A ball is dropped from rest from a Cliff and falls for 3 seconds.
Neglecting air resistance, the final velocity of the ball is
m/s. (g = -9.8 m/s2)
Enter the answer

Answers

Answer 1

Answer:

-29.4 m/s

Explanation:

Given:

v₀ = 0 m/s

t = 3 s

a = -9.8 m/s²

Find: v

v = at + v₀

v = (-9.8 m/s²) (3 s) + (0 m/s)

v = -29.4 m/s

Answer 2

The final velocity of a ball dropped from rest for 3 seconds is -29.4 m/s.

How to find final velocity?

Given the following information:

The ball is dropped from rest.

The acceleration due to gravity is g = -9.8 m/s².

The time the ball falls is t = 3 seconds.

Use the following formula to calculate the final velocity of the ball:

v = v_0 + g × t

where:

v is the final velocity of the ball

v_0 is the initial velocity of the ball (which is 0 in this case)

g is the acceleration due to gravity

t is the time

v = 0 + (-9.8 m/s²) × 3 seconds

v = -29.4 m/s

Therefore, the final velocity of the ball is -29.4 m/s.

The negative sign indicates that the velocity is downwards.

Find out more on final velocity here: https://brainly.com/question/25905661

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Related Questions

If one wave of 10 m amplitude meets constructively with another of amplitude 20
m, what is the new amplitude?
20 m
30 m
200 m
10 m

Answers

Answer:

B. 30m

Explanation:

This is because when a wave interferes constructively with another wave, they will add since constructive relates to joining or building up.

So, 10m + 20m equals a 30m wave.

If the mass of Mars is 0.11 ME (mass of Earth) and its radius is 0.53 RE (radius of
Earth), How much is the gravitational field g at the surface of Mars?
Given: ME=6.0x1024 kg and RE=6.4x106m

Answers

Answer:

3.8 m/s²

Explanation:

g = GM / R²

g = G (0.11 ME) / (0.53 RE)²

g = 0.39 G ME / RE²

g = 0.39 (9.8 m/s²)

g = 3.8 m/s²

Answer:

vote me brainliest! Please!

simple put is 3.8 m/s²

took it on edge 2020

If a race car is traveling South due to a 30N force and the parachute deploys resulting in a 10N force North what is the Net Force (or Resultant Force)?

a) 40n east
b) 40n south
c) 10n west
d) 20n south

Answers

Answer:

F = 20 N south  

Explanation:

It is given that,

Force applied on the racing car in south direction is 30 N and parachute deploys resulting in a 10 N force due North.

We need to find the net force on the car.

Let North denotes +y axis and South denotes -y axis.

So, F₁ = +10 N

F₂ = -30 N

Net force is :

[tex]F=F_1+F_2\\\\F=10+(-30)\\\\F=-20\ N[/tex]

It means that the net force is 20 N and it is acting in south. Hence (d) is correct.    

lake water flows downward through tunnels

Answers

Answer:

what's your question?

An 11.98-gram sample of zinc metal is placed in a hot water bath and warmed to 78.4°C. It is then removed and placed into a Styrofoam cup containing 50.0 mL of room temperature water (T=27.0°C; density = 1.00 g/mL). The water warms to a temperature of 28.1°C. Determine the specific heat capacity of the zinc.

Answers

Answer:

383.34 J/kg.K

Explanation:

From the question,

Heat lost by zinc = heat gained by water in the Styrofoam cup.

c'm'(t₁-t₃) = cm(t₃-t₂).............. Equation 1

Where c' = specific heat capacity of zinc, m' = mass of zinc, t₁ = initial temperature of zinc, t₂ = initial temperature of water in the Styrofoam cup, t₃ = temperature of the mixture

Make c' the subject of the equation

c' = cm(t₃-t₂)/m'(t₁-t₃).............. Equation 2

given: m' = 11.98 g = 0.01198 kg, m = density of water×volume of water = (1×50) = 50 g = 0.05 kg, t₁ = 78.4°C, t₂ = 27°C,  t₃ = 28.1°C

Constant: c = 4200 J/kg.K

Substitute these values into equation 2

c' = 0.05×4200(28.1-27)/[0.01198×(78.4-28.1)]

c' = 231/0.602594

c' = 383.34 J/kg.K

A gene is
1. a change in a DNA sequence
2. the 2-letter code representing the alleles inherited from parents
3. a part of a chromosome that controls a particular trait, like eye color
4. a characteristic that is inherited, like eye color​

Answers

Answer:

C - a part of a chromosome that controls a particular trait, like eye color

Explanation:

(if theres an option to pick two, i would pick C and D)

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