Answer:
It increases to three times its original value. Given the same radius of wire and other constant property. current is directly proportional to the magnetic field.
B1=B2
MoI1/2pir=MoI2/2pir; cancel the same values on both sides
B2/B1=6/2 =3
Explanation:
The magnetic field produced by a current-carrying wire depends on the current and distance from the wire.
Explanation:
The magnetic field produced by a current-carrying wire is given by the formula B = μi / (2πR), where B is the magnetic field strength, μ is the permeability of free space, i is the current in the wire, and R is the distance from the wire.
In this case, the current in the wire increases from 2 A to 6 A. As a result, the magnetic field at a distance of 0.01 m from the wire will also increase. However, the exact value of the magnetic field change can only be determined if the initial distance from the wire is known.
It is important to note that the magnetic field strength is inversely proportional to the distance from the wire, meaning that as the distance increases, the magnetic field strength decreases.
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Which describes a relationship when calculating the energy of a photon? The energy of the photon is directly proportional to frequency. The energy of the photon is inversely proportional to frequency. As the energy of the photon increases, Planck’s constant increases. As the energy of the photon increases, Planck’s constant decreases.
Answer:
The energy of a photon is directly proportional to it's frequency
Answer:
B. The energy of the photon is directly proportional to frequency.
Explanation:
1) My 14V car battery could be used to charge my laptop, but I need to use an inverter to first convert it to a standard 120V. Then my laptop charge cord has a resistor inside which ensures that 1.6A of current flow through to the laptop. What is the resistance in the charge cord?
2) My laptop charge cord actually has another inverter inside tat converts the electricity to 19.5V and 3.33A. What is the resistance in the cord that accomplishes this?
Answer:
1) Charge chord resistance is 75 Ω
2) Charge chord resistance is 6.33 Ω
Explanation:
1) To answer the question, we note that the the formula voltage is found as follows;
V = IR
Therefore,
[tex]R = \frac{V}{I} = \frac{120}{1.6} = 75 \, \Omega[/tex]
2) Where the voltage, V = 19.5 V and the current, I = 3.33 A, we have;
Initial resistance R₁ = 19.5 V/(3.33 A) = 5.86 Ω
However, to reduce the current to 1.6 A, we have;
[tex]R_T = \frac{19.5}{1.6} = 12.1875 \ \Omega[/tex]
Therefore, where the resistance is found by the sum of the total resistance we have;
[tex]R_T[/tex] = R₁ + Charge chord resistance
∴ 12.1875 = 5.86 + Charge chord resistance
Hence, charge chord resistance = 6.33 Ω
(1) The resistance in the charge cord at the given standard voltage is 75 ohms.
(2) The resistance in the cord that accomplishes the given voltage and current is 6.33 ohms.
The given parameters;
voltage of the car battery, V = 14 Vstandard voltage, = 120 Vcurrent in the laptop charger, I = 1.6 AThe resistance in the charge cord at the given standard voltage is calculated as follows;
[tex]V = IR\\\\R = \frac{V}{I} \\\\R = \frac{120}{1.6} \\\\R = 75 \ ohms[/tex]
The initial resistance when the voltage is 19.5 V and current is 3.33 A;
[tex]R = \frac{V}{I} \\\\R = \frac{19.5}{3.33} \\\\R = 5.86 \ ohms[/tex]
The total resistance when the current in cord is calculated as;
[tex]R = \frac{V}{I} \\\\R = \frac{19.5}{1.6} \\\\R = 12.19 \ ohms[/tex]
The internal resistance is calculated as;
[tex]r = 12.19 - 5.86\\\\r = 6.33 \ ohms[/tex]
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Timmy and Sarah go for a hike. they hike 5 miles in three hours and 15 minutes. what is the average speed to the nearest 10th of a mile. (Hint - you need to convert minutes to hours)
The average speed is 1.54 miles per hour.
As we know that,
Average speed [tex]=\frac{Distance}{time}[/tex]
Given that Timmy and Sarah travel 5 miles in three hours and 15 minutes.
Time [tex]=3+\frac{15}{60} =\frac{13}{4}hours[/tex]
Average speed [tex]=5\div \frac{13}{4} =5*\frac{4}{13}=1.54 miles/hour[/tex]
Thus, The average speed is 1.54 miles per hour.
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This a physics problem please solve the elastic collision problem use guess if you can if you can’t it’s fine
I will use my guess because I can. Unless you're the same person just spamming their question but if not, don't worry about it. they will crash at 5 m/s.
Final answer:
To analyze an elastic collision, one should use the momentum and kinetic energy conservation equations, simplifying them if one object is initially at rest. Inelastic collisions involve the conservation of momentum only and require experimental measures to determine energy dissipation.
Explanation:
An elastic collision is a type of collision where both momentum and kinetic energy are conserved. To solve a problem involving an elastic collision, one must use two independent equations: the conservation of momentum equation and the conservation of kinetic energy equation. If one of the objects is initially at rest, as stated in the question, the equations become simpler. We can set the initial velocity of the second object to zero, and then combine the equations algebraically to solve for the final velocities of both objects.
In the case of an inelastic collision, only momentum is conserved, and some kinetic energy is transformed into other forms of energy, such as heat or sound. To analyze changes in kinetic energy for an inelastic collision, one could modify an experiment to measure velocities before and after the collision and then calculate the kinetic energy to determine the fraction of mechanical energy dissipated.
In summary, analyzing an elastic collision typically involves mathematical calculations of velocities and kinetic energy, while an inelastic collision would be explored through experiments and calculations focusing on energy dissipation. If making graphical representations, one would plot momentum and kinetic energy before and after the collision to verify these relationships.
A 1400 kg vehicle travelling at 22 m/s slows at a constant rate to 4.5 m/s in 6.75 s. What was the net force acting on the car during this time?
Answer:
Net force = 3640 N
Explanation:
From first equation of motion
V = U + at
4.5 = 22 + 6.75a
( 4.5-22) ÷ 6.75 = a
acceleration (a) = -2.6m/s^2 ( negative sign shows deceleration, but actual acceleration is 2.6)
But Force = mass × acceleration
Force = 1400 × 2.6
Force = 3640 N
A red car passes a blue car. Which is true?
A.
The blue car must be parked.
B.
The red car must be moving backwards.
C.
The blue car must be moving slowly.
D.
The red car is moving faster than the blue car.
Answer:
D
Explanation:
A man is 6ft tall. What is the smallest size plane mirror he can use to see his entire image.
The smallest size plane mirror he can use is 3 feet tall, ensuring he can see his entire image reflected in the mirror
To see his entire image in a plane mirror, the mirror needs to be at least as tall as the man's height. However, since only half of his height is required for the mirror, the smallest size plane mirror he can use is half his height.
Given that the man is 6 feet tall, the smallest size plane mirror he can use to see his entire image would be [tex]\( \frac{6}{2} = 3 \)[/tex] feet tall. Therefore, the smallest size plane mirror he can use is 3 feet tall.
what is the distance between two spheres, each with a charge 2.5x10-6 C when the force between them is 0.50 N
Answer:
The distance between charges is 0.33 m.
Explanation:
We have,
The charge on each sphere is [tex]2.5\times 10^{-6}\ C[/tex]
Force between charges is 0.5 N
It is required to find the distance between spheres. The force between two charges is called electrical force. The force between them is given by :
[tex]F=\dfrac{kq^2}{r^2}[/tex]
r is distance between charges
[tex]r=\sqrt{\dfrac{kq^2}{F}} \\\\r=\sqrt{\dfrac{9\times 10^9\times (2.5\times 10^{-6})^2}{0.5}} \\\\r=0.33\ m[/tex]
So, the distance between charges is 0.33 m.
Final answer:
To find the distance between two spheres with identical charges of 2.5×10-6 C experiencing a 0.50 N force, use Coulomb's Law and rearrange it to solve for the distance, which is the square root of the product of Coulomb's constant, the magnitude of the charges, divided by the force.
Explanation:
The distance between two spheres, each with a charge of 2.5×10-6 C, when the force between them is 0.50 N, can be calculated using Coulomb's Law. The formula for Coulomb's Law is F = k × (|q1×q2|) / r2, where F is the force between the charges, k is Coulomb's constant (approximately 8.99×109 N·m2/C2), q1 and q2 are the charges, and r is the distance between the centers of the two charges.
By rearranging the formula to solve for r, we get r = √(k × (|q1×q2|) / F). Plugging in the values we have:
k = 8.99×109 N·m2/C2q1 = 2.5×10-6 Cq2 = 2.5×10-6 CF = 0.50 NThe charge on each sphere is 2.5* 10^(-6)\ C
Force between charges is 0.5 N
It is required to find the distance between spheres. The force between two charges is called electrical force. The force between them is given by :
F=(kq^2)/(r^2)
r is distance between charges
r=\sqrt{(kq^2)/(F)} \n\nr=\sqrt{(9* 10^9* (2.5* 10^(-6))^2)/(0.5)} \n\nr=0.33\ m
So, the distance between charges is 0.33 m.
An open organ pipe is 2.46 m long, and the speed of the air in the pipe is 345 m/s.
a. What is the fundamental frequency of this pipe?
Answer:
Fundamental frequency is 70.12 m
Explanation:
For an open organ pipe, the fundamental frequency is given by :
[tex]f=\dfrac{nv}{2l}[/tex]
n = 1 for fundamental frequency
v is speed of sound in air, v = 345 m/s
l is length of open organ pipe, l = 2.46 m
Substituting values in above formula. So,
[tex]f=\dfrac{1\times 345}{2\times 2.46}\\\\f=70.12\ Hz[/tex]
So, the fundamental frequency of this pipe is 70.12 m.
Final answer:
The fundamental frequency of a 2.46 m long open organ pipe, with air speed 345 m/s, is approximately 70.12 Hz.
Explanation:
To find the fundamental frequency of an open organ pipe, we can use the formula for the fundamental frequency of a pipe that is open at both ends, which is f1 = v / (2*L), where f1 is the fundamental frequency, v is the speed of sound in the pipe, and L is the length of the pipe.
In this case, the organ pipe is 2.46 meters long, and the speed of the air in the pipe is given as 345 meters per second. Plugging these values into the formula, we get:
f1 = 345 m/s / (2 * 2.46 m) = 345 m/s / 4.92 m = 70.12 Hz
Therefore, the fundamental frequency of this 2.46 m long open organ pipe is approximately 70.12 Hz.
An object with a mass of 7 kg accelerates 5 m/s2 when an unknown force is applied to it. What is the unknown force?
Answer:
35 N
Explanation:
Force, F = ma where m = mass = 7 kg and a = acceleration = 5 m/s².
So, F = ma = 7 kg × 5 m/s² = 35 N
Final answer:
To find the unknown force applied to an object with a mass of 7 kg accelerating at 5 m/s², use the formula F = ma to calculate it as 35 N.
Explanation:
The unknown force applied to the object with a mass of 7 kg can be calculated using the formula F = ma.
Given mass (m) = 7 kg and acceleration (a) = 5 m/s²
Substitute the values into the formula: F = (7 kg) (5 m/s²) = 35 N
Therefore, the unknown force applied to the object is 35 Newtons.
Figure 15-3 In Figure 15-3, which gas makes up the greatest percentage of Earth's atmosphere?
Answer:
Nitrogen
Explanation:
What is the total mechanical energy of a 200 kg roller coaster moving with a velocity of 16 m/s at a height of 18 m above the ground?
Mechanical Energy = PE + KE
PE: mgh = 200 x 9.8 x 18 = 35280
PE: 35280 Joules
KE: 1/2mv^2 = 1/2 x 200 x 16^2 = 25600
KE: 25600 Joules
ME: 35280 + 25600
ME: 60,880J
Rank these objects on the basis of their wavelength. (largest to smallest)person v=4.5m/selectron v=0.01cred light v=cproton v=0.01ccar v=27m/sbaseball v=41m/s
Answer:
red light > electron > proton > baseball > person > car
Explanation:
To calculate the wavelength associated to each object, you use the Broglie's relation:
[tex]\lambda=\frac{h}{mv}\\\\[/tex]
h: Planck,s constant = 6.62*10^-34 Js
m: mass
v: velocity
For each object you use an average values of its mass.
person:
mass = 80kg
[tex]\lambda=\frac{6.62*10^{-34}Js}{(80kg)(4.5m/s)}=1.83*10^{-36}m[/tex]
electron:
mass = 9.1*10^{-31}kg
[tex]\lambda=\frac{6.62*10^{-34}Js}{(9.1*10^{-31}kg)(0.01c)}\\\\\lambda=\frac{6.62*10^{-34}Js}{(9.1*10^{-31}kg)(0.01(3*10^{8}m/s))}\\\\\lambda=2.42*10^{-10}m[/tex]
red light:
In this case you use the following formula:
[tex]\lambda=\frac{c}{f}=\frac{3*10^8m/s}{4.3*10^{14}Hz}=6.97*10^{-7}m\approx700nm[/tex]
proton:
mass = 1.67*10^{-27}kg
[tex]\lambda=\frac{6.62*10^{-34}Js}{(1.67*10^{-27}kg)(0.01(3*10^8m/s))}\\\\\lambda=1.32*10^{-13}m[/tex]
car:
mass = 1500kg
[tex]\lambda=\frac{6.62*10^{-34}Js}{(1500kg)(27m/s)}=1.63*10^{-38}m[/tex]
baseball:
mass = 0.145kg
[tex]\lambda=\frac{6.62*10^{-34}Js}{(0.145kg)(41m/s)}\\\\\lambda=1.11*10^{-34}m[/tex]
hence, by comparing the wavelengths of the objects you have:
red light > electron > proton > baseball > person > car
Which planets have craters?
Answer:Mercury, Venus, Earth and Mars.
Explanation: The surfaces of asteroids and the rocky, ice covered moons of the outer gas planets are cratered as well.
Who is good in physics??
Answer:
joe
Explanation:
mama
(ii)
Calculate the amount of energy required to melt 15 kg of ice at 0 °C.
Specific latent heat of fusion of ice = 3.4 x 105 J/kg.
Energy =
Answer:
uekdjdbrjrnkfkdkfkff
Explanation:
E=mc(tetha)
=15(3.4x105)(0)
=0joules
A woman is pushing a 38.7kg lawnmower initially at rest with a 68.7N forward force against friction. The lawnmower speeds up to 1.44m/s in 3.81s. How much force does friction evert on the mower
Answer:
expected acceleration= 68.7/38.7=1.77 m/s^2
witnessed acceleration = 1.44/3.81 = 0.37 m/s^2
difference = 1.4m/s^2
so friction = 38.7× 1.4= 54.18 N
The magnitude of force does friction evert on the mower is 54.07 N.
What is speed?Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.
Given parameters:
Mass of the lawnmower: M = 38.7 kg.
Force applied on it: F = 68.7 N.
Final speed of the lawnmower: v = 1.44 m/s.
Time taken: t = 3.81 s.
Then, acceleration of the lawnmower: a = increase in speed/time
= 1.44/3.81 m/s² = 0.38 m/s².
Hence, resisting friction force = applied force - ma
= 68.7 N - 38.7 × 0.38 N
= 54.07 N.
Hence, the magnitude of force does friction evert on the mower is 54.07 N.
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If you drop something from low height is it faster
Faster to hit the ground because if so yes?
Amphibians live part of their lives like:___
A.Mammals
B.Fish
C.Birds
as the angle of incidence of light increases, what happens to the angle of refraction?
Answer:
it increases too as it bend away from the normal line
How much force is required to produce a torque of 100 Nm if the force is applied at an angle of 40 at a distance of 25 cm from the pivot?
Answer:
Force, F = 622.28 N
Explanation:
It is given that,
Torque, [tex]\tau=100\ N-m[/tex]
Angle between force and displacement, [tex]\theta=40^{\circ}[/tex]
Distance, d = 25 cm = 0.25 m
We need to find the force required to produce the torque. Torque produced by an object is given by :
[tex]\tau=Fd\sin\theta[/tex]
F is force required to produce torque
[tex]F=\dfrac{\tau}{d\sin\theta}\\\\F=\dfrac{100}{0.25\times \sin(40)}\\\\F=622.28\ N[/tex]
So, applied force is 622.28 N.
What is potential energy?
Energy released
Energy stored
Moving Energy
At 20°C, a length of copper wire has a resistance of 10.0 Ω What is its resistance when the wire is heated to 65°C? Let α = 0.004 at 20°C. Show all work and include units of measure. (2 points)
An object is placed 9.5 cm in front of a convex spherical mirror. Its image forms 3.2 cm behind the mirror. What is the radius of curvature of the mirror? Show all work. (2 points)
A candle is placed in front of a concave spherical mirror of focal length 9.60 cm. The image of the candle is inverted and 3.40 times as large as the candle itself. What is the distance of the candle to the mirror? Show all work and provide units of measure. (2 points)
An arrow pointing upward is placed to the left of a thin converging lens, as shown in the diagram. To identify the location of the image, a student draws three principal from the arrow. What feature should all three principal rays have in common? (2 points)
Dinosaur fossils are over 65 million years old. If some carbon from the dinosaur’s body remained in the fossil, would radiocarbon dating be useful for determining the age of the fossil? (1 point)
Yes, radiocarbon dating is useful for carbon-containing specimens of any age.
No, the carbon would have bonded chemically with other elements.
No, too much of the carbon-14 would have decayed for radiation to be detected.
A radioisotope has a half-life of 5.50 min and an initial decay rate of 7200 Bq. What will be the decay rate after 18.0 min? Show all work and include units of measure. (2 points)
A neutral atom of tin (Z = 50) has 69 neutrons. (a) How many protons does it have? (b) What is its mass number? (2 points)
Which type of nuclear reaction, fission or fusion, is used by nuclear power plants to produce electricity? Why? Be sure to include a brief explanation of the difference between fusion and fission. (2 points)
Radon-222 undergoes an alpha decay to become polonium-218. This reaction is an intermediate in a decay series that begins with uranium-238 and ends in lead-206.
A 1.0-gram sample of pure uranium-238 is sealed in a container at time = 0 years. To calculate the amount of radon-222 present in the container at any moment in the future, what is the minimum amount of information that must be known? (1 point)
The half-life of each decay reaction in the series from uranium-238 to lead-206
The half-life of each decay reaction in the series from uranium-238 to polonium-218
The half-life of each decay reaction in the series from uranium-238 to radon-222
The longest half-life in the series from uranium-238 to radon-222
The mass number of a neutral atom of iron (Z = 26) is 56. How many electrons does it have? (1 point)
56
30
26
13
Answer:
Identify arrows pointing to bonding electrons.
✔ a, b, d
Identify arrows pointing to nonbonding electrons.
✔ c
Identify arrows pointing to structures containing sigma bonds.
✔ a, b, d
Identify arrows pointing to structures containing pi bonds.
✔ a
Explanation:
On edg 2020
How can the image be described? Check all that apply. (Interpreting Ray Diagrams)
Answer:
the object is kept away from the focus of a convex lens. it form a real but inverted image of the object on the opposite side of the lens.
A series circuit consists of four resistors connected in series with values of 1.1,
11, 110, and 1100 ohms. What is the equivalent resistance of the circuit?
Answer:
Explanation:
hope this provides you with some clarity :)
To find the equivalent resistance of a series circuit consisting of resistors with values 1.1 ohms, 11 ohms, 110 ohms, and 1100 ohms, simply add the values together, resulting in an equivalent resistance of 1222.1 ohms.
The question involves calculating the equivalent resistance of a series circuit containing four resistors with the specified values of 1.1 ohms, 11 ohms, 110 ohms, and 1100 ohms. In a series circuit, the total or equivalent resistance can be found by simply adding up all the resistance values of the individual resistors.
To find the equivalent resistance of the circuit, we add the values of the resistors:
1.1 ohms11 ohms110 ohms1100 ohmsThe sum of these values gives us the total resistance:
1.1 + 11 + 110 + 1100 = 1222.1 ohms.
Therefore, the equivalent resistance of the series circuit is 1222.1 ohms.
3. A 0.35 kg puck slides across the ice with an average force of friction of 0.15 N acting on it. It slides 82 m before coming to rest. How much work was done on the puck?
Answer:
Work done is 12.3 J
Explanation:
We have,
Mass of puck, m = 0.35 kg
Force of friction acting on the puck when it slides is 0.15 N
Distance travelled by the puck is 82 m.
It is required to find the work done on the puck. Finally the puck comes to rest and the force of friction is acting on it. It means the applied force is 0.15 N. Work done is given by
[tex]W=Fd\\\\W=0.15\times 82\\\\W=12.3\ J[/tex]
The work done on the puck is 12.3 J.
How much power can a motor output if it does 25 J of work in 1 s? *
Answer:
25 W
Explanation:
Power: This can be defined as the rate at which work is done. The S.I unit of power is Watt (W).
The expression of power is given as
Power = work output/time
P = W/t................ Equation 1
Given: W = 25 J. t = 1s
Substitute into equation 1
P = 25/1
P = 25 W
Hence the output power of the motor is 25 W
Answer:
The power is 25 W
Explanation:
Given;
work done by motor output. E = 25 J
Time taken to complete this task, t = 1 s
Power is the amount of work done per unit time or energy per unit time.
The amount of power developed by the motor, can be calculated as follows using the formula below;
[tex]Power = \frac{Energy}{time} = \frac{25}{1} = 25 \ W[/tex]
Therefore, the amount of power developed by the motor in the given time is 25 W.
A 0.5 kg ball is at the top of a ramp which is 8 meters high. How much
Vinetic energy does the ball have at the bottom of the ramp? (round the
answer to the tenths place)
Answer:
same as the potential energy possessed at top
= 0.5×9.8×8
= 39.2 joules
Answer: The answer is 40 J.
Explanation: I did it just now.
An atom of 6/2 He decays by beta decay. What atom is left after decay
Answer:
6/3 LI
Explanation:
You have a tungsten sphere (emissivity ε = 0.35) of radius 25 cm at a temperature of 25°C. If the sphere is enclosed in a room whose walls are kept at -5°C, what is the net flow rate of energy out of the sphere?
The net rate of energy flow from the tungsten sphere can be calculated using the modified Stefan-Boltzmann equation, taking into account the sphere's emissivity, surface area and temperature, as well as the temperature of the surroundings. After calculating, we have the net rate of heat transfer.
Explanation:The net flow rate of energy from an object, in this case a tungsten sphere, can be calculated using the modified Stefan-Boltzmann equation which is suitable for net rate of heat transfer by radiation. The formula used is Qnet = σeA(T₁⁴ - T₂⁴), where σ is the Stefan-Boltzmann constant (5.67 × 10⁻⁸ J/s.m².K⁴), e is the emissivity (0.35 for tungsten), A is the surface area of the sphere (πr² with r being the radius of the sphere), and T₁ and T₂ are the temperatures of the sphere and the surroundings respectively, converted to Kelvin.
First, we convert the Celsius temperatures to Kelvin by adding 273.15 to each temperature, making T₁ = 298.15 K and T₂ = 268.15 K. Then, finding the surface area, we get A = 4πr² = 4.90 m² with r = 0.25 m. Substituting these values into the equation gives us Qnet = (5.67 × 10⁻⁸ J/s.m².K⁴)(0.35)(4.90 m²)[(298.15 K)⁴ - (268.15 K)⁴] which, when calculated, gives the net rate of heat transfer by radiation from the tungsten sphere.
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Final answer:
The net flow rate of energy from a tungsten sphere in a cooler room can be calculated using the Stefan-Boltzmann law; accounting for emissivity, surface area, and the difference in the fourth powers of the absolute temperatures of the sphere and its surroundings.
Explanation:
The student's question regarding the net flow rate of energy out of a tungsten sphere enclosed in a room with cooler walls can be answered using the Stefan-Boltzmann law for thermal radiation which states that the power radiated from an object is proportional to its emissivity (e), the Stefan-Boltzmann constant (σ), the surface area of the object (A), and the fourth power of its absolute temperature (T) in kelvins. For our purposes, the net power radiated is the difference in power radiated by the sphere and the power absorbed from the surroundings. To find the surface area (A) of the sphere we use the formula 4πr2 where r is the radius of the sphere. Then, we transform the temperatures from Celsius to Kelvins and plug our values into the equation P = eσA(T4 - T04) to find the net flow rate of energy out of the sphere.