A company issues 7% bonds with a par value of $200,000 at par on January 1. The market rate on the date of issuance was 6%. The bonds pay interest semiannually on January 1 and July 1. The cash paid on July 1 to the bond holder(s) is:

The claim that the ambulance service takes an average of 10 minutes to transport a patient to the hospital is false.

We know that, the confidence interval for any event shows as the interval with lower and upper bounds. Meaning it gives as the mean interval with a maximum and minimum possible values for that interval as well for unknown variables.

[tex]CI = \bar{x} \pm z \dfrac{s}{\sqrt{n}}[/tex]

where,

CI =  confidence interval

[tex]\bar{x}[/tex]      =  sample mean

z =  confidence level value

s =  sample standard deviation

n =  sample size

Similarly, given in sample of 12 transports yielded at 95% confidence interval is 11.8±1.6 minutes.

So, the mean interval is 11.8 minutes, with a lower bound as 10.2 minutes(11.8-1.6) while upper bound as 13.4 minutes(11.8+1.6).

Hence, the claim that the ambulance service takes an average of 10 minutes to transport a patient to the hospital is false.

Learn more about confidence intervals:

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Final answer:

The ambulance service's claim that their average transport time is 10 minutes is plausible since 10 minutes is within the provided 95% confidence interval of 11.8±1.6 minutes.

Explanation:

The question asks if the ambulance service's claim that their average time to transport a patient to the hospital is 10 minutes is plausible based on the provided 95% confidence interval. The confidence interval is given as 11.8±1.6 minutes, which means the interval ranges from 10.2 minutes to 13.4 minutes. Since 10 minutes is within this range, it is plausible that the true average transport time could be 10 minutes, although the intervals suggest that it is on the lower end of the sample's confidence interval.

considering this is a pythagorean theorem question (a^2+b^2=c^2)

then we can plug this in.

40^2+b^2=41^2

1600+b^2=1681 (subtract 1600 from both sides to isolate b)

b^2=81  (square root)

b=9

Answer:

a) Computing the expected value E(XY) gives 1/4

b) The probability density function fZ(z) of Z = XY is calculated in the attached picture.

c) Computing E(Z) gives 1/4

Step-by-step explanation:

Comparing the computation of E(Z) using the answer to b), it shows that the values are equal.

Answer:

[tex]z=\frac{0.0904 -0.1}{\sqrt{\frac{0.1(1-0.1)}{564}}}=-0.760 \approx -0.8[/tex]  

[tex]p_v =2*P(z<-0.760)=0.447[/tex]  

Step-by-step explanation:

Information given

n=564 represent the sample selected

X=51 represent the number of people who rated the overall services as poor

[tex]\hat p=\frac{51}{564}=0.0904[/tex] estimated proportion of people who rated the overall services as poor  

[tex]p_o=0.1[/tex] is the value to compare

z would represent the statistic

Hypothsis to analyze

We want to analyze if the proportion of customers who would rate the overall car rental services as poor is 0.1, so then the system of hypothesis are:  

Null hypothesis:[tex]p=0.1[/tex]  

Alternative hypothesis:[tex]p \neq 0.1[/tex]  

The statistic for a one z test for a proportion is given by:

[tex]z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}[/tex] (1)  

Replacing the info given we got:

[tex]z=\frac{0.0904 -0.1}{\sqrt{\frac{0.1(1-0.1)}{564}}}=-0.760 \approx -0.8[/tex]  

And the p value since we have a bilateral test is given b:

[tex]p_v =2*P(z<-0.760)=0.447[/tex]  

The question is about testing a null hypothesis in a customer satisfaction survey for a software company. The null hypothesis is that 10% of customers would rate the services as poor. The calculated test statistic was approximately -1.3.

The question involves testing a null hypothesis regarding the proportion of customers who would rate the software company's services as poor. We are given that a total of 564 customers took part in the survey, out of which 51 rated the services as poor. Here, the null hypothesis is that 10% (or 0.1) of customers would rate the services as poor.

To test the null hypothesis, we compare the sample proportion to the claimed proportion (0.1). The sample proportion in this case is 51/564 = 0.0904. We can calculate the test statistic using the formula for sample proportion, which is (p' - p) / sqrt [ p * (1 - p) / n ], where p is the claimed proportion, p' is the sample proportion, and n is the sample size. In this case, the test statistic would be approximately (0.0904 - 0.1) / sqrt [0.1 * (1 - 0.1) / 564] = -1.3 (rounded to the first decimal).

The p-value corresponds to the test statistic under the null hypothesis. The smaller the p-value, the stronger the evidence against the null hypothesis. But here, we didn't calculate the p-value as it wasn't part of the question, so we won't make a decision on the null hypothesis.

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Answer:

68.68

Step-by-step explanation:

for an approximate result, multiply the volume value by 1.057

Final answer:

The assumptions and conditions necessary for inference are satisfied, and a 95% confidence interval can be created to estimate the difference in proportions of senior men and women with arthritis. The interval provides a measure of precision, and the results do not suggest that arthritis is more likely to afflict women than men.

Explanation:

a) The assumptions and conditions necessary for inference are satisfied. Random sampling was used to select Americans age 65 and older, which helps ensure representativeness. The sample sizes are also large enough for accurate analysis.

b) To create a 95% confidence interval for the difference in proportions, we can use the formula:
CI = (p1 - p2) ± Z * sqrt((p1(1-p1)/n1) + (p2(1-p2)/n2))

c) The 95% confidence interval indicates that we are 95% confident that the true difference in proportions falls within the given range. It provides a measure of the precision of our estimate.

d) The survey results do not suggest that arthritis is more likely to afflict women than men. The confidence interval encompasses a range of values, indicating that the difference in proportions could be quite small or even favor men.

Yes, it was a random sample less than 10% of the population was sampled the groups were independent, and there were more than 10 successes and failures in each group option(D). The confidence interval for the difference in proportions (p₁ - p₂) is approximately (4.8%, 13.2%) after rounding to three decimal places as needed. The proportion of American women, age 65 and older, who suffer from arthritis is between 4.8% and 13.2% higher than the proportion of American men of the same age who suffer from arthritis. Therefore, arthritis is more likely to afflict women than men.

Yes, the entire interval lies above 0 option(C).

The assumptions and conditions necessary for inference in parts (a), (b), (c), and (d) can be evaluated as follows:

(a) The conditions for inference include:

Given the survey data:

Therefore, the correct answer is D. Yes, it was a random sample less than 10% of the population was sampled the groups were independent, and there were more than 10 successes and failures in each group.

(b) To create a 95% confidence interval for the difference in proportions of senior men and women who have arthritis, we follow these steps:

⇒ p₁ = 532 ÷ 1065 and

⇒ p₂ = 418 ÷ 1019.

⇒ SE = √((p₁(1 - p₁) ÷ n₁) + (p₂(1 - p₂) ÷ n₂))

⇒ ME = Z × SE

= (p₁ - p₂) ± ME

The confidence interval for the difference in proportions (p₁ - p₂) is approximately (4.8%, 13.2%) after rounding to three decimal places as needed.

(c)There is 95% confidence, based on these samples, that the proportion of American women, age 65 and older, who suffer from arthritis is between 4.8% and 13.2% higher than the proportion of American men of the same age who suffer from arthritis.

(d) Since the entire confidence interval lies above 0, it suggests that senior women are more likely to suffer from arthritis. The correct answer is C. Yes, the entire interval lies above 0.

Complete question:

A survey was taken of randomly selected Americans, age 65 and older, which found that 418 of 1019 men and 532 of 1065 women suffered from some form of arthritis.

a) Are the assumptions and conditions necessary for inference satisfied? Explain.

A. No, more than 10% of the population was sampled. ?

B. No, the groups were not independent.  

C. No, it was not a random sample.

D. Yes, it was a random sample less than 10% of the population was sampled the groups were independent, and there were more than 10 successes and failures in each group.

b) Let p₁ be the sample proportion of senior women suffering from some form of arthritis, and let p₂ be the sample proportion of senior men suffering from some form of arthritis. Create a 95% confidence interval for the difference in proportions of senior men and women who have this disease, p₁ - p₂.

The confidence interval is

( Round to three decimal places as needed.)

c) There is 95% confidence, based on these samples, that the proportion of American women, age 65 and older, who suffer from arthritis is between    % and    %  than the proportion of American men of the same age who suffer from arthritis.

(Round to one decimal place as needed.)

d) Does this suggest that arthritis is more likely to afflict women than men? Select the correct answer below and, if necessary, fill in the answer boxes within your choice.

A. No, the interval is too close to 0.

B.  Yes, there is 95% confidence, based on these samples that about   % of senior women suffer from arthritis, while only   % of senior men suffer from arthritis.

(Round to one decimal place as needed.)

C. Yes, the entire interval lies above 0.

D. No, a conclusion cannot be made based on the confidence interval.

Answer:

Step-by-step explanation:

Given that,

v(t) = A + B•sin(ωt)

Then,

When t = 0 v(t)= 7

7 = A + B•Sin(ω×0)

7 = A + B•Sin0

7 = A

Then,

A = 7

v = 7 + B•sin(ωt)

So,

When t = 3, v(t) = 9

v = A + B•sin(ωt)

9 = 7 + B•Sin(3w)

9-7 = B•sin(3ω)

B•sin(3w) = 2. Equation 1

Also, at t = 6 v(t) = 7, at this point, when it returns back to7, it has complete one oscillation

v = A + B•sin(ωt)

7 = 7 + B•Sin(6w)

7-7 = B•sin(6ω)

B•sin(6w) = 0

Sin(6w) = 0 / B

Sin(6w) = 0

Take arcsin of both sides

6w = Sin~1(0)

6w = π, since it has complete one oscillation

Then, w = π /6

w = π/6

Then,

v(t) = 7 + B•Sin(πt/6)

From equation 1

B•sin(3w) = 2.

B•Sin(3 × π/6) = 2

B•Sin(½π) = 2

B = 2

Then,

v(t) = A + B•sin(ωt)

A = 7, B = 2 and w = π/6

v(t) = 7 + 2•sin(πt/6)

Answer:

5n

Step-by-step explanation:

i think

To find the total number of nickels Ri’Hanna and Shania have together, add the number of nickels Ri’Hanna has (n) and the number of nickels Shania has (4n). The simplified expression is 5n.

Ri’Hanna has n nickels, and Shania has 4 times that amount. This could be represented by the expression 4n. To calculate the total number of nickels they have together, you add the amount of nickels Ri’Hanna has (n) and the amount Shania has (4n). So, the expression representing the total nickels is n + 4n. When you add n + 4n, it simplifies to 5n.

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Answer:

1.  

E(down) / Odd(Across)     H                  T

H                                  (1,-1)        (-1,1)

T                                   (-1,1)        (1,-1)

2. Even doesn't have a dominant strategy as both the strategies are providing equal payoffs for pure strategy.

Answer:

explanation

Step-by-step explanation:

The Range (Statistics) The Range is the difference between the lowest and highest values. Example: In {4, 6, 9, 3, 7} the lowest value is 3, and the highest is 9. So the range is 9 − 3 = 6.

Answer:

The range is the difference between the smallest and highest numbers in a list or set. To find the range, first put all the numbers in order. Then subtract (take away) the lowest number from the highest. The answer gives you the range of the list.

Answer:

Check the explanation

Step-by-step explanation:

a)

the formula is given by,

c.v.=[tex]\frac{\sigma}{\mu}\times 100[/tex]

where is standard deviation and is mean of the given data.

b)for asse A,

c.v.= [tex]\frac{\sigma}{\mu}\times 100[/tex] = 0.03 5 , 100 0,30 x 0.30 = 10%

for asse B,

c.v.= [tex]\frac{\sigma}{\mu}\times 100[/tex] = 1.50 x 100 26005 × 100 =8.27 %

for asset C,

c.v.= [tex]\frac{\sigma}{\mu}\times 100[/tex] = 18.70 × 100 =10.71%

c)since, c.v. of asset B is least, it is least volatile and c.v. of asset is most, it is most volatile.

The two equations expressing altitude y as a function of time in seconds x for Cassie and Josiah respectively are: y = 33 + 1.25x and y = 210 - 17.6x.

The subject of this problem is linear equations in algebra. We set up two equations to represent the altitude changes of Cassie and Josiah over time.

Firstly, Cassie is ascending from a base level of 33 feet at a rate of 15 inches per second. However, the rate needs to be converted to feet per second because the initial altitude and the altitude Josiah is descending from are both in feet. So, 15 inches equals 1.25 feet (since 1 foot = 12 inches). Therefore, the altitude y Cassie reaches after x seconds can be represented as y = 33 + 1.25x.

Secondly, Josiah is descending from an altitude of 210 feet at a rate of 17.6 feet per second. Thus, the altitude y reached over x seconds can be given by y = 210 - 17.6x.

The system of equations therefore is:

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Answer:

-28 - 16x

Step-by-step explanation:

7-7(5+x)-9x

Distribute

7 - 35 -7x -9x

Combine like terms

-28 - 16x

Answer:

The null hypothesis is rejected.

There is enough evidence to support the claim that the average age of the customers differs from 40 years.

The sample does not support the manager claim (the average age seems to differ from 40 years).

Step-by-step explanation:

This is a hypothesis test for the population mean.

The manager claims that the average age of customers is 40 years. As this is an equality, we will test if the average age differs from 40. If the null hypothesis failed to be rejected, the claim of the manager is right.

Then, the claim is that the average age of the customers differs from 40 years.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=40\\\\H_a:\mu\neq 40[/tex]

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=38.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=7.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{7}{\sqrt{50}}=0.99[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{38-40}{0.99}=\dfrac{-2}{0.99}=-2.02[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=50-1=49[/tex]

This test is a two-tailed test, with 49 degrees of freedom and t=-2.02, so the P-value for this test is calculated as (using a t-table):

[tex]P-value=2\cdot P(t<-2.02)=0.049[/tex]

As the P-value (0.049) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the average age of the customers differs from 40 years.

Answer:

Is there supposed to be a picture?

Step-by-step explanation:

Answer:

970000

Step-by-step explanation:

Answer:

(x,y) = (-1,4)

Step-by-step explanation:

y = y right? So all you have to do is replace both of the equations.

[tex]-x+3=x+5\\-x-x=5-3\\-2x=2\\x=-1[/tex]

after you've found the value of x just substitute it into ANY of these two equations!

For example if we get the first one we have

[tex]y=-(-1)+3\\y=1+3\\y=4[/tex]

And there you have it. Hope it helps!

Answer: When given a literal equation, you will often be asked to solve the equation for a

given variable. The goal is to isolate that given variable. The process is the same

process that you use to solve linear equations; the only difference is that you will

be working with a lot more letters, and you may not be able to simplify as much as

you can with linear equations. This packet will hopefully show you the process in a

simple manner so that you will be able to solve literal equations yourself.

Step-by-step explanation:

Answer:

The null and alternative hypothesis are:

[tex]H_0: \mu=5\\\\H_a:\mu< 5[/tex]

Test statistic t=-0.256

P-value = 0.4

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that that smartphone​ carrier's data speeds at airports is less than 5 mbps.

Step-by-step explanation:

The question is incomplete:

Sample mean (M): 4.79

Sample STD (s): 5.8

Sample size (n): 50

This is a hypothesis test for the population mean.

The claim is that that smartphone​ carrier's data speeds at airports is less than 5 mbps.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=5\\\\H_a:\mu< 5[/tex]

The significance level is 0.05.

The sample has a size n=50.

The sample mean is M=4.79.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=5.8.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{5.8}{\sqrt{50}}=0.82[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{4.79-5}{0.82}=\dfrac{-0.21}{0.82}=-0.256[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=50-1=49[/tex]

This test is a left-tailed test, with 49 degrees of freedom and t=-0.256, so the P-value for this test is calculated as (using a t-table):

[tex]P-value=P(t<-0.256)=0.4[/tex]

As the P-value (0.4) is bigger than the significance level (0.05), the effect is  not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that that smartphone​ carrier's data speeds at airports is less than 5 mbps.

Answer:

Step-by-step explanation:

I got it right on the test.

Using the arrangements formula, it is found that the 6 possible outcomes for the event are given as follows:

ABC, ACB, BCA, BAC, CAB, CBA.

The number of possible arrangements of n elements is given by the factorial of n, that is:

[tex]A_n = n![/tex]

In this problem, there are three students, hence the number of outcomes in given by:

[tex]A_3 = 3! = 6[/tex]

And the outcomes are as follows:

ABC, ACB, BCA, BAC, CAB, CBA.

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The volume of a square pyramid with base edges of 24 feet and a slant height of 377268 feet is 74,182,973,440 cubic feet.

The volume of a square pyramid can be found using the formula: volume = (1/3) * base area * height. In this case, the base of the pyramid is a square with edges measuring 24 feet, so the base area is

= 24 * 24

= 576 square feet.

The slant height of the pyramid is given as 377268 ft^3, but the units should be in feet, not ft^3, as ft^3 represents volume. Therefore, it is likely a typo.

Assuming the slant height is actually 377268 feet, we can use the Pythagorean theorem to find the height of the pyramid.

The height is given by

[tex]h = \sqrt{(slant height^2 - (base edge/2)^2)[/tex]

[tex]= \sqrt{(377268^2 - (24/2)^2)[/tex]

[tex]= \sqrt{(142288127824 - 144)[/tex]

= 377268 feet.

Now we can calculate the volume using the formula: volume

= (1/3) * 576 * 377268

= 74,182,973,440 cubic feet.

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Answer:

The factor which is used to convert feet per minute into miles per minute is:

                        1 ft per minute=0.000189 miles per minute.

( since,  1 ft.= 0.000189 miles )

Step-by-step explanation:

Answer:

We conclude that the proportion of cell phone users who have received commercial messages or ads in 2004 was greater than the proportion of 0.13 reported for the previous year.

Step-by-step explanation:

We are given that in a poll of 5500 cell phone users, 19% indicated that they had received commercial messages and ads on their cell phones.

We have to test the claim that the proportion of cell phone users who have received commercial messages or ads in 2004 was greater than the proportion of 0.13 reported for the previous year.

Let p = proportion of cell phone users who have received commercial messages or ads in 2004.

So, Null Hypothesis, [tex]H_0[/tex] : p [tex]\leq[/tex] 0.13      {means that the proportion of cell phone users who have received commercial messages or ads in 2004 was smaller than or equal to the proportion of 0.13 reported for the previous year}

Alternate Hypothesis, [tex]H_A[/tex] : p > 0.13      {means that the proportion of cell phone users who have received commercial messages or ads in 2004 was greater than the proportion of 0.13 reported for the previous year}

The test statistics that would be used here One-sample z proportion statistics;

                     T.S. =  [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n}} }[/tex]  ~ N(0,1)

where, [tex]\hat p[/tex] = sample proportion of cell phone users who have received commercial messages or ads in 2004 = 19%

           n = sample of cell phone users = 5500

So, test statistics  =  [tex]\frac{0.19-0.13}{\sqrt{\frac{0.19(1-01.9)}{5500}} }[/tex]

                               =  11.34

The value of z test statistics is 11.34.

Also, P-value of the test statistics is given by;

         P-value = P(Z > 11.34) = 1 - P(Z [tex]\leq[/tex] 11.34)

                                             = 1 - 0.9999 = 0.0001

Now, at 0.05 significance level the z table gives critical value of 1.645 for right-tailed test.

Since our test statistics is way more than the critical value of z as 11.34 > 1.645, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that the proportion of cell phone users who have received commercial messages or ads in 2004 was greater than the proportion of 0.13 reported for the previous year.

Answer:

(A)

Step-by-step explanation:

Given:

P(x) = 1.053(x+0.25x)

P(60) = 1.053(60+0.25*60)

=1.053(60+15)

=1.053(75)

P(60)=$78.98

Since x is the cost from the publisher, when the bookstore spends $60 on a textbook, the student pays $78.98.

The correct option is A.

The price of the book to the student is $78.98 when the bookstore spends $60 on the textbook.

The subject of this question is Mathematics and it is suitable for High School students.

The problem involves calculating the price of a book after a markup and sales tax.

To evaluate P(60), we substitute x = 60 into the given expression P(x) = 1.053(x+0.25x).

P(60) = 1.053(60 + 0.25*60) = 1.053(60 + 15) = 1.053(75) = 78.975.

The bookstore's price to the student would be $78.98 when the bookstore spends $60 on a textbook.

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Answer:

20

Step-by-step explanation:

We can use the Pythagorean theorem to solve

a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse

12^2+16^2 = c^2

144+256 = c^2

400 = c^2

Take the square root of each side

sqrt(400) = sqrt(c^2)

20 = c

Answer:

Adding all the numbers together results in 460

Answer:

460 is the answer

Step-by-step explanation:

Answer:

8.5$

Step-by-step explanation:

85 diveded by 10 is 8.5$.

Answer:

Connor's hourly pay rate is $8.50

Step-by-step explanation:

Think of it as finding the unit rate.

hours : dollars

     10 : 85

       1 : ?

Since you must divide by 10 to get from 10 to 1, you must do the same for the other side, so you do 85 divided by 10.

85 / 10 = 8.5

Therefore, Connor's hourly pay rate is $8.50.

Answer:1

1/6 3/12 2/3

Step-by-step explanation:

3/12 = 2/6

2/3 = 4/6

1/6<2/6<2/3

Answer:

The answer is 3/12 1/6 2/3

Step-by-step explanation:

The reason why is because the denominator is larger than the rest. The larger the denominator the smaller the number. For example: 2/13 is less than 4/6 because the denominator is bigger. Now if it were 6/12 and 1/2 it would be equal since 6 is half of 12. Hope this helped!

Answer:

Check the explanation

Step-by-step explanation:

1.

(a)

n>=m

(b)

n <= m

(c)

n=m

2.

(a)

let T(v1) = T(v2)

=>

T(v1)-T(v2) = 0

=>

T(v1-v2) = 0

=>

v1-v2 = 0 from the hypothesis

=>

v1=v2

=>

T is one-one

thus proved

(b)

lets assume T is onto, we already know that T is one-one, so from above problem (third case where m=n)

we should have 3=4 which is impossible

so T is NOT onto.

3.

we need to find a,b such that

T(a,b) =(a,b)

=>

a= b

=>

points on the line x=y are the required points

Answer:

choice A is the best   2nd degree, trinomial

Step-by-step explanation:

-x^2 +3x - 4

has 3 unique terms which make it a trinomial

The highest degree is 2 since the the highest valued exponent is 2