Answer:
constant deceleration required is 9 m/s²
Explanation:
Data provided in the question:
Initial Speed of the driver = 41 mph = 60 ft/s
Stopping distance = 200 ft
Now,
Since the car stops after 200 ft therefore final speed, u = 0 ft/s
from the Newton's equation of motion
we have
v² - u² = 2as
where,
v is the final speed
u is the initial speed
a is the acceleration
s is the distance
thus,
0² - 60² = 2a(200)
or
-3600 = 400a
or
a = - 9 m/s²
here, negative sign means deceleration
Hence,
The constant deceleration required is 9 m/s²
The ocular lenses of our microscopes in lab provide 10X magnification. If you are viewing cells with the 40X objective lens what would the total magnification be?
Answer:
400X
Explanation:
Total magnification = power of eyepiece (ocular) × power of the objective lenses
= 10X × 40X = 400X
Why is thermal energy from the Sun transferred to Earth through electromagnetic waves instead of any other type of thermal energy transfer?
Answer:
Because electromagnetic waves can travel through empty space
Explanation:
The energy that is emitted from the sun is transferred to the earth in the form of radioactive waves. These waves are originated due to the vibration between the electric and magnetic fields. As this energy reaches the earth, it warms the earth's atmosphere, resulting in the transfer of heat energy in three possible ways namely the conduction, convection, and radiation.
This electromagnetic waves do not require any matter for the transmission of energy, and can easily travel in empty space from the core of the sun to the earth and other nearby planets. Whereas other types of waves cannot travel in space, so it is transferred in the form of electromagnetic waves only.
Answer:
The electromagnetic waves can pass through empty space.
Explanation:
The rms (root-mean-square) speed of a diatomic hydrogen molecule at 50∘C is 2000 m/s. Note that 1.0 mol of diatomic hydrogen at 50∘C has a total translational kinetic energy of 4000 J.A) Diatomic oxygen has a molar mass 16 times that of diatomic hydrogen. The root-mean-square speed vrms for diatomic oxygen at 50∘C is:________a) (16)(2000m/s)=32000m/sb) (4)(2000m/s)=8000m/sc) 2000m/sd) (14)(2000m/s)=500m/se) (116)(2000m/s)=125m/sf) none of the aboveB) The total translational kinetic energy of 1.0 mole of diatomic oxygen at 50∘C is:________a) (16)(4000J)=64000Jb) (4)(4000J)=16000Jc) 4000Jd) (14)(4000J)=1000Je) (116)(4000J)=150Jf) none of the aboveC) The temperature of the diatomic hydrogen gas sample is increased to 100∘C. The root-mean-square speed vrms for diatomic hydrogen at 100∘C is:______a) (2)(2000m/s)=4000m/sb) (2√)(2000m/s)=2800m/sc) 2000m/sd) (12√)(2000m/s)=1400m/se) (12)(2000m/s)=1000m/sf) none of the above
Answer:
A) d. (1/4)(2000m/s) = 500 m/s
B) c. 4000 J
C) f. None of the above (2149.24 m/s)
Explanation:
A)
The translational kinetic energy of a gas molecule is given as:
K.E = (3/2)KT
where,
K = Boltzman's Constant = 1.38 x 1^-23 J/K
T = Absolute Temperature
but,
K.E = (1/2) mv²
where,
v = root mean square velocity
m = mass of one mole of a gas
Comparing both equations:
(3/2)KT = (1/2) mv²
v = √(3KT)/m _____ eqn (1)
FOR HYDROGEN:
v = √(3KT)/m = 2000 m/s _____ eqn (2)
FOR OXYGEN:
velocity of oxygen = √(3KT)/(mass of oxygen)
Here,
mass of 1 mole of oxygen = 16 m
velocity of oxygen = √(3KT)/(16 m)
velocity of oxygen = (1/4) √(3KT)/m
using eqn (2)
velocity of oxygen = (1/4)(2000 m/s) = 500 m/s
B)
K.E = (3/2)KT
Since, the temperature is constant for both gases and K is also a constant. Therefore, the K.E of both the gases will remain same.
K.E of Oxygen = K.E of Hydrogen
K.E of Oxygen = 4000 J
C)
using eqn (2)
At, T = 50°C = 323 k
v = √(3KT)/m = 2000 m/s
m = 3(1.38^-23 J/k)(323 k)/(2000 m/s)²
m = 3.343 x 10^-27 kg
So, now for this value of m and T = 100°C = 373 k
v = √(3)(1.38^-23 J/k)(373 k)/(3.343 x 10^-27 kg)
v = 2149.24 m/s
The rms speed will be "500 m/s". A further solution is provided below.
Given:
Speed of a diatomic hydrogen molecule,
2000 m/sMol of diatomic hydrogen,
1.0Temperature,
50°CNow,
The rms speed of diatomic molecule will be:
→ [tex]V_{rms} = \sqrt{\frac{5kT}{m} }[/tex]
or,
→ [tex](V_{rms})O_2 = \sqrt{\frac{5kT}{16(m)} }[/tex]
[tex]= \frac{1}{4} (V_{rms})H_2[/tex]
[tex]= \frac{1}{2} (2000)[/tex]
[tex]= 500 \ m/s[/tex]
Thus the above response is right.
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Which statement is correct about the relationship between the average speed and the magnitude of the average velocity for any motion?
Answer: They both posses magnitude, have the same unit and are covered in a specific time interval
Explanation:
One of the relationship between average speed and the magnitude of the average velocity for any motion is that the motion are covered in a specific time interval. They both specifies magnitude and are measured using the same unit which is meter per second.
One of their major difference is that average speed only deals with distance covered in a specific time interval (it doesn't specify direction) while velocity is distance covered in a "specified direction" within a time frame.
The relationship between average speed and the magnitude of average velocity is that the average speed can be greater than the magnitude of average velocity. This is particularly the case when the direction of motion changes. Both are the same when the motion is in a constant direction.
The correct statement about the relationship between average speed and the magnitude of average velocity is: Average speed can be greater than the magnitude of average velocity. To understand this, let's consider an example: if you complete a round trip starting and ending at the same location, the total displacement (change in position) will be zero, leading to an average velocity of zero. However, the average speed won't be zero, as the total distance covered isn't zero.
Another important point is that average speed and the magnitude of average velocity are the same only when the direction of motion is constant. Changing direction increases the path covered (distance), which impacts the average speed, but not the displacement, thus not affecting the average velocity.
So, while both 'speed' and 'velocity' measure how fast an object moves, 'velocity' is a vector that includes a direction, and 'speed' is a scalar without direction. Because of the direction component of velocity, the magnitude of average velocity can be less than the average speed.
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A piston/cylinder contains 2 kg of water at 20◦C with a volume of 0.1 m3. By mistake someone locks the piston, preventing it from moving while we heat the water to saturated vapor. Find the final temperature and volume and the process work?
Answer:
Hi
Final temperature = 250.11 °C
Final volume = 0,1 m3.
Process work = 0
Explanation:
The specific volume in the initial state is: v = 0.1m3/2 kg = 0.05 m3/kg.
This volume is located between the volumes as saturated liquid and saturated steam at 20 °C. For this reason the water is initially in a liquid vapor mixture. As the piston was blocked the volume remains constant and the process is isometric, also known as isocoric process, so the final temperature will be the water temperature at a saturated steam of v=0.05m3/kg, which is obtained by using steam tables for water, by linear interpolation. As follows, using table A-4 of the Cengel book 7th Edition:
v=0.05 m3/kg
v1=0.057061 m3/kg
T1=242.56°C
v2=0.049779 m3/kg
T2=250.35°C
T=[tex]\frac{T2-T1}{v2-v1} x(v-v1)+T1=\frac{250.35°C-242.56°C}{0.049779m3/kg-0.057061m3/kg}x(0.05m3/kg-0.057061m3/kg)+242.56°C=250.11°C[/tex]
The process work is zero because there is no change in volume during heating:
W=PxΔv=Px0=0
where
W=process work
P=pressure
Δv=change of volume, is zero because the piston was blocked so the volume remains constant.
Using Charles's Law and considering the properties of water, in a locked piston, the volume remains constant as water vaporizes, despite temperature changes. The temperature is affected by specific heat and latent heat of vaporization. No work is done as the locked piston prevents expansion.
Explanation:In this scenario, we would need to use principles from physics to solve this problem, particularly the laws of thermodynamics and the properties of gases and liquids, specifically water. Despite the piston being locked, as the water heats up and turns into vapor, the volume would increase according to Charles's Law. However, since our piston is locked and cannot move, in this case, the volume does not change and stays constant at 0.1 m³.
Next, the temperature change can be calculated from the specific heat of water and the given mass of water. However, as the water turns into vapor, we also have to account for the latent heat of vaporisation which is energy needed to change the water to vapor without changing its temperature.
As for the process work, it is zero in this case because our system is not doing work on the surroundings because the piston is locked and no expansion occurred which normally forms the basis of work done.
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If a photon has frequency = 2.00 x 1014s-1 and the speed of light = 3.00 x 108ms-1, then what is its wavelength?
Answer:
The photon has a wavelength of [tex]1.5x10^{-6}m[/tex]
Explanation:
The speed of a wave can be defined as:
[tex]v = \nu \cdot \lambda[/tex] (1)
Where v is the speed, [tex]\nu[/tex] is the frequency and [tex]\lambda[/tex] is the wavelength.
Equation 1 can be expressed in the following way for the case of an electromagnetic wave:
[tex]c = \nu \cdot \lambda[/tex] (2)
Where c is the speed of light.
Therefore, [tex]\lamba[/tex][tex]\lambda[/tex] can be isolated from equation 2 to get the wavelength of the photon.
[tex]\lambda = \frac{c}{\nu}[/tex] (3)
[tex]\lambda = \frac{3.00x10^{8}m/s}{2.00x10^{14}s^{-1}}[/tex]
[tex]\lambda = 1.5x10^{-6}m[/tex]
Hence, the photon has a wavelength of [tex]1.5x10^{-6}m[/tex]
Summary:
Photons are the particles that constitutes light.
What is the speed of a car going v=1.000 mph in SI units? Notice that you will need to change miles to meters and from hours to seconds. you can do each conversion separately. Use the facts that 1 mile=1609 m and 1 hour= 3600s
Answer: The speed is 0.4694 m/s.
Explanation:
S.I or M.K.S system has seven fundamental units which are used to find derived units
1) Mass - Kilogram
2) Length - meter
3) Time - Seconds
4) Electric Current - Ampere
5) Amount of substance - Moles
6) Intensity of light - Candela
7) Temperature - Kelvin
The conversion used from miles to feet is:
1 mile = 1609 m
1.000 miles= [tex]\frac{1690}{1}\times 1.000=1690m[/tex]
The conversion used from hour to sec is:
1 hr = 3600 sec
We are asked: 1.000 miles/hr = ? m/s
[tex]1.000miles/hr=\frac{1690}{3600}m/sec=0.4694m/sec[/tex]
Therefore, the speed in SI unit is 0.4694
A refrigerator has a power of 90 w and is left on for 24 hours. A hair dryer has a power of 900 w an is on for 20 minutes. Which statement correctly compares the energy used by these devices
The refrigerator has consumed more energy
Explanation:
The relationship between power and energy consumed by a device is given by
[tex]E=Pt[/tex]
where
E is the energy
P is the power
t is the time elapsed
For the refrigerator, we have
P = 90 W
[tex]t = 24 h \cdot 3600 = 86400 s[/tex]
Therefore the energy consumed is
[tex]E=(90)(86400)=7.78\cdot 10^6 J[/tex]
For the hair dryer, we have
P = 900 W
[tex]t = 20 min \cdot 60 = 1200 s[/tex]
Therefore the energy consumed is
[tex]E=(900)(1200)=1.08\cdot 10^6 J[/tex]
Therefore, the refrigerator has consumed more energy.
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Emily is a competitive swimmer. Why does wearing a swim cap help Emily swim faster?
A. The cap reduces her inertia.
B. The cap keeps the hair out of her eyes.
C. The cap increases the friction between her and the water.
D. The cap decreases the friction between her and the water.
pls help thanku
Answer:
It's helps Emily became when she swims her hair is not in the way creating friction and making her swim faster. friction acts between two metals blocks that slide past each other.
Explanation:
Answer:
I had this same question on a Science test and I chose D) and got it right.
Explanation:
The standard used by LEED in the Water Efficiency (WE) category to determine the baseline case for building water usage is the national standard for maximum flush and flow rates called:
Answer:
EPAct of 1992.
Explanation:
The Energy Policy Act (EPAct) is a United States Of America government act passed in the year 1992 and became effective in October 24, 1992.
The Energy Policy Act was established to address the energy needs in the United States of America by amending laws to increase and provide incentives for clean and renewable energy and also to decrease the dependence on imported energy.
A catapult launches a boulder with an upward velocity of 92 m/s. The height of the boulder, h, in meters after t seconds is given by the function h = –5t2+ 92t + 16. How long does it take to reach maximum height? What is the boulder’s maximum height? Round to the nearest hundredth, if necessary. A. Reaches a maximum height of 16.00 meters in 18.4 seconds. B. Reaches a maximum height of 18.57 meters in 9.2 seconds. C. Reaches a maximum height of 37.14 meters in 18.4 seconds. D. Reaches a maximum height of 439.20 meters in 9.2 seconds.
Answer:
D. Reaches a maximum height of 439.20 meters in 9.2 seconds.
Explanation:
Given
h = –5t²+ 92t + 16
then
h' = 0 when the boulder reaches its maximum height
(–5t²+ 92t + 16)' = - 10t + 92 = 0
⇒ t = 92/10
⇒ t = 9.2 s
the maximum height will be
h = –5(9.2)²+ 92(9.2) + 16
h = 439.20 m
A solid metal ball and a hollow plastic ball of the same external radius are released from rest in a large vacuum chamber. When each has fallen 1 m, they both have the same?
Answer:
time of fall and the final velocity
Explanation:
the mass of solid ball is more than the mass of hollow ball.
According to the third equation of motion
v² = u² + 2gh
As the final velocity v does not depend on the mass of the object, so the final velocity of both the ball is same.
According to the first equation of motion
v = u + gt
As v is same for both the balls, the time is also same for both the balls.
So, they both have same time of fall and final velocity.
Because of the Coriolis effect, surface ocean currents are deflected to the ________ of their path of motion in the Northern Hemisphere.
Answer:
Right
Explanation:
Because of the Coriolis effect, surface ocean currents are deflected to the Right of their path of motion in the Northern Hemisphere.
Since the Earth is revolving on its axis, flowing air in the Northern Hemisphere are deflected to the right and in the Southern Hemisphere to the left. The consequence of Coriolis is called this deflection.
A projectile is launched at a diagonal angle and is in the air for 17.5 seconds. How long does it take the projectile to reach its apex?
Answer:
[tex]t_h=8.75\ s[/tex]
Explanation:
For a projectile the total time it stays in the air is called the flight time. The path traced during a projectile motion is parabolic with symmetry of time and distance.
Given that the projectile having a flight time of 17.5 seconds, will reach the top point in half of the flight time taken by it:
So, [tex]t_h=\frac{T}{2}[/tex]
[tex]t_h=\frac{17.5}{2}[/tex]
[tex]t_h=8.75\ s[/tex] is the time by the end of which the projectile will be at its apex having the vertical component of velocity as zero.
Do note that during a projectile analysis we neglect the air resistance due to which we have a constant horizontal component of the velocity and the vertical component of the velocity varies under the influence of gravity. The vertical velocity at the top becomes zero.
A manufacturer provides a warranty against failure of a carbon steel product within the first 30 days after sale. Out of 1000 sold, 10 were found to have failed by corrosion during the warranty period. Total cost of replacement for each failed product is approximately $100,000, including the cost of environ-mental clean-up, loss of product, downtime, repair, and replacement.(A) Calculate the risk of failure by corrosion, in dollars.(B) If a corrosion-resistant alloy would prevent failure by corrosion, is an incremental cost of $100 to manufacture the product using such an alloy justified? What would be the maximum incremental cost that would be justified in using an alloy that would prevent failures by corrosion?
Answer:A) Risk(R)= $1000
B) There is justification for spending an additional cost of $100 to prevent a corrosion whose consequence in monetary terms is $1000
Explanation:R= Risk,
P=Probability of failure
C= Consequence of failure
Mathematically, R=P ×C
10 out of 1000 carbon-steal products failed
Probability of failure= 10/1000 =0.01
The consequence of failure by corrosion given in monetary term =$100,000
Risk of failure = 0.01 × $100,000
R=$1000
Find the voltage change when (a) an electric field does 12 J of work on a 0.0001-C charge and (b) the same electric field does 24 J of work on a 0.0002-C charge.
Answer:
a. [tex]Change in Voltage=12*10^{4}V[/tex]
b. [tex]Change in Voltage=12*10^{4}V[/tex]
Explanation:
The work done in moving an electric charge round a circuit is express as
[tex]workdone=voltage*charge \\Wd=v*q[/tex]
The voltage is in-turn define as the electric potential energy per unit charge.
[tex]Voltage=\frac{potitntial energy }{charge}\\[/tex]
a. for a 12J work done on a charge of value 0.0001C, we can compute the voltage change as
[tex]Voltage=\frac{potitntial energy }{charge}\\Voltage=\frac{12J}{0.0001C}\\ Voltage=12,0000J/C\\ Change in Voltage=12*10^{4}V[/tex]
a. for a 24J work done on a charge of value 0.0002C, we can compute the voltage change as
[tex]Voltage=\frac{potitntial energy }{charge}\\Voltage=\frac{24J}{0.0002C}\\ Voltage=12,0000J/C\\Change in Voltage=12*10^{4}V[/tex]
The voltage change in (a) is 1.2 × 10⁵ J/C and in (b) is 1.2 × 10⁵ J/C.
a) Based on the given information,
• Work done (W) is 12 J and charge (q) is 0.0001 C.
The change in voltage is determined by using the formula,
= W/q
Now putting the values we get,
= [tex]\frac{12}{0.0001} J/C[/tex] or 1.2 × 10⁵J/C
b) Based on the given information,
• Work done (W) is 24J and charge (q) is 0.0002 C.
The change in voltage can be calculated as,
= W/q
Putting the values we get,
=[tex]\frac{24}{0.0002} J/C[/tex] or 1.2 × 10⁵J/C
Thus, the voltage change in both the conditions is 1.2 × 10⁵J/C.
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An electric field of 280000 N/C points due west at a certain spot. What is the magnitude of the force that acts on a charge of -7.9C at this spot?
Explanation:
Electric field is the ratio of force and charge.
Electric field, E = 280000 N/C
Charge, q = -7.9 C
We have
[tex]E=\frac{F}{q}\\\\280000=\frac{F}{7.9}\\\\F=280000\times 7.9\\\\F=2.21\times 10^6N[/tex]
The magnitude of the force that acts on a charge of -7.9C at this spot is 2.21 x 10⁶ N.
Final answer:
The magnitude of the force that acts on a -7.9 C charge in a 280000 N/C electric field is 2212000 N, acting in the opposite direction of the electric field.
Explanation:
The question asks about the magnitude of the force that acts on a charge in the presence of an electric field. This can be solved by using the equation F = qE, where F is the force in Newtons, q is the charge in Coulombs, and E is the electric field strength in Newtons per Coulomb (N/C).
Given that the electric field (E) is 280000 N/C and points due west, and the charge (q) is -7.9 C, we can calculate the force as follows:
F = qE = (-7.9 C) × (280000 N/C) = -2212000 N.
This result indicates the magnitude of the force is 2212000 N, and by convention, the negative sign indicates that the force direction is opposite to the direction of the electric field; since the electric field points west, the force on the negative charge points east.
Quaternary structure is achieved when a protein folds into a compact, three-dimensional shape stabilized by interactions between side-chain R groups of amino acids.True or False.
Answer:
False: Quaternary structure is achieved when multiple polypeptide chains in protein come together.
Explanation:
There are four levels of protein structure: primary, secondary, tertiary, and Quaternary structure.
Tertiary structure is a protein structure, which is achieved when a protein folds into a compact, three-dimensional shape stabilized by interactions between side-chain R groups of amino acids.
However, Quaternary structure is achieved when multiple polypeptide chains in protein come together.
A large raindrop-the type that lands with a definite splat-has a mass of 0.0014 g and hits your roof at a speed of 8.1 m/s. a. What is the magnitude of the impulse delivered to your roof? b. If the raindrop comes to rest in 0.37 ms, what is the magnitude of the force of the impact?
The magnitude of the impulse delivered to the roof is -0.01134 kg·m/s, and the magnitude of the force of the impact is -30.70 N.
Explanation:The magnitude of impulse delivered to your roof can be calculated using the equation impulse = mass x change in velocity. In this case, the mass of the raindrop is given as 0.0014 g, which is equivalent to 0.0014 kg. The change in velocity is the final velocity (0 m/s) minus the initial velocity (8.1 m/s). Therefore, the magnitude of the impulse is 0.0014 kg x (-8.1 m/s) = -0.01134 kg·m/s.
To calculate the magnitude of the force of the impact, we can use the equation force = impulse/time. In this case, the impulse is the magnitude of the impulse calculated previously (-0.01134 kg·m/s) and the time is given as 0.37 ms, which is equivalent to 0.00037 s. Therefore, the magnitude of the force of the impact is -0.01134 kg·m/s / 0.00037 s = -30.70 N.
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In this physics problem, we calculate both the magnitude of the impulse delivered and the force of impact of a raindrop hitting a roof.
The magnitude of the impulse delivered to the roof can be calculated by multiplying the mass of the raindrop by its velocity.
The magnitude of the force of the impact can be determined using the formula for impulse, considering the time it takes for the raindrop to come to rest.
An observer sees a flower pot sail up and then back down past a window 2.45 m high. If the total time the pot is in the sight is 1 s, what is the height above the window up to which the pot rises?
Answer: 2.55meter
Explanation: Using the second equation of motion.
S{hieght} = U*t + {g*t²}/2
Where U is initial velocity =0m/s
g is acceleration due to gravity 10m/s²
t is time 1secs
So we have,
hieght = 0 + {g*t²}/2
hieght = {10*(1)²}/2
Total hieght travelled is 10/2
Which is 5 meter.
But we are asked to find the hieght above the window which as a hieght of 2.45meter.
So,
hieght above window would be
{5 - 2.45}meter
Which is 2.55 meter.
Match the characteristic or descriptive phrase to the type of application it describes.
Part A
a. sound waves
b. soft-tissue imaging
c. electromagnetic wave
d. fetal imaging
Part B
1. ultra sound
2. mri
Answer:
Sound waves and fetal imaging is related to the ultrasound.
Electromagnetic wave and soft tissue imaging is related to the MRI.
Explanation:
Ultrasound scans is basically a process in which high frequency sound waves are used for the fetal imaging or examining the internal organs like liver, kidneys etc. It's the safe procedure as no radiations are involved in this case.
However the MRI stands for Magnetic resonance imaging that use the electromagnetic waves and is best for the soft tissue imaging etc.
Sound waves and electromagnetic waves are key to ultrasound and MRI imaging. Ultrasound uses sound waves for applications like fetal imaging, while MRI uses electromagnetic waves for soft-tissue imaging.
Explanation:To match the characteristic or descriptive phrase to the type of application it describes:
a. sound waves - 1. ultrasoundb. soft-tissue imaging - 2. MRIc. electromagnetic wave - 2. MRId. fetal imaging - 1. ultrasoundUltrasound is a medical imaging technique that uses high-frequency sound waves to create images of the inside of the body. It is particularly useful for fetal imaging during pregnancy as it is non-invasive and safe for both the mother and fetus. On the other hand, Magnetic Resonance Imaging (MRI) uses electromagnetic waves in the radio-frequency range to create detailed images of the body's soft tissues, making it invaluable for detecting conditions within the body's interior.
What is the ratio of the electrical force to the gravitational force between an electron and a positron?
Answer:
Explanation:
mass of electron = 1.9 ×[tex]10^{-31} kg[/tex]
mass of proton = 1.67 ×[tex]10^{-27}[/tex][tex]kg[/tex]
Gravitational Force = [tex]F_{g}[/tex] = [tex]\frac{Gm_{p}m_{e} }{r^{2} }[/tex] = [tex]\frac{6.67 * 9.1* 1.67*10^{-69} }{r^{2} }[/tex]
Electrostatic Force = [tex]F_{E}[/tex] = [tex]\frac{1}{4\pi epsilon} \frac{e^{2} }{r^{2} }[/tex] = [tex]\frac{9*10^{9}* 1.6*1.6* }{r^{2} }[/tex]×[tex]10^{-38}[/tex]
[tex]\frac{F_{g} }{F_{E} }[/tex] = [tex]4.47[/tex]×[tex]10^{-40}[/tex]
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz. Find the possible range of wavelengths in air produced by the instrument when the speed of sound in air is 343 m/s.
Answer:
The possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
Explanation:
Given that,
The notes produced by a tuba range in frequency from approximately 45 Hz to 375 Hz.
The speed of sound in air is 343 m/s.
To find,
The wavelength range for the corresponding frequency.
Solution,
The speed of sound is given by the following relation as :
[tex]v=f_1\lambda_1[/tex]
Wavelength for f = 45 Hz is,
[tex]\lambda_1=\dfrac{v}{f_1}[/tex]
[tex]\lambda_1=\dfrac{343}{45}=7.62\ m[/tex]
Wavelength for f = 375 Hz is,
[tex]\lambda_2=\dfrac{v}{f_2}[/tex]
[tex]\lambda_2=\dfrac{343}{375}=0.914\ m/s[/tex]
So, the possible range of wavelengths in air produced by the instrument is 7.62 m and 0.914 m respectively.
A 0.145-kg baseball pitched horizontally at 27.0 m/s strikes a bat and pops straight up to a height of 31.5 m. If the contact time between bat and ball is 2.5 ms, calculate the average force between the ball and bat during contact.
The average force between the ball and the bat during the contact is 1,566 N.
The given parameters;
mass of the ball, m = 0.145 kghorizontal velocity of the ball, u = 27 m/sheight of the ball's displacement, h = 31.5 mthe contact time of the ball, t = 2.5 msThe average force between the ball and the bat during the contact is determined by applying Newton's second law of motion.
F = ma
where;
a is the acceleration of the ballm is the mass of the ballThe average force is calculated as follows;
[tex]F = ma = m\frac{v}{t} \\\\F = \frac{mv}{t} \\\\F = \frac{0.145 \times 27}{2.5 \times 10^{-3}} \\\\F = 1,566 \ N[/tex]
Thus, the average force between the ball and the bat during the contact is 1,566 N.
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To calculate the average force between the ball and bat during contact, you first calculate the speed the ball leaves the bat using the gravitational potential energy formula. Find the change in velocity, then use the formula for force using this change in velocity and the given time.
Explanation:The subject of this question is physics, specifically involving the concepts of force, mass, speed, and time. This problem first requires using the equation for gravitational potential energy to find the speed at which the ball leaves the bat. That is Potential energy = mgh, where m is the mass, g is the acceleration due to gravity, and h is the height. This will give you the final speed of the baseball after the contact with the bat.
Next, find the change in velocity (or 'delta v') by subtracting the initial speed of the baseball from its final speed. The average force can then be calculated using Newton's second law transformed in impulse form: Force = delta p / delta t = m * delta v / delta t, where delta p is the change in momentum, delta v is the change in speed, and delta t is the change in time.
This calculation should provide the answer to your question, and requires understanding of physics concepts such as gravitational potential energy, impulse, and force.
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The speed of a nerve impulse in the human body is about 100 m/s. If you accidentally stub your toe in the dark, estimate the time it takes the nerve impulse to travel to your brain.
problem is worked out down below in an attachment
Final answer:
It takes approximately 0.015 seconds for a nerve impulse from a stubbed toe to reach the brain, calculated based on the speed of the nerve impulse (100 m/s) and the estimated distance (1.5 meters).
Explanation:
To calculate the time it takes for a nerve impulse to travel from a stubbed toe to the brain, we need to consider the speed of the nerve impulse and the distance it must travel. The speed of a nerve impulse is about 100 m/s. Assuming an average distance from the toe to the brain via the spinal cord is approximately 1.5 meters (taking into account the height of an individual and that nerve paths are not completely straight), we can use the formula:
Time = Distance / Speed
Plugging in the values gives us:
Time = 1.5 m / 100 m/s = 0.015 seconds.
So, it takes approximately 0.015 seconds for a nerve impulse from a stubbed toe to reach the brain. This rapid transmission allows the body to respond quickly to stimuli, protecting it from further injury.
Check all statements that are true about nuclear radiation.
Group of answer choices
Beta radiation can be stopped by thick wood or a sheet of aluminum.
The order of radioactive particles from most to least penetrating ability is gamma, beta, alpha.
electrons are beta radiation
Gamma radiation can be stopped by clothing,
Alpha radiation is a helium nucleus.
Alpha radiation is easily stopped by paper or clothing.
Gamma radiation is an electron.
Stable and non-stable nuclei can give off radiation.
Alpha radiation is a high energy electromagnetic wave.
Answer:
Alpha radiation is a helium nucleus
Electrons are beta radiation
The order of radioactive particles from most to least penetrating ability is gamma, beta, alpha
Alpha radiations is easily stopped by paper or clothing
Explanation:
Answers:
Alpha radiation is a helium nucleus.
Electrons are beta radiation
Alpha radiation is easily stopped by paper or clothing.
The order of radioactive particles from most to least penetrating ability is gamma, beta, alpha.
Beta radiation can be stopped by thick wood or a sheet of aluminum.
Explanation:
1. only unstable nuclei give off radiation. In an unstable atom, the nucleus changes by giving off a neutron to get back to a balanced state. As the unstable nucleus changes, it gives off radiation and is said to be radioactive.
2. Gamma Rays can easily penetrate barriers that can stop alpha and beta particles, such as skin and clothing. several inches of a dense material like lead, or even a few feet of concrete may be required to stop them.
3. Alpha radiation is a helium nucleus.
4. A beta particle, also called beta ray or beta radiation (symbol β), is a high-energy, high-speed electron or positron
5. Gamma rays are a high-energy form of electromagnetic radiation.
6. Alpha radiation is easily stopped by paper or clothing.
7. Alpha denotes the largest particle, and it penetrates the least. Alpha particles carry a positive charge, beta particles carry a negative charge, and gamma rays are neutral.
8. Gamma radiation is a rigid electromagnetic radiation at the short-wave edge of the electromagnetic wave spectrum.
9. Beta particles can travel a few metres through the air and can be stopped by a thin sheet of aluminum or a piece of wood a few centimetres thick.
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A wire carrying a 32.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's field, and there is a 2.15 N force on the 3.00 cm of wire in the field. What is the average field strength (in T) between the poles of the magnet?
Answer:
2.24 T
Explanation:
From Electromagnetic Field,
F = BILsin∅................ Equation 1
Where F = Force on the wire, B = Field strength, I = current flowing in the conductor, L = length of the conductor, ∅ = The angle the conductor makes with the magnetic field.
Making B the subject of the equation,
B = F/ILsin∅..................... Equation 2
Given: F = 2.15 N, I = 32 A, L = 3.00 cm = 0.03 m, ∅ = 90° ( the wire is perpendicular to the magnetic field)
Substitute into equation 2
B = 2.15/(32×0.03×sin90°)
B = 2.15/0.96
B = 2.24 T.
Hence the Field strength = 2.24 T
In boxing, the use of 16-ounce gloves rather than 12-ounce gloves reduces the chance of injury because the force is distributed over a greater area.A. TrueB. False
Answer:
true
Explanation:
Here we have assumed that increasing the mass of a glove will increase the surface area.
Injury is caused by the application of pressure at a point on the body. The application of pressure takes place via the area of the gloves. Pressure is given by
[tex]P=\dfrac{F}{A}[/tex]
where
F = Force
A = Area to which the force is applied
So, a bigger glove will increase the surface area and reduce the pressure resulting in a lower chance of injury.
Hence, the statement is true.
A jet plane is cruising at 300 m/s when suddenly the pilot turns the engines up to full throttle. After traveling 4.0 km, the jet is moving with a speed of 400 m/s.
What is the jet's acceleration, assuming it to be a constant acceleration?
I got :
a =
8.8
m/s2
Is your answer reasonable? Explain.
Explanation:
We have equation of motion v² = u² + 2as
Initial velocity, u = 300 m/s
Acceleration, a = ?
Final velocity, v = 400 m/s
Displacement,s = 4 km = 4000 m
Substituting
v² = u² + 2as
400² = 300² + 2 x a x 4000
a = 8.75 m/s² = 8.8 m/s²
The acceleration is 8.8 m/s²
The answer got is reasonable.
Final answer:
The jet's acceleration, assuming it to be a constant acceleration, is 8.75 m/s². The initial calculation of 8.8 m/s² was close, but using the kinematic equation we find the precise acceleration value.
Explanation:
Let's calculate the jet's acceleration with the given information. We know the initial speed (u), the final speed (v), and the distance (s) covered during acceleration:
Initial speed, u = 300 m/sFinal speed, v = 400 m/sDistance covered, s = 4.0 km or 4000 mWe can use the kinematic equation:
v² = u² + 2as
Where:
v is the final velocityu is the initial velocitya is the accelerations is the distancePlugging in the values:
4002 = 3002 + 2a(4000)
Solving for a gives:
a = (400² - 300²) / (2 × 4000)
a = (160000 - 90000) / 8000
a = 70000 / 8000
a = 8.75 m/s²
Your computation of 8.8 m/s² is quite close but let's ensure we're using the correct figures. The actual acceleration is 8.75 m/s² when calculated correctly, so a slight revision may be needed on your calculation depending on your rounding during the process.
A cyclist rides at a constant speed of 4.5 m/s around a curve. If the centripetal acceleration is 29 m/s2, what is the radius of the curve?
Answer:
(B) 0.70 m
Explanation:
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A cyclist rides at a constant speed of 4.5 m/s around a curve. If the centripetal acceleration is 29 m/s2, the radius of the curve is found as 0.70m.
To find the radius of the curve, the given values are,
Speed = 4.5 m/s,
centripetal acceleration = 29m/s².
What is centripetal acceleration?Centripetal acceleration is nothing but it always means towards the centre. Any object undergoing or processing in a circular motion which is uniform (uniform circular motion) has a centripetal acceleration and that acceleration is directed radially inwards.
The acceleration which has a magnitude that is equal to the square of the speed of the object along the curve, divided by the distance from the center of the circle to the object in motion.
Mathematically it can be expressed as;
a = [tex]\frac{v^{2} }{r}[/tex]
where
v is the speed (tangential speed)
r is the radius of the curve
In this case, we know the speed, v=4.5 m/s, and the centripetal acceleration, a=29 m/s^2, so we can re-arrange the equation above to find the radius of the curve:
r =[tex]\frac{v^{2} }{a}[/tex]
= [tex]\frac{4.5^{2} }{29}[/tex]
r= 0.70 m.
The radius of the curve r = 0.70m.
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