(a) 18.3 m/s
According to the law of conservation of momentum, the total initial momentum of the system must be equal to the total final momentum, so we have
[tex]p_i = p_f\\m u = (m+M)v[/tex]
where
m = 0.0240 kg is the mass of the bullet
u = 400 m/s is the initial speed of the bullet
M = 0.5 kg is the mass of the block
v is the final speed of the block+bullet together
Solving for v, we find the velocity after the collision
[tex]v=\frac{mu}{m+M}=\frac{(0.0240 kg)(400 m/s)}{0.0240 kg+0.5 kg}=18.3 m/s[/tex]
(b) 17.0 m/s
The frictional force acting on the bullet-block system is
[tex]F_f = -\mu (m+M)g[/tex]
where
[tex]\mu = 0.30[/tex] is the coefficient of kinetic friction
The acceleration due to the frictional force, therefore, will be equal to the frictional force divided by the total mass:
[tex]a=\frac{F_f}{m+M}=\-mu g = -(0.30)(9.8 m/s^2)=-2.94 m/s^2[/tex]
The system travels for a distance of
d = 8.0 m
So we can find the final velocity using the equation:
[tex]v_f^2 = v^2 + 2ad[/tex]
where
v = 18.3 m/s is the initial velocity, found at point a). Substituting,
[tex]v_f = \sqrt{(18.3 m/s)^2+2(-2.94 m/s^2)(8.0 m)}=17.0 m/s[/tex]
(c) 2.1 m
We can use again the law of conservation of momentum:
[tex](m+M) v = (m+M+M')v'[/tex]
where
v = 17.0 m/s is the initial velocity of the initial bullet+block system
M = 2.00 kg is the mass of the second block
v' is the final velocity of the system
Solving for v',
[tex]v=\frac{(m+M)v}{m+M+M'}=\frac{(0.0240 kg+0.5 kg)(17.0 m/s)}{0.0240 kg+0.5 kg+2.00 kg}=3.5 m/s[/tex]
The acceleration of the system on the rough surface is still
[tex]a=-2.94 m/s^2[/tex]
So we can find the distance covered by using again the formula used before, and requiring that the final velocity should be zero (v''=0):
[tex]v''^2 - v'^2 = 2ad\\d=\frac{v''^2-v'^2}{2a}=\frac{0-(3.5 m/s)^2}{2(-2.94 m/s^2)}=2.1 m[/tex]
a)The velocity of the combined bullet and block just after collision is 18.32 m/s. b)After sliding with friction, the velocity is 16.99 m/s, and c) after sticking to a 2.00 kg block, the combined system travels 2.13 m before stopping.
First, we need to find the velocity of the combined bullet and block system just after the collision using conservation of momentum.
(a) Using conservation of momentum:
initial momentum = final momentum
m₁ = mass of bullet , v₁= vel of bullet , m₂ = mass of block ,v₂ = final velocity
( m₁ × v₁) = (m₁ + m₂) × v₂
(0.0240 kg × 400 m/s) = (0.0240 kg + 0.500 kg) × v₂
9.6 kg×m/s = 0.524 kg × v₂
v₂ = 9.6 kg×m/s / 0.524 kg
v₂ ≈ 18.32 m/s
(b) To find the velocity after sliding with friction:
The work done by friction = kinetic energy loss , total mass = M
friction force = μ × M × g
work done by friction = friction force × distance
M = 0.524 kg
μ = 0.30
d = 8.0 m
work = μ × M × g × d
work = 0.30 × 0.524 kg × 9.8 m/s² × 8.0 m
work ≈ 12.31 J
initial kinetic energy = 0.5 × M × (v₂)²
initial kinetic energy ≈ 0.5 × 0.524 kg × (18.32 m/s)² ≈ 87.84 J
final kinetic energy = initial kinetic energy - work by friction
final kinetic energy ≈ 87.84 J - 12.31 J ≈ 75.53 J
final velocity = √(2 × final kinetic energy / M)
final velocity ≈ √(2 × 75.53 J / 0.524 kg) ≈ 16.99 m/s
(c) To find the distance traveled after sticking to the 2.00 kg block:
Using conservation of momentum:
(m₃ × v₂) = (m₃ + m₄) × V , V = final velocity new
mass of bullet block ≈ m₃ = 0.524 kg
mass of new block = m₄ = 2.00 kg
(m₃ × final velocity found in (b))
0.524 kg × 16.99 m/s = (0.524 kg + 2.00 kg) × V
8.90 kg×m/s = 2.524 kg * V_new_final
V ≈ 3.53 m/s
Now we deal with the kinetic friction again to find the stopping distance:
work = μ × M₁ × g × d , M₁ = new total mass
M₁ = 2.524 kg
μ = 0.30
work = 0.3 × 2.524 kg × 9.8 m/s² × d
initial kinetic energy = 0.5 × M₁ × V₁²
initial kinetic energy ≈ 0.5 × 2.524 kg × (3.53 m/s)² ≈ 15.70 J
work = initial kinetic energy
0.3 × 2.524 kg × 9.8 m/s² × d = 15.70 J
d ≈ 2.13 m
A sphere completely submerged in water is tethered to the bottom with a string. the tension in the string is one-fourth the weight of the sphere.
Answer:
800 kg/m³
Explanation:
I assume you want to find the density of the sphere?
Start with a free body diagram. There are three forces acting on the sphere: gravity pulling the sphere down, buoyancy pushing the sphere up, and tension pulling the sphere down.
Applying Newton's second law:
∑F = ma
B - W - T = ma
Since the sphere isn't accelerating, a = 0.
B - W - T = 0
B = W + T
We know that the tension is one-fourth the weight:
B = W + W/4
B = 5/4 W
B = 5/4 mg
Buoyant force is defined as:
B = ρVg,
where ρ is the density of the fluid, V is the displaced volume, and g is acceleration of gravity.
ρVg = 5/4 mg
ρV = 5/4 m
The mass of the sphere is equal to its density times its volume. Since the sphere is fully submerged, it's volume is the same as the volume of the displaced water.
ρV = 5/4 ρₓV
ρ = 5/4 ρₓ
ρₓ = 4/5 ρ
So the density of the sphere is 4/5 the density of the water. Water's density is 1000 kg/m³, so:
ρₓ = 4/5 (1000 kg/m³)
ρₓ = 800 kg/m³
The submerged sphere experiences a gravitational force (its weight) and a counteracting buoyant force. The tension in the string tethering it is one-fourth of the sphere's weight. This situation could occur if the buoyant force on the sphere is three-fourths of the sphere's weight.
Explanation:The subject of this question is about the physics of forces in a fluid medium - specifically, the interaction between buoyancy, weight, and tension. In this case, a sphere is fully submerged in water and secured with a string. Despite being underwater, the object still experiences the force of gravity, which pulls it downward. This weight is represented by the mass of the sphere times the acceleration due to gravity (we use 9.8 m/s² for Earth).
However, while submerged, the sphere also experiences a buoyant force due to the displacement of the water. This force is equal to the weight of the water displaced by the sphere, which acts in the opposite direction of the weight, or upward. The string provides a tension force that prevents the sphere from moving.
In this scenario, the tension force in the string is one-fourth the weight of the sphere. This could happen if the buoyant force acting on the sphere is equal to three-fourths of the sphere’s weight, leaving one-fourth of the sphere's weight to be balanced by the string.
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Describe the difference between red light and blue light.
Answer:
Red light has longer wavelength, while blue light has higher frequency
Explanation:
Red light and blue light corresponds to two different portion of the visible part of the electromagnetic spectrum.
The two colors have different wavelengths - more precisely:
Blue: 450 - 500 nm
Red: 620 - 750 nm
So, we see that red light has a longer wavelength than blue light.
Moreover, the frequency of an electromagnetic wave, f, is inversely proportional to the wavelength, [tex]\lambda[/tex]:
[tex]f=\frac{c}{\lambda}[/tex]
where c is the speed of light. This means that blue light, which has a shorter wavelength, has a higher frequency than red light.
What property of objects is best measured by their capacitance?
a) ability to conduct electric current
b) ability to distort an external electrostatic field
c) ability to store charge
Answer:
c) ability to store charge
Explanation:
The capacity of an object gives a measure of the ability of the object to store electric charge. In formula, it is defined as the ratio between the charge stored on the object and the electric potential on the object:
[tex]C=\frac{Q}{V}[/tex]
where
Q is the charge
V is the voltage
Therefore, an object with a larger capacity than another object means that if the two objects are at same voltage V, the first object can store more charge than the second object.
Capacitance measures an object's ability to store charge, and is dependent on the geometry of conductor arrangement and the dielectric properties between conductors. It is measured in farads, with one farad being equivalent to one coulomb of charge per one volt.
Explanation:The property of objects that is best measured by their capacitance is their ability to store charge. A capacitor, which is an arrangement of objects that can store electrical energy due to their geometry, has a capacitance that is directly proportional to the electric potential energy it can store per unit electric potential. The capacitance of a system depends only on the geometry of the conductor arrangement and the physical properties of the dielectric between the conductors.
It is important to note that capacitance is not related to a material's ability to conduct electric current nor is it primarily about distorting an external electrostatic field. Instead, it defines how much charge can be separated for a given electric potential, that is, how much electric energy is stored or held in potential. The SI unit of capacitance is the farad (F), where 1 farad equals 1 coulomb (C) per 1 volt (V).
At an atmospheric pressure of 870 mm Hg with 21 percent oxygen, the partial pressure of oxygen is _____.A) 219 mm HgB) 127 mm HgC) 151 mm HgD) 182 mm HgE) 100 mm Hg
Answer:
d) 182 mm Hg
Explanation:
The ratio of partial pressure to total pressure is equal to the molar ratio.
P / 870 mm Hg = 0.21
P = 182 mm Hg
Answer is D.
Final answer:
At an atmospheric pressure of 870 mm Hg with 21 percent oxygen, the partial pressure of oxygen is D) 182mm
Explanation:
The question is asking to calculate the partial pressure of oxygen in the atmosphere when the total atmospheric pressure is 870 mm Hg, given that oxygen constitutes 21% of the atmosphere. The partial pressure of oxygen (Po₂) is found by multiplying the total pressure by the percent content of oxygen in the mixture. This can be calculated as follows:
Po₂ = (870 mm Hg) × (0.21)
Therefore, the partial pressure of oxygen is:
Po₂ = 182.7 mm Hg
Since we only have whole numbers in the options provided, we round this to the nearest whole number, which is 183 mm Hg. This is not exactly one of the options given, so it seems there might be a typo in the choices; the closest correct answer would be 182 mm Hg.
All of the statements about nuclear reactions are true except All of the statements about nuclear reactions are true except energy changes in nuclear reactions are much greater than in ordinary chemical reactions. nuclear reactions involve changes in the nucleus of an atom. the rate of a nuclear reaction is increased by the addition of a catalyst. nuclear reactions of the same element vary according to which isotope is involved. a nuclear reaction is unaffected by the chemical state of the atoms involved.
A nuclear reaction will not be affected with the use of a catalyst.
The incorrect statement is that the rate of a nuclear reaction is increased by the addition of a catalyst. Nuclear reactions result in significant energy changes and the transformation of elements or isotopes, but they are not influenced by catalysts or the chemical state of atoms.
One of the statements about nuclear reactions provided in the student's question is not true. In fact, the statement that the rate of a nuclear reaction is increased by the addition of a catalyst is incorrect. Unlike chemical reactions, the rate of a nuclear reaction is not affected by catalysts because nuclear reactions involve changes within the nucleus of an atom, and catalysts do not have the ability to affect the nuclear forces that govern these reactions.
Nuclear reactions are significant because they involve much larger energy changes compared to ordinary chemical reactions. The energy released or absorbed during nuclear reactions can result in a measurable change in mass, according to the principle of mass-energy equivalence. Also, these reactions often lead to the formation of different isotopes or even different elements, depending on the changes within the atomic nucleus.
Furthermore, nuclear reactions are not influenced by the chemical state of the atoms involved or by the presence of a catalyst. They depend primarily on factors related to the nuclei themselves, such as neutron flux in a fission reactor or temperature and pressure in a fusion reaction.
At t=0 a grinding wheel has an angular velocity of 20.0 rad/s . it has a constant angular acceleration of 35.0 rad/s2 until a circuit breaker trips at time t = 2.30 s . from then on, it turns through an angle 433 rad as it coasts to a stop at constant angular acceleration. part a through what total angle did the wheel turn between t=0 and the time it stopped?
Over the first 2.30 s, the wheel turns by angle [tex]\theta[/tex] according to
[tex]\theta=\left(20.0\dfrac{\rm rad}{\rm s}\right)t+\dfrac12\left(35.0\dfrac{\rm rad}{\mathrm s^2}\right)t^2[/tex]
so that after 2.30 s, it will have turned
[tex]\theta=138.575\,\mathrm{rad}[/tex]
Then the wheel turns a total of [tex]\theta+433\,\mathrm{rad}[/tex] over this entire interval, or [tex]572\,\mathrm{rad}[/tex].
Massive stars terminate in a brilliant explosion called a
super nova is named for such explosion
Answer:
supernova
Explanation:
gradpoint
The drag force pushes opposite your motion as you ride a bicycle. If you double your speed, what happens to the magnitude of the drag force? The drag force goes up by a factor of 4 The drag force stays the same. The drag force decreases. The drag force doubles as well
Explanation:
The Drag Force equation is:
[tex]F_{D}=\frac{1}{2}C_{D}\rho A_{D}V^{2}[/tex] (1)
Where:
[tex]F_{D}[/tex] is the Drag Force
[tex]C_{D}[/tex] is the Drag coefficient, which depends on the material
[tex]\rho[/tex] is the density of the fluid where the bicycle is moving (air in this case)
[tex]A_{D}[/tex] is the transversal area of the body or object
[tex]V[/tex] the bicycle's velocity
Now, if we assume [tex]C_{D}[/tex], [tex]\rho[/tex] and [tex]A_{D}[/tex] do not channge, we can rewrite (1) as:
[tex]F_{D}=C.V^{2}[/tex] (2)
Where [tex]C[/tex] groups all these coefficients.
So, if we have a new velocity [tex]V_{n}[/tex] , which is the double of the former velocity:
[tex]V_{n}=2V[/tex] (3)
Equation (2) is written as:
[tex]F_{D}=C.V_{n}^{2}=C.(2V)^{2}[/tex]
[tex]F_{D}=4CV^{2}[/tex] (4)
Comparing (2) and (4) we can conclude the Drag force is four times greater when the speed is doubled.
An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the right. The displacement of the object is _____.
Answer: 5 units
Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:
The trajectory is the path followed by the body (is a scalar magnitude).
The displacement is the distance in a straight line between the initial and final position (is a vector magnitude).
According to this, in the description of the object (figure attached) placed at 0 on a number line and moving some units to the left and some oter units to the right, we are talking about the path followed by the object, hence its trajectory. So, 13 units is its trajectory.
But, if we talk about displacement, we have to draw a straight line between the initial position of the object (point 0) to its final position (point 5).
Now, being this an unidimensional problem, the displacement vector for this object is 5 units.
An arrow pointing upward is placed to the left of a thin converging lens, as shown in the diagram. To identify the location of the image, a student draws three principal from the arrow. What feature should all three principal rays have in common?
Answer:
I'm not sure if I have the right words for it, but it is most likely that all three rays will form a larger inverted image after they pass through the lens because the arrow is outside the focal point. The image will be outside of F2, like the arrow is outside of F1.
Explanation:
Due to the shape of the lens in the diagram, you can imagine 3 lines branching out from point Q. I've made a digital sketch about what will happen as they pass through. It's a little crude, but it still works. I hope this was helpful.
The three principal rays intersect at the right side of the convergent lens.
To find the answer, we need to know about the trace of the principal rays.
What are the three principal rays?The three principal rays are as follows
A ray parallel to the axis A ray passes through the pole of the convergent lensA ray passes through the focus at the left side of the lensAll the above rays are drawn from the tip of the pointed arrow.
What will be the nature of the three principal rays after passing through the convergent lens?The ray that is parallel to the axis, moves through the focus that present on the right of lens after passing through the lens.The ray that passes through the pole of the lens moves without deviation.The ray that passes through the left focus moves parallel to the axis after passing through the lens.All these three rays meet at a certain point where the image is formed.Thus, we can conclude that the three principal rays intersect at the right side of the convergent lens.
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If the mass of the earth and all objects on it were suddenly doubled, but the size remained the same, the acceleration due to gravity at the surface would becomeA) 1/2 of what it now is.B) 2 times what it now is.C) 1/4 of what it now is.D) the same as it now is.E) 4 times what it now is.
Answer:
B) 2 times what it now is
Explanation:
The acceleration due to gravity at the surface of the Earth is given by
[tex]g=\frac{GM}{R^2}[/tex]
where
G is the gravitational constant
M is the mass of the Earth
R is the Earth's radius
In this problem, the mass of the Earth is doubled:
M' = 2M
while the radius remains the same:
R' = R
so the new acceleration due to gravity would be
[tex]g'=\frac{GM'}{R'^2}=\frac{G(2M)}{R^2}=2\frac{GM}{R^2}=2g[/tex]
so, the acceleration due to gravity would become twice the current value.
Note also that the value of g does not depend on the mass of the objects involved.
Planet with the most extreme temperature range
Answer:
Mercury
Explanation:
A bicycle rider increases his speed from 5 m/s to 15 m/s in while accelerating at 2.5 m/s2. How long does this take ?
Answer:
4 seconds
Explanation:
Average acceleration is change in velocity over change in time:
a = Δv / Δt
Δt = Δv / a
Δt = (15 m/s - 5 m/s) / 2.5 m/s²
Δt = 4 s
Answer: The time taken by the bicycle rider is 4 seconds.
Explanation:
To calculate the time taken by the rider, we use first equation of motion:
[tex]v=u+at[/tex]
where,
v = final velocity of the rider = 15 m/s
u = initial velocity of the rider = 5 m/s
a = acceleration of the car = [tex]2.5m/s^2[/tex]
t = time taken = ?
Putting values in above equation, we get:
[tex]15=5+(2.5\times t)\\\\t=\frac{15-5}{2.5}\\\\t=4s[/tex]
Hence, the time taken by the bicycle rider is 4 seconds.
If the star Alpha Centauri were moved to a distance 10 times farther than it is now, its parallax angle would
Answer:
decrease by a factor 10
Explanation:
The parallax angle of a close star is given by
[tex]p=\frac{1}{d}[/tex]
where
p is the parallax angle
d is the distance of the star from Earth, in parsecs
From the formula we see that the parallax angle is inversely proportional to the distance.
In this problem, the distance of the star is increased by a factor 10:
d' = 10 d
so the new parallax angle would be
[tex]p'=\frac{1}{10 d}=\frac{1}{10}\frac{1}{d}=\frac{p}{10}[/tex]
So, the parallax angle would decrease by a factor 10.
If the star Alpha Centauri were moved to a distance 10 times farther than its current position, its parallax angle would become 10 times smaller due to the inverse relationship between parallax and distance.
Explanation:The concept in question is related to the parallax method in astronomy, a way to measure the distances to nearby stars relative to distant ones. This method works because of Earth's annual motion around the Sun, essentially creating a large baseline and a triangle. Parallax is defined as the one-half angle that a star appears to shift when observed from different sides of the Earth's orbit, and this shift decreases with distance.
If the star Alpha Centauri were moved to a distance 10 times farther than it is now, it’s parallax angle would become 10 times smaller. This is because parallax and distance have an inverse relationship: as distance increases, parallax decreases, and vice versa. This rule applies to any interstellar object observed from Earth, including Alpha Centauri. Therefore, the parallax angle of Alpha Centauri would be one tenth of what it is now if it were 10 times farther away.
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How does the atmosphere interact with the geosphere
Answer:
Explanation:
The atmosphere is the gaseous portion of the earth. It consists of different molecules of gas.
The geosphere is the solid portion of the earth which include the crusts, mantle and the core.
Earth is a dynamic planet. Our planet is dynamic in the sense that it is constantly changing and all its parts interacts with one another.
The gases in the atmosphere such a CO₂, H₂O, Nitrogen oxides originates from volcanic processes from deep within the earth. Hydrothermal vents and black smokers constantly release gases into the atmosphere.
The atmosphere plays a lot of roles in determining weather and climatic conditions. Agents of denudation like wind, water and glaciers are connected to the movement of gaseous portion of the earth. As new rocks forms on the crust, wind, water and glaciers acts on them. This process plays a central role in the rock cycle. The rock cycle would not be complete without agents of denudation which are strongly connected to the workings of atmospheric gases and materials like dusts.
Therefore we see that the geosphere and atmosphere are linked.
What is a partial solar eclipse definition
Answer: It seems i am made for this since, i LOVE eclipses, so basically it's when the moon goes in front of the moon, and is kinda hidden, making an eclipse
Hello There!
A partial solar eclipse is when the moon comes between the sun and our planet "Earth" but they do not align in a perfect straight line. Because of this, the moon only covers around half of the suns disc
In adolescence, when it comes to neurological development, the _____________ matures sooner than the _____________, which helps explain why teens have emotional rushes and impulses that are not completely regulated or controlled.
Answer:
Amygdala, Frontal cortex
Explanation:
The amygdala is part of the brain responsible for aggressive behavior, fear and immediate reactions associated with high risks. The frontal cortex, on the other hand, is the part of the brain responsible for reasoning. Because the former matures faster than the latter in adolescents, then teens' behavior is generally associated with high risks and little reasoning before acting.
Which of the following is true for both outer gas planets and inner terrestrial planets?
Their orbits are inside the asteroid belt.
They have rings.
They have a round shape.
They have a core of ice.
Answer:
They have a round shape
Explanation:
The gas giants which are the outer planets, and the terrestrial planets which are the inner ones have lot of differences between them. They have different sizes, different composition, different atmospheres, temperatures etc. But they also have something in common, which is pretty much the most obvious thing, they all have round shape. All of the planets have round shape, or rather they are slightly elliptical as they are more elongated around their equators, and slightly more flattened around their poles. This kind of shape has occurred because of these planets spin around their own axis, and around the Sun, thus the surface has become much smoother over time because of the friction.
Answer: they have a round shape
Explanation:
What is the equivalent resistance for a parallel circuit that has two resistors: 18.0 ohms and 23.5 ohms?
A.
10.2 ohms
B.
20.8 ohms
C.
5.5 ohms
D.
41.5 ohms
Answer:
A
Explanation:
First of all the answer is less than the smallest resistor, so it is less than 18 ohms.
1 / r1 + 1/ r2 = 1/r
1/18 + 1/23.5 = 1/r
1/18 = 0.05555555
1/23.5 = 0.0422532
1/18 + 1/23.5 = 0.0555555 + 0.0422532
1/r = 0.0981087
r = 1/0.0981087
r = 10.193
A
Final answer:
The equivalent resistance for two resistors in parallel, one with 18.0 ohms and the other with 23.5 ohms, is approximately 10.2 ohms, which is answer choice A.
Explanation:
When calculating the equivalent resistance for resistors in parallel, you use the formula 1/Req = 1/R1 + 1/R2 where Req is the equivalent resistance, and R1 and R2 are the resistances of the individual resistors. For the two resistors with resistances of 18.0 ohms and 23.5 ohms, the calculation would be:
1/Req = 1/18.0 + 1/23.5
1/Req = 0.0556 + 0.0426
1/Req = 0.0982
Req = 1 / 0.0982
Req ≈ 10.18 ohms
Therefore, the correct answer is A. 10.2 ohms.
A transverse wave is characterized by _____.
peaks
compressions
dips
refractions
Answer:
Peaks
Explanation:
- A transverse wave is a wave in which the oscillation occurs in a direction perpendicular to the direction of propagation of the wave
- A longitudinal wave is a wave in which the oscillation occurs in a direction parallel to the direction of propagation of the wave
In a transverse wave, the highest and the lowest points of the wave are determined by the presence of crests (peaks) and troughs. On the contrary, in a longitudinal wave, the wave consists of alternating regions of higher particle density (called compressions) and of lower particle density (called rarefactions).
Therefore, the correct answer is
peaks
Answer:
Peaks, Dips
Explanation:
I got the question right
A uniform solid cylinder with a radius of 10 cm and a mass of 3.0 kg is rotating about its center with an angular speed of 33.4 rpm. What is its kinetic energy?
Answer:
Is the equation for Ec=1/2 m(Dv)^2 where Dv is the difference between the angular speed & the areolar speed?
The maximum Compton shift in wavelength occurs when a photon isscattered through 180^\circ .
What scattering angle will produce a wavelength shift of one-fourththe maximum? Express the answer as a whole number indegrees.
Answer: [tex]90\°[/tex]
Explanation:
The Compton Shift [tex]\Delta \lambda[/tex] in wavelength when the photons are scattered is given by the following equation:
[tex]\Delta \lambda=\lambda_{c}(1-cos\theta)[/tex] (1)
Where:
[tex]\lambda_{c}=2.43(10)^{-12} m[/tex] is a constant whose value is given by [tex]\frac{h}{m_{e}c}[/tex], being [tex]h[/tex] the Planck constant, [tex]m_{e}[/tex] the mass of the electron and [tex]c[/tex] the speed of light in vacuum.
[tex]\theta)[/tex] the angle between incident phhoton and the scatered photon.
We are told the maximum Compton shift in wavelength occurs when a photon isscattered through [tex]180\°[/tex]:
[tex]\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))[/tex] (2)
[tex]\Delta \lambda_{max}=\lambda_{c}(1-(-1))[/tex]
[tex]\Delta \lambda_{max}=2\lambda_{c}[/tex] (3)
Now, let's find the angle that will produce a fourth of this maximum value found in (3):
[tex]\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)[/tex] (4)
[tex]\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)[/tex] (5)
If we want [tex]\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}[/tex], [tex]1-cos\theta[/tex] must be equal to 1:
[tex]1-cos\theta=1[/tex] (6)
Finding [tex]\theta[/tex]:
[tex]1-1=cos\theta[/tex]
[tex]0=cos\theta[/tex]
[tex]\theta=cos^{-1} (0)[/tex]
Finally:
[tex]\theta=90\°[/tex] This is the scattering angle that will produce [tex]\frac{1}{4}\Delta \lambda_{max}[/tex]
Rising air colliding with fast-moving horizontal winds can form what?
-- turbulence
-- well mixed, non layered atmosphere
-- tornados
-- cumulonimbus clouds
-- thunderstorms
-- a lot of heavy clouds
A 15.0 cm object is 12.0 cm from a convex mirror that has a focal length of -6.0 cm. What is the height of the image produced by the mirror?
In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .
The Mirror equation is:
[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex] (1)
Where:
[tex]f=-6cm[/tex] is the focal distance
[tex]u=12cm[/tex] is the distance between the object and the mirror
[tex]v[/tex] is the distance between the image and the mirror
We already know the values of [tex]f[/tex] and [tex]u[/tex], let's find [tex]v[/tex] from (1):
[tex]v=\frac{u.f}{u-f}[/tex] (2)
[tex]v=\frac{(12cm)(-6cm)}{12cm-(-6cm)}[/tex]
[tex]v=-4cm[/tex] (3)
On the other hand, the magnification [tex]m[/tex] of the image is given by the following equations:
[tex]m=-\frac{v}{u}[/tex] (4)
[tex]m=\frac{h_{i}}{h_{o}}[/tex] (5)
Where:
[tex]h_{i}[/tex] is the image height
[tex]h_{o}=15cm[/tex] is the object height
Now, if we want to find the image height, we firstlu have to find [tex]m[/tex] from (4), substitute it on (5) and find [tex]h_{i}[/tex]:
Substituting (3) in (4):
[tex]m=-\frac{-4cm}{12cm}[/tex]
[tex]m=\frac{1}{3}[/tex] (6)
Substituting (6) in (5):
[tex]\frac{1}{3}=\frac{h_{i}}{15cm}[/tex]
[tex]h_{i}=\frac{15cm}{3}[/tex]
Finally we obtain the value of the height of the image produced by the mirror:
[tex]h_{i}=5cm[/tex]
Answer:
The answer is D. on edgen
Explanation:
D. 5.0
what term describes atoms with different atomic masses due to varying numbers of neutrons
The term is “ISOTOPES” These describe atoms with different atomic masses.
The term which describes different atomic masses of similar atom because of varying numbers of neutrons are Isotopes.
Explanation:
The isotopes are the chemical element which has different atomic masses due to the fact that number of neutrons are not same but it has same number of proton.
When the number of neutron increases in a nucleus, with the same electronic configuration and same number of proton, element is said to have isotopes. There are may be variants of isotopes of an element. For example, hydrogen has 3 isotopes.
Permafrost characterizes the biome called
Answer:
Tundra Biome
Explanation:
Permafrost is a type of soil that is frozen all year round. It consists of rocks, soils and ice. The ice or frost holds the earth materials together.
The tundra biome lies below the arctic circle close to the north pole. Most of the earth here is predominantly frozen all year round. A layer of glacier covers the surface and a deep lying layer of permafrost follows suit.
Some mountain tops capped with ice shows this tundra features.
Most tundras are termed cold deserts as they have little to no precipitation all year round. There is absence of vegetation cover as a result of low growing season of the plants.
An electric field can be created by a single charge or a distribution of charges. The electric field a distance from a point charge has magnitude E = k|q'|/r^2.The electric field points away from positive charges and toward negative charges. A distribution of charges creates an electric field that can be found by taking the vector sum of the fields created by individual point charges. Note that if a charge is placed in an electric field created by q', q will not significantly affect the electric field if it is small compared to q'.Imagine an isolated positive point charge with a charge Q (many times larger than the charge on a single electron).There is a single electron at a distance from the point charge. On which of the following quantities does the force on the electron depend?Check all that apply.A the distance between the positive charge and the electronB the charge on the electronC the mass of the electronD the charge of the positive chargeE the mass of the positive chargeF the radius of the positive chargeG the radius of the electron
Answer:
A the distance between the positive charge and the electron
B the charge on the electron
D the charge of the positive charge
Explanation:
The electric field produced by the positive charge Q at the location of the electron is given by
[tex]E=k\frac{Q}{r^2}[/tex]
where
k is the Coulomb constant
Q is the charge
r is the distance between the charge Q and the electron
The force exerted on a charged particle by an electric field is given by
[tex]F=qE[/tex]
where q is the magnitude of the charged particle. So, the force exerted on the electron in this problem is
[tex]F=eE = k\frac{eQ}{r^2}[/tex]
where e is the charge of the electron. As we see from the equation, the force depends only the following quantities:
A the distance between the positive charge and the electron (r)
B the charge on the electron (e)
D the charge of the positive charge (Q)
Final answer:
The force on an electron in an electric field depends on the distance between the positive charge and the electron, the charge on the electron, and the charge of the positive charge. Factors such as the masses and radii of the charges do not directly affect the electrostatic force.
Explanation:
An electric field is created by electric charges and can exert a force on other charges within the field. The force on an electron in an electric field created by a positive point charge depends on several factors. Let's identify these dependencies.
A. The distance between the positive charge and the electron: The force is inversely proportional to the square of the distance between the charges (r2).
B. The charge on the electron: The electrostatic force exerted on the electron is proportional to the magnitude of its charge.
D. The charge of the positive charge: The magnitude of the electric field, and therefore the force on the electron, is proportional to the charge of the positive point charge (Q).
The mass of the electron (C), the mass of the positive charge (E), the radius of the positive charge (F), and the radius of the electron (G) do not affect the electrostatic force the electron experiences.
A 30-gram bullet is fired and a 50-gram bullet is dropped simultaneously from the same height. Which will hit the ground first?
The 30-gram bullet fired and 50-gram bullet dropped from the same height, ignoring air resistance, will hit the ground at the same time. The reason is that the acceleration due to gravity is a constant and act only vertically downward. If air resistance were present, the fired bullet would hit the ground first due to deceleration caused by air resistive force.
Explanation:The subject of this question is Physics, and it deals with the concept of free fall and projectile motion. Free fall is a type of motion in which an object falls downward due to gravitational force only, with no other forces having an impact. Projectile motion is the motion of an object that is launched into the air and subject to gravity and air resistance.
In this case, we are asked which of the two objects, a bullet fired horizontally and another dropped directly downward from the same height, will hit the ground first, ignoring air resistance. The surprising answer is that they hit the ground at the same time. While the fired bullet travels a further horizontal distance, the vertical component of its motion behaves just like that of the dropped bullet. Therefore, both bullets hit the ground simultaneously.
However, if air resistance is taken into account, the bullet will decelerate quicker due to its higher speed resulting in a greater air resistive force. This would cause the fired bullet to hit the ground first. This is derived from the fundamental laws of Physics that describe the effect of gravity on an object's motion. The acceleration due to gravity is a constant and acts only vertically downward, therefore, it affects both scenarios the same, making both bullets hit the ground at the same time in vacuum.
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Which portion of the electromagnetic spectrum is used to identify fluorescent minerals?
a) ultraviolet light
b) X rays
c) infrared waves
d) gamma rays
Ultraviolet light, whose wavelength is approximately between 100 nm and 380 nm; is a type of electromagnetic radiation that is not visible to the human eye.
This light is used for many purposes, among which is the identification of fluerescent minerals.
In this sense, fluorescence is a property that certain materials have in which they absorb energy in the form of short wavelength not visible electromagnetic radiation (the ultraviolet, for example) and then emit some of that energy in the form of longer wavelength electromagnetic radiation (in the visible spectrum). This is also called luminiscence.
Hence, the correct option is a.
Two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at point P, what should be the path difference between the two waves? Two beams of coherent light travel different paths, arriving at point P. If the maximum destructive interference is to occur at point P, what should be the path difference between the two waves? The path difference between the two waves should be one-half of a wavelength. The path difference between the two waves should be one wavelength. The path difference between the two waves should be four wavelengths. The path difference between the two waves should be one and one-quarter of a wavelengths. The path difference between the two waves should be two wavelengths. The path difference between the two waves should be one-quarter of a wavelength.
The path difference between the two waves is the path difference between the two waves should be one and one-quarter of a wavelengths.
What is wavelength?
Wavelength is the distance between two identical or similar positions it means that it is the distance between crests or trough in the adjacent cycle of the waveform.
Wavelength is denoted by (lambda).
It is measured in meter, or centimeter, or millimeters.
Mathematically,
Wavelength is equal to velocity divided by frequency,
So,
Wavelength (lambda) = Velocity/frequency.
Velocity is in meter per second.
Frequency is in 1/second.
Prism is a transparent object in which if sunlight is passed then it will be split in a VIBGYOR
where V = vilot, I = indigo, B = blue, G = green, Y = Yellow, O = orange, R = red.
In this series wavelength of red is higher and vilot is smaller and frequency of violet is higher and red is smaller.
Therefore, The path difference between the two waves is the path difference between the two waves should be one and one-quarter of a wavelengths.
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