A car starts from rest and accelerates uniformly at 3.0 m/s2 toward the north. a second car starts from rest 6.0 s later at the same point and accelerates uniformly at 5.0 m/s2 toward the north. how long after the second car starts does it overtake the first car?

Answers

Answer 1

Answer:

the answer is t = 20.625

Step-by-step explanation:

To begin, you would need to find the displacement of the first car and the equation to find that is d = 1/2at^2. So you would plug in what you have from the problem into the equation: d = (1/2)3(6)^2 and d is equal to 54 m. THIS IS YOUR DISPLACEMENT FOR THE FIRST CAR.

Next, you need to find the velocity of the car and the equation would be v = at. Plug in what you know from the problem: v = 3(6) which is 18. THIS IS YOUR INITIAL VELOCITY.

Next, we need to find out the distance of the 2nd car and we would use d = 1/2at^2. Plug in what you now from the problem: d = (1/2)5t^2 which would be d = 2.5t^2.

Next, you would equal these two equations together: 2.5t^2 = 1.5t^2 + 18t +54.  All these values are from when we solved them from above, and once you solve it you will get 20.625. (SOLVE FOR T)


Related Questions

At 1 P.M., ship A is 150 km west of ship B. Ship A is sailing east at 35 km/h and ship B is sailing north at 25 km/h. How fast is the distance between the ships changing at 5 P.M.?

Answers

The distance between the ships is changing at a rate of 21.393 km/h

Step 1: First, you must draw an image to help better understand the problem 

The reason that ship A is moving -35km/h is because ship B acts as an "origin" and as things move closer to the "origin" they become negative and as things move away from the "origin" they become positive.

We know that the rate of Ship A is expressed as dAdt=−35 and the rate of Ship B is expressed as dBdt=25

Step 2: We want to figure out how many km Ship A and Ship B traveled in 4 hours

ShipA:−35kmh⋅4hr=−140km

Now if we take this −140km and add it to the 150km we can see that Ship A is now only 10km away from where Ship B began

ShipB:25kmh⋅4hr=100km

This means that Ship B is now 100km from where it originally started

We can now redraw our information

Step 3: We must use the Pythagorean Theorem to find the third side of the triangle

x2+y2=z2→102+1002=z2

z=√102+1002

Step 4: Now that we know z, we must differentiate the original equation in order to find the rate at which z in changing

x2+y2=z2→2xdxdt+2ydydt=2zdzdt

We can simplify by canceling out the 2's

xdxdt+ydydt=zdzdt

Step 5: Write down all the information and then plug into equation

x=10anddxdt=−35
y=100anddydt=25
z=√102+1002anddzdt=?

Now plug in the information

xdxdt+ydydt=zdzdt

10(−35)+100(25)=√102+1002dzdt

−350+2500=√102+1002dzdt

2150=√102+1002dzdt

21.393=dzdt

The distance between the ships are increasing at a rate of 21.393 km/h

Raj eats 1/11 of a pound of grapes in 1/25 of a minute. How many minutes will it take him to eat a full pound of grapes?

Answers

[tex]\bf \begin{array}{ccll} \stackrel{lbs}{grapes}&minutes\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{1}{11}&\frac{1}{25}\\\\ 1&m \end{array}\implies \cfrac{\frac{1}{11}}{1}=\cfrac{\frac{1}{25}}{m}\implies \cfrac{\frac{1}{11}}{\frac{1}{1}}=\cfrac{\frac{1}{25}}{\frac{m}{1}} \\\\\\ \cfrac{1}{11}\cdot \cfrac{1}{1}=\cfrac{1}{25}\cdot \cfrac{1}{m}\implies \cfrac{1}{11}=\cfrac{1}{25m}\implies 25m=11\implies m=\cfrac{11}{25}[/tex]

find the equation to the line that is perpendicular to y=2x-3 and goes through the point (-1,2)

Answers

first off, let's see this equation     [tex]\bf y=\stackrel{slope}{2}x-3[/tex]

so, notice, since it's already in slope-intercept form, we know the slope is just 2.

a line that is perpendicular to it, will have a negative reciprocal slope to it, let's check.

[tex]\bf \textit{perpendicular, negative-reciprocal slope for slope}\quad 2\implies \cfrac{2}{1}\\\\ slope=\cfrac{2}{{{ 1}}}\qquad negative\implies -\cfrac{2}{{{ 1}}}\qquad reciprocal\implies - \cfrac{{{ 1}}}{2}[/tex]

so, what is the equation of a line whose slope is -1/2 and goes through -1,2?

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ -1}}\quad ,&{{ 2}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies -\cfrac{1}{2} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-2=-\cfrac{1}{2}[x-(-1)] \\\\\\ y-2=-\cfrac{1}{2}(x+1)\implies y-2=-\cfrac{1}{2}x-\cfrac{1}{2}\implies y=-\cfrac{1}{2}x-\cfrac{1}{2}+2 \\\\\\ y=-\cfrac{1}{2}x+\cfrac{3}{2}[/tex]

Alyssa is building a brick mailbox. She is going to stack bricks that are each \dfrac23 \text{ft}
​3

​2
​​ ftstart fraction, 2, divided by, 3, end fraction, f, t tall, and the finished stack of bricks needs to be 4\dfrac23 \text{ft}4
​3

​2
​​ ft4, start fraction, 2, divided by, 3, end fraction, f, t tall.
How many bricks will go in the stack?

Answers

Given that each of the brick is [tex]\frac{2}{3}[/tex] ft tall and the finished stack of bricks is [tex]4\frac{2}{3}[/tex] ft tall.

Let the number of bricks in the stack be x, then

[tex] \frac{2}{3} x=4 \frac{2}{3} = \frac{14}{3} \\ \\ \Rightarrow x= \frac{ \frac{14}{3} }{ \frac{2}{3} } = \frac{14}{3} \times \frac{3}{2} \\ \\ = \frac{14}{2} =7[/tex]

Therefore, 7 bricks will go in the stack.

Of five letters (a, b, c, d, and e), two letters are to be selected at random without replacement. how many possible selections are there

Answers

Sent a picture of the solution to the problem (s). I sent the formula because I do not know if your calculator has the combination function. You will notice the denominator. I got it by the 2 picks you make and the 3 from what is left over. The 5 is from the total selection.

What is the effect of decreasing the alpha level (for example, from a = .05 to a = .01)? it decreases the probability of a type i error. it decreases the size of the critical region. it decreases the probability that the sample will fall into the critical region. all of the other options are results of decreasing alpha?

Answers

The effect of decreasing the alpha level from 0.05 to 0.01. it decreases the probability that the sample will fall into the critical region, it decreases the probability of a Type I error, and it decreases the size of the critical region.
Therefore, the answer is that all of other options are results of decreasing alpha.

Tasha earns $400 per week plus a commission of 10% on her weekly sales. Each week she saves of her earnings. In the expression , what does the expression 400 + 0.1s represent in this situation?

Answers

Final answer:

In this situation, the expression 400 + 0.1s represents Tasha's total earnings for the week, including her base salary and commission.

Explanation:

In this situation, the expression 400 + 0.1s represents Tasha's total earnings for the week. The $400 represents her base salary, and the 0.1s represents the commission she earns on her sales. The value of s represents Tasha's total sales for the week.

For example, if Tasha's total sales for the week are $2000, then her commission would be 0.1($2000) = $200. Adding this to her base salary of $400, her total earnings for the week would be $400 + $200 = $600.

Therefore, the expression 400 + 0.1s represents Tasha's total earnings for the week, including her base salary and commission.

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Three years ago, Ava lent her sister $400 to buy some clothes. Today Ava’s sister paid her loan in full with $454. What simple annual interest rate did she pay?

Answers

the answer is 4.5% i made sure it was correct
4.5 i hope it is correct!


If an original conditional statement is represented by p → q, which represents the contrapositive?

Answers

contrapositive would look like this. -q arrow -p

~q → ~p that's the answer


Find the mean median mode and range of this date 49,49,54,55,52,49,55, if necessary round to the nearest tenth

Answers

The numbers from least to greatest is (49, 49, 49, 52, 54, 55, 55) The mean is 51.8 (52 rounded), 52 is median, mode is 49, and the range is 6. :) 

25°C is what in Fahrenheit?

Answers

The correct answer is 77F.


multiply Celsius by 9/5 then add 32 to get Fahrenheit

25 * 9/5 = 45

45 +32 = 77 degrees Fahrenheit

identify the type of of function represented by the equation y=2x^2

Answers

I think it is a parabola
I believe this is a quadratic function.

Regard y as the independent variable and x as the dependent variable and use implicit differentiation to find dx/dy. x3y2 − x4y + 4xy3 = 0

Answers

Final answer:

Through applying the techniques of implicit differentiation to the equation x³y² - x⁴y + 4xy³ = 0, the derivative dx/dy is found to be [x⁴ - 4y³ - 2x³y]/[3x²y² - 4x³y].

Explanation:

The subject of your question is implicit differentiation in calculus, a branch of mathematics. You wish to know how to differentiate the equation

x³y² - x⁴y + 4xy³ = 0

with respect to y (y is independent and x is dependent).



The initial step in implicit differentiation is to derive every term of an equation. So, we end up with:

3x²y²(dx/dy) + 2x³y(dy/dx) - 4x³y(dx/dy) - x⁴ + 4y³ + 12x²y² = 0.



After grouping like terms together, the equation become:

dx/dy[3x²y² - 4x³y] = x⁴ - 2x³y - 4y³



Eventually, divide both sides by [3x²y² - 4x³y] to isolate dx/dy and get the final answer:

dx/dy = [x⁴ - 4y³ - 2x³y]/[3x²y² - 4x³y]

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A customer has six (6) $1 bills, three (3) $5 bills, four (4) $10 bills, seven (7) quarters, ten (10) dimes, seven (7) nickels, and nine (9) pennies. The customer buys a pair of shoes for $49.86. Based on the combination of bills and coins the customer has, what are the least number of bills and coins the customer can give the cashier in order to buy the shoes for the exact amount and not require any change back?

Answers

4 $10
1 $5
4 $1
3 $.25
1 $.10
1 $.01
4 tens 1 five 4 ones 3 quarters 1 dime and one penny

The 2015 senior class from puma high school raised funds for an end of the year party at club sizzle. It costs $4,000 to rent out club sizzle plus $20 per student for food and drinks. If the senior class raised 11,000, how many students can attend the end of year party ? Write an equation for the situation and solve.

Answers

4000+20x=11000
20x=11000-4000
20x=7000
20/20x=7000/20
x=350 $tudents.

Find the percent of tip: Cost of meal: $28.00 Tip: $3.36 The percent of the tip was ___%.

Answers

12% because 28.00 divided by 3.36

Answer:

12.00%

Step-by-step explanation:

[tex]$3.36\\[/tex] ÷ [tex]$28.00\\[/tex] = [tex]0.12\\[/tex]

[tex]100 *0.12=12%\\[/tex] %

A card is randomly selected from a deck of 52 cards. Find the probability that the card is between four and eight (inclusive) or is a club.

Answers

Answer:

20/52+13/52-5/52=.538

Step-by-step explanation:

The probability that the card is between four and eight (inclusive) or is a club is 4/13.

What is Probability?

Probability helps us to know the chances of an event occurring.

[tex]\rm Probability=\dfrac{Desired\ Outcomes}{Total\ Number\ of\ outcomes\ possible}[/tex]

The number of cards can be written as,

The number of cards between 4 and 8 is 3 {4,5,6,7,8}.Number of club cards = 13Number of cards between 4 and 8 from heart, spades, and diamonds = 15

Now, the probability that the card is between four and eight (inclusive) or is a club is,

Probability

= (Number of club cards+ Number of cards between 4 and 8)/(Total number of cards)

= (13+15)/(52)

= 28/52

= 4/13

Hence, the probability that the card is between four and eight (inclusive) or is a club is 4/13.

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At what projection angle will the range of a projectile equal to 6 times its maximum height?

Answers

i not sure but it might be 60 kilogrames
The formula for maximum height is:

H = v²sin²θ/2g

The formula for range is:

R = v²sin(2θ)/g

The relationship between the two is written as:
R = 6H
v²sin(2θ)/g = 6(v²sin²θ/2g)
v²sin(2θ)/g = 3v²sin²θ/g)
Cancelling out like terms,
sin(2θ) = 3sin²θ
Solving for θ using a scientific calculator,
θ = 33.7°

Can someone please help?

Answers

3(b-4)+5b=44
distribute
3b-12+5b=44
combine number with numbers and variables with variables
8b=56
decide by 8 on both sides
b=7
We need to solve the equation: 
3(b-4)+5b=44
There is only one unknown in the equation. The unknown is b. 
We must isolate the unknown b on one side of the equation.
According the law of multiplication we can write the following:
3b-3*4+5b=44
3b-12+5b=44
(3b+5b)-12=44
8b-12=44

We shift a number from one side of an equation 
to the other by writing it on the other side with the inverse operation,so we obtain:
8b=44+12
8b=56
b=56/8
b=7

The square root of 150 is between

A.10 and 11
B.11 and 12
C.12 and 13
D.13 and 14

Answers

The square of 12 is 144 and the square of 13 is 169. Since 150 is in between those, it is C.

Hope this helps!

You swim the 50-meter freestyle in 28.12 seconds.This is 0.14 second less than your previous fastest time. What was your previous fastest time?

Answers

if your fastest time was 0.14 seconds more before today then you previous fastest time would be 28.26

If a person swim the 50-meter freestyle in 28.12 seconds. This is 0.14 second less than persons previous fastest time is 28.26.

What is Equation?

Two or more expressions with an equal sign is called as equation.

Given that,

One swim the 50-meter freestyle in 28.12 seconds..

The previous fastest time be x.

The new fastest time is 28.12 seconds.

New fastest time is 0.14 second less than your previous fastest time.

So, 28.12+0.14=x

28.26=x

Hence the previous fastest time is 28.26 seconds.

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if the raidus of mars(3,397 km) is about 13.7% of of neptunes radius, what is the radius of neptune?

Answers

this is the answer check it out

A carpenter worked 34 hours a week for half a year. If her hourly wage was $20, how much did she earn during this time period?

Answers

34 hours per week times 26 weeks in half a year times $20 per hour:
34X26X20 = $17,680

There are three highways in the county. the number of daily accidents that occur on these highways are poisson random variables with respective parameters .3, .5, and .7. find the expected number of accidents that will happen on any of these highways today.

Answers

There is a theorem that we can use to find the expected value of a random variable that is a sum of other random variables as follows.

If [tex]X=X_1 + X_2 + ...+X_k[/tex], then [tex]E(X)=E(X_1)+E(X_2)+...+E(X_k)[/tex].

In this case, let X = the number of accidents that will happen on any of those highways today,
[tex]X_1,X_2,X_3[/tex] are the numbers of accidents on each highway, respectively.

Then  [tex]X = X_1+X_2+X_3[/tex].

Since [tex]X_1,X_2,X_3[/tex] are Poisson variates, their expected values are the parameters given, .3, .5 and .7.

So [tex]E(X_1)=.3, E(X_2) = .5, E(X_3) = .7[/tex]
Thus, [tex]E(X)=E(X_1)+E(X_2)+E(X_3) = .3 + .5 + .7 = 1.5[/tex]

The answer is 1.5.

Final answer:

To find the expected number of accidents on three highways with Poisson distributions, sum the individual expectations: 0.3, 0.5, and 0.7, resulting in an expected 1.5 accidents per day.

Explanation:

The student asked how to find the expected number of accidents that will happen on any of the three highways in a day, given that the number of daily accidents on these highways are Poisson random variables with parameters 0.3, 0.5, and 0.7 respectively. To solve this, we shall sum the parameters of the Poisson distributions because the expectation of the sum of independent random variables is the sum of their expectations.

Therefore, we calculate the expected number of accidents as follows:

For the first highway with parameter 0.3, the expected number of accidents is 0.3.

For the second highway with parameter 0.5, the expected number of accidents is 0.5.

For the third highway with parameter 0.7, the expected number of accidents is 0.7.

Adding these together, we get:

Expected number = 0.3 + 0.5 + 0.7 = 1.5 accidents per day.

An observer (O) spots a plane flying at a 35° angle to his horizontal line of sight. If the plane is flying at an altitude of 17,000 ft., what is the distance (x) from the plane (P) to the observer (O)?
20,757 feet
24,251 feet
29,639 feet
31,262 feet

Answers

Answer:

here are numerous information's already given in the question. Based on those information's, the answer to the question can be easily deduced.

Angle at which the plane is flying in respect to the observer = 35 degree

Altitude at which the plane is flying = 17000 feet

The distance at which the plane is flying from the observer = x 

Then

x = 17000/sin 35

 = 17000/0.57357

 = 29638.93 feet

 = 29639 feet

From the above deduction, we can conclude that the correct option among all the options given in the question is the third option.

 

GIVE BRainliest plz

The distance between the plane and the observer is 29,638 feet.

Data;

Angle = 35 degreesheight of the plane = 17,000ftdistance from the plane to the observer = x

Trigonometric Ratio

This is the use of SOHCAHTOA which is the relationship between sides of a right angle triangle and it's angle.

In this case, we have the value of opposite and angle and we need to find the hypothenuse.

Using sine of the angle,

[tex]sin\theta = \frac{opposite}{hypothenuse} \\sin 35 = \frac{17000}{x}\\ x = \frac{17000}{sin35}\\ x = 29,638 feet[/tex]

The distance between the plane and the observer is 29,638 feet.

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Which of the articles represent a proper fraction? A. 15/22 B. 8/8 C. 3/2 D. 12/9

Answers

A proper fraction is a fraction that is less than one, with the numerator less than the denominator. Which of these satisfies that criteria?
a) 15/22, numerator (top number) less than the denominator (bottom number). CORRECT ANSWER
B) 8/8 numerator equals denominator, not a proper fraction
C) 3/2, numerator greater than denominator, not a proper fraction
D) 12/9 . numerator greater than denominator, not a proper fraction

Which multiplication property is shown in the equation 3.1x(2x9)=(3.1x2)x9

Answers

Associative Property of Multiplication
Final answer:

The given equation, 3.1x(2x9)=(3.1x2)x9, demonstrates the Associative Property of Multiplication. The property means that the way numbers are grouped in multiplication does not change the result.

Explanation:

The multiplication property shown in the equation 3.1x(2x9)=(3.1x2)x9 is referred to as the Associative Property of Multiplication. This property states that when three or more numbers are multiplied, the product does not depend on how the numbers are grouped. Therefore, (a x b) x c equals a x (b x c).

In the given equation, we can see this property applied. 3.1x(2x9) can be rearranged as (3.1x2)x9 and the results of both expressions will be the same. This demonstrates that the grouping does not affect the result of the multiplication.

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Which number is 100 times greater than 6 thousandths

Answers

 6 thousandths = .006 so times that by 100
.006 * 100 = .6

If a gambler rolls two dice and gets a sum of 10, he wins $10, and if he gets a sum of three, he wins $20. the cost to play the game is $5. what is the expectation of this game?
a. $3.06
b. -$2.78
c. -$3.06
d. $2.78

Answers

Chance to win $10 is 3/36 Chance to win $20 is 2/36 Chance to lose is 31/36 So if cost of play is $5: ((3*5) + (2*15) - (5*31))/36 = -3.06 C. $-3.06

Final answer:

The expected value of the gambling game with a cost of $5, and potential winnings of $10 for a sum of 10 or $20 for a sum 3, is −$2.78. The calculation shows the player will lose $2.78 on average per game, indicating it is not a profitable game to play long term. So, option (b) is correct.

Explanation:

The student is interested in determining the expected value of a gambling game where rolling two dice can result in either winning money or losing the cost to play. To find the expected value, we must consider the probability of each outcome and its associated payoff.

First, we calculate the chances of rolling a sum of 10 with two dice. There are three combinations that give a sum of 10: (4,6), (5,5), and (6,4). Since there are 36 possible outcomes when rolling two dice, the probability of obtaining a sum of 10 is 3/36 or 1/12.

Similarly, the only combinations that result in a sum of 3 are (1,2) and (2,1). Thus, the probability of rolling a sum of 3 is 2/36 or 1/18.

The expected value (EV) can be calculated using the formula:

EV = (−cost to play) + [P(sum of 10) × winnings for 10] + [P(sum of 3) × winnings for 3]

Substituting the given values yields:

EV = (−5) + [(1/12) × 10] + [(1/18) × 20]

After calculating, we find tha-

EV = −$2.78.

Since the expected value is negative, this implies that, on average, the player will lose $2.78 per game. Therefore, playing this game would result in an average loss over time.

A pooled proportion is calculated by giving each sample proportion an equal weight.
a. True
b. False

Answers

the answer is B False
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