A chemist prepares an aqueous solution with a volume of 250 mL, containing 4.3 g of KOH. what is the molarity of the solution?

Answer:

D

Explanation:

The reactants are butane gas and oxygen, and the product is carbon dioxide and water VAPOR. The letter beside the water formula means it's a gas.

Final answer:

The correct word equation is that butane gas reacts with oxygen gas to form carbon dioxide gas and water vapor. This is a combustion reaction where the hydrocarbon butane combusts in the presence of oxygen to produce these products.

Explanation:

The correct word equation for the reaction 2C₄H₁₀ (g) + 13O₂ (g) ⇒ 8CO₂ (g) + 10H₂O (g) is D) Butane gas reacts with oxygen gas to form carbon dioxide gas and water vapor.

In this reaction, butane (C₄H₁₀) and oxygen (O₂) are the reactants, while carbon dioxide (CO₂) and water (H₂O) are the products. Since the reaction includes the conversion of gases and no liquids are mentioned in the context of products, we can conclude that the water produced is also in gaseous form which is commonly referred to as water vapor.

A complete combustion reaction always yields carbon dioxide and water as products, assuming ample oxygen is available. If the reaction had incomplete combustion, carbon monoxide (CO) could be present, but this is not indicated in the given equation.

Answer:

50CuS2 + 260HNO3 = 50Cu(NO3)2 + 100H2SO4 + 80N2O + 3H2O

Explanation:

Answer:

a0 = 2

a1= 9

a2= 6

a3= 8

Explanation:

The equation for the reaction is;

C3H7OH + O2 → CO2 + H2O

To balance the chemical equation we introduce coefficients;

Therefore the balanced chemical equation will be;

2C3H7OH + 9O2 → 6CO2 + 8H2O

Chemical equations are balanced to ensure the law of conservation of mass is obeyed, such that the mass of the reactants is equivalent to that of the products.

The problem is a chemistry problem which involves balancing a chemical equation. The given equation (C3H7OH + O2 → CO2 + H2O) can be balanced with coefficients: 1 for C3H7OH, 5 for O2, 3 for CO2, and 4 for H2O resulting in a balanced equation: 1C3H7OH + 5O2 → 3CO2 + 4H2O.

The problem you have presented is a classic chemistry problem involving balancing a chemical equation. In the given equation: a0C3H7OH + a1O2 → a2CO2 + a3H2O, these are the coefficients that will balance the equation: a0 = 1, a1 = 5, a2 = 3 and a3 = 4. This means, the balanced equation would be: 1C3H7OH + 5O2 → 3CO2 + 4H2O. Balancing a chemical equation is a fundamental aspect of stoichiometry in chemistry and is based on the law of conservation of mass.

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Answer:

11.66 L.

Explanation:

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

(V₁n₂) = (V₂n₁).

V₁ = 25.5 L, n₁ = 3.5 mol.

V₂ = ??? L, n₂ = 3.5 mol - 1.9 mol = 1.6 mol.

∴ V₂ = (V₁n₂)/(n₁) = (25.5 L)(1.6 mol)/(3.5 mol) = 11.66 L.

Hello!

A 25.5 liter balloon holding 3.5 moles of carbon dioxide leaks. If we are able to determine that 1.9 moles of carbon dioxide escaped before the container could be sealed, what is the new volume of the container?​

V1 (initial volume) = 25.5 L

n1 (initial number of moles) = 3.5 mol

V2 (final volume) = ? (in L )

Note: there was a leak in the number of moles, so we have:

n2 (final number of moles) = 3.5 mol - 1.9 mol = 1.6 mol

By Avogadro's Law it is known that the volume is directly proportional to the number of gas particles, that is, the larger the number of moles of gas, the greater its volume, on which we have the following relation:

[tex]\boxed{\dfrac{V_1}{n_1} = \dfrac{V_2}{n_2}}[/tex]

We apply the data to the formula, we have:

[tex]\dfrac{V_1}{n_1} = \dfrac{V_2}{n_2}[/tex]

[tex]\dfrac{25.5}{3.5} = \dfrac{V_2}{1.6}[/tex]

multiply the means by the extremes

[tex]3.5*V_2 = 25.5*1.6[/tex]

[tex]3.5\:V_2 = 40.8[/tex]

[tex]V_2 = \dfrac{40.8}{3.5}[/tex]

[tex]V_2 = 11.657... \to \boxed{\boxed{V_2 \approx 11.66\:L}}\:\:\:\:\:\:\bf\green{\checkmark}[/tex]

Answer:

The new volume of the container is approximately 11.66 liters

________________________

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Answer:

1. Heat capacity is the ratio of the amount of heat energy transferred to an object to the resulting increase in its temperature.

2. Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass.

3. The gold will warm by ten degrees first because it needs a low amount of heat (12.9 J) while Aluminium needs (90.3 J).

4. The 20 gram piece of aluminum will warm first.

Explanation:

1. What is heat capacity?

Heat capacity is the ratio of the amount of heat energy transferred to an object to the resulting increase in its temperature.

2. What is specific heat?

Specific heat capacity is the amount of heat energy required to raise the temperature of a substance per unit of mass.

3. You have a 10 gram piece of aluminum and a 10 gram piece of gold sitting in the sun. Which metal will warm by ten degrees first?

Q = m.c.ΔT.

where, Q is the amount of heat absorbed by Aluminium or gold (Q = ??? J),

m is the mass of Aluminium or gold (m = 10.0 g),

c is the specific heat capacity of Aluminium or gold (c of Al = 0.902 J/g °C, c of Au = 0.129 J/g °C),

ΔT is the temperature difference (final T - initial T) (ΔT = 10.0°C).

So, the gold will warm by ten degrees first because it needs a low amount of heat (12.9 J) while Aluminium needs (90.3 J).

4. You have a 20 gram piece of aluminum and a 40 gram piece of aluminum sitting in the sun. Which piece will warm by ten degrees first?

∵ Q ∝ m.

∴ The piece of higher mass (40 g) will needs a heat larger twice than that needed to warm the (20 g) piece.

So, the 20 gram piece of aluminum will warm first.

Heat capacity is the amount of heat energy necessary to change the temperature of a substance, while specific heat is similar but normalized to the mass of the substance. Therefore, substances with higher specific heat heat up more quickly. Aluminum has a higher specific heat than gold, so it will heat up more quickly when exposed to the sun.

Heat capacity is the amount of heat energy required to raise the temperature of a substance by a given amount. It's measured in joules per degree Celsius (J/°C).

On the other hand, specific heat refers to the amount of heat energy required to raise the temperature of a specific quantity (typically 1 gram or 1 kilogram) of a substance by one degree Celsius. It's a characteristic property of a substance, and its units are usually Joules per gram degree Celsius (J/g°C).

Regarding the two 10 gram pieces of aluminium and gold sitting in the sun, aluminium will heat up faster. This is because aluminium has a higher specific heat compared to gold, meaning it requires less energy to increase its temperature.

For the 20 gram and 40 gram pieces of aluminium, the 20 gram piece will warm faster by ten degrees given that it has less mass and therefore needs less energy to increase its temperature.

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Every half-life, we end up with half of the material we started with. At the beginning, we have all of the material, which we can represent with the number 1. After one half-life, we have 1 • 1/2 = 1/2 left.

After two: 1/2 • 1/2 = 1/4

Three: 1/4 • 1/2 = 1/8

Four: 1/8 • 1/2 = 1/16

And five: 1/16 • 1/2 = 1/32.

In general, after n half-lives, we’ll have 1/(2^n) of the material left over.

Answer:

The correct answer is :1 by 32 of the original sample

Explanation:

Formula used :

[tex]A=\frac{A_o}{2^n}[/tex]

where,

A = amount of reactant left after n-half lives = ?

[tex]A_o[/tex] = Initial amount of the reactant = 100 g

n = number of half lives

If five half-lives have occurred.

[tex]A=\frac{A_o}{2^5}[/tex]

[tex]A=\frac{A_o}{32}[/tex]

Hence, the correct answer is :1 by 32 of the original sample

Answer:

[tex]\boxed{\text{donate electrons}}[/tex]

Explanation:

An atom with one to three valence electrons would have to gain seven to five valence electrons, respectively to get a stable octet.

It is easier for it to donate electrons and expose the stable octet of electrons in the shell below..

(A) is wrong. You can't move electrons to a lower shell, because it's already full.

(B) is wrong. The atom will donate electrons.

(C) is wrong. Moving electrons to a higher shell will make the atom more unstable.

Answer:

A reaction is spontaneous if ΔG is negative.

Explanation:

If ΔG is negative, the reaction is spontaneous.

If ΔG = zero, the reaction is at equilibrium.

If ΔG is positive, the reaction is non-spontaneous.

Solution is here,

for initial case,

temperature(T1)=70°C=70+ 273=343K

vloume( V1) =45 L

for final case,

temperature( T2)=?

volume(V2)= 91.3 L

at constant pressure,

V1/V2 = T1/T2

or, 45/91.3 = 343/ T2

or, T2= (343×91.3)/45

or, T2=695.9 K = (695.9-273)°C=422.9°C

The temperature needed for a sample of gas to occupy 91.3 L, when originally it occupied 45.0 L at 70.0°C at constant pressure, is about 423.71°C.

This question pertains to the ideal gas law equation (P1V1/T1 = P2V2/T2, where P is pressure, V is volume, and T is temperature), we must first convert our temperatures to Kelvin (K) since the ideal gas law uses absolute temperature. To convert from degrees Celsius to K, add 273.15, thus 70.0°C becomes 343.15K. As the problem states pressure is constant, we can ignore that component of the equation and it simplifies to V1/T1 = V2/T2.

By rearranging the equation to solve for V2, we get V2 = V1 (T2/T1). Given the volume of the gas at the initial temperature (V1 = 45.0 L), and temperature T2 with unknown value, we rewrite the equation as T2 = (V2 * T1) / V1. Substituting the given values into the equation gives T2 = (91.3 L * 343.15K) / 45.0 L, which calculates to approximately 696.86K, converting back to Celsius gives us around 423.71°C.

So, your sample of gas would need to be heated to approximately 423.71°C in order for it to occupy a volume of 91.3 L at constant pressure.

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Final answer:

The speed of light waves can decrease when they pass from a faster medium to a slower medium, which happens when moving from a solid to a gas, a liquid to a gas, a gas to a liquid, or a solid to a liquid.

Explanation:

The speed of light waves can change when they pass from one medium to another. Generally, the speed of light waves decreases when they move from a faster medium to a slower medium. Based on this, the changes in the medium that will likely cause the speed of light waves to decrease are:

It is the first one that's correct...

Science is characterized by asking questions about the natural world. It involves a methodical process of observation, hypothesizing, experimentation and conclusion. Science does not use opinions to make conclusions but relies on systematic observation, experimentation and testing to ascertain facts.

A characteristic of science is that it asks questions about the natural world. This process is often initiated by observation, leading scientists to generate questions they wish to answer. Science employs systematic methods for observing the universe, forming theories and testing hypotheses to understand how the world operates.

In essence, science seeks to discover and describe the underlying order within nature. It's through the rigorous processes of observation, hypothesis formulation, experimentation, and conclusion that science separates facts from opinion, aiming to describe the universe accurately as it is and not as imagined or wished.

This investigative approach isn't conducted by single individuals; it's a collaborative endeavor involving many scientists. Most importantly, science does not use opinions to draw conclusions. Rather, it bases conclusions on evidence and facts gathered systematically through experiments, observations, and testing.

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Answer:

your answer is B:  Hydrogen sulphide

Explanation:

Answer:

Cao,NaNo3,Nacl sucrose and cuo

Explanation:

Hygroscopic substances attract water from their surroundings with examples including saltwater, soap, and toothpaste, while deliquescent substances, such as KOH and CaCl₂, can absorb enough water to dissolve. Hygroscopic materials contain bound water, which is tough to remove and can cause shrinkage upon removal.

Hygroscopic substances are those that readily attract and absorb water from their surroundings. Examples include saltwater, soap, toothpaste, bleach, cleaning agents, limewater, and ammonia water. Deliquescent substances are a subset of hygroscopic materials but are so good at absorbing water that they can dissolve in the absorbed water and form a solution. Substances like potassium hydroxide (KOH) and calcium chloride (CaCl₂) are examples of deliquescent materials.

A hygroscopic material consists of all three phases: gas, liquid water, and solid, and it contains bound water, which is strongly bonded to the material and difficult to remove. In contrast to this bound water, free water can be removed through methods such as capillary diffusion and convection flow. When bound water is removed by drying or frying, hygroscopic materials often shrink.

From the information provided in question, the metal is copper.

The specific heat capacity of a substance is an intrinsic property. It can be used to identify a substance. Intrinsic properties are characteristic of substances. From the information provided, we can obtain the specific heat capacity of the metal.

Using;

H = mcdT

Where;

H = Heat absorbed

m = mass of the metal

c = specific heat capacity of the metal

dT = temperature change

20 J = 0.0052 Kg × c × ( 40.0°C - 30.0°C)

c = 20 J/0.0052 Kg × ( 40.0°C - 30.0°C)

c = 385 JKg-1°C-1

The metal is copper.

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Answer:

A. because the wood is stored chemical energy and it is converting into heat energy

Answer:

Chemical potential energy converting to heat energy.

Explanation:

Burning of wood in a fire place or burning of any other compound in presence of oxygen involves combustion. During combustion there is breaking and making of bonds as combustion is a chemical reaction.

For example:

Combustion of carbon gives carbon dixoide:

[tex]C(s)+O_{2}(g)-->CO_{2}(g)[/tex]

Combustion is an exothermic reaction, it releases large amount of energy.

Thus in all we are converting the chemical energy of a substance to heat energy during combustion.

Hence combustion involves Chemical potential energy converting to heat energy.

Diffraction is the bending of a wave around the edges of an opening or obstacle. Examples of diffraction include Young's double-slit experiment, where light passing through two slits produces a diffraction pattern, and waves diffracted off crystal planes according to the Bragg equation, resulting in constructive or destructive interference.

Diffraction is best described as a wave characteristic. It refers to the bending of a wave around the edges of an opening or an obstacle. This phenomenon is observed for all types of waves. When we pass light through smaller openings or slits, for instance, we observe that light behaves as a wave and bends just like sound does in a similar situation.

One example of such an occurrence is Young's double-slit experiment wherein light of a single wavelength passes through a pair of slits. As a result, we observe a diffraction pattern consisting of numerous vertical light and dark lines spreading out exponentially. In simple terms, if there were no diffraction or interference, the light would merely produce two direct lines on the screen.

Another example as illustrated in figure 10.64 is a phenomenon described by the Bragg equation. This refers to waves being diffracted off two different crystal planes at the Bragg angle resulting in constructive interference, or at a different angle causing destructive interference.

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Among the given options, the rainbow patterns found on a CD (Option D) are an example of diffraction, demonstrating the interference and bending of light waves as they interact with the grooves on the CD's surface.

Diffraction is a phenomenon related to the bending of waves as they encounter obstacles or pass through small openings. Among the options provided:

A. The blue color of the sky is primarily a result of Rayleigh scattering, not diffraction. Rayleigh scattering occurs when sunlight interacts with molecules and small particles in the Earth's atmosphere, causing shorter wavelengths (like blue) to scatter more than longer wavelengths.

B. The twinkling of the stars is caused by atmospheric turbulence, leading to changes in the refractive index of air. While this phenomenon is related to light passing through varying atmospheric conditions, it is not a direct example of diffraction.

C. The Tyndall effect is the scattering of light by colloidal particles in a transparent medium, making the beam of light visible. This effect is more associated with scattering than diffraction.

D. Rainbow patterns found on a CD are indeed an example of diffraction. The microscopic grooves on the surface of a CD act as a diffraction grating, causing the incident light to diffract into its spectral components, creating the colorful patterns observed.

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The question probable may be:

Which of the following is an example of diffraction  

A.  The blue color of the sky

B. the twinkling of the stars

C. the tyndall effect

D. rainbow patterns found on a CD

Answer:

1. The amount required of H₂ = 11.0 g.

2. The amount required of O₂ = 88.0 g.

Explanation:

2H₂(g) + O₂(g) → 2H₂O,

It is clear that 2.0 moles of H₂ react with 1.0 mole of O₂ to produce 2.0 moles of H₂O.

Q1: How much hydrogen would be required to produce 5.5 mol of water?

Using cross multiplication:

2.0 mol of H₂ produce → 2.0 mol of H₂O, from stichiometry.

??? mol of H₂ produce → 5.5 mol of H₂O.

∴ the no. of moles of H₂ needed to produce 5.5 mol of water = (2.0 mol)(5.5 mol)/(2.0 mol) = 5.5 mol.

mass of H₂ = (no. of moles)(molar mass) = (5.5 mol)(2.0 g/mol) = 11.0 g.

Q2: How much oxygen would be required?

Using cross multiplication:

1.0 mol of O₂ produce → 2.0 mol of H₂O, from stichiometry.

??? mol of O₂ produce → 5.5 mol of H₂O.

∴ the no. of moles of O₂ needed to produce 5.5 mol of water = (1.0 mol)(5.5 mol)/(2.0 mol) = 2.75 mol.

mass of O₂ = (no. of moles)(molar mass) = (2.75 mol)(32.0 g/mol) = 88.0 g.

2H₂(g) + O₂(g) → 2H₂O

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 2 moles of H₂ and 1 mole of O₂

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 2 moles of H₂

Therefore,

5.5 moles of H₂O will also be produced from the reaction of 5.5 moles of H₂

Thus, 5.5 moles of H₂ is needed for the reaction

From the balanced equation above,

2 moles of H₂O were produced from the reaction of 1 mole of O₂

Therefore,

5.5 moles of H₂O will be produced from = 5.5 / 2 = 2.75 moles of O₂

Thus, 2.75 moles of O₂ is needed for the reaction

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This is filler, the answer is in the image.

Answer: I think it is HPDE.

Answer:

Copper and aluminium nitrate

Explanation:

The reaction is a simple redox reaction. Where copper ions are reduced to copper atoms and the aluminium atoms oxidized to aluminium ions.

The equation for the reaction is as follows:

2Al₍s₎ + 3Cu(NO₃)₂₍aq₎ ⇒ 2Al(NO₃)₃ + 3Cu₍s₎

The ionic equation:

2Al₍s₎ + 3Cu²⁺₍aq₎⇒2Al³⁺₍aq₎ + 3Cu₍s₎

Answer:

copper and aluminum nitrate

Explanation:

Aluminum is more reactive than copper. So, aluminum will replace copper in the nitrate compound, and pure copper will be produced.

The names of the organic compounds are.

CH- (methyl radical)

CH2 (methylene)

Organic compounds are molecules that contain carbon atoms bonded to other atoms, typically hydrogen, oxygen, nitrogen, sulfur, or halogens. These compounds form the basis of life on Earth and are essential to many biological processes. They are also widely used in industry and technology, including in the production of plastics, fuels, medicines, and many other materials.

Organic compounds can be categorized into different functional groups based on the type of atom or group of atoms bonded to the carbon backbone. These functional groups determine the chemical and physical properties of the compound, such as its reactivity, solubility, and melting point. Some common functional groups include alkanes, alkenes, alkynes, alcohols, ethers, amines, carboxylic acids, esters, and amides.

The names of the organic compounds are.

CH- (methyl radical)

CH2 (methylene)

CH (methylidyne)

CH (methylidyne)

HC- (carbene)

-CH- (methylene bridge)

CH (methylidyne)

CH (methylidyne)

CH (methylidyne)

CH (methylidyne)

CH, JCH-CH2-CH-SCH (mixture of methylidyne and other functional groups)

CH3CH-CH (1-butene)

3-ethyl-4-methylheptane

2,3,5-trimethylheptane

2-methylpropane

H€¢¢¢-H (a molecule of hydrogen gas)

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The examples provided contain different types of organic compounds. The first compound is named as 3-ethyl-2,2-dimethylheptane. The second compound is named as propene, and the third compound is named as 2-pentene. These names follow the IUPAC nomenclature rules for alkanes and alkenes.

The longest chain has seven C atoms, so we name this molecule as a heptane. We find two one-carbon substituents on the second C atom and a two-carbon substituent on the third C atom. So this molecule is named 3-ethyl-2,2-dimethylheptane.

Here are some basic rules for naming alkenes from the International Union of Pure and Applied Chemistry (IUPAC):

Answer:

Empirical Observation, Replicable Experiments, Provisional Results, Objective Approach, and Systematic Observation.

Answer:

Reliable science refers to the approximate result that is obtained after conducting various methods for the same experiment. All scientific results are based on the evidences that are obtained by conducting experiments. This derived value confirms the accuracy of the result. The more similar the result obtained by approaching various scientific methods in a particular experiment, the more is the reliability. A reliable scientific experiment shows a minimum error.

Reliable science includes an experiment with proper observation, careful reading, gathering the proper information and modeling with a justifying conclusion.

A pH is an easy way to describe the acidity of a solution (determined by the [H+] concentration) - it’s easier to say that a cup of coffee has a pH of 5 rather than saying that the “hydrogen ion concentration is 10^-5 molar”.

The way pHs work is through logarithms, which convert a set of values into a new one using a base value. For example, pHs use a base 10 to simplify the numbers, while earthquake energy scales use a base of 32. An increase of 1 on the logarithmic scale is an “n” times increase in the scale, where “n” is the base of the logarithm. So, for example, in the case of pH, three solutions with a pH of 5, 6, and 7 can be related; the pH scale uses base ten, so the pH 6 solution is 10x more acidic than the pH 7, and the pH 5 is 100x (10x10) more acidic than the pH 7. For earthquakes, a magnitude 5 earthquake is 32x weaker than a magnitude 6 and 1,024x (32x32) weaker than a magnitude 7.

The pH formula looks like this:

pH = -log [H+]

The negative sign basically serves to make the low end acidic; without the negative, a pH of 14 would be extremely acidic instead of basic. It’s one of those things that you’ll just have to remember.

So, for your solution, just enter the concentration into the formula:

pH=-log[1.0 x 10^-4] = 4

The pH of this solution would be 4.

Hope this helps!

The gas particles squeeze closer together

B) the gas particles squeeze closer together.

Answer: Acceleration can be defined as the rate at which velocity changes

Acceleration has the units m/s2.

Hope this helps! :D

Hello There!

"ACCELERATION" can be defined as the rate at which velocity changes

The energy change of the system was calculated using the formula q = mcΔT. After finding the energy change per gram of water, it was converted to energy change per mole of solute giving the heat of the solution, ΔH = -8.0 kJ/mol.

The energy change in a system is given by the formula: q = mcΔT, where m is the mass of the system, c is the specific heat capacity and ΔT is the change in temperature.

We are given that the temperature decreases so the reaction is endothermic (heat is absorbed) and we use a positive q. The mass of the water is 100g, c for water is 4.18 J/g°C, and ΔT = Final temp - Initial temp = 21.56°C - 25.00°C = -3.44°C.

So, q for water = (100g)*(4.18 J/g°C)*(-3.44°C) = -1438.72 J. We want the answer per mol NaNO3 so we get the molar mass of NaNO3= 85 g/mol. So 15.3 g is 15.3 g ÷ 85 g/mol = 0.18 mol NaNO3.

Finally, q for the solution = q for water ÷ moles of solute = -1438.72 J ÷ 0.18 mol = -7993.7 J/mol. This is the heat of solution in J the question asks for the answer in kJ so we convert, ΔH = -8.0 kJ/mol.

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To calculate Delta H for a solution in a calorimeter, utilize the formula for specific heat capacity, and then calculate the change in enthalpy on basis of moles of solute and heat energy extracted. This example uses nano3 as the solute in a water solution and measures the corresponding decrease in temperature.

The process of calculating Delta H involves using the formula for specific heat capacity Q = mcΔt, which is heat energy equals mass times specific heat capacity times change in temperature. The change in enthalpy, or Delta H, is then -Q divided by the number of moles of the solute, which in this case is nano3. With the given values, we can use the specific heat capacity of water (4.184 J/g°C), the mass of water (100g), and the change in temperature (25.00°C to 21.56°C). Performing necessary calculations, we finally find the value of Delta H for this solution process.

Specific heat capacity, change in enthalpy (Delta H), and moles of solute are the principal factors in determining the behavior of this solution in the calorimeter.

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Answer:

It is the Avogadro's Law that should be used  to determine the relationship between the volume and the number of moles in the equation. This law relates the volume and the the amount in moles of a gas.

that should be used  to determine the relationship between the volume and the number of moles in the equation. This law relates the volume and the the amount in moles of a gas.

Answer:

Volume = lwh

Explanation:

Answer:

The right choice is  V₂ = 195.7 L

Explanation:

where, P is the pressure of the gas in atm.

V: is the volume of the gas in L.

n: is the no. of moles of the gas in mol.

R:  is the general gas constant,

T: is the temperature of the gas in K.

If n is constant, and have different values of P, V and T:

(P₁*V₁) / T₁ = (P₂ * V₂) / T₂

Knowing that:  

V₁  =  225 L  ,         P₁ = 0.940 atm

T₁ = 25  °C + 273  =  298 K

V₂  =  ??? L,           P₂ = 0.990 atm  

T₂ = 0 °C + 273  =  273 K

applying in the above equation

(P ₁* V₁) / T₁ = (P₂ * V₂) / T₂

(0.940 atm * 225 L) / 298 K= (0.990 atm  * V₂) / 273 K

V₂ = (0.940 atm * 225 L * 273 K) / (298 K * 0.990 atm)

V₂ = 195.7 L

So, the right choice is:

V₂ = 195.7 L

By applying the combined gas law, the new volume of the air-filled balloon, considering changes in pressure and temperature, is approximately 188.2 L.

Given:

V1 = 225 L

P1 = 0.940 atm

T1 = 25 °C

P2 = 0.990 atm

T2 = 0 °C

To find: V2

We can use the combined gas law to solve this problem:

P1V1 / T1 = P2V2 / T2, where P1, V1, and T1 are the initial pressure, volume, and temperature, respectively, and P2, V2, and T2 are the final pressure, volume, and temperature, respectively.

Rearranging the equation to solve for V2, we get:

V2 = V1 × (P1 / P2) × (T2 / T1)

Plugging in the given values, we get:

V2 = 225 L × (0.940 atm / 0.990 atm) × (273 K / 298 K)

V2 = 188.2 L

So, the new volume of the balloon is indeed 188.2 liters.

Answer: For Number #1)

The solution above is an acidic solution  

Kw= {H+}*{OH^-}

[OH^-] =Kw/[H+]

OH^-= 1.0*10^14/ 1.0*10^-4  

=1.0*10^4

Answer:

1) [OH-] = 1*10⁻¹⁰ mol/L

Solution is Acidic

2) V = 14.4 L

3) q = -26125 J

4) Concentration of NaCl = 2.59 M

Explanation:

1) Given:

[H+] = 1*10⁻⁴ mol/L

Formula:

[tex][H+][OH-] = 10^{-14} \\[/tex]

[tex][OH-] = \frac{10^{-14} }{10^{-4} } \\\\[OH-] = 1*10^{-10} mol/L[/tex]

[tex]p[H] = -log[H+] = -log[10^{-4} ] = 4[/tex]

Since pH < 7, the solution is acidic

2) Given:

Initial conditions:

Pressure, P1 = 1 atm

Temperature, T1 = 273 K

Volume, V1 = 10.0 L

Final conditions:

Pressure, P2 = 2.0 atm

Temperature, T2 = 512+273 = 785 K

Volume, V2 = ?

Formula:

[tex]\frac{P1V1}{T1} = \frac{P2V2}{T2} \\\\V2 = \frac{P1V1}{T1} * \frac{T2}{P2} \\\\V2 = \frac{1*10.0}{273} * \frac{785}{2} = 14.4 L[/tex]

3) Given:

Volume of tea = 250 ml

Initial temp T1 = 375 K

Final temp, T2 = 350 K

Formula:

Energy transferred, q = mcΔT = mc(T2-T1)

m = mass of tea (water) = density * volume = 1 g/ml * 250 ml = 250 g

c = specific heat of tea (water) = 4.18 J/ gK

ΔT = T2-T1 = 350-375 = -25 K

q = 250*4.18*(-25) = -26125 J

4) Given:

Volume of sea water = 0.500 L

Mass of NaCl = 75 g

Molar mass of NaCl = 58 g/mol

Formula:

[tex]Molarity = \frac{Moles \ NaCl}{Volume\ of\ solution} \\\\Moles\ NaCl = \frac{mass}{molar\ mass} = \frac{75}{58} =1.293\\\\Molarity = \frac{1.293}{0.500} =2.59 M[/tex]

Answer:

b. Drainage basin

Explanation:

Answer:

rate = k[A]

Explanation:

The equation that relate reaction rate with reactant concentrations is known as the rate law.

for a reaction:

the rate law can be expressed as:  

The proportionality constant, k, is known as the rate constant, the powers a and b is the reaction order with respect to reactants A and B, respectively.

for this reaction doubling the concentration of A doubles the reaction rate that means

Rate₂ = 2 *Rate₁     and     [A]₂ = 2 [A]₁

Dividing eq. 2 by eq. 1 one can get

using

∴ (2 Rate₁ / Rate₁) = ( k [2]ᵃ[B]ᵇ) / (k[1]ᵃ[B]ᵇ)

∴ order of reaction with respect to A is first (=1)        →     (1)

Doubling the concentration of B does not affect the reaction rate.

that means

Rate₂ = Rate₁     and     [B]₂ = 2 [B]₁

Dividing eq. 2 by eq. 1 one can get

using

∴ (Rate₁ / Rate₁) = ( k [A]ᵃ[2]ᵇ) / (k[A]ᵃ[1]ᵇ)

∴ order of reaction with respect to B is zero         →     (2)

So, from 1 and 2  the right choice is rate = k[A]¹[B]⁰= k[A]