A good quarterback can throw a football at 27 m/s (about 60 mph ). How long is the ball in the air?

I believe that the correct answer for this question is:

a. the propagation of waves in the ocean

This is because like waves in form, light has two polarities in shape. It actually forms a sinusoidal wave like a wave in the ocean.

Final answer:

Light energy is best likened to the propagation of waves in the ocean (option a) because light exhibits wavelike properties, such as frequency and wavelength, similar to the behavior of ocean waves.

Explanation:

The best analogy for light energy is the propagation of waves in the ocean (option a). This is because light behaves as both a wave and a particle, a concept known as wave-particle duality. Light and other forms of electromagnetic radiation move through a vacuum at a constant speed, c, and demonstrate wavelike properties such as frequency (ν) and wavelength (λ), which relate to the energy of light. Similar to ocean waves that propagate across the sea, light waves travel through space, and their interference patterns can be observed when passing through narrow slits, analogous to water waves interacting with barriers.

Final answer:

Large bodies of water like oceans contribute to more moderate climates in coastal areas due to their thermal properties. Global warming is leading to sea level rise through glacial meltwater and thermal expansion, which affects coastal communities. Oceans also impact global weather patterns, including precipitation and climate, due to heat transport and storage.

Explanation:

Large bodies of water, like oceans and large lakes, have a significant impact on the climate of coastal communities. The thermal properties of water, which heats and cools more slowly than land, lead to moderate climates in coastal areas. These regions typically experience smaller temperature fluctuations both daily and seasonally, in comparison to interior landmasses. Additionally, global warming is causing sea levels to rise due to glacial meltwater and thermal expansion, further complicating the climate effects on coastal communities. The warmth of oceanic currents is transported across vast distances, affecting the weather patterns far inland as well.

As the planet warms, the rise in sea levels can lead to the inundation of shorelines, which poses challenges for coastal cities. This rising sea level can increase the impact of storm surges, putting infrastructure at risk. The warming of oceans also contributes to the continued melting of polar ice, which can disrupt the supply of freshwater and bring about long-term changes to global precipitation and climate patterns. Hence, the oceans play a crucial role in moderating global climate and the long-term implications of climate change.

The bulb will light up when the capacitor discharges, but the brightness will continually decrease and the bulb will go out once the capacitor is fully discharged.

In circuits containing capacitors, when the capacitor is fully charged, it starts the process of discharging. During the process of discharging, the capacitor transfers its stored energy which can light up a bulb. So, yes, theoretically, a bulb can light up during the time the capacitor discharges. However, the brightness of the bulb will diminish over time, as the energy stored in the capacitor decreases during a discharging process, resulting in a decreasing current in the circuit.

For example, imagine we have a simple circuit with a bulb, a resistor, and a discharging capacitor. At the start of the discharge process, when the capacitor holds the maximum charge, the bulb will shine the brightest. As the capacitor discharges, the current in the circuit will decrease, therefore the brightness of the bulb will also decline. When the capacitor is fully discharged, the current will be zero and therefore the bulb will not light up anymore.

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Final answer:

The bulb in a circuit with a discharging capacitor will remain lit as long as there is sufficient current flowing through it. The duration depends on the circuit's time constant and the bulb's required current to produce light. The stored energy of the battery and bulb's power consumption determine how long the bulbs will stay lit.

Explanation:

The question pertains to the discharge of a capacitor in a simple electrical circuit and whether a bulb connected to this circuit will remain lit throughout the discharge process. When a charged capacitor starts to discharge through a bulb (or any resistive load), the bulb will light up. As the capacitor discharges, the voltage across it decreases, which in turn causes the current through the bulb to decrease. The bulb will stay lit as long as there is sufficient current flowing through it to produce light. The duration for which the bulb stays lit will be influenced by the effective resistance of the circuit and the capacitance value.

For more complex circuits, such as one with a neon lamp, the bulb will light up when the capacitor discharges through the lamp. However, once the capacitor's voltage drops below the lamp's 'strike voltage', the lamp will turn off, and the capacitor may continue to discharge without producing light. Hence, the bulb does not necessarily stay lit for the entire duration of the capacitor's discharge. Instead, it stays lit until the voltage and current are too low to sustain illumination.

If a battery has a total stored energy of 800 W hr and it produces a constant potential difference until discharged, to determine how long the bulbs will stay lit, one would need to know the power consumption of the bulbs and the system voltage. This would allow for the calculation of the discharge time using the relationship between power, energy, and time.

The pressure of the gas in this mercury manometer ( Figure 1 ) is about 864 mmHg

[tex]\texttt{ }[/tex]

The basic formula of pressure that needs to be recalled is:

Pressure = Force / Cross-sectional Area

or symbolized:

[tex]\large {\boxed {P = F \div A} }[/tex]

P = Pressure (Pa)

F = Force (N)

A = Cross-sectional Area (m²)

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

In this problem , we will use Ideal Gas Law as follows:

Given:

height of mercury column = h = 89 mm

atmospheric pressure = Po = 775 mmHg

Asked:

the pressure of the gas = P = ?

Solution:

We will use Hydrostatic Pressure formula to solve this problem as follows:

[tex]P = Po + \rho g h[/tex]

[tex]P = 775 \texttt{ mmHg} + 89 \texttt{ mmHg}[/tex]

[tex]P = 864 \texttt{ mmHg}[/tex]

[tex]\texttt{ }[/tex]

The pressure of the gas in this mercury manometer ( Figure 1 ) is about 864 mmHg

[tex]\texttt{ }[/tex]

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Grade: High School

Subject: Physics

Chapter: Pressure

Solution, colloids and suspension are distinctive sort of mixtures.

Air and dust are not solutions.

There is an uncertainty about whether air and dust form a colloid or a suspension.

Colloids don't partitioned, while suspension's segments do isolated. In the event that the residue is sufficiently little it will stay in air sufficiently long to be considered  a colloid for all efects.

At that point, the most satisfactory assessment is that the  blend of air and dust is a colloid.

So, option c. a colloid is the answer.

Colloid is a heterogeneous mixture in which molecule estimate is middle of genuine arrangement and suspension. Smoke from a fire is case of colloidal framework in which small particles of strong buoy in air. Some basic cases of colloids are jewel stones, smoke, cheddar, drain, cleanser foam and froth.

From the Newton’s First Law, we can see that acceleration is simply the ratio of Force over mass. In this case, mass is the sum of the mass of each car, that is:

mass = 2300 kg + 2500 kg = 4800 kg

So the formula is:

acceleration = Force / mass

acceleration = 18,000 N / 4800 kg

acceleration = 3.75 m/s^2

In 2 significant figures:

acceleration = 3.8 m/s^2

The maximum possible acceleration the truck can give the SUV is about 3.8 m/s²

[tex]\texttt{ }[/tex]

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\boxed {F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

mass of truck = m = 2300 kg

mass of SUV = M = 2500 kg

maximum forward force = F = 18 000 N

Asked:

maximum possible acceleration = a = ?

Solution:

We will use Newton's second law of motion to solve this problem :

[tex]\Sigma F = ( m + M )a[/tex]

[tex]F = ( m + M ) a[/tex]

[tex]a = F \div ( m + M )[/tex]

[tex]a = 18000 \div ( 2300 + 2500 )[/tex]

[tex]a = 18000 \div 4800[/tex]

[tex]a \approx 3.8 \texttt{ m/s}^2[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

Without the given Figure, precise answers can't be provided. Generally, acceleration is calculated as the slope of the velocity-time graph, and position is provided by the integral (or area under the graph) of the velocity-time graph. The object's speed is lowest when its velocity is minimal, and it is farthest from x= 0 when the accumulated area under the graph is maximum.

Unfortunately, without the given Figure P2.50, it's impossible to accurately calculate the object's acceleration, position at different times, or specify when the object is moving with the lowest speed or is farthest from x = 0.

However, I can explain the general method to determine this information. Acceleration is calculated from the slope of the velocity-time graph. The position is generally obtained by calculating the area under the velocity-time graph from the beginning of the interval to the end. The object is moving with the lowest speed when the velocity is lowest (either positively or negatively). The object is farthest from x = 0 when the accumulated area under the velocity-time graph (counting areas below the time axis as negative) is a maximum. The total distance the object has moved is equal to the absolute sum of all the areas (both positive and negative) on the velocity-time graph.

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Velocity of an object can be determined from the time-varying force. By using Newton's second law and integrating the force with respect to time, we can find the total impulse applied to the object. Divide the total impulse by the mass of the object to find its velocity at t=6 seconds.

The question is related to the concept of Force and Acceleration in Physics.

To determine the velocity of the object, we need to recall Newton's second law, F = ma, which states that the force applied to an object equals its mass times its acceleration. Therefore, we can find the acceleration by dividing the force by the mass of the object. Velocity is the integral of acceleration with respect to time.

From the given physics problem, we need to calculate the area under the force-time graph (which gives the impulse) from t=0 to t=6s, then divide by the object's mass to find the object's velocity.

V=(Δp)/m, where Δp is impulse and m is mass. Impulse can be calculated as the area under the force-time graph.

Integrate the areas under the force-time graph from 0 to 6 seconds to find total impulse. Then divide this total impulse by the mass of the object to find the final velocity at t=6s.

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To find the object's velocity at t=6s, calculate the area under the force-time curve and then divide by the object's mass.

Given that the object is initially at rest, the velocity at t=6s can be found using the area under the force-time curve on the given figure. This area represents the impulse applied to the object, and it can be related to the change in momentum and thus velocity through the equation Impulse = Change in momentum = mΔv, where m is the mass and Δv is the change in velocity. Without the figure, we cannot provide a numerical value for the velocity; however, the student should calculate the area under the force-time curve up to t=6 s, and divide it by the object's mass (5.50 kg) to find out the final velocity.

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The toy rocket falls to the ground due to gravity in 2.86 seconds. During this time, it travels horizontally under constant acceleration, covering a distance of approximately 93.67 meters.

This type of problem involves projectile motion, a topic in physics. Since only vertical motion affects the time it takes for the rocket to hit the ground, we first find the time it takes for the rocket to fall from the roof to the ground. The equation to find time when we know height (H), initial vertical velocity (Vi), and acceleration due to gravity (g) is: t = √(2H/g). Plugging in H = 40 m and g = 9.8 m/s², we get t = √(2*40/9.8) = 2.86 seconds.

Next, we'll calculate the horizontal distance (or range) traveled by the rocket. The horizontal distance can be calculated using the equation x = Vi*t + 0.5*a*t², where Vi is the initial horizontal velocity, a is the horizontal acceleration and t is the time which we calculated in the previous step. Substituting the values, Vi = 11 m/s, a = 1.6*t, and t = 2.86 s, the equation becomes x = 11*2.86 + 0.5*1.6*2.86² =  93.67 m.

So, the horizontal distance that the rocket travels before reaching the ground is approximately 93.67 meters.

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1. lifts it chest high

The force opposing to this action is the force due to gravity. Therefore the work done is:

W1 = m g d

where m is mass of the barbell, g is gravity and d is displacement

2. holds it for 30 seconds

Work is a product of force and displacement, since there is no displacement, therefore work done is zero.

W2 = 0

3. puts it down slowly

If the barbell was dropped, then it would simply be a free fall. But since it was not, so the work done here is also equal to the weight of the barbell times displacement:

W3 = m g d

We can see that W1 = W3, and since W2 = 0, therefore the answer is:

w3 = w1 > w2

Final answer:

In the context of a weight lifter lifting, holding, and lowering a barbell, work is done during the lifting (w1) and lowering (w3) phases due to the movement over a distance against a force. Holding the barbell stationary (w2) involves no work as there is no displacement. Thus, ranking in terms of work done would be w1 = w3 > w2, assuming equal force and displacement for lifting and lowering.

Explanation:

To answer the student's question effectively, we need to apply the concept of work from physics. Work is defined as the transfer of energy, and mathematically, it is the product of force and displacement in the direction of the force. Thus, work requires both force and movement in the direction of that force.

w1: Lifting the barbell chest high involves applying a force that moves the weights over a distance, hence work is done here.

w2: Holding the barbell in place does not involve movement. As there is no displacement, no work is done in the physics sense during this action. Therefore, w2 is zero.

w3: Lowering the barbell slowly back down also involves work since force is applied in controlling the movement against gravity over a distance.

Given the above understanding, w1 and w3 involve doing work, with w2 being zero due to no displacement. However, without specific values for force and displacement, it's challenging to directly compare the magnitude of work done between w1 and w3 precisely.

Conceptually, if the distance and force applied are the same for lifting and lowering, then w1 = w3 > w2. This scenario assumes identical distances and forces are applied in lifting up and lowering down the weights,

The correct answer would be B. To provide support for a weakened joint. I just took the test!

Answer:

3 m /s

Explanation:

Average velocity is defined as the ratio of total displacement to the total time taken. The formula of average velocity is given by

[tex]Average velocity = \frac{Total displacement}{Total time taken}[/tex]

Take east direction is positive and west is negative.

Here the total displacement is

d = 20 - 40 + 35 = 15 m

t = 5 second

Average velocity = 15 / 5 = 3 m/s

The total work done by the donkey to pull the cart out of the mine is calculated by finding the work done against gravity and friction. The work done against gravity is 37012.5 J and against friction is 11637.5 J. The sum, and thus the total work done, is 48650 J.

To find the total work done by the donkey, we need to consider the work done against both the gravitational force and the frictional force. The total work done will be equal to the sum of these two works.

Firstly, let's find the work done against the gravitational force. The force of gravity acting on the cart can be found using the equation F = m x g x sin(θ), where m is the mass of the cart, g is the acceleration due to gravity, and θ is the angle of the slope. Therefore, F = 413 kg x 9.81 m/s² x sin(4.69°) = 211.5 N. The work done against gravity is then W = F x d, where d is the distance the cart is hauled, resulting in W = 211.5 N x 175 m = 37012.5 J.

Secondly, let's calculate the work done against friction. The frictional force can be found using the equation F = μ x m x g x cos(θ), where μ is the coefficient of friction. Therefore, F = 0.0163 x 413 kg x 9.81 m/s² x cos(4.69°) = 66.5 N. The work done against friction is again W = F x d, giving W = 66.5 N x 175 m = 11637.5 J.

The total work done by the donkey is then the sum of these two works, giving 37012.5 J + 11637.5 J = 48650 J.

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A. Starting at 1900 ft, so if he opened his parachute at 1000 ft, therefore this means that h = 1000:

 h = - 16t^2 + 1900

1000 = - 16 t^2 + 1900

t = 7.5 seconds

B. So we have h = 940

940 = - 16 t^2 + 1900

t = 7.746 seconds

C. The domain will always be time and since time starts at zero, so it is the initial point for h:

h =  - 16(0)^2 + 1900

h = 1900

We also know that at lowest point h = 0, so the last value of t is:

0 =  - 16 t^2 + 1900

t = 10.897 seconds

Therefore

domain: (0, 10.897)

range: (1900, 0)

To determine the free fall time of a smoke jumper, the equation h(t) = -16t² + 1900 is solved for the times when the height equals 1000 ft and 940 ft, respectively. The domain of the function is the time from the jump until the ground is reached, and the range is from 0 to 1900 ft.

To solve the problem of determining how long a smoke jumper is in free fall, we need to find the time t when the function h(t) = -16t² + 1900 is equal to a specific height. This function represents the height of the jumper above the ground at any given time t during free fall, assuming gravity's acceleration is -32 ft/s² (in the opposite direction to the velocity of the jumper).

We need to solve the equation -16t² + 1900 = 1000 for t. This simplifies to 16t² = 900, and by taking the square root after dividing both sides by 16, we find the time t where the height is 1000 ft.

We need to solve the equation -16t² + 1900 = 940 for t. This is a quadratic equation in standard form, so we can use the quadratic formula to find the positive value of t that gives us a height of 940 ft.

The domain of the function is the set of all possible times from when the jumper exits the plane until it reaches the ground. The range would be the set of heights from the ground level (0 ft) up to the initial height (1900 ft).

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To calculate the mass 'm' required to hold the cart stationary, you need to consider the principles of linear momentum as the water jet imparts momentum to the vane and causes a reaction force. Assuming the water jet changes its direction by 40 degrees, this means that the horizontal component of its momentum changes. The mass to hold the cart stationary must produce a weight that can counteract the force exerted by the stream of water.

To determine the mass m required to hold the cart stationary, you require knowledge of the principles of linear momentum. Since the water jet imparts momentum to the vane when it strikes it and changes its direction, this reaction force can cause the cart to move if not balanced. According to Newton's second law, in equilibrium the net force on an object is zero. Let's assume the water jet changes direction by 40 degrees, meaning the horizontal component of its velocity, and therefore its momentum, changes. The rate of change of momentum is given by the mass flow rate times the change in velocity, which equals the force exerted on the vane. The mass to hold the cart stationary must produce a weight force that counteracts this, so m = F/g, where F is the force exerted by the stream of water and g is the acceleration due to gravity. Actual calculations would require specific values for the mass flow rate of the water jet and the nozzle area.

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Final answer:

The question requires calculating the rate at which two individuals are moving apart by using their speeds and applying principles of kinematics. It involves converting time into seconds, calculating the total distance each person traveled, and then finding the distance between them 15 minutes after the woman starts walking.

Explanation:

The question involves calculating the rate at which two people are moving apart from each other, given their speeds and initial positions. It requires an understanding of relative motion and the ability to apply the principles of kinematics to solve real-world problems.

The man starts walking north from a point P at 2 ft/s, and five minutes later, a woman starts walking south from a point 500 ft due east of P at 6 ft/s. To find the rate at which they are moving apart 15 minutes after the woman starts walking, we must consider the distance each has traveled in their respective directions by that time.

The man walks for a total of 20 minutes (15 minutes after the woman starts), while the woman walks for 15 minutes. The distance the man walks is 2 ft/s × 1200 s = 2400 ft and the woman walks 6 ft/s × 900 s = 5400 ft. Since they start 500 ft apart east to west, and move in north-south directions, the distance between them after 15 minutes can be found using the Pythagorean theorem: √(24002 + (500 + 5400)2) = √(5760000 + 32400000) = √38160000, which gives the distance between them. The rate of separation is the derivative of this distance with respect to time, assuming constant speeds.

Answer: decomposers

Explanation: they are microorganisms that are responsible for the decay and break down of dead organism into nutrients that are available for the plant

Answer:

because its metal

Explanation:

Final answer:

To cook four hot dogs simultaneously with a 120 V potential difference in 3.0 min, the total energy needed is 240,000 J, which results in a required power of 1,333.33 W. This yields a necessary current of approximately 11.11 A.

Explanation:

To determine the current needed to cook four hot dogs simultaneously in 3.0 minutes using a potential difference of 120 V, we must first calculate the total energy required to cook all four hot dogs. Since it takes 60 kJ to cook one hot dog, the total energy for four hot dogs is calculated by multiplying 60 kJ by 4, which gives us 240 kJ or 240,000 J (since 1 kJ = 1000 J).

Next, to find the amount of time in seconds, we convert 3.0 minutes into seconds by multiplying it by 60 seconds/minute, giving us 180 seconds. Now we can use the formula for power (P = E/t), which is the energy (E) divided by time (t). With this, we can calculate the power required to cook the hot dogs:

P = E/t = 240,000 J / 180 s = 1,333.33 W

Finally, knowing the voltage (V) and the power (P), we can use the relationship P = V * I, where I is the current, to find the current required:

I = P/V = 1,333.33 W / 120 V = 11.11 A

Thus, the current needed to cook four hot dogs simultaneously in 3.0 min with a 120 V potential difference is approximately 11.11 A.

Answer:

Gamma rays

Explanation:

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