The total length of the spring when a 17.20 kg mass is suspended from it is 34.85 cm, calculated using Hooke's Law and the original unstretched length of the spring.
Explanation:To find the total length of the spring when a 17.20 kg mass is suspended from it, we use Hooke's Law, which is F = kx, where F is the force applied to the spring, k is the spring constant, and x is the extension from the spring's original unstretched length. First, we need to calculate the extension caused by the 8.40 kg mass: F = (8.40 kg)(9.8 m/s2) = 82.32 N. With k = 875 N/m, the extension (x) is F/k = 82.32 N / 875 N/m = 0.0941 m or 9.41 cm. This extension is in addition to the unstretched length of the spring (L0), given by the total length minus the extension for the 8.40 kg mass: L0 = 0.250 m - 0.0941 m = 0.1559 m.
Next, for the 17.20 kg mass, the force is F = (17.20 kg)(9.8 m/s2) = 168.56 N. The additional extension caused by this mass is x = F/k = 168.56 N / 875 N/m = 0.1926 m or 19.26 cm. Therefore, the total length of the spring with the 17.20 kg mass is L = L0 + x = 0.1559 m + 0.1926 m = 0.3485 m or 34.85 cm.
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A 1490-kilogram truck moving with a speed of 27.0 m/s runs into the rear end of a 1280-kilogram stationary car. if the collision is completely inelastic, how much kinetic energy is lost in the collision?
The loss in kinetic energy in an inelastic collision is equal to 251104 J.
What is law of conservation of momentum?According to the law of conservation of linear momentum, the sum of the momentum before and after an inelastic collision must be equal.
m₁u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂
where m₁ and m₂ is the mass of the collided bodies, u₁ & u₂ are their initial speed while v₁ & v₂ is their final speed.
Given the initial velocity of the truck is v₁ = 27 m/s and the other car is at rest, u₂ = 0 m/s.
The mass of the truck, m₁ = 1490 Kg
The mass of the stationary car, m₂ = 1280 Kg
From the law of conservation of momentum, find the final speed after a collision:
m₁ u₁ + m₂ u₂ = (m₁ + m₂)v'
1490 × 27 + 1280 ×0 = (1490 + 1280) v'
v' = 14.52 m/s
The loss in the kinetic energy = [tex]=\frac{1}{2} mv_1^2-\frac{1}{2} (m_1+m_2)^2v^'^2[/tex]
[tex]==\frac{1}{2} \times 1490\times(27)^2-\frac{1}{2} (2770)^2(14.52)^2[/tex]
[tex]= 543105 -292000\\=251104 J[/tex]
Therefore, the loss in the kinetic energy in the collision is equal to 251104 J.
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A daredevil decides to jump a canyon of width 8.88 m. to do so, he drives a motorcycle up an incline sloped at an angle of 22.5 ◦ . the acceleration of gravity is 9.8 m/s 2 . what minimum speed must he have in order to clear the canyon? answer in units of m/s.
Final Answer:
The daredevil must have a minimum speed of approximately 14.7 m/s to clear the canyon.
Explanation:
To clear the canyon, the daredevil's vertical displacement at the edge of the canyon must be equal to the width of the canyon. Using the kinematic equation for vertical motion [tex]\( y = v_0t + \frac{1}{2}gt^2 \)[/tex], where y is the vertical displacement, [tex]\( v_0 \)[/tex] is the initial vertical velocity, g is the acceleration due to gravity, and t is the time of flight, and solving for [tex]\( v_0 \)[/tex], we get [tex]\( v_0 = \sqrt{2gy} \)[/tex]. Substituting the given values [tex]\( g = 9.8 \, \text{m/s}^2 \) and \( y = 8.88 \, \text{m} \)[/tex], we find [tex]\( v_0 \approx 14.7 \, \text{m/s} \)[/tex], which is the minimum speed required to clear the canyon.
Which of the following is not a danger associated with hurricanes?
a) droughts
b) inland flooding
c) storm surges
d) tornadoes
The correct answer is a) droughts. Hurricanes are typically associated with heavy rain and high winds, which can lead to flooding.
Explanation:Hurricanes are powerful storms that cause a variety of hazards, including inland flooding, storm surges, and tornadoes.
Inland flooding can occur when the heavy rainfall associated with a hurricane overflows rivers and streams. Storm surges are the rise in sea level that happens when a hurricane's strong winds push water onshore. This can cause significant flooding and damage in coastal areas. Tornadoes can be produced by hurricanes when thunderstorms present within the hurricane system become severe.
However, droughts are not typically a direct result of hurricanes. In fact, the heavy rainfall associated with hurricanes often alleviates drought conditions.
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Suppose a supernova occurs in a star that initially had 10 solar masses. why would the likely end result not be a black hole?
A star with an initial mass of 10 solar masses will likely form a neutron star instead of a black hole after a supernova due to the mutual repulsion between densely packed neutrons that can support the core against its own gravitational weight.
Explanation:
Given a star with initial 10 solar masses that ends its life in a supernova explosion, it is more likely to form a neutron star rather than a black hole. Most stars end their life as white dwarfs or neutron stars. In the case of a very massive star, if the core's remaining mass is more than about three times that of the Sun, it may collapse into a black hole. However, if the mass is less than about three solar masses, the mutual repulsion between densely packed neutrons can support the core against its own weight, preventing it from becoming a black hole.
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Which of the following statements proves that scientific knowledge changed due to the discovery of the fossil of a hadrosaur in North Dakota?
Hadrosaurs were better runners than earlier thought.
Hadrosaurs had no pattern on their skin, which was not expected.
The length of the hadrosaur was shorter than previously thought.
The muscular structure of the hadrosaur was less developed than expected.
how was dance used in primitive cultures
PLZ HELP: Which food items would be appropriate for a spacecraft? Check all that apply. A< brownie, B< dry salt and pepper, C
A uniform disk is constrained to rotate about an axis passing through its center and perpendicular to the plane of the disk. if the disk starts from rest and is then brought in contact with a spinning rubber wheel, we observe that the disk gradually begins to rotate too. if after 22 s of contact with this spinning rubber wheel, the disk has an angular velocity of 3.0 rad/s, find the average angular acceleration that the disk experiences. (assume the positive direction is in the initial direction of rotation of the disk. indicate the direction with the sign of your answer.)
Sadi Carnot came up with a hypothetical heat engine that had the maximum possible efficiency. What discovery did Carnot make that helped him recognize how to create this "perfect" heat engine?
Answer:
The difference in the temperatures between the hot and cold reservoirs determined how well a heat engine would work
Explanation:
I got a 100% on my test
A force of 660 n stretches a certain spring a distance of 0.300 m. what is the potential energy of the spring when a 70.0 kg mass hangs vertically from it?
A sphere mass m1 and a block of mass m2 are connected by a light cord that passes over a pulley. The radius of the pulley is R, and the mass of the thin rim is M.. The block slides on a frictionless, horizontal surface.
Derive an expression for the linear acceleration of the two objects
The expression for the linear expression of the two objects will be
[tex]a=\dfrac{m_1g}{m_2+m_1-M}[/tex]
What is acceleration?Acceleration is defined as the change of the velocity with the time. Acceleration is a vector quantity and is defined by both the magnitude and the direction.
The mass of sphere is m1 radius is R and mass m2 is connected by light chord.
Now by using free body diagram
The tension in the chord will be
[tex]m_1g-T_1=m_1a[/tex]
[tex]T_1=m_1(g-a)[/tex]
For tension T2 we will have
[tex]T_2=m_2a[/tex]
Now the torque will be
[tex]T_{net}=I\alpha[/tex]
[tex]T_2R-T_1R=I(\dfrac{a}{R})[/tex]
[tex]T_2R-T_1R=MR^2(\dfrac{a}{R})[/tex]
[tex]T_2-T_1=Ma[/tex]
[tex]m_2a-m_1(g-a)=Ma[/tex]
[tex]m_2a-m_1g+m_1a=Ma[/tex]
[tex]a(m_2+m_1-M)=m_1g[/tex]
[tex]a=\dfrac{m_1g}{m_2+m_1-M}[/tex]
Thus the expression for the linear expression of the two objects will be
[tex]a=\dfrac{m_1g}{m_2+m_1-M}[/tex]
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It is friction that provides the force for a car to accelerate, so for high-performance cars the factor that limits acceleration isn't the engine; it's the tires. you may want to review ( pages 138 - 142) . part a for typical rubber-on-concrete friction, what is the shortest time in which a car could accelerate from 0 to 60 mph? suppose that μs=1.00 and μk=0.80.
The shortest time in which a car could accelerate from 0 mph to 60 mph is [tex]13.7s[/tex].
Further explanation:
The opposite force acting on the body is known as frictional force. It always acts in the opposite direction of motion of body.
Concept used:
The force applied to a body to keep it at rest is known as the static friction force. It always acts opposite to the direction of motion of body. It is defined as the product of coefficient of friction and the normal force acting on the body.
The expression for the normal reaction of the body is given as.
[tex]N = mg[/tex]
The expression for the net force is given as.
[tex]{F_{net}} = ma[/tex] …… (1)
The expression for the static friction is given as.
[tex]{F_s} = {\mu _s}N[/tex]
The expression for the balanced forces is given as.
[tex]{F_{net}} = {F_s} - {F_r}[/tex]
Substitute[tex]{\mu _s}N[/tex] for [tex]{F_s}[/tex] and for[tex]{F_r}[/tex] in the above expression.
[tex]\begin{aligned}{F_{net}}&={\mu _s}N-{\mu _r}N\\&= \left( {{\mu _s} - {\mu _r}} \right)N \\ \end{aligned}[/tex]
Substitute [tex]mg[/tex] for [tex]N[/tex] in above expression.
[tex]{F_{net}}=\left({{\mu _s}-{\mu _r}}\right)\left( {mg}\right)[/tex] …… (2)
Compare equation (1) and (2) we get.
[tex]a=g\left({{\mu _s}-{\mu _r}}\right)[/tex] …… (3)
Here, [tex]a[/tex] is the acceleration of the body, g is the acceleration due to gravity, [tex]{\mu _s}[/tex] is the coefficient of static friction and is the coefficient of reactive force.
The expression for the first equation of motion is given as.
[tex]v = u + at[/tex]
Rearrange the above expression for time is given as.
[tex]\fbox{\begin\\t = \dfrac{{\left( {v - u} \right)}}{a}\end{minispace}}[/tex] …… (4)
Here, [tex]v[/tex] is the final velocity, [tex]u[/tex] is the initial velocity and [tex]t[/tex] is the time.
Substitute [tex]1[/tex] for [tex]{\mu _s}[/tex], [tex]0.8[/tex] for[tex]{\mu _r}[/tex] and [tex]9.8\,{\text{m/}}{{\text{s}}^{\text{2}}}[/tex] for [tex]g[/tex] in equation (3).
[tex]\begin{aligned}a&=\left( {9.8\,{\text{m/}}{{\text{s}}^{\text{2}}}}\right)\left( {1 - 0.8}\right)\\&=1.96\,{\text{m/}}{{\text{s}}^{\text{2}}} \\ \end{aligned}[/tex]
Substitute [tex]0\,{\text{mph}}[/tex] for [tex]u[/tex], [tex]60\,{\text{mph}}[/tex] for [tex]v[/tex] and [tex]1.96\,{\text{m/}}{{\text{s}}^{\text{2}}}[/tex] for [tex]a[/tex] in equation (4).
[tex]\begin{aligned}t&=\frac{{\left( {60\,{\text{mph}}-0\,{\text{mph}}}\right)}}{{1.96\,{\text{m/}}{{\text{s}}^{\text{2}}}}}\\&=\frac{{60\,{\text{mph}}\left( {\frac{{0.447\,{\text{m/s}}}}{{1\,{\text{mph}}}}} \right)}}{{1.96\,{\text{m/}}{{\text{s}}^{\text{2}}}}}\\&= 13.7\,{\text{s}} \\ \end{aligned}[/tex]
Thus, the time required to accelerate a car is [tex]\fbox{\begin\\13.7\, {\text{s}}\end{minispace}}[/tex].
Learn more:
1. Conservation of momentum https://brainly.com/question/9484203.
2. Motion under friction https://brainly.com/question/7031524.
3. Net force on the body https://brainly.com/question/4033012.
Answer Details:
Grade: College
Subject: Physics
Chapter: Kinematics
Keywords:
Force, friction, Acceleration, acceleration due to gravity, normal, weight, mass, motion, sliding, sled, hill, inclined, plane, coefficient of friction, angle of inclination, 13.68 s, 13.69 s.
Final Answer:
So, under ideal conditions with the assumption of maximum static friction being available throughout the acceleration, the shortest time in which a typical car could accelerate from 0 to 60 mph on rubber-on-concrete would be approximately 2.734 seconds.
Explanation:
To solve this problem, we need to understand how the force of friction allows a car to accelerate and then apply the equations of motion to determine the shortest time it would take for the car to accelerate from 0 to 60 miles per hour (mph).
First, we need to define our variables and constants:
- The static friction coefficient between rubber and concrete, μs, which is 1.00. This is the factor that will limit our acceleration since it represents the maximum frictional force that can be exerted before sliding begins.
- The acceleration due to gravity, g, which is 9.81 m/s^2.
- The initial speed of the car, 0 mph, which needs to be converted to meters per second (m/s).
- The final speed of the car, 60 mph, which also needs to be converted to meters per second.
The force of static friction (f_friction) responsible for the acceleration can be calculated by multiplying the static friction coefficient (μs) with the normal force (N). The normal force, in this case, is equal to the weight of the car, which is the mass (m) times the acceleration due to gravity (g). Since we are looking for the highest possible acceleration, we can assume that the force of static friction is at its maximum value.
f_friction = μs * m * g
However, we don't need to know the mass of the car because it will cancel out in the equation of motion. The maximum possible acceleration (a_max) happens when the force of static friction is at its highest, and it can be calculated using:
a_max = f_friction / m = μs * g
Now we have the maximum possible acceleration the tires can provide on concrete, which is:
a_max = 1.00 * 9.81 m/s^2
a_max = 9.81 m/s^2
Next, let's convert the final velocity from mph to m/s:
v_final(mph) = 60 mph
v_final(m/s) = v_final(mph) * 0.44704 (conversion factor from mph to m/s)
v_final(m/s) = 60 * 0.44704
v_final(m/s) ≈ 26.8224 m/s
With the initial velocity (v_initial) being 0 m/s (since we start from rest), we can use one of the kinematic equations to find the time (t):
v_final = v_initial + a_max * t
26.8224 m/s = 0 m/s + 9.81 m/s^2 * t
Solving for t, we get:
t = v_final / a_max
t ≈ 26.8224 m/s / 9.81 m/s^2
t ≈ 2.734 seconds
So, under ideal conditions with the assumption of maximum static friction being available throughout the acceleration, the shortest time in which a typical car could accelerate from 0 to 60 mph on rubber-on-concrete would be approximately 2.734 seconds.
What force is needed to accelerate a 55kg shopping cart 2.0m/s to the second power?
A spring that has a spring constant of 1400 N/m is stretched to a length of 2.5 m. If the normal length of the spring is 1.0 m, how much elastic potential energy is stored in the spring? 700 J 1050 J 1575 J 4375 J
what do you think will happen to dirt and rocks on the Mountainside when the ice melts
Final answer:
When the ice on a mountainside melts, dirt and rocks that were held in place by the ice become unstable and may move downhill, altering the landscape. Saturated soil can cause mud flows and contribute to erosion. Glaciers also play a significant role in sculpting landscapes by carrying rock and sediment as they move.
Explanation:
When ice on a mountainside melts, the dirt and rocks that were previously held in place by the ice may become less stable. Erosion processes, such as water runoff and gravity, can lead to increased movement of these materials. As the water from the melting ice saturates the mountain's soil and rock, it can trigger debris flows or mud flows. These events have the potential to transport large amounts of material downslope, often resulting in significant changes to the landscape. The movement of this material can lead to the formation of new features, such as valleys or depressions, and can also contribute to the reshaping or smoothing of existing mountainous terrain.
It's also worth noting that glaciers, which are large bodies of ice that move slowly over land, have historically been powerful agents of erosion. As they advance and retreat, glaciers grind down rocks and carry sediment far from its origin, which is evidence of their strong impact on shaping the landscapes.
A child sets off the firecracker at a distance of 100 m from the family house. what is the sound intensity β100 at the house?
To solve this problem, we use the formula:
I100 / I1 = [P / 4π(100m)^2] / [P / 4π(1m)^2]
I100 / I1 = 1 / 100^2
I100 / I1 = 10^-4
Therefore the change in intensity from 1m to 100m in decibels is:
B100 – B1 = 10 log(10^-4) dB = -40 dB
So the intensity at 100m is calculated as:
B100 = B1 – 40 dB = 140 dB – 40 dB = 100 dB
Answer:
100 dB
The intensity of the sound produced due to the firecracker at the distance of [tex]100\text{ m}[/tex] is [tex]\fbox{\begin\\100\text{ dB}\end{minispace}}[/tex].
Further Explanation:
The vibration, produced in the medium, which travels as an wave of pressure or density through a medium is known as sound. The sound is a longitudinal wave and it requires a medium for its propagation.
Given:
The distance between the place where firecracker is set off by a child and the family house is [tex]100\text{ m}[/tex].
The intensity of the sound produced by the firecracker at the distance [tex]1\text{ m}[/tex] is[tex]140\text{ dB}[/tex].
Concept:
The intensity of the sound wave is defined as the power carried by the sound waves in the direction perpendicular to the direction of propagation per unit time.
The intensity of the sound wave is:
[tex]\fbox{\begin\\I=\dfrac{P}{4\pi r^2}\end{minispace}}[/tex] ...... (1)
Here, [tex]I[/tex] is the intesnity of the sound wave, [tex]P[/tex] is the power carried by the sound wave and [tex]r[/tex] is the distance between source and the listener.
The intensity of the sound in decible at the house is:
[tex]\fbox{\begin\\\beta _{100}=\beta _{1}+10\log \dfrac{I_{100}}{I_{1}}\end{minispace}}[/tex] ...... (2)
Here, [tex]\beta _{100}[/tex] is the intensity of the sound at the distance of [tex]100\text{ m}[/tex], [tex]\beta _{1}[/tex] is the intensity of sound produced by the firecracker at the distance of [tex]1\text{ m}[/tex], [tex]I_{100}[/tex] is the intensity of sound produced by firecracker at [tex]100\text{ m}[/tex] and [tex]I_{1}[/tex] is the intensity of sound produced by firecracker at [tex]1\text{ m}[/tex].
The ratio of the intensity of sound at distance [tex]100\text{ m}[/tex] and [tex]1\text{ m}[/tex] is:
[tex]\fbox{\begin\\\dfrac{{{I_{100}}}}{{{I_1}}}=\frac{{r_1^2}}{{r_2^2}}\end{minispace}}[/tex] …… (3)
Calculation:
Substitute the values in equation (3).
[tex]\begin{aligned}\frac{{{I_{100}}}}{{{I_1}}}&=\frac{{{{\left( 1 \right)}^2}}}{{{{\left( {100} \right)}^2}}}\\&={10^{ - 4}}\\\end{aligned}[/tex]
Substitute the values in equation (2).
[tex]\begin{aligned}{\beta _{100}}&=140\,{\text{dB}} - 40\,{\text{dB}} \\&=100\,{\text{dB}}\\\end{aligned}[/tex].
Thus, the intensity of the sound produced due to the firecracker at the distance of [tex]100\text{ m}[/tex] is [tex]\fbox{\begin\\100\text{ dB}\end{minispace}}[/tex]
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1. The motion of a body under friction brainly.com/question/4033012
2. A ball falling under the acceleration due to gravity brainly.com/question/10934170
3. Conservation of energy brainly.com/question/3943029
Answer Details:
Grade: College
Subject: Physics
Chapter: Waves and Oscillation
Keywords:
Intensity of sound, sound waves, vibration, firecracker, power carried by sound waves, 100db, 100 dB, 100dB, 100 m, bursting of firecrackers, sound inside the house, 140 db, 140 dB.
A ball is thrown horizontally from a cliff at a speed of 10 m/s. you predict that its speed 1 s later will be slightly greater than 14 m/s. your friend says it will be 10 m/s. show who is correct.
Answer:
Speed is slightly greater than 14 m/s.
Explanation:
The ball will under go projectile motion. The horizontal velocity remains constant while there would be increase in vertical velocity due to acceleration due to gravity in downward direction.
Using first equation of motion, after 1 s, vertical velocity will be:
v = u +at
v=0+(9.8 m/s²)(1 s) = 9.8 m/s
Horizontal velocity = 10 m/s
Net velocity:
[tex]V= \sqrt{(9.8)^2+(10)^2}=\sqrt{196.04}=14.001 m/s[/tex]
Speed is slightly greater than 14 m/s.
Consider a father pushing a child on a playground merry-go-round. the system has a moment of inertia of 84.4 kg · m2. the father exerts a force on the merry-go-round perpendicular to its radius to achieve an angular acceleration of 4.44 rad/s2. (a) how long (in s) does it take the father to give the merry-go-round an angular velocity of 1.43 rad/s? (assume the merry-go-round is initially at rest.)
It takes 0.322 s to give the merry-go-round an angular velocity of 1.43 rad/s
[tex]\texttt{ }[/tex]
Further explanationCentripetal Acceleration can be formulated as follows:
[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]
a = Centripetal Acceleration ( m/s² )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
[tex]\texttt{ }[/tex]
Centripetal Force can be formulated as follows:
[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]
F = Centripetal Force ( m/s² )
m = mass of Particle ( kg )
v = Tangential Speed of Particle ( m/s )
R = Radius of Circular Motion ( m )
Let us now tackle the problem !
[tex]\texttt{ }[/tex]
Given:
moment of inertia = I = 84.4 kg.m²
initial angular velocity = ωo = 0 rad/s
angular acceleration = α = 4.44 rad/s²
final angular velocity = ω = 1.43 rad/s
Asked:
time taken = t = ?
Solution:
[tex]\omega = \omega_o + \alpha t[/tex]
[tex]1.43 = 0 + 4.44t[/tex]
[tex]1.43 = 4.44t[/tex]
[tex]t = 1.43 \div 4.44[/tex]
[tex]t = 0.322 \texttt{ s}[/tex]
[tex]\texttt{ }[/tex]
Learn moreImpacts of Gravity : https://brainly.com/question/5330244Effect of Earth’s Gravity on Objects : https://brainly.com/question/8844454The Acceleration Due To Gravity : https://brainly.com/question/4189441[tex]\texttt{ }[/tex]
Answer detailsGrade: High School
Subject: Physics
Chapter: Circular Motion
[tex]\texttt{ }[/tex]
Keywords: Gravity , Unit , Magnitude , Attraction , Distance , Mass , Newton , Law , Gravitational , Constant
An energy pyramid illustrates that energy in the form of _____ is lost to the surroundings as it's passed from one organism to the next
Two waves of equal magnitude but opposite phase interfere with one another to cause the waves to disappear. This is caused by:
each wave canceling the other out, causing the waves to disappear completely
refraction of waves multiplying each other's amplitude with the effect of canceling each other out
the Conner effect
destructive interference giving the effect of making the waves disappear, but each will travel on its way
How will sunlight most likely affect a black shirt on a hot summer day?
The sunlight is absorbed more on to the black color and no color is reflected back therefore, heat energy is released by the black color and make more hot.
What is light reflection?When a light ray is incident on a transparent or translucent material, the light ray will return back after some fraction of it is absorbed on the material and the light ray travel in the straight direction from the material make it gleams.
White light absorbs all colors and reflects back all colors. Thus, the mixing of all reflected colors make the material white in color. A black light absorbs all colors and reflect no color.
The absorbed light energy in the black body is released as heat energy instead. This make the black colored material more hotter than other colors. Hence, a black shirt is most affected by sunlight.
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For an increase in the bulk modulus of a material but without any change in the density, what happens to the speed of sound in that material?
The speed of sound within a substance depends on the bulk modulus and density of the material. An increase in bulk modulus, with density remaining constant, would increase the speed of sound within the material, given that the speed of sound is proportional to the square root of the bulk modulus.
Explanation:The speed of sound within a substance is primarily determined by two physical properties of the material, namely the bulk modulus and density. The bulk modulus measures a substance’s resistance to uniform compression. The formula used to calculate the speed of sound within a substance is v = sqrt(B/p), where 'v' represents the speed of sound, 'B' signifies the bulk modulus of the material, and 'p' indicates the density of the material.
As such, if the bulk modulus of a material were to increase while the density remained constant, the speed of sound within that material would also increase because the speed of sound is directly proportional to the square root of the bulk modulus. For instance, since solids and liquids are generally more rigid (i.e., have higher bulk modulus values) than gases, the speed of sound tends to be greater in these media than in gases, assuming density remains constant.
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A train accelerates from its metropolitan cruising speed of 22 m/s to its countryside cruising speed of 32 m/s. If it takes the train 142 seconds to do this, what is its acceleration?
10 m/s2
14.2 m/s2
4.4 m/s2
0.07 m/s2
Answer:
Acceleration of the train is 0.07 m/s²
Explanation:
Initial speed of the train, u = 22 m/s
Final speed of the train, v = 32 m/s
Time taken by the train to do the process is 142 seconds
We have to find the acceleration of the train. It is given by the rate of change of speed of the train i.e.
[tex]a=\dfrac{v-u}{t}[/tex]
[tex]a=\dfrac{32\ m/s-22\ m/s}{142\ s}[/tex]
[tex]a=0.07\ m/s^2[/tex]
So, the acceleration of the car is 0.07 m/s². Hence, the correct option is (d) 0.07 m/s²
Alcohols are organic compounds that contain a. carbon and oxygen only. c. carbon, oxygen, and hydrogen. b. carbon and hydrogen only. d. carbon, nitrogen, and hydrogen.
Answer: Option (c) is the correct answer.
Explanation:
Compounds which contain carbon and hydrogen atoms are known as organic compounds.
As general chemical formula of alcohols is R-OH, where R = any alkyl or aryl group.
For example, [tex]CH_{2}CH_{2}OH[/tex] is known as ethanol and it is an alcohol as it contains the functional group "-OH".
So, alcohols contains elements carbon, hydrogen and oxygen.
Thus, we can conclude that alcohols are organic compounds that contain carbon, oxygen, and hydrogen.
you toss a coin into a wishing well full of liquid denser than the coin. witch of the following could be true? the coin will
A heat pump absorbs heat from the cold outdoors at 3°c and supplies heat to a house at 20°c at a rate of 30,000 kj/h. if the power consumed by the heat pump is 3 kw, the coefficient of performance of the heat pump is
The coefficient of performance (COP) of a heat pump is a measure of its effectiveness and is defined as the ratio of the heat transfer into the warm space to the work input required by the heat pump.
Explanation:The coefficient of performance (COP) of a heat pump is a measure of its effectiveness and is defined as the ratio of the heat transfer (Qh) into the warm space to the work input (W) required by the heat pump. Mathematically, COP = Qh/W.
In this case, the heat pump absorbs heat from the cold outdoors at 3°C and supplies heat to a house at 20°C. The rate of heat transfer is given as 30,000 kJ/h and the power consumed is 3 kW.
To find the COP, we need to convert the rate of heat transfer and power consumed to the same units. Since 1 W = 1 J/s and 1 kJ = 1000 J, we have Qh = 30,000 kJ/h x 1000 J/kJ / 3600 s/h = 8333.33 J/s and W = 3kW x 1000 J/W = 3000 J/s.
Substituting these values into the formula, we get COP = 8333.33 J/s / 3000 J/s = 2.78.
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Which of the following takes place in the combustion chamber of a gas turbine engine?
While driving your car on a level road at 60.0 mph, the traffic ahead of you comes to a sudden stop. you apply your brakes in a panic, causing them to lock. your car skids for 57.0 m before hitting the car in front of you. if µk = 0.550 for your tires on the road, find the speed of your car as it collides with the other car?
First let us calculate the acceleration of the car.
The net force is equivalent to the frictional force:
m a = µk m g
a = µk g
a = 0.550 * 9.8 m/s^2
a = 5.39 m/s^2 (negative direction) = -5.39 m/s^2
Then we use the equation:
v^2 = vi^2 + 2 a d
where v is final speed or velocity, vi is initial speed = 60 mph = 26.8224 m/s, d is distance
v^2 = (26.8224 m/s)^2 + 2 (-5.39 m/s^2) * 57 m
v^2 = 104.98 m^2/s^2
v = 10.25 m/s (ANSWER)
The board sandwiched between two other boards shown below weighs 87.5 n. if the coefficient of friction between the boards is 0.622, what must be the magnitude of the compression forces (assume horizontal) acting on both sides of the center board to keep it from slipping?
The compression forces acting on both sides of the center board = 70.338 N
Further explanationThe force acting on a system with static equilibrium is 0
[tex] \large {\boxed {\bold {\sum F = 0}} [/tex]
(forces acting as translational motion only, not including rotational forces)
[tex] \displaystyle \sum F_x = 0 \\\\\ sum F_y = 0 [/tex]
For objects undergoing rotation, the equilibrium must be met
[tex] \large {\boxed {\bold {\sum \tau = 0}} [/tex]
The force acting on the touchpad between the two fields is called the normal force (N)
While the frictional force arises because of 2 objects that come into direct contact, especially when there is motion between two objects that are in direct contact.
There are 2 friction forces
static friction: fs = us.N kinetic friction: fk = uk .N
The board sandwiched between two other boards will not fall if
a downward force = an upward force
or ΣFy = 0 (idle / equilibrium)
so that
A downward force = weight of the board sandwiched = 87.5 N
An upward force = arises from two static friction forces namely: us.N (N = reaction force of the compression forces=F) ---> us.F
then the force that works can be stated:
EFy = 0
W = 2fs
W = 2 (us.F)
87.5 N = 2 (0.622. F)
F = 70,338 N
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in texas the speed limited in a/an is 30 mph
In Texas, the speed limit in urban districts is generally set at 30 mph unless otherwise posted. This means that unless there are signs indicating a different speed limit, drivers are expected to adhere to a maximum speed of 30 miles per hour when traveling through urban areas. Therefore, the correct answer is A. 30 mph.
The rationale behind setting a default speed limit for urban districts is to promote safety for both motorists and pedestrians. Urban areas typically have higher population densities, increased pedestrian activity, and more complex traffic patterns compared to rural or suburban areas. As a result, lower speed limits help reduce the risk of accidents, particularly those involving pedestrians and cyclists.
By setting a default speed limit of 30 mph in urban districts, Texas law aims to create safer environments for all road users. However, it's essential for drivers to remain vigilant and observant of posted speed limit signs, as speed limits may vary depending on factors such as road conditions, proximity to schools or residential areas, and construction zones.
Overall, the default speed limit of 30 mph in urban districts reflects a balance between ensuring efficient traffic flow and prioritizing the safety of all individuals on the road. Therefore, the correct answer is A. 30 mph.
The complete question is:
In Texas, the speed limit in urban districts is _______ unless otherwise posted.
A. 30 mph
B. 50 mph
C. 40 mph
D. 25 mph