A fancart of mass 0.8 kg initially has a velocity of < 0.9, 0, 0 > m/s. Then the fan is turned on, and the air exerts a constant force of < -0.3, 0, 0 > N on the cart for 1.5 seconds. What is the change in momentum of the fancart over this 1.5 second interval? = < , 0, 0 > kg

Answer:

4.88505 m/s

1.21629 m

Explanation:

[tex]m_1[/tex] = Mass of bullet = 2.5 g

[tex]m_2[/tex] = Mass of block = 215 g

[tex]v_1[/tex] = Velocity of bullet = 425 m/s

[tex]v_2[/tex] = Velocity of block

Here, the linear momentum is conserved

[tex]m_1v_1+m_2v_2=(m_1+m_2)v\\\Rightarrow v=\dfrac{m_1v_1+m_2v_2}{m_1+m_2}\\\Rightarrow v=\dfrac{2.5\times 10^{-3}\times 425+0.215\times 0}{2.5\times 10^{-3}+0.215}\\\Rightarrow v=4.88505\ m/s[/tex]

The speed of the combination of mass is 4.88505 m/s

The energy in the system is conserved

[tex]\dfrac{1}{2}(m_1+m_2)v^2=(m_1+m_2)gh\\\Rightarrow h=\dfrac{v^2}{2g}\\\Rightarrow h=\dfrac{4.88505^2}{2\times 9.81}\\\Rightarrow h=1.21629\ m[/tex]

The maximum height the combined mass will reach is 1.21629 m

Answer:

Explanation:

mass of bullet, m = 2.5 g

initial velocity of bullet, u = 425 m/s

mass of block, M = 215 g

(a) Let the speed of bullet block system is v

Use the conservation of momentum

m x u + M x 0  = (M + m) x v

2.5 x 425 = ( 215 + 2.5) x v

v = 4.89 m/s

(b) Let it rise upto height h

Use conservation of energy

Kinetic energy after collision = Potential energy

1/2 (M + m) v² = ( M+ m) x gx h

0.5 x 4.89 x 4.89 = 9.8 x h

h = 1.22 m

Answer:

The average atomic mass can be calculated from the exact atomic mass of each isotope by multiplying the mass each isotope by its relative abundance and then finding the sum of the result.

for example carbon has two major isotopes ;carbon 12 ,atomic mass  with relative abundance of 98.9% and carbon  13 , atomic mass of   with relative abundance 1.1%. The relative atomic mass is calculated below.

[tex]RAM = 12*\frac{98.9}{100}+13.003355 *\frac{1.1}{100}[/tex]

RAM=11.868 + 0.143036905

RAM=12.011036905amu

Answer:

A)  R = (200 i ^ + 100 j ^ + 30k ^) m , B)    L = 223.61 m , C)   R = 225.61 m

Explanation:

Part A

This is a vector summing exercise, let's take a Reference System where the z axis corresponds to the height (flights), the x axis is the East - West and the y axis corresponds to the North - South.

Let's write the displacements

Descending from the apartment

10 flights of 3 m each, the total descent is 30 m

                Z = 30 k ^ m

Offset at street level

            L1 = 0.2 i ^ km

            L2 = 0.1 j ^ km

Let's reduce everything to the SI system

          L1 = 0.2 * 1000 = 200 i ^ m

          L2 = 100 j ^ m

The distance traveled is

          R = (200 i ^ + 100 j ^ + 30k ^) m

Part B

The horizontal distance traveled can be found with the Pythagorean theorem for the coordinates in the plane

                L² = x² + y²

                L = √ (200² + 100²)

                L = 223.61 m

Part C

The magnitude of travel, let's use the Pythagorean theorem for the sum

             R² = x² + y² + z²

              R = √ (30² + 200² + 100²)

             R = 225.61 m

According to Prof. Bill Baker, the freedom of practicing professionals to make ethical decisions may not be worth unless they use a patterned approach for the sake of people and society and their welfare. This is true statement.

Answer: Option A

Explanation:

Ethical Decisions and their impact on society

When we talk about the professional fields; Engineers and Doctors comes first in our minds. The professional fields and persons make the roots of an ideal society for which they must take ethical decisions surely worth for the society.

The society has a right to expect ethical conduct from professionals. The conduct of taking ethical decisions must involve reasoning, planning and well execution. According to the Association for Practical and Professional Ethics, there are certain moral values that one must apply while practicing ethical decisions.

Final answer:

The magnitude of the acceleration of the speed skater on the rough ice is 2.8 m/s², calculated using the equation of motion.

Explanation:

To find the magnitude of the acceleration of the speed skater on the rough ice, we can use the equation of motion: v^2 = u^2 + 2as, where v is the final velocity, u is the initial velocity, a is the acceleration, and s is the displacement (width of rough ice).

Given that the skater's initial velocity (u) is 8.0 m/s, her final velocity (v) is 6.0 m/s, and the width of the rough ice (s) is 5.0 m.

Rearranging the equation for acceleration, we get a = (v^2 - u^2) / (2s). Substituting the given values, a = (6.0^2 - 8.0^2) / (2 * 5.0) = (-28) / 10 = -2.8 m/s2. The negative sign indicates deceleration, but since the question asks for the magnitude, the acceleration is 2.8 m/s2.

Explanation:

Electric field is the ratio of force and charge.

Force, F = 6 x 10⁻⁶ N

Charge, q = 3.53 x 10⁻⁸ C

We have           

       [tex]E=\frac{F}{q}\\\\E=\frac{6\times 10^{-6}}{3.53\times 10^{-8}}\\\\E=169.97N/C[/tex]

Electric field at the location of the charge is 169.97 N/C

Answer:

top of the highest hill

Explanation:

The potential energy of an object is given by

[tex]U=mgh[/tex]

where,

m = Mass of the object

g = Acceleration due to gravity

h = Perpendicular distance from the ground.

It can be seen that the potential energy is proportional to height

[tex]U\propto h[/tex]

Here, the car will have maximum potential energy when it is at the maximum distance from the ground.

Hence, the car will be at the top of the highest hill

The front car of a roller coaster will have its greatest potential energy at the highest hill due to the stored gravitational potential energy that can be converted into kinetic energy as it descends.

Potential energy in a roller coaster system is greatest at the highest hill. At this point, the roller coaster's gravitational potential energy is at its maximum as it has the most stored energy that can be converted into kinetic energy as it descends. This transformation between potential and kinetic energy explains why the roller coaster's front car will most likely have its greatest potential energy at the top of the highest hill.

Answer:

Approximate atomic radius for polonium-209 is 167.5 pm .

Explanation:

Number of atom in simple cubic unit cell = Z = 1

Density of platinum = [tex]9.232 g/cm^3[/tex]

Edge length of cubic unit cell= a = ?

Atomic mass of Po (M) = 209 g/mol

Formula used :  

[tex]\rho=\frac{Z\times M}{N_{A}\times a^{3}}[/tex]

where,

ρ = density

Z = number of atom in unit cell

M = atomic mass

[tex](N_{A})[/tex] = Avogadro's number  

a = edge length of unit cell

On substituting all the given values , we will get the value of 'a'.

[tex]9.232 g/cm3=\frac{1 \times 209 g/mol}{6.022\times 10^{23} mol^{-1}\times (a)^{3}}[/tex]

[tex]a = 3.35\times 10^{-8} cm[/tex]

Atomic radius of the polonium in unit cell = r

r = 0.5a

[tex]r=0.5\times 3.35\times 10^{-8} cm=1.675\times 10^{-8} cm[/tex]

[tex]1 cm = 10^{10} pm[/tex]

[tex]1.675\times 10^{-8} cm=1.675\times 10^{-8}\times 10^{10}=167.5 pm[/tex]

Approximate atomic radius for polonium-209 is 167.5 pm.

To find the approximate atomic radius of polonium-209, we can use its simple cubic crystal structure and the fact that its coordination number is six. By determining the mass contained within a unit cell and its volume, we can calculate the atomic radius.

To approximate the atomic radius of polonium-209, we can use the fact that polonium crystallizes in a simple cubic structure. In this structure, each polonium atom contacts only its four nearest neighbors in its layer, one atom directly above it in the layer above, and one atom directly below it in the layer below. The coordination number for a polonium atom in a simple cubic array is six.

Since the coordination number is six, we can visualize a polonium atom at the center of a simple cubic unit cell, with one atom at each corner of the cube. The distance from the center of the unit cell to its vertices gives an approximation of the atomic radius of polonium-209.

Given that the density of polonium is 9.232 g/cm3, we can use the formula density = mass/volume to find the mass contained within the unit cell. With the knowledge that a unit cell contains one-eighth of a polonium atom at each of its eight corners, we can determine the volume of the unit cell. By dividing the mass contained within the unit cell by its volume, we can calculate the approximate atomic radius of polonium-209.

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Answer:

Oxygen atom

Ozone Molecule

Explanation:

The upper stratosphere and Mesosphere consist of the ozone layer. This layer helps in protecting us from the UV radiations of the Sun. This layer converts the UV radiation into heat energy.

The UV radiation breaks down the Oxygen molecules in oxygen atom which further combines with oxygen molecule to form Ozone. This Ozone molecule breaks to form Oxygen atom and Oxygen molecule. Oxygen atom further recombines with Oxygen molecule to make Ozone molecule. This is known as Ozone-Oxygen cycle. The excess energy is released as heat.

Everyday around 400 million metric tons of Ozone is produced through this cycle.

Answer: these regions of darkness are due to no stars being in these regions of the night sky

Answer:

The speed of the mass M is 7.2 meters per second

Explanation:

In this case because there aren't external forces on the system blocks-spring and the spring is light we should apply the conservation of linear momentum (P) that states:

[tex]\overrightarrow{p}_{f}+\overrightarrow{p}_{i}=0 [/tex] (1)

Momentum is mass (m) times velocity (v) ([tex] \overrightarrow{p}=m\overrightarrow{v}[/tex] (2)) and Initial momentum [tex] \overrightarrow{p}_{i} [/tex] is zero because the blocks are released form rest, so (1) is:

Using (2) on (1):

[tex]\overrightarrow{p}_{f}=M\overrightarrow{v_{M}}+3M\overrightarrow{v_{3M}}=0 [/tex] (3)

It's important to note that momentum and velocity are vector quantities so we should take care of directions, assuming right direction as positive, velocity of 3M mass is positive, and velocity of M mass is negative, (3) is:

[tex]M(-v_{M})+3M(v_{3M})=0 [/tex]

solving for [tex]v_{M}[/tex]

[tex] M(v_{M})=3M(v_{3M})[/tex]

[tex] v_{M}=\frac{3M(v_{3M})}{M}=\frac{3(2.4)}{1}[/tex]

[tex]v_{M}=7.2\frac{m}{s} [/tex]

Answer:

Baja naja kanaka kanaka man's kana kana

Final answer:

The stress in a steel rod due to an axial force is calculated based on the weight of the rod above the cross-section in question. Stress is calculated using σ = P / A, where P is the force and A is the cross-sectional area. The stress differs depending on the height from the lower end due to varying weights above the point.

Explanation:

The question is discussing a scenario in which a cylindrical steel rod undergoes axial deformation due to an applied force. This deformation could be either tension (elongation) or compression (shortening). The rod is experiencing stress and strain as a reaction to this force. To solve for the magnitude of the force and the stress in the steel core, we use principles from mechanical engineering, specifically statics and material science.

To find the normal stress in the steel rod at different heights when the rod is fastened vertically, we need to calculate the weight of the portion of the rod above the point in question. This is because the weight causes a compressive stress in the steel rod. The stress (σ) at a given point can be calculated using the formula σ = P / A, where P is the force (weight) acting on the cross-section and A is the area of the cross-section.

(a) For the cross-section 1.0 m from the lower end, only half of the rod's weight is above this point, and thus contributing to the stress.
(b) For the cross-section 1.5 m from the lower end, the portion of the rod above this point is 0.5 m, so only the weight of this segment contributes to the stress.

Answer:

upper-left corner

Explanation:

Most vital information are positioned in a place where users can view them clearly and without obstruction.

Answer:

A water molecule can bond to up to four other water molecules by hydrogen bonds.

Explanation:

A water molecule has angular structure about the oxygen atom which has 2 lone pair of electrons in a water molecule. Due to the repulsion of lone pairs we get the angle between the H---O bond as 109.47°.

Each of the hydrogen atom of water attracts one water molecule and the partial negative on the oxygen atom attracts two more water molecules form the electron deficit side to form a pentamer of tetrahedral structure placing itself at the center of the geometry and the bonded molecules at the vertices.

A hydrogen bond is an intermolecular bond. A water molecule bonds up to 4 water molecules by the hydrogen bond.

Therefore, a water molecule bonds up to 4 water molecules by the hydrogen bond.

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Answer:

    t = 67.04 s

Explanation:

given,

time taken by Lace on the side walk = 2 min 47 s

                                                             = 167 s

time taken by the Lace while walking = 112 s.

now, time taken by the Lace when he is walking on the side walk = ?

Assume the distance be equal to 'd'

speed of Lace on side walk

we know, distance = speed x time

     [tex]v_{sidewalk}=\dfrac{d}{167}[/tex]

speed of the lace while walking

     [tex]v_{walking}=\dfrac{d}{112}[/tex]

time taken by Lace to cover the distance by walking on the side walk

  [tex]t = \dfrac{distance}{v_{sidewalk}+v_{walking}}[/tex]

   [tex]t = \dfrac{d}{\dfrac{d}{167}+\dfrac{d}{112}}[/tex]

   [tex]t = \dfrac{167\times 112}{167+112}[/tex]

        t = 67.04 s

time taken by the Lace walking on the side walk is equal to 67.04 s

Answer: The magnitude of the Electric Field at the centre of both plastic would be equal to Zero {i.e E =0}

Explanation: A plastic either full circle or half is an insulator, and the charges in an insulator cannot move around.

Therefore, thier electric potential p(r) = 0.

Recall that,

Electric field intensity E = first derivative of p(r) with respect to r ( radius).since p(r) = 0, E = 0 inside both plastic.

Final answer:

The electric field at the center of the half ring has a greater magnitude than that of the full ring because the full ring's symmetric charge distribution cancels the field out, while the half ring's electric field remains unopposed.

Explanation:

To determine which electric field at the center has the greater magnitude between a full ring and a half ring with the same radius and charge density, we must analyze the symmetrical distribution of charges. In the case of a full ring, the charges are evenly distributed around the ring, resulting in a net electric field at the center that cancels out due to symmetry. However, for a half ring, the symmetry is broken, and there is a net electric field at the center directed away from the flat side of the half ring, because there are no opposing charges to cancel the field out. Therefore, the electric field at the center of the half ring has a greater magnitude than that at the center of the full ring, which is effectively zero.

Answer:

is in the earths orbit

Explanation:

for Suzie to hover in space beside the rotating space station, she and the center  of mass of the space station are at relative rest which happens when space station is in Earth orbit, hence she is  in the earths orbit.

Answer:

The answer to your question is pH = 1.36

Explanation:

Data

Mass = 377 mg of KOH

Volume = 130 ml

pH = ?

pH = -log[H⁺¹]

Process

1.- Calculate the moles of KOH

molecular mass of KOH = 39 + 16 + 1 = 56 g

                          56 g of KOH --------------- 1 mol of KOH

                         0.377 g KOH  -------------  x

                                x = (0.377 x 1) / 56

                                x = 0.0057 moles

2.- Calculate the concentration

Molarity = number of moles / volume

Molarity = 0.0057 / 0.13

Molarity = 0.044

3.- Calculate the pH of the solution

pH = - log [0.044]

pH = 1.36

Answer:

Aristotle.

Explanation:

Aristotle is known as the father of rhetoric and it was actually his concept that the rhetoric is just the means of communications and persuade.

Answer:

[tex]F_s=1075.9493\ N[/tex]

Explanation:

Given:

Now, using Pascal's law which state that the pressure change in at any point in a confined continuum of an incompressible fluid is transmitted throughout the fluid at its each point.

[tex]P_s=P_l[/tex]

[tex]\frac{F_s}{a_s}=\frac{W_l}{a_l}[/tex]

[tex]\frac{F_s}{0.075} =\frac{3400}{0.237}[/tex]

[tex]F_s=1075.9493\ N[/tex] is the required effort force.

Answer:

   F = 1076 N

Explanation:

given,

small piston area, a = 0.075 m²

large piston area, A = 0.237 m²

weight on the large piston, W = 3400 N

force applied on the second piston, F = ?

using pascal law for the force calculation

[tex]\dfrac{F}{W}=\dfrac{a}{A}[/tex]

[tex]\dfrac{F}{3400}=\dfrac{0.075}{0.237}[/tex]

   F = 0.3165 x 3400

   F = 1076 N

The force applied to the small piston in order to lift the engine is equal to 1076 N.

Answer:

[tex]V_{x}[/tex] = 12.99 , [tex]V_{y}[/tex] = -7.5

Explanation:

v=15units , θ=330°

the magnitude of the horizontal and vertical components are gotten by the formula below

[tex]V_{x}[/tex] = Vcosθ

[tex]V_{y}[/tex] = Vsinθ

[tex]V_{x}[/tex] = 15*cos330

[tex]V_{x}[/tex] = 12.99 (positive implies to the right)

[tex]V_{y}[/tex] =15*sin330

[tex]V_{y}[/tex] = -7.5 (negative implies downwards)

Answer:

22826.09 m/s

Explanation:

From the law of conservation of momentum,

Sum of momentum before collision = sum of momentum after collision.

For an inelastic collision, the train and the superman have a common velocity

Note: For the superman to stop the train in an opposite direction, the common velocity after collision is zero, and such the total momentum after collision is zero

Therefore,

MU + mv = 0

MU = - mu............................................ Equation 1

Making u the subject of the equation

u = -MU/m......................................... Equation 2

Where M = mass of the train, U = initial velocity of the train, m = mass of the super man, u = initial velocity of the superman.

Given: M = 75000 kg, U = 35 m/s, m = 115 kg.

u = -(75000×35/115)

u = -22826.09 m/s

Note: The velocity is negative because the direction of the superman is opposite the direction of the train.

Hence the superman have to fly 22826.09 m/s in the opposite direction

Using the principle of conservation of momentum, Superman needs to fly approximately at a velocity of 22826 m/s in the opposite direction  to stop the train.

To stop the train, Superman needs to exert a force equal to the force being exerted by the train in the opposite direction. Using Newton's second law (F=ma), we can calculate the force needed to stop the train. The force needed can be found by multiplying the mass of the train by its acceleration, which is the change in velocity divided by the time taken to stop. In this case, the initial velocity of the train is given as 35 m/s and it needs to come to a stop, so the change in velocity is 35 m/s.

The question is asking how fast Superman must fly in the opposite direction to stop a moving train using the physics principle of conservation of momentum. In Physics, momentum is calculated using the equation momentum = mass * velocity. Since the train and Superman will collide and stop (an inelastic collision) total momentum before the collision should equal total momentum after the collision. Thus, the velocity of Superman equals (mass of train * velocity of train)/ mass of Superman, i.e., (75000 kg * 35 m/s) / 115 kg which is approximately 22826 m/s in the opposite direction.

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Answer:

X is calcium and it has 21 neutrons

Explanation:

Calcium 41 is an isotope of calcium with mass number of 41 and atomic number of 20

Number of neutrons = mass number - number of electrons

The number of electrons is the same as the atomic number of the element (calcium)

Number of neutrons = 41 - 20 = 21

The seagull dropped the clam from an approximate height of 44.1 meters above the ground. This was calculated using the physics formula for the height of a dropped object, considering the acceleration due to gravity.

The subject of the question falls under Physics and it's related to the concept of gravitational acceleration. To calculate the height from which the seagull dropped the clam, we can use the physics formula for the height of a dropped object which is h = 0.5 * g * t^2.

Here, 'g' represents the acceleration due to gravity and has an approximate value of 9.8 m/s2, and 't' represents the time in seconds which is given as 3.0 seconds. So, inserting these values into the equation, we getThe seagull dropped the clam from an approximate height of 44.1 meters above the ground. This was calculated using the physics formula for the height of a dropped object, considering the acceleration due to gravity.

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Answer:

1315789.47368 lines/m

Explanation:

m = Order = 1

[tex]sin\theta[/tex] = 1 For maximum condition

[tex]\lambda[/tex] = Wavelength = 760 nm maximum

From Rayleigh criteria we have the expression for the gap

[tex]d=\dfrac{m\lambda}{sin\theta}\\\Rightarrow d=\dfrac{1\times 760}{1}\\\Rightarrow d=760\ nm[/tex]

The number of lines is the reciprocal of the slit distance

[tex]n=\dfrac{1}{d}\\\Rightarrow n=\dfrac{1}{760\times 10^{-9}}\\\Rightarrow n=1315789.47368\ /m[/tex]

The number of lines is 1315789.47368 per meter

Answer:

[tex]N_{y} =Ncos[/tex]Ф,

[tex]N_{x} =-Nsin[/tex] Ф

Explanation:

Now find the components NxNxN_x and NyNyN_y of N⃗ N→N_vec in the tilted coordinate system of Part B. Express your answer in terms of the length of the vector NNN and the angle θθtheta, with the components separated by a comma.

Vectors are quantities that  have both magnitude and direction while scalar quantities have only magnitude but no direction.

This a vector quantity

from the diagram the horizontal component of the length of the vector will be

[tex]N_{y} =Ncos[/tex]Ф

the vertical component will be

[tex]N_{x} =-Nsin[/tex] Ф

this is in the opposite direction because the x can be extrapolated to the negative axis

To solve the problem we must know about vectors and coordinate geometry.

We know that the vector quantities are those quantities that have magnitude as well as direction.

Each vector quantity can be divided into two parts a horizontal and vertical component, the vertical component is known as the sine component while the horizontal component is known as the cosine component.

A vector component is represented as the product of its length and the component angle.

For example, F Sinθ represents the vertical component of force, with magnitude F, while the F Cosθ represents the horizontal component, and will be in the same line with the axis from which the angle is been measured.

The coordinate in the tilted coordinate will be,

[tex]N_x = N Sin\theta[/tex]

[tex]N_y = N Cos\theta[/tex]

Where N is the vector magnitude and θ is the angle from the axis of measurement.

The sign of the vector will depend upon the coordinate in which it is.

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Answer:

The Piccolo have higher frequency than Flute.

Explanation:

given,

length of the tube, L = 66 cm

length of the piccolo, L'= 32 cm

speed of sound = 343 m/s

A flute is open open tube with a fundamental frequency of ;

[tex]f = \dfrac{v}{2L}[/tex]

[tex]f = \dfrac{343}{2\times 0.66}[/tex]

  f = 260 Hz

A piccolo is also an open open tube so, fundamental frequency is:

[tex]f = \dfrac{v}{2L}[/tex]

[tex]f = \dfrac{343}{2\times 0.32}[/tex]

  f = 536 Hz

from the above calculation we can clearly see that the  piccolo have much higher frequency than the flute.

now, The Piccolo have higher frequency than Flute.

Answer:

ρ_ x > ρ_ y

Explanation:

The pressure in a fluid depends on its depth with the equation

          P = ρ g h

For two points at the same depth there may be several possibilities,

- the pressure is the same if the density of the fluid is equal in the two points

- The pressure is different if the fluid density is different at each point

In this case, as the point x has greater pressure than the point, the density of the fluid in Des is greater than the density of the fluid in Y

        ρ_ x > ρ_ y

Answer:

D. 2

Explanation:

The innermost electron shell of an atom can hold up to 2 electrons.

All the elements in the periodic table have only two electrons in their inner most shell. The only exception is hydrogen because it has only one electron.