a graduated cylinder is filled to 10.0 mL with water and a piece of granite is placed in the cylinder, displacing the level to 23.7 mL. what is the volume of the granite piece in cubic centimeters

B. Magnesium + Hydrogen Sulfide (Reactors) ---->  Magnesium Sulfide + Hydrogen (Products)

Answer:

B. Mg + [tex]H_{2}S[/tex] ⇒ MgS + [tex]H_{2}[/tex]

Explanation:

There are several types of chemical reactions depending on the reaction mechanisms: combination, single-displacement, double-displacement, combustion, decomposition, combustion and redox reactions.

In this case we have a single-displacement reaction, which means that a new chemical species (Mg) replaces other (H) in a given chemical compound ([tex]H_{2}S[/tex]). It happens because the electronegativity of H (a nonmetal) is greater than the Mg electronegativity.  Thus H attracts the electrons strongly.

That's why there is a transference of electrons from Mg to [tex]H^{+}[/tex]. We can say that Mg reduces [tex]H^{+}[/tex].

Once [tex]H^{+}[/tex] is reduced to H, a covalent bond is formed between two hydrogen atoms, and then [tex]H_{2}[/tex] is released as a gas.

Answer : The concentration can be expressed as, 1.99 M, or 15.1(m/m)%, or 18(m/v)%

Solution : Given,

Volume of solution = 0.5 L = 500 ml        (1 L = 1000 ml)

Mass of solution = 596 g

Mass of oxalic acid, (solute) = 90 g

Molar mass of oxalic acid = 90.03 g/mole

First we have to calculate the concentration in terms of M(molarity).

Molarity : Molarity is defined as the number of moles of solute present in one liter of solution.

Formula used : [tex]M=\frac{w_{solute}}{M_{solute}\times V_s}[/tex]

where,

M = molarity of solution

[tex]w_{solute}[/tex] = mass of solute(oxalic acid)

[tex]M_{solute}[/tex] = molar mass of solute(oxalic acid)

[tex]V_s[/tex] = volume of solution(in liters)

Now put all the given values in this formula, we get

[tex]M=\frac{90g}{90.03g/mole\times 0.5L}=1.99mole/L=1.99M[/tex]

Now we have to calculate the concentration in terms of (m/m)%

(m/m)% : It is defined as the mass of solute present in mass of solution in grams.

Formula used : [tex](m/m)\%=\frac{w_{solute}}{w_s}\times 100[/tex]

where,

[tex]w_s[/tex] = mass of solution

[tex](m/m)\%=\frac{90g}{596g}\times 100=15.1%[/tex]

Now we have to calculate the concentration in terms of (m/v)%

(m/v)% : It is defined as the mass of solute present in one milliliter of solution.

Formula used : [tex](m/v)\%=\frac{w_{solute}}{V_s}\times 100[/tex]

where,

[tex]w_s[/tex] = mass of solution

[tex](m/m)\%=\frac{90g}{500ml}\times 100=18%[/tex]

Any salt, even though it reacts with water, will precipitate out completely when the water is completely evaporated.  If you start with 50 grams of salt, you will end up with 50 grams of salt.

1) The chemical symbol for the atom is selenium.

2) The total number of electrons is 16 electrons in the selenium atom.

3) There are 2 5s electrons are in the atom.

The electron configuration [Kr][tex]5s^24d^{10}5p^4[/tex] corresponds to the chemical element Selenium (Se).

1. Chemical Symbol: The chemical symbol for the atom is Se, representing the element selenium.

2. Number of Electrons: To determine the number of electrons in the atom, you need to add up the electron count in each orbital. In this case, the electron configuration tells us that there are:

- 2 electrons in the 5s orbital.

- 10 electrons in the 4d orbital.

- 4 electrons in the 5p orbital.

So, the total number of electrons is 2 + 10 + 4 = 16 electrons in the selenium atom.

3. Number of 5s Electrons: The electron configuration specifies that there are 2 electrons in the 5s orbital.

In summary, the chemical symbol for the atom is Se, it has 16 electrons, and there are 2 electrons in the 5s orbital of the selenium atom. This electron configuration provides insight into the distribution of electrons in the selenium atom, which is crucial for understanding its chemical behavior and reactivity.

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The  half reaction that occur  at the anode is

Zn (s)→ Zn²⁺ (aq) +  2e⁻

Explanation

Answer: The half reaction occurring at anode is [tex]Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-[/tex]

Explanation:

In a chemical cell, substance getting oxidized always act as anode and the one getting reduced always act as cathode.

Oxidation reaction is defined as the reaction in which an atom looses its electrons. Here, oxidation state of the atom increases.

[tex]X\rightarrow X^{n+}+ne^-[/tex]

Reduction reaction is defined as the reaction in which an atom gains electrons. Here, the oxidation state of the atom decreases.

[tex]X^{n+}+ne^-\rightarrow X[/tex]

For the given chemical cell reaction:

[tex]Zn(s)+2Eu(NO_3)_3(aq.)\rightarrow Zn(NO_3)_2(aq.)+2Eu(NO_3)_2(aq.)[/tex]

Oxidation half reaction (anode):  [tex]Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-[/tex]

Reduction half reaction (cathode):  [tex]Eu^{3+}(aq.)+e^-\rightarrow Eu^{2+}(aq.)[/tex]    ( × 2 )

Here, zinc is loosing electrons and is getting oxidized and europium is gaining electrons and loosing electrons.

Hence, the half reaction occurring at anode is [tex]Zn(s)\rightarrow Zn^{2+}(aq.)+2e^-[/tex]

The new volume  temperature is  = 109.9 K

  calculation

The new volume temperature  is calculated  using Charles law  equation

That is V₁/T₁ =V₂/T₂

where;

V₁ = 4.00 L

T₁ = 293 k

V₂ = 1.5 L

T₂ = ?

make  T₂ the subject of the formula

T₂= V₂T₁/V₁

T₂  = {(1.5 L×  293 k) / 4.00 L} =109.9 K

2 H-H + O=O → 2 H-O-H

There are two moles of H-H bonds and one mole of O=O bonds in one mole of reactants. All of them will break in the reaction. That will absorb

Each mole of the reaction will form two moles of water molecules. Each mole of H₂O molecules have two moles O-H bonds. Two moles of the molecule will have four moles of O-H bonds. Forming all those bond will release

Heat of the reaction:

[tex]\Delta H_{\text{rxn}}[/tex] is negative. As a result, the reaction is exothermic.

Methylene blue indicates the presence of oxidizing agents because it is oxidized itself by these compounds. When electrons are stripped from methylene blue, the resulting molecule imparts a blue color to the solution--giving a clear sign of a chemical change.

Methylene blue appears blue because of its unique molecular structure with an extended system of conjugated pi bonds, which absorbs certain wavelengths of light in the non-blue spectrum. In its oxidized state, it is blue, and in its reduced form, it is colorless.

Methylene blue shows a blue color due to its unique chemical structure. It absorbs certain wavelengths of light within the blue region of the visible spectrum due to its extended system of conjugated pi bonds, i.e., alternate single and double bonds in its molecular structure. Methylene blue does not absorb blue light, but reflects it, making the compound appear blue to our eyes.

Additionally, Methylene blue is known for its reduction-oxidation properties. In an oxidized state, it is blue, while its reduced form is colorless. This means that the molecule can change its color based on whether it is gaining or losing electrons, a property that is utilized in many biological and research applications, including staining cells for microscope viewing and acting as an antidote for certain types of poisonings, like rotenone poisoning.

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The most toxic substance that accumulates in aquarium is ammonia

It is highly toxic to fish present in aquarium

This ammonia is produced due to accumulation of fish or plant waste or unused food in aquarium.

100 centigrams over one gram  is a valid conversion factor. The answer is OPTION D.

A valid conversion factor is a ratio of two equivalent quantities expressed in different units, and it allows you to convert between those units. In this case, centigrams (cg) and grams (g) are both units of mass, but the conversion factor should be based on their relationship as defined in the metric system. In the metric system, there are 100 centigrams in one gram.

This means that one gram is equivalent to 100 centigrams. To convert from grams to centigrams, you would multiply the quantity in grams by 100, and to convert from centigrams to grams, you would divide the quantity in centigrams by 100. The correct conversion factor is a fundamental concept in metric system conversions and scientific measurements.

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a) Answer is: the reasons for the relatively high 3rd ionization energy for magnesium is necause magnesium cation Mg²⁺ has stable electron configuration as noble gas neon and hardly lose electron.

Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

Electron configuration of magnesium ion: ₁₂Mg²⁺ 1s² 2s² 2p⁶.

b) Answer is: calcium has lower 1st ionization energy because valence electron are farther from nucleaus and interaction between protons and electrons are weaker.

Atomic number of magnesium (Mg) is 12, it means that it has 12 protons and 12 electrons.  

Electron configuration of magnesium atom: ₁₂Mg 1s² 2s² 2p⁶ 3s².  

Atomic number of calcium is 20, it means that it has 20 protons and 20 electrons, so atom of calcium is neutral.  

Electron configuration of calcium atom: ₂₀Ca 1s² 2s² 2p⁶ 3s² 3p⁶ 4s².

Magnesium (Mg) and calcium (Ca) are metals from 2. group of Periodic table of elements and have low ionisation energy and electronegativity, which means they easily lose valence electons (two valence electrons).

The ionization energy (Ei) is the minimum amount of energy required to remove the valence electron, when element lose electrons, oxidation number of element grows (oxidation process).

The 3rd ionization energy for magnesium is relatively high due to the removal of an electron from a doubly charged ion. The differences in 1st ionization energies for magnesium and calcium are due to variations in their atomic structures.

a) The relatively high 3rd ionization energy for magnesium can be attributed to the removal of an electron from a doubly charged ion. As more electrons are removed, the remaining electrons are held more tightly by the positive charge of the ion, requiring more energy to remove them. b) The differences in 1st ionization energies for magnesium and calcium are due to variations in their atomic structures. Magnesium has one less electron in its outermost shell compared to calcium, resulting in a stronger attraction between the nucleus and the outermost electron in magnesium, making it more difficult to remove.

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Antacid generally contains sodium bicarbonate in it.

sodium bicarbonate is a base

Now if we add ant acid in water there will be small amount of effervescence in the glass of water.

However if we add the same ant acid in sprite then there will be large amount of uncontrolled effervescence in the glass.

so we can easily distinguish the two types of glass content.

Atoms have energy levels for its electrons. In most cases, those levels fill up from the ground up. Each energy level contains a fixed number of electrons. The number of electrons in a neutral atom of a certain element is also definite. As a result, the number of energy levels those electrons occupy in a ground state atom is certain for an element.

As its name suggests, the periodic table has multiple rows known as periods. Atoms of elements in the same row have the same number of occupied energy levels per atom. This is true only when the atom is neutral and in its ground state.

For example:

Among all occupied energy levels, the level with the highest energy is known as the valence shell. The number of electrons in that level in a neutral atom could predict chemical properties of the atom.

The periodic table is divided into columns. Each column is known as a group. Elements in each group has the same number of electrons in their valence shell. Again, this holds only if the atom is neutral and in its ground state. As a result, elements in each group have similar chemical properties.

For example, both Na and K are found in the leftmost column of the periodic table. Both are group 1 elements. The two elements have similar chemical properties:

The most toxic substance that accumulates in aquarium is ammonia

It is highly toxic to fish present in aquarium

This ammonia is produced due to accumulation of fish or plant waste or unused food in aquarium.

Answer 1: The correct answer is option (B)

Answer 2: The correct answer is option (B)

Explanation 1:

[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]

moles of NaCl = [tex]\frac{\text{given mass of NaCl}}{\text{molar mass of NaCl}}=\frac{200 g}{58.5 g/mol}=3.4188 mol[/tex]

According to reaction, 2 moles NaCl are obtained from 2 moles of Na, then 3.4188 moles of NaCl are obtained from: [tex]\frac{1}{1}\times 3.4188[/tex] moles of Na.

Mass of Na = moles of sodium × Molar mass of sodium

[tex]=23 g/mol\times 3.4188 mol=78.632 g[/tex]

From the given option nearest answer to calculated answer is option (B) that is 78.65 g.

Explanation 2:

[tex]2K+2H_2O\rightarrow 2KOH+H_2[/tex]

moles of potassium(K)= [tex]\frac{\text{given mass of K}}{\text{molar mass of K}}=\frac{23.5 g}{39 g/mol}=0.6025 mol[/tex]

According to reaction, 2 moles of K gives 2 moles of KOH , then 0.6025 moles of K will give : [tex]\frac{1}{1}\times 0.6025 moles[/tex] of KOH

Mass of KOH = moles of KOH × Molar mass of KOH

[tex]0.6025 mol\times 56 g/mol=33.74 g\approx 33.7 g[/tex]

From the given option nearest answer to calculated answer is option (A) that 33.7 g.

Final answer:

To solve the given problems, the stoichiometry of the chemical reactions and the molar masses of the reactants and products were used. For the sodium and chlorine reaction, 78.65 grams of Na is required to produce 200 grams of NaCl. For the potassium and water reaction, 23.5 grams of potassium will produce 33.7 grams of KOH.

Explanation:

The questions posed concern two stoichiometry problems involving the calculation of reactant/product masses given the chemical equations for the reactions of sodium with chlorine and potassium with water.

Problem 1: Sodium and Chlorine Reaction

To find out how many grams of Na must be reacted to produce 200 grams of NaCl, we need to use the molar masses of Na (22.99 g/mol) and NaCl (58.44 g/mol). According to the stoichiometry given by the balanced chemical equation, 2 moles of Na react with 1 mole of Cl2 to produce 2 moles of NaCl. Therefore, to produce 200 g of NaCl, the amount of Na required can be calculated using the ratio of their molar masses and the stoichiometry of the reaction:

200 g NaCl × (1 mol NaCl / 58.44 g NaCl) × (2 mol Na / 2 mol NaCl) × (22.99 g Na / 1 mol Na) = 78.65 g Na. Thus, the correct option is B. 78.65g Na.

Problem 2: Potassium and Water Reaction

For the reaction of 23.5 grams of potassium with excess water, the balanced equation gives us the stoichiometry needed to calculate the mass of KOH produced. By using the molar masses of K (39.10 g/mol) and KOH (56.11 g/mol), we can convert the mass of potassium reacted to moles, and then to the mass of KOH produced:

23.5 g K × (1 mol K / 39.10 g K) × (2 mol KOH / 2 mol K) × (56.11 g KOH / 1 mol KOH) = 33.7 g KOH. Hence, the answer is A. 33.7g KOH.

Solid

They are a mineral

The answer is:

ammonia

Answer:

0.640 Torr; 1.28 Torr  

Step-by-step explanation:

According to Raoult's Law,

(1) p₁ = χ₁p₁°,  

where p₁ is the solvent

χ₁ + χ₂ = 1                        Subtract χ₁ from each side

      χ₂ = 1 – k₁                          Substitute in (1)

(2)    p₁ = (1 – χ₂)p₁°    Remove parentheses

       p₁ = p₁°- χ₂p₁°      Subtract p₁° from each side

p₁ - p₁° = -χ₂p₁°              Multiply each side by -1

     Δp =   χ₂p₁°

Δp is the vapour pressure lowering.

If the solute is an electrolyte, we must insert the van't Hoff i factor.

ΔP = iχ₂P₁°

===============

(1) Calculate χ₂ for each solution

Water:

1000 g = 1000 × 1/18.02

          = 55.49 mol

      χ₂ = 2.10/(2.10 + 55.49)

          = 2.10/57.59

          = 0.036 46

===============

(2) Calculate the vapour pressure lowering

(a) Sucrose

   i = 1

ΔP = 1 × 0.036 46 × 17.54

ΔP = 0.640 Torr

=====

(b) NaCl

   i = 2

ΔP = 2 × 0.640

ΔP = 1.28 torr

A sub-discipline of chemistry, that is, stereochemistry includes the study of the comparative spatial alignment of atoms, which produce the composition of the molecules and their manipulation. The examination of stereochemistry aims at stereoisomers that by definition exhibits the similar sequence of bonded atoms and molecular formula, however, vary in the three-dimensional orientations of their atoms in space.  

The diagram is given in the attachment below:  

Answer : Formation of yellow precipitate is the physical evidence that there has been a chemical reaction.

Explanation :

A chemical reaction happens when 2 or more substances chemically react with each other.

There are 4 evidences indicating that a chemical reaction has occurred which are mentioned below.

1. Change in color : On mixing, the reaction mixture can change color indicating that a chemical change may have occurred.

2. Formation of precipitate : A reaction in which a solid is formed on mixing 2 aqueous solutions is called as precipitation reaction. Here, the formation of solid indicates a chemical change.

ex. [tex]AgNO_{3} (aq) + NaCl (aq) \rightarrow AgCl (s) + NaNO_{3} (aq)[/tex]

In above reaction, on mixing the solutions, a white precipitate of AgCl is formed which indicates a chemical change.

3. Evolution of gas : A chemical change also occurs when a gas is evolved on mixing 2 substances.

ex. [tex]2HCl (aq) + Na_{2}CO_{3} (aq) \rightarrow 2NaCl (aq) + H_{2}O (l) + CO_{2} (g)[/tex]

In above reaction, CO2 gas is evolved and bubbles can be seen in the form of effervescence.

4. Change in temperature : Certain chemical reactions absorb or evolve heat. When a chemical reaction evolves heat, the temperature of the final reaction mixture increases and when it absorbs heat, the temperature decreases. This increase and decrease in temperature indicates a chemical change.

ex.  [tex]HCl (aq) + NaOH (aq) \rightarrow NaCl(aq) + H_{2}O (l)[/tex]

In above reaction, the final mixture becomes hot as the reaction releases heat. ( Exothermic)

Change in odor also indicates a chemical change.

For the given reaction, a yellow precipitate of PbI2 is getting formed.

Therefore formation of this precipitate is the physical evidence that there has been a chemical reaction.

Answer:

precipitate formation occurs

Explanation:

did usa test prep

 The volume  (in liters)  of CO₂  that can  be consumed at STP by 435 g Na₂O₂  is  125 L of Co₂

calculation

2Na₂O₂(s)  +2 CO₂ (g)→  2 Na₂CO₃(s)  + O₂(g)

Step 1 : find the moles  of Na₂O₂

moles = mass÷  molar mass

from periodic table the  molar mass  of Na₂O₂ = (23 x2) +( 16 x2) = 78 g/mol

 moles= 435 g÷ 78 g/mol = 5.58 moles

Step 2: use the mole ratio to determine the moles of CO₂

from given equation  Na₂O₂ : CO₂ =2 :2 =1:1

Therefore the  moles of CO₂  is also = 5.58 moles

Step 3: find the volume  of CO₂  at STP

that is at STP      1  mole of a gas = 22.4 L

                          5.58 moles = ? l

by cross multiplication

= (5.58 moles x 22.4 L) / 1 mole = 125 L

435 g of Sodium peroxide (Na2O2) can consume about 125 liters of carbon dioxide (CO2) at Standard Temperature and Pressure (STP).

The question requires us to determine the volume of CO2 that can be consumed by 435 g of Sodium peroxide (Na2O2) at Standard Temperature and Pressure (STP).

Molar mass of Na2O2 = 2(23) + 2(16) = 78 g/mol. So, 435 g of Na2O2 = 435/78 = 5.58 mol.

From the balanced chemical equation, we know that 2 mol of Na2O2 react with 2 mol of CO2. Thus, 5.58 mol of Na2O2 will react with 5.58 mol of CO2.

At STP, 1 mol of any gas occupies 22.4 liters. Therefore, 5.58 mol of CO2 will occupy 5.58 * 22.4 = 124.99 L. So, 435 g of Na2O2 can consume about 125 L of CO2 at STP.

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Answer is: B. Energy transfer would occur between the copper bars and the surroundings.

Closed system is a physical system that does not allow transfer of mass and energy in or out of the system.

Open system is a physical system that does allow transfer of mass and energy in or out of the system, have input and output flows.

Thermal conductuction is the transfer of heat through physical contact. Thermal conduction is the transfer of heat by microscopic collisions of particles.

Heat spontaneously flows from a hotter to a colder body.

239 degrees Fahrenheit.

To find this, use the equation (Celsius x 9/5) + 32 = F

Where Celsius is, substitute with the number given to get the final answer of 239.

Hope this helps!

Answer:

239

Explanation:

This is easy

The amount of moles in 3.34x10^34 formula units of Cu(OH)2 is calculated by dividing the number of formula units by Avogadro's number (6.022 x 10^23 formula units/mol). The resulting value is approximately 5.55x10^10 moles of Cu(OH)2.

To calculate moles from a given number of formula units, we use Avogadro's number: 6.022 x 1023. This number tells us that there are 6.022 x 1023 formula units in one mole of any substance. Therefore, if we have 3.34 x 1034 formula units of Cu(OH)2, we divide this number by Avogadro's number to find the amount in moles.

Here's the calculation:
Number of Moles = 3.34x1034 formula units / 6.022 x 1023 formula units/mol = 5.55x1010 moles of Cu(OH)2

The use of Avogadro's number in this context demonstrates the direct relationship between moles and formula units in a substance, an important concept in chemistry.

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You can determine the number of moles from the number of formula units by dividing the number of formula units by Avogadro's number (6.022 x 10^23). Applying this to the problem, the number of moles in 3.34 x 10^34 formula units of Cu(OH)2 is about 5.54 x 10^10.

The chemistry concept at work here is that 1 mole of any substance contains 6.022 x 10^23 entities of that substance (Avogadro's number). This is true whether these entities are atoms, molecules, ions, electrons, or other particles. The term 'formula units' is used because copper hydroxide (Cu(OH)2) consists of multiple atoms grouped together. In this case, you're being asked the amount of moles in 3.34x10^34 formula units of Cu(OH)2.

Since 1 mole contains 6.022 x 10^23 formula units, you can calculate the number of moles by using the formula:

Number of moles = Number of formula units / Avogadro's number

Substituting the numbers into this formula gives:

Number of moles = 3.34 x 10^34 / 6.022 x 10^23

So, the number of moles in 3.34 x 10^34 formula units of Cu(OH)2 is about 5.54 x 10^10.

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Answer :

Part 1 : conversion factor required for 30%(m/m) NaCl solution.

30%(m/m) NaCl solution that means 30 grams of NaCl is present in 100 gram of solution.

Conversion factor : [tex]30\%\text{ of NaCl solution}=\frac{30\text{ g of NaCl}}{100\text{ g of solution}}[/tex]

Part 2 : conversion factor required for 8%(v/v) ethanol solution.

8%(v/v) ethanol solution that means 8 ml of ethanol is present in 100 ml of solution.

Conversion factor : [tex]8\%\text{ of ethanol solution}=\frac{8\text{ ml of ethanol}}{100\text{ ml of solution}}[/tex]

Part 3 : conversion factor required for 14%(m/v) fructose solution.

14%(m/v) fructose solution that means 14 grams of fructose is present in 100 ml of solution.

Conversion factor : [tex]14\%\text{ of fructose solution}=\frac{14\text{ g of fructose}}{100\text{ ml of solution}}[/tex]

Part 4 : conversion factor required for 5.0 M HBr solution.

'M' represent the 'molarity' which is defined as the number of moles of solute present in one liter of solution.

5.0 M HBr solution that means 5 moles of HBr is present in 1 liter of solution.

Conversion factor : [tex]5.0M\text{ HBr solution}=\frac{5\text{ moles of HBr}}{1\text{ L of solution}}[/tex]

 The number of calcium  atoms  that would  be in a  100 g sample of calcium  is 1.505 x 10²⁴  atoms

     calculation

Step 1 ; find the  moles of calcium

moles = mass÷  molar mass

from periodic table the  molar mass of Ca =40 g/mol

moles is therefore = 100 g÷ 40 g/mol = 2.5 moles

Step 2: use the Avogadro's  law constant to determine the number of atoms  of Calcium

That is According  Avogadro's law   1 mole = 6.02 × 10²³  atoms

                                                           2.5 moles=? atoms

 {(2.5  moles  ×  6.02×10²³  atoms)  / 1 mole}  = 1.505  ×  10²⁴  atoms

Answer: Option (D) is the correct answer.

Explanation:

The chemical reaction equation will be as follows.

      [tex]HCl + NaOH \rightarrow NaCl + H_{2}O[/tex]

This means a new substance has been formed and a chemical change has taken place.

A chemical reaction in which heat energy is absorbed by the reactant molecules is known as an endothermic reaction.  

For example, [tex]A + B + Heat \rightarrow AB[/tex]

On the other hand, a chemical reaction in which heat energy is released by the reactant molecules is known as an exothermic reaction.  

For example, [tex]C + D \rightarrow CD + Heat[/tex] is an exothermic reaction.

Thus, we can conclude that in the given situation the beaker most likely felt warm because a chemical reaction was producing a new substance.

Answer: The correct answer is option B.

Explanation:

Electronic Configuration of Group VII-A : [tex]ns^2np^5[/tex]

This group require 1 electron to attain stable electronic configuration.

Electronic configuration of Group I-A : [tex]ns^1[/tex]

This group will loose 1 electron to attain stable electronic configuration.

So, there will be complete transfer of electron from Group VII-A to Group I-A and hence, will form ionic bond between them.

Hence, the correct option is B.

Answer:

The volume of 3.25 grams of ammonia is 4.28 L

Explanation:

Step 1: Data given

Mass of ammonia = 3.25 grams

Molar mass of ammonia = 17.03 g/mol

Step 2: Calculate moles ammonia

Moles NH3 = mass NH3 / molar mass NH3

Moles NH3 = 3.25 grams / 17.03 g/mol

Moles NH3 = 0.191 moles

Step 3: Calculate volume of NH3

1 mol = 22.4 L

0.191 moles = 22.4 * 0.191 = 4.28 L

The volume of 3.25 grams of ammonia is 4.28 L

To find the volume of 3.25 g of ammonia, assuming an 8% solution with water-like density, we calculate the moles of ammonia and use the molarity to estimate the volume, which is approximately 40.7 mL.

To calculate the number of liters of ammonia in 3.25 g, we need to consider the density of ammonia. However, the initial question seems incomplete as it does not provide the concentration or density of ammonia directly. Instead, we are just provided a percentage which is typically used for solutions.

If we assume a solution of ammonia with a density similar to water, the number of liters can be estimated using the analytical concentration of an 8% ammonia by weight solution. Given this solution, ammonia has a concentration of 4.7 M (mol/L, assuming 1 L weighs 1000 g and 80 g of ammonia corresponds to 80 / 17 = 4.705882353 mol/L).

The number of moles of ammonia in 3.25 g can be calculated by dividing the mass by the molar mass of ammonia (17 g/mol):

n = mass / molar mass = 3.25 g / 17 g/mol = 0.1912 mol

Now, using the molarity (M), which is moles of solute per liter of solution (mol/L), we can find the volume V:

V = n / M = 0.1912 mol / 4.7 mol/L = 0.0407 L or 40.7 mL

Therefore, 3.25 g of an 8% ammonia solution corresponds to approximately 40.7 mL.