Answer:
a. 0.882 N b. 9.8 m/s² c. 6.42 m/s
Explanation:
a. The net force acting on the ball is its weight W = mg were m = mass of ball = 90 g = 0.090 kg and g = acceleration due to gravity = 9.8 m/s²
W = mg = 0.090 kg × 9.8 m/s² = 0.882 N
b. The acceleration = g = acceleration due to gravity = 9.8 m/s² since it is falling freely
c. Using v² = u² + 2as where v = final velocity of ball, u = initial velocity of ball = 0 m/s, a = acceleration of ball = 9.8 m/s² and s = height = 2.1 m. Substituting the values of the variables, we ave
v² = u² + 2as = 0² + 2(9.8 m/s²) × 2.1 m = 41.16
v = √41.16 = 6.42 m/s
A truck exerts 2700 N of force on a car that is stuck in the mud, and does not move. How much work has the truck performed?
Answer:
zero
Explanation:
although force was applied as long as there's no movement ,no work has been done
mathematically;work=force×distance
work=2700×0
work=0J
hope I helped
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What does ROCAPV mean? It says related to electricity.
Answer: Rancho de Area Comunes PV
Explanation: it means
Rancho de Area Comunes PV
In an AC Monte Roca PV System Profile, where the following are depicted:
Location
Commissioning
Production
Operator
PV system power
Module
And communication.
1) How is chemical energy
transformed into potential
energy?
Answer:
Chemical potential energy is a form of potential energy related to the structural arrangement of atoms or molecules. This arrangement may be the result of chemical bonds within a molecule or otherwise. Chemical energy of a chemical substance can be transformed to other forms of energy by a chemical reaction.
Explanation:
The entropy of steam increases in actual steam turbines as a result of irreversibilities. In an effort to control entropy increase, it is proposed to cool the steam in the turbine by running cooling water around the turbine casing. It is argued that this will reduce the entropy and the enthalpy of the steam at the turbine exit and thus increase the work output.
How would you evaluate this proposal?
Answer:
The proposal is not accepted because of greater reduction in work output and efficiency
Explanation:
The following factors influence the turbine output with the suggestion below
1 - Enthalpy at the turbine exit
2 - Heat losses in the turbine
The work output of the steam turbine is
[tex]W=m(h_1-h_2)-Q_{loss}[/tex]
Where,
m is the mass of thee steam flowing through the turbine,
h₁ is the specific enthalpy of the steam leaving the turbine, and
[tex]Q_{loss}[/tex] is the heat loss from the turbinee due to the cooking water.
Enthalpy at the turbine exit; on cooling the turbine with the cooling water, the beck pressure of the turbine is decrease.
this further decrease the specific enthalpy at the turbine exit.
the result is greater reduction in the work output and efficiency,
Heat losses in water in the turbine;
On passing the cooking water around the turbine mst of the heat is carried away by this cooliing water. As the heat losses increases in the turbine, there is a greater reduction in the work output and efficiency.
Therefore, The proposal is not accepted because of greater reduction in work output and efficiency
Although the proposal to cool the steam in the turbine with water might reduce the local entropy, it would not increase the overall work output. Cooling the steam would also decrease its enthalpy and potentially reduce the turbine's output. Instead, optimizing processes to minimize entropy production would be a better way to improve turbine efficiency.
Explanation:The proposed solution to control the entropy of steam by cooling the steam turbine assumes that reducing both the entropy and enthalpy of the steam at the turbine exit will increase the work output. While it's true that irreversibilities — such as heat transfer and friction — increase the entropy and can reduce the turbine's efficiency, directly cooling the steam in the turbine would not necessarily lead to increased output. This is due to the second law of thermodynamics, which states that the entropy of a closed system will not decrease. Thus, while local entropy may be decreased, the overall entropy in the system (including the cooling water) will still increase.
Moreover, cooling the steam would actually decrease its enthalpy, which would reduce the amount of available energy to perform work, thus potentially decreasing the turbine's output. Therefore, this proposal may not be the best method of increasing the efficiency of a steam turbine. The improvement in turbine efficiency would be better done by optimizing the processes to minimize entropy production as a result of irreversibilities.
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a man crossed a road 8.25m wide at a speed of 2.01m/s,how long does it take to get man to cross the road
Answer:
t = 4.1 seconds
Explanation:
It is given that,
Width of road which is to be crossed by a man is 8.25 m, it means it is distance to be covered.
Speed of man is 2.01 m/s
We need to find the time taken by the man to cross the road. It is a concept of speed. Speed of a person is given by total distance covered divided by time taken. So,
[tex]v=\dfrac{d}{t}[/tex]
t is time taken
[tex]t=\dfrac{d}{v}\\\\t=\dfrac{8.25}{2.01}\\\\t=4.1\ s[/tex]
So, the time taken by the man to cross the road is 4.1 seconds.
¿Por qué si cargas a uno de tus compañeros por cierto tiempo no estás realizando un trabajo mecánico?
Answer:
I will answer this in English, we can translate it to:
Why if you charge a mate by an amount of time you are not doing work?
This happens because work is defined as the displacement done by a force:
W = d*F
where W is work, d is the distance, and F is the force.
This means that the amount of time that you are charging your mate does not affect the mechanical work, the only time that you are doing work is when you are lifting him.
Romeo lanza suavemente guijarros a la ventana de julieta y quiere que los guijarros golpeen la ventana solo con con un componente horizontal de velocidad el esta parado en el extremo de un jardin de rosas 4.5m por abajo de la ventana y a 5.0m de la base de la pared cual es la rapidez de los guijarros cuando golpean la ventana
The speed of the pebbles when they hit the window is approximately 7.07 m/s.
What is the speed of the pebbles when they hit the window?Romeo wants to throw pebbles horizontally at Juliet's window. The window is 4.5m above him and 5.0m away from the wall. The pebbles' speed when they hit the window is about 7.07 m/s. This is calculated by determining the time it takes for the pebbles to reach the window vertically, using the equation t = [tex]\sqrt{\frac{2d}{g} }[/tex].
Then, the horizontal velocity is found by dividing the horizontal distance by the time of flight. The overall speed is the square root of the horizontal velocity squared, which is approximately 7.07 m/s.
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Romeo stands 4.5 meters below Juliet's window, 5.0 meters from the wall, and throws pebbles with horizontal velocity. Calculations based on time of flight and Pythagoras yield a speed of approximately 5.21 meters per second at impact.
To find the speed of the pebbles when they hit Juliet's window with only a horizontal component of velocity, we can use the following steps:
Calculate the time it takes for the pebbles to reach the window vertically.
We can use the formula for the time of flight for an object in free fall:
[tex]\[t = \sqrt{\frac{2d}{g}}\][/tex]
Where:
- t is the time of flight.
- d is the vertical distance (4.5 meters in this case, the height of the window).
- g is the acceleration due to gravity (approximately 9.81 m/s² on Earth).
Let's calculate t:
[tex]\[t = \sqrt{\frac{2 \cdot 4.5\,m}{9.81\,m/s^2}}\][/tex]
t is approximately 0.96 seconds.
Calculate the horizontal velocity.
Now that we know the time of flight (t), we can find the horizontal velocity [tex](\(v_x\))[/tex] by dividing the horizontal distance (5.0 meters) by the time of flight:
[tex]\[v_x = \frac{5.0\,m}{0.96\,s}\][/tex]
[tex]\(v_x\)[/tex] is approximately 5.21 m/s.
Calculate the overall speed when the pebbles hit the window.
To find the overall speed (v), we use the Pythagorean theorem because the pebbles' motion consists of both horizontal and vertical components:
[tex]\[v = \sqrt{v_x^2 + v_y^2}\][/tex]
Where:
- [tex]\(v_x\)[/tex] is the horizontal velocity (5.21 m/s, as calculated).
- [tex]\(v_y\)[/tex] is the vertical velocity. Since the pebbles are thrown horizontally, \[tex](v_y[/tex]= 0.
Now, calculate v:
[tex]\[v = \sqrt{5.21\,m/s)^2 + 0^2}\][/tex]
v is approximately 5.21 m/s.
So, the speed of the pebbles when they hit Juliet's window is approximately 5.21 m/s.
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The question probable may be:
Romeo gently throws pebbles at Juliet's window and wants the pebbles to hit the window with only a horizontal component of velocity. He is standing at the end of a rose garden, 4.5 meters below the window and 5.0 meters away from the base of the wall. What is the speed of the pebbles when they hit the window?
A model rocket is fired vertically upward from rest. Its acceleration for the first three seconds is a(t) = 66 t, at which time the fuel is exhausted and it becomes a freely "falling" body. 15 seconds later, the rocket's parachute opens, and the (downward) velocity slows linearly to -23 ft/s in 5 s. The rocket then "floats" to the ground at that rate.
Determine the position function s and the velocity function v (for all times t).
(x=yt-2)^2(56-tea)^2x10r
Using the given information, we determined the position and velocity functions of the model rocket at different time intervals. The velocity function varies during the rocket's upward acceleration, free fall, and the subsequent parachute slowing. The position function gives the height of the rocket at any time.
Explanation:To determine the position function s(t) and the velocity function v(t), we need to analyze the rocket's motion in different time intervals:
From time t = 0 to t = 3 seconds: The acceleration is given by a(t) = 66t. To find the velocity function, we integrate the acceleration function, v(t) = ∫ 66t dt = 33t2 + C1, where C1 is a constant of integration. We can determine C1 by using the initial condition of the rocket being at rest at t = 0 (initial velocity is 0), which gives us C1 = 0. So, v(t) = 33t2.From time t = 3 to t = 18 seconds: The rocket becomes a freely falling body. This means it is subject to a constant acceleration due to gravity, a(t) = -32 ft/s2. The velocity function can be found by integrating the acceleration, resulting in v(t) = -32t + C2. To determine C2, we use the fact that at t = 3 seconds, the velocity is 0 (since the fuel is exhausted). Plugging in these values, we find C2 = 96. Thus, v(t) = -32t + 96.From time t = 18 to t = 23 seconds: The velocity decreases linearly from -23 ft/s to 0 ft/s in 5 seconds. This means the acceleration is given by a(t) = (-23 - 0) / 5 = -4.6 ft/s2. Integrating the acceleration function, we get v(t) = -4.6t + C3. Using the fact that at t = 23 seconds the velocity is 0, we find C3 = 105.8. Thus, v(t) = -4.6t + 105.8.To find the position function s(t), we integrate the velocity function for each time interval:
From time t = 0 to t = 3 seconds: s(t) = ∫ (33t2) dt = 11t3 + C4. Using the initial condition s(0) = 0, we find C4 = 0. Therefore, s(t) = 11t3.From time t = 3 to t = 18 seconds: s(t) = ∫ (-32t + 96) dt = -16t2 + 96t + C5. Since the rocket is at rest at t = 3 seconds, we have the condition s(3) = 0, which gives us C5 = 1176. Hence, s(t) = -16t2 + 96t + 1176.From time t = 18 to t = 23 seconds: s(t) = ∫ (-4.6t + 105.8) dt = -2.3t2 + 105.8t + C6. Since the rocket starts floating to the ground at t = 18 seconds, we have the condition s(18) = 0, giving us C6 = -685. Thus, s(t) = -2.3t2 + 105.8t - 685.The position function s(t) represents the height of the rocket at any time t, while the velocity function v(t) represents the rate at which the height is changing with respect to time.
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A tennis ball has a mass of 0.058 kg and is moving to the right at 40 m/s. What is the momentum
Explanation:
Mass = 0.058Kg
Velocity = 40m/s
Momentum P = ?
P = mv
P = 0.058 × 40
P = 2.32Kgm/s
A plane lands at a speed of 38 km/s and comes to rest (0m/s) 36.3 seconds later. What is the acceleration during landing?
20 points!!!!!!!!
Acceleration = (change in speed) / (time for the change)
Change in speed = (speed at the end) - (speed at the beginning)
Change in speed = (0 km/sec) - (38 km/sec) = -38 km/sec
Acceleration = (-38 km/sec) / (36.3 sec) = -1,046.8 m/s²
Now, before we split up our points and go home, let's see what we've actually got here.
-- The plane's landing speed is about 111 times the speed of sound !
-- It rolls to rest 36.3 seconds after it touches down at this speed.
-- In order to do that, it pulls about 107 G's !
It seems to me that during the ground roll, the flight crew's eyeballs fall out, then they get ripped out of their seat belts and crash through the windshield, and the plane continues on with no life forms aboard. Then, maybe 1 second later, the drogue parachute tears off, the tires on the landing gear blow out and get shredded, the remaining fuel sloshes through the walls of the tanks and evaporates catastrophically, the wings fall off and scrape along the ground in a shower of sparks, the cloud of fuel vapor ignites and then erupts in a ball of flame, the people downtown notice it on the horizon and marvel at it, and then any remaining flaming pieces of the plane come to rest in the dense pine forest and the apartment complex 2 miles past the end of the runway.
This is not my business. I only used the numbers you gave me in the question. My math and physics are flawless, I gave you a theoretically bullet-proof answer, and this is a privilege and a pleasure for you and will stand you in good stead. You're welcome.
I need help with my physics. It’s on waves :(
Answer:
E is the Crest.
A 60-Watt bulb illuminates a surface a distance d away with
an illuminance of 3600 lux. What would be the illuminance
on a surface a distance 0.5•d away (i.e., one-half the
distance away) when illuminated by a 120-Watt bulb?
Answer:
Explanation:
Relation between power and illumination and distance is as follows
[tex]I = \frac{P}{R^2}[/tex]
For first case
[tex]3600 = \frac{60}{d^2}[/tex]
for second case
[tex]I = \frac{120}{(0.5d)^2}[/tex]
[tex]\frac{I}{3600} = \frac{d^2}{60} \times \frac{120}{.25d^2}[/tex]
I = 3600 x 8
= 28800 lux .
Final answer:
The illuminance on a surface from a 120-Watt bulb at half the distance of an initial setup with a 60-Watt bulb would be 28800 lux, due to the Inverse Square Law for Light and doubling of the bulb wattage.
Explanation:
The question is asking us to determine the illuminance on a surface from a 120-Watt bulb at half the distance of a previous setup with a 60-Watt bulb, which originally had an illuminance of 3600 lux. According to the Inverse Square Law for Light, illuminance changes with the inverse square of the distance. If the distance is halved (d/2), the illuminance increases by a factor of 4 (since (1/0.5)2 = 4). However, since we are also doubling the wattage of the bulb from 60-Watt to 120-Watt, and assuming that the bulb’s efficiency (lumens per Watt) stays the same, the illuminance would double again. Therefore, the new illuminance would be 3600 lux x 4 (due to distance) x 2 (due to wattage), equaling 28800 lux.
Need help with Physics. 100 points + Brainliest
1. Two point charges are 10.0 cm apart and have charges of 2.0 µC and –2.0 µC, respectively. What is the magnitude of the electric field at the midpoint between the two charges? (Use G.U.E.S.S.)
Answer:
I wrote down the answer and attached it below.
Explanation:
Hope this Helps!!!!
⬇⬇⬇⬇⬇⬇⬇⬇
Answer:
Every electric charge has a electric field.
The charges in the electric field are affected each other.
As you move away from the electric charge, the intensity of the electric field decreases.
The electric field is a vector quantity.
The electric field of each charge is calculated to find the intensity of the electric field at a point.
The vectorial sum of the vectors are found.
The electric field of the positive charge is directed outward from the charge.
Explanation:
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A test model for a new experimental gasoline engine does 45 J of work in one cycle for every 76 J of heat it takes in. What is the engines efficiency?
Answer:
The efficiency of the engine is 59.2%.
Explanation:
We have,
Work done by the gasoline engine is 45 J and the for every 76 J of heat it takes in.
It is required to find the efficiency of the engine. Efficiency of the engine is given by the ratio of work done to the heat taken i. Its formula is given by :
[tex]\eta=\dfrac{W}{Q}\\\\\eta=\dfrac{45}{76}\\\\\eta=0.592\\\\\eta=59.2\%[/tex]
So, the efficiency of the engine is 59.2%.
Final answer:
The efficiency of the engine is approximately 59.21%, calculated by dividing the work done by the engine (45 J) by the heat input (76 J) and then multiplying by 100.
Explanation:
The efficiency of a heat engine is the ratio of work output to heat input, expressed as a percentage. To calculate the engine's efficiency, you divide the work done by the engine by the heat energy that was put into the engine, and then multiply by 100 to convert the decimal to a percentage. In the given problem, the engine does 45 J of work and takes in 76 J of heat, which means the efficiency (η) is calculated as:
η = (Work done / Heat input) × 100
η = (45 J / 76 J) × 100
η = (0.59210526315...) × 100 ≈ 59.21%
The engine's efficiency is therefore approximately 59.21%.
A5 cm object is 18.0 cm from a convex lens, which has a focal length of 10.0 cm.
What is the distance of the image from the lens? Round your answer to three significant figures.
cm
What is the height of the image? Round your answer to three significant figures.
cm
Intro
Answer:
answer in picture
Explanation:
Based on the solar system, which planet would you expect to have the slowest orbital speed? *
Mercury
Neptune
Jupiter
Earth
Neptune, being the furthest from the Sun, has the slowest orbital speed at approximately 5 kilometers per second, in accordance with Kepler's laws.
Explanation:Based on Kepler's laws of planetary motion, the planet with the slowest orbital speed in our solar system is Neptune. This is because the speed at which a planet orbits the Sun is inversely related to its distance from the Sun. As Neptune is the furthest planet from the Sun with a vast orbital period of 165 Earth-years, it also has the slowest average orbital speed, which is approximately 5 kilometers per second. In contrast, Mercury, with an orbital period of only 88 Earth-days, moves much faster with an average speed of 48 kilometers per second.
Vicente is going to spend the afternoon in his yard. He has the choice to get in the pool, lay on a cotton chaise longue, sit on the porcelain tile bordering the pool, or sit on a plastic chair. The specific heats of these items are:
Water = 4.19 J/g•°C
Cotton = 1.30 J/g•°C
Porcelain = 1.07 J/g•°C
Plastic = 1.67 J/g•°C
Based on the specific heat values given, where is the coolest location for Vicente to be?
pool
cotton chaise lounge
porcelain tile
plastic chair
Answer:
Pool
Explanation:
I just answered it
On the basis of specific heat values, the coolest location for Vicente to be is known as Pool. Thus, the correct option for this question is A.
What is Specific heat?Specific heat may be defined as the quantity of heat that is ultimately required in order to increase the temperature of one gram of a substance by one Celsius degree. The units of specific heat are usually calories or joules per gram per Celsius degree.
According to the question, the specific heat of water is maximum, while the specific heat of porcelain is minimum. This represents that water is the coolest place in the Vicente while porcelain tile is the warmest place in the Vicente.
Therefore, on the basis of specific heat values, the coolest location for Vicente to be is known as Pool. Thus, the correct option for this question is A.
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A force of 1200 N is applied to a drum of radius 80 cm which has a 12 kg mass, m1, attached by a cord
wound on the drum. A second drum of radius 41 cm is bolted on the first and has a 39 kg mass, m2, attached
by a cord wound on it. What is the resulting torque applied to the system?
Answer:
1.022 x 103 N.m
Explanation:
Solution
Given:
The weight of the block of mass m₂ is :
w₂ = m₂*g
Where
w₂ = 39 x 9.8 = 382.2 N
Then,
The weight of the block of mass m₁
w₁= m₁*g;
so,
w₁ = 12 x 9.8 = 117.5 N
Thus,
The tension wrapped in cord on drum (80 cm) T₁ = F - w₁
Now,
T₁ = 1200 - 117.5
T₁ = 1082.5 N
The tension wrapped in the cord on drum (41 cm) T₂ = w₂;
T₂ = 382.2 N
Hence,
We calculate net torque on the center of the drum:
The net torque = T₁ x 0.8 + T₂ x 0.41;
= 1082.5 x 0.8 + 382.2 x 0.41;
= 1.022 x 103 N.m
Therefore, the resulting torque applied to the system is 1.022 x 103 N.m
The weight of a bicyclist and bicycle together is 51.0kg how much work has been done if the bicyclist slows down the bicycle from a seed of 3.95 m/s to 1.31 m/s
Answer:
The work done is 354.1032 Joules
Explanation:
To answer the question we note that the amount of work done is equivalent to the reduction in the kinetic energy of the bicyclist and bicycle.
Therefore, initial kinetic energy. KE[tex]_i[/tex] of the system is given by the following relation;
[tex]KE_i=\frac{1}{2} mv_{1}^{2}[/tex]
Final kinetic energy [tex]KE_f = \frac{1}{2} mv_{2}^{2}[/tex]
Where:
v₁ = Initial velocity = 3.95 m/s
v₂ = Final velocity = 1.31 m/s
m = Mass of the bicyclist and bicycle = 51.0 kg
Change in kinetic energy ΔKE;
[tex]\Delta KE = KE_f - KE_i[/tex]
[tex]\Delta KE =\frac{1}{2} mv_{2}^{2}-\frac{1}{2} mv_{1}^{2} = \frac{1}{2} m(v_{2}^{2}-v_{1}^{2}) = \frac{1}{2} \times 51 \times (1.31^{2}-3.95^{2}) = -354.1032 \ J[/tex]
Therefore, work done = -ΔKE = 354.1032 Joules.
What are all atoms with the same number of protons called
A. cells
B. elements
c. molecules
OD. compounds
Answer:
B elements
...............
A wire on the left with 9 coils and labeled primary winding. Another coil is near it with 3 coils labeled secondary winding V subscript 2 baseline equals 120. Use the values provided to calculate the initial voltage at the primary winding.
V1 = ? V
Answer:
V1 = 360 V
Explanation:
Applying,
Vs/Vp = Ns/Np................ Equation 1.
Vs = Voltage of the secondary coil, Vp = voltage of the primary coil, Ns = number of coils in the secondary winding, Np = number of coils in the primary winding
make Vp the subject of the equation
Vp = VsNp/Ns............ Equation 2
Given: Vs = 120 V, Np = 9 coils, Ns = 3 coils
Substitute into equation 2
Vp = 120(9)/3
Vp = 360 V.
Hence, V1 = 360 V
Answer:
V1 = 360 V
Explanation:
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One gram of Uranium averages release 1.01 KJ (10^7) of energy. How much mass could be converted to energy to release this much energy?
Answer:
The amount of mass that needs to be converted to release that amount of energy is [tex]1.122 X 10^{-7} kg[/tex]
Explanation:
From Albert Einstein's Energy equation, we can understand that mass can get converted to energy, using the formula
[tex]E= \Delta mc^{2}[/tex]
where [tex]\Delta m[/tex] = change in mass
c = speed of light = [tex]3 \times 10 ^{8}m/s[/tex]
Making m the subject of the formula, we can find the change in mass to be
[tex]\Delta m = \frac{E}{c^{2}}= \frac{1.01 \times 10^{3} \times 10^{7}}{(3 \times 10^{8})^{2}}= 1.122 \times 10 ^{-7}kg[/tex]
There fore, the amount of mass that needs to be converted to release that amount of energy is 1.122 X 10 ^-7 kg
Which planets receive more of the Sun's concentrated light?
Answer: Mercury is closest to the Sun and receives more of the Sun's concentrated light.
Explanation: I hope this helps :]
Answer:
The planets closest in the solar system rotation, or the "inner four"
Mercury recieves the most though.
(The inner four include Mercury, Venus, Earth, and Mars)
i hope this helps!
Explanation:
Cleo stated that light travels through air in straight paths, and when it moves from air to water, light changes direction, speeds up, and bends toward the normal.
Which statement best describes Cleo’s mistake?
Light travels through air and water in angled, scattered paths.
Light does not change direction when it moves from air into water.
Light slows down when it moves from air into water.
Light bends away from the normal when it moves from air into water.
Answer:
Light slows down when it moves from air into water.
Explanation:
It is the property of light that travels faster in a less dense medium.
In a more dense medium, the speed of the light slows down and bends towards the normal.
The air is less dense medium and water is a more dense medium.
When light passes from air to water, the light bends.
This is known as the refraction of light.
Answer:
C is the correct answer on Ed gen uity
A current in a wire increases from 2 A to 6 A. How will the magnetic field 0.01 m from the wire change?
Answer:
It increases to three times its original value. Given the same radius of wire and other constant property. current is directly proportional to the magnetic field.
B1=B2
MoI1/2pir=MoI2/2pir; cancel the same values on both sides
B2/B1=6/2 =3
Explanation:
The magnetic field produced by a current-carrying wire depends on the current and distance from the wire.
Explanation:
The magnetic field produced by a current-carrying wire is given by the formula B = μi / (2πR), where B is the magnetic field strength, μ is the permeability of free space, i is the current in the wire, and R is the distance from the wire.
In this case, the current in the wire increases from 2 A to 6 A. As a result, the magnetic field at a distance of 0.01 m from the wire will also increase. However, the exact value of the magnetic field change can only be determined if the initial distance from the wire is known.
It is important to note that the magnetic field strength is inversely proportional to the distance from the wire, meaning that as the distance increases, the magnetic field strength decreases.
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What are two ways in which you can increase the potential energy of a marble on a ramp?
Answer:
As the marble starts rolling down the roller coaster, the amount of potential energy stored in the marble decreases while its kinetic energy increases. Potential energy is also converted into heat energy due to friction.
Explanation:
As the marble rolls down the hill its potential energy is converted to kinetic energy (its height decreases, but its velocity increases). When the marble goes back up the loop its height increases again and its velocity decreases, changing kinetic energy into potential energy.
The two (2) ways in which the potential energy of a marble on a ramp can be increased are:
I. By placing the marble higher on the ramp.
II. By increasing the mass of the marble.
Potential energy can be defined as a type of energy possessed by an object (body) as a result of its position (height) above the earth.
Mathematically, potential energy (P.E) is calculated by using the following formula:
[tex]P.E = mgh[/tex]
Where:
m is the mass of an object. g is the acceleration due to gravity. h is the height of an object.Hence, potential energy (P.E) is highly dependent on two (2) main factors and these are:
1. Height above the ground.
2. The mass of an object.
In conclusion, the two (2) ways in which the potential energy of a marble on a ramp can be increased are:
Increasing the height of the marble, by placing the marble higher on the ramp.By increasing the mass of the marble such as adding more marbles.Read more: https://brainly.com/question/23153766
What has more gravity-Earth's moon or the Sun?Why?
Answer:
Even though the sun is much more massive and therefore has stronger overall gravity than the moon, the moon is closer to the earth so that its gravitational gradient is stronger than that of the sun.
Explanation:
An arrow is fired vertically upwards by a bow and reaches an altitude of 134 m. Find the initial speed of the arrow on the ground level.
Answer:
Explanation:
Let the initial speed be u . final speed = 0
v² = u² - 2gh
v is final speed , u is initial speed , h is height .
0 = u² - 2g x 134
u² = 2 x 9.8 x 134
u = 51.25 m /s .
The initial speed of the arrow fired vertically upwards and reaching an altitude of 134m is approximately 51.7 m/s. This was calculated using the second equation of motion and taking into account gravitational acceleration.
Explanation:This physics problem relates to projectile motion and can be solved using the concepts of kinematic equations. The known variables from the question are the final altitude (y = 134m) and the acceleration due to gravity (g = 9.81 m/s^2), which is always acting downward. We're looking for the initial speed (v0) of the arrow when it was released from the ground level.
Due to the arrow being launched upwards and then coming back down, the final velocity would be the negative of its initial velocity. Hence, we can say that v = -v0
According to the second equation of motion, v^2 = v0^2 + 2gy. Replacing known values, we get (-v0)^2 = v0^2 + 2*(-9.81)*134. From which we can solve for v0.
After simplifying the equation, we find that v0 = sqrt(v0^2 - 2*(-9.81)*134), this leads us to find that the initial speed of the arrow was approximately 51.7 m/s.
Learn more about Projectile Motion here:https://brainly.com/question/29545516
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In chemical reactions, the products _____.
A. contain fewer atoms than the reactants
B. contain more atoms than the reactants
O c. are found on the left-hand side of the equation for the reaction
D. are found on the right-hand side of the equation for the reaction
In chemical reactions, the products are the substances that are found on the right-hand side of the chemical equation, indicating the outcome of the reaction.
In chemical reactions, the products are the substances that are found at the end of the reaction. The correct answer is D. The reactants, which are the chemical before the reaction starts, are situated on the left side of the chemical equation, represented by a plus sign. An arrow points from the reactants to the products, indicating the direction of the reaction. The products, which are the chemical after the reaction ends, appear on the right-hand side of the equation. For instance, in the combustion of methane, the chemical equation is CH4 + 2O2
ightarrow CO2 + 2H2O, where CH4 and O2 are the reactants and CO2 + 2H2O are the products.
A tennis ball has a mass of 0.058 kg and is moving to the right at 40 m/s. What is
the momentum of the tennis ball? (p = mv)
2.32
690
1.35
2320
A pinanong ball has a mass of 0 045 ka Approximately how fast must the ping
Answer:
since momentum = mass x velocity
m = 40m/s 0.058kg
m = 2.32