7. Which of the following relations is a function?
A.{(2, 3), (-2, 3), (3, 2), (-3,-2)}
B.{(8,-4), (-4, 8), (-4, -8), (-8,4)}
C.{(9, -1), (-1, 9), (9, 2), (2, -1)}
D.{(5, -7), (4, 6), (-3, 8), (5,9)}

Answer:

8 batches.

Step-by-step explanation:

Beth made 2.5 batches of blueberry muffins = 15 muffins

Beth needs 60 muffins in total. She already has 15 therefore she only needs 45 more.

45/6 = 7.5

7.5 would not be enough. You need to round up to 8.

Answer:

  C)  ​7×10^8/(5×10^3)

Step-by-step explanation:

In cubic inches, the volume of a bucket of sand is ...

  (π/4)(20 in)²(15 in) = 1500π in³ ≈ 5×10^3 in³

__

The volume of the warehouse is

  (250 ft)(80 ft)(20 ft) = 400,000 ft³ = 4×10^5 ft³

The conversion to cubic inches is ...

  (4×10^5 ft³)(1728 in³/ft³) = 4×1.727×10^8 in³ ≈ 7×10^8 in³

Dividing the warehouse volume by the bucket volume gives the approximate number of buckets that will fit in the warehouse:

  (7×10^8)/(5×10^3) . . . . . matches choice C

The answer would be B (the symbol ~ means similar. In other words, that they are the same shape but not the same size).

It can't be A because the symbol ≈ means "approximately"

It can't be C because the symbol = means equal

It can't be D because the symbol ≅ means congruent

Hope this helped!

~Just a girl in love with Shawn Mendes

Answer:

Part A:

1/2 base * height

=1/2*4*1.5

=3cm

Part B:

1/2 b * h squared

=1/2*4*1.5

=3cm * 2

=6cm

Part C:

8cm*2.5cm

=20cm

Part D:

Length*Width

=8m*4cm

=32cm

(the comment answers, since someone already did the other ones)
(these are all plato answers btw..)
Part E

area of rectangle i = 20 cm²
area of rectangles i and iii = 2 × 20 cm²= 40 cm²

Part F

total area of the rectangles = 32 cm² + 20 cm² + 20 cm² = 72 cm²

Part G

To find the surface area of the prism, I need to know the areas of its bases and lateral faces, which are triangles i and ii and rectangles i, ii, and iii.

Part H

surface area of the prism = areas of bases and faces =
areas of two triangles + area of one large rectangle + areas of two smaller rectangles =
6 cm² + 32 cm² + 40 cm² =
78 cm2

Part I

This statement is false. Only two rectangles in the figure have equal areas. The third rectangle is larger than the other two.

Part J

This statement is true. The triangles are the bases of the prism, so they are congruent. Congruent triangles have the same area.            

We want to write the given function in the form ax^2 + bx + c = 0.

We foil the left side.

(2x - 1)(x + 5) =0

2x^2 + 10x - x - 5 = 0

2x^2 + 9x - 5 = 0

Can you see the value of "b"?

The b-value is the coefficient of x.

So, b = 9.

Done!

Hello! :D

Answer:

[tex]\boxed{m=18}\checkmark[/tex]

*The answer should have a positive sign.*

Step-by-step explanation:

First, you do is switch sides.

[tex]\frac{m}{2}-7=2[/tex]

Then, you add by 7 from both sides.

[tex]\frac{m}{2}-7+7=2+7[/tex]

Add numbers from left to right.

[tex]2+7=9[/tex]

[tex]\frac{m}{2}=9[/tex]

Multiply by 2 from both sides.

[tex]\frac{2m}{2}=9*2[/tex]

Finally, multiply numbers from left to right.

[tex]9*2=18[/tex]

m=18 is the correct answer.

I hope this helps you!

Have a wonderful day! :)

:D

-Charlie

Thanks!

Answer:

m= 18

Step-by-step explanation:

Move all terms not containing "m" to the right side of the equation.

m/2 - 7= 2

Add +7 to each side.

m/2 - 7 = 2

       +7   +7

Add 2 and 7.

m/2= 9

Multiply both sides of the equation by 2

m= 9 (2)

Simplify.

m= 18

Answer:

785

Step-by-step explanation:

(25 - 10)² + 10(14)(4)

= 225 + 560

= 785

Answer:

The correct answer option is C. 1.

Step-by-step explanation:

We are to divide [tex] \frac { 4 0 x } { 6 4 y } [/tex] by [tex] \frac { 5 x } { 8 y } [/tex].

Rewriting them as a fraction in whole:

[tex] \frac { \frac { 4 0 x } { 6 4 y } } {\frac { 5 x } { 8 y } } [/tex]

Changing the division into multiplication by taking the reciprocal of the fraction in the denominator to get:

[tex] \frac { 4 0 x } { 6 4 y } [/tex] × [tex]\frac{8y}{5x}[/tex]

Cancelling out the like terms to get:

1

[tex]\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$20000\\ r=rate\to 7.25\%\to \frac{7.25}{100}\dotfill &0.0725\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{weekly, fifty two times} \end{array}\dotfill &52\\ t=years\dotfill &24 \end{cases}[/tex]

[tex]\bf A=20000\left(1+\frac{0.0725}{52}\right)^{52\cdot 24}\implies A\approx 20000(1.001394)^{1248} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill A\approx 113776.1384~\hfill[/tex]

Answer:

Neither

Step-by-step explanation:

step 1

Verify if the lines are parallel

we know that

If two lines are parallel, then their slopes are the same

In this problem the slope of f(x) =2/7 and the slope of g(x)=7/2

Compare

2/7≠7/2

therefore

The lines are not parallel lines

step 2

Verify if the lines are perpendicular

we know that

If two lines are perpendicular, then the product of their slopes is equal to -1

In this problem the slope of f(x) =2/7 and the slope of g(x)=7/2

Multiply

2/7*7/2=1

1≠-1

therefore

The lines are not perpendicular

1. The four subintervals are [0, 2], [2, 5], [5, 6], and [6, 7]. Their respective right endpoints are 2, 5, 6, and 7. If [tex]C(t)[/tex] denotes the change in sea level [tex]t[/tex] years after 2010, then the total sea level rise over the course of 2010 to 2017 is

[tex]\displaystyle\int_0^7C(t)\,\mathrm dt[/tex]

approximated by the Riemann sum,

[tex]C(2)(2-0)+C(5)(5-2)+C(6)(6-5)+C(7)(7-6)\approx\boxed{20\,\mathrm{mm}}[/tex]

2. The sum represents the definite integral

[tex]\boxed{\displaystyle\int_1^4\sqrt x\,\mathrm dx}[/tex]

That is, we partition the interval [1, 4] into [tex]n[/tex] subintervals, each of width [tex]\dfrac{4-1}n=\dfrac3n[/tex]. Then we sample [tex]n[/tex] points in each subinterval, where [tex]1+\dfrac{3k}n[/tex] is the point used in the [tex]k[/tex]th subinterval, then take its square root.

3. The integral is trivial:

[tex]\displaystyle\int_1^4\sqrt x\,\mathrm dx=\frac23x^{3/2}\bigg|_{x=1}^{x=4}=\boxed{\frac{14}3}[/tex]

4. Using the fundamental properties of the definite integral, we have

[tex]\displaystyle\int_1^4f(x)\,\mathrm dx=e^4-e\implies2\int_1^4f(x)\,\mathrm dx=2e^4-2e[/tex]

[tex]\displaystyle\int_1^4(2f(x)-1)\,\mathrm dx=2e^4-2e-\int_1^4\mathrm dx=\boxed{2e^4-2e-3}[/tex]

5. First note that [tex]\sec x[/tex] is undefined at [tex]x=\dfrac\pi2[/tex], so the integral is improper. Recall that [tex](\tan x)'=\sec^2x[/tex]. Then

[tex]\displaystyle\int_0^{\pi/2}\sec^2\frac xk\,\mathrm dx=\lim_{t\to\pi/2^-}\int_0^t\sec^2\frac xk\,\mathrm dx[/tex]

[tex]=\displaystyle\lim_{t\to\pi/2^-}k\tan\frac xk\bigg|_{x=0}^{x=t}[/tex]

[tex]=\displaystyle k\lim_{t\to\pi/2^-}\tan\frac tk[/tex]

[tex]=k\tan\dfrac\pi{2k}[/tex]

Now,

[tex]k\tan\dfrac\pi{2k}=k\implies\tan\dfrac\pi{2k}=1[/tex]

[tex]\implies\dfrac\pi{2k}=\dfrac\pi4+n\pi[/tex]

[tex]\implies k=\dfrac2{1+4n}[/tex]

where [tex]n[/tex] is any integer.

Evaluate the function

g(x) = 2x2 + 3x – 5 for the input values -2, 0, and 3.

This is tedious math work but necessary to sharpen your skills.

Let x = -2

g(-2) = 2(-2)^2 + 3(-2) – 5

g(-2) = 2(4) - 6 - 5

g(-2) = 8 - 11

g(-2) = -3

Now let x = 0 and repeat the process.

g(0) = 2(0)^2 + 3(0) - 5

g(0) = 0 + 0 - 5

g(0) = -5

Lastly, let x = 3.

g(3) = 2(3)^2 + 3(3) - 5

g(3) = 2(9) + 9 - 5

g(3) = 18 + 9 - 5

g(3) = 27 - 5

g(3) = 22

Did you follow through each step?

Answer:

-19

-5

-14

Step-by-step explanation:

The answer is:

The equation that is represented by the shown graph is the equation from the option D.

[tex]y=e^{x}-4[/tex]

Since we are given two types of functions, exponential and logarithmic, we need to remember that there is just an option that matches with the graph.

So, from the graph we can see that we are looking for an exponential function which intercepts are located at the point (0,-3) and a point which y-coordinate is equal to 0 and its x-coordinate is located at the x-axis between the number 1 and 2.

From the given options we can see that the only exponential function that intercepts the function at y equal to -3 is the fourth option, so, let's prove that:

Option D,

[tex]y=e^{x}-4[/tex]

Finding the y-intercept, we need to make "x" equal to 0, so:

[tex]y=e^{x}-4[/tex]

[tex]y=e^{0}-4[/tex]

[tex]y=1-4=-3[/tex]

So, we know that the y-intercept point is located at (0,-3)

Finding the x-intercept, we need to make "y" equal to 0, so:

[tex]0=e^{x}-4[/tex]

[tex]e^{x}=4[/tex]

[tex]ln(e^{x})=ln(4)\\x=ln(4)=1.386[/tex]

So, we know that the x-intercept point is located at (1.386,0)

Hence, we have that the axis interception points are (0,-3) and (1.386,0), so, the function that matches with the shown graph is the function from the option D.

[tex]y=e^{x}-4[/tex]

Have a nice day!

Note: I have attached a picture for better understanding.

Answer:

The equation that is represented by the shown graph is the equation from the option D.

Step-by-step explanation:

Answer:

options number four is correct because they are children and they can able to identify the book.

Answer:

r = 6.40 feet

Step-by-step explanation:

Given line AB is tangent to circle O at point A, this means ∡OAB = 90°

Hence this is a right angle triangle and we can use the Pythagorean theorem.

r² + 20² = 21²

r²  = 21² - 20²

r²  = 441 - 400

r²  = 41

r  = √41 = 6.40 feet

The radius of the tank is = 6.4ft

The radius of the circle can be calculated using the Pythagorean theorem since a distance in of AB and OB where given.

The formula c²= b²+a²

Where b²= AB = 20ft

a²= AO= r

c² = OB = 21ft

Make a² the subject of formula

a² = c²-b²

= 21² - 20²

= 441-400

= 41

a= √41

a= 6.4ft

Therefore, the radius of the tank is = 6.4ft

Learn more about radius of circle here:

https://brainly.com/question/12908707

Answer:

   86 m²

Step-by-step explanation:

It can be convenient to think of the figure as an 8×12 rectangle with a 4×5 triangle cut off the corner.

The rectangle area is the product of its length and width:

  (12 m)×(8 m) = 96 m²

The triangle area is half the product of its base and height:

  (1/2)(4 m)(5 m) = 10 m²

Then the area of the figure is the difference of these:

  96 m² -10 m² = 86 m²

Answer:

  55 mph

Step-by-step explanation:

Let x represent Bob's speed. Then John's speed is x+10, and their respective times are found by ...

  time = distance/speed

  330/x = 390/(x+10) . . . . . . . the times are the same

  330(x +10) = 390x . . . . . . .  multiply by x(x+10)

  3300 = 60x . . . . . . . . . . . . . subtract 330x

  55 = x . . . . . . . . . . . . . . . . . . divide by the coefficient of x

Bob is driving at 55 miles per hour.

Bob is driving at a speed of 55 miles per hour.

Let's denote Bob's speed as v miles per hour. Since John is driving 10 miles per hour faster than Bob, John's speed is ( v + 10 ) miles per hour.

 The time it takes to travel a certain distance is given by the formula [tex]\( time = \frac{distance}{speed} \)[/tex]

Bob and John travel for the same amount of time, so we can set their times equal to each other:

[tex]\[ \frac{330}{v} = \frac{390}{v + 10} \][/tex]

Cross-multiplying to solve for (v), we get:

[tex]\[ 330(v + 10) = 390v \][/tex]

Expanding the left side:

[tex]\[ 330v + 3300 = 390v \][/tex]

Now, let's move all terms involving (v) to one side:

[tex]\[ 390v - 330v = 3300 \][/tex]

Simplifying, we find:

[tex]\[ 60v = 3300 \][/tex]

Dividing both sides by 60 to solve for  v :

[tex]\[ v = \frac{3300}{60} \] \[ v = 55 \][/tex]

Answer:

12

Step-by-step explanation:

We can count the cubes.

One the right side there are 3 rows of 2 cubes each which is 6

There are 2 sets of identical " sets" of blocks

2*6 = 12

There are 12 blocks

Answer:

The answer is d. q=10 d=28 n=14

Step-by-step explanation:

Answer:

 C)

Step-by-step explanation:

Set each side of the equation equal to y, then rearrange to standard form.

  (1/2)x -5 = y . . . left side of the equal sign

  x -10 = 2y . . . . multiply by 2

  -10 = 2y -x . . . . subtract x

__

  (1/3)x +6 = y . . . right side of the equal sign

  x +18 = 3y . . . . . multiply by 3

  18 = 3y -x . . . . . subtract x

The corresponding system of equations is ...

Answer:

72* 62* & 60* 30* triangles

Step-by-step explanation:

I just remember rhombuses being made with 60 degree triangles from all the examples I did. This may be wrong though. But 90 percent confident lol.

Answer: the triangles marked 75 degrees and 45 degrees

Step-by-step explanation:

A rhombus has equal opposite obtuse angles with equal acute angles.

Answer:

Lucy bought 4 placemats.

Step-by-step explanation:

Let n be the number of placemats Lucy bought.

1 doormat = $7

1 placemat = $2

n placemats = $2n

Total = $(7+2n)

Total number of objects bought = n+1

Average [tex]=\dfrac{\$(7+2n)}{n+1}[/tex]

So,

[tex]\dfrac{\$(7+2n)}{n+1}=\$3[/tex]

Solve this equation:

[tex]7+2n=3(n+1)\\ \\7+2n=3n+3\\ \\3n-2n=7-3\\ \\n=4[/tex]

Hence, Lucy bought 4 placemats.

Answer:

4

Step-by-step explanation:

is the answer

Let’s find the amount of heartbeats for 1 minute, so it’s easier to solve.

Since we divide 4 by 4 to get 1, divide 240 by 4 to get the equivalent.

240/4=60.

Your heart beats 60 times per minute.

Since there are 60 minutes in an hour, multiply the amount of heartbeats per minute (60) by 60.

60*60=3,600

Your heart beats 3,600 times per hour.

Hope this helps!

Answer:

  6.2 cm

Step-by-step explanation:

[tex]\dfrac{26.35\,\text{cm}^{3}}{4.25\,\text{cm}^{2}}=6.2\,\text{cm}[/tex]

The height of the box is 6.2 cm.

Answer:

Monomial

Step-by-step explanation:

Let's look at the edfinitions of all three options.

Monomial: A polynomial with only one term is called a monomial.

Binomial: A polynomial with two terms is called a binomial.

Trinomial: A polynomial with three terms is called a trinomial.

So, according to the definition, the given polynomial is a monomial as it has only one term -2gh ..

Answer:

(5,3)

Step-by-step explanation:

Look for the coordinates of the point of intersection where the 2 graphs cross. This gives the solution.

In this case, they cross at (5,3) and they intersect at only one location (i.e there is only 1 solution)

From the graph, the intersecting point will be (5, 3). Then the correct option is D.

A linear system is one in which the parameter in the equation has a degree of one. It might have one, two, or even more variables.

In a diagram, the two lines are shown.

The lines are intersecting at a point.

From the graph, the intersecting point will be (5, 3).

Then the correct option is D.

The graph is given below.

More about the linear system link is given below.

https://brainly.com/question/20379472

#SPJ2

Answer:

2. 10/3.

Step-by-step explanation:

The numerator x/2 + x/ 3

= 3x/6 + 2x / 6

= 5x / 6

Now divide this by x/4

5x / 6 / x/4

= 5x/6 * 4/x .    The x's cancel so this

=  20/6

=  10/3.

Answer:

B) 67

Step-by-step explanation:

Answer:

The reflection image of P(0, 0) after two reflections is (8,-6)

Step-by-step explanation:

step 1

Find the coordinates of point P after reflection across x=4

we know that

The distance from point P to the line x=4 is equal to 4 units

so

(0,0) -----> (4+4,0) ----> (8,0)

The reflection image of P is (8,0)

step 2

Find the coordinates of point (8,0) after reflection across y=-3

The distance from point (8,0) to the line y=-3 is equal to 3 units

so

(8,0) -----> (8,-3-3) ----> (8,-6)

Answer:

Step-by-step explanation:

Our equations are

[tex]y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\[/tex]

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by  D and its formula is

[tex]D=b^2-4ac\\[/tex]

Where

a= the coefficient of the [tex]x^{2}[/tex]

b= the coefficient of [tex]x[/tex]

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant  and evaluate our answer accordingly .

Let us start with

[tex]y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\[/tex]

Hence we have two real roots for this equation.

[tex]y = 2x^2 - 6x + 5\\[/tex]

[tex]y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D<0\\[/tex]

Hence we do not have any real root for this quadratic

[tex]y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\[/tex]

Hence D>0 and thus we have two real roots for this equation.

[tex]y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\[/tex]

Hence we have one real root to this quadratic equation.

Answer:

The first box is "two real solutions," the second box is "no real solution," the third box is "two real solution," and the fourth box is "one real solution".

Step-by-step explanation: