A flight attendant pulls a suitcase 250.0 m along a level airport floor with a force of 30.0 n at an angle of 50.0 above the horizontal. How much force is done on the flight bag

Answers

Answer 1

Answer:

4820.9 J of work is done on the flight bag.

Explanation:

Given:

Force acting on the bag is, [tex]F=30.0\ N[/tex]

Displacement of the bag caused by the force is, [tex]S=250.0\ m[/tex]

Angle between the direction of force and direction of displacement caused is, [tex]\theta = 50\°[/tex]

Now, the formula to calculate work done on a body by a force 'F' causing displacement 'S' at an angle [tex]\theta[/tex] between the two vectors is given as:

[tex]W=FS\cos \theta[/tex]

Plug in the given values and solve for work done 'W'. This gives,

[tex]W=(30.0\ N)(250.0\ m)(\cos 50)\\W=4820.9 \textrm{ N-m or 4820.9 J}[/tex]

Therefore, the work done on the flight bag is 4820.9 J.


Related Questions

As motorists drive onto the acceleration lane, they must get up to the speed limit, _______, find a/an ________ and then _______.

Answers

Answer:

signal, opening and merge.

Explanation:

As motorists drive onto the acceleration lane, they must get up to the speed limit, signal, find an opening and then merge.

Acceleration lane explanation: an speed variation area or lane of adjustment consisting of additional flooring on the edges of traffic lanes to allow acceleration of vehicles until merging with traffic flow .

A rocket is launched vertically from a point on the ground. An observer who is 1000 m away from the base of the launching pad, notices that the angle of elevation of the rocket is increasing at a rate of π/40 radians per second when the angle of elevation is π/3.
Find the speed of the rocket at that instant.

Answers

Answer:

dh/dt=18.75rad/sec

Explanation:

A rocket is launched vertically from a point on the ground. An observer who is 1000 m away from the base of the launching pad, notices that the angle of elevation of the rocket is increasing at a rate of π/40 radians per second when the angle of elevation is π/3.

Find the speed of the rocket at that instant.

you should have a right-angled triangle, where the angle of elevation is Ø, the adjacent is 1000 and the opposite is h, the height of the rocket.

tangent of an angle is opposite over adjacent side

tanØ = h/100 0

h = 1000tanØ

differentiate both sides with respect to dt,change in time

tanØ=sec^2 Ø

dh/dt = 1000sec^2 Ø (dØ/dt)

where Ø = 60° or π/3 rad

dØ/dt = π/40 radians per second

substituting the value into the equation

dh/dt=1000sin^260° *π/40 rad/sec

dh/dt=750*π/40 rad/sec

dh/dt=18.75rad/sec

dh/dt is the same as speed, change in height per time

If a motor neuron involved in a reflex arc is damaged, which event in that arc is least likely to occur?

Answers

Final answer:

If a motor neuron involved in a reflex arc is damaged, the event that is least likely to occur is the muscle contraction in response to the sensory stimulus.

Explanation:

If a motor neuron involved in a reflex arc is damaged, the event that is least likely to occur is the muscle contraction in response to the sensory stimulus. In a reflex arc, the motor neuron carries the impulse from the interneuron to the muscle, causing it to contract. If the motor neuron is damaged, this communication pathway is disrupted, and the muscle will not receive the signal to contract.

For trapezoid JKLM, A and B are midpoints of the legs. Find AB.


Question 3 options:

29

20

59

58

Answers

Answer:

AB = 29

Explanation:

For a better understanding, we must work this problem in a graphic way. In the attached image we can see the solution.

First, we draw a vertical dotted lines from the point J & K to the line ML, then we can see two new portions with the same length. Then with this simple analysis:

2x = 39 - 19

x = 10

Then we know that x = 10, another important data to find the answer is that the AB line is located in the midpoints of the legs. We also can see the right triangle MJ and the dotted line.

Now for every single right triangle, no matter its size and relationship between the vertical and the horizontal lengths, if some point is located in the hypotenuse (leg) at the middle of its length. This will be proportional to the vertical and the horizontal cathetus, therefore we will have the middle point on those two lines.

So, the AB line will be the sum of JK plus two times 5

AB = 19 + 5 + 5 = 29

Two bicyclists , starting at the same place, are riding toward the same campground by two different routes. One cyclist rides 1080 m due east and then turns due north and travels another 1430 m before reaching the campground. The second cyclist starts out by heading due north for 1950 m and then.turns and heads directly toward the campground.

(a) At the turning point, how far is the second cyclist from the campground?
(b) What direction (measured relative to due east) must the second cyclist head during the last part of the trip?

Answers

Answer:

[tex]DC=1198.6659\ m[/tex]

Explanation:

Refer the schematic for explanation.

According to the given condition the first cyclist covers 1080 meters eastwards and then travels 1430 meters northwards to reach the camp.

But the second cyclist travels 1950 meters northwards therefore he travelled 520 meters more in the north than the first cyclist.

So, according to the schematic we find the distance DC in the triangle DCE using Pythagoras theorem:

[tex]DC=\sqrt{1080^2+520^2}[/tex]

[tex]DC=1198.6659\ m[/tex]

The electrical force between an inner electron and the nucleusof an atom is:_________a. larger for atoms of low atomic numberb. largerfor atoms of high atomic numberc. the same for all atoms

Answers

Answer:

b. Larger for atoms of high atomic number.

Explanation:

The atomic number  of a chemical element is the number of protons found in the nucleus of every atom of that element.

The electrical force between an inner electron and the nucleus of an atom is described by  the Coulomb law

[tex]Fe = \frac{kq_{1}q_{2} }{r^{2}}[/tex]

           where k: Coulomb constant

                       q1 and q2 are the electric charges that interact (in our case  electron and protons)

                       r: Distance between electron and each proton

Then, larger number of protons in the nucleus, more the electrical force will be.

The answer is:

b. Larger for atoms of high atomic number.

A truck travels 1430 m uphill along a road that makes a constant angle of 5.76◦ with the horizontal. Find the magnitude of the truck's horizon- tal component of displacement. Answer in units of m.

Answers

Answer:

1422.8 m

Explanation:

Given:

Displacement of the truck is, [tex]\vec S=1430\ m[/tex]

The direction of the truck's displacement is 5.76° with the horizontal.

A vector inclined at angle [tex]\theta[/tex] with the horizontal is resolved into 2 components which are mutually perpendicular to each other. One of the component is along the horizontal and the other is along the vertical.

If a vector 'A' is inclined at an angle [tex]\theta[/tex] with the horizontal, then its horizontal and vertical components are given as:

[tex]Horizontal:\\A_x=A\cos \theta\\\\Vertical:\\A_y=A\cos \theta[/tex]

Here, the vector is 'S' and its horizontal component is needed.

Therefore, the horizontal component is given as:

[tex]S_x=S\cos \theta\\S_x=1430\times \cos(5.76\°)\\S_x=1422.8\ m[/tex]

A boat is anchored in Lake Michigan by an anchor that is 30 meters long. The water is only 18 meters deep, but the boat has drifted south of the anchor so that all 30 meters of the anchor is being used. To the nearest degree, what is the angle of depression that the anchor's chain makes with the water level?

Answers

Answer:

36.87°

Explanation:

length of anchor (L) = 30 m

depth of water (d) = 18 m

find the angle of depression the anchor chain makes with the water level

from the diagram attached the anchor chain, the water bed and the depth of the water all form a right angle triangle

therefore

cos θ = [tex]\frac{d}{L}[/tex]

cos θ = [tex]\frac{18}{30}[/tex]

θ = [tex]cos^{-1}.\frac{18}{30}[/tex] = 53.13°

the angle of depression (Ф) = 90 - 53.13 = 36.87°

A stationary receiver detects a change in frequency of the signal from a jet flying directly away from it at 300 m/s. Which of the following receivers will detect the same change in frequency from a jet moving away at 600 m/s?A) A receiver moving at 900 m/s in the opposite direction as the jetB) A receiver moving at 300 m/s in the opposite direction as the jetC) A stationary receiverD) A receiver moving at 300 m/s in the same direction as the jet

Answers

Answer:

d) the receiver should be moving at 300 m/s in the same direction as the jet.

Explanation:

The change in the frequency of a moving sound (or wave) source is called Doppler Effect. The change in frequency is:

[tex]\Delta f=\frac{\Delta v}{v}f_{o}[/tex] (1)

with [tex]\Delta v=\mid v_{r}-v_{s}\mid[/tex] the velocity of the receptor respect the source, [tex] f_{o} [/tex] the real frequency  and [tex] v [/tex] the velocity of the waves in the medium, we should be verty careful because the direction of the velocities are important so we have to select a reference frame and take on account the sign of the velocities. We're going to select positive direction as airplane direction. If we assume the frequency of the airplane sound and the velocity of waves on air remain constant, we should find the option that give us [tex] \Delta v=\mid v_{r}-v_{s}\mid = 300 [/tex] as the stationary case; let's see for:

a) [tex] \Delta v=\mid v_{r}-v_{s}\mid =\mid -900-600 \mid= 1500[/tex]

b) [tex]\Delta v=\mid v_{r}-v_{s}\mid = \mid-300-600 \mid= 900 [/tex]

c) [tex]\Delta v=\mid v_{r}-v_{s}\mid = \mid0-600\mid = 600 [/tex]

d) [tex]\Delta v=\mid v_{r}-v_{s}\mid= \mid300-600\mid = 300 [/tex]

So, the correct answer is d)

In a conversation with a friend, he expresses skepticism about global warning. When you inquire about his reasons, he responds by saying that the weather in that area has been the coolest he can remember. Using the information you have learned, what information could you offer to encourage your friend to reevaluate his position?

Answers

Answer:

Explanation:

A friend observes only the weather which is different than climate. Weather refers to short term change in the atmosphere while climate refers to what weather is like over a while in a specific area.

The weather may change when we move from one area to another. Cooler weather does not mean that the climate is cooler.

Global warming is the increase in average temperature globally due to which heat is increasing but it does not imply that temperature is hotter everywhere.

                               

Which region of the early universe was most likely to become a galaxy?

Answers

Answer:

This is likely possible for a region whose matter density is higher than the normal average.

Explanation:

A galaxy is a collection of lumps in space which are clumped together and interact with each other. There are a lot of speculations on how galaxies were birthed. some believe its formed by a collection of massive gas, dust which eventually collapsed under their own gravitational pull. others says its formed by the combination of large lumps of matter which accumulated forming thee galaxies. The possibility of a galaxy forming is dependent on how massive the matter in the region of the universe is.

High density regions in the early universe, referred to as colder spots, eventually evolved into galaxies. The process began with the creation of small galaxies and star clusters followed by massive star formation due to galaxy-galaxy collisions. Over time, the universe developed into the structure we see today.

Regions in the early universe that had higher-than-average density were most likely to become galaxies.

These regions attracted additional matter due to their higher density, and were sometimes referred to as the darkest or 'colder' spots of the early universe.

These colder spots of high density matter were where small galaxies and large star clusters first formed.

In these high density regions: the creation of small galaxies and large star clusters began when the universe was about two percent of its current age.

Galaxy-galaxy collisions in these regions erupted into massive bursts of star formation, some of which led to the formation of black holes.

Over time, clusters and superclusters of galaxies emerged and the universe began to resemble what we see today.

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A boat with a horizontal tow rope pulls a water skier. She skis off to the side so that the rope makes an angle of 10 degrees with the forward direction of motion. If the tension in the room is 200 N, how much work does the rope do on the skier during a forward displacement of 100 m?

Answers

Answer:

19696 J or 19700 J

Explanation:

COMPONENT OF FORCE IN DIRECTION OF DISPLACEMENT IS

F cosФ = 200 cos 10° = 196.96 N

work = component of force in direction of displacement ×  displacement

        = 196.96 × 100

        = 19696 J

       = 19700 J

The work done by rope is equal to 19696 J on the skier during a forward displacement of 100 m

What is the work?

Work can be described as the energy used when a force is applied in order to move an object through a specific displacement. The performed work defines both the applied force and the displacement of the object.

The force acting is to move an object in a line in the direction of the pushing force over a distance 'd'.

W= F ×d

Where 'F' is the force and 'd' is the displacement and W is work done by an object.

If the angle θ  with the forward direction of motion then work = Fd cos θ

Given, the force acting, F = 200 N

The angle with the forward direction of motion, θ = 10°

Given, the displacement in the forward direction, d = 100 m

Work done by the rope, W = Fd cos θ

W = 200 × 100 cos 10°

W = 19696 J

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The process of examining a change in one variable in a model while assuming that all the other variables remain constant is called _______.

Answers

Answer:

Ceteris Paribus

Explanation:

The process of examining a change in one variable in a model while assuming that all the other variables remain constant is called Ceteris Paribus.

Ceteris Paribus is a Latin phrase that means "all other things being equal" or "all other things held constant" in English. The phrase has found application in disciplines like Economics and Statistics. This phrase as being adopted as a process of examining a change in one variable in a model while assuming that all the other variables remain constant to ascertain the relationship between the variables or make deductions from an experimental study. An example of Ceteris Paribus application is the law of demand and supply in Economics. The law of demand states, Ceteris Paribus, the higher the price, the lower the quantity demanded and vice versa. Conversely, the law of supply states, Ceteris Paribus, the higher price, the higher the quantity supply and vice versa.

car gets 12 miles per gallon uphill and 24 miles per gallon downhill. If the car goes to the top of Pikes Peak and back (48 miles uphill followed by 48 miles downhill), what is the car's gas mileage, in miles per gallon, for the entire trip?

Answers

The car's gas mileage, in miles per gallon, for the entire trip is 16.

Explanation:

Car gets 12 miles per gallon uphill and 24 miles per gallon downhill.

Uphill mileage = 12 miles per gallon

Downhill mileage = 24 miles per gallon

Distance to peak = 48 miles.

      Distance to peak = Uphill mileage x Gas used uphill

      48 = 12 x Gas used uphill

      Gas used uphill = 4 gallon

      Distance to peak = Downhill mileage x Gas used downhill

      48 = 24 x Gas used downhill

      Gas used downhill = 2 gallon

Total distance traveled by car = 48 + 48 = 96 miles

Total gas used = 4 + 2 = 6 gallons

Total distance = Mileage x Gas used

96 =  Mileage x 6

Mileage = 16 miles per gallon

The car's gas mileage, in miles per gallon, for the entire trip is 16.

Answer:

16

Explanation:

The density, rho, of sea-water is 1.2 × 103 kg m−3. Using the expression Wave Power Equation, estimate the gravitational power per metre length available in a wave of height 0.60 m.

Answers

Final answer:

The gravitational power per meter length available in a wave of height 0.60 m is calculated using the gravitational potential energy per unit length formula, incorporating the known sea-water density, the wave height, and the acceleration due to gravity.

Explanation:

To estimate the gravitational power per meter length available in a wave of height 0.60 m with the given sea-water density of 1.2 × 103 kg/m3, we use the wave power equation derived from the concept of gravitational potential energy. The gravitational potential energy per unit length of the wave (E) is given by the formula E = ½ × ρgh2L, where ρ represents the density of the seawater, g is the acceleration due to gravity (which is approximately 9.81 m/s2), h is the wave height, and L is the length of the wave under consideration.

Substituting the values, with wave height (h) as 0.60 m and considering a unit length (L = 1 m) for power per meter, we get:

E = ½ × (1.2 × 103 kg/m3) × (9.81 m/s2) × (0.60 m)2 × 1 m

This equation gives us the energy per unit length for a single wave. To get power, we consider energy over time. As waves pass a point with a specific frequency, the power can be calculated by multiplying the energy by the frequency of the waves.

An energy pyramid, like the one below, represents which principle of ecology? Question 12 options:
a.Most producer organisms use photosynthesis to create organic compounds.
b.The ultimate source of energy in the biosphere is the sun.
c.Consumer organisms are more important than producer organisms.
d.Large amounts of energy are lost in the transfer between trophic levels.

Answers

Answer:

b.The ultimate source of energy in the biosphere is the sun.

Explanation:

The pyramid represents the energy that is initiated from the sun is then retained and stored in the new biomass and the each tropic level of the ecosystem there is 10% of the transfer of energy form one level to the next or higher level.

Answer: D.Large amounts of energy are lost in the transfer between trophic levels.

Explanation:

Where is the near point of an eye for which a contact lens with a power of +2.55 diopters is prescribed?Where is the far point of an eye for which a contact lens with a power of __.

Answers

Answer:

(a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

Explanation:

Given that,

Power = 2.55 D

Object distance = 25 cm for near point

Object distance = ∞ for far point

Suppose where is the far point of an eye for which a contact lens with a power of -3.00 D  is prescribed for distant vision?

(a) We need to calculate the focal length

Using formula of power

[tex]f =\dfrac{1}{P}[/tex]

Put the value into the formula

[tex]f=\dfrac{100}{2.55}[/tex]

[tex]f=39.21\ cm[/tex]

We need to calculate the image distance

Using formula of lens

[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}[/tex]

Put the value into the formula

[tex]\dfrac{1}{39.21}=\dfrac{1}{v}-\dfrac{1}{-25}[/tex]

[tex]\dfrac{1}{39.21}-\dfrac{1}{25}=\dfrac{1}{v}[/tex]

[tex]\dfrac{1}{v}=-\dfrac{1421}{98025}[/tex]

[tex]v=-68.98\ cm[/tex]

The eye's near point is 68.98 cm from the eye.

(b). We need to calculate the focal length

Using formula of power

[tex]f =\dfrac{1}{P}[/tex]

Put the value into the formula

[tex]f=-\dfrac{100}{3.00}[/tex]

[tex]f=-33.33\ cm[/tex]

We need to calculate the image distance

Using formula of lens

[tex]\dfrac{1}{f}=\dfrac{1}{v}-\dfrac{1}{u}[/tex]

Put the value into the formula

[tex]\dfrac{1}{-33.33}=\dfrac{1}{v}-\dfrac{1}{\infty}[/tex]

[tex]-\dfrac{1}{33.33}+\dfrac{1}{\infty}=\dfrac{1}{v}[/tex]

[tex]\dfrac{1}{v}=-\dfrac{1}{33.33}[/tex]

[tex]v=-33.33\ cm[/tex]

The eye's far point is 33.33 cm from the eye.

Hence, (a). The eye's near point is 68.98 cm from the eye.

(b). The eye's far point is 33.33 cm from the eye.

The near point for which a lens of +2.55 diopters is prescribed is 71 cm.

We have to obtain the focal length of the lens as follows;

f = 100/P

Where P is the power of the lens in diopters.

f = 100/2.55 = 39.2 cm

Now;

Given that;

1/f = -1/v + 1/u

f = focal length

v = image distance

u = object distance

1/v = 1/u - 1/f

u = Near point of the normal  eye

1/v = 1/25 - 1/39.2

v = 71 cm

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Explain how high energy electrons are used in electron transport

Answers

High energy electrons & hydrogen ions from NADH & FADH2 produced in the Krebs cycle used to convert ADP to ATP

The Krebs cycle produces high-energy electrons that are used by the electron transport chain to change ADP into ATP. Through the electron transport chain, high-energy electrons from NADH and FADH2 are transferred from one carrier protein to the next.

What is an Electron?

An electron is a subatomic particle with a negative charge that can be either attached to or detached from an atom (not bound). Along with protons and neutrons, the electron, which is bonded to the atom, is one of the three major types of particles inside an atom.

Electrons, protons, and neutrons comprise the nucleus of an atom. The protons' positive charge counterbalances the electron's negative charge. The number of protons and electrons in an atom must be equal for it to be in a neutral state.

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"Which of the following is most like the rotation" of stars in the disk of the Milky Way? cars moving at a constant speed on a circular race track the planets in our solar system a DVD in a player the hands of an analog clock the tire of a car moving

Answers

Answer:

cars moving at a constant speed on a circular race track.

Explanation:

The rotation of stars in the disk of milky way is more like that of cars moving at a constant speed on a circular race track.

That is all stars are rotating at fixed point in a fixed orbit , such that no two stars are crossing each other. Speed of all stars are different from each other but all stars are rotating at a constant speed.

How is work related to potential energy and kinetic energy?

Answers

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Work is the force on the object as it changes a distance. Interestingly, as work is done on an object, potential energy can be stored in that object. For example, if you carry a load up the stairs. Now that load will have potential energy that can be transformed into kinetic energy and so on

Work is defined as the force acting on an object because it changes a distance. While work is done on an object, the potential energy can be stored in that object. Thus, the relationship between work and energy is direct because the difference in kinetic energy of an object is the work done by the object.

What is Work done?

Work done by a force is defined as the product of displacement and the component of force exerted by the object in the direction of displacement, thus when we push a block with some force the body starts moving with some acceleration moves, that's why the work is done.

Some transfer of energy may occur in the method of force where the amount of energy transferred by a force to move an object is called the work done.

Potential energy and work done are the same as kinetic energy and work done because potential energy is a state of the system, a way of storing energy as a property of its configuration or motion, while work is done in most cases there is a way to convert this energy from one body to another which is known as kinetic energy

Thus, Work is defined as the force acting on an object because it changes a distance.

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For which of the following situations is the conservation of mechanical energy most likely to be a valid assumption?a. a skateboard rolls across a sewer grate
b. a parachutist falls from a plane
c. you rub your hands together to keep warm
d. a soccer ball flies through the air

Answers

Answer: Option c is Correct!

You rub your hands together to keep warm.

Explanation:

First and foremost, mechanical energy is the sum of kinetic energy and potential energy of a system.

M.E = K.E + P.E

Where;

M.E= Mechanical energy

K.E= Kinetic energy

P.E= Potential energy

The kinetic energy is the energy possesed by a moving body, while the Potential energy is possesed by a stationary body.

When you rub your hand together to produce heat that keeps you warm, there is conservation of energy.

According to the first law of thermodynamics also known as the energy conservation law: it states that energy can neither be created nor destroyed, but can be transformed from one form to another.

The rubbing of the hand creates a motion(Kinetic energy) between the palms, this motion is opposed by a force called friction. thus the generation of heat accounts for the transfer of energy from Kinetic to Heat energy, therefore Mechanical energy is conserved according to the law of thermodynamics

How can researching travel time, routes and weather conditions benefit drivers who are planning a road trip?

Answers

Explanation:

They will be alerted of the traffic conditions. They can choose the route according to the weather condition. They will be aware if there is any road construction going on or accident happened. These awareness will save their time and avoid delays. their journey can be more comfortable and less trouble some.

Explanation:

Researching these options time, routes and weather conditions and even more gives the driver ample information about the journey, and places the driver in better position for decision making, with this information and data afore hand he can decides the best route to take should there be any gridlock, he even decides where or not to embark on the journey based on the prevailing weather conditions,

Regarding time of the journey he is well disposed for proper planning and scheduling.

A car travels over a dirt road that contains a series of equally spaced bumps (a so-called "washboard" road). While traveling at a given speed the driver experiences a very jarring ride. When the driver drives at a higher speed, however, the ride gets smoother. That is because

Answers

Answer:

Explanation:

When a car moves faster then it made suspension to oscillate at a faster rate than the previous frequency. The comfort of the car depends upon the natural frequency of suspension. A low frequency can give discomfort while the high frequency can also be harsh. An optimum frequency matching the level of human comfort is desired in the suspension system to absorb the shock.

The ride is perceived as comfortable when the natural frequency is at the level of 60 to 90 cycles per minute.                      

An oxygen sensor is being tested with a digital multimeter using the MIN/MAX function. The readings are: minimum = 78 mV; maximum = 932 mV; average = 442 mV. Technician A says that the engine is operating normally. Technician B says that the oxygen sensor is skewed too rich. Which technician is correct?

Answers

Answer:

Technician A

Explanation:

An oxygen sensor is being tested with a digital multimeter using the MIN/MAX function. The readings are: minimum = 78 mV; maximum = 932 mV; average = 442 mV. Technician A says that the engine is operating normally. Technician B says that the oxygen sensor is skewed too rich. Which technician is correct?

an oxygen sensor detects te amount of oyen in an engine at the exhaust pipe.

if the  oxygen sensor detects oxygen at the above boundary condition, ten the engine is in good working condition

"Several light bulbs each of resistance 1.25 Ω are connected in series across a 115 V power supply. If the current through the circuit is 2 A, what is the number of light bulbs in the circuit?

Answers

Answer:

The number of bulbs = 46 bulbs

Explanation:

Ohm's Law: Ohm's law states that the current flowing through a conductor is directly proportional to its potential difference across its ends. At constant temperature and pressure. It can be expressed mathematically as

V = IR............. Equation 1

making R the subject of formula in equation 1

R = V/I.............. Equation 2

Where R = combined resistance of the several bulbs, V = potential difference, I = current through the circuit.

Given: V= 115 V. I = 2 A.

Substituting these values into equation 2,

R = 115/2

R = 57.5 Ω

Since the bulbs are connected in series,

Number of bulbs = combined resistance/resistance of each bulb

Number of bulbs =  R/Rₙ...................... Equation 3

Where Rₙ = resistance of each bulb, R =combined resistance of the bulb.

Also given: Rₙ = 1.25 Ω, and R = 57.5 Ω

Substituting these values into equation 3

Number of bulbs = 57.5/1.25

Number of bulbs = 46 bulbs.

Therefore the number of bulbs = 46 bulbs

By using Ohm's law to calculate the total resistance of the circuit and dividing it by the resistance of a single bulb, we find that there are 46 light bulbs in the series circuit.

To, calculating the number of light bulbs in a series circuit based on the total resistance of the circuit, which can be found by using Ohm's law. Ohm's law states that the resistance (R) of a circuit can be calculated by dividing the voltage (V) across the circuit by the current (I) through the circuit, which is expressed as R = V/I. Given a 115 V power supply and a current of 2 A, the total resistance of the circuit is R = 115 V / 2 A = 57.5 Ω.

Each light bulb has a resistance of 1.25 Ω, so the number of light bulbs can be calculated by dividing the total resistance by the resistance of a single bulb:

Number of bulbs = Total resistance / Resistance of one bulb

= 57.5 Ω / 1.25 Ω

= 46 bulbs.

An athlete notices that, after lifting a 100 kilogram weight, he has to increase the weight to 105 kilograms before he feels that the weight is actually heavier. If the athlete later lifts a 200 kilogram weight, which of the following coincides with the just noticeable difference for this weight?
a. A 190 kg weight
b. A 205 kg weight
c. A 215 kg weight
d. A 220 kg weight

Answers

Answer:

option A

Explanation:

given,

lifting weight = 100 Kg

increase in the weight = 105 Kg

later athlete lift = 200 Kg

Weber's law states that Just noticeable difference of weight is equal to ratio of change to the original.

Just noticeable difference for weight will be

    =[tex]\dfrac{105-100}{100}[/tex]

    = 5 %

since second weight is 200 Kg

so, Just noticeable difference of 200 Kg will be equal to ± 5 % of 200 Kg  which is equal to ± 10 Kg.

now,

Just noticeable difference for 200 Kg

     = 200 + 10 or 200 -10

     = 210 Kg or 190 Kg

Hence, the correct answer is option is option A

Hole filling fasteners (for example, MS20470 rivets) should not be used in composite structures primarily because of the?

Answers

Answer:

We can cause delamination.

Explanation:

The reason why is because the probability of causing delamination increase considerably when we use Hole-filling fasteners. If we use a typical rivet, these tends to expands in order to fill the hole.

If we analyze the force applied by the expanded rod will cause that the matrial will be deteriorated and will cause that the material to delaminate around the edges of the hole and we can cause possible control and no protection to the material.

A helicopter (m = 3250 kg) is cruising at a speed of 56.9 m/s atan altitude of 185 m. What is the total mechanical energy of thehelicopter?A) 6.91 x 107 JB) 5.26 x 107 JC) 1.12x 108 JD) 2.27 x 108 JE) 3.91 x 107 J

Answers

Answer:

The mechanical energy of the helicopter is [tex]1.12\times 10^7\ J[/tex].

Explanation:

It is given that,

Mass of the helicopter, m = 3250 kg

Speed of the helicopter, v = 56.9 m/s

Position of the helicopter, h = 185 m

The energy possessed by an object due to its motion is called its kinetic energy. It is given by :

[tex]E=\dfrac{1}{2}mv^2[/tex]

[tex]E=\dfrac{1}{2}\times 3250\times (56.9)^2[/tex]  

[tex]E=5.26\times 10^6\ J[/tex]

The energy possessed by an object due to its position is called its potential energy. It is given by :

[tex]E=mgh[/tex]

[tex]E=3250\times 9.8\times 185[/tex]  

[tex]E=5.89\times 10^6\ J[/tex]

The sum of kinetic and potential energy is called mechanical energy of the system. It is given by :

[tex]M=5.26\times 10^6+5.89\times 10^6[/tex]

[tex]M=11.15\times 10^6\ J[/tex]

or

[tex]M=1.12\times 10^7\ J[/tex]

So, the mechanical energy of the helicopter is [tex]1.12\times 10^7\ J[/tex]. Hence, this is the required solution.

In Times Square in New York City, people celebrate on New Year's Eve. Some just stand around, but many move about randomly. Consider a system comprised of all of these people. Approximately, what is the total linear momentum of this system at any given instant?

Answers

Answer:

The total linear momentum at any time is zero.

Explanation:

Hi there!

The momentum of an object is a vector that is calculated by multiplying the mass of the object times its velocity.

The momentum of the system is calculated by adding the momenta of each object that comprise the system (in this case, all the people in Times Square).

Since the people move randomly in all directions, it is most probable that the total momentum of the system is zero because the momentum vectors of people moving in one direction will surely be canceled by the momentum vectors of people moving in the opposite direction. In total, the sum of momentum vectors will be zero (the standing people have null momentum because their velocities are zero).

Final answer:

The total linear momentum of a crowd in Times Square on New Year's Eve can be approximated as zero due to the random and varied movements of the people in the crowd, balancing each other out.

Explanation:

When considering the total linear momentum of a system like the crowd in Times Square on New Year's Eve, we must consider that the system is made up of individuals moving in various directions with different velocities. According to the physical definition of momentum, which is the product of mass and velocity (P = mv), every person has their own momentum. If we assume an idealized situation where movement is random and there is as much motion in one direction as in any other, the total momentum of the system can approximatively be zero at any given instant due to the cancellation of people's momentums in opposite directions. Moreover, because people are not likely to all be moving in the same direction with the same speed at the same time, the net velocity (and thus momentum) of the system may be negligible if averaged over time.

According to Newton's second law in terms of momentum, in the absence of an external force, there would be no change in the total momentum of the system. Therefore, assuming Times Square is a closed system with no significant external forces acting on it, and given the randomness of movement, it can be approximated that the total linear momentum of the crowd is approximately zero.1

Two gears are connected. Gear A has 10 teeth, while gear b has 40 teeth. If gear B turns at 10 rpms, how fast will gear a turn?

Answers

Answer:

w₁ =  40 rpm

Explanation:

Number of teeth of gear A = 10

Number of teeth of gear B =  40

Speed of gear B = w₂ = 10 rpm

Speed of gear A = w₁ = ?

Gear ratio is given by:

N₁/N₂ = w₂ / w₁

w₁ = N₂/N₁ * w₂

⇒ w₁ = 40/10 * 10

⇒ w₁ =  40 rpm

Final answer:

Gear A will turn at 40 rpms.

Explanation:

In this scenario, we can use the formula for calculating the speed of rotation of gears. The formula is based on the principle that the number of teeth on a gear is inversely proportional to its speed. In other words, the smaller the gear, the faster it rotates.

Using the formula, we can calculate the speed at which gear A turns:

Speed of gear A = (Number of teeth on gear B/Number of teeth on gear A) x Speed of gear B

Plugging in the values, we get:

Speed of gear A = (40/10) x 10 = 40 rpms

Learn more about Gear rotation here:

https://brainly.com/question/32444384

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