A car traveling at a steady 20 m/s rounds an 80-m radius horizontal unbanked curve with the tires on the verge of slipping. what is the maximum speed with which this car can round a second unbanked curve of radius 320 m if the coefficient of static friction between the car's tires and the road surface is the same in both cases?
Answers
r = the radius of the curve
m = the mass of the car
μ = the coefficient of kinetic friction
N = normal reaction
When rounding the curve, the centripetal acceleration is
[tex]a = \frac{v^{2}}{r} [/tex]
The inertial force tending to make the car skid is balanced by the frictional force, therefore
[tex]\mu mg = m \frac{v^{2}}{r} \\ \mu = \frac{v^{2}}{rg} [/tex]
When r = 80 m and v = 20 m/s, obtain
[tex]\mu = \frac{(20 m/s)^{2}}{(80 \, m)*(9.8 \, m/s^{2})} = 0.51[/tex]
When r = 320 m and μ remains the same, obtain
[tex] \frac{(v \, m/s)^{2}}{(320 \, m)*(9.8 \, m/s^{2})} =0.51 \\\\ v^{2} = 1.6 \times 10^{3} \\\\ v = 40 \, m/s[/tex]
Answer: 40 m/s
The maximum speed with which this car can round a second unbanked curve is 40 m/s
[tex]\texttt{ }[/tex]
Further explanationCentripetal Acceleration can be formulated as follows:
[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]
a = Centripetal Acceleration ( m/s² )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
[tex]\texttt{ }[/tex]
Centripetal Force can be formulated as follows:
[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]
F = Centripetal Force ( m/s² )
m = mass of Particle ( kg )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
initial speed of the car = v₁ = 20 m/s
radius of first curve = R₁ = 80 m
radius of second curve = R₂ = 320 m
Asked:
final speed of the car = v₂ = ?
Solution:
Firstly , we will derive the formula to calculate the maximum speed of the car:
[tex]\Sigma F = ma[/tex]
[tex]f = m \frac{v^2}{R}[/tex]
[tex]\mu N = m \frac{v^2}{R}[/tex]
[tex]\mu m g = m \frac{v^2}{R}[/tex]
[tex]\mu g = \frac{v^2}{R}[/tex]
[tex]v^2 = \mu g R[/tex]
[tex]\boxed {v = \sqrt { \mu g R } }[/tex]
[tex]\texttt{ }[/tex]
Next , we will compare the maximum speed of the car on the first curve and on the second curve:
[tex]v_1 : v_2 = \sqrt { \mu g R_1 } : \sqrt { \mu g R_2 }[/tex]
[tex]v_1 : v_2 = \sqrt { R_1 } : \sqrt { R_2 }[/tex]
[tex]20 : v_2 = \sqrt { 80 } : \sqrt { 320 }[/tex]
[tex]20 : v_2 = 1 : 2[/tex]
[tex]v_2 = 2(20)[/tex]
[tex]\boxed {v_2 = 40 \texttt{ m/s}}[/tex]
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Circular Motion
Related Questions
The greatest biodiversity on earth is found in the __________ biome.
A) taiga
B) grasslands
C) deciduous forest
D) tropical rainforest
Answers
The greatest biodiversity on earth is found in the tropical rainforest biome.
Explanation:Biome is actually another name for ecosystem. Rainforests are basically the wettest ecosystems and very diverse due to some reasons such as very high annual rainfall, high average temperatures, nutrient-poor soil, and high levels of biodiversity. Biomes or ecosystems are characterized by their climate and on that basis we can find which type of animals and plants can be found there. The greatest biodiversity on earth is found in the tropical rainforest biome.
The greatest biodiversity on earth is found in the tropical rainforest biome. Hence, option D is correct.
Biodiversity or biological diversity is the measure of variation at the species, genetic, and ecosystem levels. It comprises all the different kinds of life and supports life on Earth.
Biodiversity is important because it supports the entire life on the Earth including plants, animals, microorganisms, etc. Without biodiversity, a healthy ecosystem is not possible. Biome is called an ecosystem. Rainforest has the wettest ecosystems and has a higher annual rainfall and nutrient-rich soil.
The greatest biodiversity on earth is found in the tropical rainforests biome and hence, the ideal solution is option D.
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This is one of the three main types of rocks one in which fossils are frequently found
Answers
Primary action of the deltoid- 61)
Primary action of the adductor muscles 62)
Primary action of the erector spinae 63)
Primary action of the rectus abdomini
OPTIONs
A) pronation
B) rotation
C) dorsiflexion
D) flexion
E) adduction
F) circumduction
G) abduction
H) supination
I) extension
Answers
61. Deltoid muscle is the muscle that is located at the rounded contour of the shoulder. The muscle is made up of three different type of fibers, which are anterior, middle and posterior fibers. The anterior deltoid connects the collar bone to the humerus.
The primary function of the anterior fibers is flexion and medial rotation of the arm. The primary function of the middle fibers is abduction of arm and the primary function of the posterior fiber is the extension and lateral rotation of the arm.
62. Adductor muscles are muscles that draw a part of the body towards its median line or towards the axis of an extremity. These muscles can be found in the thigh, foot and hand. The abductor muscles is made up of the following muscles:
a. Adductor brevis: its primary function is the adduction of thigh at the hip joint. It also assist in flexion and medial rotation of the femur at the hip joint.
b. Adductor longus: its primary function is the adduction of thigh at the hip joint. It assist also in flexion and medial rotation of the femur at the hip joint.
c. Adductor magnus: its primary function is the adduction of the thigh. It assists in lateral rotation of the thigh.
d. Gracillis muscle: its primary function is adduction of the thigh. It also assists in flexion of the knee and medial rotation of the flexed knee.
e. Pectineus muscle: Primary function is adduction of thigh. Assists in flexion of thigh.
63. Erector spinae muscles are bundles of paired muscles and tendons which extend through the thoracic, lumbar and the cervical region. These muscles are divided into three groups, which are:
a. Spinallis muscles: primary function is the extension of the head. Also rotate the head.
b. Longissimmus muscles: primary function is extension of the spine. Assist in lateral flexion of the spine.
c. Lliocostalis muscles: primary function is extension of the spine. Assist in lateral flexion of the spine.
64. Rectus abdomini is the paired muscle, which runs vertically on each side of the anterior wall of human abdomen. The muscle is made up of two parralle muscles which are separated by connective tissues. The primary function of the muscle is flexion of the vertebra column. Assists in compression of abdominal wall.
A 5-cm-external-diameter, 10-m-long hot-water pipe at 80°c loses heat to the surrounding air at 16°c by natural convection with a heat transfer coefficient of 25 w/m2·k. determine the rate of heat loss from the pipe by natural convection.
Answers
The rate of heat loss from a hot-water pipe by natural convection is calculated using the formula Q = h * A * ΔT. After plugging in the given values and conducting the appropriate calculations, the rate of heat loss turns out to be 2512 W.
Explanation:Let's determine the rate of heat loss from a hot-water pipe by natural convection. The formula to calculate the rate of heat loss though natural convection is: Q = h * A * ΔT, where:
Q is the rate of heat transfer h is the heat transfer coefficient, which in this case is 25 w/m2·k A is the surface area of the pipe, which we can calculate using A = π * d * l, where d is the diameter and l is the length of the pipe ΔT is the difference between the temperatures of the pipe and the surrounding air, which in this case is 80°c - 16°c = 64°c
Let's plug the numbers in:
First calculate the surface area, A = π * 0.05 m * 10 m = 1.57 m2. Then, to find Q, we use the formula Q = 25 w/m2·k * 1.57 m2 * 64 K = 2512 W. Therefore, the rate of heat loss from the pipe by natural convection is 2512 W.
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The rate of heat loss from the pipe by natural convection is 2512 W.
To determine the rate of heat loss from a hot-water pipe, we can use the formula :
Q = h ×A×ΔT
Where:
Q is the rate of heat transfer (W)h is the convective heat transfer coefficient (W/m²·K)A is the surface area (m²)ΔT is the temperature difference between the pipe surface and the surrounding air (K or °C)First, we calculate the surface area of the pipe:
The external diameter of the pipe is given as 0.05 m, and the length is 10 m. The surface area of a pipe is :
A = π ×D×L
Substituting the values:
A = π × 0.05 m × 10 m = 1.57 m²
Next, we calculating the temperature difference:
ΔT = T(pipe) - T(air) = 80°C - 16°C = 64°C
Finally, using heat transfer formula:
Q = h×A×ΔT = 25 W/m²·K × 1.57 m² × 64 = 2512 W
The rate of heat loss from the pipe by natural convection is 2512 W.
in the 1960s what dance was being created in the west coast
Answers
In the 1960s, the West Coast saw the rise of Surf Rock, a dance style associated with the beach culture and the Black Arts Movement which promoted a blend of traditional and contemporary African American dance styles.
Explanation:In the 1960s, on the West Coast, particularly in California, a new dance style known as Surf Rock emerged. This musical and dance movement was a product of the beach culture prevalent there. Bands like the Kingsmen and the Ventures popularized this genre, and the music often emphasized guitar riffs and had less focus on the lyrics, a shift influenced by the noisy dance halls where the bands performed. The dance associated with Surf Rock was an energetic response to the instrumental tunes and was part of the broader youth culture's expression at the time.
While Surf Rock mainly dominated, there were also important contributions to dance from African American communities. The Black Arts Movement arose during the 1960s and celebrated "Black Dance," which was a blend of different dance styles that included historical and traditional elements of African heritage. This movement was part of a broader spectrum of cultural expression during the decade which sought to empower and reconnect with African American roots.
Final answer:
During the 1960s, the West Coast saw the rise of Surf Rock, a dance genre closely connected to the laid-back, free-spirited surfing lifestyle and characterized by instrumental rock music.
Explanation:
In the 1960s, on the West Coast, particularly in California, a dance movement that emerged was Surf Rock. This genre of music created a unique dance vibe and culture, mostly due to its instrumental focus and connection with the surf scene. Surf Rock music was linked to a style of guitar-led rock music that often had a strong association with the surfing culture and lifestyle associated with Southern California. It helped define a youthful, beach-oriented counterculture that was free-spirited and often synonymous with the freedom and allure of the West Coast. Bands like the Kingsmen, famous for 'Louie Louie', and the Ventures with 'Walk Don't Run', became the soundscape of this era, influencing the dances that accompanied their music.
A 1.4 v d-cell battery is rated at 15,000 ma⋅h. part a for how long could such a battery power a flashlight bulb rated at 1.1 w ?
Answers
[tex]P=U*I \rightarrow I=P/U[/tex]
Thus [tex]I=1.1/1.4=0.786 A[/tex]
The capacity of the battery is
[tex]C=15000 mA*h =15 A*h[/tex]
In words we say that if a current of 15 A is taken from it, it lasts for 1 hour.
If we take a current I=0.786 A the battery lasts a time of
[tex]t=C/I=15/0.786 =19.1 hours[/tex]
Two balls undergo inelastic collision. The y-momentum after the collision is 98 kilogram meters/second, and the x-momentum after the collision is 100 kilogram meters/second. What is the magnitude of the resultant momentum after the collision?
Answers
we know that px is 100 kg m/sec
and we know that py is 98 m/sec
So, to find out the momentum, you just need to insert the number into the equation
p = √(v1^2 + v2^2)
p = √(98^2 + 100^2)
p = 140.01
p = 1.4 x 10^2 k m/s
Answer:
D. 1.4 × 10^2 kilogram meters/second
The book slides from you to beth and then from beth to carlos, along the lines connecting these people. what is the work done by friction during this displacement?
Answers
W(friction) = - uk m g d
Where
uk = 0.2
m = mass = 1.9 kg
d = total distance = 8 m *2 = 16 m
Thus,
W(friction) = -59.584 J
The answer is -59.584 J
The work done due to friction is [tex]\boxed{59.58{\text{ N}}}[/tex].
Further explanation:
Here, we have to calculate the total work done due to frictional force.
Frictional force is a non-conservative force and the work done by a non-conservative force is path dependent.
Given:
The mass of the physics book is [tex]1.9{\text{ kg}}[/tex].
Coefficient of friction between the book and floor is [tex]0.2[/tex].
The distance between observer that is (you) and Beth is [tex]8{\text{ m}}[/tex]
The distance between Beth and Carlos is [tex]8{\text{ m}}[/tex].
Formula and concept used:
The work done by the conservative force is equal to the product of force and the displacement.
Now, we will know about displacement,
Displacement: The shortest distance between the initial and final position of the object is known as displacement.
But, in case of the non-conservative forces, the work done is equal to the product of the force and the total distance travel by the object.
So, friction force can be calculated as,
[tex]{F_r} = \mu mg[/tex]
Here, [tex]m[/tex] is the mass of the book, [tex]\mu[/tex] is the coefficient of friction.
So, work done due to friction when observer slides the book to the Beth and Beth slides the book to Carlos.
[tex]\boxed{W = {F_r} \cdot d}[/tex]
Here, [tex]{F_r}[/tex] is the friction force, [tex]d[/tex] is the total distance travel against friction force.
[tex]\boxed{\begin{aligned}d&=8+8\\&=16\text{ m}\end{aligned}}[/tex]
Substitute the value of [tex]{F_r}[/tex] in above equation.
[tex]W = \mu mgd[/tex] …… (1)
Calculation:
Substitute [tex]0.2[/tex] for [tex]\mu[/tex], [tex]1.9{\text{ kg}}[/tex] for [tex]m[/tex] and [tex]16{\text{ m}}[/tex] for [tex]d[/tex] in equation (1).
[tex]\begin{aligned}W&=\left( {0.2} \right)\left( {1.9} \right)\left( {9.8} \right)\left({16}\right)\\&=59.58{\text{ N}}\\\end{gathered}[/tex]
The work done due to friction is [tex]\boxed{59.58{\text{ N}}}[/tex].
Learn more:
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2. Water is a compound because: https://brainly.com/question/4636675
3. Conservation of momentum during collision https://brainly.com/question/9484203
Answer detail:
Grade: Senior School
Subject: Physics
Chapter: Work and Energy
Keywords:
Book slide, Beth, Carlos, work done, friction, four corners, square, 8m length, 59.58 N, connecting these people, displacement.
A 1040 kg car and 3360 kg truck undergo a perfectly inelastic collision. before the collision, the car was traveling southward at 1.80 m/s and the truck westward at 8.25 m/s. m/s. find the velocity (speed and direction) of the wreckage immediately after the collision.
Answers
Final answer:
To determine the wreckage's velocity after a perfectly inelastic collision, calculate the vector sum of the car's and truck's momenta, then divide by the total mass. Use Pythagorean theorem for the magnitude and arctan for the direction.
Explanation:
To find the velocity of the wreckage immediately after a perfectly inelastic collision, we apply the principle of conservation of momentum. Since the collision is inelastic, both vehicles stick together and move with a common velocity after the impact.
To calculate this, we will:
Determine the momentum of each vehicle before the collision.
Sum the momenta vectorially.
Divide the resultant momentum by the total mass of the system to find the velocity of the wreckage.
For the 1040 kg car and 3360 kg truck:
The momentum of the car is given by its mass times its velocity (1040 kg * 1.80 m/s south).
The momentum of the truck is given by its mass times its velocity (3360 kg * 8.25 m/s west).
Now we add these momenta vectorially, using the components in each direction:
Southward momentum (car's): 1040 kg * 1.80 m/s
Westward momentum (truck's): 3360 kg * 8.25 m/s
With the sum of momenta:
Total southward momentum = 1040 kg * 1.80 m/s = 1872 kg·m/s
Total westward momentum = 3360 kg * 8.25 m/s = 27720 kg·m/s
The magnitude of the wreckage's velocity can be found using Pythagoras' theorem:
√(1872^2 + 27720^2)
Finally, the direction of the velocity is given by the arctangent of the ratio between the southward and westward momentum components.
After calculating the values:
Magnitude of velocity: √(1872^2 + 27720^2) kg·m/s {÷} (Total mass 1040 kg + 3360 kg)
Direction of velocity: arctan(1872 kg·m/s {÷} 27720 kg·m/s)
This resultant velocity is the combined speed and direction of the wreckage after the collision.
In an elastic collision, an object with momentum 12 kg·m/s collides with another. the final momenta of each are 14 kg∙m/s and 16 kg∙m/s respectively. what was the initial momentum of the second object
Answers
We know that in an elastic collision the moments of the both the objects is conserved i.e
Intial momentum of object1 + Intial momentum of object2 =Final momentum of object1 + Final momentum of object2
Intial momentum of object1 =12 kg.m/s
Intial momentum of object2 = P (assume that P is the momentum)
Final momentum of object1= 14 kg.m/s
Final momentum of object2 =16 kg.m/s
On substituting all values we get
12 + P =14 kg.m/s + 16 kg.m/s
P = -18 kg.m/s
(-ve sign indicates the second object was moving in the opposite direction to the object1 before collision )
Therefore the initial momentum of the second object was 18 kg.m/s.
What are the four conditions needed to see an object?
Answers
Answer:
Four conditions need to be met for an object to be seen-an object, an eye, a source of light, and a direct, unblocked path between the object and the eye
hope this helps
if a snail starts at a position of 67cm and moves to a final position of 104 cm what is the displacement
Answers
What property do the following elements have in common? sulfur, iodine, and magnesium A) Same phase at room temperature. B) Good conductors of electricity. C) Same number of valence electrons. Eliminate D) They form cations (positive ions).
Answers
Sulphur and Iodine are not good conductors of electricity.
Also while Sulphur is in group 6, Magnesium is in group 2. Therefore they do not have the same number of valence electrons. Sulphur is making anions (negative ions) and Magnesium is making cations (positive ions).
i just did it and the answer us A
Example 2: a horizontal cylindrical drum is 2.00 m in diameter and 4.00 m in length. the drum is partially filled with benzene (density = 0.879 g/cm3). what is the mass (kg) of benzene when the liquid depth is 0.85 m?
Answers
Volume = L {(R^2)cos-1[(R-H)/R)] - (R-H)(2RH-H^2)^0.5}
Where:
L = length of the drum = 2 meters
R = radius of the drum = 4 meters
H = height of the liquid = 0.85 meter
substituting the given to the formula, we get
Volume = 5.087 m3
To solve for the mass of benzene, we must multiply the volume with the density.
Density = 0.879 g/cm3 or 879 kg/m3
Mass of benzene = Volume x Density
Mass of benzene = 5.087 x 879 = 4,471.5 kg
ANSWER: Mass of benzene = 4,471.5 kg
The mass (kg) of benzene is about 4470 kg
Further explanationThis problem is about Density.
Density is the ratio of mass to the volume of the object.
[tex]\large {\boxed {\rho = \frac{ m }{ V } } }[/tex]
ρ = density of object ( kg / m³ )
m = mass of object ( kg )
V = volume of object ( m³ )
Given:
Diameter of Cylinder = d = 2.00 m
Radius of Cylinder = R = d/2 = 2.00/2 = 1.00 m
Length of Cylinder = L = 4.00 m
Liquid Depth = H = 0.85 m
Density of Benzene = ρ = 0.879 g/cm³ = 879 kg/m³
Unknown:
mass of benzene = m = ?
Solution:
This problem is about Liquid Volume in Partially Filled Horizontal Tanks
Firstly we will calculate the volume of Benzene by using following formula:
[tex]V = A \times L[/tex]
[tex]V = ( \texttt{Area of Sector - Area of Triangle} ) \times L[/tex]
[tex]V = [ R^2 \cos^{-1}(\frac{R - H}{R}) - (R - H)\sqrt {(2RH - H^2)} ] L[/tex]
[tex]V = [ 1^2 \cos^{-1}(\frac{1 - 0.85}{1}) - (1 - 0.85)\sqrt {(2(1)(0.85) - 0.85^2)} ] 4[/tex]
[tex]V = [ \cos^{-1} (0.15) - 0.15 \sqrt{ 0.9775} ] 4[/tex]
[tex]V \approx \boxed {5.0877 ~ m^3}[/tex]
[tex]m = \rho \times V[/tex]
[tex]m = 879 \times 5.0877[/tex]
[tex]m \approx \boxed {4470 ~ kg}[/tex]
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Subject: Mathematics
Chapter: Density
Keywords: Temperature , Density , Iron , Sphere , Volume , Mass
The International Space Station is in orbit around the Earth 380 km above the surface. Which statement accurately describes its motion?
Answers
What electric field strength is needed between the electrodes to achieve this deflection?
Answers
An object is placed so that the image formed is a real image of the same size as the object. What is the position of the object?
Answers
Hope this helps!
Is the distance on a round-trip positive, negative, or zero?
Answers
The distance of every object in a round trip is always positive
Distance is a scalar quantity, the total distance of an object in any trip is the total path covered by the object from the starting point to the finish point.
In a round trip, the object start's from one point and makes a circular movement, then returns to the same starting point. The total distance of the object is the equivalent to the circumference of the circle. This measurement will be a positive value.On the other hand, the displacement of the object will be zero. Displacement is the change in the position of an object.
Thus, we can conclude that the distance of every object in a round trip is always positive while the displacement is zero.
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A 6.50-kg object is hung from the bottom end of a vertical spring fastened to an overhead beam. the object is set into vertical oscillations having a period of 3.20 s. find the force constant of the spring.
Answers
what is an exception to the rule that liquids are less dense than solids.
Answers
If HST has a tangential speed of 7,750 m/s, how long is HST’s orbital period? The radius of Earth is 6.38 × 106 m. s
Answers
what factors affect the amount of solar energy that reaches earth's surface
Answers
Particles in air such as smoke smog
cloud cover: clouds have a big impact on the amount of solar radition reaching earth surface
An electric heater is constructed by applying a potential difference of 120 v to a nichrome wire that has a total resistance of 6.00 . find the current carried by the wire and the power rating of the heater.
Answers
Current = (voltage) / (resistance)
= (120 v) / (6 Ω) = 20 Amperes .
Electrical power = (voltage) x (current) .
= (120 v) x (20 Amperes)
= 2,400 watts .
That amount of power will sure toast your buns in a hurry.
The current carried by the wire and the power rating of the heater are 20 A and 2400 W respectively.
Given data:
The potential difference across the electric heater is, V' = 120 V.
The total resistance of the nichrome wire is, [tex]R= 6.00 \;\rm \Omega[/tex].
First we need to apply the Ohm's law to find the current through the wire. The expression for the Ohm's law is given as,
[tex]V'= I \times R\\\\I =\dfrac{V'}{R}\\\\I =\dfrac{120}{6}\\\\I=20 \;\rm A[/tex]
Now, the expression for the electric power through the heater is given as,
[tex]P= V \times I\\\\P= 120 \times 20\\\\P =2400 \;\rm W[/tex]
Thus, we can conclude that the current carried by the wire and the power rating of the heater are 20 A and 2400 W respectively.
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WILL MARK AS BRAINLIEST
Compare and contrast angular momentum and linear momentum. Include two ways that they are alike and two ways that they are different. Be sure to discuss how mass affects both angular and linear momentum.
Answers
or an object with mass moving at a velocity , the angular momentum with respect to a reference point is defined using the cross product as:
where is the position vector of the object that describes the object’s position with respect to the reference point. The units for measuring angular momentum is kg m2 s-1. Since angular momentum is defined in terms of a cross product, the direction of the angular momentum vector is taken to be in a direction perpendicular to both the particle’s position vector and its velocity vector .
Imma answer so other dude can have brainliest.
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Which of these atoms is most likely to share electrons with other atoms?
Answers
It is the second one or the one with the letter F
What is the analogy heart:_____:stomach:digestive?
Answers
Cardiovascular refers to our bodily system that's functioned to transport necessary nutrients to all part of our body.
The heart in this system is functioned to pump out blood that delivers oxygen and some other nutrients to all part of our body.
When monochromatic light is incident for a short period of time on a thin barrier having two slits, how will a screen placed in front of the slits appear?
Answers
Answer:
Interference pattern- alternate bright and dark fringes
Explanation:
When a monochromatic light is incident on a thin barrier having two slits, an interference pattern can be observed.
Dark and bright fringes would appear on the screen placed in front of it. It would not be random pattern. It would be a smooth pattern with distinctive dark fringe and bright fringe alternatively.
When the light from two source would superimpose, a constructive interference would lead to bright fringe and destructive interference would lead to dark fringe.
The Federal Communications Commission (FCC) has considered lifting the ban on in-flight cell phone use. This could allow people to have conversations on their cell phones during plane flights. Give your opinion. Should the FCC allow in-flight calls? Why or why not?
Answers
Besides ... the cellular system is designed to provide coverage on the ground, not in the air. I think every call you made from an airliner would drop in a minute ar two.
There's no right or wrong answer to a "should" question. My humble OPINION is: Please, not until Satan's inferno freezes over !
Answer:
I do not think the FCC should allow in-flight calls, because they would make the flight noisy and could make it difficult for passengers to hear the pilot or flight attendants.
Explanation:
You hold a bucket in one hand. in the bucket is a 500 g rock. you swing the bucket so the rock moves in a vertical circle 2.6 m in diameter. part a what is the minimum speed the rock must have at the top of the circle if it is to always stay in contact with the bottom of the bucket?
Answers
The minimum speed the rock must have at the top of the circular path to always stay in contact with the bottom of the bucket is approximately 5.04 m/s, based on principles of circular motion and gravitational force.
Explanation:This problem can be solved using the principles of circular motion and Newton's laws of motion. When the rock is at the top of the vertical circle, the minimum speed it should have is equal to the speed at the point where the gravitational force acting downwards equals the required centripetal force to maintain circular motion. To achieve this, you can use the formula v² = 2gy to find out the minimum velocity needed.
Given:
Mass of the rock (m) = 500g = 0.5kg
Gravitational acceleration (g) = 9.81m/s²
Radius of the circle (r), since diameter = 2.6m, r = d/2 = 1.3m
The minimum speed needed at the top of the circle, v, is found by rearranging the equation to v = √(2gr). Substituting the given values, we get: v = √(2*9.81m/s²*1.3m) = √(25.386) ≈ 5.04 m/s
So, the rock must have a minimum speed of 5.04 m/s at the top of its circular path to ensure it stays in the bucket.
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The scenario presented is a physics problem that involves the concepts of forces and circular motion. It necessitates determining the minimum velocity a rock must have when at the highest point of its circular path to maintain contact with the bucket. The calculated velocity required at the highest point of the trajectory, based on the provided diameter of the circle and the force of gravity, is approximately 3.5 m/s.
Explanation:The scenario is a physics problem that deals with centripetal force and gravity. The minimum speed the rock needs to have at the top of the circle to stay in contact with the bucket can be calculated using the centripetal acceleration equation, ac = v²/r. Here, we know that the centripetal acceleration must be at least equal to gravity (9.8 m/s²) to maintain contact. We also know that the radius (r) of the circle is the diameter divided by two, which is 2.6m/2 = 1.3m. So, we can set up the equation 9.8m/s² = v²/1.3m, which when solved, gives us v = √(9.8m/s² * 1.3m) = √12.74 m²/s², resulting in v ≈ 3.5 m/s. So, the rock needs to travel at a speed of about 3.5 m/s at the top of the circle to stay in contact with the bucket.
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A moving 4.30 kg block collides with a horizontal spring whose spring constant is 223 n/m. the block compresses the spring a maximum distance of 5.00 cm from its rest position. the coefficient of kinetic friction between the block and the horizontal surface is 0.340. what is the work done by the spring in bringing the block to rest? submit answer tries 0/12 how much mechanical energy is being dissipated by the force of friction while the block is being brought to rest by the spring? submit answer tries 0/12 what is the speed of the block when it hits the spring?