5x + 2y = 8
x + y = 4

If you want to solve the system of equations by addition, which of the following could you do?

(A.) Multiply the second equation by 5 and add.
(B.) Multiply the second equation by 2 and add.
(C.) Multiply the second equation by -2 and add.

To find the parallel line's equation through the point (6, -5), we identify the slope of 9x - 2y = 7 as (9/2), and then use the point-slope form with the given point to derive the new line's equation. The final general form of this equation is 9x - 2y - 64 = 0.

To find the general form of an equation of the line that is parallel to the line 9x - 2y = 7 and passes through point a(6, -5), we first need to identify the slope of the given line. The slope-intercept form of the line can be found by rearranging the equation into y = mx + b, where m is the slope. For the given equation 9x - 2y = 7, we solve for y to get the slope:

2y = 9x - 7

y = (9/2)x - 7/2

The slope of the given line is (9/2). Since parallel lines have the same slope, our new line will also have a slope of (9/2). Using the point-slope form of a line's equation, we can insert the slope and the coordinates of point a to determine the equation of our new line:

y - y₁ = m(x - x₁)

y - (-5) = (9/2)(x - 6)

y + 5 = (9/2)x - 27

Finally, we rearrange this equation to its general form, Ax + By + C = 0:

(9/2)x - y - 32 = 0

or

9x - 2y - 64 = 0

This is the general form of the equation of the line that is parallel to 9x - 2y = 7 and passes through point (6, -5).

Answer:

C. 9

Step-by-step explanation:

Ron is five years older than twice his cousin's age. Lets assume that Pat's age is 'x' years.

So Ron's age is [tex]2\times x+5=2x+5[/tex]

The question says:

[tex]x+2x+5<35[/tex]

[tex]3x+5<35[/tex]

[tex]3x<35-5[/tex]

[tex]3x<30[/tex]

[tex]x<10[/tex]

Pat's age [tex](x)[/tex] should be less than 10. Therefore, the greatest age (in integer) that Pat can be is 9 years.

The domain will consist of all non-negative real numbers (x ≥ 0).

And, the range will consist of all real numbers (-∞, +∞).

Given that;

The function is,

c (x) = 10x - 50

Now for the domain and range of the function c(x) = 10x - 50,

Since the domain refers to all the possible input values (x) for the function.

In this case, since c(x) represents the profit from selling candles, x would represent the number of candles sold.

The number of candles sold cannot be negative, as it wouldn't make sense to sell a negative number of candles.

So, the domain will consist of all non-negative real numbers (x ≥ 0).

And, The range refers to all the possible output values (c(x)) of the function.

In this case, c(x) represents the profit. The profit can be any real number because it can be positive, negative, or zero.

Therefore, the range will consist of all real numbers (-∞, +∞).

Thus, Domain: All non-negative real numbers (x ≥ 0).

Range: All real numbers (-∞, +∞).

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Answer:

1.0 x 10 ^ 8

Step-by-step explanation:

y = A sin(Bx + C) + D

·        amplitude is A

Final answer:

To find the amplitude of a trigonometric function, identify the coefficient in front of the sine or cosine term in the wave equation. In the example equation y(x, t) = A sin(kx — wt), the amplitude is 0.2 meters, represented by A.

Explanation:

To find the amplitude of a trigonometric function, one must identify the coefficient of the sine or cosine function in the wave equation. Given the wave equation y (x, t) = A sin (kx — wt), the amplitude can be extracted directly as it is the absolute value of the coefficient A in front of the sine or cosine term. In the example provided, the amplitude of the wave is 0.2 meters because it is represented by A in y (x, t) = [tex]0.2 m sin (6.28 mx-1.57 s-t).[/tex]

Moreover, the characteristics of a sinusoidal wave such as wavelength (λ), period (T), and frequency (f) are related to the amplitude but represent different aspects of the wave's behavior. These can be determined using the wave number (k), angular frequency (ω), and initial phase shift, when present.

1) P = 9.4m, A = 4.8m^2

2) 27*14 /2 = 189 ft^2

3) 0.3^3 = 0.027

Answer: The initial number of transactions is neither an independent nor a dependent variable.

Step-by-step explanation:

Here, The initial number of transactions that took place in the first hour of day is 10 and the number of transactions doubles every hour after that.

If x represents the number of hours and y represents Number of transaction after x hours.

Therefore, The function which represents the situation is,

[tex]y = 10\times 2^x[/tex]

Where x is independent variable, while y is dependent variable.

Since initially x=0,   y=10 which is the initial transaction.

And, there is not any impact on the value of 10 by changing the values of x or y, Also 10 is not a variable( because it is a constant value)

Therefore neither it is dependent variable nor it is independent.

Answer:

The initial number of transactions is neither an independent nor a dependent variable.

Step-by-step explanation:

We know that the initial number of transactions that took place in the first hour of day is 10, i. e., a constant that is independent of the total number of transactions and the hour of the day. The independent variable is the time elapsed and the dependent variable is the total number of transactions made.

First, let's define the number we are looking for as n.

So "half a number" is (1/2)×n

Therefore, "four less than" this would be: ((12)×n)−4

And if this is or, in other words, = to #17 we can write the equation:

((12)×n)−4=17

Solving for n while keeping the equation balanced gives:

((12)×n)−4+4=17+4

(12)×n=21

(21)×(12)×n=21×(21)

((21)×(12))×n=421

1×n=42

n=42

To find 60% off of $33.00, you multiply 33 by 60, then divide the product by 100. The result is $19.80, which is the discount amount. So after the discount, the cost is $13.20.

To find out what 60% off of $33.00 is, you need to multiply 33.00 by 60 and then divide that product by 100, as percentages are always out of 100. Here's the process:

So, 60% off of $33.00 equals $19.80. Hence, after a 60% discount, you would pay $13.20 (33 - 19.80), as this is the remaining cost after the discount has been applied.

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Answer: 32 quarts

Step-by-step explanation:

We know that there area 4 quarts in one gallon.

i.e.[tex]1\text{ gallon}=4\text{ quarts}[/tex]

Now, to convert 8 gallons into quart we need to apply unitary method.

Using unitary method , to convert 8 gallons into quart , multiply 8 to 4 , we get

[tex]8\text{ gallon}=8\times4\text{ quarts}\\\\\Rightarrow\ 8\text{ gallon}=32\text{ quarts}[/tex]

Hence there are 32 quarts in 8 gallons.

There are 32 quarts in 8 gallons of quantity.

The given quantity is 8 gallons.

We know that, 1 gallon = 4 quarts

Here, 8 gallons = 8×4

= 32 quarts

Therefore, there are 32 quarts in 8 gallons of quantity.

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To calculate the total miles, first convert 50000 inches to feet, then convert the result to miles. Approximately 0.790 miles are in 50000 inches.

To answer your question, "How many miles are in 50000 inches?" We need to convert inches to miles. We have to use the given conversion rates: 1 foot = 12 inches and 1 mile = 5280 feet.

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1 mile = 5280 feet

1 hour = 3600 seconds

72 * 5280 = 380160 feet per hour

380160/ 3600 = 105.6 feet per second ( round answer if needed)

Final answer:

The composition h = f о g is only guaranteed to be an odd function if both g and f are odd functions. If f is an even function or neither odd nor even, h will not necessarily be an odd function. The property of the composition depends on the nature of both functions involved.

Explanation:

Whether the composition of functions h = f о g is always an odd function when g is an odd function depends on the nature of f. If g(x) is an odd function, it follows that g(-x) = -g(x). However, for h to also be odd, f must satisfy the condition h(-x) = -h(x). This can only be the case if f is also an odd function.

If f were an even function, then f(g(-x)) = f(-g(x)) would equal f(g(x)) due to the even property of f. In this scenario, h would not be an odd function since h(-x) = f(g(-x)) = f(g(x)) = h(x), which violates the definition of an odd function.

When an odd function and an even function are multiplied, the result is an odd function, as exemplified by g(x) = x³ - 3x and h(x) = x². But when composing functions, the outer function's properties dominate the result. Therefore, the composition h = f о g can only be assured to be odd if f itself is odd.