A fish is swimming at 500 KM/hour and suddenly as shark appears behind, for 5 seconds the fish is swimming in the same direction but increases its speed to 2500 Km/H What is its average acceleration?

Answers

Answer 1

Answer:

[tex]a =111.1\ m/s^2[/tex]

Step-by-step explanation:

The formula to calculate the average acceleration is:

[tex]a =\frac{s_2-s_1}{t_2-t_1}[/tex]

Where s is the speed of the object and t is the time it takes the object to change its speed [tex]s_1[/tex] to the speed [tex]s_2[/tex]

In this case we have that:

[tex]t_2-t_1 = 5\ sec[/tex]

[tex]s_1 = 500\ km/h = 500*\frac{1\ h}{3600\ s}*\frac{1000\ m}{1\ km}=138.89\ m/s[/tex]

[tex]s_2= 2500\ km/h = 2500*\frac{1\ h}{3600\ s}*\frac{1000\ m}{1\ km}=694.44\ m/s[/tex]

[tex]a =\frac{694.44-138.89}{5}\ m/s^2[/tex]

[tex]a =111.1\ m/s^2[/tex]


Related Questions

The table shows the effect of education on annual income. Based on the data in the table, how much more does a person with an Bachelor’s degree earn than a person with only a high school diploma over 10 years?


A) $20,800
B) $29,690
C) $208,000
D)$290,690

Answers

B is the correct answer

At which point(s) do the graphs of y = x + 1 and y = 2x intersect?

Answers

Answer:

(1,2)

Step-by-step explanation:

I just used a graphing calculator

At a summer camp, there are 50 girls out of 80 campers.What is this ratio writtin as a fraction in simplest form?​

Answers

The ratio is 5:8 campers

Answer:

50

--- Ratio: 50:80

80

Step-by-step explanation:

50 would be how many girls were that the summer camp. And the 80 is how many students all together at the summer camp.

Hoped This Helped You

Have A Wonderful day

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

Answers

Answer:

[tex]-\sqrt{11}[/tex]

Step-by-step explanation:

As square root value is written with both + and - signs

In Given case:

A polynomial has root [tex]\sqrt{11}[/tex]

= ±3.316

Also [tex]-\sqrt{11}[/tex]

= ±3.316

Hence [tex]-\sqrt{11}[/tex] is also root of the polynomial!

Hello! :)
Please help me. Thanks!
~ Destiny ^_^

Answers

Answer:

720 in³

Step-by-step explanation:

The volume (V) of a right prism is calculated as

V = area of triangular end × length

area of Δ = [tex]\frac{1}{2}[/tex] bh

where b is the base and h the perpendicular height

here b = 8 and h = 15, thus

area of Δ = 0.5 × 8 × 15 = 4 × 15 = 60 in²

The length of the prism is 12 in, hence

V = 60 × 12 = 720 in³

if tanØ = 3/4, Find sinØ

a. SinØ=1/2

b. sinØ = 3/5

c. sinØ = 2

d sin Ø = 8/5

Answers

Answer: This is some information I have gathered to help you since I cannot answer this directly sin θ + (cot θ)(cos θ)  

= sin θ + (cos θ / sin θ)(cos θ)  

= sin θ + cos² θ / sin θ  

Since cos² θ = 1 - sin² θ,  

= sin θ + (1 - sin² θ) / sin θ  

= sin θ + 1 / sin θ - sin θ  

= 1 / sin θ  

= csc θ ∎ Sin(x) = tan(x) / [sqrt(1 + tan^2(x)]  

Sin(theta) =3/4 / sqrt[1 + .75^2]

Sin(theta) =0.75 / sqrt[ 1.5625 ]

Sin(theta) =0.75 / 1.25

Sin(theta) = 0.60

which will result in a difference of squares?

Answers

Answer:

C

Step-by-step explanation:

Answer:

The correct option is 3.

Step-by-step explanation:

The difference of squares is defined as

[tex]a^2-b^2=(a-b)(a+b)[/tex]

In option 1,

[tex](-7x+4)(-7x+4)=(-7x+4)^2[/tex]

This expression is a perfect square, therefore this is not the difference of squares. Option 1 is incorrect.

In option 2,

[tex](-7x+4)(4-7x)=(-7x+4)(-7x+4)=(-7x+4)^2[/tex]

This expression is a perfect square, therefore this is not the difference of squares. Option 2 is incorrect.

In option 3,

[tex](-7x+4)(-7x-4)=(-7x)^2-(4)^2[/tex]

This expression is the difference of squares., therefore Option 3 is correct.

In option 4,

[tex](-7x+4)(7x-4)=-(-7x+4)(-7x+4)=-(-7x+4)^2[/tex]

This expression is a perfect square, therefore this is not the difference of squares. Option 4 is incorrect.

which expression is equivalent to (64y^100)^1/2

Answers

Answer:

8y^50

Step-by-step explanation:

Answer:

8y^50

Step-by-step explanation:

Solve the Equation
2x-3=14
-x+3y=-6

Answers

Step-by-step explanation:

If you lost "y" in the first equation.

[tex]\underline{+\left\{\begin{array}{ccc}2x-3y=14\\-x+3y=-6\end{array}\right}\qquad\text{add both sides of the equations}\\\\.\qquad x=8\\\\\text{Put the value of x to the first equation:}\\\\2(8)-3y=14\\16-3y=14\qquad\text{subtract 16 from both sides}\\-3y=-2\qquad\text{divide both sides by (-3)}\\y=\dfrac{2}{3}\\\boxed{x=8,\ y=\dfrac{2}{3}}[/tex]

If first equation is correct.

[tex]2x-3=14\qquad\text{add 3 to both sides}\\2x=17\qquad\text{divide both sides by 2}\\x=8.5\\\\\text{Put the value of x to the second equation:}\\-8.5+3y=-6\qquad\text{add 8.5 to both sides}\\3y=2.5\qquad\text{divide both sides by 3}\\y=\dfrac{2.5}{3}\\y=\dfrac{25}{30}\\y=\dfrac{5}{6}\\\\\boxed{x=8.5,\ y=\dfrac{5}{6}}[/tex]

how do you make a vegetable necklace? middle school math with pizzazz! book E

Answers

Final answer:

The question from 'Middle School Math with Pizzazz! Book E' appears to utilize pie as a topic to explore fractions. It illustrates fractions visually, such as expressing three out of five slices of pie as 3/5, or six out of ten slices as 6/10 (which simplifies to 3/5).

Explanation:

The question seems to be from the 'Middle School Math with Pizzazz! Book E'. It doesn’t seem to relate directly to the creation of a vegetable necklace, but I can infer that it relates to the concept of fractions, as suggested in the information. In mathematical terms, the slicing of pies and selection of pieces can be equated to the division of a whole into smaller parts, which is how fractions are defined.

For example, slicing one pie into five slices and taking three of them can be represented as 3/5, or three-fifths.  This represents the concept of fractions in an easy-to-understand, visual way. Similarly, splitting one pie into 10 pieces and selecting 6 can be expressed as 6/10, or six-tenths, which also reduces to three-fifths when simplified.

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Final answer:

The 'vegetable necklace' problem seems to be a math-related craft activity aimed at teaching fractions or ratios. It involves creating a necklace pattern with vegetables in a consistent ratio, providing a hands-on way to understand these mathematical concepts in middle school math.

Explanation:

The question appears to be from a workbook called Middle School Math With Pizzazz! Book E, which suggests that the problem is related to a math puzzle or activity. Although the question mentions making a vegetable necklace, this is likely a math-based craft or theoretically presented problem for representing fractions, ratios, or patterns that are common in middle school mathematics.

Based on the provided reference (A.1), we can understand that this problem might be connected to fractions or proportional reasoning. The example given explains how we can divide pies into slices to represent different fractions yet end up with the same quantity. This principle can be applied to making a necklace, where vegetables represent parts of a whole, and different combinations can result in a necklace of the same length or number of items.

To make a vegetable necklace, a student could take a string and add vegetables at regular intervals, ensuring that the pattern or ratio remains consistent. For instance, if the pattern is one carrot for every two tomatoes, and the length of the necklace is to have 15 vegetables, there would be 5 carrots and 10 tomatoes on the string, maintaining the ratio.

This activity would give them a tangible representation of fractions and ratios, providing a hands-on experience in understanding these mathematical concepts.

What is the x-intercept of the graph?

Answers

Answer:

-3

Step-by-step explanation:

The x-intercept is the plot point where y = 0.

Answer:

-3

Step-by-step explanation:

the x-intercept is the point on the graph where the ploted line crosses the x axes  

Can someone help me out with this question plz

Answers

Answer:

[tex]\left(s\cdot t\right)\left(x\right)=2x^2+12x+16[/tex]

[tex]\left(s-t\right)\left(x\right)=-x[/tex]

[tex]\left(s+t\right)\left(4\right)=20[/tex]

Step-by-step explanation:

Given functions are:

[tex]s\left(x\right)=x+4[/tex]

[tex]t\left(x\right)=2x+4[/tex]

Then [tex]\left(s\cdot t\right)\left(x\right)=s\left(x\right)\cdot t\left(x\right)[/tex]

or [tex]\left(s\cdot t\right)\left(x\right)=\left(x+4\right)\left(2x+4\right)[/tex]

or [tex]\left(s\cdot t\right)\left(x\right)=2x^2+4x+8x+16[/tex]

or [tex]\left(s\cdot t\right)\left(x\right)=2x^2+12x+16[/tex]

---------

Similarly

[tex]\left(s-t\right)\left(x\right)=s\left(x\right)-t\left(x\right)[/tex]

or [tex]\left(s-t\right)\left(x\right)=\left(x+4\right)-\left(2x+4\right)=x+4-2x-4[/tex]

or [tex]\left(s-t\right)\left(x\right)=-x[/tex]

---------

Similarly

[tex]\left(s+t\right)\left(4\right)=s\left(4\right)+t\left(4\right)=\left(4+4\right)+\left(2\left(4\right)+4\right)=\left(8\right)+\left(12\right)=20[/tex]

[tex]\left(s+t\right)\left(4\right)=20[/tex]

what are the solutions of this equation 16-2x^2=-64

Answers

Answer:

x = ± 2[tex]\sqrt{10}[/tex]

Step-by-step explanation:

Given

16 - 2x² = - 64 ( subtract 16 from both sides )

- 2x² = - 80 ( divide both sides by - 2 )

x² = 40 ( take the square root of both sides )

x = ± [tex]\sqrt{40}[/tex] = ± [tex]\sqrt{4(10)}[/tex] = ± 2[tex]\sqrt{10}[/tex]

11-30x+24. what is this answer ​

Answers

Answer:

-30x+35

Step-by-step explanation:

Add 11 and 24

Question: An arithmetic sequence is a sequence with a common difference. It can be represented by the recursive formula a1 = a (where a is the first term of the sequence); an = an - 1 + d. a) Create your own arithmetic sequence. Write out the first 3 terms. b) What is the common difference of your sequence? c) Write the recursive formula representing your sequence. Use the underscore symbol to indicate a subscript. For example, the recursive formula would be written like a1 = a; a_n = a_(n – 1) + d

Answers

Answer:

a) 3,6,9,12,15,..

b) Common Ratio is 3

c) Recursive Formula : aₙ= aₙ₋₁ + d where a₁=3 and d= 3

Step-by-step explanation:

a) Create your own arithmetic sequence. Write out the first 3 terms.

Consider the sequence: 3,6,9,12,15,..

a₁ = 3

a₂ = 6

a₃ = 9

b) What is the common difference of your sequence?

6-3 = 3

9-6 = 3

12 -9 =3

So, common difference is 3

c) Write the recursive formula representing your sequence.

a₁ = 3

a₂ = aₙ₋₁ + d

   = a₁ + d

   = 3+ 3 = 6

a₃ = aₙ₋₁ + d

    = a₂ + d

   = 6+3 = 9

so, recursive formula is aₙ = aₙ₋₁ + d where a₁ = 3 and d= 3

Final answer:

An example of an arithmetic sequence can be created with a starting value (a1) of 2 and a common difference (d) of 3. The sequence's terms would be 2, 5, 8, etc. Its recursive formula would be a1 = 2; a_n = a_(n–1) + 3.

Explanation:

Let's create an arithmetic sequence, starting with the first term (a1) of 2 and a common difference (d) of 3. So, the first three terms of the sequence would be 2, 2+3=5, and 5+3=8.

The common difference of this arithmetic sequence is 3 as each term is 3 greater than the previous term.

The recursive formula for this sequence is a1 = 2; a_n = a_(n–1) + 3. What this formula means is that the first term is 2, and each subsequent term (an) is the previous term (an-1) added to the common difference (3).

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The histogram shows the weekly attendance of participants in a school's study skills program. Student attendance numbers were the same during which two weeks of the workshop?



A.
weeks 1 and 2
B.
weeks 2 and 4
C.
weeks 5 and 6
D.
weeks 4 and 6

Answers

That would be week 2 and 4 (B). They are both at 12 students attending

Hope this helped!

Answer:

The correct option is B.  weeks 2 and 4.

Step-by-step explanation:

Consider the provided histogram.

The histogram shows the weekly attendance of participants in a school's study skills program.

Now, consider the Histogram.

In week 1 the Student attendance was 8.

In week 2 the Student attendance was 12.

In week 3 the Student attendance was 15.

In week 4 the Student attendance was 12.

In week 5 the Student attendance was 18.

In week 6 the Student attendance was 16.

Hence the Student attendance numbers were the same during week 2 and week 4 of the workshop.

Therefore, the correct option is B.  weeks 2 and 4

Taxes are used for which of the following?​

Answers

Depending on the country, most democracies use taxes for:

-public programs (any governmentally run or funded services)

-infrastructure (roads, bridges, etc)

-the military

-schools

-governmental departments (EPA, Department of Homeland Security, etc)

-government employee paychecks

And SOMETIMES:

-universal healthcare

-college/university

-etc.

Final answer:

Taxes are used to fund government services, reduce income inequalities, and support state and local government activities.

Explanation:

Taxes are used for a variety of purposes. They are primarily used to fund government services such as military, police, education, infrastructure, and social security. Taxes are also used to reduce income and wealth inequalities by transferring income to lower income groups. Additionally, taxes are used to support state and local government activities and services.

For example, in the United States, the federal government raises revenue through income taxes, corporate earnings taxes, and sales taxes on goods such as gasoline, alcohol, and tobacco. State and local governments also collect taxes, including income, property, and sales taxes, which fund activities like maintaining public parks and providing a police force.

Overall, taxes play a crucial role in financing government operations and essential public services that benefit communities.


9 is subtracted from 5 times 3 and 10 is added

Answers

The answer to “9 is subtracted from 5 times 3 and 10 is added” is 16.

The final answer is 16

What is subtraction?

The act or process of taking one number away from another is called subtraction.

How to now the final value  after subtraction?

According to the problem,

9 is subtracted from 5 times 3 and 10 is added

This can be written as (5 x 3) + 10- 9

 =  16

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Given the system of equations, match the following items.
2 x - y = 0
x + y = -3

[0 -1
-3 1]

[2 0
1 -3]

[2 -1
1 1]

Answers

The x - determinant of the equation is [tex]\left[\begin{array}{cc}0&-1\\-3&1\\\end{array}\right][/tex]

The y - determinant of the equation is [tex]\left[\begin{array}{cc}2&0\\1&-3\\\end{array}\right][/tex]

The system determinant is [tex]\left[\begin{array}{cc}2&-1\\1&1\\\end{array}\right][/tex]

How to find the determinants of x, y and the entire system?

The given system of equation include the following;

2x - y = 0

x + y = - 3

The x - determinant of the equation will be obtained by replacing coefficient of x with the constant terms.

[tex]\Delta x = \left[\begin{array}{cc}0&-1\\-3&1\\\end{array}\right][/tex]

The y - determinant of the equation will be obtained by replacing coefficient of y with the constant terms.

[tex]\Delta y = \left[\begin{array}{cc}2&0\\1&-3\\\end{array}\right][/tex]

The system determinant is obtained by removing the constant term and writing only the x and y coefficient in the matrix;

[tex]\Delta = \left[\begin{array}{cc}2&-1\\1&1\\\end{array}\right][/tex]

What is the y-intercept of the equation of the line that is perpendicular to the line y = 3/5 x + 10 and passes through the point (15, –5)?

The equation of the line in slope-intercept form is y = -5/3 x +

Answers

Answer:

[tex]\large\boxed{y-intercept=20}[/tex]

Step-by-step explanation:

[tex]\text{Let}\ k:y=_1x+b_1\ \text{and}\ l:y=m_2x+b_2.\\\\l\ \perp\ k\iff m_1m_2=-1\to m_2=-\dfrac{1}{m_1}\\============================\\\\\text{We have}\ y=\dfrac{3}{5}x+10\to m_1=\dfrac{3}{5}.\\\\\text{Therefore}\ m_2=-\dfrac{1}{\frac{3}{5}}=-\dfrac{5}{3}.\\\\\text{The equation of the searched line:}\ y=-\dfrac{5}{3}x+b.\\\\\text{The line passes through }(15,\ -5).[/tex]

[tex]\text{Put thecoordinates of the point to the equation.}\ x=15,\ y=-5:\\\\-5=-\dfrac{5}{3}(15)+b\\\\-5=(-5)(5)+b\\\\-5=-25+b\qquad\text{add 25 to both sides}\\\\b=20\\\\\boxed{y=-\dfrac{5}{3}x+20}[/tex]

A number increase by 7 is greater than 30

Answers

Answer:

x > 23

Step-by-step explanation:

Subtract 7 on both sides in the equation: x + 7 > 30

You will get x > 23

(b)
5 cm
5 cm
108
cm
1080
1080
5 cm
5 cm
108°
1089
5 cm​

Answers

Answer:

(b)

5 cm

5 cm

108

cm

1080

1080

5 cm

5 cm

108°

1089

5 cm​

Step-by-step explanation:

Ummmmm. :)

well hope it helped you!

Answer:

Given that ΔJKL ≅ ΔUVW and ΔUVW ≅ ΔABC, complete the following statements.

Triangle JKL is congruent to triangle .

Side LK corresponds to sides .

Angle JLK corresponds to angles .

Step-by-step explanation:

HELP ME PLEASE!!!!I BEGG YOUUUU PLEASE IM STUCK!!!

Answers

Hello There!

All of the areas are indeed perfect squares.

4x4 is 16

5x5 is 25

3x3 is 9

what is the location of the point on the number line that is 2/5 of the way from A=-6 to B=9?​

Answers

Answer:

0

Step-by-step explanation:

Between -6 and 9 are 15 units.

2/5 of 15 units is 6 units.  Add this to -6 to obtain 0.

0 is the answer to this question

Step-by-step explanation:

I'm not sure but I think its like the distance between -6 and 9 is 15 or something and 15 divided by 5 is 3 and 2/5 is 6 so 6-6 is 0 and that's that point.

The distance between two cities is 500 miles. On a map, they are 4 inches apart. What is the scale of the map?

Answers

500/4 = x/1

125 = x

125 miles per inch.

What is the surface area of this composite solid?

square feet

Answers

let's take a peek

we really have a rectangular prism below a square pyramid.

the prism has a front, back, left and right of a rectangle 2x11 .

its bottom or base is an 11x11 square.

the pyramid 4 triangles, each one has a base of 11 and a height of 7.

[tex]\bf \stackrel{\textit{front, back, left, right}}{4(2\cdot 11)}~~+~~\stackrel{\textit{base}}{(11\cdot 11)}~~+~~\stackrel{\textit{four triangles}}{4\left[ \cfrac{1}{2}(11)(7) \right]} \\\\\\ 88+121+154\implies 363[/tex]

Answer:

The surface area of composite solid = 363 ft²

Step-by-step explanation:

Points to remember

Area of rectangle = Length * Breadth

Area of triangle = bh/2

Where b - Base and h - Height

To find the surface area of composite solid

Surface area = Base area  + side area  + area of 4 triangles

 = (11 * 11) + 4(11 * 2) + 4(11 * 7)/2

 = 121 + 88 + 154

 = 363 ft²

Therefore the surface area of composite solid = 363 ft²

there are 48 heads and 134 legs how many sheep is there​

Answers

Answer:

48

Step-by-step explanation:

48 heads =48sheep. .i guess. .......

Something's odd with this question: each sheep has one head, so if you see 48 heads there are 48 sheeps.

But each sheep has also 4 legs, so if you have 48 sheeps you should see

[tex]48\cdot 4 = 192\text{ legs}[/tex]

So, unless you have some sheeps with missing legs, there must be a mistake in the question.

If m1 = 110°, an arc with a measure of 250°.

BC
BCA
CTA


Answers

Answer:

the correct answer is BCA

Answer:

The correct option is 2.

Step-by-step explanation:

Given information: [tex]m\angle 1=110^{\circ}[/tex].

It is given that [tex]m\angle 1=110^{\circ}[/tex], so arc(BA)=110° and the central angle of arc BCA is

[tex]Arc(BCA)=360^{\circ}-Arc(BA)[/tex]

[tex]Arc(BCA)=360^{\circ}-110^{\circ}[/tex]

[tex]Arc(BCA)=250^{\circ}[/tex]

The measure of arc BC is

[tex]180^{\circ}-110^{\circ}=70^{\circ}[/tex]

The measure of arc CTA is 180° because AC is the diameter.

It means options 1 and 3 are incorrect.

The measure of arc BCA is 250°. Therefore the correct option is 2.

What is the solution to the equation?

(A) d = –4 and d = 2
(B) d = –2 and d = 4
(C) d = 1
(D) d = 2
MY LAST QUESTION HELP.

Answers

ANSWER

(C) d=1

EXPLANATION

The given equation is

[tex] \frac{ - 3d}{ {d}^{2} - 2d - 8} + \frac{3}{d - 4} = \frac{ - 2}{d + 2} [/tex]

Factor the first fraction to get,

[tex] \frac{ - 3d}{(d + 2)(d - 4)} + \frac{3}{d - 4} = \frac{ - 2}{d + 2} [/tex]

Multiply through by (d+2)(d-4)

[tex] - 3d + 3(d + 2) = - 2(d - 4)[/tex]

Expand:

[tex] - 3d + 3d + 6 = - 2d + 8[/tex]

[tex] 6 = - 2d + 8[/tex]

[tex]6 - 8= - 2d[/tex]

[tex] - 2 = - 2d[/tex]

divide both sides by -2

[tex]d = 1[/tex]

The correct answer is (B) [tex]\( d = -2 \)[/tex] and [tex]\( d = 4 \)[/tex].

To find the solution to the given quadratic equation, we can factor it or use the quadratic formula. The equation is not provided in the conversation, but based on the options given, it seems that the equation could be in the form [tex]\( (d - a)(d - b) = 0 \)[/tex], where [tex]a[/tex] and [tex]b[/tex]are the roots of the equation.

The quadratic equation can be written as [tex]\( d^2 - (a+b)d + ab = 0 \)[/tex]. To have the sum of the roots [tex]\( a + b \)[/tex] equal to 0 and the product of the roots [tex]\( ab \)[/tex] equal to -8, we can set up the following system of equations:

1. [tex]\( a + b = 0 \)[/tex]

2. [tex]\( ab = -8 \)[/tex]

From equation 1, we can express [tex]\( b \)[/tex] in terms of [tex]\( a \): \( b = -a \).[/tex]

Substituting [tex]\( b \)[/tex] into equation 2, we get:

[tex]\( a(-a) = -8 \)[/tex]

[tex]\( -a^2 = -8 \)[/tex]

[tex]\( a^2 = 8 \)[/tex]

Taking the square root of both sides, we find:

[tex]\( a = \pm\sqrt{8} \)[/tex]

[tex]\( a = \pm2\sqrt{2} \)[/tex]

Since [tex]\( b = -a \),[/tex] we have:

[tex]\( a = 2\sqrt{2} \) and \( b = -2\sqrt{2} \)[/tex]

[tex]\( a = -2\sqrt{2} \) and \( b = 2\sqrt{2} \)[/tex]

However, these are not the exact values given in the options. We need to find the exact integer values for [tex]a[/tex] and [tex]b[/tex]. Since the product [tex]\( ab \)[/tex] is -8, we can look for two numbers that multiply to -8 and add up to 0. These numbers are -2 and 4.

Therefore, the solutions to the equation are [tex]\( d = -2 \)[/tex] and [tex]\( d = 4 \)[/tex], which corresponds to option (B).

Solve the equation for x. If a solution is extraneous, be sure to identify it in your final answer.

Square root of the quantity x-6 end quantity - 4 =x

Answers

Answer:

x=-2 is the only solution

Step-by-step explanation:

The given equation is

[tex]\sqrt{x+6}-4=x[/tex]

Add 4 to both sides of the equation.

[tex]\sqrt{x+6}=x+4[/tex]

Square both sides

[tex]x+6=(x+4)^2[/tex]

[tex]x+6=x^2+8x+16[/tex]

Rewrite in standard form;

[tex]x^2+8x-x+16-6=0[/tex]

[tex]x^2+7x+10=0[/tex]

[tex]x^2+7x+10=0[/tex]

[tex](x+2)(x+5)=0[/tex]

x=-2 or x=-5

Checking for extraneous solution.

When x=-2

[tex]\sqrt{-2+6}-4=-2[/tex]

[tex]\sqrt{4}-4=-2[/tex]

[tex]2-4=-2[/tex]. This statement is true. This implies that: x=-2 is a solution.

When x=-5

[tex]\sqrt{-5+6}-4=-5[/tex]

[tex]\sqrt{1}-4=-5[/tex]

[tex]1-4=-5[/tex]. This statement is not true. This implies that: x=-5 is an extranous solution.

Other Questions
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