrations in 60 seconds, what is its: Period? And Frequency
Answer:
Period = 1.67 seconds
Frequency = 0.6 Hz
Explanation:
Number of vibrations in 60 seconds = 36
Frequency is defined as vibrations per second.
So, Frequency = 36/60 = 0.6 Hz
Time period is defines as time taken for 1 vibration,
So, Time period = 60/36 = 1.67 seconds.
The period of vibration of a simple pendulum is 1.67 s.
The frequency of vibration of a simple pendulum is 0.6 Hz.
What is frequency of vibration?The frequency of vibration of a simple pendulum is the number of complete oscillation of the pendulum per second.
F = n/t
where;
n is number of vibrationst is time of vibrationF = 36/60
F = 0.6 Hz
What is period of vibration?The period of vibration is the inverse of frequency of vibration.
T = 1/f
T = 1/0.6
T = 1.67 s
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From a window that is 20 m from the ground a stone with a speed of 10m / s is thrown vertically upwards. Calculate:
a) the maximum height reached and the time it takes to reach it
b) the total time that is in the air
a)
consider the motion in upward direction as positive and down direction as negative
Y₀ = initial position of the stone = 20 m
v₀ = initial velocity of the stone = 10 m/s
a = acceleration = - 9.8 m/s²
Y = final position of the stone when it reach the maximum height
v = final velocity at the maximum height = 0 m/s
t = time taken to reach the maximum height
Using the equation
v² = v₀² + 2 a (Y - Y₀)
0² = 10² + 2 (- 9.8) (Y - 20)
Y = 25.1 m
also using the equation
v = v₀ + a t
inserting the values
0 = 10 + (- 9.8) t
t = 1.02 sec
b)
consider the motion in upward direction as positive and down direction as negative
Y₀ = initial position of the stone = 20 m
v₀ = initial velocity of the stone = 10 m/s
a = acceleration = - 9.8 m/s²
Y = final position of the stone when it reach the ground = 0 m
t = time taken to reach the ground
Using the equation
Y = Y₀ + v₀ t + (0.5) a t²
0 = 20 + 10 t + (0.5) (- 9.8) t²
t = 3.3 sec
You are an astronaut in space far away from any gravitational field, and you throw a rock as hard as you can. The rock will: slowly slow down and stop continue at the same speed forever continue to accelerate at the rate it was when it left your hand
the answer to that question is the second option
Drawing from Newton's first law of motion, a rock thrown in space, distant from any significant gravitational field, would continue at the same speed in perpetuity.
Explanation:
In the context of Physics, and in particular Newton's first law of motion, the rock you throw in space, far from any gravitational field, will continue at the same speed forever. This law states that an object will remain at rest or in uniform motion in a straight line unless acted upon by an external force. In space, far from any significant gravitational field, there are essentially no external forces to slow the rock down or change its direction, so it will keep moving at the speed it had when it left your hand.
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