Answer:
3024 in^3Step-by-step explanation:
let width=x
length=x+4
height=x-2
A=W×L
252=(x)(x+4)
252=x^2 +4x
0=x^2 +4x -252
use quadratic formula
x=14
W=14
L=18
H=12
V=W×L×H
V=(14)(18)(12)
V=3024 in^3Final answer:
To calculate the volume of the crate, solve for the width using the base area and the relation between length and width, then find the height. Multiply length, width, and height to obtain the crate's volume.
Explanation:
To find the volume of the crate, we must first determine the dimensions of the base. We know that the area of the base is 252 square inches, and that the length (L) is 4 inches greater than the width (W).
Therefore, we can express the length as L = W + 4. Since the area of a rectangle is given by length times width (A = L × W), we can write the equation W × (W + 4) = 252.
Step 1: Find the width (w)
Substitute l=w+4 into the first equation:
w² + 4w - 252= 0
Solve the quadratic equation using the quadratic formula:
w = −b ±√ b²−4ac/2a
where a=1, b=4, and c=−252.
w = −4 ± √4²−4 × 1 × −252/2 × 1
w = −4 ± √1024/2
w = −4 ± 32/2
Since the width cannot be negative, we discard the negative solution.
Therefore, w=14 inches.
Step 2: Find the length (l) and height (h)
l=w+4=14+4=18 inches
h=w−2=14−2=12 inches
Step 3: Find the volume (V)
V = l × w × h = 18 × 14 × 12 = 3024 cubic inches.
A woman who is 5.75ft tall stands next to a lamp post that is 12ft tall. If its' shadow is 30ft long, how long is the shadow of the woman?
Answer:
The length of shadow of the woman is 14.375 ft.
Step-by-step explanation:
Here we are given that
Height of the woman = 5.75 ft
Height of the lamp post = 12 ft
Shadow of the lamp post = 30 ft
Let the angle of elevation of the light source be θ
By definition, in a right triangle, with respect to angle θ, we have;
tan(θ) = Opposite÷Adjacent
Therefore, tan(θ) = (Height of the lamp post)÷(Shadow of the lamp post)
and tan(θ) = 12 ft ÷ 30 ft = 0.4
θ = Actan(0.4) = tan⁻¹(0.4) = 21.8°
Since, angle of elevation of the light = Angle of depression of the light (alternate angles) = 21.8° we have
tan(θ) = (Height of the woman) ÷ (Length of shadow of the woman)
∴ Length of shadow of the woman = (Height of the woman) ÷ tan(θ)
Length of shadow of the woman = 5.75 ft ÷ tan(21.8) = 5.75 ft ÷ 0.4
Length of shadow of the woman = 5.75 ft ÷ 0.4 = 14.375 ft.
Alex has five rolls of shelf paper that is 800 cm long.She wants to use the to line the 1-meter wide shelves in her pantry. How many 1-meter wide can she line with the paper?
1 meter = 100 cm
So a 800 cm roll can cover 8 meters
(800/100 = 8)
She has 5 rolls so 5 x 8 = 40 meters total.
You are given 4 matrices M1, M2, M3, M4 and you are asked to determine the optimal schedule for the product M1 ×M2 × M3 ×M4 that minimizes the number of operations (addition/multiplication) involved. The dimensions of the four matrices are respectively 100 × 50, 50 × 200, 200 × 50, and 50 × 10. What is the best (cheapest) schedule to multiply all the matrices together and compute M1 × M2 × M3 × M4? What is the total cost for this schedule?
Answer:
Step-by-step explanation:
first method is to try out all possible combinations and pick out the best one which has the minimum operations but that would be infeasible method if the no of matrices increases
so the best method would be using the dynamic programming approach.
A1 = 100 x 50
A2 = 50 x 200
A3 = 200 x 50
A4 = 50 x 10
Table M can be filled using the following formula
Ai(m,n)
Aj(n,k)
M[i,j]=m*n*k
The matrix should be filled diagonally i.e., filled in this order
(1,1),(2,2)(3,3)(4,4)
(2,1)(3,2)(4,3)
(3,1)(4,2)
(4,1)
Table M[i, j]
1 2 3 4
4 250000 200000 100000 0
3
750000 500000 0
2 1000000 0
1
0
Table S can filled this way
Min(m[(Ai*Aj),(Ak)],m[(Ai)(Aj*Ak)])
The matrix which is divided to get the minimum calculation is selected.
Table S[i, j]
1 2 3
4
4 1 2 3
3
1 2
2 1
1
After getting the S table the element which is present in (4,1) is key for dividing.
So the matrix multiplication chain will be (A1 (A2 * A3 * A4))
Now the element in (4,2) is 2 so it is the key for dividing the chain
So the matrix multiplication chain will be (A1 (A2 ( A3 * A4 )))
Min number of multiplications: 250000
Optimal multiplication order: (A1 (A2 ( A3 * A4 )))
to get these calculations perform automatically we can use java
code:
public class MatrixMult
{
public static int[][] m;
public static int[][] s;
public static void main(String[] args)
{
int[] p = getMatrixSizes(args);
int n = p.length-1;
if (n < 2 || n > 15)
{
System.out.println("Wrong input");
System.exit(0);
}
System.out.println("######Using a recursive non Dyn. Prog. method:");
int mm = RMC(p, 1, n);
System.out.println("Min number of multiplications: " + mm + "\n");
System.out.println("######Using bottom-top Dyn. Prog. method:");
MCO(p);
System.out.println("Table of m[i][j]:");
System.out.print("j\\i|");
for (int i=1; i<=n; i++)
System.out.printf("%5d ", i);
System.out.print("\n---+");
for (int i=1; i<=6*n-1; i++)
System.out.print("-");
System.out.println();
for (int j=n; j>=1; j--)
{
System.out.print(" " + j + " |");
for (int i=1; i<=j; i++)
System.out.printf("%5d ", m[i][j]);
System.out.println();
}
System.out.println("Min number of multiplications: " + m[1][n] + "\n");
System.out.println("Table of s[i][j]:");
System.out.print("j\\i|");
for (int i=1; i<=n; i++)
System.out.printf("%2d ", i);
System.out.print("\n---+");
for (int i=1; i<=3*n-1; i++)
System.out.print("-");
System.out.println();
for (int j=n; j>=2; j--)
{
System.out.print(" " + j + " |");
for (int i=1; i<=j-1; i++)
System.out.printf("%2d ", s[i][j]);
System.out.println();
}
System.out.print("Optimal multiplication order: ");
MCM(s, 1, n);
System.out.println("\n");
System.out.println("######Using top-bottom Dyn. Prog. method:");
mm = MMC(p);
System.out.println("Min number of multiplications: " + mm);
}
public static int RMC(int[] p, int i, int j)
{
if (i == j) return(0);
int m_ij = Integer.MAX_VALUE;
for (int k=i; k<j; k++)
{
int q = RMC(p, i, k) + RMC(p, k+1, j) + p[i-1]*p[k]*p[j];
if (q < m_ij)
m_ij = q;
}
return(m_ij);
}
public static void MCO(int[] p)
{
int n = p.length-1; // # of matrices in the product
m = new int[n+1][n+1]; // create and automatically initialize array m
s = new int[n+1][n+1];
for (int l=2; l<=n; l++)
{
for (int i=1; i<=n-l+1; i++)
{
int j=i+l-1;
m[i][j] = Integer.MAX_VALUE;
for (int k=i; k<=j-1; k++)
{
int q = m[i][k] + m[k+1][j] + p[i-1]*p[k]*p[j];
if (q < m[i][j])
{
m[i][j] = q;
s[i][j] = k;
}
}
}
}
}
public static void MCM(int[][] s, int i, int j)
{
if (i == j) System.out.print("A_" + i);
else
{
System.out.print("(");
MCM(s, i, s[i][j]);
MCM(s, s[i][j]+1, j);
System.out.print(")");
}
}
public static int MMC(int[] p)
{
int n = p.length-1;
m = new int[n+1][n+1];
for (int i=0; i<=n; i++)
for (int j=i; j<=n; j++)
m[i][j] = Integer.MAX_VALUE;
return(LC(p, 1, n));
}
public static int LC(int[] p, int i, int j)
{
if (m[i][j] < Integer.MAX_VALUE) return(m[i][j]);
if (i == j) m[i][j] = 0;
else
{
for (int k=i; k<j; k++)
{
int q = LC(p, i, k) + LC(p, k+1, j) + p[i-1]*p[k]*p[j];
if (q < m[i][j])
m[i][j] = q;
}
}
return(m[i][j]);
}
public static int[] getMatrixSizes(String[] ss)
{
int k = ss.length;
if (k == 0)
{
System.out.println("No matrix dimensions entered");
System.exit(0);
}
int[] p = new int[k];
for (int i=0; i<k; i++)
{
try
{
p[i] = Integer.parseInt(ss[i]);
if (p[i] <= 0)
{
System.out.println("Illegal input number " + k);
System.exit(0);
}
}
catch(NumberFormatException e)
{
System.out.println("Illegal input token " + ss[i]);
System.exit(0);
}
}
return(p);
}
}
output:
What is the area of a regular pentagon with an apothem of 8 centimeters
Answer:
The of the pentagon is A=232.48cm²
Step-by-step explanation:
This problem bothers on the mensuration of flat shapes, a pentagon
Now given the apothem the area can be expressed as
A=a²n tan (180/n)
where
a = the length of the apothem (in radius)
n = the number of sides= 5 for pentagon
tan is the tangent function calculated in degrees
Substituting our given data we can solve for the area A
A= 8²*5 tan (180/5)
A= 64*5 tan 36
A= 320tan 36
A= 320*0.7265
A=232.48cm²
Which best describes the numbers satisfying the inequality x <7?
all numbers greater than 7
all numbers less than 7
all numbers greater than and including 7
all numbers less than and including
FU
O
RRET
Sa
Answer:
(B) all numbers less than 7
Step-by-step explanation:
Given the inequality:
x<7
It means that:
x cannot be equal to 7x cannot be greater than 7Therefore, x<7 consists of all numbers less than 7.
Answer:
B
Step-by-step explanation:
Dr. Vegapunk thinks that watching anime (Japanese animated shows) decreases social skills in college students. To test this, Dr. Vegapunk randomly selected 30 brooklyn college students and assigned them to watch an episode of anime everyday for a week. After the week, each of the students answered a questionnaire about their social skills. The results showed that the sample had a mean social skills score of 7.3 and a standard deviation of 2.4. A previous study showed that the overall population of brooklyn college students had a mean social skills score of 6.2, but the standard deviation was not reported. Dr. Vegapunk decides to use an alpha level of 0.05. e) what is the obtained statistic
Answer:
The test statistic = 2.51
Step-by-step explanation:
For hypothesis testing, the first thing to define is the null and alternative hypothesis.
The null hypothesis plays the devil's advocate and usually takes the form of the opposite of the theory to be tested. It usually contains the signs =, ≤ and ≥ depending on the directions of the test.
While, the alternative hypothesis usually confirms the the theory being tested by the experimental setup. It usually contains the signs ≠, < and > depending on the directions of the test.
For this question, Dr. Vegapunk wants to test the claim that watching anime decreases social skills in college students.
So, the null hypothesis would be that there isn't significant evidence to conclude that watching anime decreases social skills in college students. That is, watching anime does not decrease social skills in college students.
And the alternative hypothesis is that there is significant evidence to conclude that watching anime decreases social skills in college students.
If the previous known mean social skills of college students is 6.2 and the new population mean social skills of college students who watch anime is μ,
Mathematically,
The null hypothesis is represented as
H₀: μ ≥ 6.2
The alternative hypothesis is given as
Hₐ: μ < 6.2
To do this test, we will use the t-distribution because no information on the population standard deviation is known
So, we compute the t-test statistic
t = (x - μ)/σₓ
x = sample mean = 7.3
μ₀ = Standard to be compared against = 6.2
σₓ = standard error of sample mean = [σ/√n]
where n = Sample size = 30
σ = Sample standard deviation = 2.4
σₓ = (2.4/√30) = 0.4382
t = (7.3 - 6.2) ÷ 0.4382
t = 2.51
Hope this Helps!!!
Carlita goes jogging and her gps collects the data for her distance over time. What would the rate of change for that data represent
Answer:
Carlita's Speed or distance over time
Step-by-step explanation:
The rate of change of the data (her distance) is her speed.
Speed is the rate of change of distance, distance covered overtime.
Speed = distance/time
Unit = meter/seconds or miles per hour
Therefore, the rate of change for that data represent Carlita's Speed or distance over time
What’s does 200% increase mean
Answer:
from what I understand a 200% increase is tripling the number the increase is on
Terry ran 1/10 of the distance from school to home. He walked 3/10 more of the distance and then skipped 2/10 more the distance. What fraction of the distance
home does Terry still have to go?
Answer: 4/10, simplified to 2/5
Step-by-step explanation:
1/10 plus 3/10 plus 2/10 is 6/10
10/10 minus 6/10 is 4/10
4/10 simplified (divide the numerator and the denominator by 2) is 2/5
Final answer:
Terry has covered 3/5 of the distance to home by running, walking, and skipping. Therefore, he still has 2/5 of the distance left to cover.
Explanation:
The question asks how much distance Terry still has to cover to reach home, given the fractions of the journey he has completed by running, walking, and skipping.
Terry ran 1/10 of the distance, walked 3/10 more, and skipped 2/10 more of the distance. To find the total distance covered, we add these fractions together:
1/10 (running) + 3/10 (walking) + 2/10 (skipping) = 6/10 or 3/5 of the distance.To find the distance Terry still has to go, we subtract the fraction of the distance he has covered from the whole distance (1 or 5/5):
5/5 - 3/5 = 2/5Therefore, Terry still has to cover 2/5 of the distance to reach home.
A schools enrollment in 2012 was 1234 now it is 1456 what does the expression look like that would help me find the percent change
Answer:
.18 % increase
Step-by-step explanation:
First you would find what the difference is between the school enrollment
you would do 1456 - 1234 = 222
Then you would divide 1234/1456 = 84.75% to see the total percentage
The increase however has a percentage of .18%
To check your work you would do .18 x 1234 = 222.12 ( round to the nearest whole number so it would just be 222) then add 1234+ 222 = 1456!
Answer:
A) (1,456-1,234) ÷ 1,456
Find the coordinates for the vertex of the graph of the function y = 2x' + 2x - 4.
Answer:
(-1/2,-9/2)
Step-by-step explanation:
that is the coordinates for the vertex of the function y=2xsqaured+2x-4
Please help! ASAP :)
Answer:
3.14 miles but that doesn't sound right
Step-by-step explanation:
Assuming you have to find area of the circle its
A = πr² Radius is half of diameter so half of 2 = 1
A = 3.14 x 1²
A = 3.14 x 1
A = 3.14
If you have to find area than its 3.14 it just sounds odd
Sorry if its wrong
I need help :( please help. Best answer = Brainiest,
Answer:
5
Step-by-step explanation:
let a be the other number
so one number is [tex]\frac{2}{3}a - 3[/tex]
a + [tex]\frac{2}{3}a - 3[/tex] = 17
[tex]\frac{5}{3}a - 3 = 17[/tex]
[tex]\frac{5}{3}a[/tex] = 17 + 3 = 20
a = 20 x [tex]\frac{3}{5}[/tex] = 12
[tex]\frac{2}{3}(12) - 3[/tex] = 5
Manuel painted 0.75 of a rectangular banner green. After the paint dried, he painted 0.6 of the green area orange. What part of the banner is painted orange?
Answer:
0.45 part of the banner is painted orange.
Step-by-step explanation:
Given that the area for green = 0.75
The area of orange on green is = 0.6
So the area of orange is = 0.75*0.6 = 0.45
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To find the part of the banner that is painted orange, we multiply the green area by 0.6 and divide by the total area of the banner.
Explanation:To find the part of the banner that is painted orange, we need to calculate the orange area compared to the total area of the banner.
First, we calculate the green area by multiplying the total area of the banner by 0.75.Then, we find the orange area by multiplying the green area by 0.6.Finally, we divide the orange area by the total area of the banner to get the part that is painted orange.Let's say the total area of the banner is 100 square units. Using the steps above:
The green area is 100 * 0.75 = 75 square units.The orange area is 75 * 0.6 = 45 square units.The part of the banner that is painted orange is 45 / 100 = 0.45, which is 45%.Learn more about Calculating the part of a rectangular area that is painted orange here:https://brainly.com/question/30659007
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Katrina is asked to simplify the expression Negative 3 a minus 4 b minus 2 (5 a minus 7 b).
She writes: Negative 3 a minus 4 b minus 2 (5 a minus 7 b) = negative 3 a minus 4 b minus 10 a + 14 b
Answer:
-13a+10b
Step-by-step explanation:
Which set of ordered pairs could be generated by an exponential function?
(1, 1), (2.2), (3, 3), (4-4)
• (1, 1), (2.4), (0.5) (470)
Answer:
(1, 1), (2.4), (0.5) (470)
Step-by-step explanation:
Honestly, I only know it's this one because the first one is a linear function. If you think about it on a graph, all of the points on the first one can connect with a straight line.
Prove that if A2 = O, then 0 is the only eigenvalue of A. STEP 1: We need to show that if there exists a nonzero vector x and a real number λ such that Ax = λx, then if A2 = O, λ must be . STEP 2: Because A2 = A · A, we can write A2x as A(Ax). STEP 3: Use the fact that Ax = λx and the properties of matrix multiplication to rewrite A2x in terms of λ and x. A2x = x STEP 4: Because A2 is a zero matrix, we can conclude that λ must be .
Answer:
Check the explanation
Step-by-step explanation:
Kindly check the attached image below to see the step by step explanation to the question above.
Evaluate the function. Find f(5). f(x)=4x-1
Answer:
19
Step-by-step explanation:
plug in 5 for x so f(5)=4(5)-1 = 20-1 = 19
The solution of expression f (x) = 4x - 1at x = 5 would be 19.
Given that the expression is,
f (x) = 4x - 1
Used the concept of substitution method to solve the expression.
Now, substitute x = 5 in the expression,
f (x) = 4x - 1
f (5) = 4(5) - 1
f (5) = 20 - 1
f (5) = 19
Therefore, the value of the expression is f (5) = 19.
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What is the sum of the
measures of the exterior
angles on a polygon with
20 sides?
Answer:
360 degree
Step-by-step explanation:
The sum of all the exterior angles is 360 for any polygon.
This can be proved for polygon with 20 sides also.
We know that sum of all the angles of polygon is given by formula = (2*n -4) *90
where n is the no. of sides of polygon
for 20 sides polygon sum of sum of all the angles = (2*20 -4) * 90
= (40-4)*90 = 36*90 = 3240 degree
measure of each angle of polygon = sum of total angles of polygon/ no of sides of polygon = 3240/20 = 162
We also know that sum of interior and exterior angle of triangle is 180 degree, as interior and exterior angle lies on straight line and they are supplementary
so
162 + value of exterior angle = 180
=> value of exterior angle = 180 - 162 = 18
Value of one exterior angle is 18 degree
in 20 sided polygon there are 20 exterior angle
therefore, value of 20 exterior angle is 18*20 degree which is 360 degree.
__________________________________________________________
As a general point one can memorize than sum of all the exterior angle for a polygon with any number of side is 360.
Which of the following statements is false? a. When the alternative hypothesis is two-tailed, any hypothesis test is said to be a two-tailed test. b. When the alternative hypothesis is two-tailed, the null hypothesis is rejected for values of the test statistic located in either tail of that statistic's sampling distribution. c. When the alternative hypothesis is two-tailed, the rejection region is split between the two tails of the test statistic's sampling distribution. d. When the alternative hypothesis is two-tailed, the null hypothesis is rejected for values of the test statistic located in either tail of that statistic's sampling distribution and when the alternative hypothesis is two-tailed, the rejection region is split between the two tails of the test statistic's sampling distribution. e. None of these.
Answer:
Step-by-step explanation:
For a two tailed alternative hypothesis, it involves the "not equal to symbol,≠ ". This can never be in the null hypothesis.
The curve is symmetrical and the rejection regions would be in the left and right tails
In order to reject the null hypothesis, the test statistic must be smaller than the critical value on the left tail or greater than the critical value on the right tail.
Therefore, the following statements are false
B. When the alternative hypothesis is two-tailed, the null hypothesis is rejected for values of the test statistic located in either tail of that statistic's sampling distribution.
D. When the alternative hypothesis is two-tailed, the null hypothesis is rejected for values of the test statistic located in either tail of that statistic's sampling distribution and when the alternative hypothesis is two-tailed, the rejection region is split between the two tails of the test statistic's sampling distribution.
Final answer:
Statement d is false because it combines parts of two separate true statements, which could be misleading. A two-tailed test is indicated by a not equals symbol in the alternative hypothesis, and the rejection region is split between the two tails of the test statistic's sampling distribution.
Explanation:
The false statement is d. While it's true that when the alternative hypothesis is two-tailed, the null hypothesis is rejected for values of the test statistic located in either tail of that statistic's sampling distribution, statement d is false because it repeats the earlier part of the statement and combines it with a correct statement from option c, which can be misleading. The correct information is provided in separate statements b and c.
The alternative hypothesis indicates the type of test to be conducted. If the alternative hypothesis has a not equals symbol (≠), it indicates a two-tailed test. In a two-tailed test, the rejection region is split between the two tails of the test statistic's sampling distribution. In terms of p-value, it represents the probability of obtaining test results at least as extreme as the results actually observed, under the assumption that the null hypothesis is correct. A small p-value (< 0.05) typically indicates strong evidence against the null hypothesis, leading to its rejection.
Solve the system of equations:
y=2x-3
y=x2-3
Answer: x = 0 or x = 2
Step-by-step explanation:
To solve this, we must note that the two equations speaks of a single function of y. So
y = 2x - 3 = x² - 3
So from.here we can equate the two together and solve for x.
x² - 3 = 2x - 3, biw convert to a quadratic expression
x² - 2x - 3 + 3 = 0
x² - 2x = 0
Now factorize
x( x - 2 ) = 0, so solving for x
x = 0 or x = 2. .I believed getting the 2 won't be a problem
When x - 2 = 0
Then x = 2.
Write a verbal expression for 3m-8n/13
Step-by-step explanation:
Three m minus eight n divided by thirteen
find lim x →0 f(2+h)-f(2)/h if f(x)=x^3
Answer:
The value of the limit is 12.
Step-by-step explanation:
Small typing mistake, the limit is of h tending to 0.
We have that:
[tex]f(x) = x^{3}[/tex]
Then
[tex]f(2+h) = (2+h)^{3} = 8 + 12h + 6h^{2} + h^{3}[/tex]
[tex]f(2) = 2^{3} = 8[/tex]
Calling the limit L
[tex]L = \frac{f(2+h) - f(2)}{h}[/tex]
[tex]L = \frac{8 + 12h + 6h^{2} + h^{3} - 8}{h}[/tex]
[tex]L = \frac{h^{3} + 6h^{2} + 12h}{h}[/tex]
h is the common term in the numerator, then
[tex]L = \frac{h(h^{2} + 6h + 12)}{h}[/tex]
Simplifying by h
[tex]L = h^{2} + 6h + 12[/tex]
Since h tends to 0.
[tex]L = 0^{2} + 6*0 + 12[/tex]
[tex]L = 12[/tex]
So the answer is 12.
Using the definition of a derivative, the expression lim h→0 [f(2+h)-f(2)]/h for f(x)=x^3 simplifies to 12, which is the derivative of the function at x=2.
Explanation:The limit you are trying to find is representative of the definition of a derivative at a point. In this case, the function is f(x) = x^3 and we're trying to find the derivative at x = 2. This is the definition of the derivative at a point:
lim h→0 [f(x+h) - f(x)] / h
Now, we plug in the equation for f(x):
lim h→0 [(2+h)^3 - 2^3] / h = lim h→0 [8+12h+6h^2+h^3 - 8] / h
Simplify that to get:
lim h→0 h [12+6h+h^2] / h
Then, by cancelling the h's, you have:
lim h→0 [12+6h+h^2]
As h→0, 6h and h^2 become 0, so finally, you obtain 12 as the derivative of f at x=2.
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The Normal model N(65, 2.5) describes the distribution of heights of college women (inches). Which of the following questions asks for a probability and which asks for a measurement (and is thus an inverse Normal question)? a. nbsp What is the probability that a random college woman has a height of 68 inches or more? b. nbsp To be in the Tall Club, a woman must have a height such that only 2% of women are taller. What is this height?
Answer:
a) 11.51% probability that a random college woman has a height of 68 inches or more
b) This height is 70.135 inches.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
The normal distribution has two parameters, which are the mean and the standard deviation.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 65, \sigma = 2.5[/tex]
a. What is the probability that a random college woman has a height of 68 inches or more?
This is 1 subtracted by the pvalue of Z when X = 68. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{68 - 65}{2.5}[/tex]
[tex]Z = 1.2[/tex]
[tex]Z = 1.2[/tex] has a pvalue of 0.8849
1 - 0.8849 = 0.1151
11.51% probability that a random college woman has a height of 68 inches or more
b. To be in the Tall Club, a woman must have a height such that only 2% of women are taller. What is this height?
This weight is the 100-2 = 98th percentile, which is the value of X when Z has a pvalue of 0.98. So X when Z = 2.054.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]2.054 = \frac{X - 65}{2.5}[/tex]
[tex]X - 65 = 2.054*2.5[/tex]
[tex]X = 70.135[/tex]
This height is 70.135 inches.
In 2005, there were 74,250 car accidents. In 20,187 of them, the driver was a
female. Based on this, what is the probability that a female driver was
involved in an accident?
Answer:
27.19% probability that a female driver was involved in an accident
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
In this question:
74,250 car accidents. Of those, in 20,187, the driver was a female.
Based on this, what is the probability that a female driver was involved in an accident?
p = 20187/74250 = 0.2719
27.19% probability that a female driver was involved in an accident
The probability that a female driver was involved in one of the car accidents in 2005 is approximately 27.2%.
To determine the probability that a female driver was involved in an accident, we use the following formula:
Probability (P) = Number of favorable outcomes / Total number of outcomesIn this case, the number of favorable outcomes is the number of accidents involving a female driver (20,187), and the total number of outcomes is the total number of car accidents (74,250).
Divide the number of accidents involving female drivers by the total number of accidents: 20,187 / 74,250Simplify the fraction to get the decimal form: P ≈ 0.272Convert the decimal to a percentage if needed: 0.272 × 100 = 27.2%Therefore, the probability that a female driver was involved in an accident is approximately 27.2%.
A small tie shop finds that at a sales level of x ties per day its marginal profit is MP (x )dollars per tie, where MP (x )equals 1.85 plus 0.12 x minus 0.0024 x squared. Also, the shop will lose $65 per day at a sales level of x equals 0. Find the profit from operating the shop at a sales level of x ties per day.
Question:
A small tie shop finds that at a sales level of x ties per day its marginal profit is MP(x )dollars per tie, where
MP(x) =1.85 + 0.12x - 0.0024x². Also, the shop will lose $65 per day at a sales level of x= 0. Find the profit from operating the shop at a sales level of x ties per day.
Answer:
P(x) = 1.85x + 0.06x^2 - 0.0008x^3 - 65
Step-by-step explanation:
MP(x) = 1.85 + 0.12(x) - 0.0024(x^2)
At sales level, x=0, loss = $65
P(0) = - $65
Integrating MP(x) with respect to x
P(x) = ∫MP(x) dx = ∫ 1.85 + 0.12(x) - 0.0024(x^2)
P(x) = 1.85x + 0.06x^2 - 0.0008x^3 + C
Therefore :
P(x) = 1.85x + 0.06x^2 - 0.0008x^3 - 65
Correct question:
A small tie shop finds that at a sales level of x ties per day its marginal profit is MP(x )dollars per tie, where
MP(x) =1.85 + 0.12x - 0.0024x². Also, the shop will lose $65 per day at a sales level of x= 0. Find the profit from operating the shop at a sales level of x ties per day.
Answer:
P(x) =1.85x +0.06x² - 0.0008x³ - 65
Step-by-step explanation:
Given the marginal profit function:
MP(x) =1.85 +0.12x - 0.0024x², P(0)= -65
We are to find P(x).
P(x) = ∫MP(x) dx
P(x) = ∫(1.85 + 0.12x - 0.0024x²) dx
= ∫1.85 dx+∫0.12x dx+∫(-0.0024x²)dx + C
= 1.85x + 0.06x² - 0.0008x³ + C
Initial condition at P(0) = - 65
where x(0), P(x) = -65
we have:
-65 = 1.85(0)+0.06(0)² - 0.0008x(0)³ + C
-65 = 0 + 0 - 0 + C
-65 = C
C = -65
P(x) =1.85x + 0.06x² - 0.0008x³ - 65
What are the coordinates of the image of point A after the segment has been dilated by a scale factor of One-fourth with a center of dilation at the origin? On a coordinate plane, point B is at (negative 2, 4) and point A is at (4, negative 8). (–2, 1) (1, –2) (Negative one-half, 1) (1, negative one-half)
Answer:
The answer is B
Step-by-step explanation:
Just did the assignment on Egn.
1:
Which equations represent linear functions? Select all that apply.
A
y=x2
B
−x=y
C
y=14x2+4
D
6x−3y=12
E
y=−2x2+1
Final answer:
Equations B (−x = y) and D (6x −3y = 12) represent linear functions because they can be written in the standard linear form y = mx + b, where m and b are constants.
Explanation:
When determining if an equation represents a linear function, we look for the standard form y = mx + b, where m represents the slope and b represents the y-intercept. In this form, both m and b must be constants, and the equation should not have variables with exponents other than 1. Given the options:
A. y = x2 - This equation is not linear because of the exponent on x.
B. −x = y - This can be represented in linear form as y = −x (or y = −0x + 0), hence it is linear.
C. y = 14x2 + 4 - This equation is not linear due to the exponent on x.
D. 6x −3y = 12 - This can be rewritten in linear form as y = 2x - 4, making it a linear equation.
E. y = −2x2 + 1 - This is not linear for the same reason as options A and C.
The equations that represent linear functions from the given options are B and D.
If f(x) = −3x + 4 and g(x) = 2, solve for the value of x for which f(x) = g(x) is true.
x =
Answer: x= 2/3
Step-by-step explanation: For f(x) = g(x) we should equate the two functions to get the value of x.
f(x) = g(x)
−3x + 4 = 2
-3x + 4 - 4 = 2 - 4
-3x = -2
Dividing by -3 on both sides;
(-3x)/-3 = (-2)/-3
x = 2/3
Answer:
[tex]\frac{2}{3}[/tex]
Step-by-step explanation:
If f(x)=g(x), should be : -3x+4= 2
-3x + 4 = 2
-3x = -2
x= -2/-3
x = [tex]\frac{2}{3}[/tex]
Hope this helps ^-^
Suppose you roll a standard number cube and spin a spinner with four equal-sized sections labeled 1, 2, 3, 4. What is the probability you will roll a prime number and spin a prime number
Answer:
25% probability you will roll a prime number and spin a prime number
Step-by-step explanation:
If we have two events, A and B, and they are independent, we have that:
[tex]P(A \cap B) = P(A) \times P(B)[/tex]
In this question:
Event A: Rolling a prime number.
Event B: Spinning a prime number.
Both the cube and the spinner have four values, ranging from one to four.
2 and 3 are prime values, that is, 2 of those values. Then
[tex]P(A) = P(B) = \frac{2}{4} = \frac{1}{2}[/tex]
What is the probability you will roll a prime number and spin a prime number
The cube and the spinner are independent of each other. So
[tex]P(A \cap B) = \frac{1}{2} \times \frac{1}{2} = \frac{1}{4} = 0.25[/tex]
25% probability you will roll a prime number and spin a prime number
Answer:
= 1/4
Step-by-step explanation:
In a cube , we have numbers labeled 1 - 6
the prime numbers we have is 2 , 3 and 5
The probability of selecting a prime number is
[tex]=\frac{3}{6} \\\\=\frac{1}{2}[/tex]
Now this means the probability of rolling a prime number here is 1/2
Now we calculate the probability of spinning a prime number
Prime numbers here are just 2 and 3
The probability of spinning a prime number is thus 2/4 = 1/2
Thus, the probability of rolling a prime number and spinning a prime number also becomes; 1/2 * 1/2
= 1/4